824.377 the 7 in the thousandth place is the value of the 7 in the hundredth place.
This statement is false because , the value of the 7 in the hundredth place is greater than the value of the 7 in the thousandth place.
How to determine the value of the 7 in the thousandth place equals the value of the 7 in the hundredth place.Each digit in a number has a particular place value dependent on its position in the decimal number system. The digits in the number 824.377 have the following place values:
The 7 in the hundredth position has a value of 7/100, or 0.07. This is because the digit 7 is in the hundredth position, which is in the second position to the right of the decimal point.
The value of the 7 in the thousandth place is 7/1000, or 0.007. This is due to the fact that the digit 7 is in the third place to the right of the decimal point
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ASTU ASGF Find the missing length. 2 U F 270 75 Type only your number answer. S 65 ? G T
The value for the missing length ST of the similar to triangle ∆STU is equal to 234
What are similar trianglesSimilar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.
Given that the triangle ∆STU is similar to the triangle ∆SGF, then SF correspond to SU, and SG correspond to ST. So;
SF/SU = SG/ST
75/270 = 65/ST
ST = (65 × 270)/75
ST = 13 × 18
ST = 234
Therefore, the value for the missing length ST of the similar to triangle ∆STU is equal to 234
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A bowl of raffle tickets contains the numbers 1 through 70. What is the probability that a randomly selected ticket will be a number that is not a multiple of 9?
The probability that a randomly selected ticket will be a number that is not a multiple of 9 is 0.9.
To find the probability that a randomly selected ticket will not be a multiple of 9, we need to find the total number of tickets that are not multiples of 9 and divide it by the total number of tickets in the bowl.
There are 7 multiples of 9 between 1 and 70, namely 9, 18, 27, 36, 45, 54, and 63. Therefore, there are 70 - 7 = 63 tickets that are not multiples of 9.
So, the probability that a randomly selected ticket will not be a multiple of 9 is:
P(not multiple of 9) = 63/70
This can also be written as a decimal or percentage:
P(not multiple of 9) ≈ 0.9 or P(not multiple of 9) ≈ 90%
Therefore, there is a high probability that a randomly selected ticket will not be a multiple of 9.
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$5,581 is invested, part at 15% and the rest at 6% . If the interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54 , how much is invested at each rate? (Round to two decimal places if necessary.)
The amount invested at 15% is $2,840 and at 6% is $2,741. The interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54.
Let's assume that the amount invested at 15% is x, and the amount invested at 6% is y. We know that
x + y = 5,581 (equation 1) (since the total amount invested is $5,581)
We also know that the interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54. This can be expressed as
0.15x - 0.06y = 261.54 (equation 2)
(since the interest earned is equal to the amount invested multiplied by the interest rate)
Now, we can use these two equations to solve for x and y.
First, we will isolate y in equation 1
y = 5,581 - x
Next, we will substitute this expression for y into equation 2
0.15x - 0.06(5581 - x) = 261.54
Simplifying this equation gives
0.15x - 334.86 + 0.06x = 261.54
0.21x = 596.40
x = 2,840
Now that we know x, we can use equation 1 to find y
2,840 + y = 5,581
y = 2,741
Therefore, $2,840 is invested at 15%, and $2,741 is invested at 6%.
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Hey can someone help with this
The company should invest in 69.06 units of labor and 67.47 units of capital to maximize production output given the budget constraint.
We have,
We want to maximize the production output
P = L^0.8 K^0.2
subject to the constraint 10L + 20K = 2700.
We can solve for K in terms of L from the constraint equation:
10L + 20K = 2700
20K = 2700 - 10L
K = (2700 - 10L) / 20
K = 135 - 0.5L
Substitute this expression for K into the production function:
P = L^0.8 K^0.2
P = L^0.8 (135 - 0.5L)^0.2
We want to maximize P with respect to L.
Taking the derivative of P with respect to L:
dP/dL = 0.8L^-0.2 (135 - 0.5L)^0.2 + 0.2L^0.8 (135 - 0.5L)^-0.8 (-0.5)
dP/dL = 0.16(135 - 0.5L)^0.2 L^-0.2 - 0.1(135 - 0.5L)^-0.8 L^0.8
Setting dP/dL equal to zero and solving for L:
[tex]0.16 (135 - 0.5L)^{0.2} L^{-0.2} - 0.1 (135 - 0.5L)^{-0.8} L^{0.8} = 0[/tex]
0.16(135 - 0.5L)^0.2 = 0.1(135 - 0.5L)^-0.8 L^1
1.6(135 - 0.5L) = (135 - 0.5L)^-0.8 L
1.6 = (135 - 0.5L)^-1.8 L^-1
1.6L = (135 - 0.5L)^1.8
1.6L = (135^1.8 - 0.5L)^1.8
1.6L = 2.24474e+15 - 4.52222e+14 L + 1.22313e+13 L^1.8
1.22313e+13 L^1.8 - 4.52222e+14 L + 2.24474e+15 - 1.6L = 0
This equation can be solved numerically using a solver or a graphing calculator.
