Select the correct answer. What is the solution to this equation? 9^x - 1 = 2 O A. - 1/1/20 OB. 2 O C. OD. 1/1/20 1 23 Edmentum. All rights reserved. Reset Next​

Answer:

Step-by-step explanation:

add it then subtract the value

The expression/equation as written in the question is ∠A ≈ ∠C

From the question, we have the following parameters that can be used in our computation:

∠A ≈ ∠C

The above expression means that

The angles A and C are congruent

From the question, we understand that

The question is not to be solved; we only need to write out the expression

Hence, the expression/equation as written is ∠A ≈ ∠C

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The numerical value of x in the minor arc KU of the circle is 7.

The inscribed angle theorem states that an angle x inscribed in a circle is half of the central angle 2x that subtends the same arc on the circle.

It is expressed as:

Internal angle = 1/2 × ( major arc + minor arc )

From the diagram:

Internal angle = 122 degrees

Major arc = 194 degrees

Minor arc = ( 6x + 8 )

Plug these values into the above formula and solve for x:

Internal angle = 1/2 × ( major arc + minor arc )

122 = 1/2 × ( 194 + ( 6x + 8 ) )

Multiply both sides by 2:

122 × 2 = 2 × 1/2 × ( 194 + ( 6x + 8 ) )

122 × 2 =( 194 + ( 6x + 8 ) )

244 = 194 + 8 + 6x

244 = 202 + 6x

6x = 244 - 202

6x = 42

x = 42/6

x = 7

Therefore, the value of x is 7.

Option B) 7 is the correct answer,

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Only Graph A satisfies the criteria for a density curve, making it the correct answer.

Graph A represents a density curve because the area under the curve equals 1, and the curve is above the horizontal axis. In a density curve, the total area under the curve represents the probability, and it should always equal 1.

This indicates that the curve represents a probability distribution, where the probability of an event occurring within a certain range is given by the area under the curve within that range.

The fact that the curve is above the horizontal axis indicates positive values, which is consistent with a density curve representing a probability distribution.

On the other hand, Graph B does not represent a density curve because the area under the curve equals 2, which is not valid for a probability distribution. The area under a density curve should always equal 1, indicating that the total probability is accounted for.

As a result, only Graph A meets the requirements for a density curve, making it the right response.

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Answer:

Only one scalene triangle with side lengths of 12 in, 15 in, and 18 in exists. Therefore, exactly one unique triangle exists with the given side lengths.

Step-by-step explanation:

Answer:

1. linear equation

2. linear equation

3. algebraic equation

Step-by-step explanation:

1. The expression 20x + 14y + 6z represents a linear equation with three variables: x, y, and z. It consists of three terms: 20x, 14y, and 6z. The coefficients of these terms are 20, 14, and 6 respectively. This equation represents a plane in a three-dimensional coordinate system, where the variables x, y, and z determine the position on the plane.

2. The expression 6x + 2y represents a linear equation with two variables: x and y. It consists of two terms: 6x and 2y. The coefficients of these terms are 6 and 2 respectively. This equation represents a straight line in a two-dimensional coordinate system, where the variables x and y determine the position on the line.

3. The expression 1/2(6n - 12m) represents an algebraic equation with two variables: n and m. It consists of one term: 6n - 12m. The coefficient of this term is 1/2. This equation represents a relationship between the variables n and m, where n and m could be any real numbers.

Triangles ZWN and ZXY are similar by the SAS congruence theorem.

The Side-Angle-Side (SAS) congruence theorem states that if two sides of two similar triangles form a proportional relationship, and the angle measure between these two triangles is the same, then the two triangles are congruent.

In this problem, we have that the angle Z is equals for both triangles, and the two sides between the angle Z, which are ZW = ZY and ZV = ZX, form a proportional relationship.

Hence the SAS theorem holds true for the triangle in this problem.

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The solutions to the equation (cosec(x)+2)(2cos(x)-1) are x = -π/6 + 2πn, 7π/6 + 2πn, x = π/3 + 2πn, 5π/3 + 2πn.

To solve the given equation, we can make use of zero-product property. The zero-product property states that if the product of the two factors is equal to zero, then one of the factors has to be equal to zero. So, now we will equate each factor to zero to find the solution.

