The amount of radioactive substance has decreased from 467.8 ng to 58.48 ng after 47 days, so 2.5 half-lives have occurred.
A radioactive isotope's half-life is the amount of time it takes for one half of the radioactive isotope to decay. A specific radioactive isotope's half-life is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.
Half-life = 47/2.5 = 18.8 days
Decrease in Radioactive Substance = 467.8 - 58.48 = 409.32
Half-life amount = 409.32/2.5 = 163.728
Number of half-lives = 409.32/163.728 = 2.5
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Container A holds 747 mL747 mL of ideal gas at 2.90 bar2.90 bar . Container B holds 119 mL119 mL of ideal gas at 4.30 bar4.30 bar . If the gases are allowed to mix together, what is the partial pressure of each gas in the total volume
the partial pressure of gas A in the total volume is 3.57 bar, and the partial pressure of gas B in the total volume is 0.70 bar.
When the gases are allowed to mix together, the total pressure of the mixture is equal to the sum of the partial pressures of each gas. The partial pressure of each gas is equal to the product of the total pressure and the mole fraction of that gas. To find the mole fraction of each gas, we first need to find the number of moles of each gas. The number of moles of gas in container A is given by PV/RT where P is the pressure, V is the volume, R is the ideal gas constant and T is the temperature.
n_A = (2.90 bar * 747 mL) / (8.314 J/molK * (273.15 + 23)) = 0.0295 mol
The number of moles of gas in container B is given by PV/RT
n_B = (4.30 bar * 119 mL) / (8.314 J/molK * (273.15 + 23)) = 0.0045 mol
The total number of moles of gas in the mixture is the sum of the number of moles of gas in container A and container B.
n_total = n_A + n_B = 0.0295 mol + 0.0045 mol = 0.0340 mol
The mole fraction of gas A in the mixture is the number of moles of gas A divided by the total number of moles of gas.
x_A = n_A / n_total = 0.0295 mol / 0.0340 mol = 0.8735
The mole fraction of gas B is
x_B = n_B / n_total = 0.0045 mol / 0.0340 mol = 0.1324
The partial pressure of gas A is equal to the total pressure multiplied by the mole fraction of gas A.
P_A = (0.8735) * (2.90 bar + 4.30 bar) = 3.57 bar. The partial pressure of gas B is equal to the total pressure multiplied by the mole fraction of gas B. P_B = (0.1324) * (2.90 bar + 4.30 bar) = 0.70 bar
So the partial pressure of gas A in the total volume is 3.57 bar, and the partial pressure of gas B in the total volume is 0.70 bar.
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3. A student placed artificial cells, each containing a 25% sugar solution, into three different beakers containing sugar solution which varied in concentration from 0% to 25%. The setups are shown below. The student collected data on the mass of each artificial cell. The student predicted that the cell in the beaker with 25% sugar solution would have the greatest change in mass after 24 hours. Would his prediction be correct? Support your answer.
The student collected data on the mass of each artificial cell. The student predicted that the cell in the beaker with 25% sugar solution would have the greatest change in mass after 24 hours. The student's prediction would be correct.
Why would the prediction of the experiment be correct?The artificial cell placed in the beaker with 25% sugar solution would likely have the greatest change in mass after 24 hours because of osmosis.
Osmosis is the movement of water across a semi-permeable membrane from an area of high water concentration to an area of low water concentration. In this case, the artificial cell has a semi-permeable membrane that allows water to pass through, but not sugar.
The 25% sugar solution in the beaker is less concentrated than the sugar solution inside the artificial cell, so water will move from the beaker into the cell, causing the cell to swell and increase in mass.
On the other hand, the artificial cells in the beakers with 0% and 12.5% sugar solutions will have less of a change in mass as the solution outside of the cell is more concentrated than inside the cell.
Therefore, the correct answer is as given above
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CAN SOMEONE OR SOMEBODY HELP ME ASAP
Answer: ahem...
Explanation: 1. True 2. reproducing 3. All of them 4. i would say true, the only thing is plants dont really digest food and it says "all" organisms... 5. B, C, and D...A is more of defense and not really "maintaining structure"
How many cm is meter stick?
100 cm is meter stick.
Centimeter is denoted by the (cm). It is a metric unit of the measurement which is used for measuring the length of an object.
Meterstick is a foldable ruler which is used to measure the length, and it is common in the construction industry. They are made up of wood or plastic and often they have a plastic or metal joints so that they can be folded together.
