5. Journalise the following transactions:
1. Pater commenced business with 40,000 cash and also brought
into business furniture worth
*5,000; Motor car valued for ₹12,000 and stock worth 20,000.
2. Deposited 15,000 into State Bank of India.
3. Bought goods on credit from Sen ₹9,000
4. Sold goods to Basu on Credit for ₹6,000
5. Bought stationery from Ram Bros. for Cash ₹200
6. Sold goods to Dalal for ₹2,000 for which cash was received.
7. Paid 600 as travelling expenses to Mehta in cash.
8. Patel withdrew for personal use ₹1,000 from the Bank.
9. Withdrew from the Bank ₹3,000 for office use.
10. Paid to Sen by cheque 8,800 in full settlement of his account.
11. Paid ₹400 in cash as freight and clearing charges to Gopal,
12. Received a cheque for ₹6,000 from Basu.
The journal entries for the given transactions are as follows:
Cash A/c Dr. 40,000
Furniture A/c Dr. 5,000
Motor Car A/c Dr. 12,000
Stock A/c Dr. 20,000
To Capital A/c 77,000
Bank A/c Dr. 15,000
To Cash A/c 15,000
Purchase A/c Dr. 9,000
To Sen's A/c 9,000
Basu's A/c Dr. 6,000
To Sales A/c 6,000
Stationery A/c Dr. 200
To Cash A/c 200
Cash A/c Dr. 2,000
To Dalal's A/c 2,000
Travelling Expenses A/c Dr. 600
To Cash A/c 600
Drawings A/c Dr. 1,000
To Bank A/c 1,000
Cash A/c Dr. 3,000
To Bank A/c 3,000
Sen's A/c Dr. 8,800
To Bank A/c 8,800
Freight and Clearing A/c Dr. 400
To Cash A/c 400
Bank A/c Dr. 6,000
To Basu's A/c 6,000
Journal entries for the given transactions are as follows:
Pater commenced business with 40,000 cash and also brought into business furniture worth ₹5,000; Motor car valued for ₹12,000 and stock worth ₹20,000.
Cash A/c Dr. 40,000
Furniture A/c Dr. 5,000
Motor Car A/c Dr. 12,000
Stock A/c Dr. 20,000
To Capital A/c 77,000
Deposited ₹15,000 into State Bank of India.
Bank A/c Dr. 15,000
To Cash A/c 15,000
Bought goods on credit from Sen for ₹9,000.
Purchase A/c Dr. 9,000
To Sen's A/c 9,000
Sold goods to Basu on Credit for ₹6,000.
Basu's A/c Dr. 6,000
To Sales A/c 6,000
Bought stationery from Ram Bros. for Cash ₹200.
Stationery A/c Dr. 200
To Cash A/c 200
Sold goods to Dalal for ₹2,000 for which cash was received.
Cash A/c Dr. 2,000
To Dalal's A/c 2,000
Paid ₹600 as travelling expenses to Mehta in cash.
Travelling Expenses A/c Dr. 600
To Cash A/c 600
Patel withdrew for personal use ₹1,000 from the Bank.
Drawings A/c Dr. 1,000
To Bank A/c 1,000
Withdrew from the Bank ₹3,000 for office use.
Cash A/c Dr. 3,000
To Bank A/c 3,000
Paid to Sen by cheque ₹8,800 in full settlement of his account.
Sen's A/c Dr. 8,800
To Bank A/c 8,800
Paid ₹400 in cash as freight and clearing charges to Gopal.
Freight and Clearing A/c Dr. 400
To Cash A/c 400
Received a cheque for ₹6,000 from Basu.
Bank A/c Dr. 6,000
To Basu's A/c 6,000
These journal entries represent the various transactions and their effects on different accounts in the accounting system.
They serve as the initial records of the financial activities of the business and provide a basis for further accounting processes such as ledger posting and preparation of financial statements.
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Si 3,390 kg de plomo ocupan un volumen de 0.3m3. Encuentra la densidad del plomo
The density of lead is 11.3 kg/m³.
The density of lead can be calculated by using the formula D = M/V, where D represents density, M represents mass and V represents volume. The density of lead is the ratio of the mass of lead to the volume occupied by it.
Density of Lead:
Given that the lead has a mass of 3.390 kg and occupies a volume of 0.3 m³.
