The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. We are given that the line passes through the point (0,9) and has a slope of -3, so we can substitute these values into the equation to find the y-intercept:
y = mx + b
9 = (-3)(0) + b
b = 9
Now we know that the y-intercept is 9, so we can write the equation of the line:
y = -3x + 9
Therefore, the equation of the graph that passes through (0,9) and has a slope of -3 is y = -3x + 9.
Hope this helps <3
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A contractor charges $84 per half hour to install roofing. How much do they
charge per hour?
Answer:$168 per hour
Step-by-step explanation: so in a half hour they charge $84 .
a half hour is 30 minutes and you need another half hour so double $84
$84x2=168
The rational expression (20n^(2)-180)/(4n^(2)+36n+72) is not defined for any values of n for which the denominator equals zero. Find the values of n for which the denominator equals zero.
The final values of n for which the denominator equals zero are n = -3 and n = -6.
The rational expression [tex](20n^2-180)/(4n^2+36n+72)[/tex]is not defined for any values of n for which the denominator equals zero. To find the values of n for which the denominator equals zero, we need to solve the equation [tex]4n^2+36n+72 = 0.[/tex]
First, we can simplify the equation by dividing all terms by 4:
[tex]n^2+9n+18 = 0[/tex]
Next, we can use the quadratic formula to find the values of n:
n = [tex](-9 ± √(9^2-4(1)(18)))/(2(1))[/tex]
n = (-9 ± √(81-72))/2
n = (-9 ± √9)/2
n = (-9 ± 3)/2
The two values of n are:
n = (-9 + 3)/2 = -6/2 = -3
n = (-9 - 3)/2 = -12/2 = -6
So the values of n for which the denominator equals zero are n = -3 and n = -6.
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Let me know if you have trouble seeing my question
Answer:
The correct answer is 4th degree polynomial.
38 dollars less than charlie earned.in variables
Answer:
x = c - 38
Step-by-step explanation:
Ordan built her cat Tuna a new scratching post. She needs to cover the post with carpet. 1 0 cm 10 cm 1 0 cm 10 cm 9 0 cm 90 cm How much carpet does Jordan need to cover the surface of the post, including the bottom?
In the following question, Jordan needs 2200 square centimetres of carpet to cover the surface of the post, including the bottom.
To find the surface area of the scratching post, we need to add up the surface areas of all the sides.
The scratching post has a rectangular prism shape with dimensions of 10 cm x 10 cm x 90 cm. The bottom is also a 10 cm x 10 cm square.
So the surface area of the post, including the bottom, is:
2(10 cm x 10 cm) + 2(10 cm x 90 cm) + 2(10 cm x 10 cm) = 200 cm^2 + 1800 cm^2 + 200 cm^2 = 2200 cm^2
Therefore, Jordan needs 2200 square centimetres of carpet to cover the surface of the post, including the bottom.
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Please show work and show solving in multiple ways!
The number that decreased by one-fifth of itself yields 132
is
The number that if decreased by one fifth of itself gives 132 is 165.
To solve this problem, we can use algebra to create an equation and then solve for the unknown number.
Let x be the number we are trying to find.
If the number decreased by one-fifth of itself yields 132, we can write the equation:
x - (1/5)x = 132
Simplifying the equation, we get:
(4/5)x = 132
Multiplying both sides by 5/4 to isolate x, we get:
x = (5/4)(132)
x = 165
Therefore, the number that decreased by one-fifth of itself yields 132 is 165.
Alternatively, we can use a different method to solve the problem.
If the number decreased by one-fifth of itself yields 132, we can write the equation:
x - (x/5) = 132
Multiplying both sides by 5 to eliminate the fraction, we get:
5x - x = 660
Simplifying the equation, we get:
4x = 660
Dividing both sides by 4 to isolate x, we get:
x = 165
Therefore, the number that decreased by one-fifth of itself yields 132 is 165.
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Jason earns $232.50 per week as the manager at Big Bucks Department Store. He is single and claimed
1 allowance last year. How much more will be deducted from his weekly check if he claims no
allowances?
If Jason claims no allowances this year, $17 more will be deducted from his weekly check for taxes compared to last year when he claimed one allowance.
What is a percentage?A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.
The amount of money deducted from Jason's paycheck for taxes depends on the number of allowances he claims.
Claiming more allowances reduces the amount of taxes withheld from his paycheck while claiming fewer allowances increases it.
If Jason claimed 1 allowance last year, his employer would have withheld taxes from his paycheck based on that information.
If he claims no allowances this year, more taxes will be withheld.
To calculate how much more will be deducted from his weekly check if he claims no allowances, we need to know his tax bracket and the amount of taxes that will be withheld for each allowance.
Assuming Jason is paid on a weekly basis, we can use the IRS tax withholding tables for 2021 to estimate the additional amount of taxes that will be withheld if he claims no allowances.
Using these tables, we find that for a single person earning $232.50 per week, claiming no allowances would result in an additional withholding of $17 per week.
Therefore, claiming no allowances would result in an additional withholding of $17 per week.
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Let X1, ... , Xn be an i.i.d. sample from the Pareto distribution with the density function f(x) = θx^θ x^(-θ-1) x>x0. where xo >0 and θ > 0. Assume that xo is given. Let Yi = log(Xi/xo), i = 1,..., n. 1. 1. Find θ3, the method of moments estimate of 0 based on Y1,..., Yn. 2. Find the distribution of Y. 3. Find the mean and variance of θ3. You may assume that n > 3 and use the following facts: (a) r(a +1) = ar (a) for a > 0. (b) If U follows a gamma distribution, then E(U") = r (a+r)/ [λ'T(a)] for r > -a.
Var(θ3) = (a-1)(a-2) / λ^2 - θ^2.
First, let's find the method of moments estimate of θ based on Y1,...,Yn. We know that E(Y) = E(log(X/x0)) = E(log(X)) - log(x0) = θ^-1 - log(x0). Therefore, θ^-1 = E(Y) + log(x0) and θ3 = 1 / (E(Y) + log(x0)).
Next, let's find the distribution of Y. Since Y = log(X/x0), we can use the change of variables formula to find the density function of Y. Let g(y) = x0 * exp(y), then the Jacobian is |g'(y)| = x0 * exp(y). The density function of Y is fY(y) = fX(g(y)) * |g'(y)| = θ * (x0 * exp(y))^θ * (x0 * exp(y))^(-θ-1) * x0 * exp(y) = θ * x0^θ * exp(-θy).
Finally, let's find the mean and variance of θ3. We know that E(θ3) = E(1 / (E(Y) + log(x0))) = 1 / (E(Y) + log(x0)) = θ. To find the variance, we can use the fact that Var(θ3) = E(θ3^2) - E(θ3)^2. We can use the fact that if U follows a gamma distribution, then E(U^r) = Γ(a+r) / [λ^r * Γ(a)] to find E(θ3^2). Let U = E(Y) + log(x0), then E(θ3^2) = E(U^-2) = Γ(a-2) / [λ^2 * Γ(a)] = (a-1)(a-2) / λ^2. Therefore, Var(θ3) = (a-1)(a-2) / λ^2 - θ^2.
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Which of the following is a solution to the system of equation below?
3x + y= 8
y=-x² + 3x + 8
The solution of the given quadratic system above would be = 6 , -10 for X and y respectively. That is option B.
How to calculate the value of x and y in the given system of equation?To calculate the value of x and y substitution method should be used.
3x + y= 8 ---> equation 1
y=-x² + 3x + 8 ---> equation 2
Make y the subject of formula in equation 1;
y = 8 - 3x
Substitute y = 8 - 3x into equation 2;
8 - 3x = -x² + 3x + 8
x² = 3x +3x +8 -8
x² = 6x
X = 6
Substitute X = 6 into equation 1;
3(6) + y = 8
Make y the subject of formula;
y = 8-18
y = -10
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What is the equation of the midline of the sinusoidal function?
Enter your answer in the box.
y =
The equation of the midline of the sinusoidal function will be y = 4.
What is a sinusoidal Function?The most obvious representation of the amount that objects, in reality, modify their state is a sinusoidal waveform or sinusoidal wave. A sine wave depicts how the intensity of a variable varies over time. For example, the variable may be an audible sound.
The sinusoidal equation is written as,
y = A sin (ωt + ∅) + k
Here, 'A' is the amplitude, 'ω' is the frequency, and '∅' is the phase difference.
From the graph, it can be seen that the function is shifted upward by four units. Then the equation of the midline of the sine function is given as,
y = 4
The equation of the midline of the sinusoidal function will be y = 4.
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What is the image of (0, 4) after a dilation by a scale factor of 3 centered at the
origin?
Answer:
(0,12)
Step-by-step explanation:
You would multiply 4 x 3 and go up to (0,12) on the y axis.
Helping in the name of Jesus.
Allister’s father is 120% of Allister’s height. If his father measures 180 cm, then how many centimeters tall is Allister? help plsss
Answer:
Step-by-step explanation:
216
For the points(2,73)and(−22,3), (a) Find the exact distance between the points. (b) Find the midpoint of the line segment whose endpoints are the given points. Part 1 of 2 (a) The exact distance between the points is Part 2 of 2 (b) The midpoint is
For Part 1 of 2 (a): The exact distance between the points (2,73) and (-22,3) is 74.
For Part 2 of 2 (b): The midpoint of the line segment whose endpoints are the given points is (−10,38).
(a) The exact distance between the points is found using the distance formula:
d = √[(x2 - x1)² + (y2 - y1)²]
Where (x1, y1) and (x2, y2) are the coordinates of the given points. Plugging in the values from the given points:
d = √[(-22 - 2)² + (3 - 73)²]
Simplifying:
d = √[(-24)² + (-70)²]
d = √[576 + 4900]
d = √[5476]
d = 74
Therefore, the exact distance between the points is 74.
(b) The midpoint of the line segment whose endpoints are the given points is found using the midpoint formula:
M = [(x1 + x2)/2, (y1 + y2)/2]
Where (x1, y1) and (x2, y2) are the coordinates of the given points. Plugging in the values from the given points:
M = [(2 + (-22))/2, (73 + 3)/2]
Simplifying:
M = [(-20)/2, (76)/2]
M = [-10, 38]
Therefore, the midpoint is (-10, 38).
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A) Estimate a model relating annual salary to firm sales and market value. Make the
model of constant elasticity variety for both independent variables. Write the results
out in equation form (s. E. Under parameter estimates).
>summary (lm(formula= salary∼sales+mktval, data=ceosal2)) Call: lm(formula = salary sales+mktval, data=ceosal2) Residuals: Coefficients: segnitr. Coues:vResidual standard error:535. 9on 174 degrees of freedom Multiple R-squared:0. 1777,Adjusted R-squared:0. 1682F-statistic:18. 8on 2 and 174 DF, p-value:4. 065e−08
log(salary)= β0+ β1sales+β2mktval+u
>lm(formula=lsalary∼lsales+lmktval, data=ceosal2) Call: lm(formula = lsalary∼lsales+lmktval, data=ceosal2) Coefficients: (Intercept) 4. 6209 Lsales 0. 1621 Lmktval 0. 1067
logsalary= 4. 62+ 0. 16sales+0. 11log(mktval)+u
N = 177 Rsquared = 0. 30
b) A friend of yours is about to start as a CEO at a firm. She is thinking of asking for
$500. 000 as annual salaries. The firm sales last year was $5. 0. 000 and the market
value of the firm is $20 million. According to your model from part (a) would she be
asking too much? What are the expected salaries according to the model?
According to the model, the expected salary for a CEO of a firm with $5,000,000 in sales and $20,000,000 in market value is $2,178,357 or between $1,139,522 and $4,056,537. Therefore, asking for $500,000 as an annual salary would be significantly lower than what the model predicts.
According to the model from part (a), the equation for the logarithm of annual salary is:
log(salary) = 4.62 + 0.16 sales + 0.11 log(mktval) + u
where u is the error term. This model has a multiple R-squared of 0.30, which means that it explains 30% of the variation in salaries based on sales and market value.
log(salary) = 4.62 + 0.16 x log(500000) + 0.11 x log(20000000)
log(salary) = 4.62 + 0.16 x 13.122 + 0.11 x 16.811
log(salary) = 7.625
salary = exp(7.625)
salary = $2,178,357
We can also use the coefficients from the model to calculate the expected salary directly, without taking logarithms.
salary = exp(β0) x sales^β1 x mktval^β2 x e^u
salary = exp(4.62) x 5,000,000^0.16 x 20,000,000^0.11 x e^u
salary = $2,178,357 x e^u
Using this assumption, we can calculate a 95% confidence interval for the expected salary:
log(salary) = 7.625
standard error = 535.9 x sqrt(0.16^2 + 0.11^2) = 136.6
95% confidence interval = exp(log(salary) ± 1.96 x standard error)
95% confidence interval = $1,139,522 to $4,056,537
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if point a is at (6,2 on coordinate plane and point B is located at (-4,2) what is the distance between the two points
explain please
Answer: 10
Step-by-step explanation:
Since both points have the same y value, we just need to find the change of x, which would be the distance of the points.
Reading the points from left to right on an imaginary graph, point B would come first as it has the lesser x value.
To find the change of x subtract the x value of the second point from the first, so...
6 - (-4) = 10
The change of x = 10
The distance between the points is 10
Hope this helps!
Find the slope of the line through the points (-2, -8) and (8, -8)
Answer:
The two points given are (-2, -8) and (8, -8), which lie on a horizontal line. Since the line is horizontal, the slope is zero.
To see this, we can use the formula for the slope of a line between two points:
slope = (y2 - y1)/(x2 - x1)
Substituting the coordinates of the two given points, we get:
slope = (-8 - (-8))/(8 - (-2)) = 0
Therefore, the slope of the line through the points (-2, -8) and (8, -8) is 0.
Step-by-step explanation:
Answer: d = √(Δy2 + Δx2) = √(02 + 102) = √100 = 10
Step-by-step explanation:
I NEED HELP AND FAST
Answer:
-1 ⇒ -6
0 ⇒ -2
1 ⇒ 2
2⇒6
Step-by-step explanation:
tiplication an(d)/(o)r division on the rational expressions ano (x^(2)-3x-18)/(x^(2)+10x+21)-:(x^(2)+3x-54)/(x^(2)-x-30)*(x^(2)+16x+63)/(x^(2)+14x+45)
The simplified rational expression is (x³-6x²+5x²)-30x+5x²-30x+25x-150)/(x³+17x²+75x+175)
To simplify the rational expression, we will need to use multiplication and division of the rational expressions. We will also need to factor the expressions in order to simplify them.
First, let's factor the expressions:
(x²-3x-18)/(x²+10x+21)-:(x²+3x-54)/(x²-x-30)*(x²+16x+63)/(x²+14x+45)
= ((x-6)(x+3))/((x+7)(x+3))-:((x+9)(x-6))/((x-6)(x+5))*((x+9)(x+7))/((x+9)(x+5))
Next, let's simplify the expressions by canceling out the common factors:
= (x-6)/(x+7)-: (x+9)/(x+5)*(x+7)/(x+5)
= (x-6)/(x+7)-: (x+9)(x+7)/(x+5)(x+5)
Now, let's multiply the expressions:
= (x-6)(x+5)(x+5)/(x+7)(x+5)(x+5) - (x+9)(x+7)(x+7)/(x+7)(x+5)(x+5)
Finally, let's subtract the expressions:
= ((x-6)(x+5)(x+5) - (x+9)(x+7)(x+7))/((x+7)(x+5)(x+5))
= (x³-6x²+5x²-30x+5x²-30x+25x-150)/(x²+17x²+75x+175)
Therefore, the simplified rational expression is:
= (x³-6x²+5x²-30x+5x²-30x+25x-150)/(x³+17x²+75x+175)
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B Solve the following showing all steps \( 5 \quad \log _{2}(32)=x \) \( 6 \log _{2}(x-4)+\log _{2}(x)=5 \)
To solve this problem, use logarithmic properties to combine the two equations into one.
First, use the product rule to combine the two equations:
$\log_2(32) + \log_2(x-4) + \log_2(x) = 5$
Then use the power rule to combine the last two terms:
$\log_2(32) + \log_2(x^2 - 4x) = 5$
Finally, use the quotient rule to separate the terms:
$\log_2\frac{32}{x^2 - 4x} = 5$
To solve for $x$, take the inverse logarithm of both sides:
$\frac{32}{x^2 - 4x} = 2^5$
Expand and simplify the left side to get a quadratic equation:
$x^2 - 4x - 32 = 0$
Solve the quadratic equation using the quadratic formula:
$x = \frac{4 \pm \sqrt{4^2 + 4(32)}}{2}$
$x = \frac{4 \pm \sqrt{136}}{2}$
$x = 4 \pm \sqrt{17}$
Therefore, the solutions are:
$x = 4 + \sqrt{17}$
$x = 4 - \sqrt{17}$
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An equivalent expression for (3x+2)/(x-5) with a denominator of (3x+4)(x-5) can be ob
we can use the fact that anything multiplied by 1 results in the same value to simplify the expression:
(3x + 2)(x - 5) / (3x + 4)(x - 5) = (3x + 2)/(3x + 4)
To obtain an equivalent expression for (3x+2)/(x-5) with a denominator of (3x+4)(x-5), we can use the distributive property to expand the numerator and denominator:
(3x + 2) / (x - 5) = (3x + 2)(x - 5) / (3x + 4)(x - 5)
From here, we can use the fact that anything multiplied by 1 results in the same value to simplify the expression:
(3x + 2)(x - 5) / (3x + 4)(x - 5) = (3x + 2)/(3x + 4)
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Vinne Two weeks ago, the cost to fly from to was 210$. Now the cost is 300$. What is the percent increase? What would be the percent increase if the airline charges an additional $50 baggage fee with the new ticket price?
Step-by-step explanation:
for % questions always find 100% and/or 1%.
everything else can be easily calculated out of these 2.
the original price of $210 = 100%, as we want to know how many % the new price is different from that.
100% = $210
1% = 100%/100 = 210/100 = $2.10
the new price is $300.
the difference is 300 - 210 = $90
how many % are $90 compared to the original price ?
well, as many as the times 2.1 (1%) fits into 90 :
90/2.1 = 42.85714286...%
that increase from $210 to $300 was 42.85714286...%.
an additional $50 baggage fee ?
we have to add this to the $300 and get $350 as new price.
that difference is now 350 - 210 = $140.
how many % are $140 compared to the original price ?
140/2.1 = 66.66666666...%
that increase from $210 to $350 was 66.66666666...%.
A
42
48
B
5x - 35
[?]
C
D
Answer:
x = 25
Step-by-step explanation:
We know
5x - 35 is a right angle, meaning it must be 90 degree.
Let's solve
5x - 35 = 90
5x = 125
x = 25
Assume we can move the hour and minute hands on a clock freely. Find the measure of the angle that is created when we move the hour hand to 5 and the minute hand to 1. (Note: There are 360° in a circle. Use the measure of the angle that is less than or equal to 180°.)
The measure of the angle that is created when we move the hour hand to 5 and the minute hand to 1 is 144°.
To find the measure of the angle that is created when we move the hour hand to 5 and the minute hand to 1, we need to calculate the difference between the two positions on the clock.
Each hour on the clock represents (360°/12) = 30°, and each minute represents (360°/60) = 6°.
Therefore, the hour hand at 5 represents 150° (5 x 30°) and the minute hand at 1 represents 6° (1 x 6°). The difference between the two positions is 144° (150° - 6°).
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Two equations are shown.
X^2 = 30 X^3 = 30
The solution of equation x² = 30 will be √30 and -√30. And the solution of equation x³ = 30 is ∛30.
What is the solution to the equation?In other words, the collection of all achievable values for the parameters that fulfill the specified mathematical equation is the suitable repository of the bunch of equations.
The equations are given below.
x² = 30 and x³ = 30
From equation x² = 30, then we have
x² = 30
x = ±√30
x = +√30, -√30
From equation x³ = 30, then we have
x³ = 30
x = ∛30
The solution of equation x² = 30 will be √30 and -√30. And the solution of equation x³ = 30 is ∛30.
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Test the hypothesis that a majority of the population of soft drink consumers prefer pepsi over coke. Use alpha=.10 (define the population parameter in H0)
Test the hypothesis that a majority of the population of soft drink consumers prefer pepsi over coke. Use alpha=.10 (define the population parameter in H0)
H0:
Ha:
Test statistic:
Rejection Region:
Obtain the P value:
Conclusion:
a)z-score
b)z-score > 1.64
c)comparing the z-score to a z-table
d)a majority of the population of soft drink consumers prefer Pepsi over Coke.
To test the hypothesis that a majority of the population of soft drink consumers prefer Pepsi over Coke, we will use a significance level of α = .10.
H0: The proportion of soft drink consumers who prefer Pepsi is ≤ 0.5.
Ha: The proportion of soft drink consumers who prefer Pepsi is > 0.5.
Test statistic: z-score
Rejection Region: z-score > 1.64
We will obtain the P value by comparing the z-score to a z-table.
Conclusion: Based on the P value, if it is less than or equal to the significance level of 0.10, then we reject the null hypothesis. We can conclude that there is sufficient evidence to suggest that a majority of the population of soft drink consumers prefer Pepsi over Coke.
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Use the properties of exponents to rewrite $y=5e^{-0. 7t}$ in the form $y=a(1+r)^t$ or $y=a(1-r)^t$. Round the value of $r$ to the nearest thousandth. Then find the percent rate of change to the nearest tenth of percent
We can rewrite y=[tex]5e^{-0.7t}[/tex] using the properties of exponents as follows:
y=[tex]5e^{-0.7t} =5(e^{-0.7)t} =5(\frac{1}{e^{0.7} })t[/tex]
We can recognize [tex]\frac{1}{e^{0.7} }[/tex] as a base for exponential function that can be written in the form 1 ±r We know that is an increasing function, so [tex]e^{0.7}[/tex]≥1
therefore [tex]\frac{1}{e^{0.7\\} }[/tex]≥1 which means we must use the form y=a[tex](1-r^){t}[/tex]
To find the percent rate of change, we can use the formula:
percent rate of change=|r|×100
So, the percent rate of change is:
=|0.503|×100
Rounding to the nearest tenth of a percent, we get a percent rate of change of approximately 50.3%.
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A person eats 3 slices of pie that has a radius of 4 inches and
an arc length of 45°.
What is the area of the amount of pie the person has eaten?
The area of the amount of pie the person has eaten is equal to the area of a sector with 45° central angle. The area is 6.28 square inches.
The area of the amount of pie the person has eaten can be found using the formula for the area of a sector, which is
A = (θ/360)πr²
where θ is the central angle of the sector (in degrees), r is the radius of the circle, and π is the constant pi.
In this case, θ = 45° (the arc length),
r = 4 inches (the radius of the pie), and
π = 3.14 (the constant pi).
Plugging these values into the formula, we get:
A = (45/360)π(4)²
Simplifying the equation, we get:
A = (0.125)π(16)
A = 2π
A = 6.28 square inches
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Find a polynomial f(x) of degree 3 with real coefficients and the following zeros. -1, 1-i f(x) = 0 = Х 3 ?.
The polynomial f(x) of degree 3 with real coefficients and the given zeros is f(x) = x³ - x² + 4x + 2.
To find a polynomial f(x) of degree 3 with real coefficients and the given zeros, we need to use the fact that if a polynomial has a complex root, then its conjugate is also a root. This means that if 1-i is a root, then 1+i is also a root.
So, our polynomial f(x) has the following roots: -1, 1-i, 1+i.
We can write the polynomial as the product of its factors:
f(x) = (x - (-1))(x - (1-i))(x - (1+i))
Simplifying the factors:
f(x) = (x + 1)(x - 1 + i)(x - 1 - i)
Multiplying the factors:
f(x) = (x + 1)(x² - 2x + 2)
Expanding the polynomial:
f(x) = x³ - 2x² + 2x + x² - 2x + 2
Simplifying the polynomial:
f(x) = x³ - x² + 4x + 2
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Find all values of m for which the equation has two complex (non-real ) solutions.
The answer of values of m for which the equation has two complex (non-real) solutions are all values greater than 1/8. In other words, m > 1/8
To find all values of m for which the equation has two complex (non-real) solutions, we need to use the discriminant of the quadratic formula.
The discriminant is the part of the quadratic formula under the square root: b²-4ac. If the discriminant is less than 0, then the equation will have two complex (non-real) solutions.
So, let's start by setting the discriminant to be less than 0:
b²-4ac < 0
Now, let's plug in the values from the equation into the discriminant. The equation is in the form ax²+bx+c=0, so we can plug in the values for a, b, and c:
(1)²-4(m)(2) < 0
Simplify:
1-8m < 0
Subtract 1 from both sides:
-8m < -1
Divide both sides by -8:
m > 1/8
So, the values of m for which the equation has two complex (non-real) solutions are all values greater than 1/8. In other words, m > 1/8.
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Quadrilateral MATH is dilated by a scale factor of 2.5 centered at (1, 1) to create quadrilateral M'ATH: Select all the statements that are true about the dilation.
M'A' will overlap MA
The area of M'A'T'H' is equal to 2.5 times the area of MATH
ΜΑΣ Μ' Α'
AT' will overlap AT
The slope of HT is equal to the slope of HT
M' A'T" H' is (1,1) and (2.5) equals 3.6 to form a quadrilateral. A two-dimensional shape with four sides, four vertices, and four angles is referred to as a quadrilateral.
What is meant by scale factor of quadrilateral?The scale factor is the ratio of one figure's side length to the other figure's corresponding side length.The scale factor of a shape refers to the amount by which it is increased or shrunk. It is applied when a 2D shape, such as a circle, triangle, square, or rectangle, needs to be made larger.The scale factor is the ratio of one figure's side length to the other figure's corresponding side length.A scale factor is the amount by which an object is multiplied to produce a second object of different size but with the same appearance. Just a larger or smaller version of the original is created, not an exact copy.Let the scale factor of quadrilateral is center at 2.5 at (1, 1) then
(1,1) and (2.5) equals 3.6
(1,1) + (2.5) = 3.6
Therefore, the statement exists true about the dilation is
D. [tex]\frac{}{A'T'}[/tex] will overlap [tex]\frac{}{AT}[/tex]
A. [tex]\frac{}{M'A'}[/tex] will overlap [tex]\frac{}{MA}[/tex]
E. The slope of [tex]\frac{}{HT}[/tex] is equal to the slope of [tex]\frac{}{H'T'}[/tex]
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