Answer:
118.13 m³Step-by-step explanation:
Given,
Length ( l ) = 5 meters
Width ( w ) = [tex]6 \frac{3}{4} [/tex] meters
Height ( h ) = [tex]3 \frac{1}{2} [/tex] meters
Now, Let's find the volume of rectangular prism :
[tex]volume \: = l \: \times \: w \: \times \: h[/tex]
plug the values
[tex] = 5 \times \frac{27}{4} \times \frac{7}{2} [/tex]
Calculate the product
[tex] = \frac{5 \times 27 \times 7}{4 \times 2} [/tex]
[tex] = \frac{945}{8} [/tex]
[tex] = 118.13 \: {m}^{2} [/tex]
Hope this helps..
Best regards!!
Cece works at a dress shop and needs to calculate the discounts for dresses on sale using the formula d=(p−c)÷2, where d is the discount, p is the original price, and c is the store's cost for the dress. If the store's cost for a dress is $50 and the original price of the dress is $120, what is the discount on the dress?
Answer:
$35
Step-by-step explanation:
Using the formula provided, d=(p−c)÷2 (where d is the discount, p is the original price, and c is the store's cost for the dress.) we can determine the discount.
The original price is 120,
d=(120−c)÷2
The store's cost is 50,
d=(120−50)÷2
So we subtract 120 and 50 to get
d=(70)÷2
70 divide by two is
d= 35
The discount is $35
Suppose we have four integers, no two of which are congruent $\pmod 6$. Let $N$ be the product of the four integers. If $N$ is not a multiple of $6$, then what is the remainder of $N$ when $N$ is divided by $6$?
Answer:
4
Step-by-step explanation:
Given:
A, B, C, D have distinct positive values for mod 6
A (mod 6) = 1
B (mod 6) = 2
C (mod 6) = 4
D (mod 6) = 5
Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.
Furthermore, in order that ABCD mod 6 > 0, we cannot have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.
Thus the only positive residues can only be 1,2,4,5
A*B*C*D (mod 6) > 0 = 1*2*4*5 (mod 6) = 4
Find the area of the shaded region
Answer:
[tex] \mathsf{ {5x}^{2} + 28x + 21}[/tex]
Option A is the right option.
Step-by-step explanation:
Let's find the area of large rectangle:
[tex] \mathsf{(3x + 6)(2x + 4)}[/tex]
Multiply each term in the first parentheses by each term in the second parentheses
[tex] \mathsf{ = 3x(2x + 4) + 6(2x + 4)}[/tex]
Calculate the product
[tex] \mathsf{ = 6 {x}^{2} + 12x + 12x + 6 \times 4}[/tex]
Multiply the numbers
[tex] \mathsf{ = 6 {x}^{2} + 12x + 12x + 24}[/tex]
Collect like terms
[tex] \mathsf{ = {6x}^{2} + 24x + 24}[/tex]
Let's find the area of small rectangle
[tex] \mathsf{(x - 3)(x - 1)}[/tex]
Multiply each term in the first parentheses by each term in the second parentheses
[tex] \mathsf{ = x( x - 1) - 3(x - 1)}[/tex]
Calculate the product
[tex] \mathsf{ = {x}^{2} - x - 3x - 3 \times ( - 1)}[/tex]
Multiply the numbers
[tex] \mathsf{ = {x}^{2} - x - 3x + 3}[/tex]
Collect like terms
[tex] \mathsf{ = {x}^{2} - 4x + 3}[/tex]
Now, let's find the area of shaded region:
Area of large rectangle - Area of smaller rectangle
[tex] \mathsf{6 {x}^{2} + 24x + 24 - ( {x}^{2} - 4x + 3)}[/tex]
When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \mathsf{ = {6x}^{2} + 24x + 24 - {x}^{2} + 4x - 3}[/tex]
Collect like terms
[tex] \mathsf{ = {5x}^{2} + 28x + 21}[/tex]
Hope I helped!
Best regards!
The quadrilateral MNOP is a trapezoid. If MQ ≅ NR and m∠NMQ - 140° calculate m∠MNR.
Answer:
140 degrees.
Step-by-step explanation:
As MQ = NR and MNOP is a trapezoid MNRQ is an isosceles trapezoid.
So m<MNR = m < NMQ.
