The value shown on the number line is 3 8/10
How to determine the value shown on the number lineThe number line represents the given parameter
On the number line, we have the point located between 3 and 4
Such that the point is at 0.8 between 3 and 4
When the above expression is represented as a number, we have
Number = 3 + 0.8
Express the decimal as a fraction
So, we have
Number = 3 + 8/10
Evaluate
Number = 3 8/10
Hence, the solution is 3 8/10
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There are 124 people waiting to take a ride in a hot air balloon. The balloon can hold 14 passengers at a time
If the balloon can hold 14 passengers at a time, then number of rounds to empty the que is 9.
In order to find out number of rounds it will take to empty the queue of 124 people, we divide the total number of people by the number of people that can be carried in each round,
⇒ Number of rounds = (Total number of people)/(Number of people per round);
⇒ Number of rounds = 124/14,
⇒ Number of rounds = 8.86 (rounded to two decimal places)
Since we can't have a fraction of a round, we round up to the nearest whole number.
Therefore, the balloon will need to make 9 rounds to empty the queue of 124 people.
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The given question is incomplete, the complete question is
There are 124 people waiting to take a ride in a hot air balloon. The balloon can hold 14 passengers at a time, how many rounds will it take to empty the que?
Let A = |b с| . |a d| Assume that det(A) = -11, compute the following: NOTE: Enter all values exactly. (b) det (4A) det( A ) = (c) (d) ) det(2A-1) =( det ((24)-1) =( (e) d a 9 det b h с e
Given that A = |b с| . |a d| and det(A) = -11, the following computations can be made:
(b) det(4A) det(A) = 4^2 * (-11) * (-11) = 1936
(c) det(2A - 1) = 2^2 * (-11) - 1 = -43
(d) det((24)^-1) = (1/24) ^2 = 1/576
(e) d a 9 det b h с e
The determinant of a matrix is defined as the sum of the products of the elements of the matrix multiplied by the corresponding cofactor. The cofactor is a signed minor of the matrix, which is obtained by deleting the row and column of the element for which the cofactor is being computed.
In the case of the matrix A = |b с| . |a d|, the determinant can be computed as follows:
|b с| . |a d| = (b*d) - (a*c)
Therefore, det(A) = (b*d) - (a*c) = -11.
To compute det(4A) det(A), first, find det(4A), which is equal to:
|4b 4c| . |4a 4d| = 4^2 * (b*d - a*c)
Thus, det(4A) = 16(b*d - a*c) = 16(-11) = -176.
Then, det(4A) det(A) = (-176) * (-11) = 1936.
For det(2A - 1), first, find 2A - 1, which is equal to:
|2b 2c| . |2a 2d| - |1 0| . |0 1|
= 2|b с| . |a d| - |1 0| . |0 1|
= 2A - |1 0| . |0 1|
= 2A - I
where I is the identity matrix.
Therefore, det(2A - 1) = det(2A - I) = det(2A) det(I^-1)
Since det(I) = 1, det(I^-1) = 1/det(I) = 1/1 = 1.
Therefore, det(2A - 1) = 2^2 * (-11) * 1 - 1 = -43.
Finally, to compute det((24)^-1), it is necessary to find the inverse of the matrix 24.
|a b| . |c d| = 24I
=> |a b|^-1 . |c d| = (1/24)I
=> (1/24) . |d -b| . |-c a| = (1/24)I
Therefore, |d -b| . |-c a| = I
Since the determinant of the identity matrix is 1, it follows that:
1 = det(I) = det(|d -b| . |-c a|) = (a*d) - (b*c)
Hence, det((24)^-1) = (1/24)^2 = 1/576.
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3. A car travels 740 miles in 10 hours. Some of the time the car travels \( 70 \mathrm{mph} \) and some of the time the car travels \( 80 \mathrm{mph} \). How many hours did the car travel at each spe
The car traveled for 6 hours at 70 mph and 4 hours at 80 mph.
