(15 points) How does change in a roller coasters motion depend on the sum of the forces and the mass of the ride?

Answer:  The thermal energy transfer is When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along.

Explanation: heat transfer is called convection.  hopefully this was helpful.

Answer:

The first one

Explanation:

The answer is 13.5 because 27÷3.0=13.5

Answer:

Representative Democracy.

Explanation:

It is simple and easy because you choose a representative to make choices for the good of your people. It is much simpler then all the rest.

Answer:

(b) 0.0176

(c) -0.0124

(d) 209

(e) Also comes to rest

(a) 2.38

(b) 5.95

Explanation:

(a) Your answer is correct.  Angular momentum is conserved, so as the lighter beetle moves clockwise, the heavier turntable will move counterclockwise at a slower speed.

(b/c) Initial angular momentum = final angular momentum

L₀ = L

I₁ ω₁,₀ + I₂ ω₂,₀ = I₁ ω₁ + I₂ ω₂

0 = mr² ω₁ + ½ Mr² ω₂

0 = 2m ω₁ + M ω₂

The beetle's angular velocity relative to the turntable is 0.03 rad/s, so ω₁ = ω₂ + 0.03.  Plugging in:

0 = 2 (30 g) (ω₂ + 0.03 rad/s) + (85 g) ω₂

0 = 60ω₂ + 1.8 rad/s + 85ω₂

145ω₂ = -1.8 rad/s

ω₂ = -0.0124 rad/s

ω₁ = ω₂ + 0.03

ω₁ = 0.0176 rad/s

Relative to a stationary observer, the beetle moves 0.0176 rad/s clockwise and the turntable moves -0.0124 rad/s counterclockwise.

(d) Angular distance = angular velocity × time

2π rad = (0.03 rad/s) t

t = 209 s

(e) Angular momentum is conserved.  Since both the beetle and the turntable were originally at rest, the turntable will again come to rest when the beetle stops.

(a) Angular momentum is conserved.

L₀ = L

I₀ ω₀ + I₂ ω₀ = I ω + I₂ ω

(I₀ + I₂) ω₀ = (I + I₂) ω

(M (R/2)² + ½ (3M) (R)²) ω₀ = (M (R)² + ½ (3M) (R)²) ω

(¼ MR² + ³/₂ MR²) ω₀ = (MR² + ³/₂ MR²) ω

(¼ + ³/₂) ω₀ = (1 + ³/₂) ω

(1 + 6) ω₀ = (4 + 6) ω

7ω₀ = 10ω

ω = 0.7ω₀

ω = 0.7 (3.40 rad/s)

ω = 2.38 rad/s

(b) Angular momentum is conserved.

L₀ = L

I₀ ω₀ + I₂ ω₀ = I ω

(I₀ + I₂) ω₀ = I ω

(M (R/2)² + ½ (3M) (R)²) (3.40 rad/s) = M (R)² ω

(¼ MR² + ³/₂ MR²) (3.40 rad/s) = MR² ω

(¼ + ³/₂) (3.40 rad/s) = ω

ω = 5.95 rad/s

Notice we could also have used our answer from part a and I₀ = MR².

(I₀ + I₂) ω₀ = I ω

(M (R)² + ½ (3M) (R)²) (2.38 rad/s) = M (R)² ω

(MR² + ³/₂ MR²) (2.38 rad/s) = MR² ω

(1 + ³/₂) (2.38 rad/s) = ω

ω = 5.95 rad/s

Answer:

-2.478

0.379

11.14

24.78

Explanation:

Angular frequency of spring in harmonic motion is given by?

ω = √(k/m)

ω = √(10/2.2)

ω = √4.54

ω = 2.13 s^-1

If at t=0 the mass is in negative amplitude (x = -A = -2.48 m) then we describe the position with negative cosine

x(t) = -A * cos(ωt)

x(t) = -2.48 * cos(2.13 * 1)

x(t) = -2.48 * 0.9993

x(t) = -2.478

Velocity and acceleration are 1st and 2nd derivative of position

b)

v(t) = Aω * sin(ωt)

v(t) = 2.48 * 2.13 * sin(2.13 * 1)

v(t) = 5.282 * sin2.13

v(t) = 5.282 * 0.03717

v(t) = 0.379 m/s

c)

a(t) = Aω^2 * cos(ωt)

a(t) = 2.48 * 2.12² * cos(2.13 * 1)

a(t) = 2.48 * 4.494 * cos2.13

a(t) = 11.15 * 0.9993

a(t) = 11.14 m/s²

d)

F = -k * x(t)

F = -10 * -2.478

F = 24.78 N

The question is incomplete. Here is the complete question.

