Answer:
The correct option is;
(A) 1 m/s
Explanation:
Given that Ramu and Somu are running towards North with 3 m/s and 4 m/s respectively.
Their friend Srinu is running towards South with a speed of 2 m/s
The magnitude of the relative velocity of Ramu with respect to Ramu is found as follows;
Velocity of Ramu = 3 m/s North ↑
Velocity of Srinu = 2 m/s South↓ = -2 m/s North ↑
Relative velocity of Ramu to Srinu = Velocity of Ramu North + Velocity of Srinu North
Relative velocity of Ramu to Srinu = 3 m/s + (-2) m/s = (3 - 2) m/s = 1 m/s
Relative velocity of Ramu to Srinu = 1 m/s.
What is the change in internal energy if 60 J of heat are released from a
system and 20 J of work is done on the system? Use AU = Q-W.
Answer:
60 J of heat are released from the system: Q=-60 J
20 J of work is done on the system: W=-20 J
∆U=Q-W
∆U=-60-(-20)
∆U=-40 J
Explanation:
If the heat is released from the system, Q should be negative.
If the heat is gained by the system, Q should be positive.
If the work is done on the system, W should be negative.
If the work is done by the system, W should be positive.
As light from a star spreads out and weakens, do gaps form between the photons?
Answer:
There are no gaps in space between the photons as they travel. If you look at light as a wave, then there no gaps unless specifically placed there on purpose. ... The light from a distance star indeed spreads out and weakens as it travels, but this just reduces the wave strength and does not introduce gaps.
A truck is moving with a certain uniform velocity. It is accelerated uniformly by 0.75 m/s^2. After 20 seconds , the velocity becomes 72km/h.Find the initial velocity
Answer:
Vi = 5 m/s
Explanation:
let (a) acceleration = 0.75 m/s²
(t) time = 20 seconds
Vf = final velocity = 72 km/hr (convert to m/s to units consistency = 20 m/s)
find Initial velocity (Vi)
Vf - Vi
a = -----------
t
Vi = Vf - (a * t) = 20 - (0.75 * 20)
Vi = 5 m/s
a boy has a mass of 80kg on earth where g= 10N/kg a) what is his mass on the moon b ) find his weight on the moon ( g= 10N/kg)
Explanation:
mass on moon is also 80kg because it doesn't differed according to place.
I think we can't calculate weight because there is no gravity in moon
Answer 80kg
Explanation Mass is constant in every corner of universe. It's better if u have asked about weight on moon. It is same in both earth and moon.
Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional 70.0 m to her car. What is the magnitude of the displacement of her car from the grocery store exit?
Answer:
165.529454
Explanation:
According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.
A 20.0 Ohm and 60.0 Ohm resistor
are connected in series to a 9.00 V
battery. What is the voltage drop
across the 20.0 Ohm resistor?
(Hint: How much current flows
across it?)
(Unit = V)
Answer:
2.25 V
Explanation:
The equivalent resistance is:
R = 20.0 Ω + 60.0 Ω
R = 80.0 Ω
The current is:
V = IR
9.00 V = I (80.0 Ω)
I = 0.1125 A
The voltage drop across the 20.0 Ω resistor is:
V = IR
V = (0.1125 A) (20.0 Ω)
V = 2.25 V
What includes a distance and a direction? A. Acceleration B. Speed C. Displacement D. Velocity
Answer:displacement
Explanation:
2. Calcula la presión que se ejerce una bicicleta sobre el suelo. Si la bicicleta tiene un peso de 620kg y el área de la superficie rectangular es de 0.5m x 0.6m.
Responder:
20253.33N / m²Explicación:
La presión se define como la fuerza ejercida por un cuerpo por unidad de área de sección transversal de ese cuerpo.
Presión = Fuerza / Área de sección transversal
Dada la masa de la bicicleta m = 620 kg
Peso de la bicicleta = mg = 620 * 9.8
Peso de la bicicleta = 6076N
Si la dimensión de su área de superficie es 0.5m por 0.6m, el área de la sección transversal será 0.6m * 0.5m = 0.30m²
Presión que ejerce la bicicleta en el suelo = 6076 / 0.30 = 20253.33N / m²
A boat floats in a lake. When the boat moves the force of resistance is proportional to the velocity of the boat. Initially the boat is at rest. A person walks from the stern to the bow of the boat. What will be the position of the boat long time after the person stopped moving?
