Which sequence of transformations on preimage Triangle ABC will NOT produce the image A’B’C’

here is the data set for the complete question

x: 18 21 19 21 20 21

y; 2 14 5 6 18 18

Answer:

B. 0.652

Step-by-step explanation:

x   y   rank of x     rank of y   d         d²

18   2     1                1               0          0

21   14    4                4             0          0

19    5     2               2             0          0

21    6     4               3            1            1

20    18    3             5.5         -2.5      6.25

21     18    4             5.5          -1.5       2.25

∑d² = 8.5

rs = 1 - 6[∑di² + ∑m(m²-1)]/n(n²-1)

= 1 - 6[8.5 +{3(3²-10/12 + 2(2² - 1)/12}]/6(6²-1)

= 1 - 0.348

= 0.652

therefore option b is the right answer.

Answer:

∛-2

Step-by-step explanation:

The aritmetic expressión is:

∛-2

Answer:

18167474898

Step-by-step explanation:

I used a calculator.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

Answer:

The value of e is approximately 2.71828.

Step-by-step explanation:

An exponential function is of the form:

[tex]y=a^{x}[/tex]

Here a is any value that is more than 0.

The natural form of an exponential function is:

[tex]y=e^{x}[/tex]

Here e is known as the Euler's number.

The value of e is approximately 2.71828.

None of these options seem to be correct. You can check each result by differentiation:

[tex](e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)[/tex]

[tex](e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)[/tex]

[tex](e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)[/tex]

[tex](e^x\tan x)'=e^x(\tan x+\sec^2x)[/tex]

But none of these are equivalent to [tex]e^x(\sec x+\tan^2x)[/tex]...

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

[tex]SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000[/tex]

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

[tex]\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}[/tex]

                               [tex]=\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907[/tex]

Use Excel's NORMSINV{0.907} function to find the Z-score.

z = 1.322

Compute the optimal production quantity for the card as follows:

[tex]\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\[/tex]

                                               [tex]=8000+(1.322\times 1000)\\=8000+1322\\=9322[/tex]

Thus, the optimal production quantity is 9,322 cards.

Greetings from Brasil...

Here we have internal collateral angles. Its sum results in 180, so:

(6X + 8) + (4X + 2) = 180

6X + 4X + 8 + 2 = 180

10X + 10 = 180

10X = 180 - 10

10X = 170

X = 170/10

Answer:

Step-by-step explanation:

y= 3x

x            y

0           0

1             3

2            6

3             9

-1            -3

-2             -6

Answer:

2(x^2 + 8x -55)

Step-by-step explanation:

Well to do the box method we first need to simplify the given equation further to,

[tex]2x^2 + 16x - 110\\[/tex],

For this quadratic the box method doesn't work so we can divide everything by 2 make make it

2(x^2 + 8x -55)

Thus,

[tex]2x^2 + 16x - 110\\[/tex] factored is 2(x^2 + 8x -55).

Hope this helps :)

[tex]\bold{\text{Answer: b.}\quad \dfrac{y^2}{100}+\dfrac{x^2}{49}=1}[/tex]

Step-by-step explanation:

The ellipse is vertical so y has the biggest radius.

Major axis (y) = 20 so the y-radius is 20/2 = 10

Minor axis (x) = 14 so the x-radius is 14/2 = 7

The equation of an ellipse is:   [tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]   where

Given: a = 7, b = 10

Assume: (h, k) = (0, 0)

[tex]\dfrac{(x-0)^2}{7^2}+\dfrac{(y-0)^2}{10^2}=1\\\\\\\dfrac{x^2}{49}+\dfrac{y^2}{100}=1\\\\\\\longrightarrow \dfrac{y^2}{100}+\dfrac{x^2}{49}=1[/tex]

Answer:

3 or -3

Step-by-step explanation:

sqrt(9)

What number multiplied by itself will give you 9

3*3 =9

-3 * -3 =9

The square root of 9 is 3 or -3

Answer:

Hey there!

Your answer would be 4/50. The total times she drawed a purple tile was 4, and she drawed 50 times.

Hope this helps :)

Answer:

[tex]\boxed{7.955>7.95}[/tex]

Step-by-step explanation:

7.95 can also be written as 7.950 .

