Write an equation you can use to solve for x. I need 1-7 answered. I don't understand this

Answer:

Step-by-step explanation:

1. the initial population at t=0 is 1

2. 16

The two numbers are 4 and 1.

To solve the problem, we will use algebraic equations.

We will call 2 numbers x and y. So, we know that:

------ x + y = 5 (equation 1)

------ xy = 20 (equation 2)

We will solve for y in terms of x:

y = 5 - x

We will substitute for y into equation 2 and simplify:

x(5 - x) = 20

5x - x^2 = 20

x^2 - 5x + 20 = 0

As a quadratic equation which will be solved using the quadratic formula, the solutions are x = 4 and x = 1. We can check that these solutions satisfy both equation 1 and equation 2.

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[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} h=0\\ k=0\\ \end{cases}\implies y=a(~~x-0~~)^2 + 0\hspace{4em}\textit{we also know that} \begin{cases} x=3\\ y=18 \end{cases} \\\\\\ 18=a(3-0)^2+0\implies 18=9a\implies \cfrac{18}{9}=a\implies 2=a \\\\\\ y=2(~~x-0~~)^2 + 0\implies \boxed{y=2x^2}[/tex]

Step-by-step explanation:

Draw a rectangle.  If the length is 3 inches longer than its width, we can write the width as "w" and the length as the width + 3

Area is (width)(Length) = (width)(width+3)

    W

 ----------

 |         |

 |         |

 |          |  L = w+3

 |         |

 |          |

 -----------

A = (w+3)(w)

A = w2 + 3w = 108.

(Problem states that area is 108 sq in)

Need to solve this quadratic equation

w2 + 3y - 108 = 0

Factor:

(w - 9) (w + 12) = 0

So

w - 9 = 0.    or.    w + 12 = 0

Solve these and get

w = 9. or. w = -12

Only one that makes sense in real life is the poitive one.

So the dimensions are

Width = 9 inches

Length = 12 inches

hope this helped-nia.

The first five coefficients are explained.

Given is power series, f(x) = eˣ about x = 4 as [tex]\sum_{\infty}^{n=0}C_n}(x+4)^n[/tex]

f(x) = eˣ

a = 4,

The general form of a Taylor series is:

f(x) = [tex]\sum_{n=0}^{\infty}\frac{f'(a)}{n!} (x-a)^n[/tex]

Note that since the function is a basic exponential function, its derivative is:

f'(x) = eˣ

That is, the function is the same for whatever order of differentiation. So, let us substitute our values here,

f(x) = [tex]\sum_{n=0}^{\infty}\frac{e^4}{n!} (x-4)^n[/tex]

The general expression for the coefficients is: [tex]C_n = \frac{e^4}{n!}[/tex]

The first coefficient is: [tex]C_0 = e^4[/tex]

The second coefficient is: [tex]C_1 = e^4[/tex]

The third coefficient is: [tex]C_2 = 1/2e^4[/tex]

The fourth coefficient is: [tex]C_3 = 1/6e^4[/tex]

And lastly,

[tex]C_4 = 1/24e^4[/tex]

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The value of x is, x = 6 ft

Now, We can formulate;

Area of the polygon = area of the square + 2(area of the triangle)

Here, We have;

Area of the polygon = 176 ft²

So, Area of the square = length × width

                                   = 16 × 8

                                  = 128

And, Area of the two triangles = 2( 1/2 x base x height)

                                               = 2(1/2 × x × 8)

                                               = 8x

Now, Plug in the above values into the equation for area of the polygon.

Thus: We get;

176 = 128 + 8x

Subtract 128 from each side

176 - 128 = 8x

48 = 8x

Divide both sides by 8

6 = x

x = 6 ft

Thus, The value of x is, x = 6 ft

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We have shown that the solution to the differential equation dp/dt = -0.1P is P = 495e^(1.1t).

We have,

To show that the solution to the differential equation dp/dt = -0.1P is

P = 495e^(1.1t),

we can use separation of variables and integration.

Starting with the differential equation:

dp/dt = -0.1P

We can separate the variables by dividing both sides by P and multiplying both sides by dt:

dp/P = -0.1 dt

Integrate both sides:

∫ dp/P = -0.1 ∫ dt

Integrating the left-hand sid.

ln|P| = -0.1t + C

where C is the constant of integration.

To solve for C, we can use an initial condition.

Suppose that when t = 0, P = P0.

Then we have:

ln|P0| = -0.1(0) + C

ln|P0| = C

Substituting this value of C back into the equation for P.

ln|P| = -0.1t + ln|P0|

ln|P/P0| = -0.1t

Taking the exponential of both sides.

