Which statements are true about a triangular pyramid? Check all that apply
It has exactly to faces that are triangles.
has exactly three faces that are triangles.
It has exactly four faces that are triangles
chas 4 vertices
it has 5 faces
It has 6 edges

Answer:

[tex]4m+20>50[/tex]

Step-by-step explanation:

Let m represent the amount of months that has passed.

Paulo started out with 20 coins.

Each month, he adds four more coins to his collection.

Therefore, the amount of coins added after m months will be given by 4m.

So, the amount of coins Paulo has total after m months can be given by:

[tex]4m+20[/tex]

We want to know when Paulo will have "more than" 50 coins in his collection. Therefore, we will use the "greater than" sign. Thus, our inequality will be:

[tex]4m+20>50[/tex]

9514 1404 393

Answer:

  (x +4)^2 +(y +8)^2 = 64

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

The circle centered at (h, k) = (-4, -8) with radius 8 has equation ...

  (x +4)^2 +(y +8)^2 = 64

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Step-by-step explanation:

According to the question, the values will be:

The service rate of guess will be:

= [tex]5+3.5[/tex]

= [tex]8.5 \ minutes[/tex]

The mean arrival rate will be:

[tex]\lambda =\frac{60}{5}[/tex]

  [tex]=7.5 \ cabs/hr[/tex]

The mean service rate will be:

[tex]\mu= 7.05 \ cabs/hr[/tex]

(1)

The average time a cab must wait will be:

⇒ [tex]W_q=22.95-\frac{1}{7.05}[/tex]

⇒       [tex]=\frac{161.798-1}{7.05}[/tex]

⇒       [tex]=\frac{160.798}{7.05}[/tex]

⇒       [tex]=22.81 \ minutes[/tex]

(2)

The required probability will be:

⇒ [tex]P(X\geq 6)=\frac{1-2.115}{1-7.5}[/tex]

⇒                  [tex]=\frac{-1.1115}{-6.5}[/tex]

⇒                  [tex]=0.171[/tex]

Answer:

Step-by-step explanation:

180 - ( 37+67) = 180 - 104

                      = 76°

9514 1404 393

Answer:

  D.  none of the above

Step-by-step explanation:

The sides are different lengths and not at right angles, so the figure is not a rhombus or a rectangle. It is "none of the above."

__

Counting grid squares in the attached figure, we see that one side is the diagonal of a 2×3 rectangle, and the adjacent side is the diagonal of a 1×3 rectangle. This tells you two things: (a) the sides are different length, (b) they are not at right angles to each other. (If the sides were perpendicular, the slopes of the segments would be opposite reciprocals.)

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{n - \dfrac{31}{105}>1}[/tex]

[tex]\large\textsf{First you have to SIMPLIFY EACH SIDES of the INEQUALITY}[/tex]

[tex]\mathsf{n + (-\dfrac{31}{105})>1}[/tex]

[tex]\large\textsf{Second ADD }\mathsf{\dfrac{31}{105}}\large\textsf{ to BOTH of your SIDES}[/tex]

[tex]\mathsf{n - \dfrac{31}{105}+\dfrac{31}{105}> 1 +\dfrac{31}{105}}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{-\dfrac{31}{105}+\dfrac{31}{105}}\large\textsf{ because that gives the value of 0}[/tex]

[tex]\large\textsf{KEEP: }\mathsf{1+\dfrac{31}{105}}\large\textsf{ because it helps what is being COMPARED to the n value}[/tex]

[tex]\large\textsf{Simplify above (}\mathsf{1+\dfrac{31}{105}}\large\textsf{) and you should have your result to this question}[/tex]

[tex]\mathsf{1+\dfrac{31}{105}=\bf \dfrac{136}{105}}[/tex]

[tex]\boxed{\mathsf{Answer: \bf n> \dfrac{136}{105\ }\boxed{\large\textsf{ it is an \bf O P E N E D circle shaded to the right}}}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

shaded area = 2x² + 6x + 17

If these are squares, what is the "x + 3"?