To find out how many hours the car traveled at each speed, we can use a system of equations. Let x be the number of hours the car traveled at 70 mph and y be the number of hours the car traveled at 80 mph. We can set up the following equations:
Distance equation: 740 = 70x + 80y
Time equation: 10 = x + y
We can rearrange the time equation to solve for one of the variables in terms of the other:
y = 10 - x
Now we can substitute this into the distance equation:
740 = 70x + 80(10 - x)
740 = 70x + 800 - 80x
10x = 60
x = 6
So the car traveled for 6 hours at 70 mph. We can use this to find the number of hours the car traveled at 80 mph:
y = 10 - x = 10 - 6 = 4
So the car traveled for 4 hours at 80 mph.
Therefore, the car traveled for 6 hours at 70 mph and 4 hours at 80 mph.
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Help
Algebra 2 please help answer 17
The natural logarithm function is ln(p) = ln(100) - 0.35t
How to determine the natural logarithm functionFrom the question, we have the following parameters that can be used in our computation:
The table of values
The function can be represented as
p = ae^kt
Using the points on the table, we have
ae^(k * 0) = 100
So, we have
a = 100
This gives
p = 100e^kt
Using another point, we have
70.5y = 100e^(k * 1)
70.5y = 100e^k
So, we have
e^k = 0.705
Take the natural logarithm of both sides
k = ln(0.705)
k = -0.35
The function becomes
p = 100e^(-0.35t)
Take the natural logarithm of both sides
ln(p) = ln(100) - 0.35t
Hence, the function is ln(p) = ln(100) - 0.35t
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Please Help, My progress report grades are going in soon for the semester!!
Look at the Screenshot <33
Answer:
Step-by-step explanation:
Pages Alana writes = m+4
to fill in the blanks add 4 to 5, 7, and 9 because of the 4 extra pages Alana writes.
That will give you: 9, 11, and 13 as your answers
Testi 24 Unit 4 Test, Objectives 24-26 Math F Solve the absolute value equation. |(5x+10)/(2)|=5
The solutions for the absolute value equation are x = 0 and x = -4.
To solve the absolute value equation |(5x + 10)/(2)| = 5, we need to remove the absolute value bars and create two separate equations, one positive and one negative. Then we can solve for x in each equation.
First, let's remove the absolute value bars and create two separate equations:
(5x + 10)/2 = 5 and (5x + 10)/2 = -5
Now we can solve for x in each equation:
(5x + 10)/2 = 5
5x + 10 = 10
5x = 0
x = 0
And:
(5x + 10)/2 = -5
5x + 10 = -10
5x = -20
x = -4
So the solutions to the equation |(5x + 10)/(2)| = 5 are x = 0 and x = -4.
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A post office has 2 clerks. Alice enters the post office while 2 other customers, Bob and Claire, are being served by the 2 clerks. She is next in line. Suppose a clerk’s serving time for any customer follows an exponential distribution with parameter λ independently. Customers will be served once any of the clerks are available.
What is the probability that Bob the last customer to leave the post office?
The probability that Bob is the last customer to leave the post office comes out as (1 - e^(-λx))^2. The probability that Bob is the last customer to leave the post office can be calculated using the exponential distribution formula.
The exponential distribution is a continuous probability distribution used to model the time between events in a Poisson process. The formula for the exponential distribution is: P(X=x) = λe^(-λx)
Where X is the random variable representing the time between events, λ is the rate parameter, and e is the base of the natural logarithm.
P(Bob is the last customer to leave) = P(Bob's serving time > Alice's serving time) * P(Bob's serving time > Claire's serving time). Since the serving times follow an exponential distribution with parameter λ, we can use the formula to calculate the probabilities:
P(Bob's serving time > Alice's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)
P(Bob's serving time > Claire's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)
P(Bob is the last customer to leave) = (1 - e^(-λx))^2
Therefore, the probability that Bob is the last customer to leave the post office is (1 - e^(-λx))^2.
