Which statement is NOT true about the dot plot the right?

Answer: Your welcome!

Step-by-step explanation:

5n / (n + 3) = n - 8

5n = n(n + 3) - 8(n + 3)

5n = n^2 + 3n - 8n - 24

n^2 - 5n - 24 = 0

n = 4 or n = -6

The verbal sentence to represent 5n/n+3=n-8 is "When n is 4 or -6, 5n divided by n plus 3 is equal to n minus 8."

[tex]\textit{circumference of a circle}\\\\ C=2\pi r ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=17 \end{cases}\implies C=2\pi (17)\implies C=34\pi[/tex]

Answer:Let's convert hours to minutes:

Now we have:

44 minutes to 300 minutes

We write the ratio as a fraction:

We can reduce both the numerator and denominator by 4, to get:

The correct answer is:

Step-by-step explanation:

The correct statement regarding the histogram is given as follows:

The data is bimodal, with a maximum range of 24. This means that the tide was frequently between 6 to 10 or 16 and 20 feet.

An histogram is a graph that shows the number of times each element of x was observed.

Hence the number of observations of each interval is:

Here are two similarly high bins, hence the distribution can be said to be bimodal, with maximum range given as follows:

25 - 5 = 21 - 1 = 20.

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Answer: its d

Step-by-step explanation:

We can use the future value formula for an annuity to solve this problem:

FV = PMT * ((1 + r)^n - 1) / r

where:

FV is the future value of the annuity

PMT is the regular payment or deposit

r is the annual interest rate

n is the number of periods (in this case, the number of years)

We want to solve for PMT, so we can rearrange the formula to get:

PMT = FV * r / ((1 + r)^n - 1)

Plugging in the given values, we get:

FV = $80,000

r = 6% = 0.06

n = 15 years

So, the annual deposit required is:

PMT = $80,000 * 0.06 / ((1 + 0.06)^15 - 1) ≈ $3,782.58

Therefore, the man would need to deposit approximately $3,782.58 into the account each year in order to have $80,000 saved up for his granddaughter's college education in 15 years, assuming a 6% return.

Some numeric values of the exponential function y = 9(3)^x are given as follows:

To obtain the numeric value of a function or of an expression, we substitute each instance of the variable in the function or in the expression by the value at which we want to find the numeric value.

The function for this problem is given as follows:

y = 9(3)^x.

Hence some numeric values of the function are given as follows:

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Answer:

X+15 is the answer..................

Answer:

Step-by-step explanation:

Kelly bought a total of 1500 pencil boxes.

Answer:

$ 1,937.50.

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 3.875%/100 = 0.03875 per year,

then, solving our equation

I = 10000 × 0.03875 × 5 = 1937.5

I = $ 1,937.50

The simple interest accumulated

on a principal of $ 10,000.00

at a rate of 3.875% per year

for 5 years is $ 1,937.50.

Answer:

This type of study would be a comparative study, as it involves comparing the level of academic motivation between college students and their siblings.

Step-by-step explanation:

Answer: 112 business cards

Step-by-step explanation:

    We will divide the number of business cards by the number of days cards were handed out to see how many cards were handed out per day.

5,376 cards / 48 days = 112 business cards

The service's expected profit is $6,800.

What is the basic arithmetic operations?

The four basic mathematical operations are Addition, subtraction, multiplication, and division.

To find the service's expected profit, we need to calculate the total revenue and the total cost, and then subtract the cost from the revenue.

First, let's calculate the total revenue. The service sells maintenance agreements for $75 a year, so for every 100 customers, the revenue will be:

100 customers x $75/customer = $7,500

Now, let's calculate the total cost. We know that 2 in every 100 people who purchase maintenance agreements have air conditioners that need repair, and the average cost of repairing an air conditioner is $350. So for every 100 customers, the cost of repairs will be:

2 customers x $350/customer = $700

Finally, let's calculate the expected profit:

Expected profit = Total revenue - Total cost

Expected profit = $7,500 - $700

Expected profit = $6,800

Hence, the service's expected profit is $6,800.

