You want to bake a 20" diameter pizza. Give exact answers.

a. What should be the circumference of the pan?
b. What is the area of the pizza?
c. If you cut the pizza into 8 congruent slices, what is the area of one slice?
d. What is the length of the crust of one slice?

Answers

Answer 1

Step-by-step explanation:

pizza = circle

the area of a circle is

pi×r²

r = radius (half of the diameter). in our case 20/2 = 10".

the circumference of a circle is

2×pi×r

again, r = radius.

in our case that gives us

a.

2×pi×r = 2×pi×10 = 20×pi = 62.83185307... "

b.

the area of the pizza is

pi×10² = 100×pi = 314.1592654... in²

c.

it is 1/8 of the whole area, of course.

314.1592654... / 8 = 39.26990817... in²

d.

it is 1/8 if the whole circumference, of course.

62.83185307... / 8 = 7.853981634... "


Related Questions

if n=14 when m=4 find n when m=23

Answers

divide 14 by 4 which gives you 3.5
3.5 x 23 = 80.5
therefore n=80.5 or you round up and get 81.

Two math classes took the same quiz. The scores of 10 randomly selected students from each class are listed below.

Sample of Class A: 75, 80, 60, 90, 85, 80, 70, 90, 70, 65

Sample of Class B: 95, 90, 85, 90, 100, 75, 90, 85, 90, 85

Based on the medians of the scores for each class, what inference would you make
about the quiz scores of all the students in Class A compared to all the students in
Class B? Explain your reasoning to justify your answer.
(written answer)

Answers

Answer:

The score of class b were better than the scores of class a.

the median for class a was 77.5

the median for class b was 90

therefore class b overall scored better on the quiz than class a

Step-by-step explanation:

hope this helps :)

Which pairs of polygons are similar?

Select each correct answer.

Answers

Answer:

Two polygons are similar if their corresponding angles are congruent and the corresponding sides have a constant ratio (in other words, if they are proportional). Typically, problems with similar polygons ask for missing sides.

Step-by-step explanation:

this is the correct answer

Help me, paid well just answer

Answers

Answer:

30.67

Step-by-step explanation:

[tex] \frac{9}{ \sin(x) } \: = \frac{16}{ \sin(115) } \\ \\ \frac{9}{ \sin(x) } \: = \frac{16}{ 0.91 } \: \: \\ \\ \frac{9 \times 0.91}{16} = \sin(x) \\ x = 30.67[/tex]

A model satellite has a scale of 1 cm : 3 m. If the real satellite is 18 m wide, then how wide is the model satellite?

A. 54 cm
B. 1 cm
C. 6 cm
D. 15 cm

Answers

C

1cm : 3cm
= 1 x 6 cm : 3 x 6 m
= 6cm : 18m

Here is a right angled triangle work out the value of x using trigonometry

Answers

[tex]~~~~~\sin 30^{\circ} = \dfrac{\text{Perpendicular}}{\text{Hypotenuse} }\\\\\\\implies \dfrac 12 = \dfrac{8}x\\\\\\\implies x = 8\cdot2\\\\\\\implies x = 16 ~ \text{cm.}[/tex]

The measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.

What is a right-angle triangle?

It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.

It is given that:

A right-angle triangle is shown in the picture.

To find the side length of the hypotenuse apply the sin ratio

sin30 = side opposite to the angle/hypotenuse

1/2 = 8/x

x = 8(2)

x = 16 cm

Thus, the measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.

Learn more about the right-angle triangle here:

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#SPJ2

The value of 30 is between which two integers


Answers

Answer:

[tex]5 < \sqrt{30} < 6[/tex]

Step-by-step explanation:

[tex]Locate\ \sqrt{30}\ between\ two\ integers:\\ \downarrow\\ 5 < \sqrt{30} < 6[/tex]

I hope this helps you

:)

Which function is represented by the graph below?

Answers

Answer:

[tex]f(x)=2^x[/tex]

Step-by-step explanation:

Exponential function:

[tex]f(x)=a(b^x)+c[/tex]

Step 1. Find a, y-intercept

Step 2. Find b, slope

Step 3. Find c, horizontal asymptote

a = 1

m = (y₂ - y₁)/(x₂ - x₁)

m = (3 - 1)/(1 - 0) = 2/1

b = 2

c = 0

[tex]f(x)=1(2^x)+0\\f(x)=2^x[/tex]

Hi can someone help me find domain and range

Answers

Answer:

Step-by-step explanation:

Domain is ( - ∞ , ∞ )

Range is [ 0 , 1 ] ∪ ( 2 , ∞ )

Please help i have an assignment due TODAY i need to get this done
rules:
NO LINKS! im not getting myself a virus

Answers

Answer:

Line LK is the dimameter

Step-by-step explanation:

A diameter is a line that goes through the center and goes from one end a the circle to the other end of the circle.