If each side of a cube is halved, its surface area will be __________________.
(a) halved (b) one-fourth (c) doubled (d) same
Answer:
b)
Step-by-step explanation:
Surface area of a cube = 6a² , here a is the side of cube
When side is halved, side = a/2
Now, the surface area of new cube = 6* (a/2)²
= [tex]6*\frac{a^{2}}{4}=\frac{1}{4}*6a^{2}\\[/tex]
= one fourth of the cube
PLEASE HELP!! DUE SOON
Answer:
b=3a/8
a=8b/3
Step-by-step explanation:
b/a=k ( k is the constant proportional)
3/8=9/24=15/40
b/a=3/8
b=3a/8
a=8b/3
I hope this is right answer
Which equation represents a linear function that has a slope of Four-fifths and a y-intercept of –6? y = negative 6 x + four-fifths y = four-fifths x minus 6 y = four-fifths x + 6 y = 6 x + four-fifths
Answer:
The answer is
[tex]y = \frac{4}{5} x - 6[/tex]
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
m / slope = 4/5
c / y intercept = - 6
Substituting the values into the above formula
We have the final answer as
[tex]y = \frac{4}{5} x - 6[/tex]
Hope this helps you
Answer:
the correct answer is C.
Step-by-step explanation:
i got it right on edge 2020
Find the value of x.
x = 64°
Step-by-step Explanation
x = 1/2[(360° - 2*58°)-2*58°]
x = 1/2[(360° - 2*58°) - 2*58°]
x = 1/2[(360° - 116°) - 116°]
x = 1/2[244° - 116°]
x = 1/2[128°]
x = 64°
if amir joins indian army, he is courageous.
convert this into contrapositive statement
If Amir is not courageous, then he will not join the indian army.
If a circle is dilated by a scale factor of
what will be the lenth of the new radius?
18m
12 m
9 m
36 m
27 m
Answer/Step-by-step explanation:
The scale factor is missing in the question. However, here's how to find the length of the new radius if given a known scale factor.
Length of new radius = length of the radius of the dilated circle × scale factor of dilation
Length of the radius of the dilated circle is given as 18m
Therefore,
Length of new radius = 18m × scale factor.
If the scale factor is a fraction, it means the new length would be smaller than 18m. But if the scale factor is a whole number, the new length of the radius would be greater than 18m.
Let's assume any of the following scale factors was what was given in the question:
*If scale factor given is ½, new radius length = 18m × ½ = 9m
*If scale factor given is 2, new radius length = 18m × 2 = 36m
pls help me do this (atleast one) using quadratic formula
Need help with this problem!
Answer:
1 Pound of Rock = .01 cubic feet
OR 100 pounds per cubic foot
A) Company needs 500,000 pounds of rock
Volume of Rock to be transported: = 500,000 * .01 =
5,000 cubic feet
B) Volume of each truck 12 * 9 * 8 = 864 cubic feet
C) Trucks needed for entire shipment:
= 5,000 / 864 = 5.78
So, we'll need 6 trucks.
Step-by-step explanation:
Help somebody please!!Thank you
The diagonal of the square is the same as the diameter of the circle.
So, the diameter of the circle is 36.
Circumference formula:
C = 2πr
To find the radius, we just need to divide the diameter by two:
36 / 2 = 18
Now, solve using the given values.
C = 2π(18)
C = 36π
Therefore, the answer is D.
Best of Luck!
A triangle has squares on its three sides as shown below. What is the value of x?
x cm
6 cm
8 cm
A) 2 centimeters
B) 6 centimeters
C) 8 centimeters
D) 10 centimeters
Answer:
D
Step-by-step explanation:
This is an illustration of Pythagoras' identity.
The square on the hypotenuse x of a right triangle is equal to the sum of the squares on the other 2 sides, that is
x² = 8² + 6² = 64 + 36 = 100 ( take the square root of both sides )
x = [tex]\sqrt{100}[/tex] = 10 cm → D
Answer:
D. 10 cm
The answer is 10 cm. This can be found through the use of Pythagorean. Theorem because it is a right triangle and you are finding the hypotenuse.
HOPE THSI HELPS
PLSSSSS MARK AS BRAINLIEST
THANK YOU..
