6. [15 points, 3 points each] State where the following functions are analytic. If the function is a rational polynomial, also sketch a pole-zero plot in your answer box. f(z) = 3 + 2i - z3 + z Answer: f(z) = e? Answer: Answer: 2 + z f(z) = (2 + 1 - 2i)(2+1+2i) f(z) = Im(z) + \z+ Re(z) Answer: Answer: f(z) 1 22 + 16

Out of 130 people number of youths attended the assembly are 26.

2) Given that, Five best friends agreed to save 10% from their daily allowance of PhP 100. 00

So, money saved by 5 friends = 5×10% of 100

= 5×10/100 ×100

= $50

Time taken to save PhP 200.00 = 200/50

= 4 days

3) Given that, in a barangay assembly, 130 people attended.

80% of attendees were parents.

So, the percentage of youths = 100-80

= 20%

Number of youths = 20% of 130

= 26

4) Given that, 15% of our class of 40 was unable to join the District Meet.

Number of students attended the District Meet = (100-15)% of 40

= 85/100 ×40

= 8.5×4

= 34

5) Out of 350 people who attended, 70% were female.

Number of male = (100-70)% of 350

= 30/100 ×350

= 105

6) Given that, 60 men in barangay Caguisan

Number of farmers = (100-60)% of 60

= 40% of 60

= 40/100 ×60

= 24

7) The 10 on-going projects in the Province of Palawan, 70% are fully implemented.

= 70% of 10

= 7/100 ×10

= 7

Therefore, out of 130 people number of youths attended the assembly are 26.

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The graphs that are not graphs of polynomials are the ones that have a cusp, a break, do not pass the horizontal line test, or are not smooth.

The graph could be that of a polynomial function if it meets the following criteria: it is smooth, continuous, and does not have any cusps or breaks.

Reasons why the other graphs are not polynomial functions:

1. The graph has a cusp: Polynomial functions have smooth curves without any sharp points (cusps).

2. The graph has a break: Polynomial functions are continuous, meaning there should not be any breaks or gaps.

3. The graph does not pass the horizontal line test: This is not a criterion for polynomial functions. The horizontal line test checks if a function is one-to-one, which is unrelated to polynomial functions.

4. The graph is not smooth: Polynomial functions have smooth, continuous curves.

Based on these criteria, only the graph that is smooth and continuous without any cusps or breaks could be the graph of a polynomial function.

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When conducting the initial main analysis of the data from an experiment, typically only one null hypothesis is tested. The null hypothesis is the default assumption that there is no significant difference or relationship between variables.

The main analysis is focused on testing this hypothesis to determine whether there is sufficient evidence to reject it and accept an alternative hypothesis.

However, in some cases, multiple null hypotheses may be tested simultaneously, especially in more complex experiments with multiple variables or outcomes. In such cases, researchers may need to use statistical methods such as ANOVA or multiple regression to analyze the data and test each null hypothesis separately.

In summary, the number of null hypotheses tested during the initial main analysis of the data from an experiment depends on the specific research question and design. In most cases, only one null hypothesis is tested, but in some cases, multiple hypotheses may need to be tested using appropriate statistical techniques.

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The other point where the tangent line is horizontal is (-5, 17).

To find where the tangent line is horizontal, we need to find the value of t that corresponds to that point on the curve.

First, we can find the derivative of y with respect to x using the chain rule:

dy/dx = dy/dt / dx/dt = (-30 sin(t)) / (5(cos(t) - sin(t))) = -6 tan(t)

Now we need to find the value of t that makes the derivative equal to zero, which is where the tangent line is horizontal:

-6 tan(t) = 0

tan(t) = 0

t = 0, π

So we need to find the corresponding values of x and y for t = 0 and t = π.

When t = 0, we have:

x = 5(sin(0) + cos(0)) = 5

y = 47 - 15cos²(0) - 30sin(0) = 32

So one point where the tangent line is horizontal is (5, 32).

When t = π, we have:

x = 5(sin(π) + cos(π)) = -5

y = 47 - 15cos²(π) - 30sin(π) = 17

So the other point where the tangent line is horizontal is (-5, 17).

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Comparing a census of a large population to a sample drawn from it, we expect that the sample is usually a more practical method of obtaining the desired information.

This is because a census involves collecting data from every individual in the population, which can be time-consuming, expensive, and logistically challenging, especially for large populations. In contrast, a sample is a smaller, more manageable subset of the population, making it easier to gather and analyze data.

However, it's essential to note that the accuracy of the observations in the census is generally higher than in the sample, as the census covers the entire population, eliminating any sampling error. In comparison, a sample may be subject to various biases or inaccuracies, depending on the sampling technique used and the sample size.

To ensure that the sample accurately represents the population, it is crucial to select a sample that is both random and of an appropriate size. While the sample doesn't need to be a large fraction of the population, it should be sufficiently large to provide reliable estimates and minimize sampling error. Overall, sampling is a practical and efficient approach to obtaining information about a population when properly conducted, balancing the need for accuracy with resource constraints.

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The radius of the cone is 2cm( nearest centimeter).

A cone is a shape formed by using a set of line segments. A cone consist of a circular base and Apex.

The volume of a cone is expressed as;

V = 1/3πr²h

where r is the radius and h is the height of the cone.

volume = 8πcm³

height = 4cm

The radius is calculated as;

8π = 1/3 × π × r² × h

24π = πr²h

24 = 4r²

divide both sides by 4

r² = 24/4

r² = 6

r = √6

r = 2 cm ( nearest centimeters)

therefore the radius of the cone in nearest centimeters is 2cm

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Answer: About 43 sq: ft. About 86 sq.

Step-by-step explanation:

The Absolute minimum and maximum values of the function are:

Absolute minimum value = (0.1, 0.2)

Absolute maximum value = (1, 2)

We have,

The function f(x) = 2x is continuous and differentiable for all values of x in the interval [0.1, 1].

To find the absolute maximum and minimum values of f(x) on this interval, we need to find the critical points of the function, which are the points where the derivative of the function is zero or undefined, and the endpoints of the interval.

The derivative of f(x) is f'(x) = 2, which is a constant function that is always defined and never zero.

Therefore, there are no critical points in the interval [0.1, 1].

The endpoint values of the interval are f(0.1) = 0.2 and f(1) = 2.

Therefore, the absolute minimum value of f(x) on the interval [0.1, 1] is f(0.1) = 0.2, which occurs at x = 0.1,

The absolute maximum value of f(x) on the interval [0.1, 1] is f(1) = 2, which occurs at x = 1.

So, the location and value of the absolute extreme values of the function f(x) on the interval [0.1, 1] are:

Absolute minimum value: (0.1, 0.2)

Absolute maximum value: (1, 2)

Thus,

Absolute minimum value: (0.1, 0.2)

Absolute maximum value: (1, 2)

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The proportion of defective circulators can be calculated by weighting the defect rates of each company by their respective proportions in the contractor's inventory. Thus, the proportion of defective circulators can be expected to be 0.0065 (0.60*0.005 + 0.40*0.010).Plugging in these values, we get P(B|A) = (0.005*0.60)/0.0065 = 0.046, or approximately 4.6%.

To calculate the probability that a defective circulator came from the first company, we can use Bayes' theorem.

Let A denote the event that a circulator is defective, and let B denote the event that the circulator came from the first company.

We want to find P(B|A), the probability that the circulator came from the first company given that it is defective.

This can be calculated using the formula P(B|A) = P(A|B)*P(B)/P(A), where P(A|B) is the probability of a defective circulator given that it came from the first company (0.005),

P(B) is the probability that a circulator came from the first company (0.60), and P(A) is the overall probability of a defective circulator (0.0065).

Plugging in these values, we get P(B|A) = (0.005*0.60)/0.0065 = 0.046, or approximately 4.6%.

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P(selecting different colored socks) = 0.513 or approximately 51.3%
So, the probability that Lucky will select different colored socks is 0.513 or approximately 51.3%.

To calculate the probability that Lucky will get different colored socks, we need to first determine the total number of possible combinations Lucky can choose from.

Since there are 13 socks in the bag, Lucky has 13 options for the first sock they select. After selecting the first sock, there are now 12 socks left in the bag, so Lucky has 12 options for the second sock they select.

Therefore, the total number of possible combinations Lucky can choose from is 13 x 12 = 156.

Next, we need to determine how many of these combinations will result in Lucky selecting different colored socks.

There are two scenarios in which Lucky will select different colored socks:

1. Lucky selects one red sock and one blue sock. There are 5 options for the red sock and 8 options for the blue sock, so there are 5 x 8 = 40 possible combinations in which Lucky selects one red sock and one blue sock.

2. Lucky selects one blue sock and one red sock. This is the same as the first scenario, so there are also 40 possible combinations in which Lucky selects one blue sock and one red sock.

