why the efficiency of the single movable pully system is not 100%​

Answers

Answer 1

Answer:

This is because part of the energy input is used to overcome gravity, inertia and friction

Answer 2
The efficiency of a single movable pulley system is not 100% this is because (i)The friction of the pulley bearing is not zero , (ii)The weight of the pulley and string is not zero. b) The efficiency of a movable pulley is always less than 100%. ... (a) In a single fixed pulley, some effort is wasted in overcoming friction between the strings and the grooves of the pulley; so the effort needed is greater than the load and hence the mechanical advantage is less than the velocity ratio. When you pull either up or down on the rope, the wheel will turn. This makes moving the object easier, because pulling a rope downward, for instance, is easier than lifting a heavy object upward. Of course, a single pulley will not affect the amount of work necessary to move an object very much.

Related Questions

A contact lens is made of plastic with an index of refraction of 1.60. The lens has an outer radius of curvature of 2.08 cm and an inner radius of curvature of 2.48 cm. What is the focal length of the lens?

Answers

Answer:

The value  [tex]f = 21.49 \ cm[/tex]

Explanation:

From the question we are told that

    The index of refraction is  [tex]n = 1.60[/tex]

     The outer radius of curvature is  [tex]R = 2.08 \ cm = 0.0208 \ m[/tex]

     The  inner radius is  [tex]r = 2.48 \ cm = 0.0248 \ m[/tex]

Generally from  Maker's equation we have that

       [tex]\frac{1}{f} = [n - 1 ][\frac{1}{(R)} - \frac{1}{r} ][/tex]

=>    [tex]\frac{1}{f} = [1.60 - 1 ][\frac{1}{( 0.0208 )} - \frac{1}{0.0248} ][/tex]

=>    [tex]\frac{1}{f} = 4.65[/tex]

=>    [tex]f = 0.2149 \ m[/tex]

=>    [tex]f = 21.49 \ cm[/tex]

Amy is in a tuck and skiing straight down a 30° slope. Air resistance pushes backward on her with a force of 10 N. The coefficient of dynamic friction between her skis and the snow is 0.08. Amy’s mass is 60 kg. What is the resultant of the external forces that act on Amy?

Answers

The resultant of the external forces that act on Amy are the force due to gravity, friction and air resistance which equals 243.26 N

Given that,

Force due to air resistance, [tex]F_{air}[/tex] = 10 N

Angle of slope, θ = 30°

Mass, m = 60 kg

Coefficient of dynamic friction, μ = 0.08

Force due to gravity, w = m g

w = 60 * 9.8 = 588 N

Since the slope is at an angle, the weight exerted on the ground is not along the axis of slope. So resolving the axis into its vertical and horizontal components,

cos θ = [tex]w_{y}[/tex] / w

[tex]w_{y}[/tex] = 588 * cos 30°

[tex]w_{y}[/tex] = 509.2 N

Frictional force, [tex]F_{fr}[/tex]  = μ * [tex]F_{N}[/tex]

where,

[tex]F_{N}[/tex] = Normal force = [tex]w_{y}[/tex]

[tex]F_{N}[/tex] = 509.2 N

[tex]F_{fr}[/tex]  = 0.08 * 509.2

[tex]F_{fr}[/tex]  = 40.74 N

sin θ = [tex]w_{x}[/tex] / w

[tex]w_{x}[/tex] = 588 * sin 30°

[tex]w_{x}[/tex] = 294 N

Force due to gravity, [tex]F_{g}[/tex] = [tex]w_{x}[/tex]

[tex]F_{g}[/tex] = 294 N

The resultant of external forces acting on Amy, [tex]F_{R}[/tex] =  [tex]F_{g}[/tex] - [tex]F_{air}[/tex] - [tex]F_{fr}[/tex]  

[tex]F_{R}[/tex] = 294 - 10 - 40.74

[tex]F_{R}[/tex] = 243.26 N

Therefore, the resultant of the external forces that act on Amy is 243.26 N

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The mass of an electron is 9.11 x 10-31 kg. If you want to increase the speed of the
electron from 90% of the speed of light to 95% of the speed of light (where the
speed of light is 2.997x108 m/s), the amount of work that must be done is:
8.2 x 10-13)
0 3.2× 10-13 ,
O 2.6% 10-13 ,
O 7.4× 10-14 ,
3.8 x 10-15)

