The density of the person is 480.24 kg/m³.
Given,
Mass of the person = m = 550 N
Apparent weight =[tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
Density of water = р = 1000 kg/m³
We need to find the density of the person.
The formula for the apparent weight of an object when it is immersed in a liquid is given as:
[tex]F_ apparent[/tex][tex]= (m[/tex]р[tex]V)_g[/tex]...…(1)
Where m is the mass of the object, ρ is the density of the liquid, V is the volume of the object and g is the acceleration due to gravity.
Let V be the volume of the person. Then, the weight of the person in air = mg And, the weight of the person in water = [tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
We know that, Weight of the person in air - Weight of the person in water = Buoyant force = Weight of water displaced by the person[tex]mg - F_ a_p_p_a_r_e_n_t[/tex]
550 - 21.2 = р[tex]V_g[/tex]
528.8 = р[tex]V_g[/tex].......(2)
Dividing both sides of equation (1) and (2), we get:
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - mg/m[/tex] = [tex](m -[/tex] р[tex]V)_g/m[/tex] = р[tex]V_g/m[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - g =[/tex] р/[tex]V_g[/tex][tex]/m - g[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]m - g =[/tex] р/[tex]V_g[/tex][tex]/m[/tex]
21.2/550 - 9.81 = рVg/550 - 9.81Vg/550 = (21.2/550 - 9.81)/(р).........(3)
We know that, Density = mass/volume => р= m/V => V = m/р
Substituting V in equation (3), we get:
Vg/550 = (21.2/550 - 9.81)/m/рg
V = m/р = (21.2/550 - 9.81)/(1000*9.81)≈ 0.0113 m³
Substituting the value of V in equation (2), we get:528.8 = р(0.0113) (9.81)р = 480.24 kg/m³
Therefore, the density of the person is 480.24 kg/m³.
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a ski starts from rest and slides down a 30o incline 150m long. a) if the coefficient of friction is 0.15, what is the ski's speed at the base of the incline? b) if the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level? use energy methods.
a) Using energy methods and assuming negligible air resistance, the speed of the ski at the base of the incline is approximately 34.1 m/s. b) The ski will travel approximately 110.6 m along the level snow.
a) When the ski descends the gradient, its original potential energy is transformed into kinetic energy. Friction causes part of this energy to be wasted, which reduces the ski's speed at the bottom of the hill. The ski's ultimate kinetic energy may be calculated by subtracting the work done by friction from its starting potential energy using the laws of energy conservation. b) The ski only has kinetic energy left as it reaches the bottom of the gradient since all of its potential energy has been expelled. The ski's kinetic energy is transformed into thermal energy as it travels down the flat snow by the frictional force pressing on it, slowing it down until it ultimately comes to a stop. making use of energy saving once more.
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Before rotating the platform, the hanging mass is disconnected from the test mass and removed from the platform.TrueFalse
The given statement "Before rotating the platform, the hanging mass is disconnected from the test mass and removed from the platform." is True because the concept of a rotating platform involves a disc that rotates about its central axis with a pendulum suspended from its edge.
The plane of rotation and the plane of the pendulum oscillation are separated by a tiny angle. A rotating platform is utilized to generate an artificial gravity environment in space. The centrifugal acceleration produced by rotation is used to imitate the gravitational pull of Earth's mass on objects.
The pendulum is an instrument that measures acceleration, and it functions by oscillating with a period that is dependent on the magnitude of the acceleration it experiences. Besides, it has a number of other applications, including scientific research, engineering tests, and astronaut training in simulated gravity. The test mass is left alone on the platform while the hanging mass is disconnected and removed from the platform before the platform is rotated.
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the higher the r-value, the greater the insulating effectiveness. (1 point) group of answer choices true false
It is true that the higher the R-value, the greater the insulating effectiveness of a material.
True.
The R-value is a measure of a material's insulating effectiveness.
A higher R-value indicates greater insulation effectiveness, as it represents the material's resistance to heat flow.
This means that a material with a high R-value will be more effective at insulating and maintaining temperature differences between the interior and exterior environments.
