y = 49 - 4x y = 73 - 7x

The solution to this system of equations are x = -5 and y = 8.

In order to determine the solution to a system of two linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

x + y = 3                .........equation 1.

x - 3y = -29                .........equation 2.

By subtracting equation 2 from equation 1, we have:

(x - x) + (y - (-3y) = 3 - (-29)

y + 3y = 3 + 29

4y = 32

y = 32/4 = 8

x = 3 - y

x = 3 - 8

x = -5

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Answer:80%

Step-by-step explanation:

When approximating mixed fraction 5 6/13 to the nearest whole number, the rounded value is 5.

To round the mixed fraction 5 6/13 to the nearest whole number, we examine the fractional part, which is 6/13. The general rule for rounding mixed fractions is to consider the fractional part and round up if it is greater than or equal to 1/2, and round down if it is less than 1/2.

In this case, 6/13 is approximately 0.4615. Since it is less than 1/2, we need to round down to the nearest whole number. Therefore, when rounding 5 6/13 to the nearest whole number, the answer is 5.

A mixed fraction consists of a whole number part and a fractional part. When rounding a mixed fraction, we focus on the fractional part to determine the appropriate rounding direction. If the fractional part is exactly 1/2, it is typically rounded up to the next whole number.

However, in the case of 5 6/13, the fractional part is less than 1/2, so we round down. Rounding down gives us a more accurate approximation that is closer to the original value. In this instance, rounding 5 6/13 down to 5 provides a whole number estimate that is slightly smaller but still reasonably close to the initial mixed fraction.

Rounding serves as a useful tool in situations where precise values are not necessary and a simpler approximation is sufficient for practical purposes.

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The slope of the line that represents the proportional relationship between x and y in the given table is 1/6. To graph the line, we can plot the points from the table and connect them with a straight line passing through the origin (0,0).

The relationship between x and y is proportional, which means that there is a constant ratio between the two variables. We can find the slope of the line that represents this relationship by calculating the ratio of the change in y over the change in x between any two points on the line. Let's use the first and last points

slope = (y2 - y1) / (x2 - x1) = (2.0 - 0) / (12 - 0) = 2/12 = 1/6

So, the slope of the line that represents this proportional relationship is 1/6.

To graph the line, we can plot the points from the table and connect them with a straight line. The line will pass through the origin (0,0) and have a slope of 1/6. The graph will look like.

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To solve the equation [tex]2^{3-x} + 2^{x+1} = 17[/tex] and the equation log x + log (x+3) = 1, We get the solution to the system of equations is x = 2. To check if x = 2 satisfies the first equation [tex](2^{3-x} + 2^{x+1} = 17).[/tex]

Solve the first equation, [tex]2^{3-x} + 2^{x+1} = 17.[/tex] Rewrite the equation as[tex]2^{3-x} = 17 - 2^{x+1}.[/tex] Take the logarithm of both sides (base 2): [tex]3-x = log2(17 - 2^{x+1})[/tex]. Rewrite the equation as [tex]x = 3 - log2(17 - 2^{x+1}).[/tex]

Solve the second equation, log x + log (x+3) = 1. Combine the logarithms: log(x(x+3)) = 1. Remove the logarithm by taking the exponent of both sides: x(x+3) = 10. The equation: x^2 + 3x = 10. Rearrange to form a quadratic equation:[tex]x^2 + 3x - 10 = 0.[/tex]

Factor the quadratic equation: (x+5)(x-2) = 0. Set each factor to zero: x+5 = 0 or x-2 = 0. Solve for x: x = -5 or x = 2. The solutions. Check if x = -5 satisfies the first equation [tex](2^{3-x} + 2^{x+1} = 17).[/tex]([tex]2^{3-x} + 2^{x+1} = 17)[/tex]. If it does not, discard it.  

The solution to the system of equations is x = 2.

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Answer:

divide by 100

Step-by-step explanation:

hope it helps

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.1 kg = 1 m.

Convert 1 Kilograms to Meters (kg to m) with our conversion calculator and conversion tables. To convert 1 kg to m use direct conversion formula below.1 kg = 1 m.You also can convert 1 Kilograms to other Weight (popular) units.