Answers

I'm not sure of this question, yet i know you may get angry but, just know your loved and if going through a hard time i'm so so sorry, i know how it feels it sucks. take care of yourself, drink water, listen to that one song that makes you dance in your room and go do what YOU love. your beautiful your perfect and dont listen to what anyone says. i love u, everyone loves u, i know its scary but it happens to everyone life isnt a peice of cake unfortunatly and it sucks but woahh your strong! if you need someone to talk to leave a comment below, happy hoildays everyone!

P.S, im looking into the answer of this question. I may not answer it right on time (since i'm not the smartest...) but i promise ill try my best! Also, i am not doing this for points im doing this to make others smile. I hate how no one checks up on anyone, lots of people are going through a stressful time (including me) and i just want to let everyone know that its okay not to be okay! I hope that you all find happiness in every possible situation, once again  HAPPY HOLIDAYS!

8th grade science, Two questions.
Please help me​

Answers

Answer:

for 10 some advantages are that it has a much better bandwidth,low power loss, and it allows for longer transmission distance.

motion is a change in

Answers

i think it’s position measured by distance and time.

12) You find 13,406,190 pennies. If each penny weighs 4 grams, how much did all that loot weigh in lbs.? (2.2 lbs = 1 Kilogram)

(please show work!)​

Answers

Answer:

here is the answer

Explanation:

117974.472

A cyclist travels from point A to point B for 10 minutes. During the first 2.0 minutes of her trip, she maintains a uniform acceleration of 0.076 m/s2. She then travels at constant velocity for the next 5.0 minutes. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 minutes later

What is the acceleration during the last 3.0 minutes

Answers

Answer:

im not really good at explaining, but i found this website url:

https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/

same question just with the explanation

What makes ramps useful simple machines?
By increasing the distance, the force
required decreases
b. By increasing the distance, the required
work decreases
c. By increasing the force, the required
distance decreases

Answers

Answer:

It reduces the force necessary to move a load a certain distance up by providing a path for the load to move at a low angle to the ground.

Explanation:

Testosterone is used to treat breast cancer ? True or false?

Answers

Answer:

True

Explanation:

Because I had a test on this

What is matter ?


...​

Answers

Explanation:

a matter is solid gas and liquid

Answer:

matter is anything made of mass which occupys volume

Explanation:

matter is a thing which concludes mass and mentioned and also has volume ( volume is defined as space too) so everything is made of matter

The scientific method can easily be misinterpreted as ___________. Question 1 options: a great magical trick, or slide of hands, rather than factual an "auto mechanics" guide to Science Investigation a "cookbook" recipe for performing scientific investigations the perfect method for finding the answers to all questions

Answers

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

A bowling ball with a mass of 5 kg is rolled at an acceleration of 2 m/s2. What is the force of the bowling ball when it hits the pins? (Hint: Force = ?)

Answers

Answer:

[tex]F=10\ N[/tex]

Explanation:

[tex]We\ are\ given\ that,\\Mass\ of\ the\ bowling\ bowl=5\ kg\\Acceleration\ of\ the\ ball=2\ m/s^2\\Hence,\\As\ we\ know\ that\ F=ma\\Here,\\Force\ of\ the\ bowling\ ball\ when\ it\ hits\ the\ pins=Mass\ of\ the\ bowling\ bowl* its\ Acceleration.\\Hence,\\F=5*2\\F=10\ Newtons\\[/tex]

Clear selection
10 points
A laptop battery stores energy with an efficiency of 80%. If 16 000 J of
energy are transferred to the laptop from the battery, how much energy
must have been transferred to the battery?
20 kJ
20 J
1.28 kJ
12 800 J
Next
Page 1 of 2

Answers

Answer:

20000J or 20kJ

Explanation:

Given parameters:

Efficiency of the battery = 80%

Amount of energy transferred  = 16000J

Unknown:

How much energy was transferred to the battery = ?

Solution:

Since the battery is 80% efficient, it loses 20% of energy anytime it wants to store energy.

 Now, 16000J of energy is contained in the battery, the original amount of energy sent to the battery;

   Let the amount of energy sent to the battery be y

  80% of y  = 16000

       0.8y  = 16000

            y  = 20000J or 20kJ

Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .

Answers

Answer:

The value is [tex]L = 0.0073 \ H[/tex]      

Explanation:

From the question we are told that

    The number of turns is  [tex]N = 650 \ turns[/tex]

     The length is  [tex]l = 28 \ cm = 0.28 \ m[/tex]

      The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]

Generally the cross-sectional area  is mathematically represented as

       [tex]A = \pi * r^2[/tex]

=>    [tex]A = 3.142 * 0.035^2[/tex]

=>    [tex]A = 0.00384 \ m^2[/tex]

Generally the inductance is mathematically represented as

      [tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

=>    [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]

=>    [tex]L = 0.0073 \ H[/tex]      

Both the pressure and volume of an ideal gas of diatomic molecules are doubled. The ratio of the new internal energy to the old both measured relative to the internal energy at 0 K is

Answers

Answer:

The ratio of the new internal energy to the old is 4

Explanation:

let the old pressure of the gas = P₁

let the old volume of the gas = V₁

then, the new pressure of the gas = 2P₁

the new volume of the gas = 2V₁

The internal energy of the gas is given as;

PV = nRT

PV = k

P₁V₁ = P₂V₂

[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]

The ratio of the new internal energy to the old is 4

In the Vomitus carnival ride, passengers travel in a horizontal 4.0 m radius circle. For safe operation, the maximum sustained acceleration that riders may experience is 20 m/s2 , approximately twice the free fall acceleration. What is the period of the ride when it is being operated at the maximum acceleration?

Answers

Answer:

The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.

Explanation:

We can use the centripetal acceleration here:

[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]

Let's find the angular velocity ω at the maximum acceleration.

[tex]20=\omega^{2}*4[/tex]

[tex]\omega=2.24 rad/s[/tex]

The period is given by:

[tex]T=\frac{2\pi}{\omega}[/tex]

[tex]T=\frac{2\pi}{2.24}[/tex]

Therefore, the period will be T=2.81 s.

I hope it helps you!

A person travels by car from one city to another. She drives for 30.1 min at 82.1 km/h, 9.11 min at 83.1 km/h, 49.6 min at 41.3 km/h, and spends 18.7 min along the way eating lunch and buying gas. Determine the distance between the cities along this route. Answer in units of km.

Answers

The distance between the cities along the route is 87.95 Km

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

How to determine the distance travelled in 30.1 minsTime = 30.1 mins = 30.1 / 60 hourSpeed = 82.1 Km/hDistance =?

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 82.1 × (30.1 / 60)

Distance = 41.19 Km

How to determine the distance travelled in 9.11 minsTime = 9.11 mins = 9.11 / 60 hourSpeed = 83.1 Km/hDistance =?

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 83.1 × (9.11 / 60)

Distance = 12.62 Km

How to determine the distance travelled in 30.1 minsTime = 49.6 mins = 49.6 / 60 hourSpeed = 41.3 Km/hDistance =?

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 41.3 × (49.6 / 60)

Distance = 34.14 Km

How to determine the distance between the citiesDistance travelled in 30.1 mins = 41.19 KmDistance travelled in 9.11 mins = 12.62 KmDistance travelled in 49.6 mins = 34.14 KmTotal distance =?

Total distance = 41.19 + 12.62 + 34.14

Total distance = 87.95 Km

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100 Points!

A projectile is launched in the horizontal direction. It travels 2.050 m horizontally while it falls 0.450 m vertically and then strikes the floor. How long is the projectile in the air? Show your work.

B. What is the original velocity of the projectile described? Show your work.

Answers

Answer:

A)  0.303 s  (3 s.f.)

B)  6.76 ms⁻¹  (3 s.f.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

Part A

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]s=0.450\quad u=0\quad a=9.8[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\0.450&= (0)t+\dfrac{1}{2}(9.8)t^2\\0.450&= 4.9t^2\\t^2&= \dfrac{0.450}{4.9}\\t&=\sqrt{\dfrac{0.450}{4.9}\\t &=0.3030457634...\\ \implies t&=0.303\:\sf s\;\;(3\:s.f.)\\\end{aligned}[/tex]

Part B

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]s=2.050 \quad a=0 \quad t=0.3030457634...[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\2.050&= u(0.3030457634...)+\dfrac{1}{2}(0)(0.3030457634...)^2\\2.050&= 0.3030457634...u\\u&= \dfrac{2.050}{0.3030457634...}\\ u &=6.764654873...\\\implies u & = 6.76\:\sf ms^{-1}\;\;(3\:s.f.)\end{aligned}[/tex]

A pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s, therefore the pig is __________during the next 2 seconds.

Question 7 options:

moving faster in the negative direction


moving faster in the positive direction


moving slower in the positive direction


moving slower in the in the negative direction

Answers

Answer:

Moving slower in the negative direction.

Explanation:

This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.

Which term is described as a seamount with a flattened top?


deep-sea trenches


guyots

continental shelf


abyssal plains

Answers

The term which is described as a seamount with a flattened top is called as guyots.

Guyot, commonly known as Tablemount, is an uninhabited submarine volcano with a flat peak that is more than 200 meters (660 feet) above sea level. These flat summits could be more than 10 kilometres in circumference (6 miles).

Seamounts called guyots have grown above sea level. The seamount's top was eroded by erosion by waves, leaving it with a flattened shape. The sea bottom gradually falls as a result of the ocean floor moving away from oceanic ridges, submerging the flattened guyots to form undersea flat-topped peaks. Once the guyot is formed, on it's top a coral colony will start developing and little by little make a circle shaped island, which represents the formation of the atoll.

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A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of 3.50 s. Find the force constant of the spring.

Answers

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]

Hence the force constant of the spring is 17.71N/m

A copper rod has a length of 1.7 m and a cross-sectional area of 3.2 × 10-4 m2. One end of the rod is in contact with boiling water and the other with a mixture of ice and water. What is the mass of ice per second that melts? Assume that no heat is lost through the side surface of the rod.

Answers

Given :

A copper rod has a length of 1.7 m and a cross-sectional area of [tex]3.2 \times 10^{-4} \ m^2[/tex].

One end of the rod is in contact with boiling water and the other with a mixture of ice and water.

To Find :

The mass of ice per second that melts.

Solution :

Amount of heat transfer from boiling water to ice through the copper bar is :

[tex]Q = \dfrac{kA\Delta T }{L}\\\\Q = \dfrac{390\times 3.2 \times 10^{-4} \times 100}{1.7}\\\\Q = 7.34 \ J/s[/tex]

Let, amount of ice melts per second is :

[tex]m=\dfrac{Q}{L_f}[/tex]

Here, [tex]L_f[/tex] is the latent of fusion of water and is equal to [tex]L_f = 3.34\times 10^5 \ J/s[/tex].

Putting all values in above equation, we get :

[tex]m=\dfrac{7.34}{3.34\times 10^5}\\\\m = 2.19 \times 10^{-5} \ kg/s[/tex]

Hence, this is the required solution.

A stunt man drives a car at a speed of 20m/s off a 30-m-high cliff. The road leading to the cliff is inclined upward at an angle of 20 degrees. How far from the base of the cliff does the car land?

Answers

The car lands at a distance of 60 m from the base of the cliff.

s = ut + 1 / 2 a[tex]t^{2}[/tex]

s = Displacement

u = Initial velocity

t =Time

a = Acceleration

u = 20 m / s

[tex]s_{y}[/tex] = 30 m

θ = 20°

g = 9.8 m / s²

Resolving the velocity into its horizontal and vertical components

sin θ = [tex]u_{y}[/tex] / u

[tex]u_{y}[/tex] = - 20 sin 20°

[tex]u_{y}[/tex] = - 6.84 m / s

Considering only the vertical components,

[tex]s_{y}[/tex] = [tex]u_{y}[/tex] t + 1 / 2 g t²

30 = - 6.84 t + 4.9 t²

4.9 t² + ( - 6.84 ) t - 30 = 0

This is in the form of a quadratic equation,

t = - ( - 6.84 ) + √ [ ( - 6.84 )² - ( 4 * 4.9 * ( - 30 ) ) ] / 2 ( 4.9 )

t = 3.2 sec

The distance we need to calculate is in horizontal direction,

[tex]v_{x}[/tex] = [tex]s_{x}[/tex] / t

[tex]s_{x}[/tex] = 20 cos 20° / 3.2

[tex]s_{x}[/tex] = 60 m

Therefore, the car lands at a distance of 60 m from the base of the cliff.

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On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.
If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?

Answers

Answer:

The increase in pressure inside the lungs is 0.09 atm

Explanation:

From the Pressure law

Pressure law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature provided that the volume remains constant.

That is,

P ∝ T

Where P is the Pressure and T is the temperature.

Then, we can write that

P = kT

Where k is the proportionality constant

∴ [tex]\frac{P}{T} = k[/tex]

Then,

[tex]\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }[/tex]

From the question, [tex]P_{1}[/tex] = 1.0 atm

[tex]{T_{1}[/tex] = 12 °C = (12 + 273.15) K = 285.15K

[tex]{T_{2}[/tex] = 37 °C = (37 + 273.15) K = 310.15K

Therefore,

[tex]\frac{1.0}{285.15} = \frac{P_{2} }{310.15}[/tex]

[tex]P_{2} = \frac{1.0 \times 310.15}{285.15}[/tex]

[tex]P_{2} = 1.09[/tex] atm

Increase in pressure = [tex]P_{2} - P_{1}[/tex] = 1.09 atm - 1.0 atm

Increase in pressure = 0.09 atm

Hence, the increase in pressure inside the lungs is 0.09 atm

At constant volume, pressure of the gas is directly proportional to the temperature of the gas. The increased pressure inside the lungs is 0.9 atm.

From Gas law,

[tex]\bold {\dfrac {P_1} {T_1 } = \dfrac {P_2} {T_2 } }[/tex]

Where,

P1 - initial pressure = 0.1 atm

P2 - final pressure = ?

T1 - initial temperature = 12 °C = (12 + 273.15) K = 285.15 K

T2 - final temperature = 37 °C = (37 + 273.15) K = 310.15 K

Put the values in the formula,

[tex]\bold {\dfrac {1.0} {285.15 } = \dfrac {P_2} {310.15 } }[/tex]

[tex]\bold {P_2 = 1.09\ atm}[/tex]

Thus, increased pressure in the lungs

= 1.9 - 1.0

= 0.9 atm

Therefore, the increased pressure inside the lungs is 0.9 atm.

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QUESTION 1
energy is the work done by a force acting through a distance.

Answers

[tex]acslerishne[/tex]

A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How far did the ball travel horizontally when it hit the ground?
15.4 m
38.5 m
67 m
45.5 m

Answers

Answer:

38.5

Explanation:


Elements known as noble gases do not have the ability or the room in their valence
electron shell to form bonds with other elements.
O True
O False

Answers

Answer:

true

Explanation:

noble gases are octet meaning they they have eight electrons in their outer shell so the are stable

The sound level at 1.0 m from a certain bullfrog is 60 dB. You are surrounded by 18 such bullfrogs, all 1.0 m from you and all croaking equally loudly at the same time. What sound level are you being exposed to

Answers

Answer:

The value is  [tex]S_a = 72.56 \ dB[/tex]

Explanation:

From the question we are told that

     The sound level is  [tex]S = 60 dB[/tex]

     The distance from the source is d = 1 m  

     The number of sources  is  n =  18

     

Generally the sound which the person is been exposed to is mathematically represented as

            [tex]S_a = S + 10log(18)[/tex]

=>         [tex]S_a = 60 + 10log(18)[/tex]

=>         [tex]S_a = 72.56 \ dB[/tex]

A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonball hits the ground?
96.7 s
55.3 s
65.3 s
45.5 s

Answers

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

What is the velocity of a group of explorers traveling from Antarctica to Australia, traveling 1500 miles in 48 hours?31.25 mph south
72,000 mph
48 mph
31.3 mph north

Answers

Answer:

31.3mph North

Explanation:

Given parameters:

Distance traveled  = 1500miles

Time taken  = 48hrs

Unknown:

Velocity of the group of explorers = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 So;

       Velocity = [tex]\frac{displacement}{time}[/tex]

Displacement is the distance moved in a specific direction = 1500miles North

 Insert the parameters and solve;

   Velocity = [tex]\frac{1500}{48}[/tex]   = 31.3mph North

Other Questions
research has demonstrated that which parental practice is associated with less hostility in sibling relationships? does the narrator seem trustworthy as he gives his account of the events in the story? cite evidence from the text to explain your opinions. The day was humid.What part of speech is "day?" Which of the following minerals from your lab is metallic? (E.S. 5.2)O haliteO sulfurO pyriteO diamond Which of the following ordered triples is the solution to the system of equations?2x y z = 13x + y z = 2x + y 5z = 8 For each of the following, state whether it is an organelle, a cell, a tissue, an organ, an organ system or an organism A heart B trachea C onion epidermis D onion bulb E onion plant F human being G lungs Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square. 100 points and brainliest a postmenopausal client has been prescribed ibandronate (boniva) 3 mg intravenously every 3 months. boniva is available 1 mg/ml. how many ml should the nurse administer? a 46-year-old man is currently enrolled in a phase 2 study of a drug for severe diabetic neuropathy. while the study is on-going, a new drug becomes carlys cupcakes calculated $10,000 in depreciation expense for its baking equipment in the first quarter. what is the adjusting journal entry carly must record to recognize this expense? My mom plans to drop off Uncle Eric at the airport as he begins his trip to Europe. Find the missing number so that the equation has no solutions.x+1=2x6 Select all the correct answers. a scientist carried out several different procedures, each of which caused a change in matter. select each procedure that is likely a chemical change. salt crystals were crushed into a fine powder. bubbles were produced when iron was placed in acid. two liquids were combined, and a solid appeared. a piece of metal melted when it was heated. a white substance turned blue when water was added. A shop displays a total of 50 type A and type B mice. The cost of a type A mouse is $6 and that of a type B mouse is $13. If the total cost of all 50 mice is $433, find the number of type A mice displayed. The answers is 31 Write a letter to your sister who lives in another part of the country, telling her about all that has happened.In your letter you should cover the following points: Which equation represents a line through (4, -6) and (0, 2)? Have you ever been to a zoo? You were probably able to see many animals that you had only ever seen in a science textbook. The experience you had at the zoo was probably memorable and taught you things you never knew before.Zoos allow animals to live in a safe environment. These animals do not have to worry about the threat or stress of predators. They do not have to deal with the irritation or pain of injuries and illnesses that they would if they lived in the wild. Animals in the zoo are given top-quality treatment when they are hurt or in need of special care. The animals are hydrated and fed, and zookeepers are sure to give them a high-quality diet with all the nutrients needed. A good zoo provides great care and protection for the animals in their care. Because there are many species of animals in danger of going extinct, zoos provide an even more important role in our world. Zoos help protect species going extinct. A species that is kept in captivity is a zoos effort to help rebuild the population. Once the population is rebuilt, the zoos can reintroduce the animals to the wild. Without zoos, many more species would be extinct. When an animal species is extinct, there is no new research that can be done. Many children and adults enjoy seeing animals in person. Kids learn seeing, hearing, smelling and watching what an animal does. This allows humans to have a greater understanding of animal species that they would never have had the chance to learn about if zoos did not exist. When we as humans have opportunities to learn about the animals on our planet, we can make the right decisions in order to keep our ecosystems successfully functioning.1. What is the authors message? In the other circles (4), write the authors evidence and reasons you found in the text.2. Why did the author write this?3. Find one sentence that supports the authors claim that zoos are an enjoyable experience for visitors.4. What claim is the author making in paragraph 2?5. Find one piece of evidence that supports your answer to #4. The sum of three lengths of a fence ranges from 45 to 60 inches. Two side lengths are 9 and 18 inches. If the length of the third side is x inches, write and solve a compound inequality to show the possible lengths of the third side. a. 9 x 18 b. 18 x 33 c. 36 x 42 d. 45 x 60 cos x + sin x tan x = sec x ill give uu crown if you answer this for me