Let the ball at the ground be A and that at the top be B.
Assume that you see the motion of A while sitting at B.
You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.
Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.
Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.
Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.
Since B falls freely, he covers a distance of 1/2(g)(1²)=5 (assuming g = 10m/s²)
Thus, they meet at a height of (20–5)m = 15m from the ground.
mars one mission essay
so bassicly Mars is a planet
Explanation:
planet
A ball of mass 2.0 kg is travelling at a speed of 12 m/s. It moves towards an object of mass 3.0 kg which is at rest.
The ball hits the object and sticks to it.
Which row gives the total momentum, and the speed of both objects immediately after the collision?
total momentum (kg m/s)
A- 0
B- 0
С- 24
D- 24
AND..
speed (m/s)
A- 4.8
B- 8.0
C- 4.8
D- 8.0
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Do comment if you have any query.
The velocity for the entire trip is 0.4 m/s as It takes her 500 seconds to make the round trip and 60 kg • m/s2 = (45 kg • v) + (20 kg • 3 m/s).
Path 1 = 400 m В B. A Path 2 = 200 m Path 3 = 300 m. Thus, option C is correct.
What is velocity?A particle's settling velocity known as the rate at which is travels through a still fluid. The specific gravity of the particles, their size, and their shape all have an impact on settling velocity.
A particle in still air will gravitationally settle and reach its terminal velocity fairly quickly. A particle's terminal velocity in a still fluid is referred to as the settling velocity (also known as the "sedimentation velocity").
Understanding variations in the hydraulic regime and interactions between sediment and fluid in the surf zone depends heavily on the particle settling velocity at the foreshore region. In contrast to sedimentation, which is the end product of the settling process, settling is the movement of suspended particles through the liquid.
Therefore, Thus, option C is correct.
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What are nucleic acids, and what are their function and structure? Give an example
IF THE VECTOR COMPONENTS OF VECTOR A ARE MULTIPLIED BY 9 THEN THE MAGNITUDE OF VECTOR A IS INCREASES BY A FACTOR OF .........
Answer:
it increased by 29 sorry hope this helps
I will give Brainliest answer and 5 stars
Jay decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jay traveling?
A. 1 mile/10 minutes
B. 1 mile/15 minutes
C. 1 mile/20 minutes
D. 1 mile/30 minutes
Answer:
James is traveling at 4 miles per hour.
Explanation:
3 miles per 45 minutes
x miles per 60 minutes(1 hour)
___________________
3*60=45*x
180=45x |:45
x=4
what we have learned about the different cultures of Native Americans
Native Americans worldview is deep and intense and infused with spiritual meaning. Everything in their culture ties into their belief system and their love for their land and people.
The surface of this planet is obscured by an atmosphere of thick clouds and toxic gases. What planetary body is it
Answer:
Venus....
Explanation:No explanation just simple answers
10. Which of the following will happen to the respiratory-associated muscles if you were to blow up a balloon?
A. Diaphragm contracts, Internal intercostal would relax
B. Diaphragm would contract, external intercostal would relax
C. Internal intercostal and abdominal muscles would contract
D. External intercostal would contract and diaphragm would relax
Answer:
C
for sure
go for it
..............
ignore this i put the wrong grade sorry
Answer:
Oh its fine i am not in college but its still fine
Explanation:
A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.
a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.
Answer:
a) Answer: 0.16331 m/s
b) Answer: 8522.66 joules
Explanation:
The final speed is 0.1633 m/s.
When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.
What is momentum?A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.
(a) Given parameter:
Mass of the railroad car, M = 2900 Kg.
Mass of the scrap metal, m= 11750 Kg.
Initial speed of the car, u = 0.0825 m/s.
Initial speed of the scrap metal = 0 m/s.
Final speed of the system, v = ?
Then, initial momentum of the system = initial momentum of the car + initial momentum of the scrap metal .
= (29000×0.825 + 117500×0) kg.m/s.
= 23925 kg.m/s.
Final momentum of the system = total mass of the system× final speed
= (29000 + 117500)× v kg.m/s
= 146500v kg.m/s.
Hence, from principle of conservation of momentum,
initial momentum of the system = Final momentum of the system
⇒ 23925 = 146500v
⇒ v = 0.1633 m/s.
The final speed of the loaded freight car is 0.1633 m/s.
(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.
= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.
= 7915.72 Joule.
Hence, 7915.72 Joule kinetic energy is lost in this process.
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As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.
calculate the relative density of a block having dimension 4m x 3m x 2m given its mass in 48000g
Answer:
in the picture
Explanation:
CARRY ON LEARNING
16g 2g/cm3 what is the Volume
Answer:
V = 1.25E-7 cubic meter
A helicopter travelling at a velocity of 15 m/s [W] accelerates uniformly at a rate of 7.0 m/s2 [E] for 4.0 s. What is the helicopter’s final velocity?