The solution is L = 69.06 units of labor.
To find the corresponding value of K, we can use the constraint equation:
10L + 20K = 2700
20K = 2700 - 10L
K = (2700 - 10(69.06)) / 20
K = 67.47 units of capital
Therefore,
The company should invest in 69.06 units of labor and 67.47 units of capital to maximize production output given the budget constraint.
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Sketch the graphs of the following equations. y=x +5, y = -(x + 5), and y=|x +5|
Answer: below
Step-by-step explanation:
The first equation y = x + 5 is the equation of a straight line with slope 1 and y-intercept 5. We can plot this line by starting at the point (0, 5) and then moving up one unit for every one unit to the right.
The second equation y = -(x + 5) is also the equation of a straight line, but with slope -1 and y-intercept -5. We can plot this line by starting at the point (0, -5) and then moving down one unit for every one unit to the right.
The third equation y = |x + 5| is the equation of a V-shaped graph, or an absolute value function, centered at x = -5. We can plot this graph by first plotting the portion of the graph for x < -5, which is given by y = -(x + 5). Then, we can plot the portion of the graph for x > -5, which is given by y = x + 5. Finally, we can connect these two portions of the graph at x = -5 by drawing a vertical line segment from (-5, 0) to (-5, 10).
Answer:
First, let's start with y = x + 5.
To graph this equation, we can use a table of values. We'll choose a few values of x, and then plug them into the equation to find the corresponding values of y.
x | y
--|---
-5 | 0
-4 | 1
-3 | 2
-2 | 3
-1 | 4
0 | 5
1 | 6
2 | 7
3 | 8
4 | 9
5 | 10
Now, we can plot these points on a graph and connect them with a straight line.
```
| *
10|
| *
| *
| *
|*
| -------------
| -5 -4 -3 -2 -1 0 1 2 3 4 5
```
This is the graph of y = x + 5.
Next, let's look at y = -(x + 5).
This equation is similar to the first one, but with a negative sign in front of the parentheses. This means that the graph will be a mirror image of the first one, reflected across the y-axis.
So, we already know some of the points on this graph. If we take the points from the first graph and flip them horizontally (i.e. change the sign of the x-coordinate), we'll get the points for the second graph.
x | y
--|---
5 | 0
4 | -1
3 | -2
2 | -3
1 | -4
0 | -5
-1 | -6
-2 | -7
-3 | -8
-4 | -9
-5 | -10
Plotting these points on a graph and connecting them with a straight line, we get:
```
|*
10| *
| *
| *
| *
| *
| *
| *
|---------------
| -5 -4 -3 -2 -1 0 1 2 3 4 5
```
This is the graph of y = -(x + 5).
Finally, let's look at y = |x + 5|.
This equation involves absolute value, which means that the graph will be "V"-shaped. The vertex of the "V" will be at x = -5.
To find some points on this graph, we can again use a table of values. We'll choose some values of x, and then plug them into the equation, being careful to take the absolute value of the result.
x | y
--|---
-10 | 5
-5 | 0
0 | 5
5 | 10
10 | 15
Now, we can plot these points on a graph and connect them to form a "V" shape.
```
| *
15| *
| *
| *
| *
| *
|-------------
|-10 -5 0 5 10
```
This is the graph of y = |x + 5|.
Are the triangles similar? If so, complete the similarity statement and state how you know they are similar. Not Similar OA BST by SSS~ A BTS by SSS~ O A BTS by SAS~ OA BST by SAS~ 64 D 176 S ABCD~ B 44 121 C
The triangle triangle ∆BCD is not similar to the triangle ∆BTS since their sides and angle does not correspond in proportion.
What are similar trianglesSimilar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.
Triangle ∆BCD is not similar to the triangle ∆BTS, BT does not correspond to BC, and BS does not correspond to BD. Also, the angle m∠SBT does not correspond to m∠DBC.
