Hi there!
For an object on an incline with friction being pulled, the following forces are present.
Force due to Gravity Force due to FrictionForce due to tensionThe force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.
Let up the incline be positive, and down the incline be negative.
Doing a summation of forces:
[tex]\Sigma F = F_T + F_f - F_g[/tex]
For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:
[tex]0 = F_T + F_f - F_g[/tex]
Now, we can express each force as an equation.
Force due to tension:
Must be solved for.Force due to gravity:
On an incline, this is equivalent to the SINE component of its weight. (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)This is expressed as:
[tex]F_g = Mgsin\theta[/tex]
Force due to friction:
Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:[tex]N = Mgcos\theta[/tex]
[tex]F_f = \mu Mgcos\theta[/tex]
Now, plug these expressions into the above equation.
[tex]0 = F_T + \mu Mgcos\theta - Mgsin\theta\\\\Mgsin\theta - \mu Mgcos\theta = F_T[/tex]
Mg = 245 N (weight). Plug in all values:
[tex]245sin(20) - 0.270(245)cos(20) = F_T\\\\F_T = \boxed{21.634 N}[/tex]
The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:
[tex]N = Mgcos\theta\\\\N = 245cos(20) = \boxed{230.225 N}[/tex]
To find the tension in the rope needed to make the crate move at a constant velocity, we need to consider the forces acting on the crate.
1. Tension in the rope (T): This force is applied upwards at an angle of 20 degrees above the horizontal.
2. Weight of the crate (W): This force acts downward vertically and is equal to 245 N.
3. Normal force (N): This force is exerted by the floor on the crate and acts perpendicular to the surface of the floor.
4. Kinetic friction force (f_k): This force opposes the motion of the crate and acts parallel to the surface of the floor. The magnitude of kinetic friction is given by: f_k = μ_k * N, where μ_k is the coefficient of kinetic friction (0.270 in this case).
Since the crate is moving at a constant velocity, the net force on the crate must be zero. In other words, the forces pulling the crate forward (T and the horizontal component of the weight) must balance the forces opposing its motion (kinetic friction). The vertical forces (the vertical component of the weight and the normal force) must also balance.
Let's proceed with the calculations:
Horizontal Forces:
T * cos(20°) - f_k = 0
T * sin(20°) + N - W = 0
We can now solve for T and N:
From the horizontal forces equation:
T * cos(20°) = f_k
vertical force:
T = f_k / cos(20°)
T = (0.270 * N) / cos(20°)
From the vertical forces equation:
T * sin(20°) + N = W
T * sin(20°) + N = 245 N
Now, substitute the expression for T from the horizontal forces equation:
(0.270 * N) / cos(20°) * sin(20°) + N = 245 N
Now, solve for N:
N * (0.270 * tan(20°) + 1) = 245 N
N = 245 N / (0.270 * tan(20°) + 1)
Now, plug in the values and calculate N:
N = 245 N / (0.270 * tan(20°) + 1)
N ≈ 208.75 N
Now, we can calculate the tension in the rope (T):
T = (0.270 * N) / cos(20°)
T ≈ (0.270 * 208.75 N) / cos(20°)
T ≈ 67.24 N
So, the tension in the rope needed to make the crate move at a constant velocity is approximately 67.24 N, and the normal force exerted by the floor on the crate is approximately 208.75 N.
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name some factors that would increase braking distance with word not calculation
a rescue diver of mass 89 kg jumps from a hovering helicopter into the ocean below, what is the diver's speed (in m/s) when he hits the water
Answer:
Need the HEIGHT of the helicopter to complete this answer
Explanation:
PE (=mgh) is converted to KE ( = 1/2 mv^2 )
mgh = 1/2 m v^2
gh = 1/2 v^2
v^2 = 2 gh
v = sqrt (2gh) = sqrt ( 2 * 9.8 * h)
Question 8
What is the mass of an object if it takes a net force of 2,400 Newtons
to accelerate it at a rate of 60 m/s2?
Answer:
It has a mass of 40 kg.
Explanation:
Because Force = mass x Acceleration or F = m a, we could say that the mass is force/acceleration which in your case is 2,400/60 which equals 40 kg.
what is the type of energy possessed by moving water?
Answer:
hydro energy.
Explanation:
The energy possessed by fast-moving water is called hydro energy
When in a crowd, individuals may lose awareness of their own sense of individuality, and as a result may avoid taking responsibility or action.
True or false ?
What scientific process would you be using as you identified the characteristics of the buttery
and leaves?
Answer:
The butterfly and moth develop through a process called metamorphosis.
Explanation:
hoped i helped
FM radio means what?
Question 3 options:
Frequency measured in megahertz
Frequency measured in kilohertz
Frequency measured in hertz
Frequency measured in gigahertz
Answer:
frequency measured in megahertz
Styrofoam holds onto its electrons because is has a high _____ for them.
a
polarization
b
affinity
c
insulator
d
conductor
Answer:
Polarization
Explanation:
Obviously, B wouldn't be it as objects don't have feelings. C, and D wouldn't be it also because the grammar of it doesn't fit.
What is the term for trade without barriers, tariffs, or quotas?
A. Free trade
B. Trade deficit
C. Surplus trade
D. Trade bloc
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A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration?
Explanation:
Initial velocity ( u ) = 10 m/s
Final velocity ( v ) = 40 m/s
Time taken ( t ) = 15 second
Now
[tex]acceleration = \frac{v - u}{t} \\ = \frac{40 - 10}{15} \\ = 2m /{s}^{2} [/tex]
What is the wave where the oscillation is perpendicular to the direction
of motion.
A 15-kg object accelerates at 3 m/s2. What is the net force acting on the object?
Answer:
Fnet = 45N
Explanation:
Fnet = m.a
= (15)(3)
= 45N
Which parts of an X-ray image appear white because few X-rays reach the
detector?
A. Those that show where tissues transmitted the most X-rays
B. Those that show where tissues refracted the most X-rays
O C. Those that show where tissues reflected the most X-rays
D. Those that show where tissues absorbed the most X-rays
Answer:
D
Explanation:
Those that show where tissues absorbed the most X-rays.
The way roughness of surfaces affects kinetic friction is called the __________ of kinetic friction?
Answer:
coefficient
Explanation:
five physical properties of metals
What is the surface area of the right cone below?
OA. 63 units²
15
OB. 99 units²
O C. 126 units²
13
OD. 54 units²
Answer:
option d is the answer of given statement
The surface area of the right cone is 54π units². Hence option D correct.
What is Surface Area ?The surface area of a solid object is a total area measured that the surface of the object occupies. the surface area of the cube is 6 times side², cause it has 6 faces.
The surface area is total area occupied by the surface of the object.
A cone is geometrical shape which is having circular base and cone shaped body. when a line is drawn from tip to the center of the base it will make right angle between radius and height of the cone. We can apply Pythagoras theorem to get values of radius, height and hypotenuse.
The total area of the cone is nothing but area of the base plus curved area of the body.
Hence area of the cone is,
A = πr²+πr[tex]\sqrt[]{r^{2}+h^{2} }[/tex]
Given,
r = 3
hypotenuse = [tex]\sqrt[]{r^{2}+h^{2} }[/tex] = 15
A = ?
A = π3²+π3*15
A = π (9+45)
A = 54π units²
Hence area of the cone is 54π units².
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two thin lenses of focal length 10cm and 20cm are placed in contract calculate the effective power of the combination
Answer:
20/3
Explanation:
We can use the formula : 1/R1 + 1/R2 = 1/f here
Therefore 1/10 + 1/20 = 3/20
And as it is 1/f its reciprocal will be 20/3
what are two ways an object can gain more gravitational potential energy?
When an item is raised, the work is done in opposition to gravity. When an item is worked on, energy is transmitted to it, and it develops gravitational potential energy. If the same thing falls from that height, gravity must do the same amount of effort to bring it back to the Earth's surface.
Weather hazards and natural disasters such as tsunamis, earthquakes, and flooding are considered which type of migration factor?
A. Pull factor
B. Both push and pull factors
C. Neither push or pull factor
D. Push factor
Answer:
D. Push Factor
Explanation:
Pull factors are known as positive aspects of a place that make people want to stay/remain in that area.Push factors are known as negative aspects of a place that make people want to leave/depart from that area.Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.
(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)
7. The speed of a wave is 65 m/s. If the wavelength is 0.8 meters, what is the frequency of the wave?
Explanation:
velocity = wavelength × frequency
65 = 0.8 × frequency
frequency = 65/0.8=81.25Hz
PLS HELP!!
The speed of light is 300,000,000 m/s. What is the frequency of microwaves with a wavelength of 0.01 meter?
Answer:
c = 3.00E8 m/s speed of light
c = f * λ frequency ^ wavelength
f = c / λ = 3.00E8 m/s / .01 m = 3.00E10 / sec
f = 30,000,000,000 /sec
Suppose a spacecraft of mass 17000 kg is accelerated to 0.14c. How much kinetic energy would it have? If you used the classical formula for kinetic energy, by what percentage would you be in error?
Answer:
1.32% error
Explanation:
You can derive the relativistic kinetic energy by integrating the velocity function over a differential change in momentum. Then use integration by parts to get the answer of:
[tex]KE=mc^2[gamma-1][/tex]
Gamma is the lorentz factor equal to:
[tex]gamma=\frac{1}{\sqrt{1-(v/c)^2}}[/tex]
Therefore the relativistic kinetic energy would be:
[tex]KE=mc^2[\frac{1}{\sqrt{1-(v/c)^2}}-1][/tex]
Plug everything in to get:
[tex]KE=(17000)(3x10^8)^2[\frac{1}{\sqrt{1-(0.14c/c)^2}}-1][/tex]
[tex]KE=(17000)(9x10^{16})[\frac{1}{\sqrt{1-0.0196}}-1][/tex]
[tex]KE=1.53x10^{21}[\frac{1}{\sqrt{1-0.0196}}-1][/tex]
[tex]KE=1.52x10^{19}J[/tex]
The classical non-relativistic formula for kinetic energy is:
[tex]KE=\frac{1}{2} mv^2[/tex]
Therefore the classical kinetic energy is:
[tex]KE=1.50x10^{19}J[/tex]
Use the error percentage formula, found online if you dont recall:
[tex]error=\frac{|KE_c-KE_r|}{KE_r} \frac{100}{1} =1.32[/tex]
Calculate the useful output energy of an electric motor which is 70% efficient if it uses 600 J of electrical energy.
Answer:
420J
Explanation:
The formula (useful output ÷ total output) × 100 is used. We need to find the the useful output. So:
(useful ÷ 600) × 100 = 70(%)
We rearrange the formula so that 'useful' is the subject of the equation.
useful ÷ 600 = 0.7 {70 ÷ 100}
useful = 0.7 × 600
useful = 420J
The frequency of a wave does not change as it passes from one medium to another.
What will most likely happen if a light wave moves from the air into a solid?
The wavelength of the light wave will increase.
The speed of the light wave will decrease.
The wavelength of the light wave will remain the same.
The speed of the light wave will remain the same.
Answer:
The Speed Of The Lightwave Will Be Modified As It Enters Another Medium (State Of Matter)
Explanation:
As The Lightwave Enters The Medium The Light Will Bend Toward The Normal E.g. Incident Ray Which Indicates It Will Modify It's Speed But When it Leaves The Medium It Will Increase Until As It Leaves The Sold
Answer:
B
Explanation:
its B on Edge
29. All living organisms contain carbon. As organisms grow, they require
large quantities of carbon to carry out life processes and make new cells.
Where is the source of most of Earth's available carbon?
A. New carbon atoms are constantly being created by the process of
photosynthesis.
B. Carbon atoms are constantly transferred from the Sun to Earth along
with sunlight
C. Carbon is constantly transported from the mantle to the crust by volcanic
eruptions.
D. Carbon is constantly recycled from dead organisms back into the
environment.
Answer:
The answer will be D/ Carbon is constantly recycled from dead organisms back into the
environment.
The source of most of Earth's available carbon is: carbon is constantly recycled from dead organisms back into the environment. Hence, option (D) is correct.
What is carbon cycle?The carbon cycle is the exchange of carbon compounds between the earth's biosphere, geosphere, pedosphere, hydrosphere, and atmosphere.
The following are the major steps in the carbon cycle process:
Plants absorb carbon from the atmosphere in order to perform photosynthesis.Animals consume these plants, and carbon is bioaccumulated in their bodies.When these animals and plants die, carbon is released back into the atmosphere as they decompose.Some of the carbon that is not re-emitted into the atmosphere is converted into fossil fuels.These fossil fuels are then used for man-made activities that release additional carbon into the atmosphere.Learn more about carbon cycle here:
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If a electrician measures the current of a circuit to be 100 Amps and the circuit is only designed to have a current of 80 Amps, which of the following is the best explanation of what has happened to the circuit ?
A. a There are too many batteries in the circuit.
B. There are too many resistors in the circuit.
C. A battery in the circuit is missing.
D. A resistor in the circuit is missing.
There are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.
Current in the circuitThe current in the circuit is determined by applying Ohms law as shown below;
V = IR
where;
I is the currentV is the voltageR is the resistanceI = V/R
At a constant resistance of the circuit, the current in a circuit will increase when the emf of the circuit increases.
Thus, we can conclude that, there are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.
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The current in the wires of a circuit is 120.0 milliAmps. If the
resistance of the circuit were halved (i.e., reduced to one-
half the original value) (with no change in voltage), then its
new current would be
milliAmps.
If the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.
Current in the circuit
The current in the circuit is inversely proportional to the resistance of the circuit. This implies that the increase in the resistance of the circuit decreases the current in the circuit.
V = IR
At constant voltage;
I₁R₁ = I₂R₂
when, R₂ = 0.5R₁
I₂ = I₁R₁ /R₂
I₂ = I₁R₁ /0.5R₁
I₂ = 2I₁
I₂ = 2 x 120 mA
I₂ = 240 mA
Thus, if the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.
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The fundamental frequency of a musical note is 330Hz. Which harmonic is this?
Answer:
it is a type of even harmonic
Part 1
An engine absorbs 1969 J from a hot reservoir and expels 1223 J to a cold reservoir in each cycle. What is the engine’s efficiency? Answer with an efficiency in decimal form.
Part 2
How much work is done in each cycle?
Answer in units of J.
Part 3
What is the mechanical power output of the engine if each cycle lasts for 0.345 s?
Answer in units of kW
Answer:
Part 1: 0.3789
Part 2: 746 J
Part 3: 2.162 kW
Explanation:
Part 1:
Eff= [tex]1-\frac{1223}{1969}[/tex]
Eff= 0.378873 ≈ 0/3789
Part 2:
W= 0.3789(1969)
W= 746 J
Part 3:
[tex]Power=\frac{W}{t}[/tex]
[tex]Power= \frac{746}{0.345}[/tex]
Power= 2162.3188 Watts
2162.3188 W-----> 2.162 kW