Density of Lead (D) = Mass of Lead (M) / Volume of Lead (V)D = 3.390 kg / 0.3 m³D = 11.3 kg/m³
Therefore, the density of lead is 11.3 kg/m³.
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Margie's work for adding linear expressions is shown below. After checking her answer with the answer key, she solved it incorrectly.
Given (−2.67b + 11) − (5.38b − 15)
Step 1 −2.67b + 11 + (−5.38b) + 15
Step 2 −2.67b + 5.38b + 11 + 15
Step 3 (−2.67b + 5.38b) + (11 + 15)
Step 4 2.71b + 26
Part A: Identify and explain the first step where Margie made an error. (2 points)
Part B: Explain how to correctly write the expression in fewest terms by correcting the error in Part A. Show all work. (2 points)
Step-by-step explanation:
Part A: The first step where Margie made an error is Step 1:
−2.67b + 11 + (−5.38b) + 15
The error lies in the addition of the two terms: (−5.38b) + 15. Margie incorrectly added the two terms together instead of subtracting them.
Part B: To correctly write the expression in the fewest terms, we need to correct the error from Part A. The correct step-by-step process is as follows:
Given: (−2.67b + 11) − (5.38b − 15)
Step 1: Distribute the negative sign to the terms inside the second parentheses:
−2.67b + 11 − 5.38b + 15
Step 2: Combine like terms:
(−2.67b − 5.38b) + (11 + 15)
Step 3: Simplify:
−7.05b + 26
Therefore, the correct expression, written in the fewest terms, is −7.05b + 26.
Find the indefinite integral. (Use C for the constant of integration.)
1. v + 1/
(2v − 20)^5dv
2. x^2/
x − 5 dx
3. x cos 8x2 dx
4. 176/e^−x + 1 dx
5.
1. The indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.
2. The indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.
3. The indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.
4. The indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.
1. To find the indefinite integral of (v + 1) / (2v - 20)^5 dv:
Let u = 2v - 20. Then du = 2 dv.
The integral becomes:
(1/2) ∫ (1/u^5) du
Now we can integrate using the power rule:
(1/2) ∫ u^(-5) du
Applying the power rule, we get:
(1/2) * (u^(-4) / -4) + C
= -1 / (8u^4) + C
Substituting back u = 2v - 20:
= -1 / (8(2v - 20)^4) + C
Therefore, the indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.
2. To find the indefinite integral of x^2 / (x - 5) dx:
We can use polynomial long division to simplify the integrand:
x^2 / (x - 5) = x + 5 + 25 / (x - 5)
Now we can integrate each term separately:
∫ x dx + ∫ (5 dx) + ∫ (25 / (x - 5) dx)
Using the power rule, we get:
(1/2) x^2 + 5x + 25 ln|x - 5| + C
Therefore, the indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.
3. To find the indefinite integral of x cos(8x^2) dx:
We can use the substitution method. Let u = 8x^2, then du = 16x dx.
The integral becomes:
(1/16) ∫ cos(u) du
Integrating cos(u), we get:
(1/16) sin(u) + C
Substituting back u = 8x^2:
(1/16) sin(8x^2) + C
Therefore, the indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.
4. To find the indefinite integral of 176 / e^(-x) + 1 dx:
We can simplify the integrand by multiplying the numerator and denominator by e^x:
176 / e^(-x) + 1 = 176e^x / 1 + e^x
Now we can integrate:
∫ (176e^x / 1 + e^x) dx
Using u-substitution, let u = 1 + e^x, then du = e^x dx:
∫ (176 du / u)
Integrating 176/u, we get:
176 ln|u| + C
Substituting back u = 1 + e^x:
176 ln|1 + e^x| + C
Therefore, the indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.
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please help will give brainliest...........
A
no, because they are both right triangles and
the one on the left is 88° at the right anglr
Which is the graph of the linear inequality 1/2x – 2y > –6? On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything above and to the left of the line is shaded. On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything above and to the left of the line is shaded. On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded. On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded.
The correct graph of the linear inequality 1/2x - 2y > -6 is the one where a solid straight line has a positive slope and goes through (negative 4, 2) and (4, 4), and everything below and to the right of the line is shaded.
