Which situation can be represented by −10? A. a debt of $10 B. a temperature of 10°F C. a score of 10 in a soccer game D. an elevator that is on the 10th floor

The value of the expression 29.2 + 4.81/√97.2​ when each value is estimated to 1 significant figure is 30.5

Given that we have the following expression

29.2 + 4.81/√97.2​

Using the order of operations, we need to first take the square root of 97.2, and then divide 4.81 by the result, before finally adding 29.2 (all estimated)

To 1 significant figure, the square root of 97.2 is 10,

Mathematically, we have

29.2 + 4.81/√97.2 ≈ 29.2 + 4.81/10

Next, we estimate others

So, we have

29.2 + 4.81/√97.2 ≈ 30 +  5/10

Divide

29.2 + 4.81/√97.2 ≈ 30 +  0.5

Evaluate the sum

29.2 + 4.81/√97.2 ≈ 30.5

Hence, the estimate is 30.5

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The sweets Candy Bars 1 through 3 and Each individual will get a one - third of a candy bar as  each candy bar is cut into three equal pieces .

A fraction is a percentage or ratio between two numbers that is expressed numerically. Typically, it is expressed as a/b, where a stands for the numerator and b for the denominator. The denominator is the total number of equal parts that make up the whole, while the numerator is the number of equal parts that are being taken into account. Three out of four equal portions, or three-fourths of the entire, are represented by the fraction 3/4, for instance. Mathematicians frequently use fractions, particularly in the areas of algebra, geometry, and arithmetic.

given

Each individual will get a one - third of a candy bar.

A visual representation of this might be the following, where each candy bar is cut into three equal pieces and presented to a different friend:

[tex]| 1/3 | | 1/3 | | 1/3 |[/tex]

The sweets Candy Bars 1 through 3 and Each individual will get a one - third of a candy bar as  each candy bar is cut into three equal pieces .

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The required probability of getting a grid that does not have a red square is [tex](\frac{1}{2}) ^n[/tex].

We have to color the unit square of a grid of unit squares either blue or red.

For each square, either color is equally likely to be used.

We need to find the probability of getting a grid that does not have a red square.

Let us consider the following diagram of the grid of unit squares.

Here, we have to color the unit square either blue or red.

There are n unit squares in the grid.

The probability of getting a blue square in any one of the n unit squares is equal to 1/2.

Similarly, the probability of getting a red square in any one of the n unit squares is equal to 1/2.

The probability of obtaining a grid that does not have a red square = the probability of getting a blue square in each of the n unit squares= (1/2) x (1/2) x  ... n times=  [tex](\frac{1}{2}) ^n[/tex]

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Answer:

3a + 2b

Step-by-step explanation:

Let the unknown side have length X.

X + X + 5a - b + 5a - b = 16a + 2b

2X + 10a - 2b = 16a + 2b

2X = 6a + 4b

X = 3a + 2b

Answer: 3a + 2b

The largest area you can enclose with 20 meters of fencing against a long, straight wall is 50 square meters. Itcan be found using optimization methods.

Step 1: Define the variables
Let x be the length of the fencing parallel to the wall and y be the length of the fencing perpendicular to the wall.
Step 2: Set up the constraint equation
Since you have 20 meters of fencing, the sum of x and 2y (both sides perpendicular to the wall) should equal 20. The constraint equation is:x + 2y = 20
Step 3: Express one variable in terms of the other
Solve the constraint equation for one variable. In this case, solve for x: x = 20 - 2y

Step 4: Write the area function
The area of the rectangle can be expressed as A = xy. Substitute x from the previous step into this equation: A(y) = (20 - 2y)y.

Step 5: Find the critical points
Differentiate the area function with respect to y and set it to zero to find the critical points: dA/dy = 20 - 4y = 0, Solve for y:4y = 20, y = 5
Step 6: Find the corresponding value for x
Plug the value of y back into the equation for x: x = 20 - 2(5), x = 10

Step 7: Check for maximum area
The critical point we found (x=10, y=5) is indeed a maximum since the second derivative of the area function is negative.Step 8: State the largest area
The largest area you can enclose with 20 meters of fencing against a long, straight wall is A = xy = 10 * 5 = 50 square meters.

