You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only point of contact between the wheelbarrow and the ground is at the front wheel. Assume the distances are as shown in the figure, where 0.50 m is the horizontal distance from the center of the wheel to the center of gravity of the wheelbarrow. The center of gravity of the dirt in the wheelbarrow is assumed to also be a horizontal distance of 0.50 m from the center of the wheel. Suppose that the maximum total upward force that you can apply to the wheelbarrow handles is 75 lb.
Answers
Answer:
Wl = 1740 N
Explanation:
maximum lift weight unaided = force exerted (F) = 650 N
length of the wheelbarrow (L) = 1.4 m
weight of the wheelbarrow (w) = 80 N
distance of center of gravity of the wheel barrow from the wheel = 0.5 m
distance of center of gravity of the load from the wheel = 0.5 m
find the weight of the load (Wl)
from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive
ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0
(F x 1.4) = ((Wl x 0.5) + (w x 0.5)
Wl =
Wl =
Wl = 1740 N
Related Questions
North of Carthage is this, it is a shallow evaporate lake:
A. Rub al-Khali
B. Sebkhet Arina
C. Sebkhet Qaddafi
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Sebkhet Arina
Explanation:
sorry if it's wrong need more information
what is a literature review?
Answers
Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.
Explanation:
to which end of the horseshoe magnet will the north end of the magnet be attracted
Answers
Answer:
The north end of the magnet will be attracted to the south end of the horseshoe magnet.
Likewise, the north end of the magnet will be attracted to the earth's north pole - so the north pole of the earth is actually a south magnetic pole.
A force of 600N is applied to an object that accelerates at a rate of 15m/s/s. What is the mass of the object?
Answers
Answer:
The answer will be it has a mass of 40 kg.
Explanation:
Because Force = mass x acceleration or F = m a, we can say Force divided by mass or F/a = m or mass so 600 divided by 15 equals 40 kg.
Breifly describe how traits are passed down from human parents to their offspring. In your description, be sure to include the terms gene, chromosome, and meiosis.
Answers
Answer:
Parents pass on traits or characteristics, such as eye colour and blood type, to their children through their genes
Explanation:
If I want to calculate the normal force of an object on two legs but the weight of the object is not uniform throughout, how do I go about calculating such a problem?
Answers
Use the right equation. To calculate the normal force of an object at an angle, you need to use the formula: N = m * g * cos (x) For this equation, N refers to the normal force, m refers to the object's mass, g refers to the acceleration of gravity, and x refers to the angle of incline.
The cart is then pushed up the ramp, compressing the spring a distance A from equilibrium. When
released from rest, the cart oscillates up and down the ramp with a period of T₁. Assume that any friction
is negligible.
The spring is then replaced with a second spring that has a constant k2 = 2k₁, and the new period, T2, is
measured.
Determine the period of T2 in terms of T₁.
Answers
When the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
Period of the mass oscillation
The period of the oscillation of the mass or cart on the spring is given by the following formula;
[tex]T = 2\pi \sqrt{\frac{m}{k} } \\\\[/tex]
at a costant mass;
[tex]T_1\sqrt{k_1} = T_2\sqrt{k_2} \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{k_2} }[/tex]
when spring constant is doubled, k2 = 2k1. the new period, T2 is determined as follows;
[tex]T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2k_1} } \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2} \times \sqrt{k_1} } \\\\T_2 = \frac{T_1}{\sqrt{2} }\\\\T_2 = \sqrt{\frac{1}{2} } \ T_1[/tex]
Thus, when the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
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5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?
Answers
Answer:
Explanation:
Force of Tension = (m)(g)
120 = (m)(9.8)
m = volume(density)
120 = (4/3)πr³(0.308)(9.8)
[tex]\frac{(120)(3)}{(pi)(0.308)(9.8)}[/tex] = r^3
solve
The radius of the brass ball is equal to 6.94 × 10⁻² m when the tension in the wire is 120 N.
What is tension?Tension can be demonstrated as the pulling force transmitted by the means of a string, or a rope or can be described as the action-reaction pair of forces acting at each end of said elements.
The tension in the wire attached to the ceiling will be given by:
T = mg ⇒m = T/g
The radius of the brass ball is given by: [tex]r =\sqrt[3]{\frac{3V}{4\pi } }[/tex]
The density is given by: ρ = m/V = T/gV
V = T/gρ
Therefore, the expression for the radius can be written as:
[tex]r =\sqrt[3]{\frac{3T}{4\pi\rho g } }[/tex]
Given the tension in the wire, T = 120 N
The density of the brass is = 8730 Kg/m³
[tex]r =\sqrt[3]{\frac{3\times 120}{4\times 3.14 \times 8730 \times 9.81 } }[/tex]
r = 6.94 × 10⁻² m
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A person driving in a neighborhood traveling 9 m/s slows to a stop (0 m/s) over 4
seconds as they approach a stop sign. What is the rate of acceleration of the car coming
to a stop in m/s²?