P/P0 = e^(-0.1t)

Multiplying both sides by P0.

P = P0 e^(-0.1t)

We can substitute P0 = 495 (since P(0) = 495 is given in the solution) and e^(-0.1t) = e^(1.1t)/e^t.

P = 495 e^(1.1t)/e^t

Simplifying the expression by combining the exponentials.

P = 495 e^(0.1t)

which is the same as the given solution.

Therefore,

We have shown that the solution to the differential equation dp/dt = -0.1P is P = 495e^(1.1t).

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Answer:

Yeeeaaa, no.

Hope this helps!

Step-by-step explanation:

( x, y )

Plug the numbers of the ordered pair into the equation: y = 6x

3 = 6 × ( 0 )

3 = 0

Three does not equal zero...

3 [tex]\neq[/tex] 0

(a) The range for the graduates is 86760 hours.

(c) The graduates had the greater median number of hours.

(a) The range is the difference between the maximum and minimum values in a set of data. We are given the following data:

Graduates: 9641 hours, 6655432 hours, 93310 hours, and 92501 hours

Non-graduates: 2138 hours, 3 hours, 4 hours, and 13445559 hours

The range for the graduates is 9641 - 92501 = 86760 hours.

The range for the non-graduates is 2138 - 13445559 = 13443421 hours.

(c) To find the median, we need to arrange the data in order from smallest to largest and find the middle value. If there are an even number of data points, we take the average of the two middle values.

Graduates: 9641 hours, 93310 hours, 92501 hours, 6655432 hours

The median is the average of 93310 hours and 92501 hours, which is (93310 + 92501)/2 = 92905.5 hours.

Non-graduates: 2138 hours, 3 hours, 4 hours, 13445559 hours

The median is the average of 3 hours and 4 hours, which is (3 + 4)/2 = 3.5 hours.

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Answer:

Many buildings and structures around us involve transformed shapes in their design. For example, a skyscraper may have a rectangular base that is transformed into a triangular shape as it reaches higher levels. This transformation is achieved by using a technique called tapering, where the building's width gradually decreases as it goes up, resulting in a triangular shape at the top.

Another common transformation is the use of rotation, which is seen in the design of many cylindrical structures like water towers or chimneys. The cylinder is rotated around its axis to create a three-dimensional shape.

These transformed shapes contribute to the design of the object in many ways. For instance, the triangular shape of a skyscraper's top helps to reduce wind resistance and improve stability. Tapering also allows more sunlight to reach street level and reduces the impact of shadows on the surrounding area. In the case of cylindrical structures, rotation can provide structural stability while minimizing the amount of material used in the construction.

Overall, the use of transformed shapes in building and structure design helps to achieve specific aesthetic and functional goals, from stability to energy efficiency.

Step-by-step explanation:

Answer:

The Empire State Building is a skyscraper in Midtown Manhattan, New York City, on Fifth Avenue between West 33rd and 34th Streets. It has a roof height of 1,250 feet (381 m), and with its antenna spire included, it stands a total of 1,454 feet (443.2 m) high. Its name is derived from the nickname for New York, the Empire State.

The Empire State Building is an example of a transformed shape. The original shape is a square, but the architects transformed it into a triangle by adding a spire to the top. The spire adds height and visual interest to the building. It also helps to make the building more stable.

The use of transformed shapes in the design of the Empire State Building contributes to its overall aesthetic appeal. The building is both visually striking and structurally sound. It is a testament to the skill and ingenuity of the architects who designed it.

Here are some other examples of transformed shapes in buildings and structures:

* The Parthenon in Athens, Greece, is a rectangular building with a triangular pediment at each end. The pediments are decorated with sculptures that depict scenes from Greek mythology.

* The Eiffel Tower in Paris, France, is a wrought iron lattice tower that was built for the 1889 World's Fair. The tower is a transformed shape of a regular hexagon.

* The Gateway Arch in St. Louis, Missouri, is a stainless steel arch that spans the Mississippi River. The arch is a transformed shape of a catenary curve.

These are just a few examples of the many ways that transformed shapes are used in the design of buildings and structures. Transformed shapes can be used to add visual interest, create a sense of movement, or simply to make a building more structurally sound.

Step-by-step explanation:

He covered a distance of 5 miles for 5 days of the total days of training. The total distance he covered = 6 miles.

The total number of days Anthony used for training = 8 days.

The number of days he covered 1/4 mile = 2days

The number of days he covered 1/2 mile = 1 day

The number of days he covered 1 mile = 5 days.