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Answer:

Step-by-step explanation:

[tex]\frac{17}{25}[/tex]

Answer: We will start by using the identity cos² A + sin² A = 1 to replace sin² A with cos² A - 1 in the expression 1 - 2sin A sin B sin C:

1 - 2sin A sin B sin C = 1 - 2sin A (cos B cos C - sin B sin C) [Using the product-to-sum formula for sin (B + C)]

= 1 - 2sin A cos B cos C + 2sin A sin B sin C

Now, we will use the identity cos (180° - x) = -cos x to replace cos C with -cos (A + B):

cos² A + cos² B - cos² C = cos² A + cos² B - cos² (A + B)

= cos² A + cos² B - (cos² A cos² B - 2cos A cos B sin A sin B)

= cos² A + cos² B - cos² A cos² B + 2cos A cos B sin A sin B

= (cos² A)(1 - cos² B) + (cos² B)(1 - cos² A) + 2cos A cos B sin A sin B

= cos² A + cos² B - cos² A cos² B + 2cos A cos B sin A sin B

Now, we will use the identity sin (A + B) = sin A cos B + cos A sin B to rewrite the last term:

cos² A + cos² B - cos² A cos² B + 2cos A cos B sin A sin B

= cos² A + cos² B - cos² A cos² B + 2sin A sin B cos A cos B

= (cos² A)(1 - cos² B) + (cos² B)(1 - cos² A) + 2sin A sin B cos A cos B

= (cos² A + cos² B - 1) + (1 - cos² A)(1 - cos² B) + 2sin A sin B cos A cos B

= 2sin² A sin² B + 2sin A sin B cos A cos B

= 2sin A sin B (sin A cos B + cos A sin B)

= 2sin A sin B sin (A + B)

= 2sin A sin B sin (180° - C) [Using A + B + C = 180°]

= -2sin A sin B sin C

Substituting this expression back into the original equation, we get:

cos² A + cos² B - cos² C = 1 - 2sin A sin B sin C

Therefore, the expression is proved.

Step-by-step explanation:

As the temperature of the pan increases, the heat transfer from the butter to the pan increases, causing the butter to melt faster. Ultimately, this heat transfer is necessary for Luke to prepare his food. Without it, the butter would stay solid and would not cook properly.

Heat transfer is the transfer of energy from one place to another due to a difference in temperature. Heat transfer can occur through conduction, convection, and radiation. Heat is always transferred from hotter to colder objects and the rate of transfer depends on the temperature difference between the two and the material it is passing through. Heat transfer is essential in many natural and man-made processes.

The energy is moving in two directions. Cold is moving from the pan and into the butter, while the heat is moving from the butter and into the pan. This is known as a heat transfer. Heat transfers occur when two objects at different temperatures come into contact with each other. In this case, the cold pan is coming into contact with the warm butter, causing the heat to move from the butter and into the pan. This heat transfer causes the butter to melt. As the temperature of the pan increases, the heat transfer from the butter to the pan increases, causing the butter to melt faster. Ultimately, this heat transfer is necessary for Luke to prepare his food. Without it, the butter would stay solid and would not cook properly.

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Answer:

The answer you're looking for is 7000ml

Step-by-step explanation:

Since there are 1000 millimeters inside a liter we can use the equation
x = 7×1000.
We need to first simplify all terms giving us this equation
x = 7000
With that, we are finished and that's how you do this question.

I hope this was helpful!

Answer:ILL GIVE BRAINLIEST!! Pls answer A

Find the mÁB

104°

126°

B

D

Step-by-step explanation:ILL GIVE BRAINLIEST!! Pls answer A

Find the mÁB

104°

126°

B

D

Using the scale factor of 5:2, the volume of the larger cylinder is (C) 70m³.

When a shape is magnified and each side is multiplied by the same number, this is known as a scale factor.

The scaling factor is this figure. Scale factors are used on maps to accurately depict distances between locations.

With a scale factor of 2, the new shape that results from scaling the old shape is twice as large.

So, get the volume of the larger cylinder as follows:

x/5 = 28/2

2x = 28*5

2x = 140

x = 70m³

Therefore, using the scale factor of 5:2, the volume of the larger cylinder is (C) 70m³.

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Complete question:

The scale factor of two similar cylinders is 5:2. The volume of the smaller cylinder is 28 m3. What is the volume of the larger cylinder?

Question 8 options:

A. 700 m3

B. 350 m3

C. 70 m3

D, 437.5 m3

E. 175 m3

The inverse of function is (x + 3)^(1/3) + 2 and the graph is attached below

a) To find the inverse of the function f(x) = (x - 2)^3 - 3, we can follow these steps:

1. Replace f(x) with y: y = (x - 2)^3 - 3

Solve for x in terms of y:

a. Add 3 to both sides: y + 3 = (x - 2)^3

b. Take the cube root of both sides: (y + 3)^(1/3) = x - 2

c. Add 2 to both sides: x = (y + 3)^(1/3) + 2

Replace x with f^-1(x): f^-1(x) = (x + 3)^(1/3) + 2

b) To graph the inverse function f^-1(x), we can use the equation we found in part a) and plot some points:

So we have three points: (0, 3^(1/3) + 2), (1, 2^(1/3) + 2), and (3, 4).

To sketch the graph, we can also note that the function f(x) = (x - 2)^3 - 3 has a vertical asymptote at x = 2 and a local minimum at (2, -3). Therefore, the inverse function f^-1(x) will have a horizontal asymptote at y = 2 and a local maximum at (4, 2).

Combining all of this information, we can sketch the graph of f^-1(x) as shown below:

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The perimeter of triangle QST is 32.

option D.

The perimeter of triangle QST is calculated by determining the value of x as shown below.

If length SQ = length ST, then angle STQ must be equal to angle SQT,  so we will have the following equation.

Cos T = ( 3x - 1 ) / ( 5x + 1 )

Cos Q = ( 2x + 1 ) / (5x + 1 )

Cost T = Cos Q

( 3x - 1 ) / ( 5x + 1 ) = ( 2x +1 ) / ( 5x + 1 )

3x - 1 = 2x + 1

x = 2

The perimeter of triangle QST is calculated as;

= 5x + 1  + (3x -1  + 2x + 1 ) + 5x + 1

= 15x + 2

= 15 (2)  + 2

= 32

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The value of the functions are,

⇒ f (- 10) = 20201

⇒ f (2) = 17

⇒ f (3) = 143

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The value of function is,

⇒ f (x) = 2x⁴ + x² - 10x + 1

Now, We can find all the values as;

At x = - 10;

⇒ f (x) = 2x⁴ + x² - 10x + 1

⇒ f (- 10) = 2 (- 10)⁴ + (- 10)² - 10 (- 10) + 1

⇒ f (- 10) = 20000 + 100 + 100 + 1

⇒ f (- 10) = 20201

At x = 2;

⇒ f (x) = 2x⁴ + x² - 10x + 1

⇒ f (2) = 2 (2)⁴ + (2)² - 10 (2) + 1

⇒ f (2) = 32 + 4 - 20 + 1

⇒ f (2) = 17

At x = 3;

⇒ f (x) = 2x⁴ + x² - 10x + 1

⇒ f (3) = 2 (3)⁴ + (3)² - 10 (3) + 1

⇒ f (3) = 162 + 9 - 30 + 1

⇒ f (3) = 143

Thus, The value of the functions are,

⇒ f (- 10) = 20201

⇒ f (2) = 17

⇒ f (3) = 143

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Answer:

x ≤ 6.8

Step-by-step explanation:

1.25x + 6.50 ≤ 15

1.25x ≤ 8.5

x ≤ 6.8

So, the answer is x ≤ 6.8

Answer:

Below

Step-by-step explanation:

1.25x + 6.50 <= 15     SUBTRACT 6.50 from both sides of the equation

  1.25x ≤ 8.50            DIVIDE both sides by 1.25

         x ≤ 6.8

Answer:

A

Step-by-step explanation:

step by step you will learn

a. Journal entries for the issue of debentures:

Issues 4000, 12% debentures of Rs. 100 each at Rs 100 and redeemable at Rs 100.

Debit: Cash/Bank Account (4000 x 100) = 400,000

Credit: Debentures Account (4000 x 100) = 400,000

Issued 4000, 12% debentures of Rs. 100 each at Rs 100 and redeemable at Rs 90.

Debit: Cash/Bank Account (4000 x 100) = 400,000

Credit: Debentures Account (4000 x 90) = 360,000

Credit: Discount on Issue of Debentures Account (4000 x 10) = 40,000

Issued 4000, 12% debentures of Rs. 100 each at Rs 100 and redeemable at Rs 110.

Debit: Cash/Bank Account (4000 x 100) = 400,000

Credit: Debentures Account (4000 x 110) = 440,000

Credit: Premium on Issue of Debentures Account (4000 x 10) = 40,000

Issued 4000, 12% debentures of 100 each at Rs 110 and redeemable at Rs 100.

Debit: Cash/Bank Account (4000 x 110) = 440,000

Credit: Debentures Account (4000 x 100) = 400,000

Credit: Loss on Issue of Debentures Account (4000 x 10) = 40,000

Issued 4000, 12% debentures of 100 each at Rs 110 and redeemable at Rs 90.

Debit: Cash/Bank Account (4000 x 110) = 440,000

Credit: Debentures Account (4000 x 90) = 360,000

Credit: Discount on Issue of Debentures Account (4000 x 20) = 80,000

Issued 4000, 12% debentures of 100 each at Rs 110 and redeemable at Rs 110.

Debit: Cash/Bank Account (4000 x 110) = 440,000

Credit: Debentures Account (4000 x 110) = 440,000

Issued 4000, 12% debentures of Rs.100 each at Rs 90 and redeemable at Rs 100.

Debit: Cash/Bank Account (4000 x 90) = 360,000

Credit: Debentures Account (4000 x 100) = 400,000

Credit: Discount on Issue of Debentures Account (4000 x 10) = 40,000

Issued 4000, 12% debentures of Rs.100 each at Rs 90 redeemable at Rs 105.

Debit: Cash/Bank Account (4000 x 90) = 360,000

Credit: Debentures Account (4000 x 105) = 420,000

Credit: Premium on Issue of Debentures Account (4000 x 15) = 60,000

b. for the redemption of debentures:

Redemption of debentures issued at Rs. 100 and redeemable at Rs. 100:

Debenture Redemption A/C Dr. 400,000

To Debentureholders A/C 400,000

(Being the debentures of Rs. 100 each redeemed at par)

Redemption of debentures issued at Rs. 100 and redeemable at Rs. 90:

Debenture Redemption A/C Dr. 360,000

Loss on Redemption A/C Dr. 40,000

To Debentureholders A/C 400,000

(Being the debentures of Rs. 100 each redeemed at a discount of Rs. 10)

Redemption of debentures issued at Rs. 100 and redeemable at Rs. 110:

Debenture Redemption A/C Dr. 440,000

Gain on Redemption A/C Dr. 40,000

To Debentureholders A/C 400,000

(Being the debentures of Rs. 100 each redeemed at a premium of Rs. 10)

Redemption of debentures issued at Rs. 110 and redeemable at Rs. 100:

Debenture Redemption A/C Dr. 400,000

To Debentureholders A/C 400,000

(Being the debentures of Rs. 110 each redeemed at par)

Redemption of debentures issued at Rs. 110 and redeemable at Rs. 90:

Debenture Redemption A/C Dr. 360,000

Loss on Redemption A/C Dr. 40,000

To Debentureholders A/C 400,000

(Being the debentures of Rs. 110 each redeemed at a discount of Rs. 20)

Redemption of debentures issued at Rs. 110 and redeemable at Rs. 110:

Debenture Redemption A/C Dr. 440,000

To Debentureholders A/C 400,000

Gain on Redemption A/C Cr. 40,000

(Being the debentures of Rs. 110 each redeemed at par with a premium of Rs. 10)

Redemption of debentures issued at Rs. 90 and redeemable at Rs. 100:

Debenture Redemption A/C Dr. 400,000

Loss on Redemption A/C Dr. 10,000

To Debentureholders A/C 390,000

To Securities Premium Reserve A/C 20,000

(Being the debentures of Rs. 90 each redeemed at a discount of Rs. 10 and Securities Premium Reserve credited with Rs. 2.50 per debenture redeemed)

Redemption of debentures issued at Rs. 90 and redeemable at Rs. 105:

Debenture Redemption A/C Dr. 420,000

Loss on Redemption A/C Dr. 30,000

To Debentureholders A/C 390,000

To Securities Premium Reserve A/C 30,000

(Being the debentures of Rs. 90 each redeemed at a discount of Rs. 15 and Securities Premium Reserve credited with Rs. 7.50 per debent

Using  Remainder Theorem and synthetic division, f(-10) = 191, f(2) = 1, f(3) = 34

What is synthetic division?

A polynomial's coefficients are split one by one in synthetic division.

The split polynomial's zero, which belongs in the box on the far left, has this value.

To use the Remainder Theorem and synthetic division to evaluate f(-10), f(2), and f(3) for the function[tex]f(x)=2x^2+x^2-10x+1[/tex], we can proceed as follows:

First, we need to perform synthetic division using -10, 2, and 3 as the divisors.

1) For f(-10):

The result of the division is 191, so f(-10) = 191.

2) For f(2):

The result of the division is 1, so f(2) = 1.

3) For f(3):

The result of the division is 34, so f(3) = 34.

Therefore, we have:

f(-10) = 191

f(2) = 1

f(3) = 34

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Making linear equations for given scores, Grace scored 51 marks, John scored 47 marks, and Julius scored 52 marks in the examination.

What is a linear equation, exactly?

A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a variable, with the degree of each variable being 1. In other words, a linear equation is an equation of a straight line, which can be expressed in the form of y = mx + b, where y is the dependent variable, x is the independent variable, m is the slope of the line, and b is the y-intercept of the line. Linear equations are used to model relationships between variables that have a constant rate of change, such as distance traveled over time or cost per item.

Now,

Let's assume that Grace's score is x.

Then, John's score will be x-4.

And, Julius's score will be x-4+5 = x+1.

The sum of their scores is given as 150. So, we can write an equation as:

x + (x-4) + (x+1) = 150

Simplifying the equation, we get:

3x - 3 = 150

Adding 3 to both sides, we get:

3x = 153

Dividing by 3 on both sides, we get:

x = 51

So, Grace's score is x = 51.

John's score is x-4 = 47.

And, Julius's score is x+1 = 52.

Therefore,

                      Grace scored 51 marks, John scored 47 marks, and Julius scored 52 marks in the examination.

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