A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocean. (b) If we assume the meteoroid survives the impact with the ocean surface, what is the (initial) Mach angle of the shock wave the meteoroid produces in the water?

Answer:

think 2 also if not im so sorry  but i think it is :)

Answer:

6m/s

Explanation:

Given that a 1.50 kg ball moving at 8.00 m/s south, strikes a 2.00 kg ball moving at 3.00 m/s south. If the velocity of the 2.00 kg ball after the collision is 4.50 m/s south, what is the velocity of the 1.50 kg ball

This is elastic collision.

M1U1 + M2U2 = M1V1 + M2V2

Substitute all the parameters into the formula above

1.5×8 + 2×3 = 2×4.5 + 1.5V

12 + 6 = 9 + 1.5V

18 = 9 + 1.5V

1.5V = 9

V = 9/1.5

V = 6 m/s

Therefore, the velocity of the 1.5kg ball is 6 m/s

The amplitude of the resultant wave in terms of the common amplitude [tex]y_m[/tex] of the two combining waves which are out of phase by [tex]\frac{\pi}{2} \ \text{rad}[/tex] is [tex]\sqrt{2} y_m[/tex].

The amplitude of two waves interfering with each other depends on the principle of superposition.

Since, the waves are out of phase by [tex]\frac{\pi}{2} \ \text{rad}[/tex] so we can write the waves to be:

[tex]y_1=Asin(kx-\omega t)[/tex]

[tex]y_2=Asin(kx-\omega t+\frac{\pi}{2})\\ \therefore y_2=Acos(kx-\omega t)[/tex]

According to the principle of superposition, the resultant wave is written as:

[tex]y=y_1+y_2[/tex]

[tex]\Rightarrow y=A[sin(kx-\omega t)+cos(kx-\omega t)]\\\Rightarrow y=\sqrt{2}A[\frac{1}{\sqrt{2}}sin(kx-\omega t)+\frac{1}{\sqrt{2}}cos(kx-\omega t)]\\y=\sqrt{2}Asin(kx-\omega t+ \frac{\pi}{4})[/tex]

So from the above relation, we have the amplitude to be:

New Amplitude = [tex]\sqrt{2}A[/tex]

Hence, the amplitude of the combined waves is [tex]\sqrt{2}A[/tex].

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The aircraft takes 25s to become airborne and will cover a distance of 1.0417km.

Distance, s = [tex]\frac{300km}{1 h}[/tex]

                s = [tex]\frac{300 }{1}[/tex] × [tex]\frac{1000m}{3600s}[/tex]

                s = [tex]\frac{250}{3}[/tex] m/s

Velocity is the time derivative of the displacement, [tex]v(t)=\frac{d}{dt}(\frac{5}{3}t^{2})[/tex]

                                                                                      [tex]v(t)=\frac{10}{3}t^{2}[/tex]

The time required to reach [tex]v=\frac{500}{3}[/tex] m/s,

                                              [tex]\frac{10}{3}t=\frac{250}{3}[/tex]

                                              [tex]t=25s[/tex]

Now, during this time, the aircraft travels a distance, [tex]D= \frac{5}{3} (25)^{2}[/tex]

                                                                                       [tex]D= 1041.667m[/tex]

                                                                                      [tex]D= 1.0417km[/tex]

Therefore, the aircraft takes 25s to become airborne and will cover a distance of 1.0417km.

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Answer:

  0.6 seconds

Explanation:

The time to fall from height h is ...

  t = √(2h/g)

  t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

Answer:

0.6 seconds

is ur answer :)

✌❤

Time taken to reach height is 4 seconds.

Given that;

Velocity of cannon ball = 80 m/s

Height taken = 320 meter

Find:

Time taken to reach height

Computation:

S = ut + (1/2)gt²

320 = (80)(t) + (1/2)(10)(t²)

320 = 80t + 5t²

t² + 16t + 64

So,

t = 4

Time taken = 4 seconds

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They are maintaining their body temperature by cooling down, like dogs do, as they don't have enough sweat glands to keep them cool without panting.

Brown bears maintain body temperature by cooling as a result of panting. So, the correct option is D.

Normal human body-temperature is defined as the typical temperature range found in humans which is commonly referred to as 36.5–37.5 °C. The human body temperature varies. Temperature is known as the degree of hotness or coldness of an area or object.