Please answer ASAP I will brainlist
The result of the row operation on the matrix is given as follows:
[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
How to apply the row operation to the matrix?The matrix in this problem is defined as follows:
[tex]\left[\begin{array}{cccc}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
The row operation is given as follows:
[tex]R_1 \rightarrow \frac{1}{2}R_1[/tex]
The first row of the matrix is given as follows:
[2 0 0 16]
The meaning of the operation is that every element of the first row of the matrix is divided by two.
Hence the resulting matrix is given as follows:
[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
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Mrs. Rodriquez has 24 students in her class. Ten of the students are boys. Jeff claims that the ratio of boys to girls in this class must be 5:12. What is Jeff’s error and how can he correct it?
Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls to get a ratio of 10:14 or 5:7.
Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls. The ratio would be 14:10 or 7:5.
Jeff did not write the ratio in the correct order. He should have written it as 24:10.
Jeff did not write the ratio in the correct order. He should have written it as 12:5.\
Step-by-step explanation:
24-10=14. So the girls are 14 the ratio is 10:14 =5:7
NO LINKS!! URGENT HELP PLEASE!!
29. A tree casts a shadow that is 12 feet long. If the tree is 20 feet tall, what is the angle of elevation of the sun? Draw a diagram to represent the situation. Round the answer to the nearest tenth.
30. In ΔABC, m∠A = 75°, m∠B = 50°, and c = 9. Draw ΔABC, then use the Law of Sines to find a. Round final answer to the nearest tenth.
Answer:
29. 59.06°
30. 10.6
Step-by-step explanation:
29.
By using the Tangent angle rule, we can find the angle of elevation,
We know that
Tan Angle = opposite/adjacent
Tan x=AB/BC
Tan x=20/12
Tan x=5/3
[tex]x=Tan^{- }(\frac{5}{3})[/tex]
x=59.06°
30.
The law of sine is a formula that can be used to find the lengths of the sides of a triangle, or to find the angles of a triangle, when two sides and the angle between them are known. The formula is:
a / sin(A) = b / sin(B) = c / sin(C)
Here taking
a / sin(A) = c / sin(C)
here A=75°, C=180-75-50=55° and c -9 and
we need to find a,
substituting value
a/Sin(75°)=9/Sin(55°)
a=9*Sin(75°)/Sin(55°)
a=10.61
Therefore, the value of a is 10.6
Answer:
Question 29: Angle of Elevation is -------> 59.0°Question 30: The length of side A in --------> △ABC is approximately 10.3Step-by-step explanation:Question 29: In this question, we can use the tangent function to solve the problem. We can set the Sun's elevation angle as theta (θ). Then we can get the equation:
tan (θ) = 20/12, and solve for θ
Solve the problem:We can draw a right triangle with the tree, the shadow, and the Sun.The tree's height is the opposite side, and the length of the shadow is the adjacent side.The angle of the sun's elevation is the angle between the ground and the line from the top of the tree to the sun.We can set the angle of elevation of the sun as theta (θ).We then get the equation tan (θ) = 20/12
We can solve for theta (θ) using the equationθ = arctan(5/3)
We can use a calculator to find that: Let the angle of elevation = θTan θ = opp/adj
Tan θ = 20/12
θ = Tan^-1 (20/12)
θ = 59.03624346 degrees
θ = 59.0 degrees
Draw the conclusion:Hence, the Angle of Elevation is -------> 59.0°
Question 30: △
m < C = 180 degrees - m<A - m<B
m<C = 180 degrees - 75 degrees - 50 degrees
Simplify:
m<C = 55 degrees
Apply the Law of Sines:
a/sin A = c/sin C
Substitute the values:
a/sin 75 degrees = 9/sin 55 degrees
Solve for A:
a = 9 * sin 75 degrees/sin 55 degrees
Calculate the value of A:a = 10.3
Draw a conclusion:Therefore, The length of side A in --------> △ABC is approximately 10.3
Hope this helps you!
HELP DUE IN 3 DAYS!!!!! Which symbol should go in the box to make the equation true, and why? (1 point) the fraction two fourths followed by a box followed by the fraction four eighths a >, because the fraction two fourths is equal to the fraction eight eighths. b >, because the fraction two fourths is equal to the fraction six eighths. c =, because the fraction four eighths is equal to the fraction two fourths. d =, because the fraction four eighths is equal to the fraction two halves.
