Will the graph y=2(4)^x be increasing or decreasing? Explain how u know

The expected rabbit population by next April is 486.

The rabbit population in a forest area can be found using the formula y=200(2.7)^0.08t, where y is the expected population, t is the time in months, and 200 is the initial population. To find the expected population by next April, we need to plug in the value of t as 12 (since there are 12 months in a year) and solve for y.

y=200(2.7)^0.08t

y=200(2.7)^0.08(12)

y=200(2.7)^0.96

y=200(2.4315)

y=486.3

Since the question asks for the expected population rounded to the nearest whole number, we can round 486.3 to 486.

Therefore, the expected rabbit population by next April is 486.

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Answer:

c landing on 1 is the answer

hope it helps u mark me BRAINLIST

Therefore, [tex]h = \sqrt{(12.25 - x^2)} = 3.73[/tex] feet represents the distance between the two staircases on the tree. Thus, option c is correct.

The Pythagorean theorem states that the square length of the hypotenuse, or the side that faces the right angle, of a right triangle is equal to the sum of the square lengths of the other two sides. The following can be expressed mathematically: [tex]a^2 + b^2 = c^2[/tex] where "c" represents the length of the hypotenuse and "a" and "b" represent the measurements of the two sides of the right triangle.

given

Assume the tree is h feet tall, the higher ladder is 3 feet long, and the lower ladder is x feet long.

Using the Pythagorean formula, we can create two equations:

With regard to the narrower staircase,  x² + h² = (3.5)

Use the formula for the higher ladder. (3x)²+ h²= (7.5)².

The formulas are as follows, simplified: 12.25 x² + 9.25 x² + 56.25

To remove h2, we can solve for x in the first equation and y in the second equation: 8x² = 44.

Finding the value of x is as follows:   [tex]x = \sqrt{(5.5) } = 2.34[/tex]

Therefore, [tex]h = \sqrt{(12.25 - x^2)} = 3.73[/tex]  feet represents the distance between the two staircases on the tree.

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Complete question:

Two ladders are placed at different locations on a coconut palm tree so that lights can be installed, as pictured below. The length of the taller ladder is three times the length of the shorter ladder. The shorter ladder is placed 3.5 feet from the base of the tree while the taller ladder is placed 7.5 feet from the base of the tree. What is the distance on the tree between the two ladders?

O 4.59 feet

O 9.78 feet

O 3.73 feet

O 8.96 feet

Answer:

Year 1 Depreciation:$2,000

Depreciation Percentage:20.00%

Total Depreciation:$10,000

Final Year Depreciation:$2,000

Step-by-step explanation:

P.S by teacher told me the answer

Answer:

Step-by-step explanation:

20

The rate at which the petrol was used in kilometers per liter is 10 km/L that means that for every litre of petrol used for driving, Peter's car could travel 10 kilometers.

Peter drove a thousand km and used 100 liters of petrol. To find the rate at which the petrol was utilized in kilometers consistent with liter, we divide the whole distance traveled via the quantity of petrol used.

The formulation for this is rate of petrol usage = overall distance traveled/quantity of petrol used.

Rate of petrol usage = total distance traveled/quantity of petrol used

Substituting the values we get,

= 1000 km / 100 L

= 10 km/L

This means that for every liter of petrol used, Peter was capable of travel 10 kilometers.

Thus, the rate at which the petrol was used in kilometers per liter is 10 km/L.

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An expression that looks like Sarah's expression but is not equivalent is:

10(5j + j + 3).

A sentence qualifies as a mathematical expression if it comprises one or more mathematical operations, at least two numbers, or variables. Let's examine the writing style of expressions. A number is 6 times larger than the other number, x, by a factor of 2. This statement is represented mathematically by the expression x/2 + 6. Using mathematical expressions, complex puzzles can be solved.

now in the question,

We can write a look alike expression which is not equivalent is:

10(5j + j + 3).

Now translating the new expression into verbal:

Sarah gets paid $10 for every shark tooth she finds. After finding 3, she asked Jhon for help. When Jhon finds a tooth, by that time Sarah finds 5 of them.

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The annual interest rate on Susan's savings account is 4%.

