The survey approach is one efficient way to count barn owl populations. To estimate the population size, a survey of the neighbourhood is necessary.
What is Visual counts?Visual counts, such as counting the number of owls observed during a nocturnal survey, or audio measures, such as counting their calls, can be used in surveys
.
What us trap and label survey?Another method of conducting surveys is to trap and label individuals, then capture and count them again in subsequent surveys. The distribution and abundance of barn owls in a specific area can be determined using this technique.
To know more about populations visit:-
https://brainly.com/question/27991860?
#SPJ1
Calculate the standard deviation of the concentration for each method. (sd = 2(2-0) n-1 Why would it be okay to run a single determination for each of the known concentration solutions used in preparing the standard curve plot?
Regarding the question of whether it would be okay to run a single determination for each of the known concentration solutions used in preparing the standard curve plot, the answer is no.
Running a single determination for each concentration would not provide enough data points to accurately determine the standard deviation. The standard deviation is a measure of how spread out the data is, and running multiple determinations for each concentration would provide a more accurate representation of the spread of the data.
In general, it is recommended to run at least three replicates for each concentration value to obtain a reliable estimate of the standard deviation.
For more questions like Standard deviation click the link below:
https://brainly.com/question/23907081
#SPJ11
The population of a country dnalgne is 20 million in 1997 and increasing at a rate of 0. 2 million per year. The average annual income of a person in dnalgne during 1997 was 15000 dollars per year and increasing at a rate of 800 dollars per year. How quickly was the total income of the entire population rising in 1997? dollars per year
the total income of the entire population of Dnalgne was increasing at a rate of $319 billion/year in 1997.
20 million times $15,000 equals $300 billion in total income in 1997.
Total population growth rate is 0.2 million per year.
Average annual income growth per person = $800 per year
We can get the rate of change of total revenue using the product rule of differentiation:
Total income = population x average per-person income + rate of population growth x average per-person income + population x (rate of increase in average income per person)
At time t = 1997, the population was 20 million, the average annual income was $15,000, the population was growing at a pace of 0.2 million people per year, and the average annual income was growing at a rate of $800.
Total income is calculated as (20,000,000) x ($15,000) + (0.2,000,000/year) x ($15,000) + (20,000,000) x ($800/year).
= $3 billion, $16 billion, and $300 billion
= $319 billion annually income
To know more about income click here
brainly.com/question/25745683
#SPJ4
How do the properties of water benefit freshwater fish in Ontario during the winter?
The properties of water, including its high heat capacity, expansion when freezing, and cohesive property, all benefit freshwater fish in Ontario during the winter by helping to maintain a stable and safe environment for them to live in.
The properties of water benefit freshwater fish in Ontario during the winter in several ways. First, the high heat capacity of water helps to keep the water temperature stable, even during extreme temperature fluctuations. This allows fish to maintain their body temperature and metabolism without experiencing stress or harm.
Second, the fact that water expands when it freezes is also beneficial for freshwater fish in Ontario during the winter. This expansion creates a layer of ice on the surface of the water, which acts as an insulator and helps to prevent the water from freezing solid. As a result, fish are able to continue living in the water, even when the air temperature drops below freezing.
Lastly, the cohesive property of water, which allows it to stick together, also benefits freshwater fish in Ontario during the winter. This property helps to keep the water from evaporating, which helps to maintain a stable water level and prevent the fish from becoming stranded or exposed to predators.
Learn more about the properties of water: https://brainly.com/question/18681949
#SPJ11
pacemaker potential does not require neural input, but neural input from both division of the autonomic nervous system can...
Pacemaker potential is the ability of certain cells in the heart to generate electrical impulses without the need for neural input. However, the autonomic nervous system can influence the rate and strength of these impulses.
The sympathetic division of the autonomic nervous system can increase the rate and strength of the impulses, leading to an increase in heart rate and contractility. This is achieved through the release of the neurotransmitter norepinephrine, which binds to receptors on the pacemaker cells and increases their activity.
