which type of graph represents a system of linear equations that has muttiple common coordinate pairs as a solutions

Answer:

y=2.05x

Step-by-step explanation:

Figure out what the total cost is for 1 of them then you put that in as your M value, then X stands for number of sheets so 2.05 multiplied by the number of sheets sold you get your Y which is the total cost in dollars for x sheets.

The ratio of boys to total kids can be expressed in three different ways fraction, decimal, and percent which are 27:59,  0.4576 and 45.76% respectively.

First, let's find the total number of kids in the program. The total number of kids in the program is the sum of boys and girls. Total kids = boys + girls = 27 + 32 = 59. Now that we have the total number of kids, we can find the ratio of boys to total kids in three different ways. 1. Fraction: The ratio of boys to total kids can be expressed as a fraction, where the numerator is the number of boys and the denominator is the total number of kids. Boys: Total kids = 27:59 This fraction cannot be simplified.

2. Decimal: The ratio of boys to total kids can also be expressed as a decimal. To find the decimal, divide the number of boys by the total number of kids. Boys/Total kids = 27/59 = 0.4576 (rounded to four decimal places). 3. Percent: The ratio of boys to total kids can also be expressed as a percentage. To find the percentage, multiply the decimal by 100. Boys/Total kids × 100 = 0.4576 × 100 = 45.76%. Therefore, the ratio of boys to total kids can be expressed as a fraction, decimal, and percent as shown above.

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The equation will be :20 + 8.95 × 10 = $109.50

Here the total cost is $109.50.

Total cost refers to the total cost of production, which includes the fixed and variable parts of the cost. In economics, total cost is described as the cost required to produce a product. The total cost consists of two parts and they are: Fixed costs: These are the costs that do not change.

According to the Question:

C = 20 + 8.95× t

This can be read as : The total cost (C) will be $20 (setup fee) plus $8.95 for each t-shirt ordered (t).

The equation will be:

10 shorts would be 20 + 8.95*10, or $109.50.

Complete Question:

A t-shirt company charges a $20.00 set-up fee plus $8.95 for each t-shirt that is screen-printed with a school’s logo. Write a function that can be used to find the total cost, C, for purchasing and screen printing, t, number of t-shirts.

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The equation 125ˣ⁻² = (1/25)³ˣ when solved for x by the calculations below is 2/3

We can simplify both sides of the equation using the properties of exponents:

125ˣ⁻² = (1/25)³ˣ

Rewrite 125 as 5³ and 1/25 as 5⁻²

(5³)ˣ⁻² = (5⁻²)³ˣ

Simplify the exponents by multiplying:

5³ˣ ⁻ ⁶ = 5⁻⁶ˣ

Now we can see that the equation involves powers of the same base (5).

Therefore, we can solve for x by equating the exponents:

3x - 6 = -6x

Add 6x to both sides:

9x - 6 = 0

Add 6 to both sides:

9x = 6

Divide both sides by 9:

x = 2/3

Therefore, the solution to the equation is x = 2/3.

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In a sampling distribution of means, the distribution will approximate the normal distribution, the mean of the sampling distribution will equal the mean of the population and the standard deviation of the sampling distribution is based on Central Limit Theorem, option A.

The central limit theorem (CLT) of probability theory states that, under the assumption that all samples are of equal size and regardless of the population's actual distribution shape, the distribution of a sample variable approaches a normal distribution (i.e., a "bell curve") as the sample size increases.

In other words, the central limit theorem (CLT) is a statistical assumption that, given a sufficiently enough sample size from a population with a limited degree of variance, the mean of all sampled variables from the same population will be roughly equal to the mean of the entire population. According to the law of large numbers, these samples also resemble a normal distribution, with their variances almost equaling the variation of the population as the sample size increases.

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Complete question:

In a sampling distribution of means... 1. the distribution will approximate the normal distribution (bell curve). 2. the mean of the sampling distribution will equal the mean of the population 3. the standard deviation of the sampling distribution is called the standard error. This is based on the...

Central Limit Theorem

Standardization of Transformation

Z-Score Distribution Table

Relative Frequency of Probability

Answer:

(5 x 5 = (25) + 1 = (26) + 6 = ?)

Step-by-step explanation:

You're welcome.

Answer: 32

Step-by-step explanation:

5x5 is 25 +1=26 so 26+6=32

Answer:

Data Visualization Tools

Step-by-step explanation:

To solve this problem, we need to convert the hexadecimal numbers (20cba)16 and (a02)16 to decimal form, add them together, and then convert the result back to hexadecimal form.

(20cba)16 = 2x16^4 + 12x16^3 + 11x16^2 + 10x16^1 = 131402

(a02)16 = 10x16^2 + 0x16^1 + 2x16^0 = 256

Adding the two decimal numbers together gives us:

131402 + 256 = 131658

To convert this decimal number back to hexadecimal form, we can use the repeated division method.

131658 / 16 = 8228 remainder 10 (A)

8228 / 16 = 514 remainders 4 (4)

514 / 16 = 32 remainder 2 (2)

32 / 16 = 2 remainder 0

2 / 16 = 0 remainder 2

Therefore, (20cba)16 + (a02)16 = (131658)10 = (2002A)16.

To find their product, we can multiply the two decimal numbers together and then convert the result to hexadecimal form.

131402 x 256 = 33559552

Converting this decimal number to hexadecimal form gives us:

33559552 / 16 = 2097472 remainder 0

2097472 / 16 = 131092 remainder 0

131092 / 16 = 8193 remainder 4 (4)

8193 / 16 = 512 remainders 1 (1)

512 / 16 = 32 remainder 0

32 / 16 = 2 remainder 0

2 / 16 = 0 remainder 2

Therefore, the product of (20cba)16 and (a02)16 is (33559552)10 = (2011004)16.

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Therefore , the solution of the given problem of equation comes out to be the parabola expands upwards, with the vertex being a minimum point.

Complex algorithms frequently employ variable words to demonstrate consistency between two conflicting assertions. Equations are academic expressions that are used to demonstrate the equality of different academic figures. In this instance, normalization results in b + 7 rather than a singular formula that divides 12 into two components along with is able to be utilized to evaluate data obtained from y + 7.

Here,

A parabolic route taken by the eagle as it soars into the sky and then descends to the ground is shown by the equation

=> h = t² - 10t + 25.

The vertex of the equation, which is provided by the formulas

=> t = -b/2a and h = f(t),

where a, b, and c are the coefficients of the quadratic equation, can then be found in order to graph it.

Here,

=> a = 1, b = -10, and c = 25.

Consequently, the apex is at t = 5 and h = f(5) = 0, respectively.

Given that t² has a positive coefficient, the parabola expands upwards, with the vertex being a minimum point.

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The expression that equals ∠BEC is 3x - 27, and the answer is B.

First, we find the measure of ∠BEC using the given information and the value of x. We get

Then, we use the fact that ∠AED is vertically opposite to ∠BEC, so ∠AED = ∠BEC = 63 degrees.

Finally, we need to find the expression among the given choices that equals 63 when x = 30.

Option A is too large, option C is too large, and option D is too small. Option B gives us

which matches the measure of ∠BEC. Therefore, the answer is B.

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Complete Question:

If the measure of BEC is (2x+3) and x=30, which expression could represent the measure of AED?

Answer:

The Factor Theorem and Synthetic Division are not the same. The Factor Theorem states that if a polynomial f(x) has a root c, then x - c is a factor of f(x). Synthetic Division is a way of dividing a polynomial by a binomial.

Step-by-step explanation:

To use Synthetic Division, you first need to find the coefficients of the polynomial. Then, you set up the synthetic division table with the binomial on top and the coefficients of the polynomial on the bottom. Starting with the first coefficient, you multiply it by the first term of the binomial and write the product below the coefficient. Then, you add the two numbers below the product and write the sum below that. Continue until you reach the end of the binomial. The remainder at the bottom of the table is the remainder when f(x) is divided by x - c.

If the remainder is 0, then x - c is a factor of f(x).

To find the difference between 3/5 and 1/2 using fraction strips, we can use strips that are divided into fifths and halves, respectively.the difference between 3/5 and 1/2 is 2/10 or 1/5, , the answer in the simplest form is 1/5.

First, we'll need to represent each fraction using the fraction strips.

For 3/5, we can use three fifths strips to represent the numerator and put them together to form a whole.

For 1/2, we can use one half strip and cut it into two equal parts to represent the numerator.

Next, we'll need to compare the two fractions by placing them side by side.

We can see that the two fractions do not have the same denominator, so we need to find a common denominator to make the comparison easier.

The smallest common multiple of 5 and 2 is 10, so we can represent 3/5 using six tenths strips, and 1/2 using five tenths strips.

We can see that there are two tenths strips that are not shared between the two fractions.

Therefore, the difference between 3/5 and 1/2 is 2/10 or 1/5, , the answer in the simplest form is 1/5.

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Answer:

Step-by-step explanation: Since the rectangle sits within the larger circle, let's look at it this way:

Area of Shaded Region = Area of Circle - Area of Rectangle

OR

(X) =( pi * r^2 ) - (rectangle length * rectangle width)

Now we fill in the numbers where we know the numbers:

(X) = (pi * (12 cm)^2) - (3cm * 10cm)

(X) = (pi * 144cm^2) - (30 cm^2)

(X) = 144pi - 30

(X) = 452.39 - 30

(X) = 422.39 cm^2

The equation of the quadratic function that passes through these points is:

[tex]y = -3x^2 - 12x - 8.[/tex]

What is quadratic equation?

A quadratic equation is a polynomial equation of the second degree, which means it contains one variable with an exponent of 2. The general form of a quadratic equation is:

[tex]ax^2 + bx + c = 0[/tex]

Using polynomial interpolation with these 5 points, we can find a quadratic polynomial that passes through all the points. Let the equation of the polynomial be [tex]y = ax^2 + bx + c[/tex].

Using the point (0, -8), we get:

[tex]-8 = a(0)^2 + b(0) + c[/tex]

c = -8

Using the point (-1, 1), we get:

[tex]1 = a(-1)^2 + b(-1) - 8[/tex]

a - b = 9

Using the point (-3, 1), we get:

[tex]1 = a(-3)^2 + b(-3) - 8[/tex]

9a - 3b = 27

Using the point (-4, -8), we get:

[tex]-8 = a(-4)^2 + b(-4) - 8[/tex]

16a - 4b = 0

Using the point (-2, 4), we get:

[tex]4 = a(-2)^2 + b(-2) - 8[/tex]

4a - 2b = 12

Solving this system of equations, we get:

a = -3

b = -12

c = -8

Therefore, the equation of the quadratic function that passes through these points is:

[tex]y = -3x^2 - 12x - 8.[/tex]

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Answer:

The possible coordinates of point A are (−8,1) or (8,1).

Answer:

Y = 6*y

Step-by-step explanation:

We have Y = b * y by a factor of 6.

That is, b = 6.

now, to find what results only in a horizontal compression of y = b * y by a factor of 6.

By transformation rule, the function would be a horizontal compression f (a * x) if a> 1.

Therefore, knowing the above, the answer would be:

Y = 6 * y

Answer:

Step-by-step explanation:

3 2/5 -1 3/5 = 1.8

One way to do this is to subtract 1.8x from both sides of the equation, which gives:

x - 1.8x = 32

Simplifying the left-hand side, we get:

-0.8x = 32

To solve for x, we can divide both sides of the equation by -0.8:

x = 32 / (-0.8)

Simplifying, we get:

x = -40

Answer:

eqn of line : x-3y=15

slope1=m= -coefficient of x/coefficient of y=1/3

As lines are parallel slope must be equal.

slope3=m'=1/3

passing points of second line =(0,7)

eqn of line = (y-y')=m(x-x')

=(y-7)=1/3(x-0)

=y-7=1/3x

=1/3x-y+7=0

=x-3y+21=0

Step-by-step explanation:

Answer: y -5

Step-by-step explanation:

Yes, it is possible for all solutions of a homogeneous system of ten linear equations in twelve variables to be multiples of one fixed nonzero solution.

This occurs when the rank of the matrix of coefficients of the system is less than the number of variables, in this case 12. In this case, the system has infinitely many solutions, all of which can be expressed as a multiple of one nonzero solution.

To illustrate this concept, consider the following system of two equations in three variables:

[tex]2x + y + 3z = 0[/tex]

[tex]3x + y + 2z = 0[/tex]

The matrix of coefficients for this system is:

[tex][[3, 1, 2][/tex]

[tex][2, 1, 3]][/tex]

The rank of this matrix is 2, which is less than the number of variables, 3. Therefore, this system has infinitely many solutions, all of which can be expressed as a multiple of the following nonzero solution:

[tex](x, y, z) = (2, -3, 1)[/tex]

In other words, any solution [tex](x, y, z)[/tex] of the system will be of the form [tex](2a, -3a, a)[/tex], where a is any real number. This concept can be generalized to systems of ten linear equations in twelve variables.

In conclusion, when the rank of the matrix of coefficients of a homogeneous system of linear equations is less than the number of variables, then all solutions of the system are multiples of one fixed nonzero solution.

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Answer: 100000

Step-by-step explanation:

Answer:10

Step-by-step explanation: 14/4= 3.5, 35/3.5=10

Answer: B

Step-by-step explanation:

because I did it and it was right lol

One example of a quadrilateral that is not a rectangle or a rhombus is a trapezoid. A trapezoid has one pair of opposite sides that are parallel, but the other pair of sides are not. (the figure is attached is attached below)

Yes, there are many other shapes that could have been drawn, such as a kite, parallelogram, or irregular quadrilateral. The possibilities are endless, as long as the shape has four sides.

A trapezoid is a quadrilateral with one pair of opposite sides parallel, but the other pair of sides are not. It can be visualized as a shape that resembles a ladder. Unlike a rectangle or rhombus, a trapezoid does not have equal side lengths or equal angles. It can be used in various mathematical contexts, such as finding the area or perimeter of a geometric figure. Additionally, there are many other shapes that could have been drawn instead of a trapezoid, as long as they have four sides. The shapes could have different angles and side lengths, leading to different properties and applications.

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Even a process that is functioning as it should will not yield output that conforms exactly to a standard because of natural variation.

The natural variation is the variability in the output of a system that is caused by factors that are not controlled.This type of variation is also known as common cause variation.

The output of the system is changed by natural variation in such a way that it deviates from a fixed standard. Despite this, natural variation is usually present in any system, and it cannot be entirely eliminated.

There will always be some variation, and it is vital to understand how much of it is acceptable. The output of the system may be brought back into conformity with the standard by removing the cause of special cause variation.

Measurement errors can be caused by a variety of factors, including incorrect equipment calibration, user error, or environmental factors.

These errors may be distinguished from natural variation and special cause variation because they are caused by the measurement process rather than the system itself.

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The solution of the system 2 -1 5 with -2 -1 in real form is (x, y) = (7/4, 7/2).

To solve the system with the given coefficients, first, let's rewrite it as a linear system of equations:

2x - y = 5
-2x - y = -2

Now, let's solve this system step-by-step:

Step 1: Solve for y in the first equation:
y = 2x - 5

Step 2: Substitute the expression for y from Step 1 into the second equation:
-2x - (2x - 5) = -2

Step 3: Simplify and solve for x:
-2x - 2x + 5 = -2
-4x = -7
x = 7/4

Step 4: Substitute the value of x back into the expression for y:
y = 2(7/4) - 5
y = 7/2

The solution in real form is (x, y) = (7/4, 7/2).

Regarding the ellipse with counterclockwise orientation, the trajectory can be described as a smooth, closed curve in the shape of an ellipse. The ellipse will have a major and minor axis, with the points on the ellipse moving continuously in a counterclockwise direction along the curve.

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The product of the eigenvalues is equal to the determinant of the matrix. In other words, if λ1, λ2, ..., λn are the eigenvalues of a square matrix A, then det(A) = λ1 * λ2 * ... * λn. This relationship also holds true for both matrices A and C.

To enter matrices A and C in MATLAB, we can use the following commands:

A = [6, -1, 0; -1, -2, -1; 0, -1, 2];

C = [1, -1, 1; -1, 2, 0; 0, -1, 2];

To find the trace of A and C, we can use the following commands:

trace_A = trace(A);

trace_C = trace(C);

The trace of matrix A is 6 - 2 + 2 = 6, and the trace of matrix C is 1 + 2 + 2 = 5.

To find the eigenvalues of A and C, we can use the eig() function in MATLAB:

[eig_vec_A, eig_val_A] = eig(A);

[eig_vec_C, eig_val_C] = eig(C);

The eigenvalues of matrix A are -1, 1, and 6, and the eigenvalues of matrix C are 1, 1, and 2.

There is a relationship between the trace of a square matrix and its eigenvalues. Specifically, the sum of the eigenvalues is equal to the trace of the matrix. In other words, if λ1, λ2, ..., λn are the eigenvalues of a square matrix A, then trace(A) = λ1 + λ2 + ... + λn. This relationship holds true for both matrices A and C.

To find the determinant of A and C, we can use the following commands:

det_A = det(A);

det_C = det(C);

The determinant of matrix A is 12, and the determinant of matrix C is 5.

There is also a relationship between the eigenvalues and the determinant of a square matrix. Specifically, the product of the eigenvalues is equal to the determinant of the matrix. In other words, if λ1, λ2, ..., λn are the eigenvalues of a square matrix A, then det(A) = λ1 * λ2 * ... * λn. This relationship also holds true for both matrices A and C.

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