[tex]Direct \: \: conversion \: \: formula: 1 Kilograms * 1 = 1 Meters[/tex]

Using the formula for the area of a circle:

A = πr^2

A = π(4m)^2

A = 16π

A ≈ 50.3 m^2

Breaking the circle into equal sectors and rearranging the sectors as a parallelogram:

We can break the circle into 8 equal sectors, like this:

[IMAGE: circle with 8 equal sectors]

Each sector is 1/8th of the circle, so its angle is 45°. We can rearrange the sectors to form a parallelogram, like this:

[IMAGE: parallelogram made up of 8 sectors of the circle]

The base of the parallelogram is the same as the circumference of the circle, which is 2πr:

base = 2πr

base = 2π(4m)

base = 8π

The height of the parallelogram is the radius of the circle, which is 4m.

Now we can find the area of the parallelogram:

A = base × height

A = 8π × 4m

A = 32π

A ≈ 100.5 m^2

Finally, we can divide the area of the parallelogram by 8 to get the area of the circle:

A = (area of parallelogram) ÷ 8

A = (32π) ÷ 8

A = 4π

A ≈ 12.6 m^2

Therefore, the area of the circle is approximately 50.3 m^2 (using the formula) or 12.6 m^2 (using the parallelogram method).

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The expression represents the second partial sum for 2(0. 4) + 2(0. 4)2 2(0. 4)2 + 2(0. 4)3 2 + 2(0. 4) 0 + 2(0. 4)1 is 0.8.

The second partial sum of a sequence refers to the sum of the first two terms of the sequence.

The given sequence is: 2(0.4) + 2(0.4)^2 + 2(0.4)^2 + 2(0.4)^3 + 2(0.4)^0 + 2(0.4)^1

To find the second partial sum, we simply add the first two terms of the sequence:

2(0.4) + 2(0.4)^2 = 0.8

Therefore, the expression that represents the second partial sum for the given sequence 2(0. 4) + 2(0. 4)2 2(0. 4)2 + 2(0. 4)3 2 + 2(0. 4) 0 + 2(0. 4)1 is 0.8.

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In the given diagram, using the intersecting secant theorem, the length of c is 2 cm

From the question, we are to determine the length of segment c

From the intersecting secant theorem, we have that

If two secant segments intersect outside a circle, then the product of the secant segment with its external portion equals the product of the other secant segment with its external portion

Thus,

In the given circle, we can write that

a × b =  c × d

Substitute the values

3 × 12 = c × 18

36 = c × 18

Divide both sides by 18

36 / 18 = (c × 18) / 18

2 = c

Therefore,

c = 2

Hence, the length of c is 2 cm

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The equation of this model situation with  $4500 into an account earning 6% interest compounded annually is  4500(1.06)ᵗ.

The equation to model the situation would be:

A = P(1 + r/n)ⁿᵗ

where A is the amount of money in the account after t years, P is the initial investment (which is $4500), r is the interest rate (which is 6% or 0.06 as a decimal), n is the number of times the interest is compounded per year (in this case, annually), and t is the number of years.

Plugging in the values, the equation becomes:

A = 4500(1 + 0.06/1)ⁿᵗ

Simplifying further, it becomes:

A = 4500(1.06)ᵗ

This equation can be used to find the amount of money in the account after any number of years.

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The exponential growth function V(t) is:
V(t) ≈ 35,000 * (1.068)^t

To find the exponential growth rate k and the exponential growth function V(t), we can use the formula:

V(t) = V₀ * (1 + k)^t

where V(t) is the value of the painting at time t, V₀ is the initial value of the painting, k is the growth rate, and t is the number of years after 1950.

Given:
Initial value, V₀ = $35,000 (in 1950)
Final value, V(54) = $92,906,000 (in 2004, which is 54 years after 1950)

We can now solve for k:

92,906,000 = 35,000 * (1 + k)^54

Divide both sides by 35,000:

2,654.457 = (1 + k)^54

Now take the 54th root of both sides:

1.068 = 1 + k

Subtract 1 from both sides to find k:

k ≈ 0.068

Now, we can plug k back into the exponential growth function formula:

V(t) = 35,000 * (1 + 0.068)^t

So, the exponential growth function V(t) is:

V(t) ≈ 35,000 * (1.068)^t

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Distribute

50+30(2x+10)

50+30×2x+30×10

50+60×+300

add the number

50+300+60×

350+60x

60x+350

common factors

10(6x+35)

a) The mean monthly rainfall amount for City A is 334.17 inches and for City B is 5.83 inches.

b) The MAD for City A is 464.28 inches and for City B is 0.46 inches.

c) The median for City A is 5 inches and for City B is 6 inches.