Step-by-step explanation:

shaded area = (x + 4)² - (x - 1)² = x² + 8x + 16 + x² - 2x + 1 = 2x² + 6x + 17

The answer is No!! I hope this helps, have a wonderful day!

Answer:

A) yes, both functions are inverses of each other.

[tex]---------[/tex]

[tex]hope ~ it ~ helps\\\\have ~ a ~ great ~day!![/tex]

Answer:

a) 0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

b) 0.4129 = 41.29% probability that the mean return will be less than 8%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 8.7% and standard deviation 20.2%.

This means that [tex]\mu = 8.7, \sigma = 20.2[/tex]

40 years:

This means that [tex]n = 40, s = \frac{20.2}{\sqrt{40}}[/tex]

(a) What is the probability (assuming that the past pattern of variation continues) that the mean annual return on common stocks over the next 40 years will exceed 13%?

This is 1 subtracted by the pvalue of Z when X = 13. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{13 - 8.7}{\frac{20.2}{\sqrt{40}}}[/tex]

[tex]Z = 1.35[/tex]

[tex]Z = 1.35[/tex] has a pvalue of 0.9115

1 - 0.9115 = 0.0885

0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

(b) What is the probability that the mean return will be less than 8%?

This is the pvalue of Z when X = 8. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{8 - 8.7}{\frac{20.2}{\sqrt{40}}}[/tex]

[tex]Z = -0.22[/tex]

[tex]Z = -0.22[/tex] has a pvalue of 0.4129

0.4129 = 41.29% probability that the mean return will be less than 8%

Step-by-step explanation:

1.

Given that,

L = 18 in , w = 20 in , h = 16 in

The surface area of the box is given by :

SA= 2lw + 2lh + 2wh

Put all the values,

SA= 2lw + 2lh + 2wh

= 2(lw+lh+wh)

= 2(18(20)+18(16)+20(16))

= 2 (968)

= 1936 in²

2.

L= 10.5 in , W= 15.5 in , H= 20 in

The surface area of the box is given by :

SA= 2lw + 2lh + 2wh

Put all the values,

SA= 2lw + 2lh + 2wh

= 2(lw+lh+wh)

= 2(10.5(15.5)+10.5(20)+15.5(20))

= 2 (682.75)

= 1365.5 in²

Hence, this is the required solution.

Answer:

1. 1/4 or 25/100, .25 and 25%

2. 1/10 or 1/100, .10 and 10%

Step-by-step explanation:

25 cubes out of 100 is 25/100

Simplify to 1/4

if its 25 cubes out of 100 its gonna fill up 25% or .25 of the whole thing

10 cubes out of 100 is 10/100

then simplify to 1/10

other two are obvious lol

Answer:

March is the first month

Step-by-step explanation:

If we make a graph. We can see that the quantity of sold water skis overpasses the quantity of snow skis in the month of March.

Answer:

Hello!

answer x = 46

z = 24

y = 14

Answer:

Method 1 = 8.75

method 2 = 12.16

Hope this helped gll

Step-by-step explanation:

Answer:

Step-by-step explanation:

F=9/5C+32 should be F = (9/5)C + 32

We are given 111 degrees F and want the same temperature in degrees Celcius.

In F = (9/5)C + 32 multiply all three terms by 5:

5F = 9C + 160, which can be solved for C:

5F - 160 = 9C

Let F = 111.  Then   555 - 160 = 9C, or

                               395 = 9C

Dividing both sides by 9, we get   C = 395/9 = 43 8/9 degrees C

Answer:

[tex] {(x + 5)}^{2} - {x}^{2} \\ {x }^{2} + 10x + 25 - {x}^{2} \\ 10x + 25 \\ 5(2x + 5)[/tex]

Answer: 18

Step-by-step explanation:

you just times the 4 1/2 4 times

Answer:

[tex] = 9102 \div 7 \\ = 1300.29 \\ [/tex]

Answer:

okey???????????????????????? p and q is true got it.

Answer:

wat?

Step-by-step explanation:

9514 1404 393

Answer:

  50

Step-by-step explanation:

The attachment shows the vocabulary associated with a subtraction equation.

In your equation, the difference is 50.

Answer:

6,9 and 3 times respectively

The product of given numbers is 60x³(x−3)²(x+2)

What is an expression?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a complete sentence. Any one of the following mathematical operations can be used. A sentence has the following structure: Number/variable, Math Operator, Number/Variable is an expression.

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra,

Multiply the numbers:

6x²x(x−3) * (x−3)10(x+2)

Multiply 6 and 10

60x²x(x−3) (x−3)(x+2)

Multiply x terms

60x³(x−3) (x−3)(x+2)

Multiply (x-3) terms

60x³(x−3)²(x+2)

So, the product of given numbers is 60x³(x−3)²(x+2)

To learn more about the expression from the given link

https://brainly.com/question/1859113

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Answer:

it  wont let me put any numbers down, it keeps saying they're improper

Step-by-step explanation:

Answer: She has read 33.75% of the pages.

Explanation: You can divide 27 by 80 to get the answer :)

Answer:

  14

Step-by-step explanation:

You want to know the size of the universal set if ...

The given sets are mutually exclusive and exhaustive, so the sum of their sizes is the size of the universal set:

  n(u) = 3 + 4 + 7

  n(u) = 14

__

Additional comment

  (r'∩s') ∪ (r'∩s) = r'∩(s' ∪ s) = r' . . . . n(r') = 3

  (r∩s) ∪ (r∩s') = r∩(s ∪ s') = r . . . . . . n(r) = 4 +7 = 11

Then r' ∪ r = u, the universal set.  . . . . n(u) = 3 +11 = 14

The probability to choose tiles with the numbers 1, 2, and 3 in that order is a form of permutation and is equal to 1/504.

Permutations refer to the arrangements of objects in certain order or way.

The number of alternative arrangements in a set can be calculated mathematically using a permutation where the order of the configurations is important.

The probability to choose tiles with the numbers 1, 2, and 3 in that order is a form of permutation.

The probability is obtained as 1 / ₉P₃

where;

₉P₃ = 9! / (9 - 3)!

₉P₃ = 9! / 6!

9! = 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

6! = 6 * 5 * 4 * 3 * 2 * 1

₉P₃ = 504

Hence, the probability = 1/504

Learn more about permutations at: https://brainly.com/question/1216161

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Dirk will make 70 pars or better.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is that During the first several rounds of a golfing league, Dirk made par or better on 42 out of 90 holes.

Out of 90 holes, Dirk made par or better on 42 holes.

At this rate, Out of 1 hole, Dirk made par or better on (42/90) holes.

Then, Out of 150 holes, Dirk will make par or better on -

(42/90 x 150) holes

(42/90 x 150)

70

Therefore, Dirk will make 70 pars or better.

To solve more questions on expressions, visit the link below -

brainly.com/question/1041084

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Answer:

  see below

Step-by-step explanation:

You want the ingredient quantities for several different multiples of the basic recipe.

To fill the table, consider what the column heading is as a multiple of the recipe for 12 people. Use that multiplier for the rest of the numbers in the column.

  [tex]\begin{array}{ccccc}\text{12 people}&\times2&\times3&\times\dfrac{1}{3}&\times\dfrac{1}{2\vphantom{g_g}}\\\cline{1-5}1\text{ cup}&2&3&\dfrac{1\vphantom{b^b}}{3\vphantom{g_g}}&\dfrac{1}{2}\\3\text{ cups}&6&9&1&1\dfrac{1}{2}\\2\text{ cups}&4&6&\dfrac{2}{3\vphantom{_g}}&1\\\dfrac{1}{2}\text{ cup}&1&1\dfrac{1}{2}&\dfrac{1}{6}&\dfrac{1\vphantom{^b}}{4\vphantom{_g}}\\1\dfrac{\vphantom{^b}1}{3}&2\dfrac{2}{3}&4&\dfrac{4}{9}&\dfrac{2}{3}\end{array}[/tex]

Answer:

hdvbn

Step-by-step explanation:

nfshvjjnmmnjjmbm