You throw a water ballon straight up with a velocity of 12 m/s. What is its maximum height

Answers

Answer 1

Answer:7.35 meters

Explanation:

Assuming that air resistance is negligible, we can use the kinematic equation:

h = (v^2)/(2g)

where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values:

h = (12^2)/(2 × 9.8)

h = 7.35 meters

Therefore, the maximum height of the water balloon is approximately 7.35 meters.


Related Questions

A ballast bag is dropped from a balloon that is 300 m above the ground and rising at 13 m/s. For the bag, find (a) the maximum height reached, (b) its position and velocity 5.0 s after it is released, and (c) the time at which it hits the ground.

Answers

a. The maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

b. 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s

c. The ballast bag hits the ground approximately 18.1 s after it is released.

(a) To find the maximum height reached by the bag, we can use the kinematic equation:

v_f^2 = v_i^2 + 2aΔy

where v_f is the final velocity (which is zero at the maximum height), a is the acceleration due to gravity (approximately -9.8 m/s^2), and Δy is the change in height.

Rearranging and solving for Δy, we get:

Δy = v_i^2 / (2a) = (13 m/s)^2 / (2*(-9.8 m/s^2)) ≈ 8.45 m

Therefore, the maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

(b) To find the position and velocity of the bag 5.0 s after it is released, we can use the equations:

y = y_i + v_it + (1/2)at^2

v_f = v_i + at

where y_i is the initial height (300 m), v_i is the initial velocity (13 m/s), t is the time elapsed (5.0 s), and a is the acceleration due to gravity (-9.8 m/s^2).

Using these equations, we can find:

y = 300 m + 13 m/s*(5.0 s) + (1/2)(-9.8 m/s^2)(5.0 s)^2 ≈ 177.5 m

v_f = 13 m/s + (-9.8 m/s^2)*(5.0 s) ≈ -36.5 m/s

Therefore, 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s (i.e., it is moving downward).

(c) To find the time at which the ballast bag hits the ground, we can use the equation:

y = y_i + v_i*t + (1/2)at^2

Setting y = 0 (since the ground is at y = 0), y_i = 300 m, v_i = 13 m/s, and a = -9.8 m/s^2, we get:

0 = 300 m + 13 m/st + (1/2)(-9.8 m/s^2)*t^2

Rearranging and solving for t using the quadratic formula, we get:

t = (-13 ± sqrt(13^2 - 4*(-4.9)(300))) / (2(-4.9))

The positive solution is the time at which the ballast bag hits the ground:

t ≈ 18.1 s

Therefore, the ballast bag hits the ground approximately 18.1 s after it is released.

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if five violins sound the same note of 1000Hz, each at the same sound pressure level of 60 dB, what is their total intensity in decibels, compared with the violin alone?

Answers

When five violins play the same note with a sound pressure of 60 dB, the total intensity is 66.99 dB, as opposed to just one violin.

What is an illustration of pressure?

Holding a knife against a fruit piece will demonstrate pressure in an easy way. It won't cut any surface of the fruit if you press the flat part of a knife against it. A sizable area is affected by the force.

What 2 sorts of pressure are there?

Absolute and gauge pressure are the two fundamental forms of pressure, and the reference pressure, which serves as a comparison between them, is what distinguishes them. Someone may find the lingo used to convey the chemical properties of a pressurized system to be a little confusing.

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A charge of 4.60 mC
is placed at each corner of a square 0.100 m
on a side.

A) Determine the magnitude of the force on each charge.
B) Determine the direction of the force on each charge. Assume that the positive x-axis is directed to the right.

Answers

Answer:

A. 1.66x10^-3 N

B. An angle of 45 degrees from the positive x-axis

Explanation:

To solve this problem, we can use Coulomb's law, which states that the force between two point charges is given by:

F = kq1q2/r^2

where k is Coulomb's constant (k=8.99x10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

A) Magnitude of force on each charge:

The force on each charge due to the other three charges is the vector sum of the individual forces. Since the charges are located at the corners of a square, the distance between each pair of charges is r = 0.100 m * sqrt(2) = 0.1414 m.