A meter measuring stick, which is one meter (39.37 inches) long, it contains 100 centimeters. Thus, centimeter is equal to one-hundredth of a meter. The word centimeter comes from the late 18th-century. The word centimeter derived from the Latin root "centum"/ means "hundred" and the Greek root "metron", meaning "measure".
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1. In your own words, differentiate absorption, reflection, refraction.
2. Compare/Contrast Sound Waves and Light Waves.
FOR 20 POINTS
Answer:
Reflection: reflection is the process of returning of light into the same medium after striking a surface.
Which of the following would be a reasonable unit for the rate constant of a second order reaction?
1. mol/L.sec
2. mol2/sec.L2
3. 1/sec
4. L/mol.sec
5. L2/mol2.sec
Option (4) is correct. The rate constant of a second order reaction has the unit L/mole. sec.
In the Second order reaction the rate is proportional to the square of the concentration of one reactant. Rate of Second order reaction is proportional to the product of the concentrations of two reactants. Such reactions generally have the form,
A + B → products.
Each monomer combines to form a larger molecule is called dimer. For the units of the reaction rate to be moles per liter per second (M/s), the units of a second-order rate constant must be the inverse (M−1·s−1). Because the units of molarity are expressed as mole/L, the unit of the rate constant can also be written as L(mole ·s).
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A calibrated flask was filled to the 25.00 mL mark with ethyl alcohol. By weighing the flask before and after adding the alcohol, it was determined that the flask contained 19.7325 g of alcohol. In a second experiment, 25.1060 g of metal beads were added to the flask, and the flask was again filled to the 25.00 mL mark with ethyl alcohol . The total mass of the metal plus alcohol in the flask was determined to be 38.6794 g.
The density of the metal beads, given that total mass of the metal plus alcohol in the flask was determined to be 38.6794 g is 3.22 g/mL
How do I determine the density of the metal beads?We'll begin by obtaining the density of the alcohol in the flask with the metal beads. This is illustrated below:
Mass of alcohol = 19.7325 gVolume of alcohol = 25 mLDensity = ?Density = mass / volume
Density of alcohol = 19.7325 / 25
Density of alcohol = 0.7893 g/mL
Next, we shall determine the volume of the alcohol in the 25 mL flask. This can be obtained as follow:
Density of alcohol = 0.7893 g/mLMass of metal beat = 25.1060 gTotal mass of metal beat and alcohol = 38.6794 gMass of alcohol in flask = 38.6794 - 25.1060 = 13.5734 gVolume of alcohol in flask =?Volume = mass / density
Volume of alcohol in flask = 13.5734 / 0.7893
Volume of alcohol in flask = 17.2 mL
Finally, we shall determine the density of the metal beads. Details below:
Mass of metal beat = 25.1060 gVolume of alcohol in flask = 17.2 mLVolume of flask = 25 mLVolume of metal beads = 25 - 17.2 = 7.8 mLDensity of metal beads =?Density = mass / volume
Density of metal beads = 25.1060 / 7.8
Density of metal beads = 3.22 g/mL
Thus, we can conclude that the density of the metal beads is 3.22 g/mL
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Complete question:
A calibrated flask was filled to the 25.00 mL mark with ethyl alcohol. By weighing the flask before and after adding the alcohol, it was determined that the flask contained 19.7325 g of alcohol. In a second experiment, 25.1060 g of metal beads were added to the flask, and the flask was again filled to the 25.00 mL mark with ethyl alcohol . The total mass of the metal plus alcohol in the flask was determined to be 38.6794 g. What is the density of the metal in g/mL?
What were the 3 missing elements in the periodic table?
The three missing elements in the periodic table are gallium, germanium and scandium.
Gallium, germanium, and scandium have been all unknown in 1871, however, Mendeleev left areas for every and expected their atomic loads and different chemical properties. Within 15 years, the “lacking” factors have been discovered, conforming to the simple traits Mendeleev had recorded. Scientists in Japan suppose they have eventually created the elusive detail 113, one of the lacking gadgets at the periodic table of factors. Element 113 is an atom with 113 protons in its nucleus — a kind of depend that should be created inner a laboratory as it isn't always located evidently on Earth.
The elements are gallium, germanium and scandium.
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How many grams of water (H2O) will be produced from 96.0 grams of oxygen (O2)?
i need a fast answer pls !
Answer & Explenation:
2H2 + O2 -> 2H20 is the balanced equation for the reaction of Hydrogen with Oxygen to form water so
If you have 32g of O2 this is a simple Dimensional analysis problem
32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced. Just a different way to view and solve the problem with the balanced equation so you can see the way everything relates to everything else. the molar masses of O2 and H2O are simply found my adding up 2 Oxygens 15.9994g x2 = 31.9988g and H2O = 2(1.00794) + 15.9994 = 18.01258 but you then have to multiply that by 2 because the reaction states you get 2 mols in the reaction so that is where I came up with the 36.03056g for the solution. Hope this helps. Dimensional Analysis is and can be one of the best ways to solve these problems, because not always are you going to be dealing with 1:2 ratios.