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can you please help with this assignment
The side lengths from the triangles are LN = 24 inches, KL = 9 cm and DE = 6 ft
How to determine the side lengths from the trianglesSide length LN
Given that the triangles are similar, we have the following equivalent ratio:
AC : BC = LN : MN
By substitution, we have
36 : 24 = x : 16
So, we have
x/16 = 36/24
Multiply by 16
x = 24
Hence, the length LN is 24 inches
Side length KL
Here, we have the following equivalent ratio:
KL : KJ = AB : AD
By substitution, we have
x : 14 = 7.2 : 11.2
So, we have
x/14 = 7.2/11.2
Multiply by 14
x = 9
Hence, the length KL is 9 cm
Side length DE
Here, we have the following equivalent ratio:
DE : AE = BC : CA
By substitution, we have
x : 9 = 10 : (6 + 9)
So, we have
x/9 = 10/15
Multiply by 9
x = 6
Hence, the length DE is 6 ft
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ative. Check your work by evaluating the ve rules given in this chapter. 3. g(x)=(1)/(x^(2)+5) 27. 29.
The five rules given in this chapter are important for algebraic manipulation. Firstly, the Commutative Rule states that when two numbers are added or multiplied, the order of the numbers does not matter.
Secondly, the Associative Rule states that when three or more numbers are added or multiplied, the order in which the operations are performed does not affect the result.
Thirdly, the Distributive Rule states that when a number is multiplied by a sum of two numbers, the number can be distributed to each of the two numbers.
Fourthly, the Additive Identity Rule states that when any number is added to zero, the result is the same number. Finally, the Multiplicative Inverse Rule states that if a number is multiplied by its reciprocal, the result is one.
Together, these five rules form the basis for many algebraic operations. They are important for understanding and manipulating equations, solving for unknowns, and more. By understanding and applying these five rules, students will be able to work more efficiently and accurately with algebraic expressions.
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Select each expression that can be factored as a difference of squares. 16x^(2)+25y^(2) x^(3)-125 25x^(2)y^(2)-64z^(2) 4x^(2)-9y^(2)
a) The expression can be factored as (5xy+8z)(5xy-8z).
b) The expression can be factored as (2x+3y)(2x-3y).
The expressions that can be factored as a difference of squares are:
- 25x^(2)y^(2)-64z^(2)
- 4x^(2)-9y^(2)
A difference of squares is an expression in the form a^2 - b^2, which can be factored as (a+b)(a-b). In the first expression, 25x^(2)y^(2) can be rewritten as (5xy)^2 and 64z^(2) can be rewritten as (8z)^2. Therefore, the expression can be factored as (5xy+8z)(5xy-8z).
In the second expression, 4x^(2) can be rewritten as (2x)^2 and 9y^(2) can be rewritten as (3y)^2. Therefore, the expression can be factored as (2x+3y)(2x-3y).
The other two expressions, 16x^(2)+25y^(2) and x^(3)-125, cannot be factored as a difference of squares because they do not have the form a^2 - b^2.
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A family buys 6 airline tickets online. The family buys travel insurance that costs $18 per ticket. The total cost is $1,128. Let x represent the price of one ticket. Then find the price of one ticket.
Answer: $170
Step-by-step explanation:
6x + 18(6) = 1128.
6x + 108 = 1128
6x = 1020
x = 170
The price of one ticket is 170
For the rational function x² – 2x - 8 f(x) = (x - 2)2 a) Determine the x-intercepts b) Determine the approximation equation near each x-intercept c) Determine the equation for the vertical asymptote d) Determine the approximation equation near the vertical asymptote e) Determine the formula for any horizontal and/or slant asymptote
a) To find the x-intercepts, we set f(x) = 0 and solve for x:
0 = (x² - 2x - 8)/(x - 2)²
0 = x² - 2x - 8
(x - 4)(x + 2) = 0
x = 4, -2
So the x-intercepts are (4,0) and (-2,0).
b) To find the approximation equation near each x-intercept, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
For x = 4:
f'(4) = (2(4) - 2)/(4 - 2)³ = 6
So the approximation equation near x = 4 is y = 6(x - 4).
For x = -2:
f'(-2) = (2(-2) - 2)/(-2 - 2)³ = -1/8
So the approximation equation near x = -2 is y = -1/8(x + 2).
c) To find the equation for the vertical asymptote, we set the denominator of f(x) equal to 0 and solve for x:
(x - 2)² = 0
x = 2
So the equation for the vertical asymptote is x = 2.
d) To find the approximation equation near the vertical asymptote, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
f'(2) = (2(2) - 2)/(2 - 2)³ = undefined
Since the first derivative is undefined at x = 2, we can use the second derivative:
f''(x) = (6x - 6)/(x - 2)⁴
f''(2) = (6(2) - 6)/(2 - 2)⁴ = undefined
Since the second derivative is also undefined at x = 2, we cannot find an approximation equation near the vertical asymptote.
e) To find the formula for any horizontal and/or slant asymptote, we can look at the degree of the numerator and denominator of f(x):
The degree of the numerator is 2 and the degree of the denominator is 2, so there is a horizontal asymptote.
To find the equation of the horizontal asymptote, we can divide the leading coefficients of the numerator and denominator:
1/1 = 1
So the equation of the horizontal asymptote is y = 1.
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What is the frequency of each interval?
81, 65, 2, 24, 25, 44, 97, 12, 38, 37
Question 5 options:
81 - 100
61 - 80
1 - 20
21 - 40
41 - 60
1.
1
2.
2
3.
3
4.
4
5.
5
1 - 20, 21 - 40, 41 - 60, 1.1, 2.2, 3.3, 4.4, 5.5
Truncated Poisson: Suppose observations come from Poisson(x), but only non-zero values are recorded. The likelihood is L(µ) ἁ || e^(- µ) µ^xi
Data: 3, 1, 2, 4, 2, 1,3,1,2,1 Prior: p(µ) = 1 (a) Construct a Metropolis-Hasting (M-H) algorithm. Use M-H with proposal distribution q(µ| µo) : N(θ: mean = µp, std = 2). Set Prob(acceptance) 0 if µ < 0. Number of MCMC draws 15000 with burn-in phase 1500. Give a 95% confidence interval for µ.
The result is the 95% confidence interval for µ.
The Metropolis-Hasting (M-H) algorithm is a Markov Chain Monte Carlo (MCMC) method used to sample from a probability distribution. In this case, we want to sample from the posterior distribution of µ, given the recorded data and the prior distribution. The M-H algorithm works by proposing a new value for µ, calculating the acceptance probability, and then deciding whether to accept or reject the proposed value. Here are the steps to construct the M-H algorithm:
Start with an initial value for µ, denoted as µ0.
Propose a new value for µ, denoted as µp, from the proposal distribution q(µ| µo) : N(θ: mean = µp, std = 2).
Calculate the acceptance probability, denoted as α, using the likelihood function L(µ) and the prior distribution p(µ):
α = min{1, [L(µp)/L(µ0)]*[p(µp)/p(µ0)]*[q(µ0| µp)/q(µp| µ0)]}
Generate a random number u from the uniform distribution U(0,1).
If u ≤ α, accept the proposed value and set µ0 = µp. Otherwise, reject the proposed value and keep µ0 unchanged.
Repeat steps 2 to 5 for a specified number of MCMC draws (15000 in this case), and discard the first 1500 draws as the burn-in phase.
Calculate the 95% confidence interval for µ using the remaining 13500 draws.
The 95% confidence interval for µ can be calculated by finding the 2.5th and 97.5th percentiles of the posterior distribution of µ. This can be done by sorting the 13500 draws of µ in ascending order and finding the values that correspond to these percentiles. The result is the 95% confidence interval for µ.
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Find the missing variable and indicated
angle measure.
A
X =
51°
(3x)°
B
C
mzBDC =
This is the last one for me to be done with the assignment please answer fast:) will mark brainiest
Answer:x=a
Step-by-step explanation:
Using the numbers 1 to 9 (one time each), fill in the boxes to make
the equation true.
0:0=00:0=00:00
The complete equation using the numbers from1 to 9 will be:
2:2 = 3×3:9 = 4×4 =16.
What do you mean by proportion?A contrast between two numbers in arithmetic, this is referred to as a proportion. According to the law of proportion, two sets of given numbers are said to be directly proportional to one another if they grow or shrink in the same ratio.
In the question given:
By using the digits 1 to 9 at one time each, we have to form the equation to make the equality true.
Now,
All the numbers from 1 to 9 are = 1, 2 ,3, 4, 5, 6, 7, 8 and 9
Let the proportion be = 1
Hence, the equivalent ratios are:
1:1, 2:2. 3:3
Now, according to the question the required equation will be:
2:2 = 3×3:9 = 4×4 =16.
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You will create a map with locations that will identify
the different types of angles and lines we have learned
about in class. The base of your map must include at
least two parallel lines which will be named streets,
and at least one transversal which will be named as a
highway.
This assignment can be done digitally or on paper.
Your map must have a key which identifies each of the
following:
➢ One set of corresponding angles
➢ One set of alternate interior angles
➢ One set of alternate exterior angles
➢ One set of vertical angles
➢ One set of complementary angles
➢ One set of supplementary angles
In addition, ALL ANGLES MUST HAVE MEASURES
LISTED. Check back to your notes to see the
relationships between these angles.
Your final map should include two streets, a highway, and labels for each angle with their corresponding measures. The key should clearly explain each type of angle and their relationships.
What does a map help with?Maps are also used to help people understand the relationship between different places and their relative size and position. Maps can provide information about the landforms of an area, such as mountains, rivers, valleys, and deserts.
To begin, draw two parallel lines on the map, and then add a transversal crossing them. Label the parallel lines as “streets” and the transversal as “Highway.” Then, label each pair of angles with the corresponding names listed above. For example, the angles that form when the two parallel lines are crossed by the transversal would be labeled as “Alternate Interior Angles.”
Next, measure the angles using a protractor or a ruler. For example, if two parallel lines are crossed by a transversal, measure the four resulting angles. Each angle should be measured and labeled with its degrees.
Finally, add a key to your map. This should include an explanation of each type of angle and their relationships with one another. For example, the key should explain that complementary angles add up to 90 degrees, supplementary angles add up to 180 degrees, etc.
Your final map should include two streets, a highway, and labels for each angle with their corresponding measures. The key should clearly explain each type of angle and their relationships. By completing this assignment, you will have a visual understanding of the different types of angles and lines we have learned in class.
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Find any numbers for which the rational expression is undefined. (7x^(4)+8)/(5x^(2)+20x)
The numbers for which the rational expression is undefined are x=0 and x=-4.
To find the numbers for which the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined, we need to find the values of x that make the denominator equal to zero. This is because division by zero is undefined.
So, we need to solve the equation 5x^(2)+20x=0 for x.
We can factor out a common factor of 5x from the equation:
5x(x+4)=0
Now, we can use the zero product property to set each factor equal to zero and solve for x:
5x=0 or x+4=0
x=0 or x=-4
So, the numbers for which the rational expression is undefined are x=0 and x=-4.
In summary, the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined for x=0 and x=-4.
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Two chords |AB| = 10cm, and |CD| = 6cm are drawn on the alternative sides of a circle of radius 6cm. Find the distance between the chords
The distance between the two chords is approximately 0.894 cm where |AB|=10cm and |CD|=6cm
What is a chord?Chord is the longest segment that can be drawn within the circle, connecting two points on the circle that are not necessarily opposite each other.
According to question:We can use the following formula to find the distance between two chords in a circle:
d = |(AB-CD)/(2√(r²-(AB/2-CD/2)²))|
where d is the distance between the chords, AB and CD are the lengths of the chords, and r is the radius of the circle.
By substituting, we get:
d = |(10-6)/(2√(6²-(10/2-6/2)²))|
d = |4/(2√(6²-(8/2)²))|
d = |4/(2√(6²-4²))|
d = |4/(2√(20))|
d = |4/(2×2√(5))|
d = |2/√(5)|
d ≈ 0.894 cm
Therefore, the distance between the two chords is approximately 0.894 cm.
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The demand function for a certain brand of compact discs is given by
p = −3x2 − 4x + 69
where p is the wholesale unit price in dollars and x is the quantity demanded each week, measured in units of a thousand.
(a) Compute the price, p, when x = 4.
Price, p = dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 4. Do not round your answer.
Rate of change of demand, x' = thousands of units per dollar
(c) Compute the elasticity of demand when x = 4. Do not round your answer.
The elasticity of Demand =
2) The yearly demand function for Penn State Bakery cookie trays is given by
x2 + 3p2 + 8x + 12p = 216
where p is the wholesale unit price in dollars and x is the quantity demanded each year, measured in units of a thousand.
(a) Compute the price, p, when x = 10.
Price, p =
dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 10. Do not round your answer.
Rate of change of demand, x' = thousands of units per dollar
(c) Compute the elasticity of demand when x = 10. Do not round your answer.
Elasticity of Demand =
3)
The weekly demand equation is given by
p + x + 3xp = 53,
where x is the number of thousands of units demanded weekly and p is in dollars. If the price p is decreasing at a rate of 70 cents per week when the level of demand is 5000 units, then demand is
decreasing
increasing
at units per week.
4)
A company is decreasing production of math-brain protein bars at a rate of 100 cases per day. All cases produced can be sold. The daily demand function is given by
p(x) = 20 −
x
200
,
where x is the number of cases produced and sold, and p is in dollars.
If the daily production is 800 cases, then revenue is
increasing decreasing
at a rate of dollars per day.
5)
The wholesale price p of e-tablet writing styluses in dollars is related to the supply x in thousands of units by
400p2 − x2 = 14375,
If 5,000 styluses are available at the beginning of a week, and the price is falling at 30 cents per week, then supply is
falling rising
at a rate of styluses per week.
1. a) The price is 5 dollars. b) The rate of change of demand with respect to price, p, when x = 4 is 5/6 thousands of units per dollar. c) The elasticity of demand when x = 4 is 25/24.
2. a) The price is 2*sqrt(3) dollars. b) The rate of change of demand with respect to price, p, when x = 10 is - (3 * sqrt(3))/(7) thousands of units per dollar. c) The elasticity of demand when x = 10 is -6/7.
3. Demand is increasing at -23.30 thousands of units per week.
4. If the daily production is 800 cases, then revenue is decreasing at a rate of -1200 dollars per day.
5. Supply is rising at a rate of 150.90 thousands of styluses per week.
1)
(a) Compute the price, p, when x = 4.
Price, p = −3(4)^2 − 4(4) + 69 = -48 -16 + 69 = 5 dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 4.
Rate of change of demand, x' = - (2 * -3 * x + 4)/(-3 * 2 * x) = -(-24 + 4)/(-24) = 20/24 = 5/6 thousands of units per dollar
(c) Compute the elasticity of demand when x = 4.
The elasticity of Demand = (x'/x) * (p) = (5/6)/(4) * (5) = 25/24
2)
(a) Compute the price, p, when x = 10.
Price, p = sqrt((216 - 10^2 - 8*10)/3) = sqrt((216 - 100 - 80)/3) = sqrt(12) = 2*sqrt(3) dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 10.
Rate of change of demand, x' = - (2 * 3 * p)/(2 * x + 8) = - (6 * 2 * sqrt(3))/(20 + 8) = - (12 * sqrt(3))/(28) = - (3 * sqrt(3))/(7) thousands of units per dollar
(c) Compute the elasticity of demand when x = 10.
Elasticity of Demand = (x'/x) * (p) = (- (3 * sqrt(3))/(7))/(10) * (2*sqrt(3)) = -6/7
3)
The weekly demand equation is given by p + x + 3xp = 53,
where x is the number of thousands of units demanded weekly and p is in dollars. If the price p is decreasing at a rate of 70 cents per week when the level of demand is 5000 units, then demand is increasing at a rate of (53 - 5000 - 70)/(3*70 + 1) = -4917/211 = -23.30 thousands of units per week.
4)
A company is decreasing production of math-brain protein bars at a rate of 100 cases per day. All cases produced can be sold. The daily demand function is given by p(x) = 20 − x/200,
where x is the number of cases produced and sold, and p is in dollars.
If the daily production is 800 cases, then revenue is decreasing at a rate of (20 - 800/200) * (-100) + (800) * (-1/200) * (-100) = (20 - 4) * (-100) + (800) * (1/2) = -1600 + 400 = -1200 dollars per day.
5)
The wholesale price p of e-tablet writing styluses in dollars is related to the supply x in thousands of units by 400p^2 − x^2 = 14375,
If 5,000 styluses are available at the beginning of a week, and the price is falling at 30 cents per week, then supply is rising at a rate of (2 * 400 * p * (-0.30) - 2 * x * x')/(2 * -1 * x) = (800 * p * (-0.30) - 0)/(2 * -5000) = (800 * sqrt(14375 + 5000^2)/400 * (-0.30) - 0)/(2 * -5000) = (800 * sqrt(14375 + 25000000)/400 * (-0.30))/(2 * -5000) = (2 * sqrt(14375 + 25000000) * (-0.30))/(-5000) = 0.012 * sqrt(14375 + 25000000) = 150.90 thousands of styluses per week.
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What is the solution of log^3x-2^125=3
The solution to the logarithmic equation log_(3x - 2)(125) = 3 is given as follows:
x = 7/3.
How to solve the logarithmic equation?
The logarithmic equation for this problem is defined as follows:
log_(3x - 2)(125) = 3
The definition of the logarithm can be applied, which means that if we elevate the base of 3x - 2 to the power of 3, we obtain the result of 125.
With the application of the definition, the expression is given as follows:
(3x - 2)³ = 125.
125 is the third power of 5, hence:
(3x - 2)³ = 5³.
The third power function is one-to-one function, meaning that each output is related to a single input, hence the value of x is obtained as follows:
3x - 2 = 5
3x = 7
x = 7/3.
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The Question is the About the mathematic about the passengers How many total passengers are on the flight? How many that is the Question and I need the Answer Now
The number of passengers on one flight is 467.
To calculate the average number of passengers on one flight, we need to divide the total number of passengers by the total number of flights:
Total number of passengers = 456,705
Total number of flights = 995
Maximum passenger capacity per flight = 467
Therefore, the average number of passengers on one flight can be calculated as follows:
Average number of passengers per flight = Total number of passengers / Total number of flights
= 456,705 / 995
= 459.18 (rounded to two decimal places)
However, since the maximum passenger capacity per flight is 467, the actual number of passengers on one flight cannot be higher than that. Therefore, the answer is:
Number of passengers on one flight = Maximum passenger capacity per flight = 467
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The given question is incomplete, the complete question is:
United Airlines flies 456705 passengers every week. A Flight has a maximum passenger capacity of 467 passengers. if it completes 995 flights in a week ,then how many passengers are there on one flight?
PLS HELP 30 POINTS I REALLY NEED HELP RN
Answer:
Bears: 12
Tigers: 5
Step-by-step explanation:
9:15
the common factor of 9 and 15 is 3. so we divide both sides by 3.
3:5
12:20
Which function has a zero with a multiplicity of 2 ? f(x)=-3x^(2)+12x+12 f(x)=3x^(2)+24x+48 f(x)=x^(2)+3x+9 f(x)=x^(2)-2x-1
The function f(x) = 3x² + 24x + 48 has a zero with a multiplicity of 2.
To determine which function has a zero with a multiplicity of 2, we need to find the discriminant of each quadratic function and check if it is equal to zero.
The discriminant is given by the formula: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
Let's calculate the discriminant for each function:
1) f(x) = -3x² + 12x + 12
Discriminant: b² - 4ac = (12)² - 4(-3)(12) = 144 + 144 = 288 (not zero)
2) f(x) = 3x² + 24x + 48
Discriminant: b² - 4ac = (24)² - 4(3)(48) = 576 - 576 = 0 (zero)
3) f(x) = x² + 3x + 9
Discriminant: b² - 4ac = (3)² - 4(1)(9) = 9 - 36 = -27 (not zero)
4) f(x) = x² - 2x - 1
Discriminant: b² - 4ac = (-2)² - 4(1)(-1) = 4 + 4 = 8 (not zero)
Based on the calculations, the function f(x) = 3x² + 24x + 48 has a zero with a multiplicity of 2.
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I need some help please
Answer:
Step-by-step explanation:
so first you add 3 by 4 and see if it is greater than six and then that's your answer.
What is the distance between the points (-9, 4) and (3, 12) ?
A. 12 units
B. 16 units
C. 20 units
D. 28 units
The distance between the points (-9, 4) and (3, 12) is approximately 14.42 units.
what exactly is distance?
Distance is the amount of space between two objects or locations. It is a measure of how far apart two things are from each other, typically expressed in units such as meters, kilometers, miles, feet, or yards. Distance can be measured in a straight line, known as the "Euclidean distance," or it can be measured along a path or route, known as the "distance traveled." Distance is a fundamental concept in many areas of science and mathematics, including physics, geography, and geometry
The formula for calculating the distance between two points is d = ((x2 - x1)2 + (y2 - y1)2).
Let's use this formula to find the distance between the two points (-9, 4) and (3, 12):
d = √((3 - (-9))² + (12 - 4)²)
= √(12² + 8²)
= √(144 + 64)
= √208
≈ 14.42
So the distance between the points (-9, 4) and (3, 12) is approximately 14.42 units.
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Line AB below is 10 cm long.
Line AC is 15 cm long.
Line BE is 8 cm long.
Calculate the length of line CD.
Give your answer as an integer or as a fraction
in its simplest form.
Using the triangle proportionality theorem, the length of CD is calculated as: 12 cm.
How to Calculate the Length of the Line?The triangle proportionality theorem states that if a line is parallel to one side of a triangle, it divides the other two sides proportionally.
To calculate the length of the line, recall the triangle proportionality theorem which states that:
Given the following:
AB = 10 cm
AC = 15 cm
BE = 8 cm
CD = ?
Based on the triangle proportionality theorem, we have:
AC/AB = CD/BE
Substitute:
15/10 = CD/8
Cross multiply:
10CD = 120
CD = 120/10
CD = 12 cm
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Answer this quickly please
The size of the angle that the line DE makes with the plane ABCD is 50.8 degrees
How to determine the measure of the angleFrom the question, we have the following parameters that can be used in our computation:
The figure
To start with, we calculate the measure of length BE using the following tangent ratio
tan(60) = BE/60
So, we have
BE = 60√3
Next, we calculate DB using the Pythagoras theorem
DB = √(60² + 60²)
Evaluate
DB = 60√2
The measure of the required angle is then calculated as
tan(Angle) = 60√3/60√2
Evaluate
tan(Angle) = 1.2247
Take the arc tan
Angle = 50.8 degrees
Hence, the angle is 50.8 degrees
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What function does this graph represent?
Solve this number riddle:
I am an odd number.
I am less than 100.
The sum of my digits is 12.
I am a multiple of 15.
What number am I?
Answer:75
Step-by-step explanation:
7+5=12
15x5=75
75 is odd and I just went through the multiples of 15 haha