Using Coulomb's law, the magnitude of the force on each charge is:

F = kq1q2/r^2

= 8.99 x 10^9 N m^2/C^2 * (4.60 x 10^-3 C)^2 / (0.1414 m)^2

= 1.66 x 10^-3 N

So the magnitude of the force on each charge is 1.66 x 10^-3 N.

B) Direction of force on each charge:

The force on each charge due to the other three charges is a vector sum of the individual forces, so we need to use vector addition to find the direction of the net force. We can break the forces into x- and y-components and then add them up.

Since the charges are located at the corners of a square, the force on each charge will be directed along the diagonal of the square. Let's define the positive x-axis to be to the right and the positive y-axis to be up. Then, the direction of the force on each charge will be at an angle of 45 degrees from the positive x-axis.

The x-component of the force will be equal in magnitude for each charge since they are all equidistant from the y-axis. Using trigonometry, we can find that the x-component of the force is:

F(x) = F * cos(45) = 1.18 x 10^-3 N

The y-component of the force will be equal in magnitude for each charge since they are all equidistant from the x-axis. Using trigonometry, we can find that the y-component of the force is:

F(y) = F * sin(45) = 1.18 x 10^-3 N

So the direction of the force on each charge is at an angle of 45 degrees from the positive x-axis and has components of 1.18 x 10^-3 N in the x-direction and 1.18 x 10^-3 N in the y-direction.

Please help (50 points and Brainly)

Answers

The kinetic energy of the airliner of 80000 kg is given 11 × 10⁸ J. Then, the velocity of the airliner will be 165.8 m/s.

What is kinetic energy ?

The kinetic energy of an object is generated by virtue of its motion. When an object starts moving from rest, its potential energy starts to convert into kinetic energy.

The kinetic energy of an object is related to its mass and velocity as follows:

Ke = 1/2 mv²

Given m = 80000 kg

Ke = 11 × 10⁸ J

then v = √(2 Ke/m)

v = √(2 × 11 × 10⁸ J /80000 kg)

  = 165.83 m/s.

Therefore, the velocity of the airliner will be 165.83 m/s.

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The figure shows an arrangement of a very large, charged disk of radius R = 0.2 m and a dipole such that the net electric field at the point marked 'x', at a distance d=3.2 cm from the center of the dipole, is zero. The magnitude of the dipole moment of the dipole is 1.5e-12 C.m. (Figure provided in the photo)


A. Is the disk negatively charged or positively charged?


B. Calculate the charge density of the disk.


C. Calculate the charrge on the disk.

Answers

A. We must examine the direction of the electric field the disk produces in order to identify whether it is negatively or positively charged.

If a charged disk is positively charged, the electric field it produces is directed away from the disk, and if it is negatively charged, the electric field is directed toward the disk.

The electric field owing to the disk must be directed away from the disk since the electric field due to the dipole at point "x" is directed toward the positive charge, proving that the disk is positively charged.

B. The electric field at point 'x' due to the disk can be calculated using Gauss's law, which gives us:

E = σ/(2ε0),

σ/(2ε0) = 0

σ = 0

This indicates that the disk has zero charge density.

C. Since the disk has zero charge density, the charge on the disk is also zero. Therefore, there is no charge on the disk.

Describe the dipole moment using an example.

The symmetry of the molecules is established using the dipole moment. The molecules would not be symmetrical and have some dipole moment if they contained two or more polar links.

For illustration, H2O = 1.84 D and CH 3Cl, or methyl chloride, = 1

Why does a dipole moment exist?

When there is a separation of charge, dipole moments happen.

Dipole moments, which result from variations in electronegativity, can happen between atoms in a covalent link or between two ions in an ionic bond.

The dipole moment increases with the difference in electronegativity.

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I’n a miracle of modern physics a 20.0-kg frictionless…

Answers

The acceleration of the lawn mower is  1.25 m/s².