There are 20 mg of cromolyn sodium in 2 ml of normal saline. What is the percentage strength of the solution
The percentage strength of the solution is 1%.
According to question,
we are given that the 20mg of cromolyn sodium in 2 ml of normal saline is taken.
Now, to find the percentage strength first know the meaning of percentage strength.
The amount of solute dissolved in gram per liter of the solution is used to determine the solution's strength. It stands for the solution's potency or concentration. It uses gram per liter of expression.
Now here we are given the the mass and volume connection so we have to find the percentage in terms of it.
percentage strength=[tex]\frac{mass}{volume} *100[/tex]
percentage strength=[tex]\frac{0.020*100}{2}[/tex]
on solving we get,
percentage strength=1%
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A relationship between two organisms that benefits both organisms is called
A. symbiosis
B.mutualis
C. commensalism
D.parasitism
Answer:
Mutualism
Explanation:
A relationship in which both benefit
select the correct structure that corresponds to the name 4-chloro-3-ethyl-2-hexene
Answer:
Its A
Explanation:
The structure that corresponds to the name 4-chloro-3-ethyl-2-hexenebased on IUPAC nomenclature is option A is correct.
What is IUPAC nomenclature and structure?In organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
The Word root of the name indicates the number of carbon atoms in the longest possible continuous carbon chain also known as the parent chain stucture.
The primary suffix structure is used to indicate the degree of saturation or unsaturation in the main chain. A secondary suffix is used to indicate the main functional group in the organic structure and is added immediately.
The 1o suffix in the name and the prefix are used to indicate the side chains, substituents, and low-priority functional groups which are considered as substituents.
Therefore, the name is 4-chloro-3-ethyl-2-hexene option A is correct.
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calculate the mass of .00566 mol of germanium, show work.
Iron is often found joined to another element. What is this element
Answer:
It combines vigorously with chlorine on mild heating and also with a variety of other nonmetals, including all of the halogens, sulfur, phosphorus, boron, carbon, and silicon (the carbide and silicide phases play major roles in the technical metallurgy of iron). Metallic iron dissolves readily in dilute mineral acids.
Explanation:
Iron is the chemical species that is the most used metal and is often found attached to the chlorine element.
What is the chemical reactivity of iron?Iron metals react with many elements and are an abundant element in the Earth's crust. It combines with the chlorine element when subjected to mild heating.
Along with chlorine it also reacts with halogen groups, carbon, sulfur, silicon, etc. This application is used in the metallurgy of iron.
Therefore, iron is joined to chlorine.
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Element X has a charge of +2 and Element Y has a charge of -1.
Give the formula that would form between Element X and Element Y. Enter the subscripts needed to complete the formula.
X ____ Y _____
the chemical equation will be XY2
What type of reaction is Fe+H2O=Fe3O4+H2
Answer:
single replacement
Explanation:
it's when one element starts out by itself, then replaces another element in a compound, kicking it out
Answer: This is a chemical reaction
Explanation: Hope this helps:)))
A 2.317 gram sample of an oxide of iron was found to contain 1.677 grams of iron and 0.640 grams of oxygen. What is the simplest formula for this compound?
The simplest formula for a compound is made up of 1.677 grams of iron and 0.640 grams of oxygen would be FeO.
Empirical formulaWhat the question is asking here is the empirical formula of an oxide of iron made up of 1.677 grams of iron and 0.640 grams of oxygen. The empirical formula shows the formula in the simplest whole-number ratio of the atoms.
Iron (Fe) = 1.677 grams
Oxygen (O) = 0.640 grams
Converting the masses to moles:
Fe = 1.677/56 = 0.0299 mol
O = 0.640/16 = 0.0400 mol
Now, let's divide by the smallest mole:
Fe = 0.0299/0.0299 = 1.0
O = 0.0400/0.0299 = 1.3
Thus, the empirical formula of the oxide of iron is FeO.
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True or false: Energy and matter are the same thing.
Answer:
yes they are same thing by E=MC^2 EINSTEIN'S EQUATION
Answer:
True.
Explanation:
The mass of these three particles is less than the mass of a neutron, so they each get some energy as well. So energy and matter are really the same thing. Completely interchangeable. And finally, Although energy and mass are related through special relativity, mass and space are related through general relativity.
So energy and matter are really the same thing. Completely interchangeable. And finally, Although energy and mass are related through special relativity, mass and space are related through general relativity. ... So in a way, energy, matter, space and time are all aspects of the same thing.
Identify the 13 c nmr chemical shift for each carbon atom in a molecule of 1-penten-3-one
Carbon 1: δ = 2.09 ppm (The C1 atom is a methyl group, and is in a tertiary environment, which typically corresponds to a chemical shift of around 2.09 ppm).
What is chemical shift?Chemical shift is a term used in NMR spectroscopy to describe the relative difference in the resonance frequency of a nucleus in a molecule compared to a reference frequency.
2. Carbon 2: δ = 11.81 ppm (This is the carbonyl carbon, and is in a sp2 hybridized environment, which typically corresponds to a chemical shift of around 11.81 ppm).
3. Carbon 3: δ = 13.92 ppm (This is the terminal carbon of the pentene chain, and is in a sp3 hybridized environment, which typically corresponds to a chemical shift of around 13.92 ppm).
4. Carbon 4: δ = 16.53 ppm (The C4 atom is a methylene group, and is in a secondary environment, which typically corresponds to a chemical shift of around 16.53 ppm).
5. Carbon 5: δ = 17.86 ppm (The C5 atom is a quaternary carbon, and is in a sp3 hybridized environment, which typically corresponds to a chemical shift of around 17.86 ppm).
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How many atoms are in 1.4 moles of Cadmium?
Answer:
Answer Below
Explanation:
Answer: 8.4322×1024atoms atoms are in 1.4 moles of cadmium. Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes.
Answer:
The answer is 8.4308 × 10²³ atoms
Explanation:
Multiply by Avogadro's number (Nₐ)
Nₐ = 6.022 × 10²³ mol⁻¹
Now,
1.4 × 6.022 × 10²³ = 8.4308 × 10²³
Thus, 8.4308 × 10²³ atoms are in 1.4 moles of Cadmium.
Which statement is TRUE about liquid and gases? *
a. They have both definite shape.
b. They have both definite volume
c. Their particles are incompressible
d. They assume the shape of container.
Answer:
The Answer is gonna be d. They assume the shape of container
This is the right Answer
I hope you are having a great day :3
A sample of n2o gas has a density of 3.10 g/l at 298 k.what must be the pressure of the gas (in mmhg)?
P=___mmHg
The pressure of N2O gas at a density of 3.10 g/L and a temperature of 298 K is 751 mmHg. To calculate the pressure of the N2O gas at a given density and temperature, we can use the ideal gas law: PV = nRT.
We know that the density of the gas is 3.10 g/L, and the temperature is 298 K. To find the pressure, we can assume that the volume of the gas is 1 L, and solve for pressure. where P is the pressure of the gas, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
The density of a gas can be converted to moles using the formula:
Density = m/V
m = Density*V
Now we can use the ideal gas law to calculate the pressure:
P = (mRT)/V
R is the ideal gas constant = 0.0821 L atm K^-1 mol^-1
P = (3.10g0.0821 L atm K^-1 mol^-1298 K)/1 L
P = 751 mmHg
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is vinegar an example of an element or compound?
Answer:
Hey mate.....
Explanation:
This is ur answer....
Vinegar is a compound and a mixture, being mainly acetic acid (compound)mixed into water (another compound).
Hope it helps!
Brainliest pls!
Follow me! :)
Answer:
Vinegar is an example of a homogeneous mixture, and not a pure substance since water, its solute, is dissolved in the solvent, being acetic acid. Homogeneous mixtures are also known as solutions, which are mostly composed of liquids (including vinegar), but can include gases.
mendeleev is given the most credit for the concept of a periodic table of the elements because:
Mendeleev is given the most credit for the concept of a periodic table of the elements because he emphasized its usefulness in predicting the existence and properties of unknown elements.
What is Periodic table?This is referred to as a tabular arrangement of the chemical elements by increasing atomic number which displays the elements so that one may see trends in their properties.
It consists of a rows and columns arrangement of the chemical elements and each they are grouped according ti the similar features which are present in the elements.
Mendeleev was the scientist who was given the most credit for the concept of a periodic table of the elements despite others working on it previously as a result of his emphasis in its usefulness in predicting the existence and properties of unknown elements.
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An extremely efficient enzyme has a ____ KM and a ____ kcat.
An extremely efficient enzyme has a small KM and a large kcat.