To provide a concise explanation:
1. R-value measures a material's insulating effectiveness.
2. A higher R-value indicates greater resistance to heat flow.
3. Materials with high R-values are better at insulating and maintaining temperature differences.
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Which of these best explains the ability of small insects to walk on the surface of still water?
A: Water molecules at the surface experience fewer hydrogen bonds than water molecules within the liquid.
B: The insects' feet are coated with ionic compounds.
C: Water has a very high specific heat.
D: Water molecules near the surface produce more buoyant force than water molecules within the liquid.
Answer: water molecules at the surface experience fewer hydrogen bonds than water molecules within the liquid
Explanation: I took the test
a 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s. What is the tension on the string?
The string is under 4.82N of tension.
Tension is the pulling force exerted on a string, rope, cable, or wire when it is stretched or pulled. The tension on a string is equal to the amount of force applied to it divided by its cross-sectional area.
The tension on the string of a conical pendulum can be calculated using the equation:
[tex]T =\frac{ (4\pi^2m)}{(L^2T^2)},[/tex]
where T is the string's tension, m is the pendulum's mass, L is the string's length, and T is the pendulum's period of motion.
m=mass of pendulum=0.400kg
L=length of string =0.9m
T=pendulum's period of motion=1.4s
Plugging in the given values, we get:
[tex]T =\frac{ (4 \pi^2 * 0.400 kg) }{ (0.9 m^2 * 1.4 s^2)}\\\\T = 4.82 N[/tex]
Therefore,The Tension on the string is 4.82N
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what would be the path of a positive charge moving from left to right through the pair of oppositely charged electric plates in the diagram?
When a positive charge moves from left to right through a pair of oppositely charged electric plates, it follows a specific path due to the electric field produced by the plates.
The electric plates in the diagram have opposite charges. The top plate is positively charged, while the bottom plate is negatively charged. When a positive charge is placed in the electric field, it experiences a force that pushes it towards the negative plate. This is because opposite charges attract each other.
The path that the positive charge follows depends on the strength of the electric field and the speed at which it is moving. If the electric field is weak, the positive charge will not experience a significant force and will move in a straight line from left to right. However, if the electric field is strong, the positive charge will experience a stronger force and will curve towards the negative plate.
The direction of the force can be determined using the right-hand rule. If the positive charge is moving from left to right and the electric field is pointing down (from the positive plate to the negative plate), then the force on the charge will be towards the center of the plates (in the direction of the negative plate).
In summary, the path of a positive charge moving from left to right through a pair of oppositely charged electric plates depends on the strength of the electric field and the speed at which it is moving. If the electric field is weak, the charge will move in a straight line. If the electric field is strong, the charge will curve towards the negative plate. The direction of the force can be determined using the right-hand rule.
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how much does it cost to operate a 120-w lightbulb for 25 min if the cost of electricity is $0.086 per kilowatt-hour?
Answer:
120 W * 25/60 hr = 50 Whr = .05 kwh
.05 kwr * $.086 / kwr =$ .0043 = .43⊄
If a lightbulb of 120-w operate for 25 min then the cost of electricity is $0.086 per kilowatt-hour is $4.3.
What is energy ?Energy is nothing but the ability to do work. there are different energies in different form which are thermal energy, mechanical energy, electric energy and sound energy etc. According to first law of thermodynamic, Energy neither be created nor be destroyed. it can only be transferred from one form into another form. Energy is expressed in joule (J). its dimensions are [M¹ L² T⁻²]. Energy is conserved throughout the motion, according to conservation law of energy, initial energy is equal to final energy.
Power is given by,
P = Work/time.
Given,
Power P = 120 W
Time t = 25 min = 25/60 = 0.416 hr
Total energy needed for the bulb to run 25min is,
Work = Power × time.
Work = 120 W × 0.416 hr.
Work = 50 W-hr
Total cost = 50 W-hr × $0.086 per kilowatt-hour = $4.3
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fiber optic cable is thicker and heavier than unshielded twisted pair. question 10 options: true false
False, Fiber optic cable is thinner and lighter than unshielded twisted pair (UTP) cable.