Lightning bolts can carry currents up to approximately 20kA. We can model such a current as the equivalent of a very long, straight wire.

(a) If you were unfortunate enough to be 5.5m away from such a lightning bolt, how large a magnetic field would you experience?

(b) How does this field compare to one you would experience by being 5.5cm from a long, straight household current of 5A?

Answer: (a) B = 7.27 x 10⁻⁴ T

              (b) Approximately 40 times higher than a household one.

Explanation: Using Biot-Savart Law, the magnetic field in a straight, long wire is given by

[tex]B=\frac{\mu_{0}I}{2.\pi.r}[/tex]

where:

[tex]\mu_{0}[/tex] (permeability of free space) = [tex]4.\pi.10^{-7}[/tex]T.m/A

(a) If lightning bolt is compared to a long and straight wire, then magnetic field is

[tex]B=\frac{4.\pi.10^{-7}.10.10^{3}}{2.\pi.5.5}[/tex]

B = 7.27 x 10⁻⁴ T

The magnitude of magnetic field in a lightning bolt is 7.27 x 10⁻⁴ T

(b) Magnetic field in a household wire will be

[tex]B=\frac{4.\pi.10^{-7}.5}{2.\pi.5.5.10^{-2}}[/tex]

B = 1.82 x 10⁻⁵ T

Comparing fields:

[tex]\frac{7.27.10^{-4}}{1.82.10^{-5}}[/tex] ≈ 40

The filed for a lightning bolt is approximately 40 times higher than for a household wire.

Answer:

Yes

Explanation:

Beacause u have 25 kg,and falls off from a cliff hanger cause its too bit heavy

Answer:

15 seconds

Explanation:

Given that the initial speed of a cannon ball is 0.20 km/s. If the ball is to strike a target that is at a horizontal distance of 3.0 km from the cannon. The minimum time of flight for the ball can be calculated by using the formula for speed

speed = distance / time

Where

speed = 0.2 km/s

distance = 3 km

Substitute the two parameters into the formula

0.2 = 3 / t

make t the subject of the formula

t = 3/0.2

t = 15 s

Therefore, the minimum time of flight for the ball is 15 seconds

I'm pretty sure your answer should be

C. Riding uphill, the boy's work is converted into potential energy, riding on level ground, his work is converted into kinetic energy.

Complete question

The diagram for this question is shown on the first uploaded image

Answer:

 [tex]T_a   =  44.8 \  N [/tex] ,   [tex]  F =  86.03 \ N  [/tex]

Explanation:

From the question we are told that

    The magnitude of  [tex]T_b  =  80 N[/tex]

From the diagram we can see that

     [tex]Ta * sin (38) +  F *  sin (29) =   T_b *  cos  (30) \  \cdots (1)[/tex]

    [tex]Ta * sin (38) +  F *  sin (29) = 80 *  cos  (30) \  \cdots (1)[/tex]

   [tex]0.616 Ta +  0.485F  = 69.3 \  \cdots (1)[/tex]

=>  [tex]T_a   = \frac{69.3 - 0.485F}{0.616}[/tex]

Also

    [tex]T_a  *  cos(38) + T_b *  sin (30)= F *  cos (29) \  \cdots  (2)[/tex]

=>   [tex]T_a  *  cos(38) + 80*  sin (30)= F *  cos (29) \  \cdots  (2)[/tex]

=>   [tex]0.788 T_a + 40 =  0.875 F \  \cdots  (2)[/tex]

=>  [tex]0.788 [\frac{69.3 - 0.485F}{0.616}]+ 40 =  0.875 F[/tex]

=>  [tex]  88.65  -  0.6204 F + 40 =  0.875 F[/tex]

=>  [tex]  88.65  + 40 =  0.875 F+0.6204 F [/tex]

=>  [tex]  128.65  =  1.4954 F [/tex]

=>  [tex]  F =  86.03 \ N  [/tex]

substituting  this obtained value  for F in the above equation

       [tex]T_a   = \frac{69.3 - 0.485(86.03)}{0.616}[/tex]

      [tex]T_a   =  44.8 \  N [/tex]