Hope this helps!!

Tori invests $1,500 into the stock market which earns 9% per year. In 20 years, how much will Tori's investment be worth if interest is compounded semiannually (twice a year)?​

Answers

[tex]\bold{ANSWER:}[/tex]
$8725

[tex]\bold{EXPLANATIONS:}[/tex]

The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year.

8.40, 8.35, 8.50, 8.40, 8.90, 8.20, 8.50, 8.30, 8.50, 8.50, 8.75, 8.30, 8.10, 8.55

Which box plot best represents this data?

Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and the interquartile ranges approximately between 8.3 and 8.5 and the median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.7 and interquartile ranges approximately between 8.3 and 8.6 and median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.2 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.6 and median is approximately at 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.5.

Answers

To create the dot plot you will list the data in order and use the given numbers to create the box plot.

8.10, 8.20, 8.30, 8.32, 8.34, 8.50, 8.50, 8.50, 8.55, 8.60, 8.60, 8.65, 8.65, 8.90

Lower extreme: 8.10

Upper extreme: 8.90

Median: 8.50

1st/lower quartile: 8.32

3rd/upper quartile: 8.60

Please see the attached picture for the boxplot.

Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross the x-axis at the zero.

Answers

Answer: See below

Step-by-step explanation:

To find the factor,

f(x) = 0

[tex]\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}[/tex]

So,

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

Therefore,

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of 20 years. The salvage value is $4,000.00. The book value at the end of year 2 is

Answers

The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.

What is the book value at the end of  year 2?

Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.

Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Depreciation expense in year 1:

Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Undepreciated life of the asset = 20

(20 / 210) x ($79,600 - 4,000) = 7200

Depreciation expense in year 2:

19 / 210 x ($79,600 - 4,000) = 6840

Book value = 79600 - 7200 - 6840 = $65,560

To learn more about depreciation, please check: https://brainly.com/question/25552427

MY SISTER NEEDS HELP IN MATH...

Answers

Answer:

[tex]b. \: 16[/tex]

Step-by-step explanation:

Divide the numbers ⬇

16 ÷ 4 = 4

[tex](4 + 2) \times 2 + 4[/tex]

Add the numbers ⬇

4+2=6

[tex]6 \times 2 + 4[/tex]

Multiply the numbers ⬇

6 x 2 = 12

[tex]12 + 4[/tex]

Add the numbers ⬇

[tex]12 + 4 = 16[/tex]

OPTION B IS RIGHT :)

hope this helps!! Mark me brainliest please!

Answer: B. 16

Step-by-step explanation:

Hope this helps!

four dice are thrown simultaneously. what will be the probability that all of them have the same face ?​

Answers

Answer:

1/216

Step-by-step explanation:

A dice (assuming it is from 1-6) has 6 faces. There are 4 dices.

equation will be

6*6*6=answer

Multiply 6 three times by itself because there are 4 dices. That is because One die would be 1

Two would be 1/6

Three would be 1/36

And four would be the ...

Asnwer=216

The volume of the given figure is __ ft3

Answers

Answer:

I believe the answer is 20

Which of the following sets of ordered pairs defines a relation that
is NOT a function?
O {(1, 5), (5, 1), (7, 9), (9, 7)}
O {(6, 7), (8, 10), (13, 9), (21, 10)}
O {(2, 2), (3, 4), (5, 8), (12, 16)}
O {(5, 14), (5, 16), (7, 23), (11, 31)}

Answers

para lang po sa points hehe

please help
i cant do this

Answers

Answer:

42 sq. cm

Step-by-step explanation:

Answer: 42 sq. cm

Length of Big Rectangle: 7

Width of Big Rectangle 7+0.5+0.5 = 8

Area of Big Rectangle: 56

Area of Small Rectangle = 0.5*7 = 3.5

Area of 4 Small Rectangles = 3.5 *4 = 14

Shaded Area = Big Rectangle - 4 Small Rectangles = 56 - 14 = 42 sq. cm

To reassure the answer above is correct

Complete the equation of the line through (-10,-7)(-5,−9)

Answers

Slope
-9+7 -2
—— = ——
-5+10 5

Equation of a line
y+7=-2/5(x+10)
y+7=-2/5x-4
y=-2/5x-11

When my pot of paint is half full, it weighs 5.8 kg. When my pot of paint is one quarter full, it weighs 3.1 kg.
What is the weight of the full pot?