Can someone help again please
Answer:
192km^2
Step-by-step explanation:
Well there are 5 surfaces
1) The back one
10km*6km=60km^2
2) the square
(6km)^2=36km^2
3) the two triangles
2(6km*8km/2)=48km^2
4) the front one
6km*8km=48km^2
add all up and get
192km^2
Answer: 192 square kilometers
Step-by-step explanation:
Two triangular Sides A=bh/2 8×6/2=24
So add two of them. : 48
Back side 10 × 6 = 60
Top 6×6=36
Front 6×8=48
Total: 48+60+36+48=192
Chen is baking muffins and banana bread for a brunch buffet. He needs 3 and one-fifth cups of flour to make the muffins and 3 and two-thirds cups of flour to make the banana bread. Which is the best estimate of the number of cups of flour that Chen needs to bake both recipes?Chen is baking muffins and banana bread for a brunch buffet. He needs 3 and one-fifth cups of flour to make the muffins and 3 and two-thirds cups of flour to make the banana bread. Which is the best estimate of the number of cups of flour that Chen needs to bake both recipes? A. 6 cups B. 7 cups C. 8 cups D. 9 cups
Answer:
hi:) If chen needed 3 1/5 and 3 2/3, the answer should be 7. 7 cups. i hope this is right but feel free to correct me if im wrong.
B. 7 cups
The best estimate of the number of cups of flour that Chen needs to bake both recipes is 7cups.
What is the fraction?A fraction is a number which has numerator and denominator.Number of cups used to make muffins = 3 1/5
Estimation = 3 cups
Number of cups used to make banana bread = 3 2/3
Estimation = 4 cups
Number of cups of flour needs to bake both recipes = Estimated number of cups used to make muffins + Estimated number of cups used to make banana bread
= 3 + 4 cups
= 7 cups.
The best estimate of the number of cups of flour that Chen needs to bake both recipes is 7cups.
Learn more about fraction here:
https://brainly.com/question/78672
#SPJ2
Write an expression for the cost of 1 uniform, add $13, $11 and $8 .
Answer:
Hey there!
Let the cost of one uniform be c, so the expression becomes
c+13+11+18
Thus, we have c+42
Hope this helps :)
Answer:
32
Step-by-step explanation:
13+11+8=32
In 1819, the United States purchased Florida from Spain for
$5 X 106. The area of Florida is about 6.6 x 104 square miles.
Which key strokes on a calculator will give the cost the
United States paid for each square mile of Florida?
Answer:
Option D. 5 EE 6 ÷ 6.6 EE 4
Step-by-step explanation:
Data obtained from the question include the following:
Area of land purchased = 6.6×10^4 square miles
Cost = $ 5×10^6
To determine the key strokes on a calculator which will give the cost the
United States paid for each square mile of Florida, let us calculate cost of 1 square mile.
This can be obtained as follow:
6.6×10^4 sq mile = $ 5×10^6
Therefore,
1 sq mile = $ 5×10^6 ÷ 6.6×10^4
In calculator, the key strokes will be:
5 EE 6 ÷ 6.6 EE 4
Answer:
Like Eduard22sly said D). 5 EE 6 ÷ 6.6 EE 4 is correct.
plus i took the test 100% :)
What is the vertex on the graph of the absolute-value parent function?
Answer:
The highest or the lowest point on the graph is the vertex of an absolute-value function!
Step-by-step explanation:
Select the correct answer.
Write (21 − 4i) − (16 + 7i) + 28i as a complex number in standard form.
A.
5 + 39i
B.
5 + 17i
C.
5 − 39i
D.
5 − 17i
Answer:
B) 5 + 17i is your answer.
Step-by-step explanation:
In order to write this equation as a complex number in standard form, you must first simplify each term.
Apple the distributive property.
21 - 4i - 1 * 16 - (7i) + 28i
Multiply -1 by 16.
21 - 4i -16 - (7i) + 28i
Multiply 7 by -1.
21 - 4i - 16 - 7i + 28i
Now simplify by adding terms :)
Subtract 16 from 21.
5 - 4i - 7i + 28i
Subtract 7i from -4i.
5 - 11i + 28i
Add -11i and 28i.