Answer: from the vertical, one should aim  86.6°

Explanation:

height of the center of object = 7.0 m - 0.05 m = 6.95 m

now let the bullet hits centre at point A height x meters from the ground

also let t be the time taken for the bullet to hit the object

so distance travelled by the target will be

d = h - x = 6.95 - x

now using the equation of motion

d = 1/2gt²

so 1/2gt² = 6.95 - x

x = 6.95 - 1/2gt² .........let this be equ 1

let angle of fire be ∅

so v(cos∅) × t = 100

our velocity v is 1200 ft/sec = 365.76 m/s

365.76(cos∅) × t = 100 ........equ 2

also vertical position of the bullet after t is

y = y₀ + c(sin∅)t - 1/2gt²

y = 1 + 365.76(sin∅)t - 1/2gt² ----- equ 3

After time t. the vertical position x and y are same, else the bullet wouldn't have strike target at centre, so;

x = y

we substitute

equ 1 = equ 3

6.95 - 1/2gt² = 1 + 365.76(sin∅)t - 1/2gt²

6.95 - 1 = 365.76(sin∅)t - 1/2gt² +  1/2gt²

5.95 = 365.76(sin∅)t

t = 5.96 / 365.76(sin∅)

now input the above equ  into equ 2

365.76(cos∅) ×  5.96/365.76(sin∅) = 100

5.95(cos∅)/sin∅ = 100

tan∅ = 5.95/100 = 0.0595

∅ =  3.40°

therefore from the vertical, one should aim (90° - 3.40°) = 86.6°

Answer:

cause without gravity, the earth will start to move away from the orbit and crash into the sun like a raining meteor of babies diaper falling on the ground of smelly dunken doughnuts

Explanation:

lol

Answer:

Solids can hold their shape because their molecules are tightly packed together. Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms.

Answer : The volume of water in graduated cylinder is 15.5 mL.

Explanation :

As we know that for the measurement of the volume of liquid in graduated cylinder are shown by placing the graduated cylinder on the flat surface and then view the height of the liquid in the graduated cylinder with the naked eyes directly level with the liquid.

The liquid will tend to curve downward that means this curve is known as the meniscus.

In the case of colored liquid, we are always read the upper meniscus of the liquid for the measurement.

In the case of colorless liquid, we are always read the lower meniscus of the liquid for the measurement.

In the given image, there are 5 larger and 5 smaller division between the 15 and 20 and the solution is colored. The value of larger division is 1 mL and smaller division is 0.5 mL.

So, we will read the upper meniscus of the liquid for the measurement.

Hence, the volume of water in graduated cylinder is 15.5 mL.

Answer:

25,300,000,000,000 miles away

Answer:

True

Explanation:

Whenever electrons are transferred between objects, neutral matter becomes charged. For example, when atoms lose or gain electrons they become charged particles called ions. Three ways electrons can be transferred are conduction, friction, and polarization. In each case, the total charge remains the same.

I tried, hope this helps :)

* I might be wrong though

Complete Question

Two electrons, each with mass m and charge q, are released from positions very far from each other. With respect to a certain reference frame, electron A has initial nonzero speed v toward electron B in the positive x direction, and electron B has initial speed 3v toward electron A in the negative x direction. The electrons move directly toward each other along the x axis (very hard to do with real electrons). As the electrons approach each other, they slow due to their electric repulsion. This repulsion eventually pushes them away from each other.

A) Which of the following statements about the motion of the electrons in the given reference frame will be true at the instant the two speeds reach their separations?

A) Electrons A is moving faster than electron B.

B) Electron B is moving faster than electron A.

C) Both electrons are moving at the same (nonzero) speed in the opposite direction

.D) Both electrons are moving at the same (nonzero) speed in the same direction.

E) Both electrons are momentarily stationary.

2) What is the minimum separation[tex]r_{min}[/tex] that the electrons reach?