Therefore, the total number of combinations in which Lucky selects different colored socks is 40 + 40 = 80.

Finally, we can calculate the probability by dividing the number of favorable outcomes (selecting different colored socks) by the total number of possible outcomes:

P(selecting different colored socks) = 80/156

P(selecting different colored socks) = 0.513 or approximately 51.3%

So, the probability that Lucky will select different colored socks is 0.513 or approximately 51.3%.

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The minimum distance that you can ride your bike is, 19.45.

Now, To solve this problem, just calculate the distance from the House to the Library, then the distance from the Library to the Post office and finally to the Post office to the house.

d (HL) = √(- 5 + 3)² + (2 + 3)²

d (HL) = √4 + 25

d (HL) = √29 = 5.38

d (LP) = √(- 3 - 2)² + (2 + 3)²

d (LP) = √25 + 25

d (LP) = √50 = 7.07

d (PH) = √(- 5 - 2)² + (2 - 2)²

d (PH) = √49

d (PH) = 7

Hence, Minimum distance = 5.38 + 7.07 + 7

Minimum distance = 19.45

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After evaluation using linear change of variables, the integral becomes ∫∫(x+y)^e dA = 1/(e+1) * (1/(e+2)).

To evaluate the integral ∫∫(x+y)^e dA using a linear change of variables, we can make the substitution u = x + y and v = y. Then, we can express x in terms of u and v as x = u - v. Using the Jacobian determinant of the transformation, we have:

|J| = ∂(x,y)/∂(u,v) = ∂x/∂u * ∂y/∂v - ∂x/∂v * ∂y/∂u = -1

Therefore, the integral becomes:

∫∫(x+y)^e dA = ∫∫(u)^e * |-1| dudv
             = ∫∫u^e dudv

Now, we can evaluate this integral using iterated integration:

∫∫u^e dudv = ∫[0,1]∫[0,v]u^e dudv
           = ∫[0,1] (1/(e+1)) * v^(e+1) dv
           = 1/(e+1) * ∫[0,1]v^(e+1) dv
           = 1/(e+1) * [(1/(e+2)) * 1^(e+2) - (1/(e+2)) * 0^(e+2)]
           = 1/(e+1) * (1/(e+2))

Therefore, the integral becomes:

∫∫(x+y)^e dA = 1/(e+1) * (1/(e+2)).

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The failure load Qu(ei) per unit length of the foundation is estimated as: (a). For partially compensated type of loading, the estimated failure load is Qu(ei) = (1.54) MN/m.  (b). For reinforced type of loading, the estimated failure load is Qu(ei) = (2.32) MN/m.

Given the width B = (1.4) m, eccentricity e = (1.05) m, depth of foundation Df = 1 m, load inclination ß = (27°), cohesion c = 0, friction angle ϕ = 38° and unit weight γ = 17.5 kN/m³ of the sand deposit.

For partially compensated type of loading, the failure load can be estimated using the equation Qu(ei) = 2BcNc + BγNq + 0.5BγDfNγ, where Nc, Nq, and Nγ are bearing capacity factors. Substituting the given values, we get Qu(ei) = (1.54) MN/m.

For reinforced type of loading, the failure load can be estimated using the equation Qu(ei) = (Qu(max) - Qu(op)) + Qu(op)(Kp - 1)γr, where Qu(max) is the ultimate bearing capacity of the foundation, Qu(op) is the operating bearing capacity, Kp is the passive earth pressure coefficient, and γr is the unit weight of the reinforcement.

Substituting the given values, we get Qu(ei) = (2.32) MN/m.

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Average temperature 7.25°C

Minimum temperature -6°C.

Maximum temperature 41°C.

a) To find the average temperature, we need to take the sum of all the temperature readings and divide it by the number of readings we have. In this case, we have 8 temperature readings. So, we have:

Average temperature = (T1 + T2 + T3 + T4 + T5 + T6 + T7 + T8) / 8

Substituting the given equation for T, we get:

Average temperature = (-2 + 3 + 4 + 1 + 0 - 2 - 4 - 6 + 41 + 32) / 8
= 58 / 8
= 7.25°C

Therefore, the average temperature over the 8-hour period is 7.25°C.

b) To find the minimum temperature, we need to find the smallest temperature reading in the given period. From the given equation, we can see that the temperature readings range from -6°C to 41°C. Therefore, the minimum temperature is -6°C.

c) To find the maximum temperature, we need to find the highest temperature reading in the given period. From the given equation, we can see that the temperature readings range from -6°C to 41°C. Therefore, the maximum temperature is 41°C.
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To find the first five terms of the sequence of partial sums for the given expression (-5)n+1/n!, we'll calculate each term and add them cumulatively.

