A random sample of 64 cars traveling on a section of an interstatewed an average speed of 66 mph. The distribution of speeds of all cars on this section of highway is normally distributed with a standard deviatior9.5 mph.The 75.8% confidence interval for is (Round your answer to 3 deci-Places)

4 more students have 2 or 3 siblings than 4 or 5 siblings in Austin's swim class.

To determine how many more students have 2 or 3 siblings than 4 or 5 siblings in Austin's swim class, we'll count the number of responses for each category.

Step 1: Count the number of students with 2 or 3 siblings.

Responses: 2 students, 2 students, 8 students, 8 students, 9 students, 9 students

There are 6 students with 2 or 3 siblings.

Step 2: Count the number of students with 4 or 5 siblings.

Responses: 11 students, 11 students

There are 2 students with 4 or 5 siblings.

Step 3: Subtract the number of students with 4 or 5 siblings from the number of students with 2 or 3 siblings.

6 students (2 or 3 siblings) - 2 students (4 or 5 siblings) = 4 students

So, 4 more students have 2 or 3 siblings than 4 or 5 siblings in Austin's swim class.

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If a between-subjects design uses random assignment, the design will be called an independent groups design.

This means that participants are randomly assigned to either the experimental or control group, ensuring that the groups are equivalent at the start of the study. This type of design allows for a comparison of the effects of the independent variable on the dependent variable between the groups. I

t is important to note that an independent groups design is different from a matched groups design, in which participants are paired based on certain characteristics before being assigned to different groups. The use of random assignment in an independent groups design helps to control for extraneous variables and increase the internal validity of the study.

If a between-subjects design uses random assignment, the design will be called a(n) c. independent groups design. This design involves assigning participants to different experimental groups or conditions using random allocation. This ensures that each participant has an equal chance of being assigned to any group, reducing potential confounds and increasing the validity of the results. The independent groups design allows for comparison between the groups and the examination of the effects of the independent variable on the dependent variable.

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The coordinates for a similar triangle DEF by dilating triangle ABC with respect to the origin using a scale factor of √5/2.

In this case, we can choose any point as the center of dilation, but for simplicity, let's choose the origin (0,0). This means that we will stretch or shrink triangle ABC with respect to the origin.

This point has coordinates (2s, s), where s is the scale factor. To see why, consider that the distance from the origin to the point (2s, s) is given by the Pythagorean theorem as:

√((2s)² + s²) = s√5

This distance should be 2 times the scale factor, so we have:

s√5 = 2s

Solving for s, we get:

s = √5/2

Therefore, the corresponding side of triangle DEF is the line passing through (0,0) and (2√5, √5). Similarly, we can find the corresponding sides for the other two sides of triangle ABC to get the complete set of coordinates for triangle DEF.

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The sine, cosine and tangent of angle A are given as follows:

For an angle [tex]\theta[/tex] the unit circle is a circle with radius 1 containing the following set of points:

[tex](\cos{\theta}, \sin{\theta})[/tex].

Considering the x and y-coordinates of the point, the sine and the cosine are given as follows:

The tangent is given by the division of the sine by the cosine, hence:

[tex]\tan{A} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}[/tex]

[tex]\tan{A} = \frac{1}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}[/tex]

[tex]\tan{A} = \frac{\sqrt{3}}{3}[/tex]

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Using the sum of a geometric series we can say that the sum of the series that has this repeating decimal 12/5.

Let us first define a geometric sequence before learning the geometric sum formula. A geometric sequence is one in which each phrase has a constant ratio to the word before it. A geometric sequence with a finite number of terms with the initial term a and the common ratio r is often expressed as a, ar, ar2,..., arn-1. A geometric sum is the sum of the geometric sequence's terms.

The geometric sum formula is the formula for calculating the sum of all the terms in a geometric sequence. There are two geometric sum formulae. The first is used to calculate the sum of the first n terms of a geometric sequence, while the second is used to calculate the sum of an infinite geometric sequence.