Therefore, the triangle ∆BCD is not similar to the triangle ∆BTS since their sides and angle does not correspond in proportion.
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The question is below.
The formula for the volume of a rectangular prism is:
V = l x w x h
where V is the volume, l is the length, w is the width, and h is the height.
We know that the volume of Caleigh's jewelry box is 14 cubic inches, and the area of the base is 7 square inches. Since the base of the box is a rectangle, we can use the formula for the area of a rectangle to find the length and width of the base:
A = l x w
7 = l x w
We don't know the exact values of l and w, but we do know that their product is 7.
Now we can use the formula for the volume of a rectangular prism to find the height:
14 = l x w x h
We know that l x w = 7, so we can substitute 7 for l x w:
14 = 7 x h
Dividing both sides by 7 gives:
h = 2
Therefore, the height of Caleigh's jewelry box is 2 inches.
Researchers were interested in whether eating fruits and vegetables impacts life expectancy. Below are the life expectancy data from people who ate a diet centered around fruits and vegetables for much of their lives and data from people who did not eat many fruits and vegetables throughout their lives. Conduct the steps of hypothesis testing on these data.
Data table: Life expectancies for people to ate fruits and vegetables vs those who did not eat fruits and vegetables.
Ate fruits and vegetables Did not eat fruits and vegetables
82 71
83 75
92 81
71 74
81 95
73
There is a statistically significant difference in life expectancy between people who ate fruits and vegetables and people who did not eat fruits and vegetables by hypothesis
State the null hypothesis and the alternative hypothesis.
The null hypothesis (H₀) is that there is no difference in life expectancy between people who ate fruits and vegetables and people who did not eat fruits and vegetables.
The alternative hypothesis (Ha) is that there is a difference in life expectancy between the two groups.
H₀: μ₁ = μ₂
Ha: μ₁ ≠ μ₂
Determine the appropriate test statistic and significance level.
Since we are comparing the means of two independent samples, we can use a two-sample t-test.
We will use a significance level of α = 0.05.
We can use a calculator or statistical software to calculate the test statistic.
t = -2.379
df = 8.98
p-value = 0.042
where t is the test statistic
The p-value is 0.042, which is less than the significance level of 0.05.
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AOC and BOD are diameters of a circle, centre O.
Prove that triangle ABD and triangle DCA are congruent by RHS.
If AOC and BOD are diameters of a circle, centre O, we can prove that triangle ABD and triangle DCA are congruent by RHS.
First, we can observe that angle AOB and angle COD are both right angles since they are angles subtended by diameters of the circle.
Since AO and BO are equal radii of the circle, they have the same length. Similarly, CO and DO are equal radii of the circle and have the same length. Thus, we have:
AO = BO = CO = DO
Now, consider triangle ABD and triangle DCA. We have:
AB = DC (both are diameters of the circle, hence have the same length)
AD = AD (common side)
∠ADB = ∠CDA = 90° (both are right angles)
Therefore, by the RHS (Right Angle-Hypotenuse-Side) congruence criterion, we can conclude that triangle ABD and triangle DCA are congruent.
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Find the minimum and maximum values of the objective function, and the points at which these values occur subject to the given constraints. Round your answers to the
nearest hundredth.
The minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).
To solve this linear programming problem, we need to first graph the feasible region defined by the given constraints:
The first constraint, x ≥ 0, represents the non-negative values of x along the x-axis.
The second constraint, 4x + 8y ≥ 32, can be rewritten as y ≥ -(1/2)x + 4, which is a line with a y-intercept of 4 and a slope of -(1/2). The feasible region is above this line.
The third constraint, 10x - y ≤ 30, can be rewritten as y ≥ 10x - 30, which is a line with a y-intercept of -30 and a slope of 10. The feasible region is above this line as well.
The fourth constraint, x + 6y ≤ 54, can be rewritten as y ≤ -(1/6)x + 9, which is a line with a y-intercept of 9 and a slope of -(1/6). The feasible region is below this line.
The feasible region is therefore the polygon bounded by the lines y = -(1/2)x + 4, y = 10x - 30, y = -(1/6)x + 9, and x = 0. To find the minimum and maximum values of the objective function f(x,y) = 11x + 13y, we need to evaluate this function at each corner of the feasible region and compare the results.
The corners of the feasible region are (0,4), (3,2), (5,4), and (0,9). Evaluating the objective function at these corners, we get:
f(0,4) = 52
f(3,2) = 47
f(5,4) = 89
f(0,9) = 117
Therefore, the minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).