Conversely, the parasympathetic division of the autonomic nervous system can decrease the rate and strength of the impulses, leading to a decrease in heart rate and contractility. This is achieved through the release of the neurotransmitter acetylcholine, which binds to receptors on the pacemaker cells and decreases their activity.
In summary, while pacemaker potential does not require neural input, the autonomic nervous system can influence the rate and strength of the impulses generated by the pacemaker cells.
For more question on Pacemaker click on
https://brainly.com/question/10886983
#SPJ11
if the frequency of stimulus is 10 pulse per/sec,
calculate how lo g the period is?
The period (the time it takes to complete one cycle of a waveform) of a 10-pulse-per-second stimulus is 0.1 seconds.
The period is the inverse of the frequency. In other words, the period is the amount of time it takes for one cycle of a repeating event to occur. The formula for calculating the period is:
Period = 1 / Frequency
In this case, the frequency of the stimulus is 10 pulses per second. To calculate the period, we can simply plug the frequency into the formula:
Period = 1 / 10
Period = 0.1 seconds
Therefore, the period of the stimulus is 0.1 seconds.
Answer: The period of the stimulus is 0.1 seconds
Learn more about formula of period at https://brainly.com/question/27992917
#SPJ11
1. The redox reaction between photosystem 2 and plastoquinone produces energy. In this reaction, which chemical species is more electronegative?
A- Photosystem 2
B- Plastoquinone
2. Is photosystem 2 reduced or oxidized by plastoquinone?
3. For the electron transfer between plastoquinone and cytochrome b6f, is plastoquinone an oxidant or reductant?
4. What is the end-point for electrons in light dependant reactions? This is the product of the final chemical reaction in the electron transport chain of light dependant reactions.
In the redox reaction between photosystem 2 and plastoquinone, plastoquinone is more electronegative, Photosystem 2 is oxidized by plastoquinone, plastoquinone acts as a reductant, and the end-point for electrons in light dependant reactions is NADP+.
1. In the redox reaction between photosystem 2 and plastoquinone, plastoquinone (B) is more electronegative. This is because it accepts electrons from photosystem 2, indicating that it has a greater affinity for electrons.
2. Photosystem 2 is oxidized by plastoquinone, as it loses electrons to plastoquinone in the redox reaction.
3. In the electron transfer between plastoquinone and cytochrome b6f, plastoquinone acts as a reductant. This is because it donates electrons to cytochrome b6f, reducing it.
4. The end-point for electrons in light dependant reactions is NADP+. This is the product of the final chemical reaction in the electron transport chain of light dependant reactions, as it accepts electrons from the final electron carrier and is reduced to NADPH.
Learn more about Redox reaction at https://brainly.com/question/2671074
#SPJ11
What are all of the different types of pathology found in people
infected with: Entamoeba histolytica but not found in Trichomonas
infected human?
The different types of pathology found in people infected with Entamoeba histolytica but not found in Trichomonas infected human are : Colitis, Liver abscess, Peritonitis, Lung abscess, Gingivitis, Brain abscess, Amoeboma, Cutaneous amebiasis, and Genital ulceration.
Entamoeba histolytica is a protozoan parasite that can lead to a life-threatening disease called amoebiasis. It causes intestinal disease in humans and other primates, which is responsible for approximately 55,000 deaths per year.The pathology that develops in people infected with Entamoeba histolytica but not in Trichomonas infected humans is due to the parasite's ability to invade tissues outside of the intestine. In contrast, Trichomonas vaginalis, which infects the urogenital tract, is not associated with these types of pathological conditions.
Learn more about Entamoeba histolytica here: https://brainly.com/question/10815668.
#SPJ11
You are asked to draw animals that fly, including insects, birds, and bats. You read that fossil evidence suggests that bat wings and bird wings arose independently from forelimbs of different tetrapod ancestors. If this is the case, then a bird's wing is ________ a bat's wing.
Select one:
a. homologous to
b. related to
c. descended with modification from
d. analogous to
If fossil evidence suggests that bat wings and bird wings arose independently from forelimbs of different tetrapod ancestors, then a bird's wing is analogous to a bat's wing.
So, the correct answer is D.