(Please help urgently if you can, thanks :D)
Answers
Answer:
-2.25 metres per second squared
find the distance and displacement by minutes hand of length by 7 cm at the end of 3 ⅔ mins
Answers
Answer:
3 14/3
Explanation:
you put a 1 under the 7 then times it with 3 2/3 and you get 3 14/3
If a small appliance is rated at a current of 18 amps and a voltage of 120 volts, what is the
power rating of the appliance?
Answers
2160 watts
thank you
Hope this helped
Have a good day
(Stop flagging my anwsers I got to many I’m gonna get banned)
Rilee Cartner
How does paragraph 3 help develop the ideas in this passage
Answers
Answer:
celebrating different points.
Explanation:
adds more information to what your talking about
What is the distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º
Answers
The distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º will be 0.0000034 m.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º is;
The equation of diffraction grating is given as;
[tex]\rm d sin \theta = n \lambda \\\\ dsin60=2 \times 760 \times 10^{-9} \\\\ d=0.00000304 \ m[/tex]
Hence,he distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º will be 0.0000034 m.
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Can someone please help me!
Answers
Answer: I've solved the above questions and attached pictures too which show the working for better understanding of the questions.
hope that helps...
A tortoise challenges a hare to a four-hour race. The hare is so confident of winning that he allows the tortoise to start with a 10-km lead. The hare runs at a speed of 14 km per hour, but stops for a two-hour nap in the middle of the race. The tortoise plods along at 4 km per hour the whole race. Who gets farther in four hours?
Answers
Explanation: Because in the first place the challenge was to run a four hour race. So the focal point was to make it in 4 hrs, we see the tortoise continuously running in the race for four hours in which he covers a distance of 4km per hour which when we multiply the 4hrs with 4km distance he covered, we will discover that he covered a distance of 16km in 4hrs, so for him its mission accomplished. On the other hand the hare only covered a distance of 14km which he covered in an hour, but that wasn't the challenge, the challenge was to run for 4hours. So not only did the tortoise cover a longer distance, but he also achieved the four hour challenge.
Answer ASAP and only if you know its correct
this is science btw also, brainliest to the correct answer
Answers
Answer:
the doppler effect shows stars with red shifted light
Explanation:
light from a receding star is shifted toward red or redshifted
redshift is an example of the doppler effect
the wavelength of the light is stretched so the light is seen as shifted towards the red part of the spectrum
A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration?
Answers
Answer:
According to the question,
Initial velocity of car (at t=0) = 10 m/s
Final velocity of car (after 15 sec) = 40m/s
Time taken = 15 sec.
Now use, first equation of motion viz.
Explanation:
v = u + at.
40 = 10 + a *15
30 = a*15
a = 30/15
a = 2 m/sec square.
Pluto was first discovered in 1930.It was determined to be located about 39.48 times as far away from the Sun as Earth is. How long does Pluto take to orbit the Sun?
Answers
Answer:
It takes total 248 years for Pluto to orbit the sun.
Pluto will take 253 year to orbit the sun.
What is the distance between the Sun and Earth ?Earth's average distance to the Sun is about 93 million miles (150 million kilometers) from the Sun.
What is the distance between Pluto and the Sun?Pluto is located about 39.48 times as far away from the Sun as Earth is.So the distance between Pluto and Sun will be , 39.48 X 93 = 3671.64 million miles.What is Kepler's third law?The squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits.P^2 = a^3 , where P = period of orbit , a = distance of semi major axis.Pluto has a semi-major axis distance a=40 then T2=403, which gives T=253 years.
Therefore, Pluto will take 253 year to orbit the sun.
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50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED
Answers
Hope this helps!
Please give Brainliest!
This is all about reflection.
So my theory on this is that you have to look at the checklist:
L : Location
O : Orientation
S : Size
T : Type
Answer the questions ( by questions I mean the LOST questions, where they ask you to choose on of the options. For example, for ‘T’ you have to choose as to whether it is ‘real or virtual’ ) by using the diagram below:
Holding a pen crosswise in your mouth is likely to improve your mood, a result predicted by
Answers
Answer:
the facial-feedback hypothesis
Explanation:
If you wanted the car to roll a long way , would you choose carpet or wood
Answers
Will the positioning of your Slinky along the east-west, north-south, or some other orientation affect your readings? Why?