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35 fluid ounces equals how many cup and ounces
Answer: 4.375 Cups and 35 Ounces.
Step-by-step explanation:
The amount of fluid ounces in 1 cup is 8, meanwhile the amount of fluid ounces in an ounce is 1.
Hope that helps
Question 22
The sum of two numbers is 107. The difference of the two numbers is 53. What are the two
numbers.
Let z be the larger number and y be the smaller number.
Write an equation that expresses the information in the sentence "The sum of two numbers is 107."
Write an equation that expresses the information in the sentence "The difference of the two
numbers is 53."
Solve the system you have written above.
The larger number, a is
> Next Question
The smaller number, y is
The requried larger number x is 80 and the smaller number y is 27.
Let's use the given variables:
x be the larger number
y be the smaller number
According to question
The sum of two numbers is 107 is represented by x + y = 107
The difference between the two numbers is 53 is represented by x - y = 53.
Solving the system of equations:
(x + y) + (z - y) = 107 + 53
2x = 160
x = 80
Now, z = 80, substitute this value into one of the original equations to solve for y.
x + y = 107
80 + y = 107
y = 27
Therefore, the requried larger number x is 80 and the smaller number y is 27.
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Un trabajo puede ser realizado por 30 obreros durante 40 días. si el plazo para terminarlo es de 12 días, ¿cuántos obreros más se deben contratar?
To complete the job in 12 days, they need 100 workers.
How many works are needed?We know that 30 workes can complete 1 job in 40 days, then if each worker works at a rate R, then we can write:
30*R*40 days = 1 job
R = (1/1200) job/day
Then if they need to complete the job in 12 days, the number N of workers needed is:
N*(1/1200)*12 = 1
N = (1200/12) = 100
100 workers are needed.
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Amanda graphed the equation 10x + 5y = 20
For a unique solution is: [tex]\frac{10}{a}\neq \frac{5}{b}[/tex]
For an infinitely many solution is: [tex]\frac{10}{a}= \frac{5}{b}=\frac{-20}{c}[/tex]
What is a linear equation?An equation of the form ax+by+c=0 is called a linear equation where a, b, c∈R
We have the linear equation is:
10x + 5y = 20
Now, we have to find the unique solution and infinitely many solution:
Firstly, For a unique solution, we need an equation ax+by+c=0 such that
[tex]\frac{10}{a}\neq \frac{5}{b}[/tex]
Now, For an infinitely many solutions, we need an equation ax+by+c=0 such that:
[tex]\frac{10}{a}= \frac{5}{b}=\frac{-20}{c}[/tex]
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For, complete question, to see the attachment.
Unique ID: 2174
Watch help video
Find the length of the third side. If necessary, write in simplest radical form.
6
3√5
The length of the third side is given as follows:
x = 3√3.
What is the Pythagorean Theorem?The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.
The theorem is expressed as follows:
c² = a² + b².
In which:
c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.The parameters for this problem are given as follows:
Side lengths of 3 and x.Hypotenuse of 6.Hence the third side is given as follows:
x² + 3² = 6²
x² + 9 = 36
x² = 27
x = √3³
x = 3√3.
Missing InformationThe triangle is given by the image presented at the end of the answer.
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Please answer these 3 questions
The Volume of the box is 12 cubic unit.
We have,
Height = 1 unit
Width = 2 unit
Length = 6 unit
So, Volume of box
= l w h
= 1 x 2 x 6
= 12 cubic unit
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Solve for x:
3x - 3 = 4(x-9)
Show your work
Answer:
[tex]\Huge \boxed{\bf{x = 33}}[/tex]
Step-by-step explanation:
To solve for x in the equation [tex]3x - 3 = 4(x - 9)[/tex], we will follow these steps:
1. Distribute the 4 on the right-hand side of the equation:
[tex]3x - 3 = 4x - 36[/tex]2. To isolate x, subtract 3x from both sides:
[tex]-3 = x - 36[/tex]3. Lastly, add 36 to both sides of the equation to solve for x:
[tex]x = 33[/tex]So, the solution to the equation [tex]3x - 3 = 4(x-9)[/tex] is [tex]x = 33[/tex].
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________________________________________________________
Which answers describe the shape below? Check all that apply.
31
A
A. Quadrilateral
B. Rhombus
C. Trapezoid
D. Parallelogram
E. Rectangle
F. Square
Answer:
A and D are correct. This is a parallelogram, which is a quadrilateral. B is not correct because not all the sides are congruent. C is not correct. E and F are not correct because this parallelogram does not have any right angles.
Question 14(Multiple Choice Worth 5 points)
(07.02 MC)
A system of inequalities is shown.
Which system is represented in the graph?
Oy
y
Oy2x² - 2x+4
y<-x² + 4
Oyzx² - 2x+4
ys-x² +4
Oy>x² - 2x +4
y≤ x² + 4
The system of inequalities that represents the graph is
y ≥ x² - 2x + 4 and y < -x² + 4 is the
Option B is the correct answer.
We have,
The inequality y ≥ x² - 2x + 4 represents a parabola that opens upwards and has a vertex at (1,3) as shown below:
The inequality y < -x² + 4 represents an inverted parabola that opens downwards and has a vertex at (0,4) as shown below:
Therefore,
The system of inequalities that represents the graph is
y ≥ x² - 2x + 4 and y < -x² + 4 is the
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A Circle has a radius of 6cm, an arc AB of the circle is 9cm calculate this angle subtended by AB
The angle subtended by the arc AB in the circle is 68.75 degrees.
We have,
We know that the circumference of a circle is given by 2πr,
where r is the radius of the circle.
The circumference of the circle with a radius of 6 cm is.
C = 2πr = 2π(6) = 12π cm
Since the arc AB of the circle is 9 cm, we can find the angle subtended by this arc using the formula:
angle = (arc length / circumference) x 360°
Plugging in the values we have:
angle = (9 / 12π) x 360°
angle = 68.75°
Therefore,
The angle subtended by the arc AB is 68.75 degrees.
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Given the point (8,11π/6) in polar coordinates, find the Cartesian coordinates of the point.
Select the correct answer below:
(−4√3,4)
(4√3,−4)
(4,−4√3)
(−4√3,−4)
(−4,4√3)
Answer: b
Step-by-step explanation:Remember that the Cartesian coordinates are given by the formulas
xy=rcosθ=rsinθ
We are told that r=8 and θ=11π6, so we can plug in to find that
x=rcosθ=(8)(cos11π6)=(8)(3‾√2)=4√3
Similarly, we find that
y=rsinθ=(8)(sin11π6)=(8)(−12)=−4
So the final answer is (4√3,−4).
The maker of a cell phone screen protector would like to estimate the proportion of customers who file a warranty claim. To do so, they select a random sample of 200 customers and determine that the 96% confidence interval for the true proportion of customers who file a warranty claim to be 0.15 to 0.28. Which of the following would decrease the margin of error?
selecting another sample
decreasing the sample size
increasing the confidence level
decreasing the confidence level
In order to decrease the margin of error, the best option in this instance is by decreasing the confidence level would make the interval to be narrower.
The correct option is D.
What is the margin of error?The margin of error, also known as the confidence interval, provides information on how closely your survey results will likely reflect the opinions of the general community.
The margin of error is a measure of the potential uncertainty in your survey results. It is more likely that the results will deviate from the "true figures" for the entire population the wider the margin of error.
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Help with this question.
The contrapositive statement is option D
What is contrapositive statement?If the hypothesis and conclusion of an earlier conditional statement are reversed, a contrapositive statement is produced.
Technically speaking, the contrapositive of a conditional statement that starts with "If p, then q" is "If not q, then not p." The initial assertion and its contrapositive, then, are both true because they are logically equivalent.
Thus the contrapositive statement as shown is the statement ~q ~p
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Solve for x. 3x2−6x+2=0
x=3±23√3
x=3±3√3 x equals fraction numerator 3 plus or minus square root 3 end root end numerator over 3 end fraction x=6±43√3 x equals fraction numerator 6 plus or minus 4 square root 3 end root end numerator over 3 end fraction x=6±23√3 x equals fraction numerator 6 plus or minus 2 square root 3 end root end numerator over 3 end fraction
The solution of "quadratic-equation" , 3x² - 6x + 2 = 0 is (b) x = (3 ± √3)/3.
A "Quadratic-Equation" is defined as a second-degree polynomial equation of the form : ax² + bx + c = 0,
where x = variable, and "a", "b", and "c" are constants, with a ≠ 0.
We use the "quadratic-formula" to solve : which is ⇒ x = (-b ± √(b²-4ac))/(2a),
In the quadratic equation "3x² - 6x + 2 = 0", We get , a = 3, b = -6, and c = 2.
Substituting the values,
we get,
⇒ x = (-(-6) ± √((-6)²-4(3)(2)))/(2×3),
⇒ x = (6 ± √(36-24))/6,
⇒ x = (6 ± √12)/6,
⇒ x = (6 ± 2√3)/6,
⇒ x = (3 ± √3)/3,
So the two roots of the quadratic equation 3x² - 6x + 2 = 0 are : x = (3 + √3)/3 and x = (3 - √3)/3.
Therefore, the correct option is (b).
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The given question is incomplete, the complete question is
Find the solution of the given quadratic equation , 3x² - 6x + 2 = 0.
(a) x = 3 ± 23√3
(b) x = (3 ± √3)/3
(c) x = 6 ± 43√3
(d) x = 6 ± 23
Fill in the missing purchase prices and selling prices for stock trades in the table.
Number
of Shares
Selling Price
per Share
Capital Gain
or Loss
500
100
650
1,300
Purchase Price
per Share
$54
C.
g.
$31
$62
$12
$23
a.
f.
$700
-$7,800
Percent Gain or Loss
(nearest tenth of a percent)
b.
d.
h.
15% (gain)
The blanks will be -
(a) Capital Gain = $4000
(b) Percent of Capital Gain = 14.8%
(c) Purchase price per share = $5
(d) Percent of capital gain = 140%
(e) The selling price per share = $35.65
(f) Capital Gain = $3022.5
(g) Purchase price per share = $29
(h) Percent of capital loss = 20.7%
(i) Purchase price per share $54 and selling price per share $62.
The number of shares is 500.
So, Capital Gain = (500*62 - 500*54) = $4000
Percent of Capital Gain = (4000/(500*54))*100% = 14.8% (rounding to nearest tenth)
(ii) Number of shares = 100 and selling price of per share = $12 and capital gross = $700.
Purchase price per share = (12*100 - 700)/100 = 500/100 = $5
So the percent of capital gain = (700/(5*100))*100% = 140%
(iii) Number of shares = 650 and purchasing price per share = $31 and percent of capital gain = 15%
The selling price per share = 31*(100+15)/100 = $35.65
Capital Gain = (31*650)*15% = $3022.5
(iv) Number of shares = 1300 and selling price of per share = $23 and capital loss = - $7800
Purchasing price per share = $ (23*1300+7800)/1300 = $29
Percent of capital loss = (7800/(29*1300))*100% = 20.7% (rounding to nearest tenth)
Hence, (a) $4000; (b) 14.8% (gain); (c) $5; (d) 140% (gain); (e) $35.65; (f) $3022.5; (g) $29; (h) 20.7% (loss).
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Solve for b:
-3(3+6b) = 36 - 3b
Show your work.
27. The side length of a cube is (b+7). What is its volume?
HELP WHICH INE IS IT CORRECTT ITS DUE TODAY
Answer:
Step-by-step explanation:
The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.0700% by weight. A 24.0 g sample of this fertilizer is dissolved in 2.00 L of solution.
The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.0700% by weight. A 24.0 g sample of this fertilizer is dissolved in 2.00 L of solution. Number of moles of copper ions available in the solution is 8.77×10⁻⁵mole.
In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like atoms, molecules, and other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number. In this the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, per the decisions of the General Conference upon Measurements and Weights. Amount of copper sulfate available in 24.0 grams of the sample =
0.07/100× 24.0 =0.014g
number of moles of copper sulfate=0.014/159.6=8.77×10⁻⁵
Number of moles of copper ions available in the solution=8.77×10⁻⁵mole
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a) What is the area of the top face of this
cuboid?
b) What is the area of the bottom face of
this cuboid?
4 cm
9 cm
7 cm
The area of both the top face and the bottom face of the cuboid is 63 square centimeters (cm²).
To find the area of each face of the cuboid, we'll use the formulas for finding the area of a rectangle (which is the shape of each face of the cuboid).
Given dimensions:
Length (L) = 9 cm
Width (W) = 7 cm
Height (H) = 4 cm
a) Area of the top face of the cuboid:
The top face is a rectangle with dimensions 9 cm (length) and 7 cm (width).
Area = Length × Width
Area = 9 cm × 7 cm
Area = 63 square centimeters (cm²)
b) Area of the bottom face of the cuboid:
The bottom face is also a rectangle with dimensions 9 cm (length) and 7 cm (width).
Area = Length × Width
Area = 9 cm × 7 cm
Area = 63 square centimeters (cm²)
Therefore, the area of both the top face and the bottom face of the cuboid is 63 square centimeters (cm²).
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