When the electrons accelerated through a potential difference of 84 kV, the electrons have half the speed that she wishes.
When the potential is quadrupled to 336 kV, the electrons acquire the desired speed.
Let u be the speed of the electrons after accelerating through a potential difference ΔV.
Now,
K = eΔV = (γ - 1)mc² where K is the kinetic energy.
K = (γ - 1)mc² =[ 1/ ( √1 - (u/c)² ) - 1]mc²
Therefore,
[ 1/ ( √1 - (u/c)² ) - 1] = (eΔv / mc² ) + 1 = (eΔV + mc² ) / (mc²)
1 - (u/c)² = [ (mc²) / (eΔV + mc² ) ]²
u/c = √[ 1 - ( m / {(eΔV/c²) + m})² ]
u / c = √[ 1 - ( 9.11 × 10⁻¹³ / {(1.6 × 10⁻¹⁹ × 8.4 × 10⁴ /(3 × 10⁸)² + 9.11 × 10⁻¹³ })² ]
u = 0.512c
Despite the increased accelerating voltage, this speed cannot be doubled because it is greater than half that of light. The electrons move at u = 0.798c faster if the accelerating voltage is quadrupled to 336 kV.
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explain the way to get wind energy for our use
Answer:
YOUR ANSWER IS HERE....
Wind turbines work on a simple principle: instead of using electricity to make wind—like a fan—wind turbines use wind to make electricity. Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.USES OF THE WIND ENERGY.generating electricity.generating electricity.milling grain.generating electricity.milling grain.pumping water.generating electricity.milling grain.pumping water.powering cargo ships (via kites)generating electricity.milling grain.pumping water.powering cargo ships (via kites)reducing carbon footprint.generating electricity.milling grain.pumping water.powering cargo ships (via kites)reducing carbon footprint.sailing.generating electricity.milling grain.pumping water.powering cargo ships (via kites)reducing carbon footprint.sailing.windsurfing.generating electricity.milling grain.pumping water.powering cargo ships (via kites)reducing carbon footprint.sailing.windsurfing.land surfing.HOPE IT HELPS! MARK AS BRAINLIAST.M A uniformly charged ring of radius 10.0cm has a total charge of 75.0μC . Find the electric field on the axis of the ring at from the center of the ring.(b) 5.00 cm,
The electric field on the axis of the uniformly charged ring at the center of the ring at 5.00cm is 2.41×〖10〗^7 N/C
Where a positive charge (q) is given, always note that the charges point away from the electric field. The expression used to calculate the electric field away from the center of the ring is given by the equation below,
E=(K_e×b)/(r^3×Q)
Where
E is Electric field
Ke is electric field constant
a is radius of the charge q from the center of the circle
Q is electric charge = 75.0μC
The radius of the charge is a = 10cm= 0.1m
Distance from the electric field = 5cm = 0.05m
Ke is a constant given as 8.99×〖10〗^(9 ) Nm^2/c^2
E=(8.99×〖10〗^(9 ) Nm^2/c^2×0.05)/(〖0.1〗^3×75×〖10〗^(-6) )
E=2.41×〖10〗^7N/C
Therefore, the electric field away from the center of the ring is 2.41×〖10〗^7N/C away from the center of the ring
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Giving brainliest!!! Pls answer
Is a rocket in the process of launching Balanced or Unbalanced force?