Therefore that total distance that he used for the training = 2(1/4)+1(1/2)+5(1)

= 0.5+0.5+5

= 6 miles.

The number of days he covered the highest distance would be for 5 days.

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Answer:

The answer is **FD = 1.52**.

Since triangle ABC ~ triangle DEF, we know that the ratio of their corresponding sides is equal. So, we have:

```

AB/DE = AC/DF = BC/EF

```

We are given that AB = 11, DE = 2.2, and AC = 7.6. Substituting these values into the first equation, we get:

```

11/2.2 = 7.6/DF

```

Cross multiplying, we get:

```

11 * DF = 2.2 * 7.6

```

```

DF = (2.2 * 7.6) / 11

```

```

DF = 1.52

```

Step-by-step explanation:

The coordinates of the vertices for the image if the preimage is translated 3 units up is : A′(−3, 6), B′(0, 10), C′(−3, 3).

The correct option is (B)

If we are given the translated image of something, we need to work backwards given the translation rules. For example, if we have a general translation of (x +a, y +b), then to find pre-translation coordinates, we do: (x−a, y−b).

We have the Triangle ABC has vertices at A(−3, 3), B(0, 7), and C(−3, 0).

Now, let's consider the translation that moves the triangle 3 units up. This means that we need to add 3 to the y-coordinate of each vertex to get the coordinates of the image.

So, the coordinates of the vertices of the image triangle, let's call it A'B'C', will be:

A' = (-3, 3+3) = (-3, 6)

B' = (0, 7+3) = (0, 10)

C' = (-3, 0+3) = (-3, 3)

The coordinates of the vertices for the image if the preimage is translated 3 units up is : A′(−3, 6), B′(0, 10), C′(−3, 3)

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Answer:c

Step-by-step explanation:

Answer: B 1585

took the test

Answer:

119

Step-by-step explanation:

Firstly, we need to solve the expression inside the parentheses, which is 23-11. This gives us 12. Then we need to carry out the division to get 48 divided by 12, which is 4. We can then multiply 4 by 14 to get 56. Finally, we add 56 to 63 which gives us the answer of 119. Therefore, the solution to the expression 63+48÷(23-11)×14 is 119.

a) The range of chest measurements contains 68% which falls closest to the mean is between 38 inches and 42 inches

b) The chest measurements for the 2.5% of the men with the smallest chest measurements in the population to be approximately 36 inches

Given data ,

The Empirical rule, also known as the 68-95-99.7 rule, is a statistical guideline that describes the approximate distribution of data in a normal distribution.

Approximately 68% of the data falls within one standard deviation (σ) of the mean (μ)

Approximately 95% of the data falls within two standard deviations of the mean (μ ± 2σ)

Approximately 99.7% of the data falls within three standard deviations of the mean (μ ± 3σ)

It would be within one standard deviation of the mean for the range of chest measures that accounts for 68% of the data and is closest to the mean. Since the standard deviation is 2 inches and the mean chest measurement is 40 inches, we can get the range as follows:

Mean - 1 standard deviation = 40 - 2 = 38 inches

Mean + 1 standard deviation = 40 + 2 = 42 inches

b)

We may look at the bottom end of the distribution to obtain the chest dimensions for the 2.5% of males with the smallest chest measurements in the population. The empirical rule states that 2.5% or less of the data goes outside of two standard deviations of the mean. So, using the following formula, we can get the chest size of the 2.5% of men:

Mean - 2 standard deviations = 40 - 2(2) = 36 inches

Hence , the standard deviations are solved

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Answer:

w(w + 4) = 117

w^2 + 4w = 117

w^2 + 4w - 117 = 0

(w - 9)(w + 13) = 0

w = 9 meters

The width of the rectangle is 9 meters, and the length of the rectangle is 13 meters.

By using the substitution method, the value for (x,y) = (-2, 2)

The substitution method for solving a system of algebra equations is a process where by we make a variable (say variable x) the subject of the formula and substitute it into the second equation to solve for the other variable.

In essence, from the given system of equations; let's make x the subject of the formula in the first equation.