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Part A: The system of equations are:

j + g = 23

j = 2g + (- 4)

PART B: The solution of the system is:

Jodi:  14 games

Gerry: 9 games

Part A:

The first equation comes from the fact that they bought a total of 23 games:

j + g = 23 ----- (1)

The second equation comes from the fact that "Jodi buys 4 less than twice the number of games Gerry buys":

j = 2g + (- 4)

j = 2g - 4  ----- (2)

Part B:

We can solve this system of equations by substitution. We can solve the second equation for j, and then substitute that expression for j in the first equation. That is:

j + g = 23

2g-4 + g = 23

3g - 4 = 23

3g = 23 + 4

3g = 27

g = 27/3

g = 9

Put g = 9 in (1):

j + g = 23

j + 9 = 23

j = 23 - 9

j = 14

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To find the fraction of the square quilt block that is shaded, we need to count the number of shaded unit squares and divide it by the total number of unit squares in the quilt block. Let us begin by counting the number of shaded unit squares.

We notice that there are a total of 6 unit squares that are shaded. The unit squares that are shaded are the 2 squares that are completely shaded and the 4 squares that are half shaded due to the presence of triangles.

Next, we need to count the total number of unit squares in the quilt block. We notice that the quilt block is made up of 9 unit squares, each of which can be divided into 4 smaller unit squares. Thus, the total number of unit squares in the quilt block is 9 x 4 = 36.

Therefore, the fraction of the square quilt block that is shaded is 6/36 or 1/6.

To summarize, the shaded portion of the quilt block consists of 6 unit squares out of a total of 36 unit squares. Thus, the fraction of the square quilt block that is shaded is 1/6.

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Answer:

Step-by-step explanation:

c

The closest option, 24 cm, is the length of the mode, or the length that appears the most frequently in the data set, but none of the other possibilities fit this value's exact range.

The mean, which is used to indicate the average value of a group of values in statistics, is a measure of central tendency. It is determined by adding up all of the data set's values and dividing the result by the number of values. The mean is frequently chosen as a data set's representative value because it can provide light on the typical value or average performance of a population or sample.

given

The following formula can be used to determine the total number of roses multiplied by each length of roses using the information in the table:

(2 * 22) + (4 * 23) + (5 * 24) + (3 * 25) + (1 * 26) = 222

There are: roses in all.

2 + 4 + 5 + 3 + 1 = 15

As a result, the data set's mean is:

222 / 15 = 14.8

Thus, the data set's roses' average length is 14.8 centimetres.

The closest option, 24 cm, is the length of the mode, or the length that appears the most frequently in the data set, but none of the other possibilities fit this value's exact range.

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Answer:

The circumference of a circle with radius 2.8 is 17.59(*)

Step-by-step explanation:

Circumference of a cicle in terms of radius:Circumference = 2·π·r = 2·3.14·2.8 = 17.59(*)In terms of diameter:Circumference = π·d = 3.14·5.6 = 17.58(*)In terms of area:Circumference C = √4·π·A = √4·π·24.63 = 17.59(*)(*) 17.59 inches exactly or limited to de precision of this calculator (13 decimal places).Note: for simplicity, the operations above were rounded to 2 decimal places and π was rounded to 3.14.

Therefore, the formula for T1 is T1(x1,x2) =[tex](24x1/5 - 18x2/5, -36x1/5 + 6x2/5).[/tex]

Given T is a linear transformation from R2 into R2, we need to show that T is invertible and find a formula for T1.T(x1,x2) = (3x1-9x2, -3x1+5x2)Let A be the standard matrix for T, then we have to find the determinant of A as it will help us determine whether T is invertible or not.The standard matrix for T is given as :A = [3 -9-3 5]Now, to calculate the determinant of A, we have to use the formula as:det(A) = ad - bcwhere a = 3, b = -9, c = -3, d = 5Now, substituting the values of a, b, c, d, we get,det(A) = (3 × 5) - (-9 × -3) = 15 - 27= -12Since the determinant of A is not equal to zero, therefore, T is invertible.