= 5 + 17i
check 3 is a zero of the polynomial p(x)= 3x2-27
Answer:
see explanation
Step-by-step explanation:
If x = 3 is a zero then p(3) = 0 , that is
p(3) = 3(3)² - 27 = 3(9) - 27 = 27 - 27 = 0
Thus x = 3 is a zero of p(x)
Answer:
Step-by-step explanation:
p(x) = 3x² - 27
p(3) = 3*3² - 27
= 3 * 9 - 27
= 27 - 27
= 0
p(3) =0 . Therefore, 3 is z zero of p(x)
Which equation is represented by the intersection of the graphs below? a. cosx=-1 b.secx=-1 c. cscx=-1 d.tanx=-1
Answer:
Option D.
Step-by-step explanation:
From the given it is clear that the horizontal line intersect the y-axis at -1. So, the equation of horizontal line is y=-1.
The curves represent the graph of [tex]y=\tan x[/tex].
We need to find the equation which is represented by the intersection of the graphs.
We have two equations one is for curve and another for horizontal line.
[tex]y=\tan x[/tex]
[tex]y=-1[/tex]
Equate both equations to get the equation which is represented by the intersection of the graphs.
[tex]\tan x =-1[/tex]
Therefore, the correct option is D.
Please answer this ASAP. The question is down below. Thank you!
Answer:
[tex]y = .5x^2 -2x -5[/tex]
Step-by-step explanation:
Well we can start by seeing if the parabola is the same width by comparing it to its parent function ( y = x^2 )
In y = x^2 the 2nd lowest point is just up 1 and right 1 away from the vertex.
This is not true for our parabola.
So we can widen it by to the desidered width by making the x^2 into a .5x^2.
So far we’ve got y = .5x^2
Now the parabola y intercept is at -5.
So we can add a -5 into the equation making it.
y = .5x^2 - 5
Now for the x value.
So we can find the x value by seeing how far away the parabola is from from the y axis.
So the x value is -2x.
So the full equation is [tex]y = .5x^2 -2x -5[/tex]
Look at the image below to compare.
Answer: [tex]Vertex: y=\dfrac{1}{2}(x-2)^2-7[/tex]
[tex]Standard: y=\dfrac{1}{2}x^2-2x-5[/tex]
Transformations: vertical shrink by a factor of 1/2,
horizontal shift 2 units to the right,
vertical shift 7 units down.
Step-by-step explanation:
Vertex form: y = a(x - h)² + k
Standard form: y = ax² + bx + c
Given: Vertex (h, k) = (2, -7), the y-intercept (0, c) = (0, -5)
Input those values into the Vertex form to solve for the a-value
-5=a(0 - 2)² - 7
2 = a(- 2)²
2 = 4a
[tex]\dfrac{1}{2}=a[/tex]
a) Input a = 1/2 and (h, k) = (2, -7) into the Vertex form
[tex]\large\boxed{y=\dfrac{1}{2}(x-2)^2-7}[/tex]
b) You can plug in a = 1/2, c = -5, (x, y) = (2, -7) to solve for "b"
or
You can expand the Vertex form (which is what I am going to do):
[tex]y=\dfrac{1}{2}(x-2)^2-7\\\\\\y=\dfrac{1}{2}(x^2-4x+4)-7\\\\\\y=\dfrac{1}{2}x^2-2x+2-7\\\\\\\large\boxed{y=\dfrac{1}{2}x^2-2x-5}[/tex]
c) Use the Vertex form to describe the transformations as follows:
a is the vertical stretch (if |a| > 1) or shrink (if |a| < 1)h is the horizontal shift (positive is to the right, negative is to the left)k is the vertical shift (positive is up, negative is down)[tex]y=\dfrac{1}{2}(x-2)^2-7[/tex]
a = 1/2 --> vertical shrink by a factor of 1/2
h = 2 --> horizontal shift 2 units to the right
k = -7 --> vertical shift 7 units down
Two numbers are 10 units away in different directions
from their midpoint, m, on a number line. The product of
the numbers is -99.
Which equation can be used to find m, the midpoint of
the two numbers?
(m - 5)(m + 5) = 99
0 (m - 10)(m + 10) = 99
Om2 - 25 = -99
om? - 100 = -99
Will give brainliest
Answer:
m² - 100 = -99
Step-by-step explanation:
Two numbers are 10 units away from the midpoint m in different directions.