The correct answer is c) =, because the fraction four eighths is equal to the fraction two fourths.
To determine which symbol should go in the box to make the equation true, let's analyze the fractions given and compare their values.
The fraction "two fourths" can be simplified to "one-half" since both the numerator and denominator can be divided by 2. Therefore, "two fourths" is equal to "one-half."
Now, let's look at the fraction "four eighths." We can simplify this fraction by dividing both the numerator and denominator by 4, which gives us "one-half" as well. So, "four eighths" is also equal to "one-half."
Now, based on the given fractions, we have the equation:
(one-half) [BOX] (one-half)
We need to determine the correct symbol to fill in the box.
Looking at the values of the fractions, we see that both "two fourths" and "four eighths" are equivalent to "one-half." Therefore, the correct symbol to make the equation true is the equality symbol (=).
Hence, the correct answer is:
c) =, because the fraction four eighths is equal to the fraction two fourths.
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7
What fraction of the shape is shaded?
18 mm
10 mm
12 mm
The shaded fraction of the shape is 2/3.
To determine the fraction of the shape that is shaded, we need to compare the shaded area to the total area of the shape.
1. Identify the shaded region in the shape. In this case, we have a shape with some part shaded.
2. Calculate the area of the shaded region. Given the dimensions provided, the area of the shaded region is determined by multiplying the length and width of the shaded part. In this case, the dimensions are 18 mm and 10 mm, so the area of the shaded region is (18 mm) × (10 mm) = 180 mm².
3. Calculate the total area of the shape. The total area of the shape is determined by multiplying the length and width of the entire shape. In this case, the dimensions are 18 mm and 12 mm, so the total area of the shape is (18 mm) × (12 mm) = 216 mm².
4. Determine the fraction. To find the fraction, divide the area of the shaded region by the total area of the shape: 180 mm² ÷ 216 mm². Simplifying this fraction gives us 5/6.
5. Convert the fraction to its simplest form. By dividing both the numerator and denominator by their greatest common divisor, we get the simplified fraction: 2/3.
Therefore, the fraction of the shape that is shaded is 2/3.
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find the inverse of each function
Answer:
Step-by-step explanation:
Afiq. Bala and Chin played a game of marbles. Before the game, Bala had fewer marbles than Afig and Chinhad?
- as many marbles as Bala.
After the game, Balahad lost 20% of his marbles to Chinwhile Afig had lost
3
of his marbles to Chin. Chingained 105 marbles at the end of the
game.
(a)How many marbles didChinhave after the game?
(b)After the game, the 3 children each bought another 40 marbles. How manymarbles did the 3 children have altogether?
(a) Chin had 93.1 marbles after the game.
(b) The three children had a total of 271.44 marbles altogether.
Let's break down the problem step by step to find the answers:
Initial marbles
Before the game:
Let's assume Afiq had x marbles.
Bala had 1/6 fewer marbles than Afiq, so Bala had (x - 1/6x) marbles.
Chin had 3/5 as many marbles as Bala, so Chin had (3/5)(x - 1/6x) marbles.
After the game
After the game, Bala lost 20% of his marbles to Chin, so he has 80% (or 0.8) of his initial marbles remaining.
Afiq lost 2/3 of his marbles to Chin, so he has 1/3 (or 0.33) of his initial marbles remaining.
Calculating the marbles
(a) How many marbles did Chin have after the game?
To find Chin's marbles after the game, we add the marbles gained from Bala to Chin's initial marbles and the marbles gained from Afiq to Chin's initial marbles.
Chin's marbles = Initial marbles + Marbles gained from Bala + Marbles gained from Afiq
Chin's marbles = (3/5)(x - 1/6x) + 0.8(x - 1/6x) + 0.33x
Chin's marbles = (3/5)(5x/6) + 0.8(5x/6) + 0.33x
Chin's marbles = (3/6)x + (4/6)x + 0.33x
Chin's marbles = (7/6)x + 0.33x
We are given that Chin gained 105 marbles, so we can equate the equation above to 105 and solve for x:
(7/6)x + 0.33x = 105
(7x + 2x) / 6 = 105
9x / 6 = 105
9x = 105 * 6
x = (105 * 6) / 9
x = 70
Substituting the value of x back into the equation for Chin's marbles:
Chin's marbles = (7/6)(70) + 0.33(70)
Chin's marbles = 10(7) + 0.33(70)
Chin's marbles = 70 + 23.1
Chin's marbles ≈ 93.1
Therefore, Chin had approximately 93.1 marbles after the game.
