Answer:
Displacement
Explanation:
Question 3 of 5
Which object absorbs the most sound waves?
A. Earplugs
B. Tissue paper
C. Water
D. Air
Answer:
The correct option is B.
Tissue paper
Explanation:
Tissue paper absorb most sound waves because it is porous. Materials that absorb sound most are highly porous like tissue because that have pores and allow sound to penetrate through it channels or cavities which makes it to loss part or all of it energy. This material allow sound wave to enter through it.
Sound energy is distributed as a result of heat loss which is caused by the air molecules of the pores wall in the material.
Answer:
Option A: Earplugs is your answer.
Explanation:
Merry Christmas
A wave traveling at 100 m/s has a frequency of 200Hz. What is the wavelength of this wave?
A driver in a car is driving 65 m/s when she sees a
police car. Over 10 seconds, the driver slows down
to a velocity of 22 m/s to avoid getting a ticket.
What is the deceleration of the car over that 10
seconds? (Include units in your answer.)
Answer:
43 m\s in the 10 seconds?
Explanation:
Which of the following examples shows that a chemical reaction has occurred?
O A solid is formed when heat is removed from a sample of water.
A rock breaks into smaller pieces when it is struck with a hammer.
O A cup of water turns pink when a few drops of red food coloring are added.
Bubbles form when baking soda is added to vinegar and mixed.
Formation of bubbles when baking soda and vinegar are mixed is an example showing a chemical reaction has occurred as these two substances on mixing form sodium acetate.
What are chemical reactions?
Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.
There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical reactions:
1) inorganic reactions
2)organic reactions
3) biochemical reactions
During chemical reactions atoms are rearranged and reactions are accompanied by an energy change as new substances are formed.
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Convert 400.0 nm to mm.
Answer: 0.0004
Explanation: hope this helpsss ^-^
A materials density is the same , no matter how large or small the sample is or what it’s shape is as long as it is solid uniform piece of the material explain how this is possible and give an example
Answer:
See the explanation below
Explanation:
Density is defined as the relationship between mass and volume, i.e. the following equation can be used:
density = m/v
where:
density [kg/m^3]
m = mass [kg]
v = volume [m^3]
If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.
m = density*v
To understand this concept more clearly, let's use the following example:
We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.
1000 = m /1
m = 1000*1 = 1000 [kg]
Now if we have 500 kilograms of water, that would pass with the volume so that the density remains constant.
1000 = 500/v
v = 500/1000
v = 0.5 [m^3]
We can see that the volume of water has halved. Since the mass of water was reduced by half. That is, the relationship between mass and volume is proportional to the density of the material or substance.
1.
What is a force? What changes can be produced by a force?(AS)
Answer:
the pull or push which changes or tends to change the position of an object from rest to motion or motion to rest is called force.
Changes of force that can be produced:
Force can change the shape of a body.Force can change the position of a body.Force can stop the moving body.Force can change the speed of a moving body.Force can change the direction of a moving body.Pete rides his horse 64 km in 4 hours.
What is his average speed in kilometers
per hour?
Given:
D=64 km
T=4 hour
Answer:
His average speed is
[tex] \frac{64km}{4h} = {16kmh}^{ - 1} [/tex]
A sprinter running a 100 m race starts at rest, accelerates at constant acceleration of magnitude A for 2 seconds, then runs at a constant speed until the end. Find the position (relative to the start) and speed of the runner at the end of the 2 seconds, in terms of A.
Answer:
The distance ran by the runner in the 2 seconds is 2·A
The speed of the runner at the end of the 2 seconds is 2·A
Explanation:
The given information are;
The distance the sprinter is running = 100 m
The initial constant acceleration of the sprinter, a = A
The duration of the initial acceleration, t = 2 s
The initial speed of the printer, u = 0 (The sprinter starts from rest)
The rate with which the sprinter then runs with to the end = Constant speed
Therefor, we have, from the equation of motion;
s = u × t + 1/2 × a × t²
Where;
s = The distance ran by the sprinter
∴ at t = 2 seconds, we have;
s = 0 × 2 + 1/2 × A × 2² = 1/2 × A × 4 = 2·A
The distance ran by the runner in the 2 seconds = 2·A
The speed, v, of the runner at the end of the 2 seconds is given as follows;
v = u + a × t
When t = 2 seconds, we have;
v = 0 + A × 2 = 2·A
The speed of the runner at the end of the 2 seconds = 2·A.
What is the acceleration of the object in this graph?
Answer: 6 and 0.75
Explanation:
because you look how far up it goes and just use the graph
hello what is quantum physics
Answer:
It is a fundamental theory in physics that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.
A car is traveling on a level road at a constant rate of speed. What additional force is necessary to bring the car into equilibrium? zero. greater than the normal force times the coefficient of static friction. the normal force times the coefficient of kinetic friction. equal to the normal force times the coefficient of static friction.
Answer: Zero.
Explanation:
By the first Newton's law, we know that:
every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
Now, we know that the car is moving with constant speed, then there is no net force acting on the car, which means that the car is already in equilibrium.
