A 'array palindrome' is an array which, when its elements are reversed, remains the same (i.e., the elements of the array are same when scanned forward or backward) Write a recursive, boolean-valued method, isPalindrome, that accepts an integer-valued array, and a pair of integers representing the starting and ending indexes of the portion of the array to be tested for being a palindrome. The function returns whether that portion of the array is a palindrome. An array is a palindrome if: the array is empty (0 elements) or contains only one element (which therefore is the same when reversed), or the first and last elements of the array are the same, and the rest of the array (i.e., the second through next-to-last elements) form a palindrome.

Answer:

I believe it is the Second Option as all the others are correct.

Answer:

player1Wins = player1Losses = player2Wins = player2Losses = tieCount = 0

score1 = 10

score2 = 10

if score1>score2:

   player1Wins=player1Wins+1

   player2Losses=player2Losses+1

   print("player1 wins")

elif score2>score1:

   player2Wins=player2Wins+1

   player1Losses=player1Losses+1

   print("player2 wins")

else:

   tieCount=tieCount+1

   print("tie")

Explanation:

Since your indentation can not be understand what you give us, please try to do it as you see in the answer part.

Although it seems that this is a part of the code, it is normal that you get errors. However, since you keep track of the variables, it is better to initialize the variables that will keep the counts. Since initially, they are 0, you may set them as 0. Also, if you assign the values to the scores, probably you would not get any error. This way, you may test your code as I did.

Other than these, in the else part you do not need to write "score1=score2", because if score1 is not greater than score2 and if score2 is not greater than score1, this already implies that they are equal

Answer:

Here is the Python program:

import math #import math to use mathematical functions

height = float(input("Enter wall height (feet): ")) #prompts user to enter wall height and store it in float type variable height

width = float(input("Enter wall width (feet): ")) #prompts user to enter wall width and store it in float type variable width

area = height *width #computes wall area

print('Wall area: {} square feet'.format(round(area))) #displays wall area using round method that returns a floating-point number rounded

sqftPerGallon = 350 #sets sqftPerGallon to 350

paintNeeded = area/ sqftPerGallon #computes needed paint

print("Paint needed: {:.2f} gallons".format(paintNeeded)) #displays computed paint needed up to 2 decimal places

cansNeeded = int(math.ceil(paintNeeded)) #computes needed cans rounding the paintNeeded up to nearest integer using math.ceil

print("Cans needed: {} can(s)".format(cansNeeded)) #displays computed cans needed

colorCostDict = {'red': 35, 'blue': 25, 'green': 23} #creates a dictionary of colors with colors as key and cost as values

color = input("Choose a color to paint the wall: ") #prompts user to enter a color

if color in colorCostDict: #if the chosen color is present in the dictionary

    colorCost = colorCostDict.get(color) #then get the color cost from dictionary and stores it into colorCost using get method that returns the value(cost) of the item with the specified key(color)

    cost = cansNeeded * colorCost #computes the cost of purchasing paint of specified color per cansNeeded

  print("Cost of purchasing {} paint: ${}".format(color,colorCostDict[color])) #displays the real cost of the chosen color paint

print("Cost of purchasing {} paint per {} gallon can(s): ${}".format(color,cansNeeded, cost)) #displays the cost of chosen color paint per cans needed.

Explanation:

The program first prompts the user to enter height and width. Lets say user enter 20 as height and 50 as width so the program becomes:

Wall area computed as:

area = height *width

area = 20 * 50

area = 1000

Hence the output of this part is:

Wall area: 1000 square feet                                                                                                                     Next program computes paint needed as:

paintNeeded = area/ sqftPerGallon

Since sqftPerGallon = 350 and area= 1000

paintNeeded = 1000 / 350

paintNeeded = 2.86

Hence the output of this part is:

Paint needed: 2.86 gallons

Next program computes cans needed as:      

cansNeeded = int(math.ceil(paintNeeded))

This rounds the computed value of paintNeeded i.e. 2.86 up to nearest integer using math.ceil so,

cansNeeded = 3                                                                  

Hence the output of this part is:

Cans needed: 3 can(s)                                                                                                                            Next program prompts user to choose a color to paint the wall

Lets say user chooses 'blue'

So the program get the cost corresponding to blue color and multiplies this cost to cans needed to compute the cost of purchasing blue paint per gallon cans. So

cost = cansNeeded * colorCost

cost = 3 * 25

cost = 75

So the output of this part is:

Cost of purchasing blue paint per 3 gallon can(s): $75                                                                                        The screenshot of the program along with its output is attached.