Fiber optic cables are made up of strands of glass or plastic fibers that transmit data through light pulses. They are immune to electromagnetic interference and can transmit signals over longer distances than UTP cables, which are made up of copper wires.The content loaded Fiber optic cable is used in high-speed internet connections because it can transmit large amounts of data at very high speeds. Additionally, fiber optic cables are more secure than UTP cables because they are much more difficult to tap into without being detected. Therefore, the statement that fiber optic cable is thicker and heavier than UTP cable is false.
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a full water tank in the shape of a hemispherical bowl of radius 5 m. 5 m. how much work is required to pump all the water to a height of 5 m 5 m above the tank?
A full water tank in the shape of a hemispherical bowl of radius 5 m. 5 m. 8.6875 × [tex]10^5[/tex] J work is required to pump all the water to a height of 5 m 5 m above the tank
The amount of work required to pump all the water in the full water tank of the shape of a hemispherical bowl of radius 5m to a height of 5m above the tank is 8.6875 x [tex]10^5[/tex] J.
Let us begin by finding the volume of the hemispherical bowl of radius 5 m.
V = (2/3)πr³
where r is the radius of the hemispherical bowl.
Substituting r = 5 m in the above formula for volume,
we get
V = (2/3) × π × 5³ m³ = 523.6 m³
Since the bowl is full of water, the volume of water it contains is also 523.6 m³.
To find the mass of the water in the bowl, we need to multiply the volume by the density of water at room temperature, which is 1000 kg/m³.
Mass of water in the bowl = 523.6 × 1000 kg = 523600 kg
The potential energy of the water when it is lifted to a height of 5m above the tank is given by
mgh
where m is the mass of water, g is the acceleration due to gravity and h is the height of the water above the tank.
Substituting the given values, we get
Potential energy of water = 523600 × 9.81 × 5 J = 25690800 J
Therefore, the amount of work required to pump all the water to a height of 5m above the tank is equal to the potential energy of the water, which is 25690800 J, rounded off to 8.6875 × 10^5 J.
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what capacitance is needed to store this much charge in a capacitor with a potential difference between its plates of 9.5
The capacitance is needed to store charge Q in a capacitor with a potential difference between its plates of 9.5 is Q/9.5
A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical conductors that are separated by a distance. The space between the conductors may be filled by vacuum or with an insulating material known as a dielectric.
Capacitance is expressed as the ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them.
The capacitance needed to store charge Q in a capacitor with a potential difference between its plates of 9.5 is given by the formula:
C= Q/V
Where, C is the capacitance, Q is the charge stored, and V is the potential difference between the plates.
Therefore,
C= Q/9.5
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The movement of crustal plates is best described as a:
1) Trend toward increased crust movement overtime
2) Series of events that happens quickly
3) continuing long-term process
4) process that has a predictable pattern
The movement of crustal plates is best described as a continuing long-term process.
Plate tectonics is a theory of geology that describes the movement and interactions of lithospheric plates that cover the Earth's surface. There are three types of plate boundaries: divergent, convergent, and transform. They all have varying rates of movement and result in various geological phenomena.
As a result, the movement of crustal plates is best described as a continuing long-term process. Crustal plates move slowly over time as they are pushed and pulled by the Earth's internal forces. The direction and speed of movement vary from one plate to another, and the rate of movement is determined by several factors, including the thickness and composition of the lithosphere.
Plate tectonics is a process that operates on a global scale and has a significant impact on the Earth's surface features and geological history.
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"The horizontal surface on which the block slides is frictionless. The speed of the block before it touches the spring is 6. 0 m/s. How fast is the block moving at the instant the spring has been compressed 15 cm? (Assume k = 2. 0 kN/m. )"
The block is moving at 6.0 m/s when the spring is compressed 15 cm.
We can use conservation of energy to solve this problem. The initial kinetic energy of the block will be converted to potential energy when the spring is compressed. At this point, the block will momentarily come to a stop before bouncing back, so its velocity will be zero.