[tex]\sum \frac{\theta(-2)^n-6^n}{\theta^n} =\sum(\frac{\theta(-2)^n}{\theta^n} -\frac{6^n}{\theta^n} )[/tex]

= [tex]\sum \frac{(\theta(-2)^n-6^n}{\theta^n} {\theta^n} )[/tex]

= [tex]\sum (\theta(\frac{-1}{4} )^n)-\sum(\frac{3}{4} )^n[/tex]

=[tex]\theta (\frac{1}{\frac{5}{4} } )-(\frac{1}{\frac{1}{4} } )[/tex]

= [tex]\theta(\frac{4}{5} )[/tex]

= 32/5 - 4 = 32-20/5 = 12/5

Therefore,

[tex]\sum \frac{\theta(-2)^n-6^n}{\theta^n}[/tex] = 12/5.

Therefore, the sum is given as 12/5.

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The value of m∠ABC is 46°.

We know that BC bisects ∠ABD. Therefore, m∠CBD = m∠ABD  = 23° *4 = 92°.

We also know that BE bisects ∠CBD.

Therefore, m∠EBD = m∠EBC + m∠CBD. Since we know that m∠EBD = 23°

and m∠CBD = 2*m∠EBD = 46°,

we can solve for m∠EBC:

23° = m∠EBC°

m∠EBC = 23°

Now we can find m∠ABC:

m∠ABC = m∠ABD - m∠CBD = 92° - 46° = 46°

Therefore, m∠ABC is 46°.

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Answer:

1.05^7 = 1.407

Every week, the mass of the starfish increases by about 40.7%, or by a factor of about 1.41.

Answer:

-2.41

Step-by-step explanation:

rearrange:

12x + 10 + 5x + 31

Or

12x + 5x + 10 + 31

Simplify and set that is = to zero so we can isolate x

17x + 41 = 0

To solve for x, we can isolate x on one side of the equation by subtracting 41 from both sides:

17x = -41

Finally, we can solve for x by dividing both sides by 17:

x = -41/17

therefore, x is equal to approximately -2.41 when we plug it back into the original equation:

12x + 10 + 5x + 31 = 0

12(-2.41) + 10 + 5(-2.41) + 31 = 0

-28.92 + 10 - 12.05 + 31 = 0

0 (which is true)

The area of trapezoid ABCD is 18.5 square units.

To find the area of trapezoid ABCD, we need to use the formula for the area of a trapezoid which is: Area = (sum of the bases/2) x height. Since AB and CD are parallel, we can consider them as the two bases of the trapezoid. Let's denote the length of AB as a and the length of CD as b.

We know that the area of 4PAB is 16 square units, which means that the height of the trapezoid from point P to AB is 4 units. Similarly, we know that the area of 4PCD is 25 square units, which means that the height of the trapezoid from point P to CD is 5 units.

Now, let's consider the diagonals AC and BD. Since P is the intersection of these diagonals, we can divide the trapezoid into two triangles: APB and CPD. The sum of the areas of these two triangles is equal to the area of the trapezoid. We can use the formula for the area of a triangle which is: Area = (base x height)/2.

The base of triangle APB is a and its height is 4. Therefore, the area of APB is (a x 4)/2 = 2a. The base of triangle CPD is b and its height is 5. Therefore, the area of CPD is (b x 5)/2 = 2.5b.

The sum of the areas of APB and CPD is 2a + 2.5b = 2(a + 1.25b). This is equal to the area of the trapezoid since the sum of the areas of the two triangles is equal to the area of the trapezoid.