So, we'll compare 7.955 and 7.950.

All the digits in ones, tenths, hundredths place are equal so we'll look at the thousandths place.

5 is in the thousandths place of 7.955 and 0 is in the thousandths place of 7.950. Since 5 is greater than 0 so 7.955 is greater than 7.95. It can also be written as:

7.955 > 7.950

Answer:

work is shown and pictured

Answer:

Step-by-step explanation:

Hello!

You have to estimate the mean length of 4000 b.c. human skulls trough a 95% confidence interval.

You know that

n= 6 human skulls

[tex]\frac{}{X}[/tex]= 94.2mm

S= 4.9

Assuming that the variable X: length of a 4000b.c. human skull (mm) has a normal distribution, to construct the interval you have to use the t statistic:

[[tex]\frac{}{X}[/tex] ± [tex]t_{n_1;1-\alpha /2} * \frac{S}{\sqrt{n} }[/tex]]

[tex]t_{n-1;1-\alpha /2}= t_{5; 0.975}= 2.571[/tex]

[94.2 ± 2.571 * [tex]\frac{4.9}{\sqrt{6} }[/tex]]

[89.06; 99.34]mm

With a 95% confidence level you'd expect the interval [89.06; 99.34]mm to contain the value for the average skull length for humans 4000 b.c.

I hope this helps!

Answer:

d) The t-distribution with 5 degrees of freedom must be used

Step-by-step explanation:

For cases of Normal Distribution where the variance is unknown and the sample size n is smaller than 30, we must use the t-student distribution.

The shape of the curve for t-student is bell-shape (flatter and with wider tails than the bell shape of normal distribution.

Actually, when we deal with t-student distribution we are dealing with a family of curves that will become closer and closer to the bell shape of the normal distribution as the degree of freedom increases. From values of n =30( and bigger),  we can assume that the curve of t-student is the same as for normal distribution

Answer:

0.081

Step-by-step explanation:

To solve this question, we would use the z score formula

z score = (x-μ)/σ, where

x is the raw score = 36.32cm

μ is the population mean = 34.5 cm

σ is the population standard deviation = 1.3cm

z score = (36.32cm - 34.5cm)/1.3cm

z = 1.4

Using the normal distribution to find the z score for 1.4

P(z = 1.4) = 0.91924

Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is

P(x>36.32) = 1 - P(z = 1.4)

= 1 - 0.91924

= 0.080757

Approximately ≈ 0.081

Answer:

126

Step-by-step explanation:

Total volume of sand = pi/3*(6^2)*(15) + pi*(6)^2*(30) = 1260*pi mm^3

So it will therefore take 1260*pi/10*pi = 126 seconds for all of the sand from the top hourglass to drip down to the bottom hourglass.

hii

Step-by-step explanation:

length-10x

width-x

perimeter-2(l+b)

66=2(10x+x)

66-2=10x+x

64=11x

x=11/64

lenght-11

width-64

Answer:

105.6

Step-by-step explanation:

If the mean is 8.8, than that means that in total the sum must be (8.8 * 12) which equals 105.6.

This is because the sum of all the numbers in a list divided by the amount of numbers in a list equals the mean.

Answer:

y = -32

Step-by-step explanation:

-6(y+15)=-3y+6

Distribute

-6y - 90 = -3y +6

Add 6y to each side

-6y -90+6y = -3y+6y +6

-90 = 3y+6

Subtract 6 from each side

-90 -6 = 3y +6-6

-96 = 3y

Divide by 3

-96/3 = 3y/3

-32 = y

Answer:

-32 !!!!

Step-by-step explanation:

Answer:

Hey there!