Let's first calculate the potential energy stored in the spring when it is compressed 15 cm:
Δx = 15 cm = 0.15 m (conversion from cm to m)
k = 2.0 kN/m = 2000 N/m (conversion from kN/m to N/m)
x = Δx = 0.15 m
[tex]U = (1/2) k x^2 = (1/2) * 2000 * (0.15)^2 = 22.5 J[/tex]
Now, we can equate this potential energy to the initial kinetic energy of the block:
[tex]K = (1/2) mv^2 = (1/2) * m * (6.0)^2 = 18 m J[/tex]
where m is the mass of the block.
Equating the two equations, we get:
18 m J = 22.5 J
[tex]m = 22.5 J / 18 (m/s)^2 = 1.25 kg[/tex]
Now that we know the mass of the block, we can use conservation of momentum to find its velocity when the spring is compressed:
Before the collision:
[tex]m_1 = 1.25 kg[/tex]
[tex]v_1 = 6.0 m/s[/tex]
After the collision:
[tex]m_2 = 1.25 kg[/tex]
[tex]v_2 = ?[/tex]
Conservation of momentum:
[tex]m_1v_1 = m_2v_2[/tex]
[tex]v_2 = m_1v_1/m_2 = (1.25 kg) * (6.0 m/s) / (1.25 kg) = 6.0 m/s[/tex]
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a convex mirror has a focal length of -24 cm. find the magnification produced by the mirror when the object distance is (a)14 cm and (b)16 cm.
The magnification produced by the convex mirror when the object distance is (a) 14 cm is 0.63 and (b) 16 cm is 0.6.To find the magnification produced by a convex mirror with a focal length of -24 cm when the object distance is 14 cm and 16 cm, we'll first need to calculate the image distance for each case using the mirror formula.
Mirror formula = 1/f = 1/v + 1/u, Where f is the focal length, v is the image distance, and u is the object distance.
(a) When the object distance (u) is 14 cm:
1/f = 1/v + 1/u
1/-24 = 1/v + 1/14
Now, solve for the image distance (v):
1/v = 1/-24 - 1/14
1/v = -38/336
v = 336/38
v = -8.84 cm Now we can find the magnification (M) using the formula: M = -v/u
For the object distance of 14 cm:
M = -(-8.84)/14
M = 0.63
(b) When the object distance (u) is 16 cm:
1/f = 1/v + 1/u
1/-24 = 1/v + 1/16
Solve for the image distance (v) again:
1/v = 1/-24 - 1/16
1/v = -40/384
v = 384/40
v = -9.6 cm. we can find the magnification (M) using the formula: M = -v/u
For the object distance of 16 cm:
M = -(-9.6)/16
M = 0.6.
Therefore the magnification produced by the mirror when the object distance is 14 cm is 0.63 and 16 cm is 0.6.
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Which of the following has a higher kinetic energy?
A 1000 kg car rolling at a speed of 5 m/s across the floor or a 1500 kg hippo swimming at a speed of 2 m/s
the hippo
their kinetic energies are equal
not enough information to determine
the car
Answer:
To solve the problem, we need to use the formula for kinetic energy:
KE = (1/2) * mass * velocity^2
For the car:
KE = (1/2) * 1000 kg * (5 m/s)^2 = 12,500 J
For the hippo:
KE = (1/2) * 1500 kg * (2 m/s)^2 = 3000 J
Therefore, the car has a higher kinetic energy:
Answer: The car.
you use the doppler method to discover a planet around a nearby star that is very similar to the sun; the velocity curve that has a period of 6 months. what can you conclude about the planet's orbital distance?
The planet's average distance from the star is approximately 0.78 astronomical units (AU).
What is the planet's orbital distance?Based on the information given, the velocity curve obtained using the Doppler method has a period of 6 months. This means that the planet completes one full orbit around the star in 6 months.