Answer: Contant.
Explanation:
You are given that When the boat moves the force of resistance is proportional to the velocity of the boat. This means that the total momentum on the boat is equal to zero. Then the boat remains at a certain position.
When a person walks from the stern to the bow of the boat, the boat will tend to move in the opposite direction with equal magnitude of momentum. The magnitude of forces will thereby cancel out.
The person will be seen moving while the boat moves in the opposite direction.
If no external force is acting on the boat, the sum of the momentum of the person and the boat will be equal to zero. And the boat will remain at rest.
The position of the boat long time after the person stopped moving will therefore remain the same.
the velocity is always _____ to the line of a circle
Answer:
tangent
Explanation:
hope it helps
Answer:
the answer is tangent
Explanation:
tangent means a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.
hope this helps please like and heart this answer and give 5 stars and brainliest pls i beg u thx!!! : )
Select the type of energy involved in each step. You turn on the burner of a gas stove. The gas ignites. The gas warms the water in the pan.
Answer:
You turn on the burner of a gas or stove - mechanical energy.
The gas ignites - Chemical energy.
The gas warms the water in the pan - Thermal energy.
A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. When will the ball hit the ground again? A. 4 s B. 6 s C. 3 s D. 5 s
Answer:
B. 6 s
Explanation:
Given in the y direction:
Δy = 0 m
v₀ = 30 m/s
a = -10 m/s²
Find: t
Δy = v₀ t + ½ at²
0 m = (30 m/s) t + ½ (-10 m/s²) t²
0 = 30t − 5t²
0 = 5t (6 − t)
t = 6
A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s, the ball will hit the ground again at approximately t = 6 seconds. The correct option is B.
We can examine the ball's vertical motion to predict when it will strike the ground once more.
h = v0t + (1/2)g[tex]t^2[/tex]
0 = 30t + (1/2)(9.8) [tex]t^2[/tex]
Simplifying the equation:
4.9 [tex]t^2[/tex] + 30t = 0
Factorizing the equation:
t(4.9t + 30) = 0
Solving for t in 4.9t + 30 = 0:
4.9t = -30
t = -30 / 4.9
t ≈ -6.1
Since time cannot be negative in this context, we discard the negative solution.
Therefore, the ball will hit the ground again at approximately t = 6 seconds.
Thus, the correct answer is B. 6 s.
For more details regarding vertical motion, visit:
https://brainly.com/question/12640444
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A skateboarder rides down the street. When his feet push down on the
skateboard, what is the reaction force?
Answer:
the skateboard pushes up
Explanation:
newton's 3rd law says for every action, there's an equal and opposite reaction, so when his feet push on the skateboard, the skateboard pushes back up.
Answer:
the skateboard pushes up
Explanation:
Mustang Sally just finished restoring her 1965 Ford Mustang car. To save money, she did not get a new battery. When she tries to start the car, she discovers that the battery is dead (an insufficient or zero voltage difference across the battery terminals) and so she will need a jump start. Here is how she accomplishes the jump start:
Explanation:
To jump start she needs
1. Jumper cables
2. Power source/jump box/ portable batteries.
The positive end of the jump cable will be connected to terminal of the car battery and the jump box, likewise the negative terminal to complete the circuit for a successful jump start to be accomplished
A student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of candle, screen and the lens as under Position of candle = 12.0 cm Position of convex lens = 50.0 cm Position of the screen = 88.0 cm i.What is the focal length of the convex lens? ii. Where will the image be formed if he shifts the candle towards the lens at a position of 31.0 cm? iii. What will be the nature of the image formed if he further shifts the candle towards the lens? iv. Draw a ray diagram to show the formation of the image in case (iii) as said above.
Answer:
Explanation:
Object distance = distance between object and lens
u = 50 - 12 = 38 cm
image distance v = 88 - 50 = 38 cm
i )
using lens formula
1 / v - 1 / u = 1 / f
1 / 38 - 1 / - 38 = 1/f
2 / 38 = 1 / f
f = 19 cm
ii ) So object is placed at 2 f or at the center of curvature of the lens .
If object distance is changed to 50 - 31 = 19 cm
using lens formula
1 / v - 1 / u = 1 / f
1 / v + 1 / 19 = 1/19
1 / v = 0
v = infinity
It is so because now the object is placed at the focal distance
iii )
If object further shifts towards the lens , then virtual image of object will be formed behind the lens which will be larger than object .
Which statement describes one feature of a closed circuit? Charges do not flow. Bulbs will not shine. The circuit is broken. The circuit is complete.
I inferred you've referring to a close electrical circuit.
Answer:
The circuit is complete.
Explanation:
A closed electrical circuit is indeed a complete circuit. Also, it allows charges to flow, the bulbs in the circuit will shine and it is not broken.
It is termed closed circuit because there is no brokage in the series of electrical wires or the switch; which may prevent the free flow of current or charges. Thus, a feature that marks closed circuits is that they are complete.
Answer:
The circuit is complete.
Explanation:
the velocity is always _____ to the line of a circle
Answer:
The velocity is always tangent to the line of a circle .
Explanation:
When an object moves in a circular path, its motion is called the circular motion. The speed of the object is constant at each and every point in such motion while the velocity changes due to change in direction.
In a circular motion, the direction of velocity is always tangent to the circle. At each and every point, its direction is found tangentially.
Bruno the bat flies at a speed of 0.5 m/s in circle of radius 1 m. What is his acceleration?
Very urgent pls help
Answer:
Acceleration is 0.25m/s^2
Explanation:
Given the following :
Speed = 0.5m/s
Radius(r) of circle = 1m
Acceleration round a circular path is given as :
a = v^2 / r
Where
a = acceleration of the body
v = speed / velocity
r = radius
Therefore,
a = v^2 / r
a = (0.5)^2 / 1
a = 0.25m/s^2
The governor of state A earns $53,745 more than the governor of state B. If the total of their salaries is $289,405, find the salaries of each.
Answer:
Sa is the salary of the governor of state A
Sb is the salary of the governor of state A
"The governor of state A earns $53,745 more than the governor of state B. "
This means that:
Sa = Sb + $53,745
"If the total of their salaries is $289,405,"
means that:
Sa + Sb = $289,405
Then we have two equations:
Sa = Sb + $53,745
Sa + Sb = $289,405
Now, we can replace the first equation into the second equation:
(Sb + $53,745) + Sb = $289,405
2*Sb = $289,405 - $53,745 = $235,660
Sb = ($235,660)/2 = $117,830
and:
Sa = Sb + $53,745 = $117,830 + $53,745 = $171,575
Governor of state A earns: $171,575
Governor of state B earns: $117,830
Please help me with this question ASAP.
In a a potentiometer circuit, a 1m long potentiometer wire PQ of resistance 10 ohms is connected in series with a cells of e.m.f. 9V with internal resistance 3 ohms Calculate:
i The p.d. across PQ
ii. The e.m.f. of a cell which has a balance point of 75cm.
Answer:
i. 6.923 V
ii. The e.m.f. = 22.5 V
Explanation:
i. The given parameters are;
Length of potentiometer = 1 m
The resistance of the potentiometer = 10 Ω
The e. m. f. of the attached cell = 9 V
The current, I flowing in the circuit = e. m. f/(Total resistance)
The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A
The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire
The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V
ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;
[tex]\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}[/tex]
Where:
E = e.m.f. of the balance point cell
[tex]R_{balance}[/tex] = Resistance of 75 cm of potentiometer wire = 0.75×10 = 7.5 Ω
[tex]R_{cell}[/tex] = Resistance of the cell in the circuit = 3 Ω
V = e.m.f. attached cell = 9 V
[tex]\dfrac{E}{7.5} = \dfrac{9}{3}[/tex]
E = 7.5*3 = 22.5 V
The e.m.f. = 22.5 V
You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength regularly over a certain period. The maximum possible size for the source of this radiation can now be calculated from the:____________
Answer:
Period of the signal.
Explanation:
So, this question is all about a concept in physics or astronomy which is called or known as Radiation Astronomy and Galactic Nuclei that are active. This concept talks most about Quasars; a powerful radiating object which derives its power from black holes.
When You take a look at Quasars, we get the to know that the more you think you can see, the more they move away from us.