1. (cosec(x)+2) = 0

 = cosec(x) = -2

 Taking reciprocal on both the sides:

 = 1/cosec(x) = -1/2

 = sin(x) = -1/2

The solutions for sin(x) = -1/2 occur when x = -π/6 + 2πn and 7π/6 + 2πn, where 'n' is an integer.

2. (2cos(x)-1) = 0

 = 2cos(x) = 1

 = cos(x) = 1/2

The solutions for  cos(x) = 1/2 occur when  x = π/3 + 2πn and 5π/3 + 2πn, where 'n' is an integer.

Therefore, the solutions to the equation (cosec(x)+2)(2cos(x)-1) are x = -π/6 + 2πn, 7π/6 + 2πn, x = π/3 + 2πn, 5π/3 + 2πn.

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The complete question is: Find out the possible solutions of the equation (cosecx+2)(2cosx-1)=0.

Answer:

be more clear of what u mean edit the question and explain more of u mean

Answer:

  (b)  7

Step-by-step explanation:

You want to find the value of x in the figure where chords that cross at an angle of 122° intercept arcs of 195° and (6x+8)°.

The angle where the chords cross is half the sum of the measures of the intercepted arcs:

  (194° +(6x +8)°)/2 = 122°

  101 +3x = 122 . . . . . . . . . . divide by °, simplify

  3x = 21  . . . . . . . . . . . subtract 101

  x = 7 . . . . . . . . . . divide by 3

The value of x is 7.

__

Additional comment

The measure of arc KU is 50°.

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49.87 because I searched it up

The range of the rational function in this problem is given as follows:

All real values. (fourth option).

From the graph of the function given by the image presented at the end of the answer, it assumes all values of y, hence the range is all real values.

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The number of paperback copies sold is 366,300.

Let's solve the problem :

Calculate the number of hardback copies sold.

We are given that 35,000 hardback copies were sold before the paperback version was issued.

Calculate the number of paperback copies sold.

From the time the first paperback copy was sold until the last copy of the novel was sold, nine times as many paperback copies as hardback copies were sold.

Let's assume the number of hardback copies sold is H.

Therefore, the number of paperback copies sold would be 9H.

Set up the equation for the total number of copies sold.

The problem states that a total of 442,000 copies of the novel were sold in all. We can set up the equation as follows:

H + 9H + 35,000 = 442,000

Solve the equation for H.

Combining like terms, we have:

10H + 35,000 = 442,000

10H = 442,000 - 35,000

10H = 407,000

H = 40,700.

Calculate the number of paperback copies sold.

We already know that the number of paperback copies sold is 9 times the number of hardback copies sold.

Therefore, the number of paperback copies sold would be:

9H = 9 [tex]\times[/tex] 40,700 = 366,300

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Answer:

80

Step-by-step explanation:

Answer:25.12

Step-by-step explanation:

Use the second equation

C = 8(3.14) = 25.12

Answer:

Area = 50.24 feet²

Circumference = 25.12 feet

Step-by-step explanation:

If the circle's diameter is 8 feet, then the radius will be 4 feet.

A=4²(3.14)

=16(3.14)

=50.24

C=2π(4)

C=8π

C≅25.12

The correct answer is option (e): None of these answers is correct.

The statement "the mode is the most frequently occurring data value" is true. However, none of the options provided accurately describes the relationship between the mode and the mean.

The mode and the mean are different measures of central tendency and can have different values. There is no general rule or guarantee that the mode will always be larger or smaller than the mean. The relationship between the mode and the mean depends on the specific dataset and its distribution. Therefore, none of the provided options correctly describes the relationship between the mode and the mean.

The first question:

"A spinner has an equal chance of landing on each of its eight numbered regions. After spinning, what is the probability you land on region three and region six?"

Since the spinner has an equal chance of landing on each of its eight regions, the probability of landing on region three is 1/8, and the probability of landing on region six is also 1/8.

To find the probability of both events occurring (landing on region three and region six), you multiply the probabilities together:

P(landing on region three and region six) = P(landing on region three) * P(landing on region six) = (1/8) * (1/8) = 1/64.

Therefore, the probability of landing on both region three and region six is 1/64.