Using Kepler's third law, we can relate the orbital period of the planet to its distance from the star:
(T^2 / a^3) = (4π^2 / GM)
where;
T is the orbital period of the planet, a is its semi-major axis (i.e., its average distance from the star), G is the gravitational constant, andM is the mass of the star.Since we know the orbital period of the planet (6 months) and the mass of the star (similar to the Sun), we can solve for the semi-major axis:
a = (T^2 GM / 4π^2)^(1/3)
Substituting the given values, we get:
a = [(6 months)^2 * (1 solar mass) * (6.67 x 10^-11 N m^2/kg^2) / (4π^2)]^(1/3)
Simplifying the expression, we get:
a ≈ 0.78 AU
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a hair dryer draws 1 350 with, a curling iron draws 700 w, and an electric light fixture draws 550 w. if all three of these appliances are operating in parallel on a 120-v circuit, what is the total current drawn?
The total current drawn in the circuit was calculated to be 21.7 A.
Given the appliances are in parallel So the voltage across all the appliances is the same i.e. V = 120 V
We know that P = IΔV
The current in the hair dryer is
I₁ = 1350/120
I₁ = 11.25 A
The current in the curling iron
I₂ = 700/120
I₂ = 5.83 A
The current inside the electric light fixture
I₃ = 550/120
I₃= 4.58 A
So the total current drawn (I) is equal to
I = I₁+ I₂ +I₃
I = 11.25 A +5.83 A +4.58 A
I = 21.7 A
Since all components in a parallel circuit have the same electrical junctions, the voltage across parallel components is the same. The total current is equal to the sum of each individual branch current.
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In an electromagnetic wave, how are the magnetic field, the electric field, and the direction of propagation oriented to each other?n electromagnetic wave, how are the magnetic field, the electric field, and the direction of propagation oriented to each other а. All three are parallel to each other and are along the x axis. b. All three are mutually perpendicular to each other. c.The electric field and magnetic fields are parallel to each other and perpendicular to the direction of propagation. d. The magnetic field and direction of propagation are parallel to each other along the y axis and perpendicular to the electric field
In an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and both are perpendicular to the direction of propagation. This is known as transverse polarization. So, the correct option is (b) "All three are mutually perpendicular to each other."
The electric field and magnetic field are in phase and oscillate perpendicular to each other and to the direction of wave propagation. The direction of propagation is the direction in which the wave travels. The wave can travel in any direction perpendicular to the fields. The speed of the electromagnetic wave is determined by the properties of the medium in which the wave is traveling and is given by the equation v = c/n, where c is the speed of light in vacuum and n is the refractive index of the medium.
Electromagnetic waves are a form of energy that can travel through a vacuum and do not require a medium for their propagation. Examples of electromagnetic waves include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Hence, option b is correct.
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12. If a person fires a gun, specifically at the head, will the person feel any pain the second the bullet hits? Explain.
Answer:
No.
Explanation:
It will be soo painful that the person won't be able to feel it any,ore the person will feel nothing but dieing and can't talk
if a 1.3 v battery stores 6.7 kj of energy (a reasonable value for an inexpensive c cell), for how many minutes could it sustain a current of 1.3 a ? if a 1.3 battery stores 6.7 of energy (a reasonable value for an inexpensive c cell), for how many minutes could it sustain a current of 1.3 ? 2.3 min 6.9 min 9.4 min 66 min
The time could it sustain a current of 1.3 A is 3.96 minutes.
To calculate the time it can sustain a current of 1.3 A, we divide the Power = Voltage x Current
in the battery (in Joules) by the current (in Amps).
The voltage of the battery is 1.3 V
The energy stored in the battery is 6.7 kJ
The current drawn by the battery is 1.3 A
We know that,
Power = Voltage x Current
P = 1.3 x 1.3
P = 1.69 W
Now,
Energy = Power x Time
6.7 kJ = 1.69 W x Time
Time = 6.7 kJ/1.69 W
Time = 3.962 min ≈ 3.96 min
Hence, the battery could sustain a current of 1.3 A for about 3.96 minutes.
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who was the scientist that discovered a magnetic field could be created by passing an electric current through a wire?
The scientist who discovered that a magnetic field could be created by passing an electric current through a wire was Hans Christian Oersted, a physicist and chemist.
Hans Christian Oersted's discovery was a significant breakthrough in the field of electromagnetism. In 1820, he conducted an experiment in which he observed that a magnetic needle was deflected when placed near a wire carrying an electric current. This discovery paved the way for the development of electromagnetism, which is the basis for many important technologies, including electric motors, generators, and transformers.
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a farsighted person has a near point of 50 cm . part a what strength lens, in diopters, is needed to bring his near point to 25 cm ?
A farsighted person has a near point of 50 cm, and to bring their near point to 25 cm, we will need a converging lens.
Let the required lens' focal length be f, and the near point be p1. We will now use the lens formula to determine the strength of the lens (in diopters).
Formula: 1/f = 1/p1 + 1/p2
Since the lens formula is expressed in meters, we must first convert the near point to meters: 50 cm = 0.5 mp1 = 0.5 m - 0.25 m (because we want the image to be formed 25 cm away from the eye) = 0.25 m
Putting in these values in the above formula, we get:1/f = 1/0.25 - 1/0.5 1/f = 4 - 2 f = 1/2 f = 0.5 m Diopters are defined as the reciprocal of the focal length in meters, and we get the strength of the lens as:
Strength of the lens = 1/f = 1/0.5 = 2 diopters. Therefore, a lens of 2 diopters strength will be required to bring the farsighted person's near point to 25 cm.
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The smith family is traveling in their car at 50 km/h due east. Mr. Smith is using cruise control to maintain a constant speed. Describe the net force acting on the Smith car.
A. Net force equals zero.
B. Net forces are unbalanced
C. There is no way to determine net force
D. Net force is positive and to the east
A. Net force equals zero. The net force acting on the Smith car is equal to zero.
The net force acting on a car on cruise control at constant speed.This is because the car is traveling in a straight line at a constant speed, meaning that the forces acting on the car are balanced. The car is being propelled forward by an applied force, such as the engine, and this force is counteracted by the force of friction from the ground. The net force is the sum of all these forces, and since they are all balanced, the net force is also equal to zero.
Cruise control helps maintain a constant speed, as it adjusts the engine power to counteract the changing frictional forces on the car. This ensures that the forces on the car remain in balance, so the net force remains equal to zero.
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brody the dog is sitting at your feet like a good boy. you throw a dog toy away from you at a speed of 34 m/s (good arm). brody runs after the ball at a constant speed of 7 m/s. the toy is designed to make a constant high frequency tone of 950 hz as it flies through the air. what frequency does brody hear initially as he chases the toy?
Brody initially hears the frequency of the toy as 1071 Hz (approximately).
To solve this problem, we need to use the Doppler effect formula, which relates the frequency of a wave to the relative motion between the source and the observer.
The frequency heard by Brody initially:
[tex]f' = f * (v + vo) / (v + vs)[/tex]
where f is the frequency of the toy (950 Hz), v is the speed of sound (assumed to be 343 m/s at room temperature), vo is the velocity of the observer (Brody, running at 7 m/s), and vs is the velocity of the source (the toy, moving away from Brody at 34 m/s).
[tex]f' = 950 Hz * (343 m/s + 7 m/s) / (343 m/s - 34 m/s)\\\f' = 950 Hz * 350 / 309\\\\\f' = 1071 Hz (approximately)[/tex]
Therefore, Brody initially hears the frequency of the toy as 1071 Hz (approximately).
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how coulomb's law is the scientific concept explaining the intraparticle relationship between electrons and protons:
Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
In the context of atoms, electrons (negatively charged) and protons (positively charged) experience an attractive force, which helps maintain the stability of the atom. The Coulomb force, also known as Coulomb's law, is an essential concept in physics. Coulomb's law describes the force between two charged particles based on their charges and the distance between them. Coulomb's law of electrostatics is a fundamental law in physics that describes the relationship between electrically charged particles.
Coulomb's law is a simple equation that states that the force between two charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. In other words, Coulomb's law can be used to determine the force of attraction or repulsion between charged particles, such as electrons and protons, based on their charges and separation distance.