The velocity of the lawn mower at the given time is 6.25 m/s.

What is the acceleration of the lawn mower?

The acceleration of the lawn mower is calculated by applying Newton's second law of motion as shown below.

Fx = ma

where;

Fx is the horizontal component of the forcem is the mass of the lawn mowera is the acceleration of the lawn mower

F cosθ = ma

where;

θ is the inclination of the force.

a = ( F cosθ ) / m

a = ( 50 N  x  cos60 ) / 20 kg

a = 1.25 m/s²

The velocity of the lawn mower at the given time is calculated as;

v = at

v = 1.25 m/s²  x 5 s

v = 6.25 m/s

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a boy drops a coin down a well that is 225m deep. how long does it take the coin to hit the bottom of the well?

Answers

the time is takes for the coin to hit the bottom of the well. t to obtain 6.87 seconds.

A brief explanation of time: what is it?

Time is a continuous series of events that happen one after another, starting in the past and continuing into the present and the future, according to the definition of time in mathematics. The length of an event, the time between them, or even the sequence of occurrences can all be quantified, measured, or compared using the concept of time.

What does "time" mean in science?

Time, according to physicists, is the flow of past occurrences into the present and the future. A system is essentially timeless if it is unchanging. The fifth dimension of reality, time, can be thought of as the means by which three-dimensional space events are described.

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What is the volume of gold obtained once submerged into the water

Answers

If the crown was indeed made of pure gold, it would displace 31.1 cm^3 of water.

What is Archimedes' principle?

Archimedes' principle is a law of physics that states that when an object is immersed in a fluid, it experiences an upward force equal in magnitude to the weight of the fluid it displaces. In other words, the buoyant force on an object is equal to the weight of the fluid it displaces.

The density of gold is 19.3 g/cm³, which means that a cubic centimeter of gold has a mass of 19.3 grams.

Let V be the volume of water displaced by the crown if it is made of pure gold. According to Archimedes' principle, the volume of water displaced is equal to the volume of the crown. Since the crown is assumed to be made of pure gold, its volume can be calculated as follows:

Density of gold = Mass of crown / Volume of crown

Solving for the volume of the crown, we get:

Volume of crown = Mass of crown / Density of gold

Plugging in the given values, we get:

Volume of crown = (6.00 x 10² g) / (19.3 g/cm³)

Volume of crown = 31.1 cm³

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A bicyclist riding in the rain suddenly applies the brakes and slides to a stop. If the acceleration is −9.5 m/s2 , what is the coefficient of kinetic friction between the bicycle’s rubber tires and the wet concrete?

Answers

Answer & Explanation:

We can use the following equation to solve the problem:

a = -μk*g

where a is the acceleration, μk is the coefficient of kinetic friction, and g is the acceleration due to gravity (9.8 m/s2).

We are given that a = -9.5 m/s2. We can assume that g is constant and equal to 9.8 m/s2. Therefore, we can rearrange the equation to solve for μk:

μk = -a/g

μk = -(-9.5 m/s2) / 9.8 m/s2

μk = 0.969

Therefore, the coefficient of kinetic friction between the bicycle’s rubber tires and the wet concrete is 0.969.

The maximum acceleration is given as 0.2m/s2

A) find the velocity and
displacement of the train in 12s if it starts to speed up from rest.

B) How long will it take for this train to reach a velocity of 54km/ h if it continues to accelerate at the same rate?

Answers

A) the train's final velocity after 12 seconds of accelerating at 0.2 m/s^2 from rest is 2.4 m/s, and its displacement is 14.4 m.

B) it will take the train 75 seconds to reach a velocity of 54 km/h (15 m/s) if it continues to accelerate at the same rate of 0.2 m/s^2.