Analogous structures are structures that have similar functions but evolved independently from different ancestors. In the case of bird and bat wings, both structures are used for flight but arose from different tetrapod ancestors, making them analogous structures. Homologous structures, on the other hand, are structures that have similar functions and evolved from a common ancestor.
Learn more about analogous structures at https://brainly.com/question/11154123
#SPJ11
The first documented registry helped in caring and controlling which disease:
a) Black Plague. b) Malaria. c) Leprosy.
The first documented registry helped in caring and controlling the disease of Leprosy. The correct answer is option c) Leprosy.
Leprosy is a chronic infectious disease caused by the bacteria Mycobacterium leprae. It primarily affects the skin, peripheral nerves, mucosal surfaces of the upper respiratory tract, and the eyes. Leprosy can be cured with a combination of antibiotics, but if left untreated, it can cause permanent damage to the skin, nerves, limbs, and eyes.
The first documented registry for leprosy was established in the 13th century by the Knights Hospitaller in Jerusalem. This registry helped in the caring and controlling of the disease by keeping track of patients, providing medical care, and preventing the spread of the disease.
Learn more about caring and controlling disease: https://brainly.com/question/30972064
#SPJ11
What is immunity? a condition of being able to resist a particular disease a condition in which an individual becomes infected by a disease causing agent a condition of being susceptible to a disease all of the above
Immunity is a condition of being able to resist a particular disease. This means that an individual's immune system is able to recognize and effectively fight off a disease-causing agent, preventing them from becoming infected or experiencing severe symptoms.
Immunity can be acquired through natural exposure to a disease, through vaccination, or through the transfer of antibodies from one individual to another. It is an important aspect of overall health and helps to prevent the spread of disease within a population.
Here you can learn more about Immunity
https://brainly.com/question/8189807#
#SPJ11
What is the Warburg effect in cancer cells?
The Warburg effect in cancer cells is a phenomenon in which the cancer cells exhibit a preference for producing energy through glycolysis even in the presence of oxygen. This is in contrast to normal cells, which typically produce energy through oxidative phosphorylation in the presence of oxygen.
The Warburg effect is named after the German biochemist Otto Warburg, who first observed this phenomenon in the 1920s. It is thought to be a hallmark of cancer cells and is believed to play a role in the rapid growth and proliferation of cancer cells. The exact mechanism behind the Warburg effect is not fully understood, but it is thought to be related to the increased metabolic demands of rapidly dividing cancer cells. By relying on glycolysis, cancer cells are able to produce energy more quickly and efficiently than normal cells, which may contribute to their ability to grow and divide rapidly.
learn more about The Warburg effect: https://brainly.com/question/16387439
#SPJ11
In your laboratory, you find that a particular drug increases learning in mice. Briefly, animals who receive the drug learn tasks more quickly, and execute the task with fewer mistakes. You are now trying to understand the mechanism of the drug's action. Specifically, you are going to test whether the drug works pre-synaptically or post-synaptically to increase learning. Set up an experiment with the relevant groups to test the following hypotheses:
1. The drug works by increasing presynaptic function
2. The drug works by increasing postsynaptic response
Please provide details on the technique and the results that would support both hypothesis.
To test the hypotheses that the drug works by increasing presynaptic function or postsynaptic response, we can set up an experiment with the following groups:
1. Control group: Mice that do not receive the drug
2. Presynaptic group: Mice that receive the drug and are treated with a presynaptic inhibitor
3. Postsynaptic group: Mice that receive the drug and are treated with a postsynaptic inhibitor
For the presynaptic group, we can use a technique such as microdialysis to measure the release of neurotransmitters from the presynaptic neuron. If the drug works by increasing presynaptic function, we would expect to see an increase in neurotransmitter release in the presynaptic group compared to the control group.
For the postsynaptic group, we can use a technique such as patch-clamp electrophysiology to measure the response of the postsynaptic neuron to the neurotransmitter. If the drug works by increasing postsynaptic response, we would expect to see an increase in the response of the postsynaptic neuron in the postsynaptic group compared to the control group.