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Jeriah places two metal cubes in contact with each other. Energy and heat flow from Cube A to Cube B. What conclusion can be drawn regarding Cube A?
It is cooler than Cube B.
It is smaller than Cube B.
It is warmer than Cube B.
It is larger than Cube B.
Answer:
C. It is warmer than Cube B.
Explanation:
Option C would be correct because energy as heat flows from warmer objects to cooler objects. If heat flows from Cube A to Cube B, then Cube A must be warmer than Cube B.
Reasoning behind the other option being incorrect:
D: This is incorrect because the direction of heat flow does not depend on the relative size of the cube.
A: This is incorrect because energy as heat would flow from Cube B to Cube A if Cube A is cooler than Cube B.
B: This is incorrect because the direction of heat flow does not depend on the relative sizes of the cubes also.
Q10:
A room contains a book, a chair, a bookshelf, and a hatch that leads to a basement, as show in the diagram. The book has a weight of 7.5 N The seat of the chair is 0.45 m above the floor of the room, the bookshelf is 1.5 m above the floor of the room, and the basement floor is 2.2 m below the floor of the room. The book is placed in various positions and its gravitational potential energy changes depending on its position.
A)How much can the gravitational potential energy of the book decrease if the book is released from a point on the floor of the room, to the left of the hatch?
B)How much can the gravitational potential energy of the book decrease if the book is released from a point on the floor of the room, to the right of the hatch?
C)How much can the gravitational potential energy of the book decrease if the book is released from a point at the height of the chair seat?
D)How much can the gravitational potential energy of the book decrease if the book is released from a point at the height of the bookshelf?
Answer:
To calculate the change in gravitational potential energy of the book as it falls from different starting points, we need to use the formula:
ΔPE = mgh
where ΔPE is the change in gravitational potential energy, m is the mass of the book, g is the gravitational acceleration (9.81 m/s^2), and h is the change in height.
A) If the book is released from a point on the floor of the room to the left of the hatch, it will fall towards the hatch and then fall further towards the basement floor. The change in height is the distance from the floor to the basement floor, which is 2.2 meters. Therefore, the change in gravitational potential energy is:
ΔPE = (7.5 N) x (9.81 m/s^2) x (2.2 m) = 162.8 Joules
B) If the book is released from a point on the floor of the room to the right of the hatch, it will fall towards the hatch and then fall further towards the basement floor as well. Therefore, the change in gravitational potential energy is the same as in Part A:
ΔPE = (7.5 N) x (9.81 m/s^2) x (2.2 m) = 162.8 Joules
C) If the book is released from a point at the height of the chair seat (0.45 m above the floor), it will fall towards the hatch and then fall further towards the basement floor. The change in height is the distance from the chair seat to the basement floor, which is:
h = 0.45 m + 2.2 m = 2.65 m
Therefore, the change in gravitational potential energy is:
ΔPE = (7.5 N) x (9.81 m/s^2) x (2.65 m) = 187.8 Joules
D) If the book is released from a point at the height of the bookshelf (1.5 m above the floor), it will fall directly towards the basement floor. The change in height is the distance from the bookshelf to the basement floor, which is:
h = 1.5 m + 2.2 m = 3.7 m
Therefore, the change in gravitational potential energy is:
ΔPE = (7.5 N) x (9.81 m/s^2) x (3.7 m) = 268.4
What must be the mass of a chunck of aluminum that takes 8550 J of engery ti be heated from 50 C to 72 C
a 3.1-mm-diameter wire carries a 14 a current when the electric field is 6.9×10−2 v/m .
What is the wire's resistivity?
Wire's resistivity is approximately 3.72 × 10^−8 Ωm.
To find the wire's resistivity, we can follow these steps:
1. Calculate the wire's cross-sectional area.
2. Use Ohm's Law to find the resistance.
3. Use the resistance and cross-sectional area to find the resistivity.
Step 1: Calculate the wire's cross-sectional area.
The wire has a diameter of 3.1 mm, so its radius is 1.55 mm. Convert the radius to meters (1.55 × 10⁻³ m). The cross-sectional area (A) of the wire can be calculated using the formula A = πr², where r is the radius.
A = π(1.55 × 10⁻³ m)² ≈ 7.54 × 10⁻⁶ m²
Step 2: Use Ohm's Law to find the resistance.
Ohm's Law states that V = IR, where V is voltage, I is current, and R is resistance. We know the electric field (E) is 6.9 × 10⁻² V/m and the current (I) is 14 A. To find the voltage (V), we can multiply the electric field by the length of the wire (L). However, we don't know the length of the wire. Instead, we can find the resistance per unit length (R/L) by dividing both sides of Ohm's Law by L:
(V/L) = I(R/L) → E = I(R/L)
Now, we can solve for (R/L):
(R/L) = E/I = (6.9 × 10⁻² V/m) / 14 A ≈ 4.93 × 10⁻³ Ω/m
Step 3: Use the resistance and cross-sectional area to find the resistivity.
Resistivity (ρ) can be calculated using the formula ρ = (R × A) / L. Since we have the resistance per unit length (R/L) and the cross-sectional area (A), we can write the formula as:
ρ = (R/L) × A
Now, plug in the values:
ρ = (4.93 × 10⁻³ Ω/m) × (7.54 × 10⁻⁶ m²) ≈ 3.72 × 10⁻⁸ Ωm
So, the wire's resistivity is approximately 3.72 × 10⁻⁸ Ωm.
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if you weigh 670 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 16.0 km ? take the mass of the sun to be ms
If a person weighs 670 N on Earth, their weight on the surface of a neutron star that has the same mass as our sun and a diameter of 16.0 km would be 9.26 x 10^12 N.
To find out, we'll need to use the formula for surface gravity: g = (GM)/r²
where: g is surface gravity in N/kg, G is gravitational constant in Nm²/kg², M is the mass in kilograms, r is the radius in meters.
First, we'll need to find the mass of the neutron star using the mass of the sun, which is Ms = 1.989 x 10³⁰ kg.
M = Ms = 1.989 x 10³⁰ kg
The radius of the neutron star is 16.0 km or 16,000 m. r = 16,000 m
Now we can plug these values into the surface gravity formula:
g = (GM)/r²g = [(6.674 x 10^-11 Nm²/kg²)(1.989 x 10³⁰ kg)]/(16,000 m)²g = 1.15 x 10^12 N/kg
Finally, to find the weight of the person on the surface of the neutron star, we'll multiply their mass by the surface gravity:
weight = mgweight = (670 N)/(9.81 m/s²)weight = 68.27 kg
weight on neutron star = (68.27 kg)(1.15 x 10^12 N/kg)
weight on neutron star = 9.26 x 10^12 N
Therefore, the weight of the person on the surface of a neutron star that has the same mass as our sun and a diameter of 16.0 km would be 9.26 x 10^12 N.
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An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.9 MJ when the flywheel is rotating at 11000 revolutions per minute. What is the moment of inertia of the flywheel?
The moment of inertia of the flywheel is approximately 0.0337 kg·m^2.
StepsTo solve this problem, we can use the formula for rotational kinetic energy:
KE = (1/2) I ω²
where KE is the kinetic energy of the flywheel, I is its moment of inertia, and ω is its angular velocity.
We can first convert the angular velocity from revolutions per minute (rpm) to radians per second (rad/s):
ω = (11000 rpm) * (2π rad/rev) * (1 min/60 s) = 1146.13 rad/s
Next, we can plug in the values for KE and ω and solve for I:
KE = 4.9 MJ = 4.9 × 10⁶ J
ω = 1146.13 rad/s
(1/2) I ω² = KE
(1/2) I (1146.13 rad/s)² = 4.9 × 10⁶ J
I = (2 * 4.9 × 10⁶J) / (1146.13 rad/s)²
I = 0.0337 kg·m²
Therefore, the moment of inertia of the flywheel is approximately 0.0337 kg·m².
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