5.
Which of the following equations has the sum of its roots as 3?
(A) 2x² – 3x + 6 = 0
(B) - x²+ 3x - 3 = 0
(C)√2x²-3/√2x+1
(D) 3x² – 3x + 3 = 0​

Answers

Answer 1

Answer:

B

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )

Then the sum of the roots = - [tex]\frac{b}{a}[/tex]

A 2x² - 3x + 6 = 0

with a = 2 and b = - 3

sum of roots = - [tex]\frac{-3}{2}[/tex] = [tex]\frac{3}{2}[/tex] ≠ 3

B - x² + 3x - 3 = 0

with a = - 1 and b = 3

sum of roots = - [tex]\frac{3}{-1}[/tex] = 3 ← True

C [tex]\sqrt{2}[/tex] x² - [tex]\frac{3}{\sqrt{2} }[/tex] x + 1

with a = [tex]\sqrt{2}[/tex] and b = - [tex]\frac{3}{\sqrt{2} }[/tex]

sum of roots = - [tex]\frac{-\frac{3}{\sqrt{2} } }{\sqrt{2} }[/tex] = [tex]\frac{3}{2}[/tex] ≠ 3

D 3x² - 3x + 3 = 0

with a = 3 and b = - 3

sum of roots = - [tex]\frac{3}{-3}[/tex] = 1 ≠ 3

Thus the equation with sum of roots as 3 is B


Related Questions

Find the equation of the following ellipse based on the following information: Vertices: (-2,0), (2,0) minor axis of length 2​

Answers

Answer:

The expression of the ellipse is: [tex]\frac{x^2}{4} + y^2 = 1[/tex]

Step-by-step explanation:

The equation of a ellipse can be written by the following expression:

[tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex]

Where 2a is the length of the major axis and 2b is the length of the minor axi. Since we were given the length of the minor vertex, then:

[tex]2b = 2\\b = 1[/tex]

The length of the major axis is the distance between the two vertices.

[tex]2a = \sqrt{[2 - (-2)]^2}\\2a = \sqrt{(2 + 2)^2}\\2a = \sqrt{4^2}\\2a = 4\\a = 2[/tex]

Therefore the expression of the ellipse is:

[tex]\frac{x^2}{2^2} + \frac{y^2}{1^2} = 1\\\\\frac{x^2}{4} + y^2 = 1[/tex]

Bob’s Bakery is counting the amount of pastries sold in 4 days. For the first 3 days, the bakery sold 147 pastries each day. On the 4th day, the bakery sold 138 pastries. How many pastries did the bakery sell in 4 days

Answers

Answer:

579 pastries

Step-by-step explanation:

You can write an equation to solve this problem.

(3 * 147) + 138

(441) + 138 = 579

They sold 579 pastries in total.

What is the equation of the graphed line in standard form? y = 2x + 6 12x+y=6 12x−y=−6 −2x+y=6

Answers

Answer:

THe standard form of equation for a line is -2x+y=6

Step-by-step explanation:

THe standard equation has a form of Ax+ By=C, where A, B and C are constants.

12x-y=-6 is not a standard form of a line equation, because the value near you is negative, but should be positive. It would be this form if we would change it a little bit to the form:

-12x=y=6

Find mQPR. If mQPS=40,mRPS=8x+7,mQPR=9x+16

Answers

Answer: QPR = 25 degree

Explanation:

QPR + RPS = QPS

9x + 16 + 8x + 7 = 40

17x + 23 = 40

17x = 17

x = 1

Since QPR = 9x + 16

And x = 1

9(1) + 16 = 9 + 16 = 25

Am I the only person that is having problems with seeing answers?

Answers

Answer:

Been having issues all night

Answer:

Step-by-step explanation: no

This isn’t too difficult of questions and I am pretty sure I know the answers but I just want to make sure. Can someone please help.

Answers

Q2 Anwser
Exact Form:
28/15
Decimal Form:
1.86
Mixed Number Form:
1 13/15

What is the slope of the line?
3(y - 1) = 2x + 2​

Answers

Answer:

The slope is 2/3

Answer:

2/3

Step-by-step explanation:

This is written in point slope form

y - y1 = m(x-x1)

3(y - 1) = 2x + 2​

Divide each side by 3

(y - 1) = 1/3(2x + 2)

Factor out a 2

(y - 1) = 2/3(x -  -1)

​​The slope is 2/3

10 point help please!!!!!!!!!