Answer:

1

The  correct option is  E

2

[tex]r_{min} =  \frac{kq^2}{4 mv^2}[/tex]

Explanation:

From the question we are told that

   The mass of each electron  is  m  

    The  charge of each electron  is  q

    The speed of electron A is  v

    The  speed of electron B  is  3v

Generally at their point of separation the repulsion force is equal to the force that is propelling the electrons due to this the electrons are  momentarily stationary

Generally the total initial kinetic energy of both electron is mathematically represented as  

         [tex]K_{inT} =  K_A + K_B[/tex]

=>      [tex]K_{inT}  =  \frac{1}{2}m (v)^2 + \frac{1}{2} m (3v)^2[/tex]

=>      [tex]K_{inT} =  \frac{1}{2} (mv^2 + 9v^2m)[/tex]

=>      [tex]K_{inT} =  5mv^2 [/tex]

Generally the total  final  kinetic energy of both electron is mathematically represented as

         [tex]K_{fT} =  \frac{1}{2} *m * v^2 + \frac{1}{2} *m * v^2[/tex]

Here v is the velocity due to the repulsion force

          [tex]K_{fT} =  mv^2 [/tex]

Generally the final  potential energy of the both electrons is  

         [tex]P_f  =  \frac{ k *  q^2}{r_{min}}[/tex]

Here k is the coulombs constant

So according to energy conservation law

     [tex]K_{inT} =  K_{fT}  +  P_f[/tex]

=>   [tex]5mv^2 =  mv^2 +   \frac{ k *  q^2}{r_{min}} [/tex]

=>   [tex]r_{min} =  \frac{kq^2}{4 mv^2}[/tex]

Answer:

between point c and point D

Answer:

a = 16.5 x 10⁻⁶ m = 16.5 μm

Explanation:

Here we will use the diffraction equation:

y = mλL/a

where,

y = distance between two consecutive dark fringes = 5.34 cm = 0.0534 m

m = order of diffraction = 1

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = Distance between hair and screen = 1.4 m

a = thickness of hair = ?

0.0534 m = (1)(6.33 x 10⁻⁷ m)(1.4 m)/(a)

a = (6.33 x 10⁻⁷ m)(1.4 m)/(0.0534 m)

a = 16.5 x 10⁻⁶ m = 16.5 μm

Answer:

a. approximately [tex]1.1\; \rm m[/tex] (first minimum.)

b. approximately [tex]2.2\; \rm m[/tex] (first maximum.)

c. approximately [tex]3.4\; \rm m[/tex] (second minimum.)

d. approximately [tex]4.7\; \rm m[/tex] (second maximum.)

Explanation:

Let [tex]d[/tex] represent the separation between the two speakers (the two "slits" based on the assumptions.)

Let [tex]\theta[/tex] represent the angle between:

The distance between the microphone and point [tex]P_0[/tex] would thus be [tex]9.4\, \tan(\theta)[/tex] meters.

Based on the assumptions and the equation from Young's double-slit experiment:

[tex]\displaystyle \sin(\theta) = \frac{\text{path difference}}{d}[/tex].

Hence:

[tex]\displaystyle \theta = \arcsin \left(\frac{\text{path difference}}{d}\right)[/tex].

The "path difference" in these two equations refers to the difference between the distances between the microphone and each of the two speakers. Let [tex]\lambda[/tex] denote the wavelength of this wave.

[tex]\displaystyle \begin{array}{c|c} & \text{Path difference} \\ \cline{1-2}\text{First Minimum} & \lambda / 2 \\ \cline{1-2} \text{First Maximum} & \lambda \\\cline{1-2} \text{Second Minimum} & 3\,\lambda / 2 \\ \cline{1-2} \text{Second Maximum} & 2\, \lambda\end{array}[/tex].

Calculate the wavelength of this wave based on its frequency and its velocity:

[tex]\displaystyle \lambda = \frac{v}{f} \approx 0.211\; \rm m[/tex].

Calculate [tex]\theta[/tex] for each of these path differences:

[tex]\displaystyle \begin{array}{c|c|c} & \text{Path difference} & \text{approximate of $\theta$} \\ \cline{1-3}\text{First Minimum} & \lambda / 2 & 0.112 \\ \cline{1-3} \text{First Maximum} & \lambda & 0.226\\\cline{1-3} \text{Second Minimum} & 3\,\lambda / 2 & 0.343\\ \cline{1-3} \text{Second Maximum} & 2\, \lambda & 0.466\end{array}[/tex].

In each of these case, the distance between the microphone and [tex]P_0[/tex] would be [tex]9.4\, \tan(\theta)[/tex]. Therefore:

Interference is the result when two or more waves combine

The distance between P₀ and

a. The first intensity minimum is approximately 1.06 m

b. The first intensity maximum is  approximately  2.165 m

c. The second intensity minimum is approximately 3.36 m

d. The second intensity minimum is approximately 4.72 m

The reasons the above values are correct are given as follows:

The known parameters are;

The distance between the two speakers = 0.94 m

Frequency of the tone produced by the two speakers = 1,630 Hz (in sync)

The line along which the microphone moves is parallel to the line between the two speakers

The distance between the parallel lines above = 9.4 m

The speed of sound in air, v₀ = 344 m/s

The interference pattern of light passing between two slits is to be applied

a. Based on the arrangement, we have;

P₀ = 9.4 × tan(θ)

Where;

θ = The angle formed formed by the line from the microphone to the midpoint of the distance between the two speakers and the perpendicular bisector to the line joining the two speakers

Based on Young's double-slit experiment, we have;

[tex]sin(\theta) = \dfrac{Path \ difference}{d}[/tex]

Where;

d = The distance between the two speakers representing the slits

The path difference for a minimum is n × λ/2

Where n = 1,  3, 5,...,(set of odd numbers)

The path difference for a maximum intensity sound is n·λ

Where n = 1, 2. 3, ..., n (n is an integer)

The wavelength, is given as follows;

[tex]\lambda = \dfrac{v}{f}[/tex]

Therefore;

[tex]\lambda = \dfrac{344}{1,630} = \dfrac{172}{815} \approx 0.211[/tex]

The wavelength, λ ≈ 0.211

Therefore, the angle, θ, for the first minima, θ, ≈arcsine(0.211/(2×0.94))

First minima, λ/2, P₀ =9.4 × tan(arcsine(0.211/(2×0.94))) ≈ 1.06

First maxima, λ, P₀ =9.4 × tan(arcsine(0.211/(94))) ≈ 2.165

Second minima, 3·λ/2, P₀ = 9.4 × tan(arcsine(3*0.211/(2×0.94))) ≈ 3.36

Second maxima, 2·λ, P₀ = 9.4 × tan(arcsine(2*0.211/(0.94))) ≈ 4.72

Therefore;

a. The distance between P₀ and the first intensity minimum is ≈ 1.06 m

b. The distance between P₀ and the first intensity maximum is ≈ 2.165 m

c. The distance between P₀ and the second intensity minimum is ≈ 3.36 m

d. The distance between P₀ and the second intensity minimum is ≈ 4.72 m

Learn more about interference of sound waves here:

https://brainly.com/question/14006922

https://brainly.com/question/12096166

Answer:

Substance X transfers thermal energy to substance Y through conduction. What is an accurate conclusion about the condition of both substances before conduction occurred? Substance X's molecules were faster than substance Y's.

Explanation:

An accurate conclusion about the condition of both substances before conduction occurred is substance X’s molecules were faster than substance Y’s.

Thermal energy is the energy released in the form of heat. It manifests itself by releasing heat. It results from the atoms' movement or vibration, so it displays the system's internal energy. We define thermal energy as part of the internal energy of a system.

It is an extensive quantity, it depends on the size of the system, or on the amount of substance it contains. The SI unit of thermal energy is the joule (J). It is the energy contained within the system, excluding the kinetic energy of motion of the system as a whole and the potential energy of the system. Thermal energy is often classified into various types on the basis of how this internal energy, in the form of heat, is transferred from one body to another.

The correct answer is option C.

Learn more about thermal energy, refer:

https://brainly.com/question/9621699

#SPJ2

Answer:

z1/z2

Explanation:

we have no quantum effects therefore we can make use of Maxwell Boltzmann distribution in the description of this system.

using the boltzman distribution the probability of finding a particle in energy state

[tex]P_{ei} = \frac{gie^{-ei/kol} }{z}[/tex]

we have

gi to be degeneration of the ith state

ei to be energy of ith state

[tex]z=e^{-ei/kbt}[/tex] summation

[tex]P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}[/tex]

We have R to be equal to

[tex]\frac{P_{ope} }{P_{Close} } = \frac{Z1}{Z2}[/tex]

Answer:

a

[tex]D =  1162.7 \  m [/tex]

b

[tex]\beta =- 65.55^o[/tex]

Explanation:

From the question we are told that

  The speed of the airplane is  [tex]u  =  92.3 \ m/s[/tex]

   The  angle is  [tex]\theta = 51.1^o[/tex]

    The altitude of the plane is  [tex]d =  532 \  m[/tex]

Generally the y-component of the airplanes velocity is  

       [tex]u_y  =  v *  sin (\theta )[/tex]

=>     [tex]u_y  =   92.3 *  sin ( 51.1 )[/tex]

=>     [tex]u_y  =  71.83  \ m/s[/tex]

Generally the displacement  traveled by the package in the vertical direction is

       [tex]d =  (u_y)t +  \frac{1}{2}(-g)t^2[/tex]

=>       [tex] -532  = 71.83 t +  \frac{1}{2}(-9.8)t^2[/tex]

Here the negative sign for the distance show that the direction is along the negative y-axis

 =>   [tex]4.9t^2 - 71.83t - 532 = 0[/tex]

Solving this using quadratic formula we obtain that

    [tex]t =  20.06 \  s[/tex]

Generally the x-component of the velocity is  

     [tex]u_x  =  u  *  cos (\theta)[/tex]

=>    [tex]u_x  =   92.3  *  cos (51.1)[/tex]

=>   [tex]u_x  =   57.96 \ m/s[/tex]

Generally the distance travel in the horizontal  direction is    

     [tex]D =  u_x  *  t[/tex]

=>   [tex]D =  57.96  *   20.06 [/tex]

=>    [tex]D =  1162.7 \  m [/tex]

Generally the angle of the velocity vector relative to the ground is mathematically represented as

       [tex]\beta  =  tan ^{-1}[\frac{v_y}{v_x } ][/tex]

Here [tex]v_y[/tex] is the final  velocity of the package along the vertical  axis and this is mathematically represented as  

     [tex]v_y  =  u_y  -   gt[/tex]

=>  [tex]v_y  =  71.83  -    9.8 *  20.06[/tex]

=>  [tex]v_y  =  -130.05 \  m/s [/tex]  

and  v_x is the final  velocity of the package which is equivalent to the initial velocity [tex]u_x[/tex]

So

       [tex]\beta  =  tan ^{-1}[-130.05}{57.96 } ][/tex]

       [tex]\beta =- 65.55^o[/tex]

The negative direction show that it is moving towards the south east direction

Answer:

mine is 9.75 so take that as you will

Explanation:

Answer:

Acceleration

Explanation:

I am writing this because it must be 20 characters to submit

Answer:

21

Explanation:

21

Answer:

speed is equal to distance divided by time

(for the chart i'm assuming that the time is measure in seconds but if not just change the s with whatever time unit you are using)

A. 0.224 m/s

B. 0.230 m/s

C. 0.258 m/s

D. 0.265 m/s

E. 0.301 m/s     (fastest speed)

F. 0.217 m/s     (slowest speed)

Answer:

3.176hours

Explanation:

270/85=3.126 hours DISTANCE / SPEED = TIME

Answer: Ranking :  a = c  > b > d      

Explanation:

The amount of electric flux is directly proportional to the amount of charge enclosed.

The greater the charge enclosed, the greater the electric flux through their surface

a)

 A cube with sides 10 cm long that contains a + 2.00 micro-coulomb point charge

∅ = Q/∈₀ = (2.00 x 10⁻³) / (8.85 x 10⁻¹²) = 2.26 x 10⁸ Nm²/C

b)

A cube with sides 10 cm long that contains a + 1.00 micro-coulomb point charge

∅ = Q/∈₀ = (1.00 x 10⁻³) / (8.85 x 10⁻¹²) = 1.13 x 10⁸ Nm²/C

c)  

A cube with sides 20 cm long that contains a + 2.00 micro-coulomb point charge

∅ = Q/∈₀ = (2.00 x 10⁻³) / (8.85 x 10⁻¹²) = 2.26 x 10⁸ Nm²/C

d)  A cube with sides 20 cm long that contains a + 1.00 micro-coulomb point charge

∅ = Q/∈₀ = (1.00 x 10⁻³) / (8.85 x 10⁻¹²) = 1.13 x 10⁸ Nm²/C

Ranking :

a = c  > b > d      

Answer:

Using Gauss's Law, the total amount of electric flux through a closed surface is proportional to the charge enclosed. (The surface integral of the electric field over the closed surface equals the enclosed charge divided by the constant of proportionality, the permittivity of free space.) So, since surfaces 1 and 3 have the most positive enclosed charge, they have the most positive electric flux (they have the same). Since surfaces 2 and 4 have the least positive enclosed charge, they have the least positive electric flux. and are the same

thus LHS to RHS; a=c > b=d

Answer:

it's uhh 0.05 my g yup that's the answer

Explanation:

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