How The Train's acceleration was calculated

A) If the train starts from rest, its initial velocity is 0 m/s. Using the equation for constant acceleration, we can find the final velocity and displacement of the train after 12 seconds:

Final velocity = initial velocity + acceleration x time

Final velocity = 0 m/s + 0.2 m/s^2 x 12 s

Final velocity = 2.4 m/s

Displacement = (initial velocity x time) + (1/2 x acceleration x time^2)

Displacement = (0 m/s x 12 s) + (1/2 x 0.2 m/s^2 x (12 s)^2)

Displacement = 14.4 m

Therefore, the train's final velocity after 12 seconds of accelerating at 0.2 m/s^2 from rest is 2.4 m/s, and its displacement is 14.4 m.

B) First, we need to convert the final velocity to m/s:

54 km/h = 15 m/s (rounded to two decimal places)

Using the same equation for constant acceleration, we can solve for the time it takes for the train to reach a velocity of 15 m/s with an acceleration of 0.2 m/s^2:

Final velocity = initial velocity + acceleration x time

15 m/s = 0 m/s + 0.2 m/s^2 x time

time = 75 seconds

Therefore, it will take the train 75 seconds to reach a velocity of 54 km/h (15 m/s) if it continues to accelerate at the same rate of 0.2 m/s^2.

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Please help (50 points and Brainly) #6

Answers

The second bullet with a mass of 0.006 kg has more kinetic energy with a value of 4.8 J compared to the first bullet with a mass of 0.003 kg and a KE value of 2.4 J.

What is kinetic energy?

Kinetic energy is the type of energy that an object has because of the motion that it is making. It is the energy that an object possesses as a result of its velocity, and its value is determined by both the mass of the object and the speed at which it is moving. K stands for kinetic energy, m stands for the mass of the object, and v stands for the object's velocity.

The kinetic energy (KE) of an object is given by the formula:

[tex]KE = 1/2 * m * v^2[/tex]

where m is the mass of the object and v is its velocity.

Using this formula, we can calculate the kinetic energy of each bullet:

For the first bullet with a mass of 0.003 kg and velocity of 40.0 m/s:

[tex]KE1 = 1/2 * 0.003 kg * (40.0 m/s)^2 = 2.4 J[/tex]

For the second bullet with a mass of 0.006 kg and velocity of 40.0 m/s:

[tex]KE2 = 1/2 * 0.006 kg * (40.0 m/s)^2 = 4.8 J[/tex]

Therefore, the second bullet with a mass of 0.006 kg has more kinetic energy with a value of 4.8 J compared to the first bullet with a mass of 0.003 kg and a KE value of 2.4 J.

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A water pump of 1.2kw rating pumps 480kg of water into an overhead tank at a height of 5m in 30 seconds. The efficiency of the pump os what​

Answers

The efficiency of the pump defines its capacity to pump water upto a certain height under applied rated power. The formula for the efficiency of the pump can be given by,

η=power required/rated power

Answer and

0.654

what does ARD or " a red " stand for

Answers

Answer:

Atmospheric Reentry Demonstrator

Explanation:

Of thats not right im sorry

If a cube that has a length, height, and width of 4 cm is broken down into 8 cubes of equal size, what is the surface area of the 8 new cubes?

Answers

Answer: When a cube is divided into smaller cubes of equal size, the length, height, and width of each new cube are one-third of the original cube.

So each new cube will have a length, height, and width of 4/3 cm.

To calculate the surface area of each new cube, we need to find the area of each face and then add them up. Each cube has six faces, so we can calculate the surface area of one cube by multiplying the area of one face by six.

The area of one face of the new cube is (4/3)*(4/3) = 16/9 cm².

So the surface area of one new cube is 6*(16/9) = 96/9 cm² = 10.67 cm² (rounded to two decimal places).

Since we have 8 new cubes, the total surface area is 8 times the surface area of one new cube:

Total surface area = 8 * 10.67 cm² = 85.33 cm² (rounded to two decimal places).

Therefore, the surface area of the 8 new cubes is 85.33 cm².

Pleas Help

Questions are in the picture

Answers

Writing by hand as opposed to printing is referred to as handwriting. The term "handwriting" has been more or less limited to denote the distinctive writing style that is unique to each individual.

What is Handwriting?

Schools placed a strong emphasis on teaching handwriting before the common usage of typewriters, when it had more practical value.

