Which statements are always true regarding the diagram? Select three options. m∠5 + m∠3 = m∠4 m∠3 + m∠4 + m∠5 = 180° m∠5 + m∠6 =180° m∠2 + m∠3 = m∠6 m∠2 + m∠3 + m∠5 = 180°

Answers

Answer 1

The options which satisfy the given diagram are

m∠5 + m∠6 = 180°

m∠2 + m∠3 = m∠6

m∠2 + m∠3 + m∠5 = 180°

What is Angle Sum Property?

The sum of the interior angles of a triangle is 180°.

What is Exterior Angle Theorem?

The exterior angle of a triangle is equal to the sum of its interior opposite angles.

Let the Triangle be ABC and the exterior angle be ∠D , then

∠A + ∠B + ∠C =  180°

∠A + ∠B = ∠D , ∠A and ∠B are interior opposite angles of the triangle

So, the Options that satisfied

m∠5 + m∠6 = 180° { linear pair}

m∠2 + m∠3 = m∠6 {exterior angle theorem}

m∠2 + m∠3 + m∠5 = 180° {Angle Sum Property}

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Which Statements Are Always True Regarding The Diagram? Select Three Options. M5 + M3 = M4 M3 + M4 +

Related Questions

-8y + 25 ≤ -31
Please Answer

Answers

Answer:

Hi

Step-by-step explanation:

im pretty sure this the answer

hope this helps

good luck;)

Answer:

y≤7

Step-by-step explanation:

-8y+25≤-31

take away 25 from both sides

-8y≤-56

then divided by -8 on both sides

y≤7

Identify the domain and range of (f(x)=4[(x-2)^(1/2)]-8 To type in your answer, type the domain first, then a comma and space, and finally the range.

Answers

The domain of the function f(x) = 4[(x-2)^(1/2)]-8 is the set of all real numbers x such that x ≥ 2.

This is because the expression (x-2)^(1/2) is only defined for x ≥ 2. The range of the function is the set of all real numbers y such that y ≥ -8. This is because the expression 4[(x-2)^(1/2)]-8 is always greater than or equal to -8 for all values of x in the domain.

So, the domain and range of the function f(x) = 4[(x-2)^(1/2)]-8 are:
Domain: [2, ∞)
Range: [-8, ∞)

In conclusion, the domain and range of the function f(x) = 4[(x-2)^(1/2)]-8 are [2, ∞), [-8, ∞).

The domain of the function f(x) = 4[(x-2)1/2]-8 is the set of all real numbers x such that x ≥ 2. This is because the expression (x-2)1/2 is only defined for x ≥ 2. The range of the function is the set of all real numbers y such that y ≥ -8. This is because the expression 4[(x-2)1/2]-8 is always greater than or equal to -8 for all values of x in the domain.

So, the domain and range of the function f(x) = 4[(x-2)1/2]-8 are:

Domain: [2, ∞)

Range: [-8, ∞)


In conclusion, the domain and range of the function f(x) = 4[(x-2)1/2]-8 are [2, ∞), [-8, ∞).

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You are given the principal, the annual interest rate, and the compounding period. Determine the value of the account at the end of the specified time period. $6000, 4%, quarterly, 3 years A. $6181.81 B.$6749.18 C.$6760.95 D. $9606.19

Answers

The value of the account at the end of the specified time period is option B.$6749.81. It can be calculated using the formula for compound interest, which is:

A = P(1 + r/n)^(nt)

Where A is the final amount, P is the principal, r is the annual interest rate, n is the number of compounding periods per year, and t is the number of years.

Plugging in the given values, we get:

A = 6000(1 + 0.04/4)^(4*3)

A = 6000(1.01)^12

A = 6749.18

Therefore, the correct answer is B. $6749.18 using the compound interest formula.