Answer:

Written in Python

print("Enter the first 9 digits: ")

d1 = int(input())

d2 = int(input())

d3 = int(input())

d4 = int(input())

d5 = int(input())

d6 = int(input())

d7 = int(input())

d8 = int(input())

d9 = int(input())

d10 = (d1 * 1+ d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9)%11

if d10 == 10:

                                   print(str(d1)+str(d2)+str(d3)+str(d4)+str(d5)+str(d6)+str(d7)+str(d8)+str(d9)+"X")

else:

                                   print(str(d1)+str(d2)+str(d3)+str(d4)+str(d5)+str(d6)+str(d7)+str(d8)+str(d9)+str(d10))

Explanation:

This line prompts user for input

print("Enter the first 9 digits: ")

The next 9 line gets the first 9 ISBN digits

d1 = int(input())

d2 = int(input())

d3 = int(input())

d4 = int(input())

d5 = int(input())

d6 = int(input())

d7 = int(input())

d8 = int(input())

d9 = int(input())

This calculates the checksum

d10 = (d1 * 1+ d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9)%11

The if condition prints the ISBN number by replacing the last digit with X if the checksum is 10 else it appends the original digits

if d10 == 10:

                                   print(str(d1)+str(d2)+str(d3)+str(d4)+str(d5)+str(d6)+str(d7)+str(d8)+str(d9)+"X")

else:

                                   print(str(d1)+str(d2)+str(d3)+str(d4)+str(d5)+str(d6)+str(d7)+str(d8)+str(d9)+str(d10))

what tha hell is that my bad i try lol im so dumb it is what it is

Answer:

1. in compatible adaptor

2. bad cable

3. software issues

4. damaged laptop battery

Explanation:

there are several reasons why this might be happening.

if this message is being displayed it means that the adaptor may not be compatible. this implies that it is spoilt or the laptop just needs to be shutdown. if this fails, then adaptor needs replacing.

the adaptor cable itself may be faulty and needs changing. the laptop's battery may be too old or damaged and needs replacing. also the laptop may be having software issues and needs updating.

Answer:

B. grants

Explanation: This is the correct answer on Edge 2021, just did the assignment. Hope this helps ^-^.

Answer:

what Is your question?

Answer:

after you are accepted in the college

Explanation:

You should apply for admission to the colleges you are interested in BEFORE filing your FAFSA. Once you are accepted to the colleges you have applied to, you can add those schools to receive financial aid award offers from when you file your FAFSA.

Answer:

Read faster

Explanation:

Technology inspires learners to learn as well. They keep trying to figure time to discover and learn stuff from blogs , videos, applications, and games on their computers. At the very same time, kids will understand and have pleasure, which lets them keep involved with the subject.

Answer:

ITS NOT B I THOUGHT IT WAS BUT DO NOT PUT B I PUT B AND GOT THE QUESTION WRONG

Explanation:

DONT PUT B just trying to help idk the answer but not b

Answer:

Attend traings

Explanation:

Because if you do you can learn diffent waay to do it and choose your way that you like.

ANd do not obseve poeple who has it easy  

the answers are:

- ask a supervisor’s opinion

- ask coworkers’ opinions

- attend trainings offered by the company

Answer:

HTML

Explanation:

HTML stands for "Hypertext Markup Language." It allows the creation of electronic documents which use semantics to indicate a particular text. The different HTML elements are being separated by "angle brackets" in order to make up a tag. These tags are not visible, but they make it possible for the browser's page to be interpreted.

Answer:

HTML

Explanation:

According to the Modern Language Association (MLA) guidelines, the correct line spacing for a document is double-spacing. This means that there should be a full blank line between each line of text in the document. Hence, option A is the correct answer.

Double spacing helps improve readability and makes it easier for readers to distinguish between different lines of text. It also allows for better legibility and makes it easier to add annotations or comments to the document.

It's important to note that the MLA guidelines may change over time, so it's always a good idea to consult the most recent edition of the MLA Handbook or check with your instructor or institution for any specific requirements regarding line spacing or formatting.

Hence, option A is the correct answer.

Learn more about MLA here:

brainly.com/question/32131813

#SPJ6

Answer:

B. double-clicking on the trendline after it's added

Explanation:

I did the assignment on edge 2020

A format trendline task pane is a task pane that is used to format or change the settings of a trendline in a chart. The correct option is B.

A format trendline task pane is a task pane that is used to format or change the settings of a trendline in a chart.

The easiest way to access the format trendline task pane for an inserted trend line is to double-click on the trendline after it is added. A preview of the Format trendline task pane is attached below. Therefore, the correct option is B.

