which of the following is true of the angle shown

the measure of the angle is greater than 360

the angle is not in standard position

the terminal side of the angle lies in quadrant 2

the angle can be measured in radians only

Answer:

a)$62.2417

b)$65.9912

c)$39.7447

d)$47.2437

Step-by-step explanation:

a)100%-30%=70%

70%+13%=83%

83/100x74.99=62.2417

b)100%-25%=75%

75%+13%=88%

88/100x74.99=65.9912

c)100%-60%=40%

40+13=53

53/100x74.99=39.7447

d)100%-50%=50%

50+13=63%

63/100X74.99=47.2437

Hope this helps! Thanks.

Answer:

15 percent

Step-by-step explanation:

Answer:

15%

Step-by-step explanation:

(80-68)*(100/80)=15%

___________

[tex] \: [/tex]

y = [tex]\sqrt{-x - 3}[/tex]

graph in picture!

EXPERIMENT

PROBLEM

CONCLUSION

INFERENCE

we know,

slope = y_2 - y_1/x_2 - x_1

1.

according to the graph given points are,

(2,1) and (0,3)

now,

→ 3 - 1/0 - 2

→ 2/-2

→ -1

therefore, slope of the given graph is -1.

2.

according to the graph given points are,

(-6,2) and (0,1)

now,

→ 1 - (-6)/0-2

→ 7/-2

→ -3.5

therefore, slope of the given graph is -3.5 OR in fraction form it is 7/-2.

3.

according to the graph given points are,

(2,2) and (0,4)

now,

→ 4 - 2/0-2

→ 2/-2

→ -1

therefore, slope of the given graph is -1.

hope this answer helps you dear...take care and may u have a great day ahead!

Answer:

I know this isn't really help but Desmos is a good place to help you with stuff like this.

Answer:

y-intercept = 34/5 (6.8), eqn, y = 0.4x +0.6

Step-by-step explanation:

Slope (m) = 0.4

(8-y)/(3-x) = o.4

8-y = 1.2 - o.4x

6.8 - y = -0.4x

y = 0.4x + 6.8

From y = mx + c , where c is the y-intercept

hence 6.8

Given :

To find :

Solution :-

The first set is ,

Solving the Quadratic equation ,

Hence ,

The second set is ,

Solving the Quadratic equation ,

Hence ,

Now ,

Since AΠ B is a null set , hence ,

Answer:

[tex]h = \frac{V}{\pi r^{2}}[/tex]

h = 4 cm

Step-by-step explanation:

Given the formula for the volume (V) of a cylinder: V = πr ²h, and the following values for volume and radius:

V = 36π cm³

r = 3 cm

First, solve for h:

V = πr ²h

Divide both sides by πr ²:

[tex]\frac{V}{\pi r^{2} } = \frac{\pi r^{2}h}{\pi r^{2} }[/tex]

[tex]h = \frac{V}{\pi r^{2}}[/tex]

Next, solve for the height of the cylinder by substituting the given values for volume and radius into the formula:

[tex]h = \frac{V}{\pi r^{2}}[/tex]

[tex]h = \frac{36\pi }{\pi (3^{2})}[/tex] → π cancels out.

[tex]h = \frac{36}{9}[/tex]

h = 4 cm

Answer:

we know that q=-18

So if we see the fraction below it says q/3

We know that q is -18

Therefore, you substitute it in for q and you get

-18/3 which equals -6

Answer:

4

Step-by-step explanation:

the answer is 4

yep it is because eight cancels out with the other one

Answer:

(8 × 4)/8

so answer=4

Answer:

yes these all are correct

Answer:

The answer is 10x

Step-by-step explanation:

Answer:

The endpoints of the line segment CD are:

$$C=(x_1,y_1)= (-4, 8) \\ D= (x_2,y_2)= (8, -4) $$

We find the midpoint using th

x-2/2=3x+8/4

x-1=3x+2

-x. -x

-1=2x+2

-2. -2

-3=2x

÷2. ÷2

-3/2=x

Answer:

jjdttfyuy

Step-by-step explanation:

Answer: F 20%

Step-by-step explanation:

50 is 20% of 250

Answer:

Step-by-step explanation:

9 - a = 9 -a

9 - a + 10 = 19 - a

Answer:

  Answer B    5.5x + 9

Step-by-step explanation:

Perimeter is the distance around the three sides of the triangle

P = (0.3x + 24) + (5x) + (0.2x - 15)

P = (0.3x + 5x + 0.2x) + (24 - 15)

P = 5.5x + 9

The number of student taking math is 37 while the number of students taking programming is 74

Universal set = 97

let

The number taking math = x

The number taking programming = 2x

The number of students that take exactly one subject = 53

The student taking neither of the subject = 15

The number of students taking only maths will be

The number of students taking only programming will be

let

n(m ∩ p) = y

Therefore,

x - y + 2x - y = 53

3x - 2y = 53

Also,

97 = x + 2x - y + 15

3x - y = 82

Therefore,

3x - 2y = 53

3x - y = 82

-y -(-2y) = 82 - 53

y = 29

3x - 29 = 82

3x = 82 + 29

3x = 111

x = 111/3

x = 37

Finally,

number of students taking maths = 37

number of student taking programming = 37×2 = 74

Check similar problem on sets: https://brainly.com/question/16132324?referrer=searchResults

Answer:

let the value of x

Step-by-step explanation:

x=8+4=17+5

x=12=22x=22/12

x=1.8334

Answer: x = -28

Step-by-step explanation:

1) Distribute

3(x-8)+4x=8x+4

3x-24+4x=8x+4

2) Combine like terms

7x - 24 = 8x + 4

3) Move x(subtract 7x from both sides)

-24 = x + 4

4) Subtract 4 from both sides.

-28 = x

Hope it helps :)

The simplified solution of the given expression is x = -28.

Given that, to determine the simplified solution of the expression  3(x-8)+4x=8x+4

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
3(x-8)+4x=8x+4
3x - 24 + 4x - 8x = 4
-x = 4 + 24
-x = 28

Thus, the simplified solution of the given expression is x = -28.

Learn more about simplification here:

https://brainly.com/question/12501526

#SPJ2

Answer:

The answer is D. Hope this helps

Answer:

you did it right

Step-by-step explanation:

Answer:

it would cost $0.74 = 74 cents

Step-by-step explanation:

The cost of one ounce of tomato = $0.37

1 portion of potato gnocchi requires 2 ounces of tomato sauce.

To find the cost of one portion of the potato gnocchi, we have to simply find the cost of 2 ounces of tomato sauce.

That is:

Cost = 2 * 0.37 = $0.74

Hence, one portion of potato gnocchi costs $0.74

Since $1 = 100 cents, the cost in cents will be:

0.74 * 100 = 74 cents

Answer:

160

Step-by-step explanation:

24/6=4

4 x 40 = 160

x is 160 when y is 24

Answer:

160

Step-by-step explanation:

Let x be... well x

24 ÷ 6 = 4

40 × 4 = 160

OR

40÷6 ≈6.66

6.6666666... × 24 = 160

Answer:

1112 grams

Step-by-step explanation:

1867-755=1112 g

Answer:

1112 grams.

Step-by-step explanation:

1867g - 755g = 1112 g

brainliest please. . . .