Answers
Positioning your Slinky along any direction different from its initial position will affect your reading, because there will be change in the magnetic field.
Effect of magnet on Slinky
If the Slinky is made of an iron alloy, it can be magnetized by itself. Moving the Slinky around can cause a change in the magnetic field, even if no current is flowing.
When there is a change in the magnetic field, the reading changes.
At any point, you change the orientation of the Slinky, you will need to zero the reading or adjust the Slinky back to its initial position, even if the sensor does not move.
Thus, Positioning your Slinky along any direction that is different to its initial position will affect your reading because there will be change in the magnetic field.
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Martin perceived that there was music playing. Martin
A
did not believe there was music.
B
was very surprised by the music.
C
let everyone know about the music.
D
became aware of the music.
Answers
If the resistance through the fat is 3 times that through the muscle, how much of the total current goes through the fat in terms of the current through the muscle?
A) 3 times the current through the muscle.
B) The same current as through the muscle.
C) No current passes through the fat.
D) 1/3 times the current through the muscle.
Answers
Answer:
it A i think
hope that helps if not i can change it
Explanation:
A projectile is fired from the ground with an initial velocity of 250 m/s at an angle 60 degrees above the horizon. Calculate the horizontal and vertical components of the velocity.
Answers
The vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
What is velocity ?Velocity is the rate of change of displacement.
To calculate the horizontal component of the projectile we use the formula below.
Formula:
Vx = Vcos∅........... Equation 1Where:
Vx = Horizontal velocity of the projectileV = Velocity of the projectile∅ = Angle of the projectileFrom the question,
Given:
V = 250 m/s∅ = 60°Substitute these values into equation 1
Vx = 250(cos60°)Vx = 125 m/sSimilarly, to calculate the vertical velocity, we use the formula below
Vy = Vsin∅................. Equation 2Where:
Vy = Vertical component of the velocity.Also Substitute the values into equation 2
Vy = 250(sin60°)Vy = 216.51 m/sHence, the vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
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The cone and the cylinder below have equal surface area.
2r
OA. True
B. False
Answers
we know that
the surface area of a cylinder is equal to
Substitute
2 Find the surface area of the cone
we know that
the surface area of a cone is equal to
3 Compare the surface area of the cylinder with the surface area of the cone
therefore
the answer is
False
B. False, the surface area of the cone and the cylinder is not the same.
What is the Surface area?The area or region that an object’s surface occupies is known as its surface area. Volume, on the other hand, refers to how much room an object has. Geometry has numerous shapes and dimensions, including spheres, cubes, cuboids, cones, cylinders, etc. Each form has its own volume and surface area.
If the slant height of the cone is 2r, then we can use the Pythagorean theorem to find the radius of the cone:
l² = (2r)² - r²
l² = 3r²
l = r√3
Using this value for the radius of the cone, the formula for its surface area becomes:
A(cone) = πrl + πr²
A(cone) = π(r)(r√3) + πr²
A(cone) = πr²(1 + √3)
For the cylinder, we can use the given height and radius to find its surface area:
A(cylinder) = 2πrl + 2πr²
A(cylinder) = 2π(r)(r) + 2π(r²)
A(cylinder) = 2πr²(1 + r)
Comparing the two surface area formulas, we can see that they are not equal in general, since each figure's coefficient in front of the second term (πr²) is different.
Therefore, we cannot conclude that the two figures have the same surface area based on the information.
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What emits infrared radiation?
Question 5 options:
Humans
Non-living objects
Anything that contains atoms
Answers
Answer:
anything that contains atoms is the correct answer of given statement
what is the mathematical equation for resistivity
Answers
Answer:
See below
Explanation:
rho = R A/l R = resistance A = cross sectional area l = length
runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.
Answers
Answer:
Take north as y and west as -x.
distance=√(x^2+y^2)
displacement= tan theta(tan^-1) (y/x)
answers should be, (9.85m, 66.04°)
A new band sensation is playing a concert and recording it for a live album to be released this summer. The band asks the sound mixer if he can autotune
the singer who has a habit of singing slightly lower than the note.
What would the mixer need to do to the sound wave? How would it affect the characteristics of the wave?
Answers
The sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.
Amplitude of sound waveThe amplitude of a sound wave is the maximum vertical displacement of the sound wave.
The sound mixer will need to increase the amplitude of the sound wave produced by the singer.
The increase in the amplitude of the sound wave produced by the lower tune singer will result in increased loudness of the sound.
Thus, the sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.
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