Answer: I don't know the right answer but it makes more sense for it to be balanced
Explanation:
Assume two identical sinusoidal waves are moving through the same medium in the same direction. Under what condition will the amplitude of the resultant wave be greater than either of the two original waves?(a) in all cases(b) only if the waves have no difference in phase (c) only if the phase difference is less than 90°(d) only if the phase difference is less than 120° (e) only if the phase difference is less than 180°
The correct options are B and C
Let us assume the amplitude of the two sinusoidal waves to be A1 and A2
Since, it is mentioned that the waves are identical, therefore let us assume A1=A2= a
The resultant wave of any two waves is given by the formula:
Resultant wave , R = [tex]\sqrt{A1^2+A2^2+2A1A2cos\alpha }[/tex]
where A1 and A2 are amplitudes of wave 1 and 2 and [tex]\alpha[/tex] is the angle between the waves
Now as per the formula, it is the the factor 2cos[tex]\alpha[/tex] that will decide that amplitude is greater than original or not
Hence we know that maximum value of cos [tex]\alpha[/tex] is when [tex]\alpha[/tex] is 0 degrees
Now it is known that value of cos[tex]\alpha[/tex] varies from 1 to 0 for o degrees to π/2
and the value varies from 0 to -1 for angle π/2 to π angle
Case 1: when [tex]\alpha[/tex]=0 degree
Resultant wave R = [tex]\sqrt{A1^2+A2^2+2cos0A1A2}= \sqrt{2A^2+2A^2}=\sqrt{4A^2} =2A[/tex]
Case 2: When [tex]\alpha[/tex] is less than 90
let us consider [tex]\alpha = 45 degree[/tex]
Resultant wave R =
[tex]\sqrt{A1^2+A2^2+2cos45A1A2}= \sqrt{2A^2+2A^2/2}=\sqrt{3A^2} =\sqrt{3} A[/tex]
case 3:
When [tex]\alpha[/tex] is less than 120
[tex]\sqrt{A1^2+A2^2+2cos120A1A2}= \sqrt{2A^2-2A^2/2}=A[/tex]
case 4: when [tex]\alpha[/tex] is less than 180 degrees
the value will be 0
Hence only option b and d are correct
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An apple is falling from a tree. Disregarding air resistance, which diagram shows the free-body diagram of the force or forces acting on the apple?
Answer:
The straight down arrow
Explanation:
Next time add a picture to also help those who would like to answer. :)
A student times a car travelling a distance of 2m. She finds that it takes the car 5 seconds to travel the first meter, and 8 to travel the second meter. Is the car traveling at a constant speed? How do you know?
The car given in the question is not traveling at a constant speed as the time interval in which it to cover the equal distance is not equal.
Speed is the physical quantity that measures the rate at which the position of a body is changing with respect to its surrounding. Its S.I. unit is meters per second. And its dimensional equation is [[tex]LT^{-1}[/tex]]
Given in the Question
Time to travel first meter = 5 seconds
Time to travel second meter = 8 seconds
The body is said to be moving with a constant speed if it travels an equal distance in equal intervals of time.
But in the above-given condition, the car travels 1m in 5 seconds but travels the next 1m in 8 seconds. Here the distance traveled is equal but the time interval in which both distances are covered is not equal.
Therefore, the car is not traveling at a constant speed.
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M A particle with positive charge q = 3.20 ×10⁻¹⁹C moves with a velocity →v = (2i + 3j - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle (in unit-vector notation), taking B = (2i + 4j + k) T and E =(4i - j - 2k ) V ,
The Magnitude of force on the charged particle is -
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.
We have to determine the total force on the moving particle.
What is Lorentz Force?The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force. Mathematically -
|F| = qE + qv x B
According to the question, we have -
q = 3.20 × 10⁻¹⁹C
v = (2i + 3j - k) m/s
B = (2i + 4j + k) T
E = (4i - j - 2k) V
Now, using the formula to calculate Lorentz force -
F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)
F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)
F = q(4i - j - 2k) + 0
F = q(4i - j - 2k)
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
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A seat on a Ferris wheel moves at a constant tangential speed around the wheel. If the seat is 7 m from the center of the wheel and has a tangential speed of 0.5 m/s, what centripetal acceleration does the seat experience?
0.04 m/s2
0.07 m/s2
0.1 m/s2
Answer:
centripetal acceleration formula
a = v²/r
v velocity
r radius
a= .5²/7
a = .25/7
a= .03571
ans .o3571
Answer:
A
Explanation:
Ricardo came up with three different designs for paper airplanes. He would like to find out which design flies the farthest. Ricardo plans to fly each paper airplane five times. What step should ricardo take after he flies each plane?.
Ricardo came up with the three different paper airplane designs. Ricardo plans to fly each paper airplane five times to see which design flies the furthest. Ricardo should calculate the aircraft's flight distance after each flight and record it.
How can one determine a distance?Two of the most popular methods in agricultural surveying involve taking measurements of angles and distances with simple equipment. even when the equipment is simple. A high level of precision can be reached with perseverance and practice.
The primary method for measuring distance is (1) pace. The mileage counter. (3) taping or chaining four phases and (6) methods for electronic distance measurement, optical range finders (EDM).
It will be helpful to first examine the common units of distance (displacement). Common English units are as follows:
A foot is made up of 12 inches (in)
Yd (yard) equals 3 ft (ft)
The length of one rod is 16.5 feet and 5.5 yards (yd)
5280 feet, 1760 yards, and 320 rods make up a mile.
The units cancellation method is very helpful when converting between different units of measurement.
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The proportions and arrangement of atoms in any compound are always
the same
or
different
an electron and a proton are fixed at a separation distance of 897 nm. find the magnitude ???? and the direction of the electric field at their midpoint.
The electric field at a midpoint is 1.425 x 10⁴ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 =e = 1.6 x 10¯¹⁹ C
Q2 = e = 1.6 x 10¯¹⁹ C
x = 897 nm = 8.97 x 10¯⁷ m
from midpoint (r = 4.495 x 10¯⁷ m)
The electric field radially outward from proton to electron so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.e/r² + k.e/r²
Etotal = 2. k.e/r²
Etotal = 2 x 9 x 10⁹ x 1.6 x 10¯¹⁹/(4.495 x 10¯⁷)²
Etotal = 1.425 x 10⁴ N/C
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at the surface of a freshwater spring, a manatee with a small amount of air in its lungs is neutrally buoyant. the manatee now dives to a depth of 10 m.
At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.
As a result, the manatee now becomes negatively buoyant and must rise to compensate.
What does it mean when something has neutral buoyancy?When something has neutral buoyancy, it is not affected by the weight of anything above or below it.
This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.
Examples of things with neutral buoyancy include air balloons and swimming caps.
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a horse track is a loop where the starting point and the finish line are at the same point. a horse gallops around a 400 m track in 20 s. calculate the velocity of the horse.
The velocity of the horse as it travels through the track is 20 m/s.
What is velocity?Velocity can be defined as the ratio of distance or displacement to time.
To calculate the velocity of the the horse, we use the formula below.
Formula:
v = d/t............... Equation 1Where:
v = velocity of the horsed = distancet = timeFrom the question,
Given:
d = 400 mt = 20 sSubstitute these values into equation 1
v = 400/20v = 20 m/s²Hence, the velocity of the horse as it travels through the track is 20 m/s.
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Answer:
A. 2s
Explanation:
time = distance ÷ speed
T = .2 ÷.1
T= 2
When a wave encounters an obstacle or a slit that is comparable in size to its wavelength, it bends around it. This characteristic is called ________.
When a wave encounters an obstacle or a slit that is comparable in size to its wavelength, it bends around it. This characteristic is called diffraction.
Diffraction refers to the phenomenon in which a propagating wave bends when it encounters an obstacle or a slit, especially when the obstacle or slit is similar in size to the wavelength of the wave.
The characteristic pattern produced from a diffracted wave is as a result of the interference of individual spherical wavelets, as described by the Huygens–Fresnel principle. Diffraction occurs in all waves, including water waves, sound waves, electromagnetic waves and even gravitational waves.
Sound waves can also diffract around objects. For example, a person is able to hear his name being called even though he is standing at the other side of an obstacle, as the sound waves bend around the obstacle.
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Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire is 5.00 A. (b) Are the currents in the same direction or in opposite directions?
The currents in the wires are in opposite directions.
Two long parallel wires separated by a distance 'r' having current I₁ and I₂ have force per unit length that is given by [tex]f=\frac{u_0 I_1I_2}{2\pi r}[/tex] .....(1) where is permittivity of free house whose worth is [tex]4\pi \times10^{-7}Tm/A[/tex]If this flowing through the wire are in same direction then they the wire attract each other and if this flowing through the wire are opposite in direction then they the wire repel each other .
As it is given that a pair of wires repel each {other} which suggests that current inside the wires area unit in other means .
Hence current flowing through wires area unit opposite in direction.
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what happens when a charged insulator is placed near an uncharged metallic object? they exert no electrostatic force on each other. they repel each other. they may attract or repel each other, depending on whether the charge on the insulator is positive or negative. the charged insulator always spontaneously discharges. they attract each other.
A metallic item becomes polarised when a charged insulator is brought close to it, as a result of the free charges in the metal moving about. The centre of charge for the type of charge opposite to that on the insulator will be positioned within the metallic item closer to the charged insulator .
What happens if a charged insulator comes into contact with a conductor?When a negatively charged insulator is in contact with a positively charged conductor, the extra negatively charged electrons will migrate to the conductor until they would prefer not to move at all. We refer to this as the system having attained equilibrium when it occurs.
When an uncharged metal item and a charged insulator are positioned close to one another, the charged insulator will induce the opposite charge, and the two objects will be drawn to one another.
The insulator and a metallic item are therefore attracted to one another by the net electric force.
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The sound level at a distance of 3.00m from a source is 120dB . At what distance is the sound level (a) 100 dB
The distance at which the sound level is 100 dB is 30m.
What is distance?Distance is a measurement of how far apart two objects or locations are. Distance in physics or common language can refer to a physical length or an estimate based on other factors (e.g. "two counties over"). |AB| is a symbol that can be used to represent the distance between two points. "Distance from A to B" and "Distance from B to A" are frequently used interchangeably. A distance function or metric is a technique to describe what it means for elements of some space to be "close to" or "far away" from each other in mathematics. It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and other social sciences.
Explanation:
We anticipate the radial distance to be 10 times greater, or 30 m, when the intensity is reduced by 20 dB, or by a factor of 102. A further 90 dB reduction might translate to an additional factor of 104.5 in terms of distance, or roughly 3030000m or 1000 miles. We measure sound intensity using the inverse square law and the decibel scale definition. According to the sound level definition,
β=10log[tex](\frac{1}{10^{-12}W/m^{2} } )[/tex]
We can compute the intensities corresponding to each of the levels mentioned as
[tex]I=[10^{\frac{\beta }{10} } ]10^{-12} W/m^{2}[/tex]
a. The power passing through any sphere around the source is
P=4π[tex]r^{2}[/tex]l
If we ignore absoption of sound by the medium,
conservation of energy requires that
[tex]r_{120} ^{2} I_{120} = r_{100}^{2} I_{100} =r_{10} ^{2} I_{10}[/tex]
then,[tex]r_{100} =r_{120} \sqrt{x} \frac{I_{120} }{I_{100} } =(3.00m)\sqrt{\frac{1\frac{W}{m^{2} } }{10^{-2}\frac{W}{m^{2} } } } =30 m[/tex]
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a 3.5 kg block is pushed along a horizontal floor by a force : f of magnitude 15 n at an angle ???? 40° with the horizontal (fig. 6-19). the coefficient of ki- netic friction between the block and the floor is 0.25. calculate the magnitudes of (a) the frictional force on the block from the floor and (b) the block’s acceleration.
The frictional force is 11 N and the block’s acceleration is 0.14 m/s².
What is the coefficient of friction?It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction, the lower the friction between the surfaces, and the higher coefficient of friction the higher the friction force between them.
For part (a):
Taking x component:
F(x) = F cosθ
Taking y component:
F(y) = -F sinθ
Applying Newton’s second law to the y-axis:
F(N) = 15 sin40 + (3.5)(9.8)
F(N) = 44 N
coefficient U = 0.25
f(k) = 11 N
For part (b):
Applying Newton’s second law to the x-axis:
a = ((15) cos40 - 11)/3.5
a = 0.14 m/s²
Thus, the frictional force is 11 N and the block’s acceleration is 0.14 m/s².
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Two spheres are made of the same metal and have the same radius, but one is hollow and the other is solid. The spheres are taken through the same temperature increase. Which sphere expands more?.
The expansion of both will be the same. Then the correct option is C.
What is thermal expansion?Thermal expansion, which often excludes phase transitions, is the propensity of matter to alter its form, area, volume, and concentration in response to a variation in heat.
The same metal is used to create two identically sized spheres, but only one is solid and the other is hollow. The same rate of warming is applied to the spheres.
The formula for the thermal expansion is given as,
[tex]\rm \alpha _L = \dfrac{1}{L} \cdot \dfrac{dL}{dT}[/tex]
[tex]\alpha_{L}[/tex] = thermal expansion
L = particular length measurement
dL = change in length
dT = change in temperature
If the material of the sphere is the same, then the coefficient of the expansion of the sphere is the same, then the expansion of both will be the same.
Both will expand at the same rate. Then, C is the right answer.
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A series of pulses, each of amplitude 0.1m , is sent down a string that is attached to a post at one end. The pulses are reflected at the post and travel back along the string without loss of amplitude.(ii) Next assume the end at which reflection occurs is free to slide up and down. Now what is the net displacement at a point on the string where two pulses are crossing? Choose your answer from the same possibilities as in part (i).
(ii) The net displacement at a point on the string where the pulses cross is 0.2 m.
The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.
A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.
At the post, the pulses are reflected and return along the string without losing any of their amplitude.
Now, let's say the ends are free.
There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.
Now, since A = 0.1 m
Then, 2A = 2(0.1) = 0.2 m
As a result, the net displacement at the string's intersection of two pulses is 0.2 m.
The correct option is (c).
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a 1,500 kg car moving with a speed of 4.00 m/s collides with a 50,000 kg truck moving with a speed of 1.80 m/s in the same direction. if the collision is perfectly inelastic, the change in kinetic energy of the car is . group of answer choices -14,600 j -9,390 j none of these -2,600 j 12,000 j
the change in kinetic energy of the car is None of these
perfectly inelastic collision - It is the physical process. Of one object which strike against another without conserving the kinetic energy of to object.
m₁ = 1,500 kg (mass of car)
v₁ = 4.00m/s (velocity of car)
m₂= 50000kg (mass of truck)
v₂ = 1.80m/s (velocity of truck)
for perfectly elastic collision
[tex]v_{f}[/tex]=?
[tex]m_{1} .v_{1,i} + m_{2} .v_{2,i} =( m_{1} + m_{2} ).v_{f}[/tex]
1500*4 + 50000*1.80
= (1500 + 50000) [tex]v_{f}[/tex]
[tex]v_{f}[/tex] = 1.864 m/s
Initial kinetic energy is
K.E (i) = [tex]\frac{1}{2} m_{1} .v_{1,i} ^{2} + \frac{1}{2} m_{2} .v_{2,i}^{2}[/tex]
[tex]\frac{1}{2}[/tex]× [(1500*4²) +(50000)*(1.8)²
= 93000J
Final kinetic energy is
K.E = [tex]\frac{1}{2}(m_{1} +m_{2} )v_{f}^{2}[/tex]
[tex]\frac{1}{2}[/tex]× ((1500+50000)*(1.864 )²
= 89476 J
Change in kinetic Energy
K.E = K.E (f) - K.E (i)
= 89476 -93000
= -3524 J
the change in kinetic energy of the car is None of these
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Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(e) what time interval is required for the ball to reach Dina?
The time interval with respect to Ed is 4.88 ×10³ s.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In the frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Now, for time intervals using the Lorentz transformation equation:
Δt = 1 / [ √( 1 - (v²/c²)] ( Δt' + (vΔx'/c²))
Now, v = 0.6c as S' is moving with respect to frame S.
Hence, the time taken is:
Δt = 1 / [ √( 1 - ((0.6c)²/c²)] ( 7.5 ×10³ + [(-0.6c)(1.8 × 10¹²)/c²))
Δt = 1.25( 75000 - 3600)
Δt = 4.88 ×10³ s
The total time taken by the ball with respect to Ed is 4.88 ×10³ s.
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Compared with a 1-kg block of solid iron, a 2-kg block of solid iron has the same select one:
a. mass.
b. volume.
c. weight.
d. all of these
e. none of these
The content of matter in a body is called mass. Weight can be defined as the amount of force required to accelerate an object with mass, while volume is the space occupied by the mass.
On comparing with 1-kg block of solid iron, a 2-kg block of solid iron, mass is different for both the blocks.
So (a) mass cannot be the correct option.
According to this formula ,[tex]Density = \frac{Mass}{Volume}[/tex] , Density for both the blocks would be same, so volume will be different for both the blocks because of the different masses.
So (b) Volume cannot be the correct option.
Weight is mass dependent therefore
(c) weight cannot be the correct option
Since (a), (b), (c), are incorrect so (d) can not be the correct answer
Therefore on Comparing a 1-kg block of solid iron, with a 2-kg block of solid iron, (e) none of these would be same.
Correct option is (e)
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1. A cat weighs 8.9 pounds. What is its weight in kilograms?
2. How many grams are in 5.4 kilograms?
3. A marathoner runs 26.2 miles in the New York marathon. What distance did she run in kilometers?
4. You drink 1000 mL of Mountain Dew. How many fluid ounces did you consume?
5. A flash drive can hold up to 8 Megabytes of information. How many centibytes can it hold?
Show ALL Work and Use 3 sig figs
The weight of the car in kilogram is 4.04 kg.
The Mass of the substance in grams is 5,400 g.
The Distance of the marathoner in kilometers is 42.2 km.
The Volume of the Mountain dew in ounces is 33.8 oz.
The Capacity of the flash drive in centibytes is 8 x 10⁸ CB.
What is unit conversion?Unit conversion is used to convert the units of some measurement into other units.
The weight of the car in kilogram is calculated as follows;
1 pound = 0.453592 kg
8.9 pounds = ?
= (8.9 x 0.453592 kg)
= 4.04 kg
The mass of the substance in grams is calculated as follows;
1 kg = 1000 g
5.4 kg = ?
= (5.4 x 1000 g)
= 5,400 g
The distance of the marathoner in kilometers is calculated as follows;
1 mile = 1.609 km
26.2 miles = ?
= (26.2 x 1.609 km)
= 42.2 km
The volume of the Mountain dew in ounces is calculated as follows;
1 ml = 0.0338 oz
1000 ml = ?
= (1000 x 0.0338 oz)
= 33.8 oz
The capacity of the flash drive in centibytes is calculated as follows;
1 MB = 1 x 10⁸ CB
8 MB = ?
= (8 x 10⁸ CB)
= 8 x 10⁸ CB
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Standing at a crosswalk, you hear a frequency of 560 Hz from the siren of an approaching ambulance. After the ambulance passes, the observed frequency of the siren is 480 Hz . Determine the ambulance's speed from these observations.
[tex]Given data : f01 = 560 hz f02 = 480 hz vs = 340 m/s ( velocity of sound ) vx = velocity of source ( police car )Condition 1 when source approach observer : f01 =[ vs /( vs - vx )].fs ...........(1)Condition 2 when source passes observer : f02 = [vs /( vs + vx) ].fs ............(2)eq(1) : eq (2) we get : f01 / f02 = ( vs + vx )/( vs - vx ) 7/6 = ( 340 + vx ) / ( 340 - vx )[/tex][tex]solve this equation get vx = 26.15 m/s[/tex]
What is frequency?The frequency of a repeated event is its number of instances per unit of time. In certain cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated. The period is the reciprocal of the frequency since it represents the length of time for one cycle in a recurring occurrence. For instance, the period, T—the space between beats—of a heart beating at a frequency of 120 beats per minute (2 hertz), is equal to 0.5 seconds (60 seconds divided by 120 beats).
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A constant force applied to object A causes it to accelerate at 5 m/s². The same force applied to object B causes an accelera-
tion of 3 m/s². Applied to object C, it causes an acceleration of
8 m/s².
a. Which object has the largest mass?
b. Which object has the smallest mass?
c. What is the ratio of mass A to mass B (mA/MB)?
(i) The largest mass will be of the object B.
(ii) The smallest mass will be of the object C.
(iii) The ratio of the mass of object A and b will be 3:5.
According to the Newton’s 2 law for the same force applied acceleration and mass will be in the inverse ratio .it means the more the acceleration the less will be the mass of the object for the same force applied. As the acceleration of the object B is less so its mass will be more and vice versa. And the ratio of the masses will be the inverse ratio of the acceleration of object.
Hence, the ratio will become inverse ratio of acceleration of both the object that is 3:5.
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In a long, straight, vertical lightning stroke, electrons move downward and positive ions move upward and constitute a current of magnitude 20.0kA. At a location 50.0m east of the middle of the stroke, a free electron drifts through the air toward the west with a speed of 300 m/s . (a) Make a sketch showing the various vectors involved. Ignore the effect of the Earth's magnetic field.
A magnetic field, often known as a vector field, describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.
In a long, straight, vertical lightning stroke, downward-moving electrons and upward-moving positive ions produce a current of magnitude I = 20.0 kA.
At a location r = 50.0 m east of the stroke's center, a free electron is moving through the atmosphere at a speed of v = 300 m/s.
Let B represent the magnetic field and F represent the magnetic force. The vector sketch may then be represented as follows:
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A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of λ, and the cylinder has a net charge per unit length of 2λ . From this information, use Gauss's law to find (a) the charge per unit length on the inner surface of the cyli
The charge per unit length on the inner surface of the cylinder is 3λL.
The electric flux across any closed surface is proportional to the net electric charge q enclosed by the surface, according to Gauss's law of electricity, which reads as = q/0, where 0 is the electric permittivity of free space, which has a value of 8.854 10-12 square coulombs per newton per square meter.
Here, q stands for charge.
Volt-metres (V m), the SI base unit of electric flux, is also equivalent to newton-meters squared per coulomb (N m2 C-1). On top of that, the fundamental units of electric flux are kgm3s-3A-1.
Q 1 = L as a result of the wire's induction of the cylinder's inner surface.
"q cylinder" is equal to "q in + q out" (cylinder).
L = L + q out
⇒q out =λL+(2λ)
L = q out =3λL
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An 80.8kg man is standing on a frictionless ice surface when he throws a 2.3kg book at 11.8m/s. with what velocity does the man move across the ice?
The man moves across the ice with a velocity of -1 m/s.
Formula:
To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Given:
After applying the law of linear momentum, we get the following value before the throw;
M₁ = Man's initial mass= 80kg,
U₁ = Initial velocity of Man = 0,
M₂= Initial mass of Book = 4kg,
U₂= Initial velocity of Book = 0.
After the throw, the book's velocity will be
M₁ = Man final mass = 80kg,
V₁ = Man's final velocity = V.
M₂ = Final mass of Book = 4kg,
V₂ = Final velocity of Book = 20 m/s
After substituting the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)
Or, 0 = 80V + 80
Or, 80V = -80
Or, V = -80/80
V= -1m/s
[Note: The -ve sign shows the opposite direction]
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A middle distance runner runs at an average speed of 6 m/s. How long will it take him to run 1500 m, give your answer in seconds. Convert your answer to minutes.
Answer:
480 meters
Explanation: