Which unit of size are the smallest organisms found on Earth?


millimeters


picometers


nanometers


micrometers

Answer:

It’s ionisation

Explanation:

Answer:

the answer to this is non impact

Answer:

3.83%

Explanation:

First, find the average of the measured value.  You should get 286.

291 + 287 + 295 + 281 = 1154

1154/4 = 288.5

Subtract the accepted value (300) from the average measured value (286).  Take the absolute value of your answer.  You should get 14.

288.5 - 300 = -11.5 = 11.5

Divide the difference from the above problem (14) by the accepted value (300).  You should get 0.0467.

11.5/300 = 0.0383

Multiply by 100%.

0.0383 × 100% = 3.83%

The percent error is 3.83%.

Answer:

3.83 percent

Explanation:

Accepted Value = 300 degrees celsius

So since we are given the formula for percentage error,

we know that we have to find the average measured value since the accepted value is already provided

Average Measured Value:

Sum of all measured values / number of measured values

(291 + 287 + 295 + 281) / 4

1154 / 4

288.5 degrees celsius

Now, plugging the values in the given formula:

(average measured value - accepted value) *100 / accepted value

(288.5 - 300) * 100 / 300

-1150 / 300

-3.83 percent

Taking Absolute Value:

3.83 percent

Hence, the average value of the temperature is 3.83 percent less than the accepted value

A brother is bragging about doing a bench press of 4000 grams at the gym. 4000 grams is equal to 8.818 pounds.

The bench press or chest press is training or weight training to strengthen your arm and chest muscles. It is done by laying down on a bench and pushing and pulling up the bars with weight.

It is a common weight-lifting exercise in gyms. Trainers use accordingly weight on the basis of the trainee's weight and strength that is doing the bench press, and the weight is measured differently in different countries. Eight-pound is not a very big amount.

In America, weight is measured in pounds, one kg is 1000 grams and

1 gram is 0.00220462

4000 x 0.00220462

4000 grams will be 8.818 pounds.

Thus, 4000 grams is equal to 8.818 pounds.

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Answer:

Liquid: water

Solid: Rocks

Gas: Air

Explanation:

Answer:

at first click done,

A: exponential

then, i just put 0.5, and somewhat close.

Explanation:

edge 2021!!!

Answer:

D. all of the answers are correct

Explanation:

edge 2020

Rainforests are defined by the evergreen and canopy trees. The tropical and temperate rainforests differ in the locations, type of plantation, and temperature. Thus, option d is correct.

Tropical and temperate rainforests are rainforests that differ from each other based on various factors. The tropical rainforest is located at the latitude near the equator, between the Tropic of Cancer and Capricorn. They are covered with canopied trees and average warm temperature conditions.

On the other hand, the temperate rainforests are found away from the Equator near the north side of the tropics and are marked by the presence of coniferous or broadleaf trees. They have a cooler climate and two seasons.

Therefore, option d. the tropical and temperate rainforests have different temperatures, locations, and trees.

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Answer:

Iron

Explanation:

The only substance that cannot be broken down by a chemical change is Iron.

Iron is an element and elements are made up of atoms. Atoms are the smallest indivisible particles that takes part in chemical reactions.

Answer:

Loss of muscle mass because there is no weight on the back and legs.

Explanation:

Answer:

106.7 degrees f

Explanation:

Answer:

4.5 × 10²³ number of atoms Al

Explanation:

Given data:

Mass of Al = 20 g

Number of atoms of Al = ?

Solution:

The given problem will solve by using Avogadro number.

'It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance" .The number 6.022 × 10²³ is called Avogadro number.

We will calculate  the number of moles of Al first:

Number of moles = mass/molar mass

Number of moles = 20 g/ 27 g/mol

Number of moles = 0.74 mol

1 mole = 6.022 × 10²³ number of atoms

0.74 mol ×  6.022 × 10²³ number of atoms / 1 mol

4.5 × 10²³ number of atoms Al

The required number of atoms is [tex]4.46\times 10^{23}[/tex]

Atomic weight, also called relative atomic mass, ratio of the average mass of a chemical element’s atoms to some standard.

Given that,

Mass=[tex]20[/tex] grams

1 mole of aluminum [tex]= 27g = 6.023\times10^{23}[/tex] number of atoms 27g of aluminum contains [tex]6.023\times10^{23}[/tex] a number of atoms.

Therefore,20 grams the number of atoms is,

[tex]6.023\times10^{23}\times\frac{20}{27} =4.46\times10^{23}[/tex]

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Answer:

Test variable (independent variable): Predators, Pollution, Food.Outcome variable (dependent variable): Cricket Frogs.Control group: Beginning Frog Count

Explanation:

If pollution isincreased, then the cricket frog population will (stay the same) over the span offive years.If the amount of food available isincreased, then the cricket frog population will (increase) overthe span of five years.Procedure:The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sureto identify the test variable (independent variable), outcome variable (dependent variable), andcontrol group for this experiment.

Answer: below -45

Explanation:

Answer:

The glass cup falling from the counter

Explanation:

the glass isn't changing in any chemical way. it's still made of the same material, just broken apart.

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

[tex]a=\frac{v-u}{t}[/tex]

thus,

[tex]t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds[/tex]

The molar mass of the unknown gas is 17.75 g/mol  

R ∝ [tex]\frac{1}{\sqrt{M}}[/tex]

Expanding further, we have

[tex]\frac{R_{1} }{R_{2} } = \sqrt{\frac{M_{2}}{M_{1}} }[/tex]

Where

R₁ and R₂ are the rate of diffusion of the individual gas

M₁ and M₂ are the molar masses of the individual gas.

With the above information in mind, we can obtain the molar mass of the unknown gas as follow:

Let R₁ be the rate of the unknown gas

Let R₂ be rate of Cl₂ gas

Let M₁ be the molar mass of the unknown gas

Let M₂ be the molar mass of the Cl₂ gas

From the question given above, we were obtained the following:

Rate of the unknown gas = 2 times the rate of Cl₂ i.e

Molar mass of Cl₂ (M₂) = 2 × 35.5 = 71 g/mol

[tex]\frac{R_{1} }{R_{2} } = \sqrt{\frac{M_{2}}{M_{1}} }\\\\\\\frac{2R_{2}}{R_{2} } = \sqrt{\frac{7 1}{M_{1}} }\\\\2 = \sqrt{\frac{7 1}{M_{1}} }[/tex]

[tex]2^{2} = \frac{71}{M_{1}} \\\\4 = \frac{71}{M_{1}}[/tex]

4 × M₁ = 71

[tex]M_{1} = \frac{71}{4}[/tex]

Therefore, the molar mass of the unknown gas is 17.75 g/mol

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Answer:

Mintu should chosen a material with a lower specific heat

Explanation:

I got the answer right on the test trust me it is correct

Answer:

A. color change

Explanation:

changing the color of a metal does not change its physical properties.

hope it helps.

Given :

Mass of given magnesium chloride, m = 256 g.

To Find :

How many grams of chloride are there in 256 g of magnesium chloride.

Solution :

Molecular formula of magnesium chloride is [tex]MgCl_2[/tex].

Molecular formula of [tex]MgCl_2[/tex] is, M = 95.211 g/mol .

Mass of chlorine in 1 mol of [tex]MgCl_2[/tex]  is , m = 35.5 × 2 = 71 g.

So, amount of chlorine in 256 gram [tex]MgCl_2[/tex] :

[tex]m =\dfrac{71\times 256}{95.211}\\\\m = 190.90\ g[/tex]

Hence, this is the required solution.

Answer:

A pure substance is a substance that is only made up of atoms of one element and so it has fixed melting and boiling points.

Answer:

nuetrons and protons

Explanation:

Explanation:

the electron pair will be attracted more strongly to the atom that has the higher electronegativity

hope it help

Answer:

protons and neutrons so A and C

Answer:Three mutual conversions of energy forms occur at nuclear power plants: nuclear energy is converted into thermal energy, thermal energy is converted into mechanical energy, and mechanical energy is converted into electric energy.

Explanation:

Answer:

Wrap a magnet in plastic lunch wrap and move it through the mixture of the three solids. The iron filings will stick to the magnet. The filings can be removed by unwrapping the plastic from the magnet carefully! Mix the remaining salt and sand in water and stir.

Explanation:

Answer:

I hope this answer is correct

Explanation:

This is an oxidation-reduction (redox) reaction:

Zn0 - 2 e- → ZnII (oxidation)

2 HI + 2 e- → 2 H0 (reduction)

Zn is a reducing agent, H2SO4 is an oxidizing agent.

Reactants:

Zn

Names: Zinc source: wikidata, accessed: 2019-09-07, Zinc powder (pyrophoric) source: ICSC, accessed: 2019-09-04, Zn source: wikidata, accessed: 2019-09-07

Appearance: Grey-to-blue powder source: ICSC, accessed: 2019-09-04

H2SO4 – Sulfuric acid source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: NIOSH NPG, accessed: 2019-09-02

Other names: Oil of vitriol source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Sulfuric acid, concentrated (> 51% and < 100%) source: ICSC, accessed: 2019-09-04, H2SO4 source: wikidata, accessed: 2019-09-07

Appearance: Clear, colorless liquid source: wikipedia, accessed: 2019-09-27; Odourless colourless oily hygroscopic liquid source: ICSC, accessed: 2019-09-04; Colorless to dark-brown, oily, odorless liquid. [Note: Pure compound is a solid below 51°F. Often used in an aqueous solution.] source: NIOSH NPG, accessed: 2019-09-02

Products:

ZnSO4 – Zinc sulfate source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04

Other names: White vitriol source: wikipedia, accessed: 2019-09-27, Goslarite source: wikipedia, accessed: 2019-09-27, Zinc sulfate (1:1) source: wikidata, accessed: 2019-09-02

Appearance: White powder source: wikipedia, accessed: 2019-09-27; Colourless hygroscopic crystals source: ICSC, accessed: 2019-09-04

H2

Names: Dihydrogen source: wikidata, accessed: 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07