Answer:
A. FUSION REQUIRES VERY HIGH PRESSURE AND TEMPERATURE
Explanation:
Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.
Nuclear Power Plants uses Nuclear Fission over Nuclear Fusion to generate electric energy because "Nuclear Fusion requires very high pressure and temperature".
What is Nuclear Fission?Nuclear fission is a reaction in which the nucleus of an atom splitting into two or more smaller nuclei and this process produces gamma photons and releases large amount of energy by the energetic standards of radioactive decay.
The Nuclear Fission process was discovered by Hahn, Strassman and Meitner in 1938.
What is Nuclear Fusion?Nuclear Fusion is a reaction in which two or more Atomic Nuclei are combined together to form one or more different atomic nuclei and subatomic particle.
The difference in mass between the reactants and products is manifested as either the release or the absorption of energy.
Robert Atkinson and Fritz Houtermans in 1929 measured masses of light elements to show that large amounts of energy could be used released by fusing small nuclei.
Nuclear Fusion cant be used as a source of energy for heat and electricity generation because developing technology for the required purpose is the subject of ongoing research which is at its nascent stage because to reach to Nuclear Fusion , one requires very high pressure and temperature and to reach such point in one closed area is quite a herculean task.
But Scientists are working towards Nuclear Fusion as it is more advantageous over Nuclear Fission and less pollutant.
Therefore, the correct answer will be option (A)
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An electric current in a copper wire is produced by the motion of which of the following particles? a. copper atoms b. neutrons c. protons d. electrons
Answer:
electrons
Explanation:
Because electric current is flowed due to the presence of free electrons.
Sally and Sam are in a spaceship that comes to within 15,000 km of the asteroid Ceres. Determine the force Sally experiences, in N, due to the presence of the asteroid. The mass of the asteroid is 8.7 1020 kg and the mass of Sally is 68 kg. For calculation purposes, assume the two objects to be point masses.
The gravitational force that is acting on the masses is 1.73 * 10^-2 N.
What is the force?We know that the force of gravity is that kind of force that is going to act on any two of the objects that we have on the earth. This force as we know it is attractive force. The implication of this is that any two masses that we find on the earth are the forces that would have to be attracted to each other.
Let us note that we would have the masses that we have of the asteroid and that of sally as m1 and m2 while we have the force as;
F = G m1m2/r^2
G = gravitational constant
F = magnitude of the force
m1 and m2 = masses
r = distance of separation.
We then have;
F = 6.6 * 10^-11 * 8.7 * 10^20 * 68/(15 * 10^6)^2
F = 3.9 * 10^12/2.25 * 10^14
F = 1.73 * 10^-2 N
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A Ferris wheel, rotating initially at an angular speed of 0.16 rad/s, accelerates over a 8.0-s interval at a rate of 0.040 rad/s2. What is its angular speed after this 8.0-s interval?
Answer:
0.48 rad/s
Explanation:
We can use this equation to find the final velocity
[tex]w_f=w_0+at[/tex]
We are given
[tex]w_0=0.16[/tex]
[tex]t=8.0[/tex]
[tex]a=0.04[/tex]
Inserting those numbers into our equation gives us
[tex]w_f=0.16+0.04*8[/tex]
Lets solve for [tex]w_f[/tex].
[tex]w_f=0.16+0.32[/tex]
[tex]w_f=0.48[/tex]
When gas condense it ______ heat and temperature _____
A. gain heat, temperature decrease
B. gain heat, temperature increase
C. loses heat, temperature decrease
D. loses heat, temperature doesn't change
Answer:
C. loses heat, temperature decreases
Explanation:
When gas condenses, energy decreases, therefore it would lose heat and the temperature would decrease.
The blending of the fundamental tone with overtones produces the __?__of an instrument.
Answer:
The blending of the fundamental tone with overtones produces the Sound Quality of Musical Instruments of an instrument.
The blending of the fundamental tone with overtones produces the sound quality of Musical Instruments of an instrument.
The tone of a sound wave determines the timbre, also known as timber, of the auditory impressions it creates. The wave structure of a sound, which varies with the amount of overtones, or harmonics, present, their frequencies, and their relative intensities, determines the timbre of the sound.Resonance is a common technique used by musical instruments to enhance sound waves and increase volume. When an object vibrates in response to sound waves of a particular frequency, this is known as resonance.What are tones and overtones?Aside from a simple sine wave, the fundamental tone and numerous additional tones of various frequencies make up the waveforms of all sounds. Overtones or harmonics are non-fundamental tones that are whole-number multiples of the fundamental tone.Learn more about sound quality of Musical Instruments brainly.com/question/9571788
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A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:
a. the force at the support point
b. the force at the left-hand end.
Answer:
[tex]F_l=1140N[/tex]
Explanation:
From the question we are told that:
Length[tex]l=3.00m[/tex]
Support distance [tex]d=1.00m[/tex]
Weight of diver [tex]W_d=500N[/tex]
Weight of board [tex]W_b=280N[/tex]
Generally the equation for Total Torque is mathematically given by
[tex]F_T=W_d-W_b[/tex]
[tex]F_T=F_d-f_b[/tex]
[tex]F_T=-280-500[/tex]
[tex]F_T=-780[/tex]
[tex]F_T=780[/tex]
Since we consider the horizontal axis
[tex]\sum Y=0[/tex]
[tex]Fs-(\frac{1}{2}l*w_b)-(l-w_d)[/tex]
[tex]Fs-1.5*280-3*300=0[/tex]
[tex]F_s=1920N[/tex]
Therefore the force at the support point 1.00m from the force at the left-hand
[tex]F_l=F_s-F_l[/tex]
[tex]F_l=1920-780[/tex]
[tex]F_l=1140N[/tex]
a charge of 2 * 10^-9C is placed at the origin, and another charge of 4 * 10^-9C is placed at x = 1.5m. find the point between these charges where a charge of 3 * 10^-9C should be placed so that the net electric force on it is zero
Answer:
x₁ = 0.62 m
Explanation:
In this exercise the force is electric, given by Coulomb's law
F =[tex]k \frac{q_1q_2}{r^2}[/tex]
This force is a vector, since the three charges are in a line we can reduce the vector sum to a scalar sum.
For the sense of force let us use that charges of the same sign repel and charges of the opposite sign attract.
∑ F = F₁₂ - F₂₃
They ask us to find the point where the summaries of the force is zero.
F₁₂ - F₂₃ = 0
F₁₂ = F₂₃
let's fix a reference system located in the first charge (more to the left), the distance between the two charges is d = 1.5 m and x is the distance to the location of the second sphere
k q₁q₂ / x² = k q₂q₃ / (d-x) ²
q₁ (d-x) ² = q₃ x²
let's solve
d² - 2 x d + x² = [tex]\frac{q_3}{q_1}[/tex] x²
x² (1 - [tex]\frac{q_3}{q_1}[/tex]) - 2x d + d² = 0
we substitute the values
x² (1- 4/2) - 2 1.5 x + 1.5² = 0
x² (-1) - 3.0 x + 2.25 = 0
x² + 3 x - 2.25 = 0
let's solve the quadratic equation
x = [-3 ± [tex]\sqrt{ 3^2 + 4 \ 2.25}[/tex]] / 2
x = [-3 ± 4.24] / 2
x₁ = 0.62 m
x₂ = 3.62 m
since it indicates that the charge q₂ e places between the spheres, the correct solution is
x₁ = 0.62 m
take 100 POINTS!!!! look the picture
claiming points because question is old + no keywords in title
calculate the maximum capillary rise of water to be expected a, in a vertical glass tube 1mm in diameter b, in between tow concentric glass tubes of radii 4 and 5 mm. take 6=0.0733n c, in between two vertical parallel.clean glass plates spaced a distance of 2mm apart.
The maximum capillary rise of water to be expected in the vertical glass tube is 15 mm.
What is capillary rise?The process of a liquid flowing in a small area without the aid of, or even in opposition to, any outside forces like gravity is known as capillary rise.
The effect can be observed in a biological cell, in a thin tube, in porous materials like paper and plaster, in some non-porous materials like sand, liquid carbon fiber, and some other porous materials.
The maximum capillary rise of water = 4σcosθ/ρgd
= ( 4 × 0.0733 × cos0°)/(10³ × 9.81 × 2 × 10⁻³) meter
= 0.015 meter
= 15 mm.
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A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
Decide which examples are Nuclear Fission reaction.
A. The reaction that is currently used in nuclear power plants.
B. Two small atoms combine together to form one larger atom.
C. A heavy atom is split when bombarded by neutrons.
D. Often involves isotopes of uranium
A) A, C, D
B) A, B, C
C) B, C, D
a,c,d, is your answer I think I hope it helps
Why the specific heat of water changed as the water state changed?
Answer:
Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.
What kind of nuclear reaction is seen in 30Y0Zr+e?
→40
OA. Beta decay
OB. Alpha decay
OC. Nuclear fusion
D. Nuclear fission
Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.
What is Beta (β) decay?A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.
The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.
As electron releases here, it is a Beta (β) decay.
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Which switches must be pressed to make bulb x come on
Answer:
Did you forget to attach the image?
Explanation:
So far, we're not sure that you even HAVE a bulb or any switches.
If you had them, you probably would have included a diagram of the circuit you built with them. THEN we could look at the diagram and answer this question.
Right now, we can't. We haven't seen such a diagram.
1. What does Louis de Broglie's principle propose about electrons?
They have energy and momentum.
They behave as a wave and a particle.
They contain high-energy and low-energy photons.
They interact with other electrons to form new substances.
Louis de Broglie's principle of electrons states that (b) They behave as a wave and a particle.
The de Broglie equation is one of the equations that is commonly used to define the wave properties of matter. It basically describes the wave nature of the electron.Electromagnetic radiation, exhibit dual nature of a particle (having a momentum) and wave (expressed in frequency, wavelength). Microscopic particle-like electrons also proved to possess this dual nature property.Louis de Broglie in his thesis suggested that any moving particle, whether microscopic or macroscopic will be associated with a wave character. It was called ‘Matter Waves’. He further proposed a relation between the velocity and momentum of a particle with the wavelength, if the particle had to behave as a wave.Particle and wave nature of matter, however, looked contradictory as it was not possible to prove the existence of both properties in any single experiment. This is because of the fact that every experiment is normally based on some principle and results related to the principle are only reflected in that experiment and not the other.To know more about electrons visit:
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____ crust forms the ocean floors
A)lithosphere
B)oceanic
C)continental
D)asthenosphere
Answer:
lithosphere
Explanation:
The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s² and Object 2 accelerates at 5m/s². Which object has the greater mass?
Answer:
Object 1
Explanation:
Newton's 2nd Law: F = ma, therefore m = F/a
This shows that mass is inversely proportional to acceleration. Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass. Therefore, the object that accelerates at 2 m/s² has the greater mass. In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.
Most stars are main-sequence stars, a group of stars for which size, mass, surface temperature, and radiated power are closely related. The sun, for instance, is a yellow main sequence star with a surface temperature of 5800 K. For a main-sequence star whose mass M is more than twice that of the sun, the total radiated power, relative to the sun, is approximately P/Psun = 1.5(M/Msun)3.5. The star Regulus A is a bluish main-sequence star with mass 3.8Msun and radius 3.1Rsun. What is the surface temperature of Regulus A?
Answer:
the surface temperature of Regulus A is 11724.13 K
Explanation:
Given the data in the question;
Sun's surface temperature T = 5800 K
total radiated power, relative to the sun is; P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex]
The star Regulus A is a bluish main-sequence star with mass 3.8M[tex]_{sun[/tex] and radius 3.1R[tex]_{sun[/tex] .
First, we determine the value power emitted by the sun or sun as follows;
P = eσAT⁴
where P is the power, e is surface emissivity, σ is Stefan Boltzmann, A is area and T is temperature.
so, lets assume emissivity of star and sun is same;
let p be power related to star and p[tex]_{sun[/tex] be power related sun.
Ratio of power radiated by star and power radiated by sun;
P/P[tex]_{sun[/tex] = eσAT⁴ / eσA[tex]_{sun[/tex]T[tex]_{sun[/tex]⁴
we know that AREA A = πR²
we input the formula for area
P/P[tex]_{sun[/tex] = eσ(πR²)T⁴ / eσ(π(R[tex]_{sun[/tex])²)T[tex]_{sun[/tex]⁴
such that we now have;
P/P[tex]_{sun[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
given that P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex], we substitute
[tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
we find temperature of the star T
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]M/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/R²)[tex]]^{1/4[/tex]
Given that; mass M is 3.8M[tex]_{sun[/tex] and radius R is 3.1R[tex]_{sun[/tex] .
we substitute
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8M[tex]_{sun[/tex]/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/( 3.1R[tex]_{sun[/tex] )²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8[tex])^{3.5[/tex] ( 1/( 3.1)²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5( 106.9652 ) ( 1/(9.61) [tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 16.69592 [tex]]^{1/4[/tex]
T = 5800 × 2.02140152
T = 11724.13 K
Therefore, the surface temperature of Regulus A is 11724.13 K
What is the unit of work in SI system?