When we are very hot, the blood vessels of the skin dilate to carry the excess heat to the surface of the skin. Brown bear panting ensures that cool air circulates over the moist surfaces in the mouth which helps maintain body temperature by cooling the body.

Therefore, the correct option is D.

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Answer:

U^U

Explanation:

Two-dimensional vectors have two components: an x vector and a y vector. Each of these vector components is a vector in the direction of one axis. The sum of the components of vectors is the original vector. Three-dimensional vectors have a z component as well.

The nfl caliber wide receiver that can reach a top speed of 10.0 m/s in only 2.4 s has an acceleration during this time of: 4.16 m/s²

The formula and procedure we will use to solve this exercise is:

a = (vf - vi) /t

Where:

Information about the problem:

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (10.0 m/s - 0 m/s) /2.4 s

a = (10.0 m/s) /2.4 s

a = 4.16 m/s²

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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The maximum height that the toy rocket reaches is 36feet.This is a type of projectile motion.

An object being launched or projected into the air will move in a projectile motion, with the sole acceleration coming from gravity. Projectile motion has many uses in both physics and engineering. Examples include the motion of any ball in sports, fireworks, and meteors entering the Earth's atmosphere. These things are known as projectiles, and the path they take is known as a trajectory. As stated in Motion Along a Straight Line, the motion of falling objects is a straightforward one-dimensional type of projectile motion with no horizontal movement. In this part, we focus on projectile motion in two dimensions while ignoring the effects of air resistance.

Explanation:

Given function is:

[tex]f(t)= -16t^{2} + 48t[/tex]

Where t = time in seconds since the toy rocket was shot.

f(t) = the toy rocket’s height in feet.

In order to get the maximum height, we need to find out the time when the rocket will reach maximum height.

For this,  [tex]f^{'} (t)=0[/tex] and find t, again check f''(t), if its value is negative, put t in f(t) to get the maximum height.

[tex]f^{'} (t)=\frac{d}{dt} (-16t^{2} +48t) =0[/tex]

-32t + 48 =0

t = 1.5

f''(t) = -32, This means t=1.5 will be the time when the rocket will be at maximum height, or mathematically t will be the point of local maxima.

So, maximum height = f(1.5) = -16*(1.5)² + 48*1.5 = 36feet

Therefore, the maximum height that the toy rocket reaches is 36feet.

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Considering the definition of velocity, the velocity is 0.2 m/s due east.

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction, so it is considered a vector magnitude.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:

velocity= distance traveled÷ time

Velocity has units of distance/time and includes direction of travel.

In this case, you know:

Replacing in the definition of velocity:

velocity= 4 meters÷ 20 seconds

Solving:

velocity= 0.2 m/s

Finally, the velocity is 0.2 m/s due east.

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Gauss law states that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Mathematically,

Φ=Q ϵo

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

According to Gauss law, which states that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Φ=Q ϵo

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

If the cube is transformed into a sphere the total flux in the electric field remains unchanged or remains the same. This is because the gaussian law does not postulate that electric flux is dependent on the object in a plane. Hence, the transformation of the cube to a sphere does not affect the electric flux generated in the field.

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Therefore, Mc² = 2mc²[ 1 + (K/mc²)] where K s the kinetic energy of each of the two identical colliding particles.

Consider a collision between two protons that is perfectly inelastic: an incident proton with mass m(p), kinetic energy K, and momentum magnitude p combines with a target proton that was initially stationary to form a single product particle with mass M.

Now,

In this case, the problem is alleviated by using colliding beams.

A pair of interacting particles' combined momentum may be zero.

After the collision, the center of mass is at rest.

Therefore, all the initial kinetic energy can be used to create particles.

Let K be the kinetic energy of each of the two identical colliding particles.

Therefore, the energy released by the two colliding beams are:

E₁ = K + mc² and E₂ = K + mc²

In the final state,

E(f) = Mc² where M is the new mass of the single product after the collision.

By conservation of energy,

E₁ + E₂ =E(f)

K + mc² + K + mc² = Mc²

2K + 2mc² = Mc²

Taking 2mc² common, we get

Mc² = 2mc²[ 1 + (K/mc²)]

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Answer:

C.

Explanation:

kilograms and m/s^2

The three different paper airplane designs were created by Ricardo. In an effort to determine which design flies the farthest, Ricardo intends to fly each paper airplane five times. Following each flight, Ricardo should measure the distance flown by the aircraft and note it.