Overall, the results of this experiment would help us determine whether the drug works pre-synaptically or post-synaptically to increase learning in mice.
For more such questions on presynaptic, click on:
https://brainly.com/question/28166751
#SPJ11
which bacteria group has a genomes similar to that of mitochondrial
DNA?
a. escherichia coli
b. rickettsia spp.
c. mycobacterium spp.
The bacteria group that has a genome similar to that of mitochondrial DNA is rickettsia spp. (Option B).
Mitochondria are organelles found in eukaryotic cells that are responsible for producing energy in the form of ATP. They contain their own DNA, which is circular and similar to that of bacteria. This has led scientists to believe that mitochondria were once free-living bacteria that were engulfed by a host cell and became endosymbionts.
Rickettsia spp. are a group of bacteria that are known to be intracellular parasites, meaning they live and reproduce inside host cells. Their genome is similar to that of mitochondrial DNA, which supports the endosymbiotic theory of mitochondrial evolution.
In contrast, Escherichia coli (Option A) and Mycobacterium spp. (Option C) are both free-living bacteria with genomes that are not similar to mitochondrial DNA.
Learn more about mitochondrial DNA: https://brainly.com/question/15688630
#SPJ11
Write two case studies - for TWO (2) diseases that we studied in
week 7. Make sure to address signs, symptoms, how the infection was
acquired, diagnosis, treatment, and if there is any prevention.
Two case studies - for TWO (2) diseases that we studied in week 7 are given with diagnosis, treatment, and prevention.
Case Study 1:
Disease: Measles
Signs & Symptoms: High fever, runny nose, cough, sore throat, and red, watery eyes. A red, spotty rash usually appears three to five days after the start of symptoms.
How Acquired: Measles is caused by a virus that is spread through the air or by direct contact with an infected person.
Diagnosis: A doctor will ask about the patient's medical history, including whether they have been exposed to the measles virus or if they have recently traveled to an area where the disease is common. A physical examination and a laboratory test of a sample of blood can confirm a diagnosis of measles.
Treatment: Measles is generally treated with supportive care. This includes rest, fluids, fever-reducing medicines, and eye drops or ointments to reduce eye irritation.
Prevention: The best way to prevent measles is to get vaccinated. Vaccines are available for free at healthcare facilities.
Case Study 2:
Disease: Meningitis
Signs & Symptoms: Headache, fever, confusion, stiff neck, sensitivity to light, and a rash.
How Acquired: Meningitis is caused by a bacterial or viral infection. It can spread from person to person through close contact or through contact with infected body fluids.
Diagnosis: A doctor will ask about the patient's medical history, including any recent contact with someone who is known to have meningitis. A physical exam and laboratory tests can confirm a diagnosis.
Treatment: Treatment depends on the cause of the meningitis. Bacterial meningitis is treated with antibiotics, while viral meningitis is treated with antiviral medications.
Prevention: Vaccines are available to protect against some of the more common causes of meningitis. Good hygiene, such as washing hands, can help reduce the spread of the disease.
Learn more about Diagnosis at https://brainly.com/question/29891523
#SPJ11
Can you please make 1 sentence
out of the two words. without just simply adding the
defintions.
1. crossing
over
2. synteny
testing
The synteny testing is a powerful tool for genetic analysis that allows scientists to gain insights into the complex relationships between different species and the genetic factors that shape their evolution.
Synteny testing is a genetic analysis method that compares gene arrangements and chromosomal organizations to determine evolutionary relationships between species.In the field of genetics, synteny testing is a method of analyzing genetic structures and evolutionary relationships between species. This approach focuses on comparing gene arrangements and chromosomal organizations between different species to determine how they evolved and how closely related they are. By examining patterns of synteny, researchers can identify which genes and regions of the genome are likely to be conserved across different species, and can use this information to better understand how these genes function and how they have evolved over time.Synteny testing has become increasingly important in recent years as genetic research has advanced, and many scientists are now using this approach to study a wide range of biological phenomena. For example, synteny testing is often used to study the evolution of different animal species, as well as to identify key genetic differences between species that may be responsible for differences in traits or behaviors. Overall, synteny testing is a powerful tool for genetic analysis that allows scientists to gain insights into the complex relationships between different species and the genetic factors that shape their evolution.
Learn more about synteny testing
brainly.com/question/30000986
#SPJ11
Crocodiles, bats, whales, and birds have similar limb bones. What do these similarities suggest?
A. Bats and crocodiles share an ancestor with whales but not with birds.
B. Crocodiles, bats, whales, and birds evolved from a common ancestor.
C. The common ancestor of birds and crocodiles was a whale.
D. A similar limb structure evolved in each species independently and by chance.
Answer:
B
Explanation:
1) With regard of RNAi, what are three possible sources for the double stranded RNA? (3 points) 2) What is meant by the term "histone code"?
The 3 possible sources for the double-stranded RNA are
Histone code
RNA interference and histone codesRNA interference is a biological process where double-stranded RNA triggers the degradation of mRNA with complementary sequences.
Three possible sources of dsRNA for RNAi include:
Viral infectionTranscriptional gene silencingExogenous dsRNAThe "histone code" refers to the specific modifications and combinations of modifications that occur on histone proteins, which play a critical role in regulating gene expression.
Histones are proteins that package DNA into chromatin, and modifications to these proteins, such as acetylation, methylation, and phosphorylation, can affect how tightly DNA is packaged and whether genes are accessible for transcription.
More on RNA interference can be found here: https://brainly.com/question/29523032
#SPJ1
Question
12(7
pointed) This table shows the
F2
data from a typical cross of pea plants. The
P
generatic cross was between a plant with tall stems and purple leaves and a plant with sh stems and white leaves. The F1 all had tall stems and purple leaves. Your job is to do a Chi-squared Goodness of Fit analysis- this is a typical ditybri cross with unlinked genes like Mendel would have performed. Do the calculations on a scratch paper and your calculator, then type your calcul numbers in the blanks in this question. Remember, you HAD to show your blank scratch paper to the screen before you started the exam. If you didn't, do it NOV What is the Expected \# of tall steams with purple flowers (the first row)? What is the expected \# for the second row, tall stems white leaves? What is the expected \# for the third row, short stems with purple leaves? What is the expected \# for the fourth row, the short stems with white leaves? Complete the calculation for the chi-square value and enter your
x 2
value it here, round to the nearest hundredth:.
The chi-square value from table that shows the F2 data from a typical cross of pea plants , rounded to the nearest hundredth, is 28.67.
In order to answer this question, we must first calculate the expected number of tall stems with purple flowers, tall stems with white leaves, short stems with purple leaves, and short stems with white leaves. To do this, you must use the equation:
Expected # = (row total × column total) ÷ grand total
Using this equation, the expected # of tall stems with purple flowers is:
Expected # = (54 × 22) ÷ 130 = 24.92
The expected # of tall stems with white leaves is:
Expected # = (54 × 8) ÷ 130 = 12.31
The expected # of short stems with purple leaves is:
Expected # = (76 × 22) ÷ 130 = 34.08
The expected # of short stems with white leaves is:
Expected # = (76 × 8) ÷ 130 = 14.62
To calculate the chi-square value, use the equation:
X2 = ∑ (O-E)2 / E
Where O is the observed value, and E is the expected value.
Therefore, the chi-square value is:
X2 = (24-24.92)2/24.92 + (14-12.31)2/12.31 + (18-34.08)2/34.08 + (22-14.62)2/14.62 = 28.67
Therefore, the chi-square value, rounded to the nearest hundredth, is 28.67.
More on chi-square: https://brainly.com/question/16749509
#SPJ11
Consider to Loci located on the same chromosome. The first locus has alleles A and a, the second locus has alleles B and b. During meiosis crossovers occur, 24% of the time. In an AaBb individual, one chromosome is AB and the other is ab. 1. The proportion of AB gametes is?