Answer:
Joule ;)
Explanation:
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
Hope this helps!
Answer:
Explanation:
Joule
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
Across a resistor, voltage
a. drops
b. builds
c. speeds up
Answer:
drops
Explanation:
Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source
Heat Transfer 12 Directions: Drag the arrows to the correct locations on the image. directions in which heat flows. The diagram below shows three solid objects. Two of the objects are hot and one is cold. If heat is transferred between these objects via conduction, use the arrows to indicate the direction.
That's the question and please someone help me I can't figure this out because of how much I've been absent throughout this lesson
If heat is transferred between these objects via conduction, both arrows will point towards the cold.
Heat energy is transferred through the mechanism of conduction when nearby atoms or molecules collide. In solids and liquids, where particles are more closely spaced, conduction happens more easily than in gases, where particles are more widely spaced. Heat transfers through solid materials via conduction. The roof, walls, and windows of your house all carry heat on hot days.
The act of heating a skillet on a stovetop is a typical illustration of conduction. The surface of the pan receives heat directly from the burner. The amount of kinetic energy that the particles in a sample of matter have converted to heat is measured by temperature. Conduction mostly comes in two flavors. Steady-state conduction is what they are. temporary conduction.
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A mass on a string is swung in a circle of radius 0.75m at 7.0m/s.what its rate of acceleration.
Explanation:
ac = v^2/r
= (7.0 m/s)^2/(0.75 m)
= 65 m/s^2
8. If the m<5 is 63°, find the
measure of <3.
The statement indicates that angle 3 seems to have a 117 degree measurement.
Short answer: What is measure?Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.
Briefing:An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.
The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.
Angle 3 is therefore = 180 - 63 = 117 degrees.
Consequently, angle 3 has a measure of 117 degrees.
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Which one has more momentum if they are all traveling at the same speed?
1. A basketball
2. A golf ball
3. A tennis ball
4. A bowling ball
Answer:
the answer is a bowling ball
It is a “new moon” (the Moon is totally dark in the sky). Using the masses of the Earth, Sun, and Moon and the average distances between the Earth-Moon and Earth-Sun, find the net gravitational force on the Earth from the Sun and the Moon combined.
Find also distance when it is full moon
It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:
2.9 x 10^20 N3.5 x 10^22 N3.5 x 10^22 NWhat is gravitational force?Generally, The gravitational force between two objects is given by the equation:
force = G * (mass1 * mass2) / distance^2
Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.
The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.
The gravitational force between the Earth and the Moon is:
force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force
= 2.9 x 10^20 N
The gravitational force between the Earth and the Sun is:
force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force
= 3.5 x 10^22 N
To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.
Net force = 2.9 x 10^20 N + 3.5 x 10^22 N
= 3.5 x 10^22 N
When it is a Full Moon the distance is the same 384,400 km
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What is the equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel?
Answer:
The equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel is 2.0 Ω.
Explanation:
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HELP How are the forces on an object added or subtracted to get net force?
Answer:
Explanation:
Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag. If forces are in opposite directions, like lift and weight, then you subtract them
What are the precautions for compound Pendulum experiment
Make sure you measure the length of the pendulum from the centre (of mass) of the plumbob.
Make sure the top edge is well defined- clamp the string between two blocks so it is clear where the string can move and where it cant.
Make sure the top support is fixed- eg a clamp stand can easily flex and so the top support moves.
Make sure you use small amplitudes ( less than 10 degrees from the vertical)
Make sure you time enough swings such that the total time is sufficeint to get the uncertainty in the timing of a single swing down. (It is the total time that is important not the number of swings)
Release the pendulum and start timing counting while it is swinging. Start the clock and say zero (not 1).
Have a pre-prepared results table so that you can record your results accurately without rushing.
Do at least 3 sets of readings to identify any anomalies.
Explanation:
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.42 cm.
Required:
How fast was the proton moving?
Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s