5x + 3y = -4

5x = -4 - 3y

Divide both sides by 5;

x = -4/5 - 3y/5

Now, we are going to substitute this value for x into the second equation. The second equation says:

y - 2x = 6

y - 2(-4/5 - (3y/5)) = 6

By solving for y;

y = 2

Now, let's replace the value of y with any of the given equation (2);

y - 2x = 6

2 - 2x = 6

-2x = 6 - 2

-2x = 4

Divide both sides by -2

-2x/-2 = 4/ -2

x = -2

Therefore, we can conclude that by using the substitution method, the value for (x,y) = (-2, 2)

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well, first of all, you don't want to go into the oven, is too hot and you'll get burned, so you may not want to do that.

now, if we start to bake something at 3:40pm and it requires 35 minutes, it'll be done by 3:40 + 35, or 3pm and 40 + 35 minutes, or 3pm plus 75 minutes or 3pm plus 60 + 15 minutes, but since 60 minutes is 1hr, that'd be 3pm plus 1hr plus 15 minutes, 4:15pm.

The Taylor polynomial of degree 3 for sin(x) for x near 0 is,

sin (x) = x - 1/6 x³

The ratio is sin (x) / x = 1 - 1/6 x².

Limit is 1.

Given function is sin(x).

We have to find the Taylor Polynomial for sin (x).

We know that,

f(x) = sin(x), so f(0) = sin (0) = 0

f'(x) = cos (x), so f'(0) = cos (0) = 1

f''(x) = -sin (x), so f''(0) = sin (0) = 0

f³(x) = -cos (x), so f³(0) = -cos(0) = -1

Taylor polynomial is,

sin (x) = {[f(0) (x - k)⁰] / 0!} + {[f'(0) (x - k)¹] / 1!} + {[f''(0) (x - k)²] / 2!} + {[f³(0) (x - k)³] / 3!}

Here c = 0.

sin (x) = 0 + x + 0 + (-x³/6)

sin (x) = x - 1/6 x³

The ratio,

sin (x) / x = (x - 1/6 x³) / x = 1 - 1/6 x²

When x tends to 0 in the expression, 1 - 1/6 x², the value tends to 1 - 0 = 1.

Hence the required Taylor polynomial is sin (x) = x - 1/6 x³.

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Answer:

  30°

Step-by-step explanation:

You want the measure of angle AEF in regular hexagon ABCDEF.

The interior angles of a regular hexagon are ...

  180° -(360°/6) = 120°

Angle AEF is 90° less than this, so is ...

  angle AEF = 120° -90°

  angle AEF = 30°

__

Additional comment

Angle AEF is also a base angle of isosceles triangle AEF, which has angle F = 120°. The base angles are (180° -120°)/2 = 30°.

Answer: so if it cosst 25,000,000 dollars to market a car and they sell it for 30,000 dollars they would need to sell 167 cars to get 5.1 million dollars or 166 for 5.0 million

Answer:

487.20

Step-by-step explanation:

1. find the area of a rectangle ( length x width)

14ft x 12ft = 168ft²

2. Multiply the number of feet needed to becovered by the price of one foot of paper

168ft x 2.90 = 487.20

Answer:

1km:100decameter(dam)

Step-by-step explanation:

so 35dam:0.35km

and 35dam:0.00035m

A line of reflection, also known as a line of symmetry, is a line that divides a figure into two congruent parts that are mirror images of each other.

When a figure is reflected across a line of reflection, every point on one side of the line has a corresponding point on the other side of the line that is equidistant from the line.

To determine the line of reflection for the given graph:

- Reflection across the x-axis: The line of reflection is the x-axis.

- Reflection across x = -6: The line of reflection is a vertical line passing through x = -6.

- Reflection across the y-axis: The line of reflection is the y-axis.

- Reflection across y = -6: The line of reflection is a horizontal line passing through y = -6.

Thus, the line of reflection is the perpendicular bisector of every segment joining a point to its image after reflection.

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[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{24}\\ a=\stackrel{adjacent}{22}\\ o=\stackrel{opposite}{MN} \end{cases} \\\\\\ MN=\sqrt{ 24^2 - 22^2} \implies MN=\sqrt{ 92 }\implies MN=2\sqrt{23}[/tex]

The volume of the cone with a diameter of 4ft and height 12ft is approximatelly 50.3 ft³

A cone is simply a 3-dimensional geometric shape with a flat base and a curved surface pointed towards the top.

The volume of a cone is expressed as;

V = (1/3)πr²h

The figure in the image is a cone.

Diameter of the base of the cone d = 4ft

Radius r = diameter/2 = 4/2 = 2ft

Height h = 12ft

Plug the given values into the above formula and solbr for the volume.

V = (1/3)πr²h

V = (1/3) × π × r² × h

V = (1/3) × π × (2 ft )² × 12ft

V = 50.3 ft³

Therefore, the volume is 50.3 ft³.

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Answer:

Step-by-step explanation:

45

Answer: first do multiplcation for each part then add everythink to find total volume

Step-by-step explanation: