Would a hurricane more likely remain a hurricane if it reached point A or point B? Explain your answer.

Answer:

Positive particles are fired at gold foil. Most pass through, but some bounce back.

Answer: c

Explanation:

Answer:

1/2hour

Explanation:

it takes the runner 1 hour to complete 10km

so 5km is half of 10km therefore would take half the time

hope that helps:)

Answer:

i think this is correct

Explanation:

For amplitude measurements, you count the number of vertical divisions occupied by the signal's vertical signal and then multiply by the vertical scale. The example below shows the process for measuring the peak-to-peak voltage of a signal.

Answer:

A calcium fluoride ([tex]{\rm CaF_{2}[/tex]) formula unit includes one calcium ion and two fluoride ions.

Explanation:

The content of one formula unit of an ionic compound is exactly the same as what its empirical formula would suggest. (The empirical formula shows the atoms that form this compound, in the smallest whole number ratio.)

For example, [tex]{\rm CaF_{2}}[/tex] is the empirical formula of the ionic compound calcium fluoride. One formula unit of this compound would thus include:

However, since [tex]{\rm CaF_{2}}\![/tex] is an ionic compound, all these atoms would take the form of ions:

Thus, one formula unit of [tex]{\rm CaF_{2}}[/tex] would include [tex]1[/tex] calcium ion and [tex]2[/tex] fluoride ions.

Answer:A.) Mechanical and nuclear

Explanation:

iv,e got nuthing sorry im only a kid i have to leared that yet

answer:

B) Radiant and Thermal

explanation:

  "In a flashlight, chemical energy in the batteries is converted to electrical energy when the circuit including the batteries, switch and light bulb is completed. The electrical energy is converted to light (electromagnetic / radiant energy) and some heat (thermal energy) by the light bulb." -https://www.crosbyisd.org/cms/lib6/TX02216626/Centricity/Domain/392/6_9C-EnergyFormsConversions.pdf

Answer:

The empirical formula is CH2O, and the molecular formula is some multiple of this

Explanation:

In 100 g of the unknown, there are 40.0⋅g12.011⋅g⋅mol−1 C;  6.7⋅g1.00794⋅g⋅mol−1 H; and  53.5⋅g16.00⋅g⋅mol−1 O.

We divide thru to get, C:H:O = 3.33:6.65:3.34. When we divide each elemental ratio by the LOWEST number, we get an empirical formula of CH2O, i.e. near enough to WHOLE numbers. Now the molecular formula is always a multiple of the empirical formula; i.e. (EF)n=MF.So 60.0⋅g⋅mol−1=n×(12.011+2×1.00794+16.00)g⋅mol−1.Clearly n=2, and the molecular formula is 2×(CH2O) = CxHyOz.

Answer:

The mass remains same after and before the reaction

Explanation:

This is because of law of conservation of mass

Which states that

Taking into account the definition of molarity, the molarity of the solution is 0.78 [tex]\frac{moles}{liter}[/tex].

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Molarity of a solution of NaNO₃

In this case, you know:

Replacing in the definition of molarity:

[tex]molarity=\frac{0.078 moles}{0.100 L}[/tex]

Solving:

molarity= 0.78 [tex]\frac{moles}{liter}[/tex]

Finally, the molarity of the solution is 0.78 [tex]\frac{moles}{liter}[/tex].

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Answer:use thise https://www.ahschools.us/cms/lib/MN01909485/Centricity/Domain/4810/Chem%202andIB%20Chem/Equilibrium_Practice_WS_CHem_1_Answer_KEy.pdf

Explanation:

Cobalt chloride exists in hydrated form. Generally it prefer to form its hexahydrated form but the actual number of water molecules per formula unit is 2. Thus it forms CoCl₂.2H₂O.

Cobalt chloride is a metallic compound formed from the transition metal cobalt and two chlorine atoms. In fact it is a coordination complex attached with water molecules.

The property of a compound to be easily dehydrated and dry is called hygroscopic whereas the property by which a compound easily absorbs moisture and forms its hydrated  form is called deliquescent.

Cobalt chloride is deliquescent in nature and absorbs water molecules forming its dihydrated, tetra hydrated and hexahydrated forms. The most common hydrate of cobalt chloride is dihydrated one and thus we can say that the number of water molecules per formula unit of CoCl₂ is 2.

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Answer:

Exergonic or Exothermic (see explanation)

Explanation:

If you're talking about heat energy specifically, then the term is exothermic, meaning that the system loses heat. If referring to overall energy of a system, the term is exergonic, meaning that the system does work on the surroundings and is thus losing energy.

Answer:

Chemical change

Answer:

Iron (III) oxide reacts with carbon monoxide according to the balanced equation: Fe2O3 + 3CO

Answer:

586000.

Explanation:

Answer: 58600 atm

Explanation:

Answer:

Just like with any other reaction, balancing the equation for the reaction is important so that people can know all the inputs and outputs, and know how much of each input (reactant) is needed to produce a certain amount of product.

The decomposition of ammonium nitrate takes place as follows :

NH4NO3 → N2O + 2H2O

Total Molecules of H = 4

Total Molecules of N = 2

Total Molecules of O = 3

The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.

The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.

The equation of the reaction is given below:

[tex]CuSO_4 + Fe \rightarrow FeSO_4 + Cu[/tex]

The mole ratio of both reactants and product is 1 : 1

molar mass of copper sulfate = 160 g

molar mass of Cu = 64

molar mass of iron = 56 g

moles of Cu in 1.5 g = 1.5/64 = 0.00234

mass of iron required = 0.00234 × 56 = 1.31 g of iron

Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.

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Answer:

The answer is nosocomical.

Explanation:

It was transmitted from a hospitial.

Answer:

A. lodine

Explanation:

In moving down to the halogen group E.N. decreases hence Iodine has lowest electronegativity.

Answer:

A. Iodine

Electronegativity decreases down the group as the size of the atom increases .

Answer:

Base

Explanation:

Bases on dissolving with water release hydroxide ions

Take a example of Sodium hydroxide

Answer:

About 1.48 M.

Explanation:

The formula for molarity is mol/L.

So firstly, you must find the amount of moles in 250 grams of NaCl.

I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.

I get that 250 grams of NaCl is equal to about 4.28 moles.

Now I just plug into the formula!

4.28 moles/2.9 L = about 1.48

I've attached a picture of my personal notes below which shows work I have done in similar equations.

Answer:

A: 92.02 g

Explanation:

Equation of the reaction;

N2 (g)+ 2O2(g)------> 2NO2(g)

Note that the balanced reaction equation is the first step in solving any problem on stoichiometry. Once the reaction equation is correct, the question can be easily solved...

The required mole ratio of  NH₃ to N₂ in the given chemical reaction is 2:4.

Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.

Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that:

4 moles of NH₃ = produces 2 moles of N₂

Mole ratio NH₃ to N₂ is 2:4.

Hence required mole ratio is 2:4.

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Answer: Heyo Kenji Here! Here's your answer- Octahedral complexes have a coordination number of six, and the six donor atoms are arranged at the corners of an octahedron around the central metal ion.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

Answer:

20.796 liters

Explanation:

PV = n RT     R = .082057  L-atm / (K-mol)      

      25 C = 298.15 K

(1) * V = .85 * .082057 * 298.15  

   V = 20.796 liters

Answer:

Let's walk through this together, and pay close attention. The answers are bolded and underlined but I insist you to read through the whole thing and understand what's being applied here.

Write down the balanced equation first:

[tex]Pb(NO_{3})_{2} \ + \ 2KI \ ----- > \ PbI_2 \ + \ 2KNO_{3}[/tex]

  24g              30g                         ???

To find the limiting reactant, convert both of the masses to moles and the lowest one is the limiting reagent.

Molar mass of Lead (II) Nitrate: 331.2g/mol

Molar mass of Potassium Iodide: 166g/mol

Remember: [tex]moles \ = \ \frac{mass}{molar \ mass}[/tex]

[tex]\frac{24}{331.2} = 0.0724 \ mol\ of\ Lead \ (II) \ Nitrate\\\\\frac{30}{166} = 0.180 \ mol \ of \ Potassium \ Iodide[/tex]

As you can see here, the compound with the lower mol value is Lead (II) Nitrate, meaning Lead (II) Nitrate is our limiting reactant.

To find the excess reactant which is the other reactant present, Potassium Iodide, you must do the mol to mol ratio of Lead (II) Nitrate to Potassium Iodide (Basically the numbers in front/coefficients of the compound in the balanced equation)

The ratio is 1 : 2, meaning you have to multiply the amount of mol of Lead (II) Nitrate by 2 to get the mol of Potassium Iodide.

[tex]0.0724 \ * \ 2 = \ 0.1448 \ mol \ of \ Potassium \ iodide[/tex]

Now we change the mol into mass by multiplying it by the molar mass of potassium iodide

[tex]0.1448 \ * \ 166 = \ 24.04g \ of \ Potassium \ iodide[/tex]

To get the amount of excess reactant, you have to subtract the original mass amount you had which was 30g by the mass you just got which is 24.04g

30 - 24.04 = 5.96g of Potassium Iodide is in excess left over

Our final question is to calculate the percentage yield of lead iodide, which we can do so by dividing the actual yield produced by the theoretical yield, and multiplying the answer of that by a 100 to get the percent.

We have our experimental yield which is 32.5g but we don't have our theoretical. We have to calculate it using our limiting reactant and mol ratios. The ratio of Lead (II) Nitrate to Lead (II) Iodide is 1 : 1 so all we have to is to change 0.0724 mol into the mass value by multiplying the mol with the molar mass of Lead (II) Iodide.

Molar mass of Lead (II) Iodide: 461.01g/mol

[tex]0.0724 \ * \ 461.01 = \ 33.4g[/tex]

So the theoretical yield is 33.4g and the actual yield was 32.5g

[tex]\frac{32.5}{33.4} * 100 = 97.3 \ percent[/tex]

The percentage yield of Lead (II) Iodide is 97.3%

Answer:

Here's your Answer → Kindly Check The Attachment.

Answer:

Molecular mass of urea (NH 2CONH 2) × 2

× (Atomic mass of N ) + 4

× (Atomic mass of H) + (Atomic mass of C) + (Atomic mass of O) = 60

Mass percentage of N =

Total mass of N atoms in the compound / Mass of compound × 100 = 28 / 60 × 100 = 46.67

Explanation:

Hope it helps u sis.