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Rachel and David were shopping for holiday gifts when they noticed a Thanksgiving sweater on the discount rack. Rachel really wanted the sweater, even though she wouldn’t be wearing it until Thanksgiving of 2021! .Rachel has a coupon for an additional 25% off the sale price of the sweater. If she pays for the shirt with a $10 bill, what will her change be?

Answers

The change is negative, Rachel needs to provide an additional $1.25 to pay for the sweater.

What is the basic arithmetic operations?

The four basic arithmetic operations are Addition, subtraction, multiplication, and division.

To calculate Rachel's change, we first need to determine the sale price of the sweater after the discount and then subtract it from the $10 bill.

Let's say the original price of the sweater was $30, and it was discounted by 50% to $15. Rachel's coupon gives her an additional 25% off the sale price, so she can get the sweater for 75% of the sale price.

To calculate the final price Rachel will pay, we can multiply the sale price by 0.75:

Final price = $15 * 0.75 = $11.25

Rachel pays with a $10 bill, so her change will be:

Change = $10 - $11.25 = -$1.25

Hence, the change is negative, Rachel needs to provide an additional $1.25 to pay for the sweater.

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ch help video solution of the system of equations. 5x-y=44 -3x-y=-12 Submit Answer

Answers

The solution of the system of equations is x=7 and y=-9.

To find the solution of the system of equations, we need to solve for x and y. We can do this using the elimination method.

Multiply the first equation by 3 and the second equation by 5 to eliminate the x variable.
3(5x-y=44) -> 15x-3y=132
5(-3x-y=-12) -> -15x-5y=-60

Add the two equations together to eliminate the x variable.
15x-3y=132
-15x-5y=-60
-----------
-8y=72

Step 3: Solve for y.
-8y=72
y=-9

Substitute the value of y back into one of the original equations to solve for x.
5x-(-9)=44
5x+9=44
5x=35
x=7

Check the solution by substituting the values of x and y back into the original equations.
5(7)-(-9)=44
35+9=44
44=44

-3(7)-(-9)=-12
-21+9=-12
-12=-12

The solution is correct.

Submit the answer.
The solution of the system of equations is x=7 and y=-9.

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9. Determine the 6-day SMA for the 10-consecutive-trading-day closing
prices for SunEdison Inc. listed below.
$2.65 $2.63 $2.70 $2.63 $2.50 $2.65 $2.66 $2.56 $2.52 $2.37

Answers

The 6-day SMA for the given closing prices is as follows:

Day 1: 2.63

Day 2: 2.63

Day 3: 2.61

Day 4: 2.59

Day 5: 2.54

Calculating Simple Moving Average (SMA)

To calculate the 6-day Simple Moving Average (SMA) for the given closing prices, we need to take the sum of the last six closing prices and divide it by 6. Then we move one day forward and repeat the process until we have calculated the SMA for each day.

Here are the calculations:

Day 1: SMA = (2.65 + 2.63 + 2.70 + 2.63 + 2.50 + 2.65) / 6 = 2.63

Day 2: SMA = (2.63 + 2.70 + 2.63 + 2.50 + 2.65 + 2.66) / 6 = 2.63

Day 3: SMA = (2.70 + 2.63 + 2.50 + 2.65 + 2.66 + 2.56) / 6 = 2.61

Day 4: SMA = (2.63 + 2.50 + 2.65 + 2.66 + 2.56 + 2.52) / 6 = 2.59

Day 5: SMA = (2.50 + 2.65 + 2.66 + 2.56 + 2.52 + 2.37) / 6 = 2.54

Therefore, the 6-day SMA for the given closing prices is as follows:

Day 1: 2.63

Day 2: 2.63

Day 3: 2.61

Day 4: 2.59

Day 5: 2.54

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Exercise 2 An engineer analyses the presence (Yes-present, No= not present) of a specific terms in received messages (100 messages), to filter spams. These terms are: Donation, Ransom, Shows, Unsubscribe The analysis is based on the data shown below: No Donation Ransom Shows Unsubscribe Total
Yes No Yes No Yes No Yes No
Spam 4/20 16/20 10/20 10/20 0/20 20/20 12/20 8/20 20
Ham 1/80 79/80 14/80 66/80 8/80 71/80 23/80 57/80 80
Total 5/100 95/100 24/100 76/100 8/100 91/100 35/100 65/100 100 Suppose that you receive a new message that contains the terms Donation and Unsubscribe, but does not contain either Ransom or Shows. In your opinion, this new message will be classified as spam or ham? (assume class conditional independence: P(An B/C) = P(A/C)P(B/C) and use conditional probability)

Answers

The new message is more likely to be classified as spam.