(b) After the game, the 3 children each bought another 40 marbles. To find the total number of marbles the 3 children have altogether, we need to sum up their marbles after the game and the additional 40 marbles for each.
Total marbles = Afiq's marbles + Bala's marbles + Chin's marbles + Additional marbles
Total marbles = 0.33x + 0.8(x - 1/6x) + (7/6)x + 40 + 40 + 40
Total marbles = 0.33(70) + 0.8(70 - 1/6(70)) + (7/6)(70) + 120
Total marbles = 23.1 + 0.8(70 - 11.7) + 81.7 + 120
Total marbles = 23.1 + 0.8 × 58.3 + 201.7
Total marbles = 23.1 + 46.64 + 201.7
Total marbles = 271.44
The three children had a total of 271.44 marbles altogether.
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Question
Afiq. Bala and Chin played a game of marbles. Before the game, Bala had 1/ 6 fewer marbles than Afig and Chinhad 3/5 as many marbles as Bala.
After the game, Balahad lost 20% of his marbles to Chinwhile Afig had lost
2/3 of his marbles to Chin. Chingained 105 marbles at the end of the
game.
(a)How many marbles didChinhave after the game?
(b)After the game, the 3 children each bought another 40 marbles. How manymarbles did the 3 children have altogether?
Ship A receives a distress signal from the northeast, and ship B receives a distress
signal from the same vessel from the west. At what location is the vessel in distress
located? Describe how you arrived at your conclusion using complete sentences. You
must show all work in order to receive credit. (10 points)
3
2
A
NE
12pt
13
W
B
Edit View Insert Format Tools
Paragraph
B T
Table
U
D
The vessel in distress is located at (-x, y), with the exact coordinates depending on the specific distances and positions of ships A and B.
To determine the location of the vessel in distress, we can analyze the information given about the distress signals received by ships A and B.
Ship A received a distress signal from the northeast, while Ship B received a distress signal from the west.
Let's consider the compass directions:
Northeast (NE) is a direction that lies between north and east.
West (W) is a direction perpendicular to both north and south.
From this information, we can deduce that the vessel in distress must be located at the intersection of the northeast and west directions.
To find this intersection point, we can draw a diagram or use a coordinate system. Let's assume the origin (0,0) represents the starting point of both ships A and B.
Based on the given information, we know that ship A received a distress signal from the northeast. This means that the vessel in distress must be located in the direction of the positive x-axis (east) and the positive y-axis (north) from the origin.
On the other hand, ship B received a distress signal from the west. This indicates that the vessel in distress must be located in the direction of the negative x-axis (west) from the origin.
Combining these two pieces of information, we can conclude that the vessel in distress is located at the point where the positive y-axis (north) intersects with the negative x-axis (west). In coordinate notation, this point can be represented as (-x, y), where x and y are positive values.
Therefore, the vessel in distress is located at (-x, y), with the exact coordinates depending on the specific distances and positions of ships A and B.
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the population in Knox is 42000 and it is declining at a rate of 3.2% per year predict the population to the nearest whole number after 8 years
The predicted population of Knox, rounded to the nearest whole number, after 8 years is 32,599.
To predict the population of Knox after 8 years, we can use the given information that the population is currently 42,000 and it is declining at a rate of 3.2% per year.
To calculate the population after 8 years, we need to apply the rate of decline for each year. Let's break down the calculation step by step:
Calculate the population after the first year:
Population after 1 year = 42,000 - (3.2% of 42,000)
= 42,000 - (0.032 * 42,000)
= 42,000 - 1,344
= 40,656
Calculate the population after the second year:
Population after 2 years = 40,656 - (3.2% of 40,656)
= 40,656 - (0.032 * 40,656)
= 40,656 - 1,299.71
= 39,356.29
Continue this process for each year up to 8 years, applying the 3.2% rate of decline each time.
After performing these calculations for each year, we arrive at the population after 8 years:
Population after 8 years ≈ 32,599
Therefore, the predicted population of Knox, rounded to the nearest whole number, after 8 years is 32,599.
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Which of the following lists of ordered pairs is a function?
The list of ordered pairs that is a function is Option D.
What is a Math Function?A math function is a relationship that assigns a unique output value to each input value. It describes how one quantity depends on another.
Functions are commonly represented using mathematical notation, such as f(x), and they play a fundamental role in various areas of mathematics and its applications.
A function is a relation in which one input (x-value) is assigned to exactly one output (y-value).
Since option D's x-values do not repeat, then it is a function.
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joan’s finishing time for the bolder boulder 10k race was 1.81 standard deviations faster than the women’s average for her age group. there were 410 women who ran in her age group. assuming a normal distribution, how many women ran faster than joan? (round down your answer to the nearest whole number.)
Yesterday, Noah ran 2 1/2 miles in 3/5 hour. Emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour. How fast, in miles per hour, did each person run? Who ran the fastest?
Anna ran the fastest with a speed of approximately 4.67 miles per hour.
To find the speed at which each person ran, we can use the formula: Speed = Distance / Time.
Let's calculate the speed for each person:
Noah:
Distance = 2 1/2 miles
Time = 3/5 hour
Speed = (2 1/2) / (3/5)
= (5/2) / (3/5)
= (5/2) [tex]\times[/tex] (5/3)
= 25/6 ≈ 4.17 miles per hour
Emily:
Distance = 3 3/4 miles
Time = 5/6 hour
Speed = (3 3/4) / (5/6)
= (15/4) / (5/6)
= (15/4) [tex]\times[/tex] (6/5)
= 9/2 = 4.5 miles per hour
Anna:
Distance = 3 1/2 miles
Time = 3/4 hour
Speed = (3 1/2) / (3/4)
= (7/2) / (3/4)
= (7/2) [tex]\times[/tex] (4/3)
= 14/3 ≈ 4.67 miles per hour
Based on the calculations, Noah ran at a speed of approximately 4.17 miles per hour, Emily ran at a speed of 4.5 miles per hour, and Anna ran at a speed of approximately 4.67 miles per hour.
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1/3 : 1/4 ratio as a fraction
Answer:
4/3
Step-by-step explanation:
1/3:(1/4) = (1/3)/(1/4) = 1/3*4 = 4/3
What is the equation in point slope form of the line that is perpendicular to the given line and passes through the point(2,5)?
Answer:
Step-by-step explanation:
To find the equation of a line that is perpendicular to a given line and passes through a specific point, we need to follow a few steps:
Find the slope of the provided line.
The point-slope form of a line is given by: y - y1 = m(x - x1), where (x1, y1) represents the given point.
Substituting the values, the equation of the perpendicular line becomes:
y - 5 = (-1/m)(x - 2)
Simplifying the equation further, we can rewrite it in point-slope form:
y - 5 = (-1/m)x + (2/m)
Solve each equation.
13x+91-30
OX= 7
Ox= 1,-19
O no solution
Ox=7,-13
DONE
Intro
12x+11--13
O no solution
Ox=-7
Ox=-14, 12
OX=-7,6
DONE
ODL
IX+21+4-11
O
X = 5
no solution
Ox=5,-9
Ox=7,-11
DONE
The solutions to the absolute value equations are:
1. b. x = 1, -19. 2. a. no solution. 3. c. x = 5, -9.
How to Solve Absolute Value Equations?1. |3x+9| = 30
To solve this equation, we isolate the absolute value expression by considering two cases: 3x+9 = 30 and -(3x+9) = 30. Solving both equations, we find x = 7 and x = -19, respectively. Thus, the answer is b. x = 1, -19.
2. |2x+11| = -13
An absolute value cannot be negative, so there is no solution to this equation. The answer is a. no solution.
3. |x + 2| + 4 = 11
To solve this equation, we isolate the absolute value expression by subtracting 4 from both sides, resulting in |x + 2| = 7. Considering two cases: x + 2 = 7 and -(x + 2) = 7, we solve for x and find x = 5 and x = -9, respectively. Thus, the answer is c. x = 5, -9.
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according to the general equation probability, if p(A∩B) =3/7 and p(B)= 7/8 , what is P(A\B)?
The probability of event A occurring given that event B has not occurred (P(A\B)) is 0.
To find P(A\B), we need to calculate the probability of event A occurring given that event B has not occurred. In other words, we want to find the probability of A happening when B does not happen.
