Answer:
3
Step-by-step explanation:
This is a classic puzzle! If you pick out three socks, and they have only 2 colors, you'll get at least one match because they can't be 3 different colors.
please solve
if the breadth of rectangle in three fourth of it's length and perimeter is 140cm,find the length and breadth of rectangle
Let lebgth be x
Breadth=3x/4[tex]\\ \rm\Rrightarrow Perimeter=2(L+B)[/tex]
[tex]\\ \rm\Rrightarrow 2(x+\dfrac{3x}{4})=140[/tex]
[tex]\\ \rm\Rrightarrow 2\left(\dfrac{4x+3x}{4}\right)=140[/tex]
[tex]\\ \rm\Rrightarrow 2\left(\dfrac{7x}{4}\right)=140[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{14x}{4}=140[/tex]
[tex]\\ \rm\Rrightarrow 14x=140(4)[/tex]
[tex]\\ \rm\Rrightarrow 14x=560[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{560}{14}[/tex]
[tex]\\ \rm\Rrightarrow x=40[/tex]
Length=40cmBreadth=3(40)/4=120/4=30[162×(-92)-(-162)×(-5)-162×3
Answer:
-16200
Step-by-step explanation:
162×(-92)+(162)×(-810)×3
Step-by-step explanation:
[tex](162 \times ( - 92) + 162 \times ( - 5 \times - 162) \times 3 = (-14904 + 162 )\times( 810 \times 3) = (-14904+ 162) \times (2430) = - 14742\times 2430 = 378,756
Can someone help me with this question?
Answer:
1. Y
2. YX , YZ
3. X
4. XZ
Pls I am really struggling here
How do you know the end behavior of a polynomial function if the first number is a variable? Do you just move on to the next term that is a number
Answer:
You need to bring the function to the standard form.
The term with highest degree exponent is the leading term and its coefficient is the leading coefficient.
Let it be axⁿ.
Depending on the n and a, the end behavior of the function will change.
Case 1a > 0, n - is oddThis is an odd function and:
x → -∞ ⇒ f(x) → -∞x → ∞ ⇒ f(x) → ∞Case 2a < 0, n - is oddThis is an odd function and:
x → -∞ ⇒ f(x) → ∞x → ∞ ⇒ f(x) → -∞Case 3a > 0, n - is evenThis is an even function and:
x → -∞ ⇒ f(x) ⇒ ∞x → ∞ ⇒ f(x) ⇒ ∞Case 4a < 0, n - is evenThis is an even function and:
x → - ∞ ⇒ f(x) ⇒ - ∞x → ∞ ⇒ f(x) ⇒ - ∞Answer:
Yeah your right
Step-by-step explanation:
Evaluate sin 300° without using a calculator.
Answer:
[tex]-\sqrt{3} /2[/tex]
Step-by-step explanation:
300 degrees is in the fourth quadrant (it's between 270 and 360); sine is negative in the fourth quadrant.
Given we're in the fourth quadrant, the reference angle is 360 - 300 = 60 degrees
sin(60°) = [tex]\sqrt{3} /2[/tex]
And since sine is negative, this value turns negative:
sin(300°) = [tex]-\sqrt{3} /2[/tex]
can u tell ans of this 2pls
Answer:
hope it helps you........
write down the next three terms of these number patterns 5;11;17;23
Answer:
29, 35, 41
Step-by-step explanation:
sequence is in the difference of 6
solve the question please
9514 1404 393
Answer:
arcsin(2/3) ≈ 41.81°, 138.19°Step-by-step explanation:
Rewrite as a quadratic in sin(θ) and solve that in the usual way.
3cos(2θ) +sin(θ) = 1
3(1 -2sin²(θ)) +sin(θ) = 1 . . . . use an identity for cos(2θ)
6sin²(θ) -sin(θ) -2 = 0 . . . . . rearrange to standard form
(3sin(θ) -2)(2sin(θ) +1) = 0 . . . . factor
The values of sin(θ) that make this true are ...
sin(θ) = 2/3, sin(θ) = -1/2
In the range 0 < θ < 180°, we're only interested in ...
sin(θ) = 2/3
θ = arcsin(2/3) or 180° -arcsin(2/3)
θ ≈ {41.81°, 138.19°}
Can anyone help me out with this? (recursive formulas)
Step-by-step explanation:
[tex]b(1) = 4[/tex]
Since this is an arithmetic sequence, notice that if you subtract b(1) (i.e., 4) from b(2)(i.e., 22), you get 18. Likewise, if you subtract b(2) from b(3) you also get 18. Therefore,
[tex]b(n) = b(n-1) + 18[/tex]
I need help with this question!!!! Given directed line segment QS, find the coordinates of R such that the ratio of QR to RS is 3:5. Plot point R.
Answer:
R(2, -2)Step-by-step explanation:
Coordinates of Q and S are:
Q(8, -5), S(-8, 3)We need to find the coordinates of R such that:
QR : RS = 3 : 5Let R has coordinates (x, y):
x = 8 + 3/8(-8 - 8) = 8 - 6 = 2y = -5 + 3/8(3 + 5) = -5 + 3 = -2The point is R(2, -2)
Answer:
2,-2
Step-by-step explanation:
A copy machine makes 168 copies in 5 minutes and 15 seconds.how many copies does it make per minute
Which of the expressions below have a value of 12? Select all that apply.
A) -4 X-3
B) 6 x 2
C) -6 X-2
D) 3 X-4
E) 12 x 1
Answer:
A, B, C, and E
Step-by-step explanation:
A) -4 X-3 = 12
B) 6 x 2 = 12
C) -6 X-2 = 12
D) 3 X-4 = -12
E) 12 x 1 = 12
the expressions that have a value of 12 are :
A, B, C, and E
Answer:
Lets find
[tex]\\ \rm\longmapsto -4(-3)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto 6(2)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto -6(-2)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto 3(-4)=-12\checkmark[/tex]
[tex]\\ \rm\longmapsto 12(1)=12\checkmark[/tex]
1, In a class of 80 students in Debreberhan University, 45 are good in mathematics, 15 are good in both mathematics and in English, 13 are good in both mathematics and psychology, 16 are good in both English and psychology only, 20 are good in psychology and 9 are good in both of the three courses.
a) How many students are good in mathematics only? b) How many students are not good in any of the three course?
Treating the data as a Venn set, it is found that:
26 students are good in mathematics only.28 students are not good in any of the three courses.---------------------------------
I am going to say that:
A is the number of students good in Math.B is the number of students good in English.C is the number of students good in Psychology.---------------------------------
9 are good in all of the three courses.
This means that: [tex]A \cap B \cap C = 9[/tex]
---------------------------------
13 are good in both mathematics and psychology
This means that:
[tex](A \cap C) + (A \cap B \cap C) = 13[/tex]
[tex](A \cap C) + 9 = 13[/tex]
[tex](A \cap C) = 4[/tex]
---------------------------------
15 are good in both mathematics and in English
This means that:
[tex](A \cap B) + (A \cap B \cap C) = 15[/tex]
[tex](A \cap B) + 9 = 15[/tex]
[tex](A \cap B) = 6[/tex]
---------------------------------
16 are good in both English and psychology
This means that:
[tex](B \cap C) + (A \cap B \cap C) = 16[/tex]
[tex](B \cap C) + 9 = 16[/tex]
[tex](B \cap C) = 7[/tex]
---------------------------------
20 are good in psychology
This means that:
[tex]c + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 20[/tex]
[tex]c + 4 + 7 + 9 = 20[/tex]
[tex]c = 0[/tex]
---------------------------------
45 are good in mathematics
This means that:
[tex]a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 45[/tex]
[tex]a + 6 + 4 + 9 = 45[/tex]
[tex]a = 26[/tex]
---------------------------------
Question a:
[tex]a = 26[/tex], which means that 26 students are good in mathematics only.
---------------------------------
Question b:
At least one is:
[tex]a + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 26 + 6 + 4 + 7 + 9 = 52[/tex]
Thus, 80 - 52 = 28
28 students are not good in any of the three courses.
A similar problem is given at: https://brainly.com/question/22003843
PLZ HELP WITH BOTHHHHH
Answer:
(5,2)
(6,-6)
Step-by-step explanation:
Simplify the expression
A. -5.1
B. - 4.21
C. 3.42
D. 5.1
Answer:
D. [tex] 5.1[/tex]
Step-by-step explanation:
[tex] \frac{ - 44.288 - 31.6}{ - 3.1(6 - 1.2)} [/tex]
➡️ [tex] \frac{ - 75.888}{ - 3.1 \times 4.8} [/tex]
➡️ [tex] \frac{24.48}{4.8} [/tex]
➡️ [tex] = 5.1[/tex]
Here’s the whole thing only posted half
Answer:
48 49 51 53 58
Step-by-step explanation:
48×2= 96 so 49 51 53 and 58 are greater hope this helps:)
mathematics geniuses where are you ? help me answer this question please.
Step-by-step explanation:
There is 7 blocks that measure is 12.0-12.2
11 blocks that measure 12.2 to 12.4
18 blocks that measure 12.4 to 12.6
10 blocks that measure 12.6-12.8
4 blocks that measure 12.8 to 13.0
We can't find a mean by with Intervals so let find the midpoint of each interval,
12.1, 12.3, 12.5, 12.7, 12.9.