2. The proportion of aB gametes is?
3. The proportion of Ab gametes is?
4. The proportion of ab gametes is?
1. The proportion of AB gametes is 38% (50% non-crossover + 12% crossover).
2. The proportion of aB gametes is 12% (24% crossover * 50% chance of aB).
3. The proportion of Ab gametes is 12% (24% crossover * 50% chance of Ab).
4. The proportion of ab gametes is 38% (50% non-crossover + 12% crossover).
During meiosis, crossovers occur 24% of the time between the two loci. This means that 76% of the time, there is no crossover and the gametes will be either AB or ab. Since there is a 50% chance of each, the proportion of AB and ab gametes will each be 38% (76% * 50%).
When crossovers do occur, there is a 50% chance of producing aB gametes and a 50% chance of producing Ab gametes. Therefore, the proportion of aB and Ab gametes will each be 12% (24% * 50%).
Learn more about gametes
https://brainly.com/question/7648924
#SPJ11
On your hospital IPPE, you are aksed to counsel a pt. on tacrolimus for a kidney transplant. What are some of the important pt. counseling tips you should relay? (select all that apply)A. wear sunscreen and avoid prolonged exposure to sunlight and ultraviolet lightB. avoid alcohol, grapefruit, and grapefruit juiceC. may cause drowsiness; avoid driving or other tasks requiring motor coordinationD. take on empty stomach
On the hospital IPPE, some of the important pt. counselling tips to counsel a patient on tacrolimus for a kidney transplant are
A. wear sunscreen and avoid prolonged exposure to sunlight and ultraviolet light
B. avoid alcohol, grapefruit, and grapefruit juice
C. may cause drowsiness; avoid driving or other tasks requiring motor coordination.
Thus, the correct options are A, B, and C.
Tacrolimus is an immunosuppressant medicine that helps in preventing the immune system from rejecting a transplanted organ, such as a kidney. The medicine is administered orally as a capsule or an extended-release tablet. The dose of tacrolimus depends on a patient’s medical condition, response to therapy, body weight, and concomitant therapy.
A. Wear sunscreen and avoid prolonged exposure to sunlight and ultraviolet light ⇒ Tacrolimus makes the skin more sensitive to the sun. Therefore, patients are advised to wear protective clothing and apply sunscreen of SPF 30 or higher.
B. Avoid alcohol, grapefruit, and grapefruit juice ⇒ Tacrolimus can interact with some foods and beverages, such as grapefruit and grapefruit juice.
C. May cause drowsiness; avoid driving or other tasks requiring motor coordination ⇒ Tacrolimus may cause drowsiness and dizziness, which can affect a patient's ability to perform tasks that require mental alertness.
D. Take on an empty stomach ⇒ Tacrolimus should be taken on an empty stomach, either 1 hour before or 2 hours after meals. Patients are advised not to take Tacrolimus with food as this can affect the absorption of the medicine.
For more information about Tacrolimus refers to the link: https://brainly.com/question/12287969
#SPJ11
3. Explain why sun and shade plants have different maximum rates of photosynthesis and different light saturation points? 4. How would you expect the light response curves of the sun and shade leaves to differ if rates of photosynthesis were expressed per unit mass of leaf chlorophyll rather than on a leaf area basis?
Q3: Sun and shade plants have different maximum rates of photosynthesis and different light saturation points because plants grown in the shade typically experience reduced light intensity and longer exposure to the same light intensity than plants grown in the sun.
In plants adapted to low light, there is an increased investment in structures that enhance light absorption such as larger, thicker, and more densely packed leaves. This increases the amount of light the plant can absorb, allowing for higher photosynthesis rates and light saturation points.
Q4: If rates of photosynthesis were expressed per unit mass of leaf chlorophyll rather than on a leaf area basis, the light response curves of sun and shade leaves would be expected to be similar.
This is because photosynthesis is directly related to chlorophyll content, so the photosynthetic rate would be proportional to the amount of chlorophyll present. Therefore, the difference in photosynthetic rates of sun and shade plants would be less significant than when expressed on a leaf area basis.
You can learn more about photosynthesis at: brainly.com/question/29764662
#SPJ11
Examine this image of bacteria cells.