If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².
After t = 4.0 s, the helicopter's velocity is
-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s
or 13 m/s [E].
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Imagine you have a ball tied to the end of a string. You hold the other end of the string and swing it around. Suppose the string breaks, what direction will the ball travel
In a titration, 50.00 cm3 of 0.300 mol/dm3
sodium hydroxide solution is exactly neutralized by 25.0
cm3 of a dilute solution of hydrochloric acid.
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Calculate the concentration of the hydrochloric acid. Show your work out
PLS URGENT ANS
Answer:
Step 1: Calculate the amount of sodium hydroxide in moles
Volume of sodium hydroxide solution = 50.0 ÷ 1,000 = 0.05 dm3
Rearrange:
Concentration in mol/dm3 = amount of solute in molvolume in dm3
Amount of solutein mol = concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide = 0.300 × 0.05
= 0.01 5mol
Step 2: Find the amount of hydrochloric acid in moles
The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
So the mole ratio NaOH:HCl is 1:1
Therefore 0.015 mol of NaOH reacts with 0.015 mol of HCl
Step 3: Calculate the concentration of hydrochloric acid in mol/dm3
Volume of hydrochloric acid = 25.00 ÷ 1000 = 0.025 dm3
Concentration in mol/dm3 = amount of solute in molvolume in dm3
Concentration in mol/dm3 = 0.015/0.025
= 0.6 mol/dm3
Step 4: Calculate the concentration of hydrochloric acid in g/dm3
Relative formula mass of HCl = 1 + 35.5 = 36.5
Mass = relative formula mass × amount
Mass of HCl = 36.5 × 0.6
= 21.9 g
So concentration = 21.9 g/dm3
which forces have physicists shown to be the same force under conditions of very high temperature, as confirmed by experiments in particle accelerators?
Answer:
the electromagnetic and weak forces
Explanation:
Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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Two conditions must
be met for work to be done, what are they?
The two conditions are:
1) Application of-force on the body.
2) Displacement of the body in the direction of force.
Hope this helps!
A crankshaft of an engine increases its spin from 1,000 rpm to 1,500 rpm in 0.5 s. What is its angular acceleration? (1 rev=2π rad)
600 rad/s2
100 rad/s2
500 rad/s2
60 rad/s2
the answer is 100 rad/s2
Alex drops a soccer ball and a table tennis ball from the top of a ladder. He wants to compare the velocities of the balls just before they hit the ground.
Which formula should Alex use to calculate the velocity of each ball,
assuming they are in free fall?
A) v=Gt
B) g=vt
C) t=vg
D) v=G/t
Answer:
d is the correct answer
Explanation:i did this math
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
The question is fishing for "balanced force".
But the description in the question is terrible.
Dhdjrjfbjsjfnsmctejzbrnj
The answer is D
I hope this helps :)
what is the main difference between a substance going through a physical change and one going through a chemical ?
Answer: Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.
Answer:
just give the other person brainlyest
Explanation:
newtons 2nd law of the law of…
Which choice can be classified as a pure substance?
A. homogeneous mixture
B. compound
C. heterogeneous mixture
D. solution
Cuáles son las diferencias, con respecto al proceso de extracción y tratamiento, entre
el gas propano y el gas metano.
Answer:
la burguesía era de clase alta y en su mayoría rica. La gente de clase trabajadora generalmente trabajaba con un salario mínimo y solo tenía suficiente dinero para poner comida en la mesa. En este momento, la gente veía a los trabajadores de clase media como menos que otras personas.
Explanation:
An object of mass of 2.0 kg rotates at constant speed in a horizontal circle of radius 5.0 m. The time
for one complete revolution is 3.0 s. What is the magnitude of the resultant force acting on the object.
Explanation:
follow the above attachment to get the answer.
A 455 kg cannon fires a 21 kg cannonball at 26 m/s. If the cannon is on wheels, at what velocity does it move backward?
Answer:
A cannon ball of mass 4.0 kg is fired from a stationary 96 kg cannon at 120 m/s. Calculate the velocity of the cannon immediately after firing.
total momentum of cannon and cannon ball before = 0 kg m/s - because neither object is moving
total momentum of cannon and cannon ball after collision = 0 kg m/s - because momentum is conserved
Momentum of cannon ball after firing = 4.0 × 120 = 480 kg m/s.
Momentum of cannon after firing = -480 kg m/s (because it recoils in the opposite direction and 480 - 480 = 0 kg m/s, the total momentum after collision).
Rearrange p = m v to find v:
v = p/m
v = 480 divided by 96
v = 5.0 m/s
Note that the forward velocity of the cannon ball was given a positive value. The negative value for the cannon's velocity shows that it moved in the opposite direction.
20 examples of electropositive radical