Two of the most frequent techniques used in agricultural surveying involve measuring angles and distances with basic tools. even when the tools are basic. With diligence and practice, a great degree of precision can be attained.

The (1) pace is the main technique for gauging distance. 2) The odometer. (3) chaining or taping. four stages. optical range finder, number 5. and (6) techniques for electronic distance measurement (EDM).

It will be beneficial to review the standard units of distance first (displacement). The following are the standard English units:

12 inches make up one foot (in)

Yd (yard) = 3 feet (ft)

1 rod is equal to 16.5 feet and 5.5 yards (yd)

A mile is equal to 5280 feet, 1760 yards, and 320 rods.

When converting between different units of measurement, the units cancellation approach comes in quite handy.

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Answer: True

Explanation:

Answer:

false

Explanation:

hope this help (brainlist plz)

Answer:

Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

Explanation:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its potential energy (PE) when it lands

The potential energy PE, relative to the ground, will be zero, because the lemming is at the ground level.

HOWEVER, a much better question would be:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its kinetic energy (KE) when it lands?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, u = 0, a = 9.81m/s^2, s = 5.36m

So we find v using equation (2)

v^2 = u^2 + 2as

v^2 = 0 + 2(9.81)(5.36) = 105.1632

So the kinetic energy resulting from the vertical drop is Ekv = ½mv^2

Ekv = ½(0.078)(105.16) = 4.101J

BUT we need to add in the kinetic energy resulting from the horizontal velocity, which did not change during the vertical drop.

Ekh = ½(0.078)(4.84^2) = 0.914J

So the total kinetic energy is Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

The potential energy of the object with a mass of 0.0780 kg  moving from a height of 5.36 m is 4.09 J.

Potential energy of an object is generated by virtue of its position at a height from the ground. It is stored in the object when it is at rest, Whereas,  kinetic energy is generated by virtue of the motion of the body.  These energies are together called mechanical energy of the object.

When the object starts moving from rest, its potential energy starts to convert into kinetic energy and when it stops the reverse occurs . The potential energy of  a body is dependant on its mass and height by the equation:

p = mgh

Given that, mass of the object = 0.078 kg

height  h = 5.36 m

acceleration due to gravity g = 9.8 m/s²

then potential energy p = 0.078 × 9.8 m/s² ×5.36 m = 4.09 J

Therefore, the potential energy of the lemming is 4.09 J.

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Answer:d

Explanation:

Answer:

The acceleration = -40 ms⁻²

Explanation:

We know that,

a = (v₂ -  v₁) / t

  = 0 - 20 / 0.5

  = -20 / 0.5

  = -40 ms⁻²

Thus, the acceleration = -40 ms⁻²

Answer:

The correct option is C

Explanation:

The pendulum bob would return at the same time because the initial angle a pendulum bob is dropped does not affect it's period (the time it takes for the pendulum to move back and forth), however the one with a larger angle move faster but would eventually arrive at the same "starting point" due to varying displacements made.

c. No one wins as the bobs come back at the same time.

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The force is attractive.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

Each parallel wire carries 3.00 A of current in the same direction and is spaced apart by 6.00 cm.

Think of these two wires as being placed side by side on a table, with currents flowing in opposite directions toward you—wire 1 to the left and wire 2 to the right. The magnetic field produced by wire 1 at the location of wire 2 is directed vertically upward, according to the right-hand rule that links current to field direction. The force experienced by wire 2 as a result of its current flowing through this field is therefore determined by the right-hand rule, which links current and field to force, to be to the left, back toward wire 1. The force that one wire applies to another is therefore an attractive force.

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Answer:

B. Applied

Explanation:

Applied means that somethings is pushing directly into it like a person to a box. and well the reasons why the others are not contact force are because gravity its cause to an attraction to the planet and no matter where you are it will still attract you, electric is not because it can flow through air, magnetic it affects to an invisible field that even if its not torching the marital you can still feel the magnetic push or pull

So applied

The negative acceleration of the truck is -2 m/s.

Acceleration of the body is the rate of change of speed with respect to time. The acceleration of the body is calculated by dividing the change in speed during a particular interval of time, by the time taken to change the speed.

According to the question, the initial speed of the truck is 40 m/s and it decreases to 20 m/s after 10 seconds. As the speed of the truck is decreasing, its sign is negative.

So given in the question

Initial Speed= u = 40 m/s

Final Speed= v = 20 m/s

Change in velocity = v - u

                               = 20 - 40

                               = -20 m/s

Time interval = 10 seconds

Acceleration = Change in Velocity/Time interval

                     = -20/10

                     = -2 m/s

So the acceleration of the truck is equal to -2 m/s. The negative sign indicates the speed is decreasing.

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Answer:

ewwwwwwwwwwww

get it out!

The calculated weight in newtons is 10 N.

Listed below is the data we will use:

Area A is where the pressure is P. Here are the details we were given:

A=1 cm2, P=101325 N/m, and w=?

Do the area conversion to square meters.

A=1cm2×1m2/1002cm2\s=1×10−4m2

From the definition of pressure, calculate the weight of the air column. In this instance, the air column's weight is determined by multiplying the atmospheric pressure by the air column's base area.

Fw = P atm A

= (101325N/m2) (1 10 4m2)

= 10N

The complete question is - Imagine a square column of the atmosphere, 1 cm on a side, that extends all the way to the top of the atmosphere. How much does this column of air weigh in newtons?

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Answer:

Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

Explanation:

Answer:

in a given direction it is a speed of something

Explanation:

velocity tells how much distance is covered by an object in other words we can tell the quickness of motion

The ranking of the measurement from the largest to the smallest is 11.6 mg > 0.000006 kg > 1021 µg > 0.31 mg.

Ranking of measurement is a classification that describes the nature of information within the values assigned to variables.

This is usually done based on the size of each item in the list of measurement.

11.6 mg = 0.0116 g

1021 µg = 0.001021 g

0.000006 kg = 0.006 g

0.31 mg = 0.00031 g

Thus, the ranking of the measurement from the largest to the smallest is 11.6 mg > 0.000006 kg > 1021 µg > 0.31 mg.

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Answer:

70.4%

Explanation:

Step one:

given data

input energy= 2280J

output energy=  1,606 Joules  of useful kinetic and 55joules waste

hence the useful out put= 1606J

Required

The efficiency of the motor

Step two:

what is the efficiency of a motor?

efficiency is the ratio of mechanical power delivered by the motor (output) to the electrical power supplied to the motor (input)

Efficiency= 1606/2280*100

Efficiency=0.704*100

Efficiency=70.4%

Answer:

The net force acting on the mass is 16.523 N

Explanation:

The given mass of the object, m = 1.3 kg

The length of the inclined plane over which the mass slides = 8.7 × 10⁻¹ m

The time it takes the mass to slide = 0.37 s

Therefore, we apply the following kinematic equation of motion;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the mass = 0 m/s

t = The time taken for the motion = 0.37 s

a = The acceleration

s = The distance moved in the motion = 8.7 × 10⁻¹ m = 0.87 m

Plugging in the values gives;

0.87 = 0 × t + 1/2 × a × 0.37²

∴ 0.87 = 1/2 × a × 0.37²

a = 0.87/(1/2 × 0.37²) ≈ 12.71 m/s²

The net force acting on the mass is F = Mass, m × Acceleration, a force = m × a

Therefore, the net force acting on the mass is F = 1.3 × 12.71 = 16.523

The net force acting on the mass, F = 16.523 N.

The net force acting on the mass along the incline is 16.523 N

From the information given:

According to the second equation of motion;

[tex]\mathbf{S = ut + \dfrac{1}{2}at^2}[/tex]

the initial velocity u = 0 m/s since the mass starts from the rest

∴

[tex]\mathbf{S =0(t) + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{S = \dfrac{1}{2}at^2}[/tex]

2S = at²

[tex]\mathbf{a = \dfrac{2S}{t^2}}[/tex]

[tex]\mathbf{a = \dfrac{2\times 0.87 \ m}{0.37^2}}[/tex]

acceleration (a) = 12.71 m/s²

The net force now acting on the mass along the incline can now be estimated as:

[tex]\mathbf{F_{net} = ma}[/tex]

[tex]\mathbf{F_{net} = 1.3 \ kg \times 12.71 \ m/s^2}[/tex]

[tex]\mathbf{F_{net} = 16.523 \ N}[/tex]

Therefore, we can conclude that the net force acting on the mass along the incline is 16.523 N

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