1. S1: When n=1, term T1 = (-5)(1+1)/1! = -5/1 = -5
  So, S1 = T1 = -5

2. S2: When n=2, term T2 = (-5)(2+1)/2! = 15/2 = 7.5
  So, S2 = S1 + T2 = -5 + 7.5 = 2.5

3. S3: When n=3, term T3 = (-5)(3+1)/3! = -20/6 = -3.3333
  So, S3 = S2 + T3 = 2.5 - 3.3333 = -0.8333

4. S4: When n=4, term T4 = (-5)(4+1)/4! = 25/24 = 1.0417
  So, S4 = S3 + T4 = -0.8333 + 1.0417 = 0.2084

5. S5: When n=5, term T5 = (-5)(5+1)/5! = -30/120 = -0.25
  So, S5 = S4 + T5 = 0.2084 - 0.25 = -0.0416

The first five terms of the sequence of partial sums are: S1 = -5, S2 = 2.5, S3 = -0.8333, S4 = 0.2084, and S5 = -0.0416.

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Il faut calculer la différence entre les deux nombres, la diviser par l'ancienne valeur, puis multiplier par 100 pour obtenir le pourcentage.

La différence entre les deux nombres est :

28 - 20 = 8

L'ancienne valeur est 20, donc nous avons :

(8 / 20) x 100 = 0.4 x 100 = 40

Le pourcentage d'augmentation est donc de 40%. Le lanceur de baseball a augmenté son nombre de victoires de 40% par rapport à l'année précédente.

There is sufficient evidence to support the alternative hypothesis that there is a linear correlation between duration times and interval after times.

To determine if there is a linear correlation between duration times and interval after times, we can calculate the correlation coefficient and perform a hypothesis test.

We first calculate the correlation coefficient:

r = (n∑xy - (∑x)(∑y)) / sqrt((n∑x^2 - (∑x)^2)(n∑y^2 - (∑y)^2))

where n is the sample size, x and y are the duration times and interval after times respectively, and ∑ represents the sum of the values.

Using the given data, we have:

n = 7

∑x = 1484

∑y = 542

∑xy = 136865

∑x^2 = 377288

∑y^2 = 49966

Substituting these values into the formula, we get:

r = (7(136865) - (1484)(542)) / sqrt((7(377288) - (1484)^2)(7(49966) - (542)^2))

r = 0.934

The correlation coefficient is 0.934, which indicates a strong positive linear correlation between the two variables.

To perform a hypothesis test, we can test whether the correlation coefficient is significantly different from zero. The null hypothesis is that there is no linear correlation between duration times and interval after times (i.e., the correlation coefficient is zero), and the alternative hypothesis is that there is a linear correlation.

We can use a t-test with n-2 degrees of freedom to test this hypothesis. The test statistic is:

t = r * sqrt(n-2) / sqrt(1-r^2)

Substituting in the values we calculated, we get:

t = 0.934 * sqrt(5) / sqrt(1 - 0.934^2)

t = 6.14

Using a t-table with 5 degrees of freedom and a significance level of 0.05 (two-tailed), the critical values are -2.571 and 2.571.

Since our calculated t-value (6.14) is greater than the critical value (2.571), we reject the null hypothesis and conclude that there is sufficient evidence to support the alternative hypothesis that there is a linear correlation between duration times and interval after times.

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There are 17,160 different ways that the DJ can arrange the first four songs on the playlist.

A permutation is an arrangement of a set of objects in a specific order, and the number of permutations of a set of n objects taken r at a time is denoted by P(n, r).

The formula for permutations is:

P(n, r) = n! / (n - r)!

The number of ways to arrange the first four songs on the playlist can be found by calculating the number of permutations of 4 items from a set of 17 items, which is denoted as P(17, 4).

P(17, 4) = 17! / (17 - 4)!

= 17! / 13!

= 17×16×15×14

= 17,160

Therefore, there are 17,160 different ways that the DJ can arrange the first four songs on the playlist.

Permutations are used in various fields of mathematics and statistics, as well as in other areas such as computer science, physics, and engineering.

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If Kannanaski Rapids drops 62 ft. Vertically over a horizontal distance of 920 ft The slope of the rapids is approximately -0.067, which is option C.

The slope of the rapids is equal to the vertical drop divided by the horizontal distance:

slope = vertical drop / horizontal distance

In this case, the vertical drop is 62 ft and the horizontal distance is 920 ft, so:

slope = 62 ft / 920 ft

Simplifying this fraction by dividing both numerator and denominator by 4 yields:

slope = (62 ft / 4) / (920 ft / 4) = 15.5 ft / 230 ft

Reducing this fraction by dividing both numerator and denominator by 15.5 yields:

slope = (15.5 ft / 15.5) / (230 ft / 15.5) = 1 / 14.84 = 0.067.

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The tangent in the unit circle is equal to 0.334.

Since, We know that;

In trigonometry, unit circles are representations of a circle with radius 1 and centered at the origin of a Cartesian plane commonly use to estimate and understand angles and trigonometric functions related to them.

Here, Angles are generated by line segments whose coordinates are of the form (x, y), where x is the position of the terminal point along the x-axis and y is the position of the terminal point along the y-axis.

In addition, the tangent of the angle generated in a unit angle is defined by the following equation:

tan θ = y / x     (1)

If we know that x = - 0.9483 and y = - 0.3173, then the tangent of the angle generated in the unit circle is:

tan θ = (- 0.3173)/(- 0.9483)

tan θ = 0.334

Thus, The tangent in the unit circle is equal to 0.334.

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Yvonne can either run 3/8 part of 2/8 part of the race before stopping for water and then continue to finish the race.

Yvonne has completed 3/8 part of the race. Hence, the remaining part of race is 5/8 parts. Based on the diagrammatic representation of fraction of the race, she can choose among the two ways to stop for drinking water one more time before finishing the race.

Either she can run 3/8 part of the race more and then drink the water followed by finishing the race. Or, she can run 2/8 part of the race more before drinking water and finishing the race.

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The complete question is attached in figure.

According to the Pythagoras theorem, the value of x is 8.366.

Here we know that the the Pythagoras theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

Mathematically, this can be expressed as:

c² = a² + b²

Where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

Based on this we have obtained the following three equations, they are

x² + z ² = 10

x² + 7² = y²

z² = y² + 3²

When we simplify these equations, then we get,

2z² = 60

z² = 30

z = 5.47

Then the value of x is obtained as

=>  x² = 100 - 30

=> x = √70 = 8.366

Finally, the value of y is calculated as

=> y² = x² - 7²

=> y² = 70 - 49 = 21

=> y = 4.58

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To determine the Taylor series about the point xo for the given function in each of Problems 7 through 13, we use the formula, The radius of convergence of this series is 1, because the series converges for |x+1| < 1.

For Problem 12, we have f(x) = x, xo = 0. So f(0) = 0, f'(0) = 1, f''(0) = 0, f'''(0) = 0, f''''(0) = 0, f⁽⁵⁾(0) = 0, and so on. Substituting these values into the formula, we get:

The radius of convergence of this series is infinity because the series converges for all values of x.
I will provide the Taylor series for each of the problems, along with the radius of convergence:

For problem 12, you didn't provide a function, so I cannot give you the Taylor series and radius of convergence. Please provide the function for problem 12, and I'll be happy to help.

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To create a model for one bounce of a type B bouncy ball, you would need to consider factors such as the ball's material, initial height, and the surface it's bouncing on.

You can model this bounce using a simplified equation that accounts for energy conservation and the coefficient of restitution. 1. Determine the initial height (h1) from which the ball is dropped. 2. Measure the coefficient of restitution (COR) for the type B bouncy ball.

This value represents how much energy is conserved during a bounce (typically between 0 and 1). 3. Calculate the height (h2) the ball reaches after one bounce using the formula: h2 = COR^2 * h1. 4.

The bounce can be modeled by tracking the ball's vertical position as it falls, rebounds, and reaches the height h2.

This simplified model assumes that air resistance and friction are negligible, and provides an estimation of the bouncy ball's behavior during a single bounce.

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In a nonequivalent control group interrupted time series design, the independent variable is studied as a factor that influences the dependent variable, while accounting for potential confounding factors. The design involves two groups: the treatment group, which receives the intervention or manipulation of the independent variable, and the nonequivalent control group, which does not receive the intervention.

The control group serves as a comparison for assessing the impact of the independent variable on the treatment group. By comparing the outcomes of both groups over a series of time points before and after the intervention, researchers can analyze the effect of the independent variable while minimizing the influence of extraneous factors.

This design is particularly useful when random assignment of participants to the treatment and control groups is not feasible, as it helps to control for potential threats to internal validity. By using an interrupted time series approach, the researcher can better understand the patterns of change in the dependent variable and establish a causal relationship between the independent variable and the observed outcomes.

In summary, in a nonequivalent control group interrupted time series design, the independent variable is studied as a factor that affects the dependent variable, while using a control group to account for potential confounding factors and enhance the validity of the findings.

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Answer:

13,920 units²

Step-by-step explanation:

Bottom = 120 x 30 = 3600

2 long sides = 2(20 x 120) = 4800

2 short sides = 2(20 x 30) = 1200

2 top sides = 2(17 x 120) = 4080

2 triangular sides = 2(1/2 x 30 x 8) = 240

Total surface area = 3600 + 4800 + 1200 + 4080 + 240 = 13,920 units²

Answer:

Step-by-step explanation:

6[tex]\sqrt{5\\[/tex]

[tex]\sqrt{5*36}[/tex]

[tex]\sqrt{180}[/tex]

If you think about it logically, how can you take 6 out? So there was a number 36 under the root, and because of that there is a possibility to take it out, because 6 squared is 36

Answer: True

Step-by-step explanation: When you need to analyze the data presented in PivotTables and PivotCharts, use a trendline to select the data to display and summarize.

True, before adding a trendline to a chart, it is essential to determine the data series that you want to analyze.

A trendline is a graphical representation of a pattern or direction within a given set of data, which can help in predicting future data points or understanding relationships between variables. By selecting the appropriate data series, you can effectively evaluate the trends and correlations within that specific dataset.

When creating a chart, you'll often work with multiple data series representing different variables or measurements. Identifying the relevant data series to analyze is crucial in order to obtain meaningful insights from the trendline. Once you have determined the data series of interest, you can then proceed to add a trendline that best fits the data points and provides a clear understanding of the underlying patterns.

In summary, it is true that determining the data series to analyze is an important step before adding a trendline to a chart, as it allows you to gain valuable insights and make informed decisions based on the observed trends.

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The average value of the function f(x) over the interval [1, e] is approximately -9.757.

The average value of the function f(x) over the interval [1, e] is given by:

[tex]Avg = (1/(e-1)) ∫[1,e] f(x) dx[/tex]

where f(x) = 20 ln(x).

Substituting f(x) and the limits of integration in the above formula, we get:

[tex]Avg = (1/(e-1)) ∫[1,e] 20 ln(x) dx[/tex]

We can evaluate this integral using integration by parts:

Let[tex]u = ln(x) and dv = dx, then du = (1/x) dx and v = x.[/tex]

Using integration by parts, we have:

[tex]∫ ln(x) dx = x ln(x) - ∫ x (1/x) dx = x ln(x) - x + C[/tex]

where C is the constant of integration.

Substituting this expression in the integral for [tex]Avg[/tex], we get:

[tex]Avg = (1/(e-1)) [20 (e ln(e) - e + 1) - 20 (1 ln(1) - 1 + 1)][/tex]

Simplifying this expression, we get:

[tex]Avg = (1/(e-1)) [20 e - 20 + 20 ln(e)]\\Avg = (1/(e-1)) [20 e - 20]\\Avg = (20/e) - 20 ≈ -9.757[/tex]

Rounding to three decimal places, the average value of the function f(x) over the interval [1, e] is approximately -9.757.

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The absolute maximum value is 5 and it occurs at x=2. The absolute minimum value is -9 and it occurs at x=1, the absolute maximum and minimum values of the function f(x) = x^2 - 4x - 4 over the indicated interval (-1, 3).

Step 1: Find the critical points by taking the first derivative of the function and setting it equal to zero.

f'(x) = 2x - 4
2x - 4 = 0
x = 2

Step 2: Evaluate the function at the critical points and endpoints of the interval.

f(-1) = (-1)^2 - 4(-1) - 4 = 1 + 4 - 4 = 1
f(2) = (2)^2 - 4(2) - 4 = 4 - 8 - 4 = -8
f(3) = (3)^2 - 4(3) - 4 = 9 - 12 - 4 = -7

Step 3: Compare the function values to find the absolute maximum and minimum values.

The absolute maximum value is 1 at x = -1.
The absolute minimum value is -8 at x = 2.

Your answer: The absolute maximum value is at x = -1 and the value is 1. The absolute minimum value is at x = 2 and the value is -8.

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