Therefore, the area of trapezoid ABCD is 2(a + 1.25b). Substituting the given values, we get:

Area = 2(a + 1.25b)
Area = 2(AB + 1.25CD)
Area = 2(a + 1.25b) = 2(4 + 1.25(5)) = 18.5 square units

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a) The beekeeper would maintain 5 hives if operating independently.

b) The  socially efficient number of hives is given by: H = 5/12.

c) In the absence of transaction costs, we would expect the beekeeper and the farmer to negotiate a price for pollination that would make both parties better off.

d) The gains from trade would be erased by transaction costs of $50 per acre.

a) To determine the beekeeper's profit-maximizing number of hives, we need to set the marginal cost equal to the marginal revenue. Since each hive yields $20 worth of honey, the marginal revenue is $20. Thus, we need to solve the following equation for H:

MC = MR

10 + 2H = 20

2H = 10

H = 5

Therefore, the beekeeper would maintain 5 hives if operating independently.

b) The socially efficient number of hives would be the number that equates the social cost of pollination to the social benefit. The social cost includes the beekeeper's marginal cost plus the cost of pollination, which is $10 per acre. The social benefit is the additional revenue the farmer earns from the pollination. Assuming that each acre of orchard produces $100 worth of apples with the bees, and that without bees the yield is reduced by 50%, the social benefit of pollination is $50 per acre.

Thus, the socially efficient number of hives is given by:

10 + 2H + 10 = 50H

20 = 48H

H = 5/12.

Since a fraction of a hive is not practical, we can round up to 1 hive, which is the socially efficient number.

c) In the absence of transaction costs, we would expect the beekeeper and the farmer to negotiate a price for pollination that would make both parties better off. Assuming that the farmer's willingness to pay for pollination is $50 per acre, the beekeeper could charge any amount between $10 and $50 per acre and both parties would be better off.

For example, if the beekeeper charged $30 per acre, the farmer would pay $30 for pollination and earn an additional $20 per acre in apple revenue, while the beekeeper would earn $20 per hive in honey revenue.

d) The gains from bargaining would be erased if the transaction costs were equal to the gains from trade. In this case, the gains from trade are the additional revenue the farmer earns from pollination, which is $50 per acre. If the transaction costs were also $50 per acre, then the farmer would have to pay $100 per acre for pollination, which is equal to the additional revenue. Thus, the gains from trade would be erased by transaction costs of $50 per acre.

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The missing value in the P-value column is approximately 0.009 (assuming a two-tailed test) or 0.005 (assuming a one-tailed test).

Here's the complete MINITAB output based on the given information:

Predictor Constant X

Coef 0.18917 (a)

SE Coef 0.43309 0.065729

t-value 0.437 (c)

P-value 0.667 (b)

S = 0.67580

R-Sq = 31.0%

The missing information that needs to be recomputed is:

The missing value in the t-value column (marked as (c)).

The missing value in the P-value column (marked as (b)).

To compute the missing t-value, we can use the formula:

t-value = Coef / SE Coef

For X, we have:

t-value = 0.18917 / 0.065729 ≈ 2.876

So the missing value in the t-value column is approximately 2.876.

To compute the missing P-value, we can use the fact that P-value is the probability of getting a t-value as extreme or more extreme than the observed one, assuming the null hypothesis is true. In other words, P-value is the area under the t-distribution curve to the right or left of the observed t-value (depending on whether the test is one-tailed or two-tailed).

Since we don't know the direction of the test, we cannot compute the exact P-value. However, we can make an educated guess based on the t-value and the degrees of freedom (df) of the test. Since there are n=20 points in the data set and we are estimating two parameters (intercept and slope), the df of the test is n-2=18.

Assuming a two-tailed test, the P-value for a t-value of 2.876 and df=18 is approximately 0.009. If the test is one-tailed, the P-value would be approximately 0.005 (half of 0.009).

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To calculate the wavelength λ1 for gamma rays of frequency f1 = 5.60×1021 hz, we can use the formula:
λ1 = c / f1, where c is the speed of light in a vacuum, which is approximately 3.00 × 108 m/s.
Plugging in the values, we get:
λ1 = (3.00 × 108 m/s) / (5.60×1021 hz) = 5.36 × 10^-14 m

Therefore, the wavelength λ1 for gamma rays of frequency f1 = 5.60×1021 hz is approximately 5.36 × 10^-14 meters.
To calculate the wavelength λ1 of gamma rays with frequency f1 = 5.60×10²¹ Hz, we can use the formula:

λ = c / f

Where λ is the wavelength, c is the speed of light (approximately 3.00×10^8 meters per second), and f is the frequency.

Step 1: Write down the given frequency:
f1 = 5.60×10²¹ Hz

Step 2: Write down the speed of light:
c = 3.00×10^8 m/s

Step 3: Use the formula to calculate the wavelength:
λ1 = c / f1
λ1 = (3.00×10^8 m/s) / (5.60×10²¹ Hz)

Step 4: Calculate λ1:
λ1 ≈ 5.36×10^-14 meters

So, the wavelength λ1 for gamma rays of frequency f1 = 5.60×10²¹ Hz is approximately 5.36×10^-14 meters.

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The linear approximation to the function at the point (x, y, z) = (1, -2,0) is: L(x,y,z) = y - 4x + 4z + 4

The linear approximation to a function is essentially an approximation of the function in the vicinity of a given point using a tangent plane. This approximation is valid for small values of x, y, and z, and can be useful in many applications where precise values of the function are not necessary.

To find the linear approximation to the function at the point (x, y, z) = (1, -2,0), we need to first find the partial derivatives of the function with respect to x, y, and z. Let's assume that the function is denoted by f(x, y, z). Then, the partial derivatives can be calculated as follows:

fx(x, y, z) = 2xy - z
fy(x, y, z) = x^2 + 2z
fz(x, y, z) = -2xy

Now, we need to use these partial derivatives to find the equation of the tangent plane to the function at the point (1, -2, 0). The equation of the tangent plane can be given by:

f(x, y, z) ≈ f(1, -2, 0) + fx(1, -2, 0)(x-1) + fy(1, -2, 0)(y+2) + fz(1, -2, 0)(z-0)

Plugging in the values of the partial derivatives and the given point, we get:

f(x, y, z) ≈ -4 + (-4)(x-1) + 1(y+2) + 4(z-0)

Simplifying this equation, we get:

f(x, y, z) ≈ -4 - 4x + y + 4z + 8

f(x, y, z) ≈ y - 4x + 4z + 4

Consequently, L(x,y,z) = y - 4x + 4z + 4 is the linear approximation to the function at the point (x, y, z) = (1, -2, 0).

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a) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = f(n-1) for n ≥ 1. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 1, which is true.

Inductive step: Assume that f(k) = f(k-1) for some k ≥ 1. Then f(k+1) = f(k) = f(k-1) = f(k+1-1), which is true.

Therefore, the formula is valid.

b) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = 2f(n-3) for n ≥ 3. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 1, f(1) = 0, f(2) = 2, which are all true.

Inductive step: Assume that f(k) = 2f(k-3) for some k ≥ 3. Then f(k+1) = 2f(k+1-3) = 2f(k-2) = 2(2f(k-3)) = 2f(k), which is true.

Therefore, the formula is valid.

c) This is not a valid recursive definition of a function f from the set of nonnegative integers to the set of integers because the recursive step does not define f(n) for all n ≥ 0.

d) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = 2f(n-1) for n ≥ 1. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 0, f(1) = 1, which are both true.

Inductive step: Assume that f(k) = 2f(k-1) for some k ≥ 1. Then f(k+1) = 2f(k+1-1) = 2f(k) = 2(2f(k-1)) = 2f(k+1-1), which is true.

Therefore, the formula is valid.

e) This is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n) is f(n) = f(n-1) if n is odd and n ≥1 and f(n) = 2f(n-2) if n≥ 2. To prove that this formula is valid, we can use mathematical induction.

Base case: f(0) = 2, which is true.

Inductive step: Assume that f(k) = f(k-1) if k is odd and k ≥ 1 and f(k) = 2f(k-2) if k ≥ 2.

If k is odd, then f(k+1) = f(k) = f(k-1) = f(k+1-1), which is true.

If k is even, then f(k+1) = 2f(k+1-2) = 2f(k) = 2(2f(k-2)) = 2f(k+1-2), which is true.

Therefore, the formula is valid.

a) The formula for f(n) is (-1)ⁿ and b) The formula for f(n) is f(n) = 2k.

a) The proposed definition of function f is a valid recursive definition as it defines f(0) as 1 and then uses the previous value of f(n-1) to determine the value of f(n) for all n greater than or equal to 1. To find the formula for f(n), we can use induction. We can see that f(1) = -f(0) = -1, f(2) = -f(1) = 1, f(3) = -f(2) = -1, and so on. Thus, we can see that f(n) alternates between 1 and -1, depending on whether n is odd or even. Therefore, the formula for f(n) is (-1)ⁿ.

b) The proposed definition of function f is also a valid recursive definition as it defines f(0), f(1), and f(2), and then uses the previous value of f(n-3) to determine the value of f(n) for all n greater than or equal to 3. To find the formula for f(n), we can again use induction. We can see that f(3) = 2f(0) = 2, f(4) = 2f(1) = 0, f(5) = 2f(2) = 4, f(6) = 2f(3) = 4, f(7) = 2f(4) = 0, and so on.

Thus, we can see that f(n) alternates between 0 and 2, depending on whether n is congruent to 1 or 2 mod 3. Therefore, the formula for f(n) is f(n) = 2k, where k is the number of times n-3 can be divided by 3 before reaching a number less than or equal to 2. This formula is valid as it agrees with our observations and satisfies the recursive definition.

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The coordinate vector of p(t) = 1 + 3t + 6t^2 relative to the basis B = {1 + 2t, t + 2t^2} is [p(t)]_B = (1, 1).

The coordinate vector of p(t) = 1 + 3t + 6t^2 relative to the basis B = {1 + 2t, t + 2t^2}, we need to express p(t) as a linear combination of the basis vectors.

Step 1: Write p(t) as a linear combination of the basis vectors.
p(t) = c1(1 + 2t) + c2(t + 2t^2)

Step 2: Equate the coefficients of the terms in p(t) to the coefficients in the linear combination.
1 = c1
3 = 2c1 + c2
6 = 2c2

Step 3: Solve the system of equations for c1 and c2.
From the first equation, we know that c1 = 1.
Now substitute c1 into the second equation:
3 = 2(1) + c2
c2 = 1

Step 4: Substitute c2 into the third equation:
6 = 2(1)
This confirms that our values for c1 and c2 are correct.

Step 5: Write the coordinate vector with the coefficients c1 and c2.
[p(t)]_B = (c1, c2) = (1, 1)

In conclusion, the coordinate vector of p(t) = 1 + 3t + 6t^2 relative to the basis B = {1 + 2t, t + 2t^2} is [p(t)]_B = (1, 1).

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The value of the expression 4(x + 3) - 2y when x=-6 and y=-1 is -10

From the question, we have the following parameters that can be used in our computation:

4(x + 3) - 2y

Given that

x = -6 and y = -1

Substitute the known values in the above equation, so, we have the following representation

4(x + 3) - 2y = 4(-6 + 3) - 2(-1)

Evaluate the expression

4(x + 3) - 2y = -10

Hence, the solution is -10

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The equation to find the full price where p is the full price of hotel room per night is 7p - 280 = 5p if the cost of 7 nights of hotel with discount of $280 is equal to the cost of 5 nights of hotel stay. The full price of hotel per night is $140.

In the given situation, full price for 5 nights is equal to 7 night of hotel stay with a discount of $280. Thus if the p is the price of full night then the equation is:

7p - 280 = 5p

7p - 5p = 280

2p = 280

p = $140

The cost of the $140 is the full price of hotel room per night.

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The correct answer for the given question is c. decision variable. Decision variables are controllable inputs for a linear programming model that can be set by the decision-maker to achieve the desired objective.

They represent the quantities to be determined and optimized in a linear programming problem. In contrast, parameters are fixed values that influence the constraints and objective function of the model, and dummy variables are artificial variables introduced to handle non-negativity constraints or binary variables. Constraints, on the other hand, are restrictions on the decision variables that must be satisfied to meet the problem's requirements. Therefore, decision variables are the most critical and controllable elements of a linear programming model that determine the optimal solution.

In a linear programming model, a controllable input is known as a decision variable. Decision variables represent the quantities that can be manipulated to optimize the objective function while satisfying the constraints. They are the primary focus of the optimization process. Parameters, on the other hand, are fixed values or coefficients. Dummy variables are used to represent categorical data in a numerical form, and constraints represent the limits or restrictions within which the decision variables must operate. So, the correct answer is c. decision variable.

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The age of new player is 34 years.

Given that, a new player joins the team and raises the mean age to 22.

From the given table,

Mean = (19×2+20×3+21×1+22×4+23×1)/(2+3+1+4+1)

= 230/11

= 20.9

A new player joins the team and raises the mean age to 22.

Let the age of new player be x

Now, new mean = (230+x)/(11+1)

(230+x)/12 =22

230+x=264

x=34

Therefore, the age of new player is 34 years.

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The domain at which the function is decreasing is (-∞, -5).

We have,

From the graph,

We see that there are two parts to the function:

Increasing and decreasing part.

Now,

The y-values are the function and the x-values are the domains.

So,

The function is decreasing from -∞ to x = -5 and increasing from x = -5 to ∞.

Thus,

The domain at which the function is decreasing is (-∞, -5).

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The statements that accurately characterize a uniform distribution are Areas within the distribution represent probabilities and The area inside the rectangle (i.e the frequency polygon) must be one.



1. In a uniform distribution, the probability of an event occurring within a certain range is proportional to the size of that range. This means that the area under the curve of the distribution within a certain range represents the probability of an event occurring within that range.

2. The area inside the rectangle (i.e the frequency polygon) must be one because the total probability of all possible events within the distribution must be equal to one.

The other statements are not accurate for a uniform distribution because:

- The mean and median of a uniform distribution are the same, so the statement "the mean is different from the median of the distribution" is false.
- The height of a uniform distribution is constant, so the statement "the height of the distribution changes depending on the value of x" is also false.

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Answer: 200

Step-by-step explanation:

1 Canadian dollar  buys 82c in US

1 dollar = 100c

=> 100 c  Canadian  =    82c in US

=> 100 Canadian dollar  buys 82 dollar  in US

Canadian dollar required to buy 82 dollar  in US    = 100

=> Canadian dollar required to buy 1 dollar  in US    = 100/82

=> Canadian dollar required to buy 164 dollar  in US  = 164 x 100/ 82

= 2  x 100

= 200 $

cost 200 in Canadian dollars   to buy a Walkman advertised for $164.00 in the USA

1/4 is the scale factor of dilation

Dilation is a transformation, which is used to resize the object.

Dilation is used to make the objects larger or smaller.

Scale Factor is defined as the ratio of the size of the new image to the size of the old image.

Let us consider L and L' coordinates to find scale factor

L has coordinates (-8, 8)

If we multiply the x and y coordinates with 1/4 we get (-2, 2)

Hence, 1/4 is the scale factor of dilation

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The investment of each brother is $21,000, $14,000, and $14,000 if they are in the ratio 3 : 2 : 2 and they all are investing a total of $49,000.

As the brother invest in the ratio of 3 : 2 : 2 then,

Let the investment of the first brother be 3x

the investment of the second brother be 2x

the investment of the third brother be 2x

Total investment = 3x + 2x + 2x

= 7x

Thus, the fraction of investment of the first brother = [tex]\frac{3x}{7x}[/tex]

The fraction of the investment of the second brother = [tex]\frac{2x}{7x}[/tex]

The fraction of the investment of the third brother = [tex]\frac{2x}{7x}[/tex]

Hence, the investment of the first brother = [tex]\frac{3x}{7x}[/tex] * 49000 = $21,000

The investment of the second brother = [tex]\frac{2x}{7x}[/tex] * 49000 = $14,000

The investment of the third brother = [tex]\frac{2x}{7x}[/tex] * 49000 = $14,000

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The volume of the box is V  21,168 in³.

Let x be the length of each side of the square base, and let y be the height of the box. Then, according to the problem statement, we have the following constraints:

The sum of the length, width, and height is not exceeding 132 in: x + x + y ≤ 132, or simply 2x + y ≤ 132.

The volume of the box is V = x²y.

To find the dimensions and volume of the box with the greatest volume, we can use the method of Lagrange multipliers. Let L(x, y, λ) = x²y + λ(132 - 2x - y) be the Lagrangian function. Then, we need to solve the following system of equations:

∂L/∂x = 2xy - 2λ = 0

∂L/∂y = x² - λ = 0

∂L/∂λ = 132 - 2x - y = 0

From the first equation, we get y = λ/x. Substituting into the second equation, we get x⁴ = λ². Substituting into the third equation, we get λ = 132/(2 + x). Substituting these expressions back into the first equation, we get:

2x(132/(2 + x)) = λ = x²(132/(2 + x)²)

Simplifying, we get:

264x = x²(2 + x)

x³ - 264x + 2x² = 0

x(x² - 264 + 2x) = 0

The solution x = 22 is the only positive real root of this equation. Thus, the dimensions of the box with the greatest volume are x = 22 in and y = 44 in. The volume of the box is V = x²y = 22² × 44 = 21,168 in³.

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The kilometers the bus travels between these two stops would be; 5.8 km

Thus we have the following parameters that can be used in our computation:

Speed = 23 km/h

Time = 13 : 40 - 13 : 25 = 15 minutes = 1/4 hr

The kilometers the bus travels between these two stops ;

Distance = Speed * Time

Substitute the known values in the equation, so, we have the following representation

Distance = 23 * 1/4

Evaluate;

Distance = 5.8 km

Hence, the distance is 5.8 km

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The type of triangle is a Right isosceles triangle.

An isosceles triangle is a type of triangle with two angles equal and corresponding sides equal. A right angle triangle is a type of triangle in which one if it's sides is exactly 90°.

Therefore an Isosceles Right Triangle is a right triangle that consists of two equal length legs.

This means one side must be 90° and the other two angles must be equal.

Therefore the value of the other two angles =

2x +90 = 180

2x = 180-90

2x = 90

x = 90/2

x = 45°

therefore each side will be 45°

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Answer:

There is no value of x and y.

Step-by-step explanation:

To solve the equation 2y + 7x = -5 for y and x, we can use the following steps:

1.

Isolate y on one side of the equation by subtracting 7x from both sides:

2y = -7x - 5

2.

Divide both sides by 2 to get y by itself:

y = (-7/2)x - (5/2)

3.

To find x, we can substitute the value of y we just found into the original equation:

2(-7/2)x + 7x = -5

4.

Simplify and solve for x:

-7x + 7x = -5

0 = -5

Since this equation has no solution, there is no value of x and y that will satisfy it.

Answer:

y = (a/x) - (h/x) + k

Characteristics of the function:

y is in terms of x

y has a denominator of x

The function is an inverse function of y = (a/x) + (h/x) + k

The graph of the function is a mirror image of the graph of y = (a/x) + (h/x) + k

The graph of the function changes orientation when it crosses the y-axis

To transform the graph of y = 1/x into the graph of y = 2-6x/x-5, we can use the following steps:

1.Reflect the graph about the y-axis

2.Translate the graph up by 1 unit on the x-axis

3.Subtract 1 from the y-coordinate of every point on the graph

This results in the graph of y = 2-6x/x-5, which is a mirror image of the graph of y = 1/x.