12.1 occurs 7 times so that equal 12.1 x 7=84.712.3 occurs 11 times so that equal 12.3 x 11=135.312.5 occurs 18 times so that equal 12.5x18=22512.7 occurs 10 times so that equal 12.7x10=12712.9 occurs 4 times 12.9×4=51.6Add up the products and divide them by 50
[tex]\frac{623.6}{50} = 12.472[/tex]
Standard Deviation is
0.23( it is alot of steps so I use a calculator to save time).
The interqualtie range is 0.4
If a 12 sided regular polygon rotates about its center at which angle of rotation will the image of the polygon coinside with the prelim age
Answer: 30 degrees
This is the minimum amount of rotation.
Why this value? Well because 360/12 = 30
Consider a triangle with 3 sides. Specifically I mean an equilateral triangle. We can rotate it 120 degrees to have it line up with itself. Now notice that 360/3 = 120.
For a square, we can rotate it 90 degrees and we can say 360/4 = 90
So the general rule is that the minimum angle of rotation is 360/n, where n is the number of sides. This rule only works for regular polygons. Regular polygons have the same side length and the same angle measure (the side and angle measure won't necessarily be equal).
So going back to this 12 sided dodecagon, we have n = 12 and 360/n = 360/12 = 30 as the minimum angle of rotation. Each 30 degree rotation will have the polygon match up perfectly with its old image. The preimage and image will be identical.
Do the mathematics please. I will give a reward.
9514 1404 393
Answer:
p = -3/4b -3/4
Step-by-step explanation:
Vectors are perpendicular when their dot product is zero.
A·B = p(4) +b(3) -3(-1) = 4p +3b +3
We want this to be zero, so ...
4p +3b +3 = 0
4p = -3b -3
p = -3/4b -3/4 . . . . the value of p that makes A⊥B
A triangle has side lengths of (8s + 8) centimeters, (s +9) centimeters, and
(8t - 1) centimeters. Which expression represents the perimeter, in centimeters, of
the triangle?
Answer:
Step-by-step explanation:
(16.2t+3.4u+2.9)cm
Step-by-step explanation:
A triangle is a plane shape that has three sides. The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;
P = s1+s2+s3
Given the side lengths
s1 = (8.1t-6.1)cm
s2 = (8.1t+7.1)cm
s3 = (3.4u+1.9)cm
Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9
collect the like terms
P = 8.1t+8.1t+3.4u-6.1+7.1+1.9
P = 16.2t+3.4u+2.9
Hence the expression that represents the perimeter, in centimeters, of the triangle is (16.2t+3.4u+2.9)cm
(6x-5y+4)dy+(y-2x-1)dx=0
(6x - 5y + 4) dy + (y - 2x - 1) dx = 0
(6x - 5y + 4) dy = (2x - y + 1) dx
dy/dx = (2x - y + 1) / (6x - 5y + 4)
Let X = x - a and Y = y - b. We want to find constants a and b such that
dY/dX = (a rational function)
where the numerator and denominator on the right side are free of constant terms. Substituting x and y in the equation, we have
dY/dX = (2 (X + a) - (Y + b) + 1) / (6 (X + a) - 5 (Y + b) + 4)
dY/dX = (2X - Y + 2a - b + 1) / (6X - 5Y + 6a - 5b + 4)
Then we solve for a and b in the system,
2a - b + 1 = 0
6a - 5b + 4 = 0
==> a = -1/4 and b = 1/2
With these constants, the equation reduces to
dY/dX = (2X - Y) / (6X - 5Y)
Now substitute Y = VX and dY/dX = X dV/dX + V :
X dV/dX + V = (2X - VX) / (6X - 5VX)
The equation becomes separable after some simplification:
X dV/dX + V = (2 - V) / (6 - 5V)
X dV/dX = (2 - V) / (6 - 5V) - V
X dV/dX = (2 - V - (6 - 5V)) / (6 - 5V)
X dV/dX = (4V - 4) / (6 - 5V)
- (5V - 6) / (4V - 4) dV = 1/X dX
Integrate both sides:
-5/4 V + 1/4 ln|4V - 4| = ln|X| + C
Extract a constant from the logarithm on the left:
-5/4 V + 1/4 (ln(4) + ln|V - 1|) = ln|X| + C
-5/4 V + 1/4 ln|V - 1| = ln|X| + C
-5V + ln|V - 1| = 4 ln|X| + C
Get this back in terms of Y :
-5Y/X + ln|Y/X - 1| = 4 ln|X| + C
Now get the solution in terms of y and x :
-5 (y - 1/2)/(x + 1/4) + ln|(y - 1/2)/(x + 1/4) - 1| = 4 ln|x + 1/4| + C
With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as
-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|x + 1/4| + 4 ln(4) + C
-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|4x + 1| + C
-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| - ln|4x + 1| = 4 ln|4x + 1| + C
-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| = 5 ln|4x + 1| + C
como escreve por extenso o número 380.210?