Learn more about Task Pane:

https://brainly.com/question/20360581

#SPJ2

Answer:

\frac is the shortcut for inserting fraction in ms-word

e.g of a/b = \frac {a}{b}

Answer: i dont now

Explanation:

Answer:

The pseudocode is as follows

1. Input Steps

2. Input Day

3. Miles = Steps/2000

4. Calories = 65 * Miles

5. Print Calories

6. Stop

Explanation:

This line gets the number of steps for the day

1. Input Steps

This line gets the current day

2. Input Day

The line calculates number of miles

3. Miles = Steps/2000

This line calculates the calories lost

4. Calories = 65 * Miles

This line prints the calories lost

5. Print Calories

The pseudocode ends here

6. Stop

Answer:

Explanation:

Answer:

Here is the JAVA program :

import javax.swing.JOptionPane;   //to use JOptionPane  

public class Main {   //class name

public static void main(String[] args) { //start of main method

   int ECount= 0;   //counts number of upper case E

   int eCount= 0;  //counts number of lower case e

   String sentence;   //stores input sentence string

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit)");  //uses showInputDialog method to display a dialog box which prompts user to enter a sentence

 int length = sentence.length();  //stores the length of the sentence

 while (!sentence.equalsIgnoreCase("stop"))  //the loop continues to execute until the user types stop

{ for (int i = 0; i < length; i++) { //loops through the sentence

             if (sentence.charAt(i) == 'E')  //if the character is an uppercase E

                  ECount += 1;  //adds 1 to the count of Ecount

             if (sentence.charAt(i) == 'e')  //if the character in a sentence is lowercase e

                  eCount += 1;}  //adds 1 to the count of lower case e

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + "  number of e's in " +sentence);   //displays the number of times uppercase and lowercase (E and e) occur in sentence

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit");  //prompts user to enter the next sentence

length = sentence.length();  //stores the length of sentence at each iteration of while loop until user enters stop

eCount=0;  //resets the counter of lowercase e

ECount=0;  } } } //resets the counter of uppercase e

Explanation:

The program uses showInputDialog() method that displays a dialog box on output screen. This dialog box prompts the user to enter a string (sentence) Suppose user enters "Evergreen" as input sentence so

sentence = "Evergreen"

Next the length of this string is computed using length() method and stored in length variable. So

length = sentence.length();

length = 9

The for loop iterates through this input sentence until the variable i is less than length i.e. 9

At first iteration

if (sentence.charAt(i) == 'E') becomes

if (sentence.charAt(0) == 'E')

Here charAt() method is used which returns the character at the specified index i. This if condition is true because the character at 0-th index (first character) of the sentence Evergreen is E. So ECount += 1; statement adds 1 to the count of upper case E so

ECount = 1

At second iteration:

if (sentence.charAt(1) == 'E')

this condition is false because the character at 1st index of sentence is 'v' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is also false because the character is not a lower case e either.

At third iteration:

if (sentence.charAt(2) == 'E')

this condition is false because the character at 2nd index of sentence is 'e' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is true because the character is a lower case e. So the statement eCount += 1; executes which adds 1 to the count of e.

eCount = 1

So at each iteration the sentence is checked for an upper case E and lower case e. After the loop breaks, the program moves to the statement:

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + "  number of e's in " +sentence);

which displays the number of uppercase E and lower case e in a message dialog box. So the output is:

There are 1 number of E's and 3 number of e's in Evergreen.

Then because of while loop user is prompted again to enter a sentence until the user enters "stop". Now the user can enter Stop, StOp, STOp etc. So equalsIgnoreCase method is used to cover all upper/lower case possibilities of the word "stop".

The screenshot of the program and its output is attached.

Answer:

Throughout the interpretation portion below, this same overview of the look at various is summed up.

Explanation:

The cybersecurity architecture as well as concepts are required to ensure websites and software apps from perpetrators that aim to interrupt, pause, modify, or redirect data flow.

This term in something like a program describes a set of data or orders that deserve security outside a program, a field of duty or regulation could be a domain.

A process seems to be a program that runs on a computer, and each process seems to have a memory region.

There are several tools for a machine. The memory, hard drive, communication overhead, battery life, or a display may have been a commodity.

In a machine, a privilege is another permission for the operator to operate on controlled machine property.

A layer seems to be a different step in the sense of information protection that really should be penetrated by an offender to break a device.

Abstraction has been the idea that it is possible to think about something complex and difficult as well as encompass it more obviously.

Answer:

D

Explanation:

Answer:

I believe it is D

Explanation:

Answer:

Its D

Explanation:

Answer:

Probably Wi-Fi or a network but if you need more specific i'm not sure

Explanation:

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <cstring>  // used to manipulate c strings

using namespace std;  //to identify objects cin cout

const int SIZE = 20;  //fixes constant size for firstName, middleName and lastName arrays

const int FULL_SIZE = 60;  //constant size for fullName array

int main() {  //start of main method

  char firstName[SIZE]; //declares a char type array to hold first name

  char middleName[SIZE];//declares a char type array to hold middle name

  char lastName[SIZE]; //declares a char type array to hold last name

  char fullName[FULL_SIZE]; //declares a char type array to hold full name

  cout << "Enter first name: ";  //prompts user to enter first name

  cin>>firstName;  //reads first name from user, stores it in firstName char array

  cout << "Enter middle name: ";  //prompts user to enter middle name

  cin>>middleName;  //reads middle name from user, stores it in middleName char array

  cout << "Enter last name: ";  //prompts user to enter last name

  cin>>lastName;  //reads last name from user, stores it in lastName array

  strcpy(fullName, lastName);  //copies last name from lastName to fullName array using strcpy method which copies a character string from source to destination

  strcat(fullName, ", ");  //appends comma "," and empty space " " after last name in fullName using strcat method which appends a string at the end of another string

  strcat(fullName, firstName);  //appends first name stored in firstName to the last of fullName

  strcat(fullName, " ");  //appends an empty space to fullName

  strcat(fullName, middleName);  //appends middle name stored in middleName char array to the fullName char array

  cout <<"Full name is:\n"<<fullName<< endl; } //displays the full name

Explanation:

I will explain the program with an example inshaAllah

Lets say user enters Carol as first name, Lynn as middle and Smith as last name. So firstName char array contains Carol, middleName char array contains Lynn and lastName char array contains Smith.

Next the fullName array is declared to store Carol Lynn and Smith in a specific format:

strcpy(fullName, lastName);

This copies lastName to fullName which means fullName now contains Smith.

  strcat(fullName, ", ");

This appends comma and an empty space to fullName which means fullName now contains Smith with a comma and empty space i.e. Smith,

strcat(fullName, firstName);

This appends firstName to fullName which means Carol is appended to fullName which now contains Smith, Carol

  strcat(fullName, " ");

This appends an empty space to fullName which means fullName now contains Smith, Carol with an empty space i.e. Smith, Carol

 strcat(fullName, middleName);

This appends middleName to fullName which means Lynn is appended to fullName which now contains Smith, Carol Lynn

Now    cout <<"Full name is:\n"<<fullName<< endl; prints the fullName so the output of this entire program is:

Full name is:                                                                                                                                  

Smith, Carol Lynn

The screenshot of the program along with its output is attached.

Answer: I’m sorry, but what is your question? Then, I may be able to help you. Also, add a link (image)!

Explanation: Thank You!

Answer:

Hi! There has to be two answers to your question. That is the only way you are able to give a brainliest. You can give a brainliest if you believe a person who wrote an answer to your question fully detailed and organized. It has to answer your question.

Hope this helps! :D

Explanation:

hope it is helpful to you

Answer:

Sometimes called the press junket or film junket, film promotion generally includes press releases, advertising campaigns, merchandising, franchising, media and interviews with the key people involved with the making of the film, like actors and directors.

Explanation:

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    int n;

    double side;

    char choice;

    while(true){

        System.out.print("Enter the number of sides: ");

     n = input.nextInt();

     System.out.print("Enter the side of a regular polygon: ");

     side = input.nextDouble();

     System.out.println("Area is: " + area(n, side));

     System.out.print("Do you want to continue(y/n): ");

     choice = input.next().charAt(0);

     if(choice == 'n')

         break;

    }

}

public static double area(int n, double side){

    double area = (n * Math.pow(side, 2) / (4 * Math.tan(Math.PI / n)));

    return area;

}

}

Explanation:

Create a function named area that takes two parameters, n and side

Calculate the area using the given formula

Return the area

In the main:

Create an indefinite while loop. Inside the loop:

Ask the user to enter the n and side

Call the area() function passing the n and side as parameters and print the result

Ask the user to continue or not. If the user enters "n", stop the loop

Answer:

Written in Python

import random

N = int(input("Enter number of questions I need to ask: "))

if N >2 and N < 11:

    signs = ['+', '-', '*', '/']

    correct = 0

    for i in range(1,N+1):

         num1 = random.randint(1,101)

         num2 = random.randint(1,101)

         sign = random.choice(signs)

         print(str(i)+":) "+str(num1)+" "+sign+" "+str(num2)+" = ")

         res = int(input(""))

         if sign == '+':

              result = num1 + num2

         elif sign == '-':

              result = num1 - num2

         elif sign == '*':

              result = num1 * num2

         elif sign == '/':

              result = num1 / num2

         if result == res:

              correct = correct + 1

    print("Your success rate is "+str(round(correct * 100/N))+"%")

Explanation:

I've added the source program as an attachment where I used comments to explain difficult lines