0.5(8.4)(h)=69.3

4.2h=69.3

h=16.5

Hope this helps :)

Answer:

[tex] \boxed{\sf Height \ of \ the \ triangle = 16.5 \ mm} [/tex]

Given:

Area of the triangle = 69.3 mm²

Base of the triangle = 8.4 mm

To Find:

Height of the triangle

Step-by-step explanation:

[tex]\sf \implies Area \ of \ the \ triangle = \frac{1}{2} \times Base \times Height \\ \\ \sf \implies 69.3 = \frac{1}{2} \times 8.4 \times Height \\ \\ \sf \implies 69.3 = \frac{1}{ \cancel{2}} \times \cancel{2} \times 4.2 \times Height \\ \\ \sf \implies 69.3 = 4.2 \times Height \\ \\ \sf \implies 4.2 \times Height = 69.3 \\ \\ \sf \implies Height \times \frac{ \cancel{4.2}}{ \cancel{4.2}} = \frac{69.3}{4.2} \\ \\ \sf \implies Height = \frac{16.5 \times \cancel{4.2}}{ \cancel{4.2}} \\ \\ \sf \implies Height = 16.5 \: mm[/tex]

Answer:

8a^5

Step-by-step explanation:

Well to start off 2*4=8

So the coefficent will be 8

and when multipling ezponents we add the exponents and 2+3=5 so the exponent will be 5.

So 8a^5 is the answer

Answer:

C. x+4y=-8

Step-by-step explanation:

The standard form of an equation is Ax+Bx=C

y= -[tex]\frac{1}{4}[/tex]x-2

Multiply 4 by both sides

4y= -x-8

1+4y= -8

Answer:

[tex]\boxed{\sf C. \ 6.6 \ units}[/tex]

Step-by-step explanation:

The triangle is a right triangle.

We can use trigonometric functions to solve.

[tex]\sf cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]\sf cos(35)=\frac{MO}{8}[/tex]

[tex]\sf 8 \ cos(35)=MO[/tex]

[tex]\sf 6.55321635...=MO[/tex]

The correct answer is D. 23

Explanation:

Histograms similar to other graphs represent numerical information, usually by using bars, as well as ranges. For example, in the case presented the information presented belongs to the scores obtained in a test, which are shown using ranges. Moreover, it is possible to know the total of people that took the test by adding each of the frequencies, as the frequency in the y-axis shows the number of times the range repeated and it is expected each grade registered belongs to 1 person. This means the total of people is equal to 2 (score from 60-69) + 9 (score from 70-79) + 7 (score from 80-89) + 5 (score from 90-99) = 23 people.

Answer:

the answer is 23

Step-by-step explanation:

hopes this helps:)

Answer:

b^2

------

2a

Step-by-step explanation:

-6ab^3          10b

-------------- * -----------

5a                   -24 ab^2

Rewriting

-6ab^3          10b

-------------- * -----------

 -24 ab^2      5a

Canceling like terms

b                  2b

-------------- * -----------

 4                a

Canceling the 2 and 4

b                  b

-------------- * -----------

 2                a

b^2

------

2a

Answer:

b²/2a

Step-by-step explanation:

[(-6ab³)/5a]*[(10b)/(-24ab²)]

-60ab^4/-120a²b²= ( when divide ,subtract the exponents)

b²/2a

The team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow.

Answer:

The answer above is correct B

Step-by-step explanation:

Took the Unit Test Review on edg 2020 correct

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

[tex]p \propto \dfrac{1}{d}[/tex]

Introducing the constant of proportionality

[tex]p = \dfrac{k}{d}[/tex]

If 150 pounds is required for a distance of 10 inches from the object

[tex]150 = \dfrac{k}{10}\\\\k=1500[/tex]

Therefore, the relationship between p and d is:

[tex]p = \dfrac{1500}{d}[/tex]

When d=3 Inches

[tex]p = \dfrac{1500}{3}\\\implies p=500$ pounds[/tex]

The pressure applied when the distance is 3 inches is 500 pounds.

Answer:

A. x <= 2

Step-by-step explanation:

The domain of a real function should be all real numbers. In

f(x) = sqrt(2-x)

we need 2-x to be non-negative, therefore

2-x >= 0

which implies

x <= 2

Answer:

[tex]\Huge \boxed{{x\leq 2}}[/tex]

Step-by-step explanation:

The function is given,

[tex]f(x)=\sqrt{2-x}[/tex]

The domain of a function are all possible values of x.

There are restrictions for the value of x.

2 - x cannot be equal to a negative number, because the square root of a negative number is undefined. 2 - x has to equal to 0 or be greater than 0.

[tex]2-x\geq 0[/tex]

[tex]-x\geq -2[/tex]

[tex]x\leq 2[/tex]

The domain of the function is x ≤ 2.