(a) To find the mean monthly rainfall amount for each city, we need to add up all the rainfall amounts and divide by the number of months:

For City A: (5 + 2.5 + 6 + 2008.5 + 5 + 3) / 6 = 334.17 inches

For City B: (7 + 6 + 5.5 + 6.5 + 5 + 6) / 6 = 5.83 inches

(b) To find the mean absolute deviation (MAD) for each city, we need to find the absolute deviations from the mean for each data point, then calculate the average of those absolute deviations:

For City A:

Mean = 334.17 inches

Absolute deviations from the mean: |5 - 334.17| = 329.17, |2.5 - 334.17| = 331.67, |6 - 334.17| = 328.17, |2008.5 - 334.17| = 1674.33, |5 - 334.17| = 328.17, |3 - 334.17| = 331.17

MAD = (329.17 + 331.67 + 328.17 + 1674.33 + 328.17 + 331.17) / 6 = 464.28 inches

For City B:

Mean = 5.83 inches

Absolute deviations from the mean: |7 - 5.83| = 1.17, |6 - 5.83| = 0.17, |5.5 - 5.83| = 0.33, |6.5 - 5.83| = 0.67, |5 - 5.83| = 0.83, |6 - 5.83| = 0.17

MAD = (1.17 + 0.17 + 0.33 + 0.67 + 0.83 + 0.17) / 6 = 0.46 inches

(c) To find the median for each city, we need to arrange the data points in order and find the middle value:

For City A: {2.5, 3, 5, 5, 6, 2008.5}

Median = 5 inches

For City B: {5, 5.5, 6, 6, 6.5, 7}

Median = 6 inches

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To determine the convergence of the integral 4(1-z)/(2^2 +1)² dz from 0 to infinity, we can use the comparison test.

First, note that (1-z) is bounded between 0 and 1, so we can compare it to the integral of 4/(2² +1)² dz from 0 to infinity, which is convergent since it is a constant times the convergent p-series with p=2.

Therefore, by the comparison test, the original integral is also convergent. To evaluate it, we can use partial fractions:

4(1-z)/(2² +1)^2 = A/(2+i)² + B/(2-i)²

Solving for A and B, we get A = (1+i)/5 and B = (1-i)/5.

Then, the integral becomes:

∫ 4(1-z)/(2² +1)² dz = A ∫ 1/(2+i)² dz + B ∫ 1/(2-i)² dz

= (1+i)/5 [-1/(2+i)] + (1-i)/5 [-1/(2-i)] from 0 to infinity

= [(1+i)(2-i) - (1-i)(2+i)]/25(2² +1)

= 0

Therefore, the integral is convergent and evaluates to 0.

To determine if an integral is convergent or divergent, you need to look at its limits and the function you are integrating. Convergent means that the integral has a finite value, while divergent means the integral does not have a finite value.

For example, if you have an integral like this:

∫(f(x) dx) from a to b,

you need to evaluate the limits 'a' and 'b' and the function 'f(x)'. If 'a' or 'b' is infinity (∞) or the function 'f(x)' behaves such that it leads to an infinite value for the integral, it is divergent. Otherwise, it is convergent.

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The P-value is less than the significance level of 0.01, we reject the null hypothesis.

Null Hypothesis: The proportion of adults who prefer window seats when they fly is 0.5 or less.

Alternative Hypothesis: The proportion of adults who prefer window seats when they fly is greater than 0.5.

Let p be the true proportion of adults who prefer window seats when they fly.

The sample proportion of adults who prefer window seats is:

= 520/813 = 0.639

The standard error of the sample proportion is:

SE = sqrt((1-)/n) = sqrt(0.639(1-0.639)/813) = 0.022

The test statistic is:

z = ( - 0.5)/SE = (0.639 - 0.5)/0.022 = 6.32

Using a normal distribution, the P-value is P(Z > 6.32) < 0.0001.

Since the P-value is less than the significance level of 0.01, we reject the null hypothesis.

Therefore, we conclude that there is sufficient evidence to support the claim that the majority of adults prefer window seats when they fly.

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The group of friends can consist of at most 9 people, given the budget constraint and pricing can go to the amusement park.

The inequality to determine the number of people who can go to the amusement park can be written as: 38.75p + 16.25 ≤ 365.

Where p represents the number of people and the left-hand side of the inequality represents the total cost of admission and parking for p people.

The inequality is set up such that the total cost cannot exceed the given budget of $365.

To solve this inequality, we can first subtract 16.25 from both sides: 38.75p ≤ 348.75. Then, divide both sides by 38.75: p ≤ 9

To determine the maximum number of people who can go to the amusement park with a given budget,

we can write and solve an inequality based on the cost of parking and admission per person.

In this case, the inequality is 38.75p + 16.25 ≤ 365, and the solution is p ≤ 9.

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For the first question, to get the limit of the function lim (In V 4x2 + 6 - In x), we can use the property of logarithms that says ln(a) - ln(b) = ln(a/b). Applying this property to the given function, we get ln[(4x^2 + 6)/x]. Now we can simplify the expression by dividing both the numerator and the denominator by x. So we get ln(4x + 6/x), which can be rewritten as ln(4 + 6/x). Now we can take the limit as x approaches infinity. As x gets larger and larger, the 6/x term becomes smaller and smaller and approaches zero. So ln(4 + 6/x) approaches ln(4), and the final answer is A. In 2.

For the second question, to get the horizontal asymptote(s) of the function f(x) = 37€*, we can take the limit as x approaches infinity. As x gets larger and larger, the exponential term €* becomes larger and larger, approaching infinity. So the function approaches 37 times infinity, which is infinity. Therefore, there is no horizontal asymptote and the answer is D. none.
For the third question, the statement is false. The limit as x approaches infinity of 2^(ln(a)/ln(x)) is equal to infinity if a > 1 and is equal to zero if 0 < a < 1.

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Ann has failed to meet the condition called the "success-failure" condition.

In order to construct a confidence interval for the proportion (p), the sample must have at least 10 successes (planning to travel outside the state) and 10 failures (not planning to travel outside the state). In her sample of 29 students, she found 12 planning to travel (successes) and 17 not planning to travel (failures). Both numbers satisfy the success-failure condition, so she can construct the confidence interval for the proportion of students planning to travel outside the state during the coming summer.

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Answer:

C: The sample must be a random sample from the population

Step-by-step explanation:

took the test on edge

To prove that the right triangles are congruent, we need to show that they have three pairs of congruent parts (sides or angles).

Let's say that the given congruent parts are the hypotenuses and one leg of each triangle. To prove congruence, we can add one more pair of congruent parts, such as the other leg.

By the Side-Angle-Side (SAS) congruence theorem, if two triangles have two pairs of congruent sides and the included angle is also congruent, then the triangles are congruent. In this case, we have two pairs of congruent sides (the hypotenuses and one leg) and the included angle (the right angle) is congruent by definition.

Therefore, we can conclude that the two right triangles are congruent by SAS.

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The total budget of the prom, using the percentage concept, is given by = $ 4000.

Hence the correct option is (D).

Let the total budget be $ 100x.

Spending on Entertainment is 25% of the Budget.

So the spending on Entertainment = 100x*(25/100) = $ 25x.

Spending on Refreshments is 30% of the Budget.

So the spending on Refreshments = 100x*(30/100) = $ 30x.

Spending on Decorations is 45% of the Budget.

So the spending on Decorations = 100x*(45/100) = $ 45x.

It is also given that the spending on refreshments in dollar is $ 1200.

According to information,

30x = 1200

x = 1200/30

x = 40

Hence the total budget is = $100x = $ 100*40 = $ 4000.

So the correct option is (D).

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The question is incomplete. The complete question will be -

"The student council is planning for the prom. They have broken down their expenses in the graph below. If they decide they will spend $1,200 on refreshments, then what is their total budget?

Prom Budget:

Entertainment: 25%

Refreshments: 30%

Decorations: 45%

Answer choices:

A. $3,600

B. $6,000

C. $7,200

D. $4,000"

Answer:

H

Step-by-step explanation:

You take each given side and multiply them all together

18.4 x 8.8 x 11 = approx 1782

The region enclosed by y = e and y = ez has an intersection point at (1, e), and the area of the region is infinite.

To sketch the region enclosed by y = e, y = ez, and 2 = 1, and find the area of the region, follow these steps:

1. Analyze the given equations:
  - y = e (a horizontal line with a constant value e ≈ 2.718)
  - y = ez (an exponential curve)
  - 2 = 1 (this equation is false and does not provide any relevant information for sketching the region)

2. Since the equation 2 = 1 is irrelevant, we'll focus on the two remaining equations.

3. Find the intersection points between y = e and y = ez:
  Set y = e equal to y = ez and solve for x:
  e = ex
  Divide both sides by e:
  1 = x

4. Sketch the region:
  - Plot the horizontal line y = e
  - Plot the exponential curve y = ez
  - Mark the intersection point (1, e)

5. Determine the area of the region:
  The region enclosed by the two given equations is unbounded, meaning that it extends infinitely in both the positive and negative x-directions. As a result, the area of the region is infinite.

In summary, the region enclosed by y = e and y = ez has an intersection point at (1, e), and the area of the region is infinite.

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To calculate the percentage of one's monthly budget that transportation costs account for, we need to know the total amount of money spent on transportation and the total monthly budget.

Let's say, for example, that John spends $500 per month on transportation and his monthly budget is $2,000.

To calculate the percentage, we would divide the amount spent on transportation by the total monthly budget and then multiply by 100 to get the percentage. So, in this case, the calculation would be:

[tex]($500 / $2,000) x 100 = 25%[/tex]

Therefore, John's transportation costs account for 25% of his monthly budget. This is a significant portion of his budget, and if he needs to save money, he may want to consider alternative modes of transportation such as carpooling,

public transportation, or biking. It's always important to keep track of expenses and prioritize spending in order to maintain a healthy financial situation.

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Thus, approximately 33.33% of the data values are between 25 and 45.

A box-and-whisker plot, also known as a box plot, is a graphical representation of a set of data that shows the distribution of the data along a number line. The plot is composed of a box that represents the middle 50% of the data, along with two "whiskers" that represent the lowest and highest values in the data set. The box is drawn between the first and third quartiles of the data, with a line inside the box representing the median value. The distance between the first and third quartiles is known as the interquartile range (IQR), which can be used to identify outliers in the data. Box-and-whisker plots are useful for comparing the distribution of data between different groups or data sets.

Here,

To find the percentage of the data values that are between 25 and 45 on the given box-and-whisker plot, we need to find the area of the box that is between the lower quartile (Q1) and the median (Q2). From the plot, we can see that the lower quartile (Q1) is at 30, and the median (Q2) is at 40. The interquartile range (IQR), which is the distance between Q1 and Q3, is 20.

Therefore, the box extends from 30 to 40, which is a distance of 10. The total length of the plot is 30 (from 25 to 55), so the percentage of data values between 25 and 45 is:

10/30 * 100% = 33.33%

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Complete question:

The box-and-whisker plot below represents some data set. What percentage of the data values are between 25 and 45?

Answer:

Step-by-step explanation:

A fair coin means that there is a 50% probability of heads and a 50% probability of tails.

Playing the game 300 times means that Mason will approach theoretical probability.

Therefore, playing 300 times, he should expect to win 50% of the time, so 50% x 300 = 150 times.

Mason should expect to win 150 times.

If a data set is normally distributed with a mean of 27 and a standard deviation of 3. 5, the z-score for a value of 25 is -0.57.

To find the z-score for a value of 25 in a normally distributed data set with a mean of 27 and a standard deviation of 3.5, we use the formula:

z = (x - μ) / σ

where:
x = the given value (25)
μ = the mean (27)
σ = the standard deviation (3.5)

Plugging in the values, we get:

z = (25 - 27) / 3.5
z = -0.57

Rounding to the nearest hundredth, the z-score for a value of 25 is -0.57.

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The fraction is equivalent to a whole number  are 9/3, -16/8, 7/0, 0/5

A fraction can simply be described as the part of a whole variable, a whole numbers, or a whole element.

In mathematics, there are different types of fractions. These fractions are listed thus;

From the information given, we have that;

Equivalent expressions or fractions are fractions with the same solutions

Then, we have;

9/3

Divide the values

3

-16/8

-2

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If the interest is compounded daily, the interest rate is 4.5%.

To determine the interest rate, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:

A = the final amount, $790

P = the principal, $350

r = the interest rate

n = the number of times the interest is compounded per year, in this case daily (n = 365)

t = the time period in years, 18

Substituting the values :

790 = 350(1 + r/365)³⁶⁵ˣ¹⁸

790 = 350(1 + r/365)⁶⁵⁷⁰

790/350 = (1 + r/365)⁶⁵⁷⁰

ln(790/350) = 6570 * ln (1 + r/365)

Using the property of logarithms that ln(1 + x) ~ x for small values of x, we can approximate the right-hand side as:

[ln(790/350)]/6570 = r/365

r = 0.045

r = 4.5%

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