3D image of probiotic bacterial cells
Which of the following statements best describes a mutualistic relationship between human health and certain types of bacteria?
Intestinal bacteria obtain nutrients from the gut and aid in human digestion.
Bacteria in improperly prepared food are consumed by humans, causing food poisoning.
Humans treat infections with antibacterial medication, which bacteria become resistant to.
Invasive bacteria in an area of injury produce toxins that damage healthy tissues of the human body.
The following statement is the mutualistic relationship that exists between certain kinds of bacteria and human health: Human digestion is aided by intestinal bacteria that obtain nutrients from the gut.
This statement explains how beneficial bacteria in the human gut play a crucial role in the breakdown of food, the extraction of nutrients, and the assistance in the synthesis of certain vitamins.
What are bacteria in the intestine?Microorganisms known as intestinal bacteria can be found throughout the human digestive system, particularly the large intestine. The group of these bacteria is referred to as the gut flora or microbiota. There are hundreds of different species of bacteria, viruses, fungi, and other microorganisms in the complex ecosystem known as the gut microbiota.
What function do intestinal bacteria play?By assisting in the digestion and absorption of nutrients, producing certain vitamins, and assisting in the maintenance of a healthy immune system, intestinal bacteria contribute significantly to human health.
To learn more about bacteria:
brainly.com/question/8008968
#SPJ1
Answer:
A. Intestinal bacteria obtain nutrients from the gut and aid in human digestion.
Explanation:
i got it right on my quiz
PLS ANSWER MY QUESTION (I WILL MARK THE BRAINLIEST IF ANSWERED CORRECTLY)
Answer:
Explanation:
There is not a trend in this graph. It is scattered.
What process is food to amino acid
The process of food to amino acid is referred to as protein digestion.
What is Digestion?
This is referred to as the breakdown of large insoluble food molecules into small water-soluble food molecules so that they can be absorbed into the watery blood plasma.
Protein digestion begins when you first start chewing but once a protein source reaches your stomach, hydrochloric acid and enzymes called proteases break it down into smaller chains of amino acids which is used in the growth and replacement of worn out tissues in the body which is therefore the reason why it was chosen as the correct choice.
Read more about Protein here https://brainly.com/question/8937671
#SPJ1
a food chain follows the connection between one
A food chain follows the connection between one producer and a single chain of consumers within an ecosystem.
What is an Ecosystem?This is a term which consists of all the organisms and the physical environment with which they interact. The biotic and abiotic components which are present are linked together through nutrient cycles and energy flows.
Food chain on the other hand is referred to as the sequence of transfers of matter and energy in the form of food from organism to organism in which the producer makes the food which is the passed to other organisms through various processes and mechanisms.
Read more about Food chain here https://brainly.com/question/2179
#SPJ1
A
snow removal business would be classified as a O A. manufacturing
company. OB. service company. OC. simple company. OD. merchandising
company.
A snow removal business would be classified as a service company. Option B.
This is because the business provides a service, which is removing snow, rather than creating or selling a product.
A service company can be described as a company that offers some kind of service or help instead of manufacturing a product.
Manufacturing companies create products, merchandising companies sell products, and simple companies typically refer to small businesses with a limited number of owners. Therefore, the correct answer is B. service company.
To learn more about business, click here:
https://brainly.com/question/15826604
#SPJ11
The stage of mitosis depicted in the image is...
A anaphaseanaphase
B telophasetelophase
C prophaseprophase
D interphase
The stage of mitosis depicted in the image is anaphase.
What is mitosis?Mitosis is a type of cell division that is essential for the growth and development of organisms. It involves the duplication of the genetic material in a cell’s nucleus, and the subsequent division of the nucleus into two new nuclei, each of which contains the same genetic material as the parent cell. During mitosis, the chromosomes (structures that contain the genetic material) are duplicated and then divided equally between the two new nuclei. The two new nuclei then separate from each other, resulting in two new cells, each with the same number of chromosomes as the parent cell.
This can be determined by the presence of the two sets of chromosomes migrating to opposite ends of the cell as part of the process of separating the sister chromatids. Anaphase is the fourth and final stage of mitosis, following prophase, metaphase, and interphase.
To learn more about mitosis
https://brainly.com/question/23750975
#SPJ1
Answer:The answer is prophase, I just did it.
Explanation:
if work at CDC, you are responsible all new bacteria mutants, determine which bacterial protein has been mutated.
Mutant A: this bacterium cannot accomplish plasmid separation (segregation). Mutated (defective) protein is: ?
Mutant B: this bacterium is unable to form a Z ring ? is ?
Mutant C: this bacterium is unable to control degradation of peptidoglycan strands during cell wall synthesis is ?
Mutant D: this bacterium from a Z ring but not in the middle of the cell is?
Mutant E: this bacterium is unable to accomplish chromosome separation (segregation)Mutated (defective) protein is ?
The mutated bacterial protein in Mutant A, Mutant B and Mutant D is FtsZ; in Muatnt C it is Ftsl and in Mutant E it is PasA.
At the Centers for Disease Control and Prevention (CDC), you are responsible for identifying and analyzing any new bacteria mutants that appear.
Mutant A: The mutated (defective) protein in this bacterium is FtsZ, which is a protein essential for plasmid separation (segregation).
Mutant B: The mutated (defective) protein in this bacterium is FtsZ, which is a protein essential for forming a Z ring.
Mutant C: The mutated (defective) protein in this bacterium is cell division protein FtsI, which is responsible for controlling degradation of peptidoglycan strands during cell wall synthesis.
Mutant D: The mutated (defective) protein in this bacterium is FtsZ, which is a protein essential for forming a Z ring in the middle of the cell.
Mutant E: The mutated (defective) protein in this bacterium is ParA, which is a protein essential for chromosome separation (segregation).
To know more about mutant bacteria, refer here:
https://brainly.com/question/14466226#
#SPJ11
question: Why was the blood collected in a tube containing EDTA
? [250 words]
note: this is lab report.
subject name: introduction biochemistry and biotechnology
The blood was collected in a tube containing EDTA (Ethylenediaminetetraacetic acid) because it is a widely used anticoagulant that prevents blood from clotting. EDTA works by binding to calcium ions in the blood and forming a stable complex, which prevents the calcium ions from participating in the coagulation cascade. This helps to keep the blood in a liquid state and prevents the formation of clots.
In a laboratory setting, it is important to collect blood samples in tubes containing anticoagulants like EDTA to ensure that the samples can be properly analyzed. If the blood were to clot, it would be difficult to obtain accurate measurements of various components of the blood, such as red blood cells, white blood cells, and platelets. By using an anticoagulant like EDTA, researchers can ensure that the blood sample remains in a liquid state and that accurate measurements can be obtained.
In addition to being used in laboratory settings, EDTA is also used in medical settings to prevent clotting in blood samples that are collected for diagnostic testing. This allows healthcare professionals to obtain accurate measurements of various components of the blood, which can help to diagnose and treat a wide range of medical conditions.
In summary, the blood was collected in a tube containing EDTA to prevent clotting and ensure that accurate measurements can be obtained. EDTA is a widely used anticoagulant that works by binding to calcium ions in the blood and preventing them from participating in the coagulation cascade.
Here you can learn more about EDTA
https://brainly.com/question/26556460#
#SPJ11
What is the issue impacting those with phenylketonuria (PKU)?
The inability to convert pyruvate into acetyl CoA.
The increase in sulfur-based amino acid excretion.
The increase in calcium excretion.
The inability to convert phenylalanine into tyrosine.
The issue impacting those with phenylketonuria (PKU) is D: "the inability to convert phenylalanine into tyrosine".
This is due to a mutation in the gene that produces the enzyme phenylalanine hydroxylase, which is responsible for the conversion of phenylalanine to tyrosine. As a result, individuals with PKU have a buildup of phenylalanine in their blood, which can lead to neurological problems and developmental delays if not treated. It is important for those with PKU to follow a strict low-phenylalanine diet to prevent these issues.
You can learn more about phenylketonuria at
brainly.com/question/24756209
#SPJ11