So, one number is (m + 10 ) away form 'm' and another is ( m + 10) away from 'm' in opposite direction.
(m + 10) ( m-10) = -99
m² - 10² = -99
m² - 100 = -99
In circle O, MP is a diameter. Circle O is shown. Line segment M P is a diameter. Line segment N O is a radius. If mArc N P is 6 more than 5 times the measure of Arc M N , what is mArc N P ? 139° 145° 151° 174°
Answer:
m arc NP = 151°
Step-by-step explanation:
m arc MN = x
m arc NP = y
5x + 6 = y
x + y = 180, I will solve with substitution
x + (5x + 6) = 180
6x + 6 = 180
6x = 174
x = 29
y = 151
Answer:
151 or c
Step-by-step explanation:
7
A section of a rectangle is shaded.
The area of the shaded section is 63 square units. What
is the value of x?
7
х
9 units
11 units
O 18 units
21 units
This question is incomplete. Please find attached to this solved question, the diagram required to solve this question.
Answer:
11 units
Step-by-step explanation:
The shaded portion of the rectangle forms the shape of a trapezium
The area of a trapezium = 1/2(a + b)h
From the diagram, we can see than x = b
a = 7 units
b = 7 units
Area of the trapezium = Area of the shaded portion = 63 square units
A = 1/2(a + b)h
63 = 1/2(7 + b)7
63 = 1/2(49 + 7b)
63 × 2 = 49 + 7b
126 - 49 = 7b
7b = 77
b = 77/7
b = 11 units
Since x = b, x = 11 units
The value of x is 11
Start by calculating the area (A) of the trapezoid using
[tex]A= 0.5 * (a + b)h[/tex]
Using the parameters from the complete question, we have:
[tex]63 = 0.5 * (7 + x) * 7[/tex]
Multiply both sides by 2
[tex]126 = (7 + x) * 7[/tex]
Divide both sides by 7
[tex]18 = 7 + x[/tex]
Subtract 7 from both sides
[tex]x = 11[/tex]
Hence, the value of x is 11
Read more about shaded areas at:
https://brainly.com/question/24579466
trigonometry plz... helllppp thx
Answer:
90°
I think.
Step-by-step explanation:
Cause... As you see it's a right angle triangle... And also when you ad 6+15 u get 90...
I
If one plane is flying at 40mph. While another is flying at 100mph. They are 200 miles apart, how long will it take them to collide if they are going in the same direction
Answer:
1 and 3/7 hour
Step-by-step explanation:
Every hour they get 140 miles closer (100 + 40). So you divide 200 by 140 which gets you 1.42... or 1 and 3/7 of an hour.
Which of the following equations is of a parabola with a vertex at (0, 3)?
Оy (x-3) 2
Оун (х+3) 2
Оy 2-3
о у х2 + 3
Answer:
Step-by-step explanation:
y=x²+3
vetex=(h,k) in the equation : ax²+bx+c
y=x²+3 ( a=1,b=0,c=0)
h=-b/2a=0
k=c=3
Efren is constructing a line parallel to EF¯¯¯¯¯ through point G. What step should be his next step? With the compass point on D, construct an arc that intersects EF¯¯¯¯¯ and GD←→ . With the compass point on G, construct an arc that intersects GD←→ . With the compass point on D, construct an arc that intersects EF¯¯¯¯¯ twice. With the compass point on G, construct an arc that intersects EF¯¯¯¯¯ .
Answer:
The correct option is;
With the compass point on G, construct an arc that intersect GD←→
Step-by-step explanation:
The steps for constructing a parallel line to a given point is as follows;
1) With the straightedge, a transversal is drawn intersecting the giving line and passing through point G
2) Copy the angle formed between the transversal and the given line and the to the point G starting by constructing an arc with the compass on point G to intersect GD←→ then with the compass opening still the same, place the compass on the point of intersection of the arc constructed from point G on GD and construct another arc to intersect the arc previous arc from G to GD
3) The line drawn from the intersection through is a parallel line to EF
Therefore, the correct option is that with the compass point on G, construct an arc that intersect GD←→.
Answer:
A. With the compass on point D , construct an arc that intersects EF¯¯¯¯¯ and GD←→.
Step-by-step explanation:
I just took the test!