Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the which the card is printed is $0.05 per card, and the cost of printing is $0.15 per card. The company receives $2.15 per card sold. Since the cards have the current year printed on them, unsold cards have no salvage value. Their customers are from the four areas: Los Angeles, Santa Monica, Hollywood, and Pasadena. Based on past data, the number of customers from the each of the four regions is normally distributed with mean 2,000 and standard deviation of 500. (Assume these four are independent.)
What is the optimal production quality for the card? (Use Excel's NORMSINV{} function to find the Z-score. Round intermediate calculations to four decimal places. Submit your answer to the nearest whole number.)

Answer:

a) rCn = 1176

b) 2352

Step-by-step explanation:

a)Each committee should be formed with 3 members ( no two members could be of the same state) then

Let´s  fix a senator for any of the 50 states so in the new condition we need to combined 49 senators in groups of 2 then

rCn =  n! / (n - r )! *r!

rCn =  49!/ (49 - 2)!*2!

rCn =  49*48*47! / 47!*2!

rCn = 49*48 /2

rCn = 1176

So we can choose in 1176 different ways a senator for a given state

b) To answer this question we have to note, that, 1176 is the number of ways a committee can be formed with senators of different sate (taking just one senator for state ) if we have 2 senators we need to multiply that figure by 2.

1176*2 = 2352

Answer:

(a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

A. The median represents the center.

Step-by-step explanation:

In statistics and probability theory, the median value is the middle value or center value in a group of data values or numbers. To find the median, the values have to be placed in value order, from smallest to largest. The center number would be the median. The number lies between the higher half and the lower half. Therefore the median represents the center of the data values.

6 1/10

Step-by-step explanation:

4 + 1/2+1+3/5

5+1+1/10=6 1/10

The difference of the rational expressions 6/x - 5x/x+2 is (x + 12)/(x(x+2)).

Thus, the correct option would be:

C. (x + 12)/(x(x+2))

To find the difference of the rational expressions, we need to subtract the second expression from the first expression.

Let's simplify the expressions first:

The first expression is 6/x - 5x/(x+2).

To combine the terms, we need a common denominator, which is (x)(x+2).

Converting the first term, 6/x, to have a denominator of (x)(x+2), we get (6(x+2))/(x(x+2)).

Now, we can combine the terms:

[(6(x+2))/(x(x+2))] - [5x/(x+2)]

To subtract the fractions, we need to have a common denominator, which is (x)(x+2).

Expanding the numerators, we get:

[(6x + 12)/(x(x+2))] - [5x/(x+2)]

Now, we can subtract the fractions:

[(6x + 12 - 5x)/(x(x+2))]

Simplifying the numerator, we have:

(6x - 5x + 12)/(x(x+2))

Combining like terms, we get:

(x + 12)/(x(x+2))

Therefore, the difference of the rational expressions 6/x - 5x/x+2 is (x + 12)/(x(x+2)).

Thus, the correct option would be:

C. (x + 12)/(x(x+2))

For similar question on rational expressions.  

https://brainly.com/question/29061047

#SPJ8

Answer:

80

Step-by-step explanation:

The quadrilateral is a kite.

The angle opposite to angle H is equal to angle H.

Angle F = 110 degrees

Angles in a quadrilateral add up to 360 degrees.

60 + 110 + 110 + G = 360

280 + G = 360

G = 360 - 280

G = 80

The measure of angle G is 80 degrees.

Answer: 80 degrees.

Step-by-step explanation:

In a kite, the angles formed by noncongruent sides are congruent.  Thus, <EFG is 110 degrees.  Then, because a kite is a quadrilateral, all of the angles in it add up to 360.  Thus, is <FGH = x, then 110+110+60+x=360.  Thus, x = 80.

Hope it helps <3

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

The CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

It is given that the objective that central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds.

It is required to describe the above theorem.

It is defined as the in statistics the assumption holds that the sample means distribution of arbitrary variables follows a normal distribution or close to normal distribution if the sample size is big.

We have an objective:

The CLT is the factor to be considered when assessing if the CLT holds a large sample size.

If we draw the random sample data and its measures, the Central limit theorem explains the distribution will explain the normal bell curve, the mean of the parameters and the distribution will be the same.

Thus, the CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

Learn more about the Central limit theorem here:

https://brainly.com/question/5027686

Answer:

Step-by-step explanation:

[tex] \mathrm{Given}[/tex],

[tex] \mathrm{Discount\% = 20\%}[/tex]

[tex] \mathrm{Marked \: price = 1250}[/tex]

[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]

[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]

[tex] \mathrm { = 20\% \: of \: 1250}[/tex]

[tex] \mathrm{ = 250}[/tex]

[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]

[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]

[tex] \mathrm{ = 1250 - 250}[/tex]

= $ [tex] \mathrm{1000}[/tex]

[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]

[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]

[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]

= $ [tex] \mathrm{ 125}[/tex]

[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]

[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]

[tex] \mathrm{ = 1000 + 125}[/tex]

= $ [tex] \mathrm{1125}[/tex]

Therefore, The final sale of the necklace is $ 1125

Hope I helped

Best regards!

Answer:

Step-by-step explanation:

The square root of 7066 is 84.0595....

Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...

That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.

84 isn't prime. But 83 is prime.

Therefore, the greatest prime that needs to be considered for divisibility is 83.

Answer:

The numbers 7066 is not prime .

But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.

Step-by-step explanation:

It is known with certainty that a number is prime when it is only divisible by and by unity.

But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.

for example; 7066/2=3533 , the remainder is zero;

Step-by-step explanation:

Intersecting secant angles theorem: The angle between two secants is half the difference of the intersected arcs.

52 = ½ (x − 38)

x = 142

Arc angles add up to 360.

360 = 80 + 38 + z + x

z = 100

Tangent-chord theorem: The angle between a tangent and a chord is half the intercepted arc angle.

y = x/2

y = 71

Answer:

B. 168 students

Step-by-step explanation:

Given that there are a total of 600 students.

28% of the students pack their lunch.

To find:

Total number of students who pack their lunch = ?

Solution:

Percentage of a given number is calculated using the following method.

[tex]y\%[/tex] of a number [tex]x[/tex] is given by:

[tex]x \times \dfrac{y}{100}[/tex]

i.e. multiply the number by percentage to be found and divide by 100.

So, we have to find 28% of 600 here, to find the answer to the question.

[tex]\therefore[/tex] Number of students who pack their lunch is given as: (Multiply the given number 600 with 28 and divide by 100.)

[tex]600 \times \dfrac{28}{100}\\\Rightarrow 6 \times 28\\\Rightarrow \bold{168}[/tex]

So, the correct answer is:

B. 168

Answer:

  19.9 days

Step-by-step explanation:

The amount remaining after d days is ...

  a = (1/2)^(d/7)

We want to find d when a = 0.14

  log(a) = (d/7)log(1/2)

  d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9

The farmers need to wait about 19.9 days for it to be safe.

Answer:

The greatest possible value of [tex]y^3=216[/tex]

Step-by-step explanation:

We have the statement [tex]y^2=36[/tex], and we have to find the greatest possible value of [tex]y^3[/tex], first we need to find the value of y.

[tex]y^2=36[/tex], to get the y by itself on the left side, we need to take the square root of both sides. [tex]\sqrt{y^2} =\sqrt{36}[/tex] The square root of [tex]y^2[/tex] is y, because y*y = [tex]y^2[/tex], and the square root of 36 is 6 or -6.

We now need to find the greatest value of [tex]y^3[/tex]. When we plug in 6 to [tex]y^3[/tex], we get positive 216, and when we plug in -6, we get -216. We need to find the greatest possible value, so in this case we compare 216 and -216, 216 is greater than -216, so the answer would be positive 216.

Answer:

216

Step-by-step explanation:

If y² = 36, then y is 6 or -6. When y = 6, we have y³ = 6³ = 216. When y = -6, we have y³ = (-6)³ = -216. The greatest possible value of y³ is 216.

Answer:

7 children

Step-by-step explanation:

Answer:

7 children is the correct answer

and you follow me if you can't I will unfollow you

Answer:

Step-by-step explanation:

According to the angle sum theorem, the interior angles of a triangle add up to 180 degrees:

So, we can use the following equation to find x:

x+(x+10)+(210-3x)=180

now add like terms:

x+x+(-3x)+10+210=180

-x+220=180

now isolate the variable:

-x=180-220

-x=-40

x=-40/-1

x=40/1

x=40

The answer is that: the measure of x is 40 degrees

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 0.5 \ in[/tex]

Generally the Null hypothesis is  [tex]H_o : \mu = 0. 5 \ in[/tex]

                The Alternative hypothesis is  [tex]H_a : \mu \ne 0.5 \ in[/tex]

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]

We are making use of this  [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that  [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that  t  lies in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

Answer:

B

Step-by-step explanation:

Answer:

the 2nd one

Step-by-step explanation:

because the Minimum is 20

the Maximum is 31

the median is 23

20, 21, 22, 23, 25, 27,  31,

21, 22, 23, 25, 27

22, 23, 25,

23

Answer:

B.77.4%

Step-by-step explanation:

Mean wage (μ) = $4.50

Standard deviation (σ) = $0.50

For nay given salary X, the z-score is given by:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

For X = $3.75, the z-score is:

[tex]z=\frac{3.75-4.50}{0.50}\\z=-1.5[/tex]

For X = $5.00, the z-score is:

[tex]z=\frac{5.00-4.50}{0.50}\\z=1[/tex]

A z-score of -1.5 corresponds to the 6.68th percentile, while a score of 1 corresponds to the 84.13th percentile. Therefore, the percentage of workers getting paid between $3.75 and $5.00 an hour is:

[tex]P=84.13-6.68\\P=77.45\%[/tex]

The answer is alternative B.77.4%

Answer:

D. 6

Step-by-step explanation:

here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}

and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }

so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.

Answer:

The sampling is dependent because an individual selected for one sample does dictate about which individual to be selected in the second sample.

The variable is qualitative because it classifies the individual.

Step-by-step explanation:

The sample is dependent as the second individual selected in the sample is dependent on the first individual selection. The sample selection is not random and is dictated. The variables selected are qualitative in nature because they identify the quality of response variable which is non numerical in nature.

Work Shown:

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\[/tex]

Answer:

√91/10

Step-by-step explanation:

sin 0.3 is equal to 18(approximate value)

cos18°=0.951

which is √91/10

Answer:

Step-by-step explanation:

Given,

AD = 38

EB = 7x - 4

FC = 6x - 6

Now, we have to find the value of X

[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )

Plug the values

[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]

Calculate the difference

[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]

Remove the parentheses

[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]

[tex]7x - 4 = 16 + 3x[/tex]

Move variable to L.H.S and change its sign

Similarly, Move constant to R.H.S and change its sign

[tex]7x - 3x = 16 + 4[/tex]

Collect like terms

[tex]4x = 16 + 4[/tex]

Calculate the sum

[tex]4x = 20[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{20}{4} [/tex]

Calculate

[tex]x = 5[/tex]

The value of X is 5

Now, let's find the value of EB

EB = 7x - 4

Plug the value of X

[tex] = 7 \times 5 - 4[/tex]

Calculate the product

[tex] = 35 - 4[/tex]

Calculate the difference

[tex] = 31[/tex]

The value of EB is 31

Hope this helps..

Best regards!!

Answer:

(a) 3:5

(b) 15

Step-by-step explanation:

Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.

It is asking for unshaded first so our ratio will be,

3:5

(a) 3:5

So if there is 9 unshaded how many shaded is there.

Well we can just make the following ratio 9:x

So 9/3 = 3

Meaning 3*5 = 15

So x = 15

(b) 15

Answer:

a) 3/5

b) 15

Step-by-step explanation:

(a)

unshaded: 3

shaded: 5

unshaded to shaded: 3/5

(b)

There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.

Add two more lines just like the given line.

Each new line will have 5 shaded and 3 unshaded squares.

Now you have a total of 9 unshaded and 15 shaded squares.

Answer:

ln(60)

Step-by-step explanation:

We have the equation [tex]5e^x=300[/tex]. We can divide both sides of the equation by 5, getting [tex]e^x=60[/tex]. Finally, we can take the natural log of both sides, getting that x is equal to [tex]\ln(60)[/tex].

Answer:

hope you get it....sorry for any mistake calculations

Answer:

x=-3/5 and y=-38/5

Step-by-step explanation:

y=6x-4  

y= x -7 substitute y=6x-4

6x-4=x-7

6x-x=-7+4

5x=-3

x=-3/5 ( substitute for x in y=6x-4)

y=6(-3/5)-4

y=-18/5-4

y=(-18-20)/5= -38/5

Answer:

18.8 cubic inches

Step-by-step explanation:

1. Solve for the volume of Cup A. (volume of a cone = 1/3πr² · h)

1/3 · 3.14 · 1² · 3 = 3.14 in³

2. Solve for the volume of Cup B (volume of a cylinder = πr² · h)

3.14 · 1² · 7 = 21.98 in³

3. Subtract the volume of Cup A from Cup B

21.98 - 3.14 = 18.84

4. Round 18.84 to the nearest tenth

18.84 → 18.8 in.³

Answer:

18 .8

Step-by-step explanation:

got it right on test

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

[tex]f(x) = \sqrt{x}[/tex]

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

[tex]f^i(c) = \frac{f(b) - f(a)}{b -a }[/tex]

After this,

[tex]f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}[/tex]

[tex]f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\[/tex]

After this,

Put the values of a and b to the above equation

[tex]f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}[/tex]

= 2.25

Answer: 189 mg.

Step-by-step explanation:

Let x be the weight of the body( in pounds) and y be the amount of medicine( in mg).

Given: A certain medicine is given in an amount proportional to patient’s body weight.

i.e. [tex]\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}[/tex]

Let [tex]x_1=116\ \ \ ,\ y_1=126[/tex] ,  [tex]x_2=174[/tex]

then,

[tex]\dfrac{116}{126}=\dfrac{174}{y_2}[/tex]

[tex]\Rightarrow\ y_2=\dfrac{174\times126}{116}\\\\\Rightarrow\ y_2=189[/tex]

Hence, he amount of medicine required by patient weighing 174 pounds = 189 mg.