The events are mutually exclusive because it is not possible for the spinner to land on both region three and region six simultaneously.

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The second question:

"A bag contains six yellow jerseys numbered 1-6. The bag also contains four purple jerseys numbered 1-4. You randomly pick a jersey. What is the probability it is purple or has a number greater than 5?"

To find the probability of either event occurring (purple or number greater than 5), we need to calculate the probabilities separately and then add them.

The probability of picking a purple jersey is 4/10 since there are four purple jerseys out of a total of ten jerseys.

The probability of picking a jersey with a number greater than 5 is 2/10 since there are two jerseys numbered 6 and above out of a total of ten jerseys.

To find the probability of either event occurring, we add the probabilities together:

P(purple or number greater than 5) = P(purple) + P(number greater than 5) = (4/10) + (2/10) = 6/10 = 3/5.

Therefore, the probability of picking a purple jersey or a jersey with a number greater than 5 is 3/5.

The events are overlapping since it is possible for the jersey to be both purple and have a number greater than 5.

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The third question:

"A box of chocolates contains six milk chocolates and four dark chocolates. Two of the milk chocolates and three of the dark chocolates have peanuts inside. You randomly select and eat a chocolate. What is the probability that it is a milk chocolate or has no peanuts inside?"

To find the probability of either event occurring (milk chocolate or no peanuts inside), we need to calculate the probabilities separately and then add them.

The probability of selecting a milk chocolate is 6/10 since there are six milk chocolates out of a total of ten chocolates.

The probability of selecting a chocolate with no peanuts inside is 7/10 since there are seven chocolates without peanuts out of a total of ten chocolates.

To find the probability of either event occurring, we add the probabilities together:

P(milk chocolate or no peanuts inside) = P(milk chocolate) + P(no peanuts inside) = (6/10) + (7/10) = 13/10.

Therefore, the probability of selecting a milk chocolate or a chocolate with no peanuts inside is 13/10.

The events are mutually exclusive since a chocolate cannot be both a milk chocolate and have no peanuts inside simultaneously.

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The fourth question:

"You flip a coin and then roll a fair six-sided die. What is the probability the coin lands heads up and the die shows an even number?"

The probability of the coin landing heads up is 1/2 since there are two possible outcomes (heads or tails) and they are equally likely.

The probability of rolling an even number on the die is 3

/6 or 1/2 since there are three even numbers (2, 4, and 6) out of a total of six possible outcomes.

To find the probability of both events occurring (coin lands heads up and die shows an even number), we multiply the probabilities together:

P(coin lands heads up and die shows an even number) = P(coin lands heads up) * P(die shows an even number) = (1/2) * (1/2) = 1/4.

Therefore, the probability of the coin landing heads up and the die showing an even number is 1/4.

The events are independent since the outcome of flipping the coin does not affect the outcome of rolling the die.

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♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

The measure of the indicated angle formed by a secant and tangent line is 61 degrees.

The outside or external angles theorem states that "the measure of an angle formed by two secant lines, two tangent lines, or a secant line and a tangent line from a point outside the circle is half the difference of the measures of the intercepted arcs.

It is expressed as;

External angle = 1/2 × ( x - y )

From the diagram:

Intercepted arc GE = y = 73°

Intercepted arc HE = x = 195°

External angle GFE = ?

Plug the given values into the above formula and solve for the indicated angle:

External angle = 1/2 × ( x - y )

External angle GFE = 1/2 × ( 195 - 73 )

External angle GFE = 1/2 × 122

External angle GFE = 61°

Therefore, the outside angle is 61 degrees.

Option C) 61° is the correct answer.

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Answer:

Step-by-step explanation:

x + 2-3

|x ≥ 1

|x + 2 ≤ -3

x + 22 -6

X = 4√6 because the tangent of 35 degrees is equal to X/8 in the first right triangle and 12/X in the second right triangle.

We have two right triangles with an angle of 35 degrees and side lengths of 8 units and 12 units.

To explain why X = 12, we can use the trigonometric ratio of tangent (tan). In a right triangle, the tangent of an angle is defined as the ratio of the length of the opposite side to the length of the adjacent side.