Then if we add one force to the situation, the car will not be anymore in equilibrium.
The correct option is zero.
How can the force of gravity affect weight?
Answer:
If you go to a planet with little gravity you will be lighter and the stronger gravity is the heavier you are. The mass of any object that is experiencing different gravity forces will stay the same the only thing that will change is the weight.
The force of gravity affects weight by exerting a downward force on objects near the Earth's surface. Weight is the measure of the gravitational force acting on an object. The force of gravity is directly proportional to the mass of an object.
How does gravity affects weight?According to Newton's law of universal gravitation, the force of gravity between two objects is determined by their masses and the distance between them. Near the surface of the Earth, the force of gravity can be approximated using the equation:
F = mg
Where:
F is the force of gravity
m is the mass of the object
g is the acceleration due to gravity (approximately 9.8 meters per second squared on the surface of the Earth)
As you can see from the equation, weight (force of gravity) is directly proportional to the mass of an object. This means that as the mass of an object increases, its weight increases as well. For example, a heavier object will experience a greater force of gravity and, therefore, have a greater weight compared to a lighter object.
It's important to note that weight is a force, typically measured in units such as newtons or pounds, whereas mass is a measure of the amount of matter in an object, typically measured in kilograms or pounds. Weight can vary depending on the strength of the gravitational field, whereas mass remains constant regardless of the location. For example, an object that weighs 100 pounds on Earth would weigh less on the Moon due to the Moon's weaker gravitational pull. However, the mass of the object would remain the same.
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A plane is traveling North at 80km/hr into a 20 km/hr headwind (South). What is the plane's resultant velocity?
Answer:
Consider our plane flying at a speed of 80 km/hr into a 40 km/hr crosswind. Its speed, relative to the ground, can be calculated by adding the two vectors as shown on the right. What happens to the speed of the plane as the crosswind increases in magnitude? Look at the animation on the right. It is obvious that the speed of the plane, relative to the ground, increases in magnitude.
Explanation:
Answer:
60km/hr
Explanation:
R=80 - 20
=60km/hr, north
What is the pressure exerted by a column of water 80 cm high ?
Answer:
[tex]P=7,840\ Pa[/tex]
Explanation:
Pressure Exerted by a Column of Liquid
The pressure P exerted by a column of liquid of height h and density ρ is given by the hydrostatic pressure equation:
P = ρgh
Where ρ is the density of the liquid, g is the acceleration of gravity g=9.8m/s^2, and h is the height of the column of liquid.
The data provided is as follows:
[tex]\rho=1000\ Kg/m^3[/tex]
[tex]g=9.8m/s^2[/tex]
[tex]h=80\ cm = 0.8\ m[/tex]
The pressure is:
[tex]P = 1000\ Kg/m^3\cdot 9.8\ m/s^2 \cdot 0.8\ m[/tex]
[tex]\boxed{P=7,840\ Pa}[/tex]
What is the displacement when t =2s to 3s
Answer:
t=5s
Explanation:
t=2 + t= 3s = t= 5s
explain the types of motion
Answer:
there are three type of notion
Giselle leaves the ground at an angle of 25° above the horizontal at a velocity of 5.5 m/s to leap over the fence.
Round all answers to the nearest hundredth.
a) What is the horizontal component of the gazelle’s velocity?
b) What is the vertical component of the gazelle’s velocity?
c) How much later did the Gisele hit the ground?
d) What is her maximum height?
e) How far did she leap?
Answer:
a) 5.01 m/s
b) 3.28 m/s
c) 0.67 s
d) 0.45 m
e) 2.78 m
Explanation:
Answer:
a) 3.04 m/s
b) 3.7 m/s
c) 0.72 s
d) 0.36 m
e) 4.12 m
Explanation:
What is the acceleration of the car from 0 to 2 s ? - What is the magnitude of the net force exerted on the car from 0 - 2s ? - What is the acceleration of the car from 2 s to 4s - What is the magnitude of the force exerted in stopping the car ? What is the instantaneous velocity at 1 ?
Answer:
a) a = 0 m / s²
, b) a = 0 ==> F = 0
, c) a = - 2 m / s²
,d) v = 4 m/s
Explanation:
a) It is asked to find the acceleration in the interval from 0 to 2s, from the graph we see that in this interval the velocity is constant with a value of 4 me / s, therefore the average eceleration is
a = (V₂ - V₁) / t
a = (4 -4) / 2
a = 0 m / s²
b) Newton's second law establishes a relationship between force and acceleration
F = m a
as acceleration is zero
a = 0 ==> F = 0
c) the acceleration in interval 2 a4 S
a = (0 - 4) / (4-2) = -4 / 2
a = - 2 m / s²
The negative sign iniquity the acceleration is slowing the movement
d) the force is
F = m a
F = 2 m
e) from the graph we can read the speed of the vehicle for time
v = 4 m / s
A car is traveling with an initial velocity of 15 m/s when the driver decides to go faster by accelerating at 5 m/s squared for 10 seconds. How far did the car travel during this time?
Answer:
x = 400 [m]
Explanation:
To solve this problem we must use the following kinematics equations, first, we find the final speed, and then we proceed to find the distance traveled.
[tex]v_{f}=v_{i} +(a*t)\\[/tex]
where:
Vf = final velocity [m/s]
Vi = initial velocity = 15 [m/s]
a = acceleration = 5 [m/s^2]
t = time = 10 [s]
Note: the positive sign in the Equation indicates that the car is accelerating, i.e. its speed is increasing.
Now replacing
Vf = 15 + (5*10)
Vf = 65 [m/s]
Now using the second equation:
[tex]v_{f} ^{2}= v_{i} ^{2}+(2*a*x)[/tex]
where:
x = distance traveled [m]
x = (65^2 - 15^2)/ (2*5)
x = 400 [m]
A net force of 500 N acts on a 100 kg cart. a. What is the acceleration?
125.5 micrograms = ____ kilograms
The part of a longitudinal wave where the particles are spread apart is called a______?
Here are the choose of answers: A- Top Wave has the highest pitch because it has the highest amplitude.
B - Bottom Wave has the highest pitch because it has the lowest frequency.
C- Bottom Wave has the highest pitch because it has the highest frequency.
D- Both waves have the same pitch because they both have the same frequency
A 2.50-mL sample of ammonia gas (NH3) is heated from 325 kelvin to 425 kelvin. What is the new volume of the sample?
Answer:
The new volume of the [tex] NH_{3}[/tex] sample is 3.27mL.
Explanation:
Given the following data;
Original Volume, V1 = 2.50-mL
Original Temperature, T1 = 325K
New Temperature, T2 = 425K
To find new volume V2, we would use Charles' law.
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles is given by;
[tex] VT = K[/tex]
[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]
Making V2 as the subject formula, we have;
[tex] V_{2}= \frac{V1}{T1} * T_{2}[/tex]
[tex] V_{2}= \frac{2.50}{325} * 425[/tex]
[tex] V_{2}= 0.0077 * 425[/tex]
V2 = 3.27mL
Therefore, new volume of the [tex] NH_{3}[/tex] sample is 3.27mL.
(BRAINLIEST AND 13 POINTS) Which two variables have an effect on the momentum of an object?
a. mass and position b. mass and velocity c. position and velocity
Answer:
B mass and velocity......................
12. The resistivity of a given wire of cross-sectional
area 0.7mm 4.9 x 10raised to the power of -4ohm mm. Calculate the
resistance of a 2ohm length of the wire
R = resistivity × (l/A), A = πr^2= πd^2/4
2 =( 4.9 × 10^ -4) * (l/π0.7^2/4)
make l the subject and calculate.
i assumed we are looking for the length if the wire.
Saturn is 1,200,000,000 kilometers from earth. What is the distance in standard form using meters?
Answer:
That would be 1,200,000,000,000Explanation:
Hope this helpsAt 1:00 p.m. a car, traveling at a constant
velocity of 82 km/h toward the west, is 24 km
to the west of our school.
How far from the school will it be at 3:30
p.m.?
Answer in units of km.
.....
The distance from the school will be 229 Km
What is Velocity ?Velocity is the distance travel in a specific direction per time taken. Velocity is a vector quantity.
Given that at 1:00 p.m. a car, traveling at a constant velocity of 82 km/h toward the west, is 24 km to the west of our school. How far from the school will it be at 3:30 pm ?
The time taken by the car will be = 3:30 - 1:00 = 2:30 = 2.5 hr
Since the speed is constant, V = s/t
82 = s / 2.5
s = 82 x 2.5
s = 205 Km
The distance from the school = 24 + 205 = 229 Km
Therefore, the distance from the school will be 229 Km
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I NEED HELP!! PLEASE ANSWER WITHIN 30MIN.. THANK YOU
Another way to represent a substance is with a picture. What information does the picture provide about carbon dioxide?
Answer:
The picture gives information about how many kinds of atoms are in carbon dioxide and how they are connected.
Explanation:
This was the answer to my test on Plato. I hope this helps :)
Answer:
The picture gives information about how many kinds of atoms are in carbon dioxide and how they are connected.
Explanation:
From the moment a 40 m/s fastball touches the catcher’s mitt until it is completely stopped takes 0.012 s. Calculate the average acceleration of the ball as it is being caught.
Answer:
3333.33 m/s²
Explanation:
From the question given above, the following data were obtained:
Total Velocity (v) = 40 m/s
Total Time (t) = 0.012 s.
Average acceleration (a) =..?
Average acceleration can be defined as follow:
Average acceleration (a) = Total velocity (v) / total time (t)
a = v / t
With the above formula, we can obtain the average acceleration of the ball as shown below:
Total Velocity (v) = 40 m/s
Total Time (t) = 0.012 s.
Average acceleration (a) =..?
a = v / t
a = 40 / 0.012
a = 3333.33 m/s²
Therefore, the average acceleration of the ball is 3333.33 m/s².