Based on the given data, we can use the class conditional independence to calculate the probability that a message containing the terms Donation and Unsubscribe, but not Ransom or Shows, will be classified as spam or ham. By applying Bayes' Theorem, we can calculate that the probability of the message being classified as spam is P(spam/Donation, Unsubscribe) = (P(Donation/spam)P(Unsubscribe/spam)) / P(Donation, Unsubscribe) = (4/20 x 10/20) / (5/100 x 8/100) = 0.8. Therefore, the new message is more likely to be classified as spam.

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hil spent $21 of his $115 pocket money on eating out for one meal. What percent of Phil's pocket money did he spend on eating out for one meal? Round your answer to the nearest hundredth.

Answers

Step-by-step explanation:

for % questions always find 100% and/or 1%. everything else can be calculated based on these.

100% = $115

1% = 100%/100 = 115/100 = $1.15

how many % are $21 ?

as many as times 1.15 (1%) fits into 21 :

21/1.15 = 18.26086957...% ≈ 18.26%

Suppose g(x)=x+3/2. Evaluate g(g(1)) and g(g(g(1)))

Answers

Answer: g(g(1)) = 4 and g(g(g(1))) = 5 1/2

Step-by-step explanation:

We will first find g(1). To do so, we plug 1 in for x.

g(1) = (1) + 3/2 = 5/2 = 2 1/2

To find g(g(1)) we will plug in 5/2 for x.

g(g(1)) = (5/2) + 3/2 = 8/2 = 4

To find g(g(g(1))) we will plug in 4 for x.

g(g(g(1))) = (4) + 3/2 = 11/2 = 5 1/2

Hope this helps!

can You Please Help Me! I will mark You Brainliest! <33

Answers

Answer:

Step-by-step explanation:

1) ballet club

2) ballet club

At noon, the temperature on a mountaintop and the temperature on the ground had opposite values. The temperature on the mountaintop was 20° lower than temperature on the ground. What was the temperature in both places?

Answers

The temperature on mountaintop was -10° and the temperature on the ground was 10°. The solution has been obtained by using the linear equation.

What is a linear equation?

One is the degree of the linear equation. It is obvious that there are no variables in linear equations with exponents greater than 1. The graph's equation results in a straight line.

We are given that the temperature on the mountaintop was 20° lower than temperature on the ground.

Let the temperature on the ground be 'x'.

So, temperature on the mountaintop = x - 20

Also, the temperature on a mountaintop and the temperature on the ground had opposite values.

So,

x = - (x - 20)

On solving this, we get

⇒x = -x + 20

⇒2x = 20

x = 10°

So, x - 20 = 10 - 20 = -10°

Hence, the temperature on mountaintop was -10° and the temperature on the ground was 10°.

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In Exercises \( 1-8, W \) is a subset of \( R^{2} \) consisting of vectors of the form \[ \mathbf{x}=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right] \] In each case determine whether \( W \)

Answers

Yes

Yes, \( W \) is a subset of \( R^{2} \) since it consists of vectors of the form
\[ \mathbf{x}=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right] \]. Therefore, for Exercises \( 1-8 \), the answer is yes.

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Find the constant of variation k for the direct variation.
f(x)
0
-1
-2
-3.5
x02
0
4
7

Answers

The value of the constant of variation for the direct variation is k = -1/2.

What is constant of variation?

Variation depicts the relationship between two variables and how it changes. Often, a ratio is used to illustrate this connection. When we remark that a variation is continuous, we are referring to how consistently the ratio changes. Hence, whenever you read the phrase "constant of variation," just keep in mind that it refers to the stability of the relationship between the variables.

The direct variation is given by the following relations:

y = kx

Now, using the table substitute the value of y = f(x) and x:

y = kx

-2 = k(4)

k = -2/4

k = -1/2

Hence, the value of the constant of variation for the direct variation is k = -1/2.

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Find a function of the form y= A sin(kx) + C or y= A cos(kx) + C whose graph matches the function
shown below:

Answers

The equation of the sinusoidal graph will be y = 3 sin[(2/π)x] - 3.

What is trigonometry?

Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.

The graph is represented by the sinusoidal equation.

From the graph, the amplitude of the graph is 3 units and the graph is shifted 3 units down.

And the value of constant k is given as,

k = 4/2π

k = 2/π

Thus, the equation of the sinusoidal graph will be y = 3 sin[(2/π)x] - 3.

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Find the values of x and y
. Write your answer in
simplest form.
X
45°
X =
y =
y
16
&

Answers

Answer:

X: 45° Y:16°

Step-by-step explanation:

by help of teacher

Helppppppppppppppppppppp

Answers

Answer:   3. 200ft  4. 21ft

5. 37.5m  6. h=4.2ft

Step-by-step explanation:

O POLYNOMIALS AND FACTORING Polynomial long division: Problem type 1 Divide. (3x^(2)+20x+30)-:(x+5) Your answer should give the quotient and the remainder.

Answers

The quotient of the polynomial long division problem (3x2 + 20x + 30) : (x + 5) is 3x + 25 and the remainder is 0.

To solve this, use polynomial long division. First, divide the leading coefficient of the dividend (3) by the leading coefficient of the divisor (1). The quotient is 3 and this is placed above the dividend.

Then, multiply the quotient (3) by the divisor (x + 5) and subtract the product from the dividend (3x2 + 20x + 30). The difference is 3x + 25.

Finally, multiply the quotient (3x + 25) by the divisor (x + 5) and subtract the product from the difference (3x + 25). Since the difference is 0, the remainder is 0.

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Isn't it supposed to be one black triangle and one black square?

Answers

The value of the model expression when simplified is (d)

How to determine the expression

From the question, we have the following representation that can be used in our computation:

Black triangle = -xWhite triangle = xBlack square = -1White square = 1

Using the above as a guide, we have the following:

The given expression is

3 * Black triangle + 2 * White triangle + 2 * Black square + 1 * White square

This gives

-3x + 2x - 2 + 1

Evaluate the like terms

-x - 1

This means

1 Black triangle and 1 Black square

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Find the period of the function f(x) = cos(2.22x+0.19). Provide four decimal places. Answer:______ Find the period of the function f(x) = sin(1.05x). Provide four decimal places. Answer:______

Answers

The period of the function f(x) = cos(2.22x+0.19) is 2.8323 and the period of the function f(x) = sin(1.05x)  is 5.9834

The period of a trigonometric function, we use the formula:
Period = 2π/|B|
where B is the coefficient of x in the function.

For the first function, f(x) = cos(2.22x+0.19), the coefficient of x is 2.22. Therefore, the period is:
Period = 2π/|2.22| ≈ 2.8323

For the second function, f(x) = sin(1.05x), the coefficient of x is 1.05. Therefore, the period is:
Period = 2π/|1.05| ≈ 5.9834

So, the period of the first function is 2.83 and the period of the second function is 5.98. Both answers are rounded to four decimal places.

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Which of the following is a proportional relationship?10 apples cost $4 plus surcharge $0.20.Bacteria doubles every day.Volume of a cube and its side.4 books cost $9.

Answers

Therefore , the solution of the given problem of proportionality comes out to be connection is not proportional as a result.

What is the process of proportionality?

When a relationship consistently has the same number, it is considered to be proportional. For instance, the average amount of apples created by each tree determines how many trees there are in an area and how many apples are harvested. Mathematicians refer to a linear relationship between two numbers or factors as being proportional. The other amount doubles if the original amount does.

Here,

When there is a constant multiple between two variables in a relationship, that relationship is called a proportional relationship.

The expense of the 10 apples, which cost $4 plus a $0.20 surcharge, is not directly related to the quantity because the surcharge is a set price regardless of the quantity of apples.

The quantity being measured is growing by a fixed proportion (in this instance, 100%) every time period, so the bacteria doubling every day is an exponential relationship rather than a proportional one.

Last but not least, because the price per book varies, the $9 cost of 4 volumes is also not proportional. We would anticipate spending $18 if we were to purchase 8 books, which is not twice as much as 4 books. The connection is not proportional as a result.

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Calculate the interest earned when $46 230 is invested for 9 years at 7.8% p.a., with interest compounded twice a year.​

Answers

Given:

What is the interest earned when $46,230 is invested for 9 years at 7.8% p.a?

To find:

The interest

Solution:

[tex]interest = \frac{p \times r \times t}{100} [/tex]let the interest be x. [tex]x = \frac{46230 \times 9 \times 7.8}{100} [/tex][tex]x = 32456.46[/tex]But the interest is compounded twice a year so,

[tex]32456.46 \times 2 \times 9[/tex][tex] = 64912.92 \times 9[/tex][tex] = 584216.28[/tex]therefore, the final answer is 584,216.28

Joni says that a rectangular prism has two bases. How many possible pairs of bases does a rectangular prism really have? Explain

Answers

A rectangular prism actually has three pairs of bases. Each pair of bases is a set of two opposite and parallel faces on the rectangular prism.

The first pair of bases is the two opposite and parallel rectangles on the top and bottom of the prism. The second pair of bases is the two opposite and parallel rectangles on the front and back of the prism. The third pair of bases is the two opposite and parallel rectangles on the left and right sides of the prism.

Each pair of bases is congruent, meaning they have the same shape and size. This is because a rectangular prism is a type of polyhedron with six rectangular faces, and each pair of opposite faces is parallel and congruent to each other.
In conclusion, a rectangular prism has three pairs of bases, each consisting of two opposite and parallel rectangular faces.
I hope this helps! Let me know if you have any further questions.

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What type of triangles has no equal sides and one right angle?
• isosceles triangle
O right scalene triangle
• right isosceles triangle
• right triangle

Answers

Answer:

[tex]\large\boxed{\textsf{Option B. Right Scalene Triangle.}}[/tex]

Step-by-step explanation:

[tex]\textsf{For this problem, we are asked which triangle has no equal sides and a right angle.}[/tex]

[tex]\textsf{Let's review the types of triangles, according to the options.}[/tex]

[tex]\large\underline{\textsf{What is an Isosceles Triangle?}}[/tex]

[tex]\textsf{An Isoceles Triangle is a triangle that has \underline{2 congruent sides}.}[/tex]

[tex]\textsf{Option A is incorrect.}[/tex]

[tex]\large\underline{\textsf{What is a Right Scalene Triangle?}}[/tex]

[tex]\textsf{An Isoceles Triangle is a triangle that has \underline{no congruent sides} and has \underline{1 right angle}.}[/tex]

[tex]\boxed{\textsf{Option B is correct.}}[/tex]

[tex]\large\underline{\textsf{What is a Right Isosceles Triangle?}}[/tex]

[tex]\textsf{A Right Isoceles Triangle is a triangle that has \underline{2 congruent sides}. and 1 right angle}[/tex]

[tex]\textsf{Option C is incorrect.}[/tex]

[tex]\large\underline{\textsf{What is a Right Triangle?}}[/tex]

[tex]\textsf{A Right Triangle is a triangle that has \underline{1 right angle}.}[/tex]

[tex]\textsf{We're not sure how many equal sides this triangle has as it can be none, or 2.}[/tex]

[tex]\textsf{Option D is incorrect.}[/tex]

In the 2020 NFL season, Drew Brees completed 73.5% of his attempted passes, and Patrick Mahomes completed 68.8% of his attempted passes. Based on those statistics, which of the following statements is true?
A. Drew Brees must have attempted more passes
B.Patrick Mahomes must have completed more passes
C.Either quarterback could have completed more passes
D.. Drew Brees must have completed more passes

Answers

Statement C is true: Either quarterback could have completed more passes

What are basic attributes of a good conclusion?

Rephrase the thesis statement first, then explain what you mean and back it with information from the prompt to show what you mean. Describe how the evidence supports your claims in further detail.

We cannot determine which quarterback completed more passes based solely on their completion percentages.

For example, if Drew Brees attempted 100 passes and completed 73.5% of them, he would have completed 73.5 passes. If Patrick Mahomes attempted 200 passes and completed 68.8% of them, he would have completed 137.6 passes, which is more than Drew Brees.

On the other hand, if Drew Brees attempted 200 passes and completed 73.5% of them, he would have completed 147 passes, which is more than Patrick Mahomes' 137.6 completed passes in the above example.

Therefore, statement C is true: either quarterback could have completed more passes, depending on the number of passes attempted.

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Find an equation of the tangent line of y=√3x (square root of
3x) passing through (3,3) using Descartes method of slope.

Answers

The equation of the tangent line of y = sqrt(3x) passing through (3, 3) is y = (1/2)x + 3/2.

To use Descartes' method of slopes, we need to find the derivative of the function first.

Taking the derivative of y = sqrt(3x) gives:

y' = (1/2) * (3x)^(-1/2) * 3 = (3/2√(3x))

Now we can find the slope of the tangent line at (3, 3) by plugging in x = 3 into the derivative:

y' = (3/2√(3*3)) = 3/6 = 1/2

So the slope of the tangent line is 1/2.

Next, we use the point-slope form of a linear equation to find the equation of the tangent line:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the point (3, 3).

Plugging in the values, we get:

y - 3 = (1/2)(x - 3)

Simplifying, we get:

y = (1/2)x + 3/2

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Eight triangles are drawn within a square to create the shaded region in the figure.

Answers

The area of the shaded region is 90 cm².

What is an Area?

The space filled by the surface of an object or any flat shape can be thought of as the area in terms of geometry. The quantity of unit squares that cover an object's surface when it is closed is known as the area of the object. Inches, millimeters, square feet, and other square measurements are used to determine the area.

The area of shaded region = area of given square - area of all given triangles

Now, Area of given square = side × side

                                             = 12 × 12

                                             = 144 cm²

Similarly, Area of all triangles

             = 4 × (area of small triangle) + 4 × (area of big triangle)

             = 4 × ( 1/2 × 3× 3) + 4 × ( 1/2 × 3 × 6)

             = 18 + 36

             = 54 cm²

∴ The area of shaded region = 144 - 54

                                                = 90 cm²

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Consider the equation x^(2)+bx+9=0 where b is a real number. Enter a value for b so that the equation has no real solutions.

Answers

This inequality will be true when b is between -6 and 6. So any value of b in this range will result in no real solutions for the equation. For example, we could choose b=4, and the equation would have no real solutions.

To find a value for b that results in no real solutions for the equation x^(2)+bx+9=0, we need to use the discriminant. The discriminant is the part of the quadratic formula under the square root sign: b^(2)-4ac. If the discriminant is less than 0, the equation will have no real solutions.

In this case, a=1, b=b, and c=9. Plugging these values into the discriminant gives us:

b^(2)-4(1)(9)=b^(2)-36

We want this to be less than 0, so:

b^(2)-36<0

We can solve this inequality by factoring:

(b+6)(b-6)<0

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3. Note this example is using weeks instead of years to calculate the interest. Mr. Lindsey is
going to start a fund for the student who completes the highest amount of classwork
assignments during the rest of the quarter. He puts in $50 at the beginning of week one and
that money will draw interest at a given rate each week for 5 weeks. At the beginning of week 3
his honey business is going so well that he puts another 25 dollars in to draw interest for the
remaining 3 weeks. He puts another 30 at the beginning of week 4.
a) Write an expression to model this situation 50/5)
b) If I paid 4% interest over that period, how much money would the winner get?

Answers

Answer: Your welcome!

Step-by-step explanation:

a) The expression to model this situation is (50/5) + (25/3) + (30/2). This expression represents the amount of money Mr. Lindsey has in the fund at each week, starting at $50 for the first 5 weeks, then adding $25 for the remaining 3 weeks, and then adding $30 for the last 2 weeks.

b) If 4% interest is paid over the period, the winner of the fund will get a total of $70.14. This is calculated by multiplying the expression from part a) by 1.04 (1.04 = 1 + 4%) to get the total amount of money in the fund at the end of the period. In this case, (50/5) + (25/3) + (30/2) * 1.04 = 70.14.

Use the table to complete the statements.
A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 50, 0, negative 6, negative 4, negative 6, 0.

The x-intercepts shown in the table are _____
and ______.

The y-intercept shown in the table is _______.

Answers

Answer:

-2, 2

-4

Step-by-step explanation:

The x-intercept is the point where the graph crosses the x-axis. At that point, the y-coordinate equals zero. At the x-intercept, f(x) = 0.

Look below f(x) and find where f(x) = 0. Which x values correspond to f(x) = 0?

There are two x values: x = -2, and x = 2

The x-intercepts shown in the table are -2 and 2.

The y-intercept is the point where the graph crosses the y-axis. At that point, the x-coordinate equals zero. At the y-intercept, x = 0.

Look below x and find where x = 0. Which f(x) value corresponds to x = 0?

There is one f(x) value: f(x) = -4

The y-intercept shown in the table is -4.

Given f(x)=-x^3+6x^3-9x
a) identify end behavior
b) the degree is?
c)Maximum number of turning points
d) The leading coefficient
e) so the end behavior is:
Given g(x)=x(x+2)(x-2)^2
The same questions

Answers

1) a) X approaches negative infinity, f(x) approaches positive infinity.

b) The degree of f(x) is 3.

c) The maximum number of turning points for f(x) is 2.

d) The leading coefficient of f(x) is -1.

e) The end behavior of f(x) is "as x approaches infinity, f(x) approaches negative infinity; as x approaches negative infinity, f(x) approaches positive infinity.

2) a) a) The end behavior of g(x) is determined by the leading term x⁴. As x approaches infinity, g(x) approaches positive infinity. As x approaches negative infinity, g(x) approaches positive infinity.

b) The degree of g(x) is 4.

c) The maximum number of turning points for g(x) is 3.

d)The leading coefficient of g(x) is 1.

e)The end behavior of g(x) is "as x approaches infinity, g(x) approaches positive infinity; as x approaches negative infinity, g(x) approaches positive infinity.

Given f(x)=-x³ + 6x³ - 9x
a) The end behavior of f(x) is determined by the leading term -x³. As x approaches infinity, f(x) approaches negative infinity. As x approaches negative infinity, f(x) approaches positive infinity.
b) The degree of f(x) is 3, as the highest exponent in the polynomial is 3.
c) The maximum number of turning points for f(x) is 2, as it is one less than the degree of the polynomial.
d) The leading coefficient of f(x) is -1, as it is the coefficient of the leading term -x³.


Given g(x)=x(x+2)(x-2)²
b) The degree of g(x) is 4, as the highest exponent in the polynomial is 4.
c) The maximum number of turning points for g(x) is 3, as it is one less than the degree of the polynomial.
d) The leading coefficient of g(x) is 1, as it is the coefficient of the leading term x⁴.

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