Answers

Answer:

Side LM is congruent to side RQ

Angle MNO is congruent to angle RST

Side ON is congruent to side ST

Angle LMN is congruent to angle QRS

Step-by-step explanation:

A way to solve this is to use parchment paper or draw the same shape next to each other, as you will get these:

Side LM is congruent to side RQ

Angle MNO is congruent to angle RST

Side ON is congruent to side ST

Angle LMN is congruent to angle QRS

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.

Answers

Answer:

Range y≥-3

Step-by-step explanation:

Answer:

D. Range: y ≥ -3.

Step-by-step explanation:

(x - 4)^2 - 3

= x^2 - 4x - 4x + 16 - 3

= x^2 - 8x - 13

Since this is a parabola, there are no limits to the x-values, but there is a limit on the y-values: the y-values cannot exceed the highest or lowest point of the parabola, the vertex.

To find the vertex...

-b / 2a

8 / 2 = 4

(4 - 4)^2 - 3

= 0 - 3

= -3

So, your answer is D. Range: y ≥ -3.

Hope this helps!

Please Help me ni️️as

Answers

Answer:  see below

Step-by-step explanation:

Multiply the coefficient by the exponent and reduce the coefficient by 1.

1) f'(x) = 10

2) f'(x) = 12x³ + 4x - 5

3) f'(x) = 6x² + 7

4) f'(x) = 20x + 20

5) f'(x) = 20x + 23

Real solution in this system of equations
BRAINLIEST WILL BE GIVEN

Answers

Answer:

A

Step-by-step explanation:

Firstly we find the x value. x-7=0; x=7

Secondly we introduce x value in 1st ecuation. So

(7-3)^2 +(y+1)^2=16, 16+y^2+2y+1=16,

Consider this ecuation: y^2+2y+1=0

y1=( -b+Δ)/ 2a, y2= (-b-√Δ)/2a, Δ=√b^2-4ac=√4-4=0

y1,2= -2/2= -1  

1 Real solution x=7 and y= -1.

What the correct answer do not want the wrong answer please

Answers

Answer:

388.5yd²

Step-by-step explanation:

We have Triangle TUV

In the question, we are given already

Angle U = 32°

Angle T = 38°

Angle V = ???

Side t = 31yd

Side u = ?

Side v = ?

Area of the triangle= ?

Step 1

We find the third angle = Angle V

Sum of angles in a triangle = 180°

Third angle = Angle V = 180° - (32 + 38)°

= 180° - 70°

Angle V = 110°

Step 2

Find the sides u and v

We find these sides using the sine rule

Sine rule or Rule of Sines =

a/ sin A = b/ Sin B

Hence for triangle TUV

t/ sin T = u/ sin U = v/ sin V

We have the following values

Angle T = 38°

Angle U = 32°

Angle V = 110°

We are given side t = 31y

Finding side u

u/ sin U= t/ sin T

u/sin 32 = 31/sin 38

Cross Multiply

sin 32 × 31 = u × sin 38

u = sin 32 × 31/sin 38

u = 26.68268yd

u = 26.68yd

Finding side x

v / sin V= t/ sin T

v/ sin 110 = 31/sin 38

Cross Multiply

sin 110 × 31 = v × sin 38

v = sin 110 × 31/sin 38

v = 47.31573yd

v = 47.32yd

To find the area of triangle TUV

We use heron formula

= √s(s - t) (s - u) (s - v)

Where S = t + u + v/ 2

s = (31 + 26.68 + 47.32)/2

s = 52.5

Area of the triangle = √52.5× (52.5 - 31) × (52.5 - 26.68 ) × (52.5 - 47.32)

Area of the triangle = √150967.6032

Area of the triangle = 388.5454973359yd²

Approximately to the nearest tenth =388.5yd²

if 12 1/2% of a sum of money is $40, what is the TOTAL sum of money?

Answers

Answer:

$320

Step-by-step explanation:

Let the total sum of money be $x.

Therefore,

12 1/2% of x = 40

25/2% * x = 40

0.125 * x= 40

x = 40/0.125

x = $320

Thus, total sum of money is $320.

Callie biked 12 miles in 3 hours. Carter biked 10 miles in 2 hours.
Represent each person's trip with a diagram.
Explain how you can see that they are not going the same speed.

Answers

Answer:

The diagrammatic representation of speed of each person's trip can be given by a column graph per second where the height of the column represents the total distance covered and the position of the column represents the time

The difference in speed is seen in the difference in the height of the column per unit time with the higher column representing the higher speed

The above graph can be combined with the distance time graph where the slope of the line graph is the speed with which the person is riding the bike.

The difference in speed is seen in the difference in slope with the steeper slope representing the higher speed

Step-by-step explanation:

W′X′Y′Z′ is a dilation image of WXYZ. Which is the correct description of the dilation?

Answers

Answer:

D. A reduction with a scale factor of [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

We know for sure it is a reduction because the image, W'X'Y'Z', is smaller than the pre-image WXYZ. Because it is a reduction, the scale factor must be less than 1, so the only option can be D. Both B and C say enlargement and A says it is a scale factor of 2.

Hope this helps and I am sorry no one has answered your question until now.

I will be happy to answer any of your other questions if you want.

Have a good day! :)

at an intersection, the red light light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25 minutes. Approximately what percent of red lights last between 2.5 and 3.5 minutes

Answers

Answer:

95.45%

Step-by-step explanation:

To go about this, what we do is to calculate the z-scores of the values in the range given.

Mathematically;

z-scores = (x-mean)/SD

Here in this case , mean is 3 and standard deviation is 0.25

So for 2.5 minutes, we have ;

z-score = (2.5-3)/0.25 = -0.5/0.25 = -2

For 3.5 minutes, we have;

z-score = (3.5-3)/0.25 = 0.5/0.25 = 2

The required probability we want to calculate according to the range is thus;

P(-2<z<2)

We can calculate this value by the use of the standard normal table

Mathematically, we can have the above as;

P(-2<z<2) = P(z<2) - P(z<-2)

We proceed using the table and we have the values as follows;

P(-2<z<2) = 0.97725 - 0.02275 = 0.9545

Now the value 0.9545 in percentage would be 95.45%

It is believed that 4​% of children have a gene that may be linked to juvenile diabetes. Researchers at a firm would like to test new monitoring equipment for diabetes. Hoping to have 21 children with the gene for their​ study, the researchers test 733 newborns for the presence of the gene linked to diabetes. What is the probability that they find enough subjects for their​ study?

Answers

Answer:

the probability that they find enough subjects for their​ study is 0.9515

Step-by-step explanation:

From the given information:

Let X be the random variable that follows a normal distribution.

Therefore:

X [tex]\sim[/tex]Binomial(n=733,p=0.04)

[tex]\mu = np[/tex]

[tex]\mu = 733*0.04[/tex]

[tex]\mu = 29.32[/tex]

[tex]\sigma = \sqrt{np(1-p)}[/tex]

[tex]\sigma = \sqrt{29.32(1-0.04)}[/tex]

[tex]\sigma = \sqrt{29.32(0.96)}[/tex]

[tex]\sigma = \sqrt{28.1472}[/tex]

[tex]\sigma = 5.305[/tex]

The probability of P(X ≥ 21) lies in the region between 20.5 and 21.5 by considering a discrete contribution of a continuous normal distribution. Eventually, X > 20.5

P(X >20.5)= P(Z > z)

Using  standard normal z formula:

[tex]z = \dfrac{x-\mu}{\sigma}[/tex]

[tex]z = \dfrac{20.5-29.32}{5.305}[/tex]

[tex]z = \dfrac{-8.82}{5.305}[/tex]

[tex]z = -1.662582[/tex]

z = -1.66

P(X >20.5)= P(Z > -1.66)

From the standard z tables ;

P(X >20.5)= 1 - 0.0485

P(X >20.5)= 0.9515

How do I find the solution of each system of equations?
y = 2x - 1
y = 3x + 2

Answers

Answer:

x = -3, y = -7

Step-by-step explanation:

You can set the equations equal to each other, so the set becomes:

2x - 1 = 3x + 2

-x = 3

x = -3

y = 2(-3) -1 = -7

Answer:

x = -3

y = -7

Step-by-step explanation:

y = 2x - 1

y = 3x + 2

Set the equations equal to each other

2x-1 = 3x+2

Subtract 2x from each side

2x-1-2x = 3x+2-2x

-1 =x+2

Subtract 2 from each side

-1-2 = x+2-2

-3 =x

Now find y

y = 2x-1

y = 2(-3) -1

y = -6-1

y = -7

A cross section is made by the intersection of a plane and a square pyramid at an angle either parallel or perpendicular to the base. The cross section can be which of these shapes? Select three options. square triangle trapezoid circle non-square rectangle

Answers

Answer:

i. square

ii. triangle

iii. trapezoid

Step-by-step explanation:

A cross section of a figure or shape can be produced by cutting a slice through the figure.

From the given question, since the angle of intersection of the planes could either be parallel or perpendicular to the base, the cross section could either be a square, a triangle or a trapezoid.

A square is generated when the angle is parallel to the base, a triangle could also be produced when the angle is perpendicular to the base, and a  trapezoid is formed when the angle is perpendicular to the base.

Answer:

A, B, C

Step-by-step explanation:

EDGE 2020

Write an equation to represent the relationship between the number of mugs and cost for company A. Use c for cost and m for the number of mugs

Answers

Answer:

Assuming this is a linear problem, the equation would look like this:

C(m)=Mx

Step-by-step explanation:

Because you don't have any other details, this as much of an answer I can give you. The cost for the company depends on how many mugs they produce. If the cost for making a mug is 3 dollars, then m would be that value, and x would be the amount of mugs you're trying to make.

The relationship between the number of mugs and the cost for company A will be c = nm.

What is a linear equation?

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

Write an equation to represent the relationship between the number of mugs and the cost for company A.

The cost for company A is directly proportional to the number of mugs.

c ∝ m

c = nm

Where 'n' is the cost of each mug.

The relationship between the number of mugs and the cost for company A will be c = nm.

More about the linear equation link is given below.

https://brainly.com/question/11897796

#SPJ2

Evaluate 3(4 - 2)2
A. 108
B. 36
C. 12
D. 100

Answers

Answer:

12

Step-by-step explanation:

3(4 - 2)^2

Parentheses first

3 ( 2) ^2

Then exponents

3 *4

Then multiply

12

Which inequality is represented by this graph?
f(0, 1)
(5,0)

Answers

Answer:

C.

Step-by-step explanation:

The dotted line means it is not "equal to" and since its shaded BELOW the line, its less than.

[tex]y < \frac{-1}{5} x+1[/tex] inequality is represented by given graph.

What is inequality?

" Inequality is defined as the relation between two variables using sign of inequality such as >, <, ≤, ≥ ."

According to the question,

From the given graph,

(0,1) and (5,0) are excluded points in the graph of the inequality .

value of y < 1 for x = 0, value of x < 5 for y =0 represents open interval.

Option (A) and (B) represent Close interval , therefore both are not correct option.

Option(D) y >1 for x=0 , x>5 for y=0 , it is not correct option.

Option (C) [tex]y < \frac{-1}{5} x+1[/tex]

y <1 for x = 0 and x<5 for y = 0 represent the graph inequality.

Hence, Option(C) is the correct answer.

Learn more about inequality here

https://brainly.com/question/17675534

#SPJ2

Given that C is at (-6, -1) and D (4, 8), find the point P that partitions CD into the ratio of 1:3.

Answers

Answer:

The coordinates of point P are (-7/2, 5/4)

Step-by-step explanation:

Here, we want to give the coordinates of the point P that divide CD in the given ratio

To do this , we shall be making use of a mathematical formula;

Let’s say the ratio 1:3 represents a:b, our formula those becomes

{(bx1 + ax2)/(a + b) ,( by1+ay2)/a+b}

From the question, we can identify that

(x1,y1) = (-6,-1)

(x2,y2) = (4,8)

a = 1 and b = 3

Plugging these values into the formula we have

3(-6) + 1(4)/(1+3) , 3(-1) + 1(8)/(1+3)

= (-18 + 4)/4 , (-3+ 8)/4

=-14/4, 5/4

= (-7/2, 5/4)

Which statement about this figure is true? Pls give an explanation

Answers

Answer:

The correct option is;

It has no reflectional symmetry

Step-by-step explanation:

Reflectional symmetry is one such that a line can be drawn across a shape or figure and the shape or figure on either side of the line is the equivalent of the reflection image obtained from a mirror

Lines of reflectional symmetry can be found in squares, circles, and triangles

The characteristics of the object that has line of reflection symmetry remains the same across the line of symmetry

Two dimensional objects have lines of symmetry while three dimensional objects have planes of symmetry.

An arithmetic sequence grows
A. at a constant percentage rate
B. linearly
C. quadratically
D. exponentially

Answers

B) linearly; the difference between terms in such a sequence remains constant

Please help pleaseee give first person to answer brainlest A system of equations is shown below: Equation A: 3c = d − 8 Equation B: c = 4d + 8 Which of the following steps should be performed to eliminate variable d first? A : Multiply equation A by −4. B : Multiply equation B by 3. C : Multiply equation A by 3. D : Multiply equation B by 4.

Answers

Answer:

Multiply the first equation by -4

Step-by-step explanation:

Equation A: 3c = d − 8

Equation B: c = 4d + 8

We want to eliminate variable d

Multiply the first equation by -4

-4( 3c = d − 8)

-12c = -4d +32

Add this to the second equation

-12c = -4d +32

c = 4d + 8

================

-11c = 0d + 40

Answer:

A : Multiply equation A by −4

Step-by-step explanation:

3c = d - 8

Multiply the equation by -4.

-12c = -4d + 32

-12c = -4d + 32

c = 4d + 8

Add equations.

-11c = 0d + 40

-11c = 40

The d variable is eliminated.

Please help me with

Answers

Answer:

[tex]\boxed{\frac{1}{2} }[/tex]

Step-by-step explanation:

Let the assistants be x

Condition:

Ratio is also "division"

So,

[tex]\frac{x}{players} = \frac{1}{6}[/tex]

=> Where players = 36

=> [tex]\frac{x}{36} = \frac{1}{6}[/tex]

Multiplying both sides by 36

=> x = 6

So,

Assistants = 6

Ratio of coaches to assistants = 3 : 6

=> 1 : 2

In Fraction form

=> [tex]\frac{1}{2}[/tex]

F) 1/2

Because no. of players= 36

Since ratio of team assistant to players is 1:6

Let no of assistant be X

X/36 = 1/6

X= 6

No of assistant= 6

Ratio of coach to assistant= 3/6=1/6

= 1:6

Solve the following system using substitution.

Answers

Answer/Step-by-step explanation:

3. By substitution method, let's substitute [tex] \frac{2}{3}x- 4 [/tex] for y in the first equation.

Thus,

[tex] \frac{1}{3}x + 2(\frac{2}{3}x- 4) = 1 [/tex]

Solve for x

[tex] \frac{x}{3} + \frac{4x}{3} - 4 = 1 [/tex]

Add 4 to both sides

[tex] \frac{x}{3} + \frac{4x}{3} - 4 + 4 = 1 + 4 [/tex]

[tex] \frac{x}{3} + \frac{4x}{3} = 5 [/tex]

[tex] \frac{x + 4x}{3} = 5 [/tex]

[tex] \frac{5x}{3} = 5 [/tex]

Multiply both sides by 3

[tex] \frac{5x}{3}*3 = 5*3 [/tex]

[tex] 5x = 15 [/tex]

Divide both sides by 5

[tex] x = 3 [/tex]

Now, substitute 3 for x in the equation.

[tex] y = \frac{2}{3}x- 4 [/tex]

[tex] y = \frac{2}{3}(3) - 4 [/tex]

[tex] y = 2 - 4 [/tex]

[tex] y = -2 [/tex]

The solution of the equation is x = 3, y = -2

4. Solving by elimination, let's try to eliminate the x-variable by adding both equation together.

[tex] 3x - 2y = 11 [/tex]

[tex]-3x - y = 4[/tex]

            [tex] -3y = 15 [/tex]  => [tex] (-3x +(-3x) = 0; -2y +(-y) = -3y; 11 + 4 = 15) [/tex]

Divide both sides by -3 to solve for y

[tex] \frac{-3y}{-3} = \frac{15}{-3} [/tex]

[tex] y = -5 [/tex]

Substitute -5 for y in the first equation to find x

[tex] 3x - 2(-5) = 11 [/tex]

[tex] 3x + 10 = 11 [/tex]

Subtract 10 from both sides

[tex] 3x + 10 - 10 = 11 - 10 [/tex]

[tex] 3x = 1[/tex]

Divide both sides by 3

[tex] \frac{3x}{3} = \frac{1}{3} [/tex]

[tex] x = \frac{1}{3} [/tex]

The solution is [tex] x = \frac{1}{3}, y = -5 [/tex]

Lupe va al mercado y compra abarrotes con los 2/5 de su dinero ; luego va a la seccion de carnes y compra con los 3/3 de lo que le queda ; si gasta 3 soles en pasaje de ida y vuelta ; ¿con cuanto dinero salio de su casa si llega de regreso a su casa con 48 soles?

Answers

Answer:

Cantidad que Lupe dejó en casa con inicialmente = 127.5 soles.

Amount that Lupe left home with initially = 127.5 soles.

Step-by-step explanation:

Pregunta correcta

Lupe va al mercado y compra abarrotes con los 2/5 de su dinero ; luego va a la seccion de carnes y compra con los 1/3 de lo que le queda ; si gasta 3 soles en pasaje de ida y vuelta ; ¿con cuanto dinero salio de su casa si llega de regreso a su casa con 48 soles?

Solución

Deje que la cantidad de dinero que Lupe dejó en casa sea x soles.

Lupe compra comestibles con 2/5 de su dinero. Es decir, Lupe gasta (2/5) × x = (2x/5)

En este punto, Lupe se queda con

x - (2x/5) = (3x/5) soles.

Lupe luego gasta 1/3 de lo que queda en la carne

(1/3) de lo que queda = (1/3) × (3x/5) = (x/5)

Lo que significa que Lupe gasta (x/5) soles en la sección de carne.

Cantidad restante después de la sección de carne = (3x/5) - (x/5) = (2x/5)

Lupe gasta 3 soles en el viaje de ida y vuelta al mercado y se queda con 47 soles después de todo.

(2x/5) - 3 = 48

(2x/5) = 48 + 3 = 51

2x = 5 × 51 = 255

2x = 255

x = (255/2) = 127.5 soles

¡¡¡Espero que esto ayude!!!

English Translation

Lupe goes to the market and buys groceries with 2/5 of her money; then he goes to the meat section and buys with 1/3 of what he has left; if you spend 3 soles on a round trip ticket; How much money did you leave your home with if you arrive home with 48 soles?

Solution

Let the amount of money Lupe left home with be x soles.

Lupe buys groceries with 2/5 of her money

That is, Lupe spends (2/5) × x = (2x/5)

At this point, Lupe is left with

x - (2x/5) = (3x/5) soles.

Lupe then spends 1/3 of what is left on meat

(1/3) of what is left = (1/3) × (3x/5) = (x/5)

Meaning that Lupe spends (x/5) soles at the meat section.

Amount left after the meat section = (3x/5) - (x/5) = (2x/5)

Lupe spends 3 soles on round ticket trip to market and is left with 47 soles after everything.

(2x/5) - 3 = 48

(2x/5) = 48 + 3 = 51

2x = 5 × 51 = 255

2x = 255

x = (255/2) = 127.5 soles

Hope this Helps!!!

Simplify csc θ + cot θ

Answers

Answer:

csc θ + cot θ

From trigonometric identities

[tex] \csc(θ) = \frac{1}{ \sin(θ) } [/tex]

And

[tex] \cot(θ) = \frac{ \cos(θ) }{ \sin(θ) } [/tex]

So we have

[tex] \frac{1}{ \sin(θ) } + \frac{ \cos(θ) }{ \sin(θ) } [/tex]

Find the LCM

The LCM is sin θ

So we have

[tex] \frac{1}{ \sin(θ) } + \frac{ \cos(θ) }{ \sin(θ) } = \frac{1 + \cos(θ) }{ \sin(θ) } [/tex]

And

[tex] \frac{1 + \cos(θ) }{ \sin(θ) } = \cot( \frac{θ}{2} ) [/tex]

So we have the final answer as

[tex] \cot( \frac{θ}{2} ) [/tex]

Hope this helps you

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