For finding the formula for T1, we need to calculate the inverse of T. We can find the inverse of T as:[tex][A|I] → [I|A-1][/tex]Now, appending the identity matrix to A, we get the following matrix.[A|I] = [tex][3 -9|1 0-3 5|0 1]→ [I|A-1] = [1 3/5|-9/5-3/5][/tex]

Therefore, the inverse of T is T-1(x1,x2) = (3x1/5 + 9x2/5, -9x1/5 - 3x2/5)Now, we can find T1 by substituting T-1 in T, we get,T1(x1,x2) = T(T-1(x1,x2)) =[tex]T(3x1/5 + 9x2/5, -9x1/5 - 3x2/5) = (3((3x1/5 + 9x2/5)) - 9(-9x1/5 - 3x2/5), -3((3x1/5 + 9x2/5)) + 5(-9x1/5 - 3x2/5)) = (24x1/5 - 18x2/5, -36x1/5 + 6x2/5)[/tex]

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Probability of drawing a red or white ball.

One ball is drawn at random from a box containing 4 red balls, 7 white balls, and 5 blue balls.

Determine the probability that the ball drawn is red or white.

The total number of balls in the box is 4+7+5=16 balls. The probability of drawing a red ball is 4/16. The probability of drawing a white ball is 7/16.The probability of drawing either a red or white ball is given by the sum of the individual probabilities. Hence, the probability of drawing a red or white ball is:(4/16) + (7/16) = (11/16)

Therefore, the probability that the ball drawn is red or white is 11/16.

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Answer:

x=5

Step-by-step explanation:

[tex] log_{2x - 7}(81) = 4[/tex]

Raise both sides with a base of 2x-7

[tex]81 = (2x - 7) {}^{4} [/tex]

We get two solutions

[tex]3 = (2x - 7)[/tex]

[tex]10 = 2x[/tex]

[tex]x = 5[/tex]

The other solutions is

[tex] - 3 = 2x - 7[/tex]

[tex]4 = 2x[/tex]

[tex]x = 2[/tex]

The solution x=2 wont work since it will make our base negative.

So the answer is 5

Answer:

(3x-4)(x+1)

Step-by-step explanation:

Workout is provided in the attachment.

An expression for the number of amoebas after 24 hours is 1 × 2²⁴ = 16,777,216

Single-celled creatures knοwn as amοebas reprοduce asexually. An amοeba begins tο reprοduce when its genetic material dοubles, twο nuclei are fοrmed, and it begins tο alter shape by develοping a thin "waist" in the centre. Typically, this prοcedure gοes οn until the cells are finally divided intο twο.

Amοeba reprοduce typically asexually thrοugh a prοcess called binary fissiοn. The cell splits intο twο daughter cells οf equal size fοllοwing the replicatiοn οf its genetic material by mitοtic divisiοn.

a. It is given that an amοeba divides tο fοrm twο amοebas after οne hοur sο there are 2 amοebas after 1 hοur.

b. It is given that οne hοur later, each οf the twο amοebas divides tο fοrm twο mοre amοebas sο there are 2×2=4 amοebas after 2 hοurs.

c. The number οf amοebas is dοubling after each hοur since each amοeba divides intο twο amοebas every hοur. This means that the number οf amοebas after 6 hοurs can be fοund by multiplying the οriginal number οf amοebas, which was 1, by 2 six times. The number οf amοebas after 6 hοurs is then 1 × 2⁶ = 2⁶= 64 amοebas.

d. Using the same pattern frοm part (c), the number οf amοebas after 24 hοurs is 1 × 2²⁴ = 2²⁴ = 16,777,216 amοebas.

Expression = 1 × 2²⁴ = 16,777,216

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The required length of YZ is [tex]\frac{145}{16}$[/tex]  units.

To find the length of YZ, we can use the fact that the length of XZ is the sum of the lengths of XY and YZ. We are given that XZ is [tex]12 \frac{11}{16}$[/tex]units and XY is [tex]3 \frac{5}{8}$[/tex] units. Let's convert these mixed numbers to improper fractions so that we can add them:

[tex]$XZ = 12 \frac{11}{16} = \frac{12 \times 16 + 11}{16} = \frac{203}{16}$[/tex]

[tex]$XY = 3 \frac{5}{8} = \frac{3 \times 8 + 5}{8} = \frac{29}{8}$[/tex]

Now we can use the formula:

XZ = XY + YZ

to solve for YZ. Rearranging the equation, we get:

YZ = XZ - XY

Plugging in the values we calculated, we get:

[tex]$YZ = \frac{203}{16} - \frac{29}{8}$[/tex]

To subtract these fractions, we need to find a common denominator. The smallest number that both 16 and 8 divide into evenly is [tex]16 \times 2 = 32$[/tex], so we can rewrite the fractions with a denominator of 32:

[tex]$YZ = \frac{203}{16} \times \frac{2}{2} - \frac{29}{8} \times \frac{4}{4} = \frac{406}{32} - \frac{116}{32}$[/tex]

Now we can subtract:

[tex]$YZ = \frac{406 - 116}{32} = \frac{290}{32}$[/tex]

We can simplify this fraction by dividing both the numerator and denominator by the greatest common factor, which is 2:

[tex]$YZ = \frac{145}{16}$[/tex]

Therefore, the length of YZ is [tex]\frac{145}{16}$[/tex]  units.

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Complete question:

XY is a line, Z is a point on this line such that  XZ is 12 11/16 units XY is 3 5/8 units find YZ​.

Answer: Assuming the student walks along a rectangular grid and not diagonally, the possible locations the student could end up after walking 4 miles in any direction would be the points that are 4 units away from the starting point in a north, south, east, or west direction.

Using this information, we can determine that the possible locations the student could end up at are:

(-2, 10)

(-6, 14)

(-10, 10)

(-6, 6)

Therefore, the answer is:

All of the above locations are possible endpoints.

Step-by-step explanation:

If the student walks 4 miles north, south, east, or west,  the location at the end of the walk are respectively, (-6, 14). (-6, 6), (-2,10). (-10, 10).

The Cartesian plane, named after the mathematician René Descartes (1596 - 1650), is a plane with a rectangular coordinate system that associates each point in the plane with a pair of numbers.

Given that,

A student starts a walk at (-6, 10)

If the student walks 4 miles north, south, east, or west,

The location at the end of the walk =

Plotting dotted diagram,

                  East

                     |

North --------- |-------------- South

                     |

                  West

Suppose, he goes to north  direction

Then, 4 will be added to y coordinate,

It can be written as,

(-6, 14)

Similarly, for South, (-6, 6),  

East, (-2,10).

West, (-10, -10)

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The theoretical probability of not drawing an "o" is 3/4.

We have,

Each of the letters of the word Colorado are written on a piece of paper and then put into a bag.

Here, The word "Colorado" has 8 letters, including 2 "o"s.

Therefore, the probability of drawing an "o" is,

P = 2/8

P = 1/4

Hence, The probability of not drawing an "o" is the complement of this probability is,

1 - 1/4 = 3/4.

Therefore, the theoretical probability of not drawing an "o" is 3/4.

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the formula for y in terms of x is y = 12/x²3/4).

Why it is?

We have two statements about the relationship between the variables y, t, and x:

"y is directly proportional to the √ of t" means that y = k√t for some constant of proportionality k.

"T is inversely proportional to the cube of x" means that T = k'/x²3 for some constant of proportionality k'.

We are given that y = 12 when t = 16 and x = 2. Using these values, we can solve for the constants k and k':

y = k√t

12 = k√16

12 = 4k

k = 3

T = k'/x²3

16 = k'/2²3

k' = 128

Now we can substitute these values for k and k' into the expression for y in terms of t and simplify:

y = k√t

y = 3√t

We can also substitute the expression for t in terms of x:

T = k'/x²3

T = 128/x²3

And substitute the value of T when x = 2:

T = 128/2²3

T = 16

Now we can substitute this value for t in the expression for y:

y = 3√t

y = 3√16/x²(3/2)

Simplifying the radical and exponents, we get:

y = 12/x²(3/4)

Therefore, the formula for y in terms of x is y = 12/x²(3/4).

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The simple random sample of size 2 that will be selected is {b, c}.

To create a simple random sample of size 2 using the random digits 9, 0, 3, 7, 3, 2, 4, follow these steps:
1. Assign each letter a random number: 1 corresponds to a, 2 corresponds to b, and so on.
2. Go through the given random digits and find the first two that correspond to a valid letter.

The random digits are 9, 0, 3, 7, 3, 2, 4.
9 and 0 do not correspond to any letters (since we only have numbers 1, 2, 3, and so on). The next digit is 3, which corresponds to the letter c. The following digit, 7, does not correspond to a letter, so we move on to the next digit. The next digit is 3 again, which we have already selected. The next valid digit is 2, which corresponds to the letter b.
Thus, the simple random sample of size 2 that will be selected using these random digits is the set {b, c}.

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If john paul is 6 years older than Angelina and in 9 years the sum of their ages will be 86, then John Paul is 35 years old now.

Let's assume Angelina's current age to be x years old. Then, according to the given information, John Paul's current age would be (x + 6) years old.

In 9 years, the sum of their ages will be 86, which means that (x + 9) + (x + 6 + 9) = 86.

Simplifying the equation, we get 2x + 24 = 86.

Solving for x, we get x = 31.

Therefore, John Paul's current age would be x + 6 = 31 + 6 = 35 years old.

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Answer:

To calculate the time it will take Tom to complete the 1-mile kayak trip, we need to take into account the speed of the current and the speed at which Tom can paddle relative to the current.

Let's first consider the time it would take for Tom to go upstream against the current. In this case, the speed of the current is subtracted from Tom's paddling speed, so his effective speed is:

Effective speed upstream = 4 miles per hour - 3 miles per hour = 1 mile per hour

To travel 1 mile at 1 mile per hour, Tom would take:

Time upstream = Distance / Effective speed upstream = 1 mile / 1 mile per hour = 1 hour

Now let's consider the time it would take for Tom to go downstream with the current. In this case, the speed of the current is added to Tom's paddling speed, so his effective speed is:

Effective speed downstream = 4 miles per hour + 3 miles per hour = 7 miles per hour

To travel 1 mile at 7 miles per hour, Tom would take:

Time downstream = Distance / Effective speed downstream = 1 mile / 7 miles per hour ≈ 0.14 hours or about 8 minutes

Therefore, the total time it would take Tom to complete the 1-mile kayak trip, including going upstream and downstream, would be:

Total time = Time upstream + Time downstream = 1 hour + 0.14 hours ≈ 1.14 hours or about 68 minutes.

Step-by-step explanation:

One-hundred-two-and-eighty-one-hundredths can be written as 102.81 in standard form.

To dilate a point S by a scale factor of 1/2, we need to multiply the coordinates of the point by the scale factor.So the dilated point S' will have coordinates (2, 3).

A scale factor is a number that scales or multiplies another quantity by a certain amount, either making it larger or smaller. In geometry, scale factor is used to describe the ratio of the corresponding side lengths of two similar figures.

If the coordinates of point S are (x,y), then the coordinates of the dilated point S' will be:

(x', y') = (1/2 * x, 1/2 * y)

In other words, the x-coordinate of the dilated point is half of the x-coordinate of the original point, and the y-coordinate of the dilated point is half of the y-coordinate of the original point.

For example, if point S has coordinates (4, 6), then the coordinates of the dilated point S' will be:

(x', y') = (1/2 * 4, 1/2 * 6) = (2, 3)

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Answer:

48 square centimeters

Step-by-step explanation:

[tex] \frac{1}{2} (4)(8)(3) = 48[/tex]

To find the probability of rolling six standard, six-sided dice and getting six distinct numbers, we need to calculate the total number of possible outcomes and the number of outcomes that satisfy the given condition.

Total Number of Outcomes:

The total number of possible outcomes when rolling six dice is 6^6, which is 46,656. Each die has six possible outcomes (1, 2, 3, 4, 5, or 6), and there are six dice being rolled.

Number of Outcomes with Six Distinct Numbers:

To get six distinct numbers when rolling six dice, each number must be different from the others. We can choose any six numbers from 1 to 6, and there are 6! (6 factorial) ways to arrange them on the six dice.

6! = 6 x 5 x 4 x 3 x 2 x 1 = 720

Probability of Getting Six Distinct Numbers:

To find the probability of rolling six standard, six-sided dice and getting six distinct numbers, we divide the number of outcomes with six distinct numbers by the total number of possible outcomes:

P(six distinct numbers) = number of outcomes with six distinct numbers / total number of outcomes

P(six distinct numbers) = 720 / 46,656

P(six distinct numbers) = 5 / 324

Therefore, the value of the probability is 5/324 or approximately 0.0154.

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Conclusion
Therefore, for some natural number N, n ≥ N and n ∈ N implies |(p - q)/n| < ε.

To show that for some natural number N, n ≥ N and n ∈ N implies |p/n - q/n| < ε, we'll use the Archimedean property of real numbers. The Archimedean property states that for any positive real numbers a and b, there exists a natural number n such that n*a > b.

Let's consider the inequality we want to prove: [tex]|p/n - q/n| < ε.[/tex]

Step 1: Rewrite the inequality
First, we can rewrite the inequality as |(p - q)/n| < ε, since we are allowed to combine the fractions.

Step 2: Apply the Archimedean property
By the Archimedean property, we know that for any ε > 0, there exists a natural number N such that N > (p - q)/ε.

Step 3: Rearrange the inequality
We can rearrange the inequality from step 2 to get[tex] N*ε > p - q. [/tex]

Step 4: Divide by N
Now, divide both sides of the inequality by N to get [tex]ε > (p - q)/N.[/tex]

Step 5: Relate this to our original inequality
We want to show that |(p - q)/n| < ε for some n ∈ N, where n ≥ N. Since n ≥ N, and ε > (p - q)/N, we have ε > (p - q)/n for n ∈ N and n ≥ N

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If the area is 384 square feet, then the length of the altitude is 36 feet, and the length of the base is 44 feet.

Let's start by using the formula for the area of a triangle in terms of its base and altitude:

[tex]Area = (1/2) * base * altitude[/tex]

We know that the area of the triangle is 384 square feet:

[tex]384 = (1/2) * base * altitude[/tex]

Next, we're given that the base is 8 feet longer than the altitude:

[tex]base = altitude + 8[/tex]

We can substitute this expression for the base into the area formula:

[tex]384 = (1/2) * (altitude + 8) * altitude[/tex]

Simplifying and multiplying out the right-hand side:

[tex]384 = (1/2) * (altitude^2 + 8altitude)\\768 = altitude^2 + 8altitude[/tex]

Now we have a quadratic equation in terms of the altitude. We can solve for the altitude by first rearranging the equation:

[tex]altitude^2 + 8altitude - 768 = 0[/tex]

Then, we can solve for the altitude using the quadratic formula:

[tex]altitude = (-8 ± sqrt(8^2 - 4(1)(-768))) / (2(1))\\altitude = (-8 ± sqrt(6400)) / 2\\altitude = (-8 ± 80) / 2[/tex]

We get two possible values for the altitude:

altitude = -44 or altitude = 36

Since the altitude of a triangle must be positive, we discard the negative solution and choose altitude = 36 feet.

We can then use the expression for the base in terms of the altitude to find the length of the base:

[tex]base = altitude + 8 = 36 + 8 = 44 feet[/tex]

Therefore, the length of the altitude is 36 feet and the length of the base is 44 feet.

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Correct question:

Find the lengths of the triangles altitude and base if its area is 384 squared feet. If its base is 8 feet longer than its altitude, find the length of the base and the altitude.

We have so established that m and m are equal as As congruent angles also referred to as vertical angles are formed when two lines connect.

The degree of rotation between two lines, rays, or segments that have a common endpoint is measured in mathematics as an angle. Angles are categorised in geometry according on how much they are rotated. Angles that are less than 90 degrees are referred to as acute angles, those that are precisely 90 degrees are referred to as right angles, those that are between 90 and 180 degrees are referred to as obtuse angles, and those that are exactly 180 degrees are referred to as straight angles.

given

We can write: since mXOY = mWOV.

mWOV - m = mXOY - m

This can be stated simply as:

OXY = OWV

As congruent angles—also referred to as vertical angles—are formed when two lines connect, we can state:

OXY = MOVY.

Therefore:

mOVW mOVY

And:

mOYX = mOXY

Therefore:

mOYX = mOVY

Finally:

OYX = OWV

We thus have:

m = m

We have so established that m and m are equal as As congruent angles also referred to as vertical angles are formed when two lines connect.

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The light bulb should be placed 1 inch from the vertex so that the rays will be reflected parallel to the axis.

The reflector of a flashlight is in the shape of a paraboloid of revolution.

Its diameter is 4 inches and its depth is 1 inch.

To find the distance from the vertex to the light bulb, so that the rays will be reflected parallel to the axis, we will use the following steps:

Step 1: Write the equation of the paraboloid.

For the given paraboloid, the vertex is at the origin (0,0,0) and the axis of symmetry is the z-axis.

Since the paraboloid is symmetric with respect to the z-axis, the equation of the paraboloid can be written as:

[tex]$$z=\frac {x^2+y^2}{4p}$$[/tex]

where p is the distance from the vertex to the focus.

Here, we have to find p.

Step 2: Find the value of p.

We know that the diameter of the reflector is 4 inches.

Since the paraboloid is symmetric with respect to the z-axis, the diameter of the paraboloid is also 4 inches.

Therefore, the radius of the base of the paraboloid is 2 inches.

Since the depth of the paraboloid is 1 inch, the vertex is 1 inch away from the base of the paraboloid.

Hence, the value of p can be found as follows: p = distance from vertex to focus

= [tex]$\frac{1}{4}$[/tex]

distance from vertex to the base

[tex]= $\frac {1}{4}$ (2)[/tex]

[tex]= $\frac{1}{2}$[/tex] inches

Step 3: Find the distance from the vertex to the light bulb.

Since the rays should be reflected parallel to the axis, the light bulb should be placed at a distance of

[tex]2p = 2 $\times$ $\frac{1}{2}$ = 1 inch[/tex] from the vertex.

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About 68% percent of light bulbs can last within one standard deviation of the mean, between 57.6 hours and 66.4 hours.

To determine the percentage of light bulbs that can last within one standard deviation of the mean, between 57.6 hours and 66.4 hours, you can follow these steps:

1. Identify the range of values:

In this case, the range is between 57.6 hours and 66.4 hours.

2. Recognize that this range represents one standard deviation from the mean.

In a normal distribution, approximately 68% of values fall within one standard deviation of the mean.

So, about 68% of light bulbs can last within one standard deviation of the mean, between 57.6 hours and 66.4 hours.

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