At the elementary schools, scales for evaluating the quality of the script from grade to grade were developed, and a number of meticulous investigations of the handwriting movements were conducted.

Research have shown that during writing, both the grip pressure on the penholder and the tip pressure on the paper change continuously. Moreover, the speed of writing is not constant and is dependent on the type of stroke being used.

Therefore, Writing by hand as opposed to printing is referred to as handwriting. The term "handwriting" has been more or less limited to denote the distinctive writing style that is unique to each individual.

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The _________________ the two objects are, the____________ gravitational force they have.

Answers

The farther apart the two objects are, the weaker gravitational force they have. Conversely, the closer the objects are, the stronger the gravitational force between them.

What is gravitational force?

Gravitational force is the force of attraction between two objects due to their masses. The greater the mass of the objects, the greater the gravitational force between them. Similarly, thethe closer the objects are to each other, the greater the gravitational force between them.  This means that if the distance between two objects is doubled, the gravitational force between them is reduced to one-fourth of its original value.

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3. When your body fills with extra electrons and you touch a good conductor, you get a shock. Is this
shock an example of static electricity or an electrical current? Explain your answer. (Hint: Review
the definitions of static and current.)

Answers

When your body fills with extra electrons and you touch a good conductor, you get a shock. This is an example of an electrical current in this type of scenario.

What is Static electricity?

This is referred to as an imbalance of electric charges within or on the surface of a material or between materials and is usually created through human effort.

Electrical shock on the other hand is created through electrical means such as an individual's contact with a good conductor which leads to the body being filled with extra electrons due to the amount of electric current flowing through the material o0r surface.

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Please!!! Brainliest will be picked!
Maria does 1000.0 J of work to lift a 98.0 N air conditioner a distance of 5.8 meters. What is the efficiency of the pulley system Maria uses?

53%

52%

64%

57%

Answers

Answer:

The efficiency of a pulley system is given by the ratio of the output work to the input work, multiplied by 100%. In this case, the input work is the work Maria does to lift the air conditioner, which is 1000.0 J. The output work is the work done by the air conditioner, which is equal to the product of the force applied (98.0 N) and the distance lifted (5.8 m), or:

output work = force x distance = 98.0 N x 5.8 m = 568.4 J

Therefore, the efficiency of the pulley system is:

efficiency = (output work / input work) x 100%

efficiency = (568.4 J / 1000.0 J) x 100%

efficiency = 56.84%

Rounding to the nearest whole number, the efficiency of the pulley system is 57%. Therefore, the answer is option (d), 57%.

Explanation:

Katie pushes a crate with 50N and does 150Nm of work. How far did she push the crate?

Answers

The work done by Katie is equal to the force applied multiplied by the distance over which it is applied.

What is force ?

Force is an invisible push or pull on an object that is exerted by another object. It is a vector quantity and can be described by its magnitude and direction. Force can cause an object to accelerate, decelerate, or remain in its state of motion. Examples of force include gravity, friction, electromagnetic force, and the force of a push or pull. Force is an essential part of our everyday lives, from the force of gravity that keeps us on the ground, to the force of a push or pull that we use to move objects.

Therefore, the equation to calculate the distance is:

Work = Force x Distance

150Nm = 50N x Distance

Distance = 150Nm / 50N

Distance = 3m

Katie pushed the crate 3m.

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A ballast bag is dropped from a balloon that is 300 m above the ground and rising at 13 m/s. For the bag, find (a) the maximum height reached, (b) its position and velocity 5.0 s after it is released, and (c) the time at which it hits the ground.

Answers

308.6 m the maximum height reached.

Define velocity

The main determinant of an object's location and rate of motion is its velocity. It can be explained as the distance an object travels in one measure of time. The displacement of the item in a given amount of time is referred to as velocity.

The distance a person travels in a predetermined amount of time is referred to as speed.

Vi is the starting speed.

Vf is final speed

A=acceleration and Y=displacement

When the bag is freed, its Vi equals that of a balloon traveling at 13 m/s upward.