In the first right triangle, the side opposite to the angle of 35 degrees is X, and the adjacent side is 8 units. So, we have:

tan(35 degrees) = X / 8

Similarly, in the second right triangle, the side opposite to the angle of 35 degrees is 12 units, and the adjacent side is X. So, we have:

tan(35 degrees) = 12 / X

Since the tangent of an angle is the same regardless of the orientation of the triangle, we can equate the two ratios:

X / 8 = 12 / X

To solve for X, we can cross-multiply:

X^2 = 8 * 12

X^2 = 96

Taking the square root of both sides, we get:

X = √96

Simplifying, we have:

X = 4√6

Therefore, X is equal to 4 times the square root of 6.

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The cost of Donna's club membership exhibits a non-proportional relationship over time.

The cost of Donna's club membership can be analyzed to determine whether it exhibits a proportional or non-proportional relationship over time.

In this scenario, Donna pays a monthly fee of $80, along with a yearly membership fee of $60.50. To assess the proportionality, we can examine how the cost changes relative to time.

In a proportional relationship, the cost would increase or decrease at a constant rate. For example, if the monthly fee remained constant, the total cost would be directly proportional to the number of months of membership.

However, in this case, the presence of a yearly membership fee indicates a non-proportional relationship.

The yearly membership fee of $60.50 is a fixed cost that Donna incurs only once per year, regardless of the number of months she remains a member.

As a result, the cost is not directly proportional to time. Instead, it has a fixed component (the yearly fee) and a variable component (the monthly fee).

In summary, the cost of Donna's club membership exhibits a non-proportional relationship over time. While the monthly fee is a constant amount, the yearly membership fee introduces a fixed cost that is independent of the duration of her membership.

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Using the z-statistic relation given, the value of the z-statistic in the scenario would be 0.61

The Z-statistic relation is written thus:

phat = 140 / 200 = 0.7

p = 0.68

q = 1 - p = 0.32

n = 200

Inputting the values into our formula

z = (phat - p) / sqrt(p * q / n)

= (0.7 - 0.68) / sqrt(0.68 * 0.32 / 200)

= 0.02 / 0.0583

= 0.61

Therefore, Z-statistic is 0.61

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The equation of the line in standard form is 3x + y - 4 = 0.

To find the equation of a line passing through two points, we can use the slope-intercept form of a linear equation, which is given by y = mx + b, where m is the slope and b is the y-intercept.

Given the points S(, 1) and T(, 4), we need to determine the slope (m) and the y-intercept (b).

The slope (m) can be found using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.

Substituting the values, we get:

m = (4 - 1) / ( - ) = 3 / ( - ) = -3

Now that we have the slope, we can substitute it into the equation y = mx + b and use one of the given points to solve for the y-intercept (b).

Using the point S(, 1):

1 = (-3)(1) + b

1 = -3 + b

b = 4

Therefore, the equation of the line passing through the points S and T is:

y = -3x + 4

Converting it to standard form Ax + By + C = 0, we rearrange the equation:

3x + y - 4 = 0

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The probability of randomly selecting either a diamond or a 3 from the bag is 100%.

Random selection refers to the process of selecting elements from a group with equal probability of selection.

Probability is a measure of the likelihood of an event occurring, which is usually expressed as a fraction or a decimal.

When it comes to random selection of a diamond or 3, we can use probability to determine the likelihood of either event occurring.

For instance, suppose we have a bag containing 10 numbered balls: 5 of them are diamonds and 5 are threes.

To find the probability of randomly selecting a diamond, we divide the number of diamonds by the total number of balls: P(Diamond) = Number of diamonds/ Total number of balls = 5/10 = 0.5 or 50%

This means that the probability of randomly selecting a diamond from the bag is 50%.

To find the probability of selecting either a diamond or a 3, we add the probability of selecting a diamond to the probability of selecting a 3, since the events are mutually exclusive: P(Diamond or 3) = P(Diamond) + P(3) = 5/10 + 5/10 = 1

This means that the probability of randomly selecting either a diamond or a 3 from the bag is 100%.

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The row operation on the matrix [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex] is [tex]\left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The row operation is given as

1/2R₁

This means that we divide the entries on the first row by 2

Using the above as a guide, we have the following:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

Hence, the row operation on the matrix is [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

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