The conversion rate at the lowest substrate concentration is measured in kcat/km. This interpretation is accurate. kcat/Km is a good indicator of an enzyme's effectiveness since it takes into account both the enzyme's maximum rate, kcat, and its affinity for its substrate (Km).The turnover number, or the number of molecules that may be created per second per active site, of an enzyme is provided by the formula k c a t / kM.Because the substrate concentration is almost usually much greater than the Km, in many situations, enzymes are only better when they have a larger kcat. It seems disingenuous to me to use the ratio when this is plainly the case, yet it still happens much too frequently. It could serve as a useful benchmark when compared to enzymes in particular situations.
complete question:An extremely efficient enzyme has a _____ KM and a _____ kcat.
A) small; small
B) small; large
C) large; large
D) large; small
E) kcat and KM do nothing to predict the efficiency of an enzyme
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How do we measure energy of a reaction?
Answer:
joules.
Explanation:
A measure of the total internal heat content.
which could be exothermic or endothermic
what are the two quantities in this module for which we will develop unit factors to do dimensional analysis with chemical substances?
The two quantities in this module for which we will develop unit factors to do dimensional analysis with chemical substances are mass (m) and volume (V).
To calculate the unit factor, we need to divide the unit of the desired quantity by the unit of the given quantity. For example, to convert from mass to volume, the unit factor is V/m.
This unit factor can then be used to convert mass to volume or vice versa. Dimensional analysis helps us to determine the proper units for a given equation and to convert from one unit to another.
It also allows us to compare different units of measurement and to check that the units in both sides of an equation match. This is especially useful in chemical calculations, where it is important to ensure the correct units are used.
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Tylee walked from her parents' farm into town at a steady speed of 10
km/h. The journey took 4 and a half hours. How far did Tylee walk?
2 points
O 14.5 km
451cm
ооо
O 14 m
O 45 m
Answer:
45 km
Explanation:
To find the distance Tylee walked, multiply her speed by the time.
[tex]d=10(4.5)[/tex]
[tex]d =45[/tex]
The distance Tylee walked is 45 kilometers.
I hope this helped :)
Tylee walked 45 km from her parents' farm into town .
What is Speed ?Speed can be understood as the measure of how fast an object is moving.
It is the rate at which an object covers certain distance in fixed amount of time.
It is scalar quantity and its S.I. unit is m/sec .
[tex]\rm Speed = \dfrac{distance}{time}[/tex]
It is given in the question speed = 10 km/h and time = 4.5 hr
So,
[tex]\rm Distance = Speed\; \times\;time[/tex]
[tex]\rm Distance = 10\; \times\;4.5\\\\\rm Distance = 45 \;km\\[/tex]
Therefore Tylee walked 45 km from her parents' farm into town .
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A sample of an unknown substance contains 24. 0 grams of carbon and 2. 0 grams of hydrogen. A sample of another unknown substance contains 24. 0 grams of carbon and 6. 0 grams of hydrogen. Which law does this observation demonstrate
The law that demonstrates this observation is the law of definite proportions.
Law of definite proportion states that a given chemical compound continually incorporates its element factors in constant ratio (with the aid of using mass) and does now no longer rely on its supply and technique of preparation. Law of Definite Proportions states that during a given kind of chemical substance, the factors are continually blended withinside the identical proportions with the aid of using mass. The Law of Definite Proportions applies while factors are reacted collectively to shape the identical product. Such as , a sample of an unknown substance contains 24. 0 grams of carbon and 2. 0 grams of hydrogen.
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A sample of methane collected when the temp was 30 C mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure
A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure
Answer:
434.32mL
Explanation:Using the combined gas law:
[tex]\frac{PV}{T}[/tex] = k
Where;
P = Pressure
V = Volume
T = Temperature
k = constant.
It can be deduced that:
[tex]\frac{P_1V_1}{T_1}[/tex] = [tex]\frac{P_2V_2}{T_2}[/tex] = k ---------------------(i)
Where:
P₁ and P₂ are the initial and final pressures of the given gas
V₁ and V₂ are the initial and final volumes of the given gas
T₁ and T₂ are the initial and final temperatures of the gas.
From the question:
the gas is methane
P₁ = 760mmHg
P₂ = 616mmHg
V₁ = 398mL
V₂ = ?
T₁ = 30°C = (30 +273)K = 303K
T₂ = -5°C = (-5 +273)K = 268K
Substitute these values into equation (i) as follows;
[tex]\frac{760*398}{303}[/tex] = [tex]\frac{616*V_2}{268}[/tex]
Solve for V₂
V₂ = [tex]\frac{760*398*268}{616*303}[/tex]
V₂ = 434.32mL
Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL