Which of the following is an equation that best describes compound interest?

Answer: Choice C. No error. Molly is correct

Note how BC is 4 units high while FG is 5 units high. We don't have a match. So there is no way the figures are the same regardless of rigid transformations.

Answer:

Its c

Step-by-step explanation:

I got it right on khan academy

Answer:

We have an extrema (local minimum) at x = -0.125

An inflection point at x = 0.25

Step-by-step explanation:

The given function is given as follows;

[tex]f(x) = 3x^{1/3} + 6x^{4/3}[/tex]

At the extrema points, f'(x) = 0 which gives;

[tex]0 = \dfrac{\mathrm{d} \left (3x^{1/3} + 6x^{4/3} \right )}{\mathrm{d} x} = \dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x}[/tex]

(8x + 1) =x- (0/((x)^(1/0.3)) = 0

x = -1/8 = -0.125

f''(x)  gives;

[tex]f''(x) = \dfrac{\mathrm{d} \left (\dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x} \right )}{\mathrm{d} x} = \dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3}[/tex]

Substituting x = -0.125 gives f''(x) = 32 which is a minimum point

The inflection point is given as follows;

[tex]\dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3} = 0[/tex]

[tex]\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right }{} = 0 \times \dfrac{x^3}{ \sqrt[0.3]{x}}[/tex]

[tex]\dfrac{8}{3}\cdot x - \dfrac{2}{3} \right }{} = 0[/tex]

x = 2/3×3/8 = 1/4 = 0.25

We check the value of f''(x) at x = 0.24 and 0.26 to determine if x = 0.25 is an inflection point as follows;

At x = 0.24,   f''(x) = -0.288

At x = 0.26,   f''(x) = 0.252

0.25 is an inflection point

Answer:

172.83 kg

Step-by-step explanation:

A cylindrical container has a radius (r) of 0.3 meter and a height (h) of 0.75 meter and density of 815 kg/m³.

The density of a substance is the mass per unit volume, it is the ratio of the mass of a substance to the volume occupied. The density is given by the formula:

Density = Mass / volume

The volume of a cylinder is given as:

V = πr²h

V = π × (0.3)² × 0.75 = 0.212 m³

Density = Mass/ volume

Mass = Density × Volume

Mass = 815 kg/m³ × 0.212 m³

Mass = 172.83 kg

Answer:

The answer is 173

Step-by-step explanation:

The other guy's answer was correct, but he forgot to round up to the nearest whole number so just in case you didn't notice the question saying that!

Complete question :

∆ABC is similar to ∆PQR. AB¯¯¯¯¯ corresponds to PQ¯¯¯¯¯, and BC¯¯¯¯¯ corresponds to QR¯¯¯¯¯. If the length of AB¯¯¯¯¯ is 9 units, the length of BC¯¯¯¯¯ is 12 units, the length of CA¯¯¯¯¯ is 6 units, and the length of PQ¯¯¯¯¯ is 3 units, then the length of QR¯¯¯¯¯ is ______units and the length of RP¯¯¯¯¯ is ________units.

Answer:

QR = 4 units ; RP = 2 units

Step-by-step explanation:

For similar triangles

Length1 ∆1/length1 ∆2 = Length 2 ∆1 /length 2∆2

AB Corresponds to PQ

BC corresponds to QR

AB = 9 Units, BC = 12 Units

CA = 6 units, PQ = 3 units

Take the ratio of the corresponding sides :

AB/ PQ = BC / QR

9/ 3 = 12 / QR

Cross multiply

9 * QR = 3 * 12

QR = 36 / 9

QR = 4 units

For RP:

AB/PQ = CA/RP

9 / 3 = 6 / RP

9 * RP = 3 * 6

RP = 18 / 9

RP = 2 units

Answer:

rp-2 qr-4

Step-by-step explanation:

Answer:

[tex]4\sqrt{2}\\\\7\sqrt{2} \\\\13\sqrt{2}[/tex]

Step-by-step explanation:

Well the diagonal using pythagora's theorem:

[tex]x\sqrt{2}[/tex] where x is the lenght is the side of the square

so when x=4

[tex]4\sqrt{2}[/tex]

when x=7

[tex]7\sqrt{2\\}[/tex]

when x=13

[tex]13\sqrt{2}[/tex]

The length of diagonal is for (a=4) is [tex]4\sqrt{2}[/tex], for(a=7) is [tex]7\sqrt{2}[/tex] and for (a=13) is[tex]13\sqrt{2}[/tex].

Given side of squares.

We have to calculate the length of diagonal.

We know that in square shape,

length of diagonal [tex]=\sqrt{2} a[/tex], here a is the side of square.

So when square has a side of 4 then its diagonal becomes [tex]4\sqrt{2}[/tex].

when square has a side of 7 then its diagonal becomes [tex]7\sqrt{2}[/tex].

when square has a side of 13 then its diagonal becomes [tex]13\sqrt{2}[/tex].

Hence the length of diagonal is for (a=4) is [tex]4\sqrt{2}[/tex], for(a=7) is [tex]7\sqrt{2}[/tex] and for (a=13) is[tex]13\sqrt{2}[/tex].

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Answer:

x = 74°

Step-by-step explanation:

The diagram shown in this question, is a Quadrilateral inscribed in a circle

It is important to note that

The sum of opposite angles in a Quadrilateral = 180°

93° + z = 180°

z = 180° - 93°

z = 87°

In a cyclic quadrilateral,

Intercepted angle = 1/2(Intercepted arc)

Intercepted angle = 93°

Intercepted arc = x + 112°

Hence,

93° = 1/2(x + 112)°

93° × 2 = x + 112°

186° = x + 112°

x = 186° - 112°

x = 74°

Answer:

It’s 87° for mine

Step-by-step explanation:

Explanation:

You could use any two points you want. For me, the easiest is when x = 0. Plug this into the equation to get

y = 2x-7

y = 2(0)-7

y = -7

So we have x = 0 and y = -7 pair up to get (0,-7) as our first point. This is the y intercept.

Repeat for x = 1

y = 2x-7

y = 2(1)-7

y = -5

So (1,-5) is another point on this line. You only need two points at minimum to graph a straight line.

Step-by-step explanation:

Keeping,  one angle FDE, many triangles are possible since length of no segment is fixed and only one angle is fixed.

At many instances, triangle ABC and DEF have same angle measurements. Referring to the image attached here.

As point G moved on the ray EF, many triangles with same angle measurements as of ABC can be formed.

Answer:

Since no segment length is fixed and only one angle is fixed, multiple triangles are possible while maintaining one angle FDE. Triangles ABC and DEF frequently have the same measured angles. referring to the picture that is attached. Numerous triangles with the same angle measurements as ABC can be constructed when point G moves along ray EF.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given figure : Trapezoid

Base sides,

a = 2.5

b = 7.5

Height ( h ) = 2.5

Now, finding the area:

[tex] \frac{1}{2} (a + b) \times h[/tex]

Plug the values

[tex] = \frac{1}{2 } \times (2.5 + 7.5) \times 2.5[/tex]

Calculate the sum

[tex] = \frac{1}{2} \times 10 \times 2.5[/tex]

Reduce the numbers with G.C.F 2

[tex] = 5 \times 2.5[/tex]

Calculate the product

[tex]12.5 \: \: {units}^{2} [/tex]

Hope this helps...

Best regards!

Answer:

28 cm²

Step-by-step explanation:

The area of Δ BDF is the area of the rectangle subtract the area of the 3 white triangles.

Since the area of the rectangle = 80 cm² and

area = length × breadth, then

breadth = 80 ÷ 10 = 8 cm

Thus CE = EF = 8 cm and CD = DE = BC = 4 cm

Area of Δ DEF = 0.5 × 10 × 4 = 20 cm²

Area of Δ ABF = 0.5 × 8 × (10 - 4) = 0.5 × 8 × 6 = 24 cm²

Area of Δ BCD = 0.5 × 4 × 4 = 8 cm²

Thus

area of Δ BDF = 80 - (20 + 24 + 8) = 80 - 52 = 28 cm²

Hey there! :)

Answer:

Slope = 2/5.

Step-by-step explanation:

Use the slope formula to solve for the slope of the line:

[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Plug in the coordinates of each point into the equation:

[tex]m = \frac{8 - 6}{10 - 5}[/tex]

Simplify:

m = 2/5. This is the slope of the line.

7x - 14 = 4x + 19

7x - 4x = 14 + 19

3x = 33

x = 11

Answer:

The third option is correct.

The domain of the function is given by

[tex]Domain = 0 \leq t \leq 40[/tex]

The range of the function is given by

[tex]Range = 0 \leq V(t) \leq 200[/tex]

Step-by-step explanation:

Sara bought a cell phone for $200 and its value has decreased at rate of $5 per month.

V(t) is the value of the phone and t is the number of months.

The domain of the function is the possible values of the number of months t.

The domain of the function is given by

[tex]Domain = 0 \leq t \leq 40[/tex]

The range of the function is the values of V(t) that we get after substituting the possible values of the number of months t.

The range of the function is given by

[tex]Range = 0 \leq V(t) \leq 200[/tex]

When the number of months is t = 0 then the value of the function is maximum V(t) = 200

When the number of months is t = 40 then the value of the function is minimum V(t) = 0

Therefore, the third option is correct.

Answer:

1st one

Step-by-step explanation:

The rational function which is graphed below is  F(x)=-1/x, the correct option is B.

Function is a type of relation, or rule, that maps one input to specific single output;

In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable). In mathematics and the physical sciences, functions are indispensable for formulating physical relationships;

Linear function is a function whose graph is a straight line;

We are given that;

The graph of the function

Now,

Points on 1/(x + 4);

The function y = 1/(x + 4) is a hyperbola. It has two branches that extend infinitely in opposite directions. The x-axis and y-axis are both asymptotes of the hyperbola.

Points on y= 1/x-4;

The function y = 1/(x - 4) is also a hyperbola. Its asymptotes are the vertical line x = 4 and the horizontal line y = 0;

Points on y = 1/(x-1);

The function y = 1/(x-1) is also a hyperbola. Its asymptotes are the vertical line x = -4 and the horizontal line y = 0.

Therefore, by the given graph function will be F(x)=-1/x;

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The required length of the base is 18 units for the square pyramid.

The square pyramid shown below has a slant height of 17 units and a vertical height of 15 units. What is the length of one of the bases of the pyramid to be determined?

In a right-angled triangle, its side, such as hypotenuse, perpendicular, and the base is Pythagorean triplets.

The verticle height = 15
Slant height = 17
Let the base length be a,
For the half slant profile applying the Pythagorean theorem,
slant heigth² = vertical height² +  base length ²
17² = 15² + ( a/2 )²
289 - 225  =  ( a/2 )²
( a/2 )² = 64
a/2 =8
a = 16

Thus, the required length of the base is 18 units for the square pyramid.

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The correct answer is C. Four pies

Explanation:

Marginal cost refers to an increase in the cost of production as additional units are made. In the case of apple pies, the graph shows the cost for one is $1.00. Moreover, this decreases when two or three pies are produced because the cost is between $0.60 and $0.30. However, if the producer makes four or more units, the cost increases. For example, at four units the cost per unit is $0.60, while at six units the cost is $1.50. Thus, the marginal cost begins to increase at four pies.

Answer: four pies

Step-by-step explanation:

The graph is a marginal cost curve that compares expenses therefore it would equal four pies because the marginal cost rises on the graph starting at 4.

Answer:

Step-by-step explanation:

It is half of equilateral triangle where 2√3 is its hight so:

[tex]2\sqrt3=\frac{k\sqrt3}2\\\\4\sqrt3=k\sqrt3\\\\k=4[/tex]

The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).

Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.

The statement correctly describes the graph of y = x + 7 as choice A.

The graph is moved 7 units up

We have given that,

The graph of y = x.

Each statement describes a transformation of the graph of y = x.

The plus 7 at the end will shift the graph 7 units up.

Replace y with f(x).

Then we have g(x) = f(x) + 7.

Adding 7 to y = f(x) will increase the y value by 7.

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Answer:

[tex]a^2+2ab+b^2[/tex]

Step-by-step explanation:

If we have [tex](a+b)^2[/tex] we can calculate this as:

[tex](a+b)*(a+b)[/tex]

So, applying distribution property, we get:

[tex](a+b)*(a+b)=a*a+a*b+b*a+b*b[/tex]

Where:

[tex]a*a=a^{2}[/tex]

 [tex]b*b=b^2[/tex]

[tex]a*b=b*a=ab[/tex]

so:

[tex](a+b)*(a+b)=a^2-ab+ab+b^2\\(a+b)*(a+b)=a^2+2ab+b^2[/tex]

Answer:

I guess y=2x+5

Answer:

[tex]f(x) =\sqrt[3]{x}[/tex]

Step-by-step explanation:

Hello!

Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:

[tex]g(x) = \sqrt[3]{x-5}+7[/tex]

To have the the parent function, we must find the parent one, let's call it by f(x).

[tex]f(x) =\sqrt[3]{x}[/tex]

This function satisfies the Domain of the given one, because the Domain is still [tex](-\infty, \infty)[/tex] and the range as well.

Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.

Answer:

5 units to the right and 7 units up (B on edge)

Step-by-step explanation:

Answer:

[tex]x=-1,5[/tex]

Step-by-step explanation:

[tex]x^2-4x-5=0[/tex]

In order to solve this quadratic, we have many methods. We can factor, complete the square, or use the quadratic formula. I'm going to factor since it's the easiest method.

To factor, find two numbers that when multiplied equal a(c) and when added equal b.

a=1, b=-4, and c=-5.

So we want two numbers that when multiplied equals 1(-5)=-5 and when added equals -4.

-5 and 1 are the possible numbers. Therefore:

[tex]x^2-4x-5=0\\x^2+x-5x-5=0\\x(x+1)-5(x+1)=0\\(x-5)(x+1)=0\\x=5, -1[/tex]

Louis traveled 7,144 miles

Answer:

cos(30)

Step-by-step explanation:

Answer:

sin(15)

Step-by-step explanation:

Answer:

A. [tex] \frac{7x^2}{6x - 10} [/tex]

Step-by-step Explanation:

To get the quotient, which is the result of

What we get by dividing the above, we would turn the divisor upside down, while the division sign would change to multiplication. This rule applied is known as "multiplying by the reciprocal".

[tex] \frac{7x^2}{2x + 6} [/tex] ÷ [tex] \frac{3x - 5}{x + 3} [/tex]

[tex] \frac{7x^2}{2x + 6} * \frac{x + 3}{3x - 5} [/tex] => multiplying by the reciprocal.

[tex] \frac{7x^2}{2(x + 3)} * \frac{x + 3}{3x - 5} [/tex]

[tex] \frac{7x^2}{2} * \frac{1}{3x - 5} [/tex] => (x + 3) cancels (x + 3)

[tex] \frac{7x^2(1)}{2(3x - 5)} [/tex]

[tex] \frac{7x^2}{6x - 10} [/tex]

Quotient = [tex] \frac{7x^2}{6x - 10} [/tex]

Answer: A

Step-by-step explanation:

Answer:

x = -7

Step-by-step explanation:

5x+8=3x-6

Subtract 3x from each side

5x-3x+8=3x-3x-6

2x+8 = -6

Subtract 8 from each side

2x+8-8 = -6-8

2x = -14

Divide by 2

2x/2 = -14/2

x = -7

Answer: x= -7

Step-by-step explanation:

[tex]5x+8=3x-6[/tex]

[tex]\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}[/tex]

[tex]5x+8-8=3x-6-8[/tex]

[tex]5x=3x-14[/tex]

[tex]\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}[/tex]

[tex]5x-3x=3x-14-3x[/tex]

[tex]2x=-14[/tex]

[tex]\mathrm{Divide\:2\:\:on\:\:both\:sides\:}[/tex]

[tex]-14/2=-7[/tex]

[tex]x=-7[/tex]

Answer:

y= 0.15x - 1, y = x, y = x + 100, y = 15x + 5.

Step-by-step explanation:

When the slope of a line is less than 1 (if the slope is a decimal), the slope will not be steep. But when the slope is more than 1, the slope will be steeper than the average.

According to that rule, the steepest will be y = 15x + 5.

The next steepest equations will be y = x and y = x + 100 (they are both at the same degree of steepness; the intercept does not impact the steepness of the line).

The least steepest will bey = 0.15x - 1.

So, the order, from least steep to most steep, will be y= 0.15x - 1, y = x, y = x + 100, y = 15x + 5.

Hope this helps!

Answer:

iv, ii, i, iii, vi, v

Step-by-step explanation:

First, it is better if you fix all of these into fractions:

2/3--> 0.6666

-4/5--> -0.8

7/4--> 1.75

-21/8--> -2.625

11/4--> 2.75

root 5--> 2.24...

Hope this helps!!

Answer:

The answer is option 2.