Thus, when "You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength regularly over a certain period. The maximum possible size for the source of this radiation can now be calculated from the "PERIOD OF THE SIGNAL.
NB: not the amplitude but the period.
The large-scale distribution of galaxies in the universe reveals Group of answer choices a smooth, continuous, and homogenous arrangement of clusters large voids, with most of the galaxies lying in filaments and sheets a large supercluster at the center of universe a central void with walls of galaxies at the edge of the universe
Question
The large-scale distribution of galaxies in the universe reveals
A) a smooth, continuous, and homogenous arrangement of clusters
B) large voids, with most of the galaxies lying in filaments and sheets a large supercluster at the center of the universe
C) a central void with walls of galaxies at the edge of the universe
Group of answer choices
Answer:
The correct answer is B)
Explanation:
The universe is arranged in a filamentary structure. Filamentary structures are very large. They are the largest kind of structures in the universe and comprise mostly of galaxies that are held together by gravity.
The structures found within Galaxy filaments have thread-like qualities spanning 52 to 78.7 megaparsecs h⁻¹ in lenght.
Other phenomena associated with the nature fo the universe is the existence of void spaces.
Cheers!
Na (g) + 2HCl (g) -> H2 (g) + 2NaCl (s) is a balanced equation? True or false?
Answer:
False, the given equation is not balanced.
Explanation:
The given equation is:
Na(g) + 2HCl(g) → H₂(g) + 2NaCl(s)
And it is not balanced, the number of atoms of Na is not the same on both sides of the equation.
The balanced equation is:
2Na(g) + 2HCl(g) → H₂(g) + 2NaCl(s)
Now, the given equation is balanced, we have the same number of atoms on both sides of the equation.
Therefore, the answer is false, the given equation is not balanced.
I hope it helps you!
Question 21 of 25
Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him
O A 352 N
O B. 122 N
C. 1150 N
O D. 813N
Answer:
B. 122N
Explanation:
f = 0.15 x 83 x 9.8 = 122.01
f = 122N
Two runners start at a distance of 10 miles from each other. They run towards each other at a constant velocity of 5 mph. A fly takes off from runner one’s nose at time zero. The fly has a constant velocity of 20 mph and flies between the runners. Find the total distance that the fly has traveled when the runners collide.
Answer:
The fly will travel 20 miles before the runners collide with each other.
Explanation:
Since the runners are both traveling at the same speed, they will meet and collide in the exact middle of each other which is 5 miles away from their starting point. Since they are traveling at 5 mph, it will take exactly one hour before they collide. The fly is going 20 mph so it will travel 20 miles before the runners collide in one hour.
Is a motor a load that can be found in a circuit?
Answer:
yes you can find a motor in a circuit
If you precisely measure the position of a particle, you __________. If you precisely measure the position of a particle, you __________. destroy information about its momentum convert it into a wave cause it to interfere cause the particle to be annihilated
Answer:
Destroy information about the speed of the particle
Explanation:
This is according to Heisenberg's Uncertainty Principle states that there is inherent uncertainty in the act of measuring a variable of a particle. Commonly applied to the position and momentum of a particle, the principle states that the more precisely the position is known the more uncertain the momentum is and vice versa.
A physics professor uses an air-track cart of mass m to compress a spring of constant k by an amount x from its equilibrium length. The air-track has negligible friction. When she lets go, the spring launches the cart. What cart velocity should she expect after it is launched by the spring
Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ = [tex]K_{e}[/tex] = ½ k x²
final point. Cart after leaving the spring
[tex]Em_{f}[/tex] = K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
WILL MARK U AS BRAINLIEST...... An aeroplane is taking off with a velocity of 360 km/h at an angle of 30° with the horizontal. find its horizontal and vertical componnent velocities.
Answer:
x=180√3. or 311.7 and y= 180km/h
Explanation:
y= sin30° × 360km/h
y= 0.5 × 360km/h
y= 180km/h
x=cos30° × 360 km/h
x=√3/2*360km/h
x=180√3. or 311.7
Spring balance measures weight, not the mass of a body.
Answer:
That is true and is easily explained by the next equation:
W= m*g
where
W= Weight
m=mass
g= gravitational acceleration
so, if you use a spring balance in another planet with a different gravitational acceleration the measured weight will be different.