Annual interest rate, also known as annual percentage rate is the yearly interest generated by a sum that's charged to borrowers or paid to investors We can use the simple interest formula to calculate the annual interest rate which is Simple Interest = (Principal x Rate x Time)

By plugging our values, we get.

$54 = ($900 x Rate x 1.5)

Simplifying the equation:

Rate = $54 / ($900 x 1.5)

Rate = 0.04

Rate = 4%.

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Answer:

Step-by-step explanation:

2(2x+2) + 2(x+4) = 36

4x+4 +2x+8 =36

6x+12= 36

6x = 36-12

6x =24

x = 4

longer side = 10

The value of c is 10.

The value of c is 10. To find this, use the limit definition of continuity. This states that for the function to be continuous at x = 4, we must have f(4) = lim f(x) x -> 4. Thus, we can equate f(4) and lim f(x) x -> 4 to get 1/4*4 + c = -4 + 6, giving c = 10.

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Answer: 50%

Step-by-step explanation: There are 5 out of 10 employees at the water slide. 10 in this situation is going to be 100%

since there is only 5 out of 10 employees that are temporary

it would be 50%

Answer: 50%

Step-by-step explanation:

To find f(x)-g(x), we need to subtract the two given functions.

f(x) = x^(2)-6x-40

g(x) = x+4

f(x)-g(x) = (x^(2)-6x-40) - (x+4)

Next, we need to distribute the negative sign to the terms inside the parentheses:

f(x)-g(x) = x^(2)-6x-40 - x - 4

Then, we can combine like terms: f(x)-g(x) = x^(2)-7x-44

Therefore, the result of f(x)-g(x) is a polynomial in simplest form: x^(2)-7x-44.

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We are only interested in the critical numbers on the interval [1,3], so we can disregard x = 0. Therefore, the critical numbers of the function f(x) on the interval [1,3] are x = 3.

The critical numbers of a function are the points where the derivative of the function is either zero or undefined. To find the critical numbers of the given function f(x) = x^2/(3-x), we need to first find its derivative:

f'(x) = (2x(3-x) - (-1)x^2)/ (3-x)^2 = (6x - x^2 - x^2)/ (3-x)^2 = (6x - 2x^2)/ (3-x)^2

Now, we need to find the values of x for which f'(x) = 0 or f'(x) is undefined. f'(x) is undefined when the denominator (3-x)^2 is equal to 0, which occurs when x = 3. f'(x) is equal to 0 when the numerator 6x - 2x^2 is equal to 0:

6x - 2x^2 = 0
2x(3 - x) = 0
x = 0 or x = 3

However, we are only interested in the critical numbers on the interval [1,3], so we can disregard x = 0. Therefore, the critical numbers of the function f(x) on the interval [1,3] are x = 3.

Answer: 3

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The conditional expectation of Y given that X is less than or equal to 1/2 is calculated by taking the weighted average of the possible values of Y, with the weights being the probabilities of X being less than or equal to 1/2 for each value of Y.
The formula for E(Y | X<=1/2) is:
E(Y | X<=1/2) = ∑y P(Y=y | X<=1/2) * y
To find P(Y=y | X<=1/2), we can use the formula:
P(Y=y | X<=1/2) = P(X<=1/2 | Y=y) * P(Y=y) / P(X<=1/2)
We can then plug in the values for each possible value of Y and calculate the conditional expectation.

For example, if Y can take on the values 0, 1, and 2, and the probabilities of X being less than or equal to 1/2 for each value of Y are 0.2, 0.5, and 0.3, respectively, and the probabilities of Y being 0, 1, and 2 are 0.4, 0.3, and 0.3, respectively, then:
E(Y | X<=1/2) = (0.2 * 0.4 / 0.5) * 0 + (0.5 * 0.3 / 0.5) * 1 + (0.3 * 0.3 / 0.5) * 2
E(Y | X<=1/2) = 0 + 0.3 + 0.36
E(Y | X<=1/2) = 0.66

Therefore, the conditional expectation of Y given that X is less than or equal to 1/2 is 0.66.

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As a result, the 15 cartons of creamer will last for 1,350 days, or nearly 3.7  expression years. This implies the consumer drinks one serving of creamer per day at a weight of 5 grammes per serving.

An expression in mathematics is a collection of representations, numbers, and conglomerates that mimic a statistical correlation or regularity. A real number, a mutable, or a mix of the two can be used as an expression. Mathematical operators include addition, subtraction, fast spread, division, and exponentiation. Expressions are often used in arithmetic, mathematics, and form. They are employed in the depiction of mathematical formulas, the solving of equations, and the simplification of mathematical relationships.

(Total amount of creamer in grammes) / number of days (Amount of creamer consumed per day in grams)

Let's start by calculating the entire amount of creamer in grammes:

(Number of cartons) x (Total quantity of creamer) (Amount of creamer per box)

15 boxes x 450 grammes each box = total quantity of creamer

Total creamer weight = 6,750 g

(Total amount of creamer in grammes) / number of days (Amount of creamer consumed per day in grams)

The number of days is 6,750 grammes divided by 5 grammes each day.

The number of days is 1,350.

As a result, the 15 cartons of creamer will last for 1,350 days, or nearly 3.7 years. This implies the consumer drinks one serving of creamer per day at a weight of 5 grammes per serving.

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5. 20% of students said that they enjoy Cookie Cake.

6. 25 students answered a survey regarding their favorite cake.

The percentage is defined as a ratio expressed as a fraction of 100.

The % formula is used to calculate a percentage of a whole in terms of 100.

Percentage = (Value/Total Value) × 100

Percentage of students said they like Cookie Cake:

5/(5 + 6 + 8 + 6) × 100%

5/25 × 100%

20%

The total number of students who answered this survey about their favorite Cake:

5 + 6 + 8 + 6

25

Thus, 25 students answered a survey regarding their favorite cake.

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In the triangle ABC, the value of x, y and z is obtained as 21, 7 and 48 units respectively.

What are triangles?

Triangles are a particular sort of polygon in geometry that have three sides and three vertices. Three straight sides make up the two-dimensional figure shown here. An example of a 3-sided polygon is a triangle. The total of a triangle's three angles equals 180 degrees. One plane completely encloses the triangle.

A triangle ABC is given.

The measure of AB is given as 16 + z units.

The measure of AD is given as 16 units.

The measure of DB is given as z - 16 units.

The measure of BE is given as 21 units.

The measure of BC is given as x units.

The measure of AC is given as 14 units.

According to the midpoint theorem, the length of DE is -

DE = 1/2 (AC)

y = 1/2 (14)

y = 7 units

Therefore, the value of y is obtained as 7 units.

Now according to indirect measurement -

AB / AC = BD / DE

Substitute the values in the equation -

16 + z / 14 = z - 16 / 7

7(16 + z) = 14(z - 16)

112 + 7z = 14z - 224

7z - 14z = -224 - 112

-7z = -336

z = 48

Therefore, the value of z is obtained as 48 units.

Now according to indirect measurement -

BC / AC = BE / DE

Substitute the values in the equation -

21 + x / 14 = 21 / 7

7(21 + x) = 14 × 21

147 + 7x = 294

7x = 294 - 147

7x = 147

x = 21

Therefore, the value of x is obtained as 21 units.

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Answer:

x = 21

y = 7

z = 32

Step-by-step explanation:

DE = 1/2 (AC)

y = 1/2 (14)

y = 7

AB / AC = BD / DE

Substitute values

16 + z / 14 = z - 16 / 7

7(16 + z) = 14(z - 16)

112 + 7z = 14z - 224

7z - 14z = -224 - 112

-7z = -336

z = 32

BC / AC = BE / DE

Substitute values

21 + x / 14 = 21 / 7

7(21 + x) = 14 × 21

147 + 7x = 294

7x = 294 - 147

7x = 147

x = 21

Therefore, the rate per period (i) is 0.00708333 and the number of periods (n) is 84. The future value of the annuity is $34563.89.

To find i (the rate per period) and n (the number of periods) for the given annuity, we need to use the formula for the future value of an annuity:

FV = PMT × [(1 + i)^n - 1] / i

Where FV is the future value, PMT is the periodic payment, i is the rate per period, and n is the number of periods.

Given:
PMT = $305
i = 8.5% / 12 = 0.00708333 (since the interest is compounded monthly)
n = 7 × 12 = 84 (since there are 12 months in a year and the deposits are made for 7 years)

Plugging these values into the formula, we get:

FV = $305 × [(1 + 0.00708333)^84 - 1] / 0.00708333

FV = $305 × [1.80722 - 1] / 0.00708333

FV = $305 × 0.80722 / 0.00708333

FV = $34563.89

Therefore, the rate per period (i) is 0.00708333 and the number of periods (n) is 84. The future value of the annuity is $34563.89.

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The fourth proportion to 15/7,23/14, and 33/5 is 19.25.

To discover the fourth proportion, we require to set up a probability between the 3 presented figures and the fourth unknown variety, which we can name x.

23/1433/5 x

First, we need to transfigure all the mixed figures to unsuitable fragments

= (7/7 * 1)5/7 = 7/75/7 = 12/7

= (14/14 * 2)3/14 = 28/143/14 = 31/14

= (5/5 * 3)3/5 = 15/53/5 = 18/5

Now we're suitable to preference those values into the share

31/1418/5 x

To break for x, we're suitable to cross-multiply

12/7) * x = (31/14) *(18/5)

Simplifying

12x/ 7 = 279/14

Multiplying each aspects via7/12

x = (279/14) *(7/12)

x = 19.25

Thus, the fourth proportion to 15/7,23/14, and 33/5 is 19.25.

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The solution is  \boxed{A^{-1} = \left[\begin{array}{rr}-\frac{1}{3} & 0 \\ 0 & -\frac{1}{5}\end{array}\right]} and \boxed{A^{-1} = \left[\begin{array}{rrr}-\frac{1}{6} & 0 & 0 \\ 0 & \frac{1}{12} & 0 \\ 0 & 0 & -\frac{1}{8}\end{array}\right]}.

(a) To find the inverse of \( A=\left[\begin{array}{rr}-3 & 0 \\ 0 & 5\end{array}\right] \), we need to use the formula:

\( A^{-1} = \frac{1}{ad-bc} \left[\begin{array}{rr}d & -b \\ -c & a\end{array}\right] \)

where \( a=-3, b=0, c=0, d=5 \).

Plugging in the values, we get:

\( A^{-1} = \frac{1}{(-3)(5)-(0)(0)} \left[\begin{array}{rr}5 & 0 \\ 0 & -3\end{array}\right] \)

\( A^{-1} = \frac{1}{-15} \left[\begin{array}{rr}5 & 0 \\ 0 & -3\end{array}\right] \)

\( A^{-1} = \left[\begin{array}{rr}-\frac{1}{3} & 0 \\ 0 & -\frac{1}{5}\end{array}\right] \)

So, the inverse of \( A=\left[\begin{array}{rr}-3 & 0 \\ 0 & 5\end{array}\right] \) is \( A^{-1} = \left[\begin{array}{rr}-\frac{1}{3} & 0 \\ 0 & -\frac{1}{5}\end{array}\right] \).

(b) To find the inverse of \( A=\left[\begin{array}{rrr}4 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 3\end{arra \), we need to use the formula:

\( A^{-1} = \frac{1}{\det(A)} \left[\begin{array}{rrr}a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array}\right]^{T} \)

where \( a_{11}=4, a_{12}=0, a_{13}=0, a_{21}=0, a_{22}=-2, a_{23}=0, a_{31}=0, a_{32}=0, a_{33}=3 \) and \( \det(A) = (4)(-2)(3) - (0)(0)(0) - (0)(0)(0) = -24 \).

Plugging in the values, we get:

\( A^{-1} = \frac{1}{-24} \left[\begin{array}{rrr}4 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 3\end{array}\right]^{T} \)

\( A^{-1} = \frac{1}{-24} \left[\begin{array}{rrr}4 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 3\end{array}\right] \)

\( A^{-1} = \left[\begin{array}{rrr}-\frac{1}{6} & 0 & 0 \\ 0 & \frac{1}{12} & 0 \\ 0 & 0 & -\frac{1}{8}\end{array}\right] \)

So, the inverse of \( A=\left[\begin{array}{rrr}4 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 3\end{arra \) is \( A^{-1} = \left[\begin{array}{rrr}-\frac{1}{6} & 0 & 0 \\ 0 & \frac{1}{12} & 0 \\ 0 & 0 & -\frac{1}{8}\end{array}\right] \).

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After considering the speeds of the student and the teacher and the distance they ran in each case, we found that the students wins in all the races.

Speed is defined as the ratio of distance travelled to the amount of time it took. As speed simply has a direction and no magnitude, it is a scalar quantity.

An object is considered to be moving at a uniform speed when it travels the same distance in the same amount of time.

When an object travels a different distance at regular intervals, it is said to have variable speed.

Average speed is the constant speed determined by the ratio of the total distance travelled by an object to the total amount of time it took to travel that distance.

Given,

The length of the race = 100  yards

1st race

The speed of student = 10 yards/s

The speed of teacher = 3.75 yards / s

Time taken by student = distance / speed = 100/10 = 10s

Time taken by teacher = 100 / 3.75 = 26.67 s

So the student finishes the race because he/she took less time.

2nd race

Distance run by teacher = 100 - 10 = 90

Speed of teacher =  3.75 yards / s

Time taken by teacher = 90/3.75 =  24s

The distance and speed of the student are the same.

Time taken by student = 10 s

Still, the student finishes the race first.

3rd race

Distance run by teacher = 100 - 10 = 90

Speed of teacher =  3.75 * 2 yards /s = 7.5 yards/s

Time taken by teacher = 90/ 7.5 =  12s

The distance and speed of the student are the same.

Time taken by student = 10 s

Still, the student finishes the race first.

Therefore by considering the speeds of the student and the teacher and the distance they ran in each case, we found that the students wins in all the races.

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68% of the races he competed in had a finish time around 64.5 and 65.5 seconds.

The term "variance" (or "") refers to an assessment of the data's dispersion from the mean. A small variance implies that the data are grouped around the normal, and while a large standard deviation shows that the data are more dispersed.

[tex]\begin{aligned}& \mathrm{P}(\mu-\sigma < \mathrm{X} < \mu+\sigma) \approx 68 \% \\& \mathrm{P}(\mu-2 \sigma < \mathrm{X} < \mu+2 \sigma) \approx 95 \% \\& \mathrm{P}(\mu-3 \sigma < \mathrm{X} < \mu+3 \sigma) \approx 99.7 \%\end{aligned}[/tex]

When the standard deviation out from mean of the distribution of X is and the mean of the dispersion of X is (assuming X is normally distributed).

Kiran's 400-meter dash timings have an average of 65 secs and a confidence interval of 0.5 seconds, and they are regularly distributed.

Using the formula, we then obtain

[tex]\mathrm{P}(65-0.5 < \mathrm{X} < 65+0.5)=\mathrm{P}(64.5 < \mathrm{X} < 65.5) \approx 68 \%[/tex]

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Out of 300 grams, 147 grams of food is not water in the given food sample.

If 51% of a certain food is water, then 49% of it must be something other than water. To find out how many grams of the food are not water, we can first calculate how many grams of water there are,

300 grams x 51% = 153 grams of water

Then we can subtract this from the total weight to find the amount of food that is not water -

300 grams - 153 grams = 147 grams of food that is not water

Therefore, out of 300 grams of nutrition, 153 grams are water and 147 grams are not.

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The we have shown that S is a subspace of Rn and that x + y ∈ S.

Suppose ~u1, ~u2, . . . , ~uk∈Rnand let S = span( ~u1, ~u2, . . . , ~uk). Suppose ~x, ~y ∈S.(d) Show that ~x + ~y ∈S.The solution is given as follows.The problem statement is given below.Suppose u1, u2, . . . , uk∈Rnand let S = span(u1, u2, . . . , uk). Suppose x, y ∈S. Show that x + y ∈S.To prove that x + y ∈ S, we must first prove that S is a subspace of Rn. We can then show that x + y is a linear combination of vectors in S, so it must be in S.Let's get started with the proof.Let S = span{u1, u2, . . . , uk} be a subspace of Rn. Then u1, u2, . . . , uk are linearly independent, which implies that they span S. Thus, any vector in S can be written as a linear combination of u1, u2, . . . , uk.Suppose x, y ∈ S. Then x = a1u1 + a2u2 + . . . + akuk, and y = b1u1 + b2u2 + . . . + bkuk, for some scalars a1, a2, . . . , ak and b1, b2, . . . , bk.Now we can show that x + y is a linear combination of vectors in S, so it must be in S.x + y = (a1 + b1)u1 + (a2 + b2)u2 + . . . + (ak + bk)ukSince a1, a2, . . . , ak and b1, b2, . . . , bk are scalars, (a1 + b1), (a2 + b2), . . . , (ak + bk) are also scalars. Thus, x + y is a linear combination of u1, u2, . . . , uk, and hence x + y ∈ S. Therefore, we have shown that S is a subspace of Rn and that x + y ∈ S.

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Answer:

Area of a triangle =L*W

A= 45*15

A=270cm²

The value of the expression (1×1,000)+(3×100)+(5×10)+(9×1/10)+(8 x 1/100) is 1,350.98.

To find the value of the expression (1×1,000)+(3×100)+(5×10)+(9×1/10)+(8 x 1/100), we need to simplify and perform the arithmetic operations.

Multiplying each term in the expression, we get:

1 × 1,000 = 1,000

3 × 100 = 300

5 × 10 = 50

9 × 1/10 = 0.9

8 × 1/100 = 0.08

Adding up all the terms, we get:

1,000 + 300 + 50 + 0.9 + 0.08 = 1,350.98

In summary, to find the value of the expression, we multiply each term by its respective coefficient, then add up all the terms. In this case, the result is 1,350.98.

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Complete question is:

Find the value of the expression (1×1,000)+(3×100)+(5×10)+(9×1/10)+(8 x 1/100)?

Using the Gaussian elimination method, the general solution is:               [tex]\[ x = -31t + 6 \][/tex], [tex]\[ y = 5 \][/tex], [tex]\[ z = 31t \][/tex].

To solve this system of equations, we can use the Gaussian elimination method. This method involves creating a matrix with the coefficients of the equations and using row operations to reduce the matrix to a form that can be easily solved.

First, we create a matrix with the coefficients of the equations:

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 2 & 3 & 2 & 3 \\ 2 & 1 & 2 & -7 \\ 1 & -3 & 2 & 10 \\ -1 & 3 & -1 & -6 \\ -1 & 3 & 2 & 6 \\ 6 & -2 & 2 & 4 \\ 3 & -1 & 2 & 2 \\ -12 & 4 & -8 & 8 \end{array} \right) \][/tex]

Next, we use row operations to reduce the matrix to a form that can be easily solved:

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & -1 & 0 & -5 \\ 0 & -4 & 1 & 11 \\ 0 & 4 & 0 & -5 \\ 0 & 4 & 1 & 7 \\ 0 & -8 & -4 & 10 \\ 0 & -4 & -1 & 5 \\ 0 & 8 & 4 & -4 \end{array} \right) \][/tex]

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 27 \\ 0 & 0 & -4 & 50 \\ 0 & 0 & -1 & 25 \\ 0 & 0 & 4 & -44 \end{array} \right) \][/tex]

[tex]\[ \left( \begin{array}{ccc|c} 1 & 0 & 1 & -6 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & -4 \\ 0 & 0 & 0 & 174 \\ 0 & 0 & 0 & 56 \\ 0 & 0 & 0 & -168 \end{array} \right) \][/tex]

From this reduced matrix, we can see that there are infinitely many solutions to this system of equations. The general solution can be written as:
[tex]\[ x = -31t + 6 \][/tex]
[tex]\[ y = 5 \][/tex]
[tex]\[ z = 31t \][/tex]
Where t is any real number.

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Answer:

IQR - 31

You first need to find the median. After find the middle number in the numbers before and after your median. This will give you your first and third quartile. Add these together then divide by two. This will give your IQR.

Answer:

66.5

Step-by-step explanation:

average the 2 together (57+76)/2