At the moment of release, choose up as positive y=0.

Vf=0 when it is maximum. Using the equation 2Vf=2Vi+2ay,

0=(13m/s)2+2(9.81m/s2)y, and y=8.6m

300 + 8.6 = 308.6 m is the highest point.

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using F=MA, if you weighed 375N what would your mass be *have to show work*

Answers

Answer:

38.22 kg

Explanation:

To use the formula F=ma to find the mass of an object, we need to know the force acting on it and its acceleration. In this case, the force acting on the object is its weight, which we can find using the equation:

weight = mass x acceleration due to gravity

The acceleration due to gravity on Earth is approximately 9.81 m/s^2. Therefore, we can write:

weight = mass x 9.81 m/s^2

We are given that the weight of the object is 375 N. Substituting this value into the equation, we get:

375 N = mass x 9.81 m/s^2

To solve for mass, we need to isolate it on one side of the equation. We can do this by dividing both sides by 9.81 m/s^2:

mass = 375 N / 9.81 m/s^2

Using a calculator, we can evaluate this expression to get:

mass = 38.22 kg

Therefore, if an object weighs 375 N, its mass is approximately 38.22 kg on Earth.

URGENT HELP NEEDED!!! BRAINLIEST WILL BE PICKED!!!
A 0.35 g BB is fired into a stationary 6.0 g ball of clay. If the BB is fired with a speed of 46 m/s, and becomes embedded in the clay ball, how fast does the clay ball move after the collision?

3.9 m/s

2.7 m/s

23 m/s

2.5 m/s

Answers

According to the question the clay ball moves with a velocity of 2.5 m/s after the collision.

What is velocity?

Velocity is the speed of an object in a specific direction. It is a vector quantity and is typically represented by the symbol v. It is the rate of change of an object's position and is expressed in units of distance divided by time, such as meters per second (m/s). Velocity can be constant, meaning the object is traveling at a steady speed, or it can be changing, meaning the object is accelerating or decelerating.

The answer is 2.5 m/s. This is because the total momentum of the system (BB + clay ball) before the collision is 0 (since the clay ball is stationary). Therefore, the total momentum of the system after the collision is 0 as well. Using the equation for momentum (p = mv), we can calculate the velocity of the clay ball after the collision.

p (total) = 0 = (0.35 g) (46 m/s) + (6.0 g) (v)

v = -2.5 m/s

Therefore, the clay ball moves with a velocity of 2.5 m/s after the collision.

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If the cheetah is running at 22 m/s, how long would it take him to run 400 meters?.

Answers

Answer:

V = distance / time = S / t

t = S / V = 400 m / 22 m/s = 18.2 sec

One person solved 40 math problems in her head. Another
person picked up a kitten. Which person did more work,
in the scientific sense?

Answers

The person who picked up the kitten did more work.

What is work done ?

Work done is defined as the dot product of force and displacement.

Here,

One person solved 40 math problems in her head. Here no physical force is applied and so no displacement has happened. Hence the work done here is zero.

Another person picked up a kitten. Here the force applied is mg and displacement of the cat is the height to which it is picked up. So, the work done, W = mgh.

Hence,

The person who picked up the kitten did more work.

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7. The sound produced by wind chimes results from resonating waves in a open-end air column.
On a cold frigid day, the speed of sound through the wind chimes is 336 m/sec. The length of
the air column is 30.0 cm. Calculate the frequency of the first, second, and third harmonics.

Answers

The frequency of the first, second, and third harmonics of the wind chimes are 560 Hz, 1120 Hz, and 1680 Hz, respectively.

What is frequency?

In physics, frequency refers to the number of waves that pass through a fixed point in one unit of time. It also describes the number of cycles or vibrations experienced by a body in periodic motion in one unit of time.

The frequency of a resonating air column can be calculated using the formula:

f = nv/2L

Where f is the frequency, n is the harmonic number, v is the speed of sound, and L is the length of the air column.

For the first harmonic, n = 1:

f1 = (1)(336 m/s)/(2(0.30 m)) = 560 Hz

For the second harmonic, n = 2:

f2 = (2)(336 m/s)/(2(0.30 m)) = 1120 Hz

For the third harmonic, n = 3:

f3 = (3)(336 m/s)/(2(0.30 m)) = 1680 Hz

Thus, the first, second, and third harmonics of the wind chimes have frequencies of 560 Hz, 1120 Hz, and 1680 Hz, respectively.

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URGENT!!! BRAINLIEST WILL BE PICKED IF POSSIBLE!!!
Rory is on a seesaw. He is at the highest point, and his partner is at the lowest point. The angle of the seesaw is 29.7° above horizontal, Rory is 2.11 m from the fulcrum, and he has a mass of 35.4 kg. What is the torque that Rory is exerting on the seesaw?

636 Nm

363 Nm

64.9 Nm

37.0 Nm

Answers

According to the question the torque that Rory is exerting on the seesaw is  636 Nm.

What is torque?

Torque is a type of rotational force or moment that can be applied to an object. It is typically measured in units of Newton meters (Nm). Torque is the rotational equivalent of linear force, and it is calculated by multiplying the force applied by the distance from the pivot point. When a torque is applied to an object, it causes the object to rotate about a pivot point. Torque can be used to perform work such as turning a bolt or lifting an object.

The torque (τ) exerted by Rory on the seesaw is equal to the mass of Rory (m) multiplied by the distance from the fulcrum (d) times the sine of the angle of the seesaw (θ):

τ = m x d x sin θ

Therefore, in this case, the torque that Rory is exerting on the seesaw is:

τ = 35.4 kg x 2.11 m x sin(29.7°) = 636 Nm

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The large block shown is =4.0×101 cm
wide, =3.0×101 cm
long, and =5.0 cm
high. This block is passing through air (density of air =1.43 kg/m3)
at a speed of =8.64 m/s
.
A rectangular block with three, different velocity vectors. The box is x wide by z high by y deep. Velocity vector v subscript 1 points perpendicularly outward from the face defined by the x and z dimensions. Velocity vector v subscript 2 points perpendicularly outward from the face defined by the y and z dimensions. Velocity vector v subscript 3 points perpendicularly outward from the face defined by the x and y dimensions.
Find the drag force d,1 acting on the block when it has the velocity ⃗ 1 and a drag coefficient Γ=0.872
Find the drag force d,2 acting on the block when it has the velocity ⃗ 2 with a drag coefficient Γ=0.959

Find the drag force d,3 acting on the block when it has the velocity ⃗ 3 with a drag coefficient Γ=1.13
.

Answers

Therefore, the drag forces for each velocity vector are: Fd,1 = 20.86 * x * z Newtons, Fd,2 = 23.18 * y * z Newtons and Fd,3 = 28.38 * x * y Newtons.

How to calculate drag forces and velocity vector?

To solve this problem, we need to use the drag force equation:

Fd = 1/2 * Γ * ρ * A * v^2

where Fd is the drag force, Γ is the drag coefficient, ρ is the density of the fluid (in this case, air), A is the area of the object perpendicular to the flow of the fluid, and v is the velocity of the object relative to the fluid.

For each velocity vector, we need to calculate the area perpendicular to the flow of the fluid and then use the drag force equation to find the drag force.

Velocity vector v1:

The area perpendicular to the flow of the fluid is the area of the face defined by the x and z dimensions, which is x * z. Therefore, A = x * z.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,1 = 1/2 * 0.872 * 1.43 kg/m^3 * (x * z) * (8.64 m/s)^2

= 20.86 * x * z Newtons

Velocity vector v2:

The area perpendicular to the flow of the fluid is the area of the face defined by the y and z dimensions, which is y * z. Therefore, A = y * z.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,2 = 1/2 * 0.959 * 1.43 kg/m^3 * (y * z) * (8.64 m/s)^2

= 23.18 * y * z Newtons

Velocity vector v3:

The area perpendicular to the flow of the fluid is the area of the face defined by the x and y dimensions, which is x * y. Therefore, A = x * y.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,3 = 1/2 * 1.13 * 1.43 kg/m^3 * (x * y) * (8.64 m/s)^2

= 28.38 * x * y Newtons

Therefore, the drag forces for each velocity vector are:

Fd,1 = 20.86 * x * z Newtons

Fd,2 = 23.18 * y * z Newtons

Fd,3 = 28.38 * x * y Newtons

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You purchase a bag of potato chips at the grocery store. You forget you have them and leave the unopened bag on the floor of your car. The next day you go out to your car in the sweltering heat, 105 degrees. The bag of potato chips is inflated like a balloon and looks like it could pop! Why? How does this relate to Charles’ Law?

Answers

The bag of potato chips inflates due to the increase in temperature inside the car. As the temperature rises, the air molecules inside the bag gain energy and begin to move around faster, increasing the pressure inside the bag. Since the bag is airtight, the pressure cannot escape, causing the bag to expand.

What is Charles’ Law?

Charles' Law is a gas law that describes the relationship between the volume and temperature of a gas, assuming that the pressure and amount of gas remain constant. It states that the volume of a fixed amount of gas at a constant pressure is directly proportional to its absolute temperature.

The potato chip bag expands as a result of the car's increased temperature. The air molecules inside the bag gather energy as the temperature rises and start to travel more quickly, which raises the pressure inside the bag. The bag expands because the pressure within cannot leave because it is airtight.

Charles' Law, which states that the volume of a gas is precisely proportional to its absolute temperature for a set amount of gas at a constant pressure, can be used to explain this phenomena. If the pressure is constant, the volume of the gas increases along with the temperature.

Since the air inside a bag of potato chips behaves like a gas, when the temperature rises, the volume of air inside the bag also expands, increasing the pressure inside the bag and causing it to inflate.

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URGENT HELP NEEDED!!!

If a force of 50.0 N acts on a 3.0 kg object for 2.0 seconds, what will its change in momentum be? what will its change in velocity be?


100 kg*m/s


300 kg*m/s


75 kg*m/s


150 kg*m/s

PART B
33 m/s

150 m/s

75 m/s

70 m/s

Answers

Answer:

The change in momentum will be 100 kg*m/s, and the change in velocity will be 33 m/s.

Explanation:

A 2000-kg car and a 7500-kg truck are traveling side by side at the same speed on a level road when the light ahead turns red. The drivers slam on their brakes, causing both vehicles to skid to a stop. The car and truck have the same coefficients of static and kinetic friction between their tires and the road surface, which one travels a greater distance before stopping?

Answers

Answer:

The distance each vehicle travels before coming to a stop depends on its initial speed, mass, and the coefficient of friction between its tires and the road surface. However, since the car and truck have the same coefficients of static and kinetic friction between their tires and the road surface, their stopping distances will be directly proportional to their masses.

To calculate the stopping distances, we can use the following formula for the distance traveled during a constant deceleration:

d = v^2 / 2a

where d is the stopping distance, v is the initial velocity, and a is the deceleration. The deceleration is related to the coefficient of friction and the gravitational acceleration as follows:

a = μg

where μ is the coefficient of friction and g is the gravitational acceleration (9.81 m/s^2).

For the car, the initial velocity is not given, so let's assume it was traveling at 30 m/s (108 km/h) before the brakes were applied. Then, the deceleration is:

a = μg = μ × 9.81 m/s^2

For the car, the mass is 2000 kg, so the stopping distance is:

d_car = v^2 / 2a = 900 / (2 × μ × 9.81) = 45.84 / μ

For the truck, we can use the same formula, but with the mass of 7500 kg:

d_truck = v^2 / 2a = 900 / (2 × μ × 9.81 × 7500/2000) = 153.12 / μ

Therefore, the truck travels a greater distance before stopping than the car, by a factor of 153.12 / 45.84 = 3.34, assuming they were traveling at the same initial speed.

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