Positioning your Slinky along any direction different from its initial position will affect your reading, because there will be change in the magnetic field.
Effect of magnet on Slinky
If the Slinky is made of an iron alloy, it can be magnetized by itself. Moving the Slinky around can cause a change in the magnetic field, even if no current is flowing.
When there is a change in the magnetic field, the reading changes.
At any point, you change the orientation of the Slinky, you will need to zero the reading or adjust the Slinky back to its initial position, even if the sensor does not move.
Thus, Positioning your Slinky along any direction that is different to its initial position will affect your reading because there will be change in the magnetic field.
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A tortoise challenges a hare to a four-hour race. The hare is so confident of winning that he allows the tortoise to start with a 10-km lead. The hare runs at a speed of 14 km per hour, but stops for a two-hour nap in the middle of the race. The tortoise plods along at 4 km per hour the whole race. Who gets farther in four hours?
runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.
Answer:
Take north as y and west as -x.
distance=√(x^2+y^2)
displacement= tan theta(tan^-1) (y/x)
answers should be, (9.85m, 66.04°)
What emits infrared radiation?
Question 5 options:
Humans
Non-living objects
Anything that contains atoms
Answer:
anything that contains atoms is the correct answer of given statement
If you wanted the car to roll a long way , would you choose carpet or wood
A big pendulum goes back and forth
once every 18.9 s. What is the
length of the pendulum?
(Unit = m)
T = 2π√(L/g)
For earth , g ~ 10
18.9 = 2×3.14 √(L/g)
9 = L/g
L = 90 metres
Answer:
88m
Explanation:
T=2π*[tex]\sqrt{L/g}[/tex]-->Τ/2π=[tex]\sqrt{L/g}[/tex]-->18.9/2π=[tex]\sqrt{L/g}[/tex]-->3=[tex]\sqrt{L/g}[/tex]-->3^2=L/g-->9=L/9.8
so L=9*9.8-->L≈88m
Can someone please help me!
Answer: I've solved the above questions and attached pictures too which show the working for better understanding of the questions.
hope that helps...
Breifly describe how traits are passed down from human parents to their offspring. In your description, be sure to include the terms gene, chromosome, and meiosis.
Answer:
Parents pass on traits or characteristics, such as eye colour and blood type, to their children through their genes
Explanation:
if lens behave like prism and disperse light then why person using glass on eye can't see colour being dispersed?
Answer:
A prism can disperse light into different colors when the light enters the prism at a "fixed" angle - light coming in, perhaps, thru a narrow slit
If light can enter at all angles, then dispersion occurs at all angles and no dispersion can be seen
find the distance and displacement by minutes hand of length by 7 cm at the end of 3 ⅔ mins
Answer:
3 14/3
Explanation:
you put a 1 under the 7 then times it with 3 2/3 and you get 3 14/3
If a small appliance is rated at a current of 18 amps and a voltage of 120 volts, what is the
power rating of the appliance?
2160 watts
thank you
Hope this helped
Have a good day
(Stop flagging my anwsers I got to many I’m gonna get banned)
Rilee Cartner
How does paragraph 3 help develop the ideas in this passage
Answer:
celebrating different points.
Explanation:
adds more information to what your talking about
Each degree on the Kelvin scale equals how many degrees on the Celius scale
Answer:
0° C = 273.15 K
0 K = - 273.15° C
Explanation:
Hello there!
The Kelvin temperature scale refers to the absolute temperature scale. The division in the Kelvin scale is equal to a degree on the Celsius scale only it's difference is zero
The Celsius scale of zero (0°C) is the freezing point.
0 K is Absolute Zero.
•°• 0 K = - 273.15° C
0° C = 273.15 K
Furthermore, this is what I would like you to know about this scales;
The Kelvin scale is used for very low or very high temperatures where water is not involved.
Note:
The boiling point of water is 100°C.
I hope this helps you to understand more on this scales. Have a nice studies.
Answer ASAP and only if you know its correct
this is science btw also, brainliest to the correct answer
Answer:
the doppler effect shows stars with red shifted light
Explanation:
light from a receding star is shifted toward red or redshifted
redshift is an example of the doppler effect
the wavelength of the light is stretched so the light is seen as shifted towards the red part of the spectrum
What is the chemical formula for sulfur trioxide?
Answer:
Sulfur trioxide is a colourless compound that exists at room temperature either as a volatile liquid or in any of three allotropic solid forms. What is SO2 and SO3? SO2 is sulfur dioxide which is a gaseous compound formed from sulfur and oxygen atoms. The melting point and the boiling point are -71℃ and -10℃respectively.
Explanation:
A force of 20 N is exerted by an electric field on a test charge of 8.0 x 10² C at a point, P. What is the electric field strength
at point P?
0.004 N/C
Ob
1.6 N/C
Oc
160 N/C
Od
250 N/C
Answer:
the answer is equal to 1.6N/C
Pluto was first discovered in 1930.It was determined to be located about 39.48 times as far away from the Sun as Earth is. How long does Pluto take to orbit the Sun?
Answer:
It takes total 248 years for Pluto to orbit the sun.
Pluto will take 253 year to orbit the sun.
What is the distance between the Sun and Earth ?Earth's average distance to the Sun is about 93 million miles (150 million kilometers) from the Sun.
What is the distance between Pluto and the Sun?Pluto is located about 39.48 times as far away from the Sun as Earth is.So the distance between Pluto and Sun will be , 39.48 X 93 = 3671.64 million miles.What is Kepler's third law?The squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits.P^2 = a^3 , where P = period of orbit , a = distance of semi major axis.Pluto has a semi-major axis distance a=40 then T2=403, which gives T=253 years.
Therefore, Pluto will take 253 year to orbit the sun.
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to which end of the horseshoe magnet will the north end of the magnet be attracted
Answer:
The north end of the magnet will be attracted to the south end of the horseshoe magnet.
Likewise, the north end of the magnet will be attracted to the earth's north pole - so the north pole of the earth is actually a south magnetic pole.
50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED
A force of 600N is applied to an object that accelerates at a rate of 15m/s/s. What is the mass of the object?
Answer:
The answer will be it has a mass of 40 kg.
Explanation:
Because Force = mass x acceleration or F = m a, we can say Force divided by mass or F/a = m or mass so 600 divided by 15 equals 40 kg.
If I want to calculate the normal force of an object on two legs but the weight of the object is not uniform throughout, how do I go about calculating such a problem?
Use the right equation. To calculate the normal force of an object at an angle, you need to use the formula: N = m * g * cos (x) For this equation, N refers to the normal force, m refers to the object's mass, g refers to the acceleration of gravity, and x refers to the angle of incline.
What is the distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º
The distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º will be 0.0000034 m.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º is;
The equation of diffraction grating is given as;
[tex]\rm d sin \theta = n \lambda \\\\ dsin60=2 \times 760 \times 10^{-9} \\\\ d=0.00000304 \ m[/tex]
Hence,he distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angle of 60.0º will be 0.0000034 m.
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A truck travelling at 22.5 m/s decelerates at 2.27 m/s2. (a) How much time does it take for the truck to stop? (b) How far does it travel while stopping? (c) How far does it travel during the third second after the brakes are applied?
We can use the "suvat" method
s is displacement
u is initial velocity
v is final velocity
a is acceleration
t is time
We substitute in what we know...
s = ?
u = 22.5 (the speed/velocity the trucks is initially)
v = 0 (the truck comes to a stop)
a = -2.27 (negative because it is decelerating
t = ?
[tex]\text{suvat formulae}:\\v = u + at\\s = ut + \frac{1}{2}at^2\\v^2 = u^2 + 2as\\s = \frac{v+u}{2}t\\s = vt - \frac{1}{2}at^2[/tex]
We have [tex]u[/tex], [tex]v[/tex], [tex]a[/tex] and we want to find the time for how long it takes the truck to stop.
We can use [tex]v = u + at[/tex]
[tex]v = u + at\\0 = 22.5 - 2.27 \times t\\\frac{-22.5}{-2.27} = t\\t = 9.91...\ \text{s}[/tex]
To find the distance (displacement), we can use [tex]s = ut + \frac{1}{2}at^2[/tex]
[tex]s = ut + \frac{1}{2}at^2\\s = 22.5 + \frac{1}{2} \times -2.27 \times 9.91^2\\s = -88.9661935\ \ \text{(we make it positive since you can't have negative distance)}\\s = 88.97...\ \text{m}[/tex]
To find the distance travelled 3 seconds after breaks are applied;
We just use the same formula, but with [tex]t = 3[/tex]
[tex]s = ut + \frac{1}{2}at^2\\s = 22.5 \times 3 + \frac{1}{2} \times -2.27 \times 3^2\\s = 12.285\ \text{m}[/tex]
A person driving in a neighborhood traveling 9 m/s slows to a stop (0 m/s) over 4
seconds as they approach a stop sign. What is the rate of acceleration of the car coming
to a stop in m/s²?
(Please help urgently if you can, thanks :D)
Answer:
-2.25 metres per second squared
If the resistance through the fat is 3 times that through the muscle, how much of the total current goes through the fat in terms of the current through the muscle?
A) 3 times the current through the muscle.
B) The same current as through the muscle.
C) No current passes through the fat.
D) 1/3 times the current through the muscle.
Answer:
it A i think
hope that helps if not i can change it
Explanation:
A projectile is fired from the ground with an initial velocity of 250 m/s at an angle 60 degrees above the horizon. Calculate the horizontal and vertical components of the velocity.
The vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
What is velocity ?Velocity is the rate of change of displacement.
To calculate the horizontal component of the projectile we use the formula below.
Formula:
Vx = Vcos∅........... Equation 1Where:
Vx = Horizontal velocity of the projectileV = Velocity of the projectile∅ = Angle of the projectileFrom the question,
Given:
V = 250 m/s∅ = 60°Substitute these values into equation 1
Vx = 250(cos60°)Vx = 125 m/sSimilarly, to calculate the vertical velocity, we use the formula below
Vy = Vsin∅................. Equation 2Where:
Vy = Vertical component of the velocity.Also Substitute the values into equation 2
Vy = 250(sin60°)Vy = 216.51 m/sHence, the vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
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5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?
Answer:
Explanation:
Force of Tension = (m)(g)
120 = (m)(9.8)
m = volume(density)
120 = (4/3)πr³(0.308)(9.8)
[tex]\frac{(120)(3)}{(pi)(0.308)(9.8)}[/tex] = r^3
solve
The radius of the brass ball is equal to 6.94 × 10⁻² m when the tension in the wire is 120 N.
What is tension?Tension can be demonstrated as the pulling force transmitted by the means of a string, or a rope or can be described as the action-reaction pair of forces acting at each end of said elements.
The tension in the wire attached to the ceiling will be given by:
T = mg ⇒m = T/g
The radius of the brass ball is given by: [tex]r =\sqrt[3]{\frac{3V}{4\pi } }[/tex]
The density is given by: ρ = m/V = T/gV
V = T/gρ
Therefore, the expression for the radius can be written as:
[tex]r =\sqrt[3]{\frac{3T}{4\pi\rho g } }[/tex]
Given the tension in the wire, T = 120 N
The density of the brass is = 8730 Kg/m³
[tex]r =\sqrt[3]{\frac{3\times 120}{4\times 3.14 \times 8730 \times 9.81 } }[/tex]
r = 6.94 × 10⁻² m
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what is a literature review?
Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.
Explanation:
which of the following is not a latent heat gain source
Martin perceived that there was music playing. Martin
A
did not believe there was music.
B
was very surprised by the music.
C
let everyone know about the music.
D
became aware of the music.
The cart is then pushed up the ramp, compressing the spring a distance A from equilibrium. When
released from rest, the cart oscillates up and down the ramp with a period of T₁. Assume that any friction
is negligible.
The spring is then replaced with a second spring that has a constant k2 = 2k₁, and the new period, T2, is
measured.
Determine the period of T2 in terms of T₁.
When the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
Period of the mass oscillation
The period of the oscillation of the mass or cart on the spring is given by the following formula;
[tex]T = 2\pi \sqrt{\frac{m}{k} } \\\\[/tex]
at a costant mass;
[tex]T_1\sqrt{k_1} = T_2\sqrt{k_2} \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{k_2} }[/tex]
when spring constant is doubled, k2 = 2k1. the new period, T2 is determined as follows;
[tex]T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2k_1} } \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2} \times \sqrt{k_1} } \\\\T_2 = \frac{T_1}{\sqrt{2} }\\\\T_2 = \sqrt{\frac{1}{2} } \ T_1[/tex]
Thus, when the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
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