The formula to calculate P(A\B) is:
P(A\B) = P(A∩B') / P(B')
Where B' represents the complement of event B, which is the event of B not occurring.
Given that P(A∩B) = 3/7 and P(B) = 7/8, we can find P(A∩B') and P(B') to calculate P(A\B).
To find P(B'), we subtract P(B) from 1, since the sum of the probabilities of an event and its complement is always equal to 1.
P(B') = 1 - P(B)
= 1 - 7/8
= 1/8
Now, to find P(A∩B'), we need to subtract P(A∩B) from P(B'):
P(A∩B') = P(B') - P(A∩B)
= 1/8 - 3/7
= 7/56 - 24/56
= -17/56
Since the probability cannot be negative, we can conclude that P(A∩B') is 0.
Finally, we can calculate P(A\B) using the formula:
P(A\B) = P(A∩B') / P(B')
= 0 / (1/8)
= 0
Therefore, the probability of event A occurring given that event B has not occurred (P(A\B)) is 0.
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The results of an analysis, on the makeup of garbage, done by the Environmental Protection Agency was published in
1990. Some of the results are given in the following table, which for various years gives the number of pounds per
person per day of various types of waste materials.
Waste materials
Glass
Plastics
Metals
Paper
1960
0.20
0.01
0.32
0.91
1970
0.34
0.08
0.38
1.19
1980
0.36
0.19
0.35
1.32
1988
0.28
0.32
0.34
1.60
For metal, calculate the average rate of change between 1980 and 1988. Then interpret what this value means.
a. From 1980 to 1988, the number of pounds of c. From 1980 to 1988, the number of pounds of
metal per person per day decreased by
metal per person per day decreased by
0.125 per year.
0.00125 per year.
b. From 1980 to 1988, the number of pounds d. From 1980 to 1988, the number of pounds
of metal per person per day decreased by
0.071 per year.
of metal per person per day increased by
0.01 per year.
The average rate of change for the number of pounds of metal per person per day between 1980 and 1988 is -0.00125 pounds per year.
To calculate the average rate of change for the number of pounds of metal per person per day between 1980 and 1988, we need to find the difference in the values and divide it by the number of years.
In 1980, the pounds of metal per person per day was 0.35, and in 1988, it was 0.34. The difference between these values is -0.01.
The number of years between 1980 and 1988 is 1988 - 1980 = 8 years.
Now, we can calculate the average rate of change:
Average rate of change = (Change in pounds of metal) / (Number of years)
= (-0.01) / 8
= -0.00125
The average rate of change for the number of pounds of metal per person per day between 1980 and 1988 is -0.00125 pounds per year.
Interpretation:
The negative value of the average rate of change (-0.00125) indicates that there was a decrease in the number of pounds of metal per person per day from 1980 to 1988.
Specifically, on average, there was a decrease of approximately 0.00125 pounds per year.
This suggests that there was a declining trend in the use or disposal of metal waste during this period.
It could indicate improvements in recycling or waste management practices, or a shift in consumer behavior towards reducing metal waste.
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HELP PLESSE
The total cost of a lunch is shared among 8 people. the total bill is 55 what is the cost
Answer: A,
Step-by-step explanation:
8 people, times whatever each person payed will equal to 55$ in total
There are 6 horses in a race. How many ways can the first three positions of the order of the finish occur assume there are no ties
Which expression is equivalent to a18a6
Answer:
[tex]\textsf{B.} \quad a^{12}[/tex]
Step-by-step explanation:
To simplify the given rational expression, we can apply the rule of exponents, which states that when dividing two powers with the same base, we subtract the exponents.
Using this rule:
[tex]\dfrac{a^{18}}{a^{6}}= a^{18-6} = a^{12}[/tex]
Therefore, the given rational expression is equivalent to a¹².
determine where there is a minimum or maximum value to the quadratic function. h(t)=-8t^2+4t-1. Find the minimum or maximum value of h
To determine whether there is a minimum or maximum value to the quadratic function h(t) = -8t² + 4t - 1 and find the minimum or maximum value of h, one has to follow the steps given below. So, the minimum or maximum value of h = -1/2.
Step 1: Write the quadratic function in standard form.
The standard form of a quadratic function is f(x) = ax² + bx + c, where a, b, and c are constants.
h(t) = -8t² + 4t - 1 ... (1)
Step 2: Calculate the axis of symmetry of the parabola.
The axis of symmetry of the parabola is given by x = -b/2a, where a and b are the coefficients of x² and x, respectively. Therefore, the axis of symmetry of the parabola given by h(t) = -8t² + 4t - 1 is given by: t = -b/2a = -4/(2 * (-8)) = 4/16 = 1/4
Step 3: Calculate the vertex of the parabola.
The vertex of the parabola is given by (h, k), where h and k are the coordinates of the vertex. Therefore, the coordinates of the vertex of the parabola given by h(t) = -8t² + 4t - 1 are given by: (1/4, h(1/4))
Substituting t = 1/4 in Equation (1), we have: h(1/4) = -8(1/4)² + 4(1/4) - 1h(1/4) = -8/16 + 4/4 - 1h(1/4) = -1/2 + 1 - 1h(1/4) = -1/2
Therefore, the vertex of the parabola given by h(t) = -8t² + 4t - 1 is given by the point(1/4, -1/2)
Step 4: Determine the nature of the extrema of the functionThe coefficient of the x² term in Equation (1) is -8, which is negative. Therefore, the parabola is downward-facing and the vertex represents a maximum value. Thus, the maximum value of the function h(t) = -8t² + 4t - 1 is given by h(1/4) = -1/2. Answer: Thus, the minimum or maximum value of h = -1/2.
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A = –5(6t – 7) + 11. B = 3(x – 5) – 3(x + 5).
B = 8 + 2y – 5(2y – 6) + 4.
C = –5z + 5z(z – 3) – 7(6 – 8z).
Answer: the answer is 110.8
Step-by-step explanation: add um all up
PLEASE I NEED HELP I DONT UNDERSTAND THIS
two points A and B, due to two spheres X and Y 4.0m apart, that are carrying charges of 72mC and -72mC respectively. Assume constant of proportionality as 9×10^9Nm²/C². Find the electric field strength at points A and B due to each spheres presence
Point B: Electric field strength due to sphere X = 2073.6 NC⁻¹ and Electric field strength due to sphere Y = -2073.6 NC⁻¹.
data: Spheres X and Y are 4.0 m apart. The charge on sphere
X = + 72 mC = 72 × 10⁻³ C.
The charge on sphere
Y = -72 mC = -72 × 10⁻³ C.
The constant of proportionality = 9 × 10⁹ Nm²/C².
The formula to calculate the electric field strength due to a point charge is
E = k q / r²
where E is the electric field strength, k is the Coulomb's constant (= 9 × 10⁹ Nm²/C²), q is the magnitude of the charge, and r is the distance from the charge.The electric field due to sphere X at point A is
EaX = [tex]k q / r²where r = 4.0 m, q = + 72 × 10⁻³ CSo, EaX = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaX = 9 × 9 × 2 × 2 × 2 × 2 / 10[/tex]EaX = 2592 / 10EaX = 259.2
NC⁻¹The electric field due to sphere Y at point A is
[tex]EaY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ CSo, EaY = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaY = -9 × 9 × 2 × 2 × 2 × 2 / 10EaY = -2592 / 10EaY = -259.2[/tex]
NC⁻¹The electric field due to sphere X at point B is
[tex]EbX = k q / r²where r = 4.0 m, q = + 72 × 10⁻³ C + 72 × 10⁻³ C = 144 × 10⁻³ C.So, EbX = 9 × 10⁹ × 144 × 10⁻³ / (4.0)²EbX = 9 × 9 × 4 × 4 × 4 × 4 / 10EbX = 20736 / 10EbX = 2073.6[/tex]
NC⁻¹The electric field due to sphere Y at point B is
[tex]EbY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ C - 72 × 10⁻³ C = -144 × 10⁻³ C. So, EbY = 9 × 10⁹ × -144 × 10⁻³ / (4.0)²EbY = -9 × 9 × 4 × 4 × 4 × 4 / 10EbY = -20736 / 10EbY = -2073.6 NC⁻¹[/tex]
Therefore, the electric field strength at points A and B due to each sphere's presence are: Point A: Electric field strength due to sphere X = 259.2 NC⁻¹ and Electric field strength due to sphere Y = -259.2 NC⁻¹.
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