Answer: trescientos ochenta mil doscientos diez es,pero te ayude
Helppppp plzzzzzzz!!!!!!!!!!!! 20+ Pts and brainliest!!!!!!
Correct the error in solving the equation.
-2(7-y)+4=-4
-14-2y+4=-4
-10-2y=-4
-2y=6
y=-3
Answer:
Y=3
Step-by-step explanation:
in the first to second step: -2(7-y)+4=-4 to -14-2y+4=-4, the part -2(7-y) should equal -14+2y instead of 14-2y because two negative signs add to be positive
so y should be 3
Answer: What that other guy said
linear equation 3+X=-2
Answer:
x = -5
Step-by-step explanation:
3+X=-2
Subtract 3 from each side
3-3+X=-2-3
x = -5
Answer:
-5
Step-by-step explanation:
1 Subtract 3 from both sides.
x=-2-3
2 Simplify -2 -3 to -5
x=-5
are these two line parallel to each other??
Answer:
No
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x + 1 ← is in slope- intercept form
with slope m = 3
Calculate the slope using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (2,4) and (x₂, y₂ ) = (4, 12) ← 2 ordered pairs from the table
m = [tex]\frac{12-4}{4-2}[/tex] = [tex]\frac{8}{2}[/tex] = 4
Parallel lines have equal slopes
The slope of these 2 lines are not equal , thus not parallel
HELP PLS! ;P
Find n.
A. 5√3
B. 5
C. 10√3/3
D. 10
Answer:
B
Step-by-step explanation:
tan(30)=n/(5*sqrt(3))
=> n=5
4/5th
part of a concrete pillar was inside the water of a river if 2 m of the player was outside the water find the full height of the Pillar
Answer:
height =10
[tex] \frac{4}{5} h + 2 = h \\ h - \frac{4}{5} h = 2 \\ \frac{1}{5} h = 2 \\ h = 2 \times 5 = 10[/tex]
2x-8=6 do addition or subtraction first. then rewrite the new equation and solve.
Answer:
x = 7
Step-by-step explanation:
2x - 8 = 6 (Given)
2x - 8 + 8 = 6 + 8 (Add 8 on both sides)
2x = 14 (Simplify)
2x/2 = 14/2 (Divide 2 on both sides)
x = 7 (Simplify)
the speed of a bus is 40km per hour how much distance it cover in 2 hour 30minutes
plz
Answer:
100 km
Step-by-step explanation:
Speed = distance/time
=> Speed × time = distance
=> Distance = speed × time
=> Distance = (40 km/h) × 2.5 hours
=> Distance = 100 km.h/h
=> Distance = 100 km
f(x)=6x^2-1/x^2
1.f(5)=
2.f(-5)=
3.f(-x)=
Step-by-step explanation:
1. 6(5)^2-1/(5)^2 = 149/25
2. 6(-5)^2-1/25 = -150/25
3. 6x^2-2/x^2
Answer:
[tex]1) \huge\boxed{ \sf f(5) = 5 \frac{24}{25} }[/tex]
[tex]2) \huge\boxed{ \sf f(-5) = 5\frac{24}{25} }[/tex]
[tex]3) \huge\boxed{\sf f(-x) = \frac{6x^2-1}{x^2} }[/tex]
Step-by-step explanation:
[tex]\displaystyle f(x) = \frac{6x^2-1}{x^2}[/tex]
For f(5):
Put x = 5
[tex]\displaystyle f(5) = \frac{6(5)^2-1}{(5)^2} \\\\f(5) = \frac{6(25)-1}{25} \\\\f(5) = \frac{150-1}{25} \\\\f(5) = \frac{149}{25} \\\\f(5) = 5 \frac{24}{25}[/tex]
For f(-5):
Put x = -5
[tex]\displaystyle f(-5) = \frac{6(-5)^2-1}{(-5)^2} \\\\f(-5) = \frac{6(25)-1}{25} \\\\f(-5) = \frac{150-1}{25} \\\\f(-5) = \frac{149}{25} \\\\f(-5) = 5\frac{24}{25}[/tex]
For f(-x):
Put x = -x
[tex]\displaystyle f(-x) =\frac{6(-x)^2-1}{(-x)^2} \\\\f(-x) = \frac{6x^2-1}{x^2} \\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!