Answers

The paint in the pot is an illustration of a linear equation and the weight of the full pot is 11.2 kg

How to determine the weight of the full pot?

The given parameters can be represented using the following ordered pairs:

(x,y) = {(0.5, 5.8) and (0.25, 3.1)}

The slope of the equation is calculated using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (3.1 - 5.8)/(0.25 - 0.5)

Evaluate

m = 10.8

The equation is then calculated using:

y = m(x - x1) + y1

This gives

y =  10.8(x - 0.5) + 5.8

Expand

y =  10.8x + 0.4

When the pot is full, we have x = 1

So, the equation becomes:

y =  10.8 * 1 + 0.4

Evaluate

y =  11.2

Hence, the weight of the full pot is 11.2 kg

Read more about linear equations at:

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Does anyone know how to get free answers? I ran out, I have a lot of points I just need more free answers again

Answers

Answer: I believe that by helping or answering others you can get get questions, but I do know there is a limited amount of questions being able to ask before paying monthly. Hope this helps

Answer:

What you have to do is answer peoples question to gain more

Step-by-step explanation:

32 divided by 1.6 how to work out

Answers

Answer:

20

Step-by-step explanation:

[tex]\frac{32}{1.6} =\frac{32}{\frac{16}{10}} =32*\frac{10}{16} =\frac{320}{16} =20[/tex]

So the answer is 20

What is the length of the diameter of a circle with a radius that is 13 centimeters? cm

Answers

Answer:

13 this is the ansewer to this

Why is circle 1 similar to circle 2?

Circle 1: center (2, 3) and radius 4

Circle 2: center (2, 3) and radius 12

Circle 1 and circle 2 have the same center.

Circle 2 is a dilation of circle 1 with a scale factor of 3.

Circle 1 and circle 2 are reflections of each other.

Circle 2 is a dilation of circle 1 with a scale factor of 8.

Answers

circle 2 is a dial at ion of circle 1

Sue has $500 in an account for 9 years at a compound rate of 7.5%. How much does she have?

Answers

Answer:

she has about $3750 in her acount.

Step-by-step explanation:

hope this helps you!

The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 1000
years?

Answers

Answer:

258.65 mg will be remain after 1000 years

Step-by-step explanation:

This problem can be solved several ways, I prefer the natural log approach for reasons I won’t go into here:

Activity final = Activity initial e^-kt, where

k = the decay constant, = ln2/half life = 0.693/1590, = 0.000436/year

t = the decay time, in the same time base as k

The problem can be worked in units of activity, mass, or number of atoms.

400 x e^-0.000436 x 1000 = 400 x e^-.436 = 258.65 mg

you can check this by estimating. There is about 2/3 of a half life, so there should be more than 200 mg, which would be the value at one half life.

Find the area of the sector.



a. 11.16 in²

b. 44.66 in²

c. 50.24 in²

d. 2.8 in²

Answers

Hi!

Circle Area Formula

[tex]A=\pi r^2[/tex]

We will start by solving for the area of the entire figure.

Plugin the values into the circle area formula. We will use 3.14 for pi:

[tex]A=3.14(4)^2[/tex]

Simplify:

[tex]A=50.24[/tex]

Now, this is the area of the entire circle, but we only want that certain shaded region.

We know that a circle has a total of 360 degrees, and the shaded sector is simply 80 degrees.

We can divide to see how much of the circle is shaded:

80 / 360 = 0.22...

Now, we can take this number and multiply it by 50.24 (our answer from above) to get the area of the shaded sector:

0.22 * 50.24 = 11.16

Therefore, your answer is A.

For a similar problem, see:

https://brainly.com/question/11952845

need help with #10 :’)

the # is “Which of the following expressions is equivalent to 42 + 63?

A- 3(15+21)

B- 6(7+9)

C- 7(6+9)

D- 14(3+3)

8

Answers

Answer:

the answer is c

Step-by-step explanation:

first add : 42+63=105

so you need to solve the expressions until you find the one that equal the same amount.

start with the problem in the parenthesis then multiply.

you will find that C equals 105

6+9=15

15×7=105

Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling via a chain. Find an expres- sion for the tension in the string and the chain.​

Answers

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

What is tension?

This is the opposing force in a stretched material.

a. Tension in the string

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

T = tension in sring and W = weight of particle = mg where m = mass of particle and g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

b. Tension in chain

The expression for the tension in the chain is T = 2mg

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

T' = tension in chain and T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

Learn more about tension here:

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