[tex]\{(x,y) | \ \ x+y = c, \ c \in \mathbb{R}\}[/tex]
Explanation:
The notation for choice A basically says "we have a line of the form x+y = c where c is a real number". Then points on the line in the form (x,y) will form a particular partition. A partition is where we break a set up into non-overlapping subsets and there are no gaps. Think of it like breaking up a house into multiple rooms. Each room is a subset of the house. There are no gaps or overlaps (ignore the regions in the walls).
Take note that if a point is on a line like x+y = 5, then it cannot be on any other line of the form x+y = c, where c is not equal to 5. Something like (x,y) = (2,3) is on x+y = 5 and not on any other line. If c is allowed to be any real number, then x+y = c will be able to partition the real numbers.
Put another way, we can pick any real number we want (aka the number c) and break it down into a sum of x and y values. Such a sum cannot yield any other c value. So going back to the house/room analogy, any particular (x,y) ordered pair will belong to one and only one room.
Let's look at an example of a non-answer. Choice B is not correct because it is perfectly possible to have circles intersect. Intersecting circles share at least one common point. Those common points are what break the idea of partitions. This idea also means choice C is false as well.
Choice D can be ruled out because the notation should be (x,y) in R2 and not simply R.
The collections of subsets of the plane, R2 is (a) {{x,y) : x + y = c} : c ∈ R}
What is a subset ?If X is a subset of Y then all the elements of A also contained in B.
According to the given statement we have o determine which of the following collections of subsets of the plane R2.
R2 defines a two dimension plane.
x+y = c where c is a real number.
Then points on the line in the form (x,y) will form a particular partition. A partition is where we break a set up into non-overlapping subsets and there are no gaps. Think of it like breaking up a house into multiple rooms. Each room is a subset of the house.
Take note that if a point is on a line like x+y = 7, then it cannot be on any other line of the form x+y = c, where c is not equal to 7. Something like (x,y) = (3,4) is on x+y = 7 and not on any other line.
B. Is not correct because it is perfectly possible to have circles intersect. Intersecting circles share at least one common point. Those common points are what break the idea of partitions.
C. is false as well
D. Is ruled out because the notation should be (x,y) in R2 and not simply R.
Learn more abouts subsets and planes here :
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Problem 2
Find the area of each shaded region. Show or explain your reasoning.
A
2 cm
B
2 cm
2cm
6 cm
5 cm
3 cm
6 cm
8 cm
C С
D
15 cm
8 cm
8 cm
15 cm
9 cm
6 cm
10 cm
Step-by-step explanation:
A
this is the combination of a 4×6 rectangle and a 2×2 square. nothing is excluded.
so, the area is
(6-2)×6 + 2×2 = 4×6 + 4 = 24 + 4 = 28 cm²
B
this is the area of the large 8×5 rectangle minus the area of the small 2×3 rectangle.
so the area is
8×5 - 3×2 = 40 - 6 = 34 cm²
C
Basically the same thing as for B. large rectangle minus smaller rectangle.
so, the area is
15×10 - 9×6 = 150 - 54 = 96 cm²
D
the area of a triangle is
baseline × height / 2
or baseline here is 2×8, and the height is 5
so we get the area
2×8 × 5 / 2 = 8×5 = 40 cm²
Anyone’s knows how do this and the answer?
Answer:
12 -16. 19
4. 8. 22
3. -9. -4
Step-by-step explanation:
13-1 = 12
-10-6= -16
12 - -7 = 12+7=19
6-2 = 4
Keep subtracting
Solve for x
ax+bx=10
Answer:
[tex]ax + bx = 10 \\ \\ x(a + b) = 10 \\ \\ x = \frac{10}{a + b} [/tex]
I hope I helped you^_^
Name the two input device
Answer:
keyboard and mouse are two examples of input device
Answer:
keyboard and mouse
Step-by-step explanation:
If you like my answer than please mark me brainliest
y=3x+2y is it a function how do you do it
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Answer:
yes
Step-by-step explanation:
Solve for y. You can do this by subtracting 3x+y from both sides of the equation.
y -(3x+y) = 3x +2y -(3x +y)
-3x = y
Or ...
y = -3x
Each value of x maps to a single value of y, so this relation is a function.
_____
This equation is a first-degree polynomial in x. Any polynomial relation y=p(x) is a function, so this is a function.
The area of a circle is 78.5 cm^2. What is the diameter of the circle?
-5 cm
-10 cm
-12.5 cm
-39.25 cm
Answer:
10cm
Step-by-step explanation:
78,5=pi.r^2
Answer5:
Step-by-step explanation:
[tex]\lim_{n \to \0}(x/(tan(x))^(cot(x)^2 )[/tex]
It looks like the limit you want to compute is
[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]
Rewrite the limand with an exponential and logarithm:
[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]
Now, since the exponential function is continuous at 0, we can write
[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]
Let M denote the remaining limit.
We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:
[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]
Simplify and rewrite this in terms of sin and cos :
[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]
As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:
[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]
Recall the double angle identity for sin:
sin(2x) = 2 sin(x) cos(x)
Also, in the numerator we have
cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)
So we can simplify M as
[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]
This again yields 0/0. Apply L'Hopital's rule again:
[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]
Once again, this gives 0/0. Apply L'Hopital's rule one last time:
[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]
Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with
[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]
Then the original limit is
[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]
Find the midpoint of the segment with the given endpoints. (-7,-4) and (3,7)?
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Answer:
(-2, 1.5)
Step-by-step explanation:
The coordinates of the midpoint are the average of the end point coordinates:
((-7, -4) +(3, 7))/2 = (-7+3, -4+7)/2 = (-4, 3)/2 = (-2, 1.5)
The coordinates of the midpoint are (-2, 1.5).
4 adults consumed food costing $60 for 3days. For the same food cost ,what would be the cost of food consumed by 7 adults for 5days?
Answer:
$175
Step-by-step explanation:
$60÷3÷4 =5
$5 is the cost of one adult's food for one day.
$5×7×5
=$175
$175 is the cost of food consumed by 7 adults for 5 days.
3/6, 1/12, 3/6, 3/60 determine the lcd by division of prime number
Answer:
LCD = 60
BRAINLIEST, PLEASE!
Step-by-step explanation:
All of the denominator numbers are multiples of 60, and since 60 is also equal to the largest denominator number, it's the LCD.
The sum of twice a number and three
Answer:
i dont get what youre asking
Step-by-step explanation:
Answer:
2n + 3
Step-by-step explanation:
n = number
Sum of twice a number (2n) and (3)
-> 2n + 3
find the value of a and b in (a,2)=(2,b)
Answer:
a=2 and b=2...............
3cm and 7cm
please help me find the area and the perimeter of the above figures using the formular
Its must be a rectangle
Length=3cmBreadth=7cmPerimeter:-
[tex]\\ \sf\longmapsto 2(L+B)[/tex]
[tex]\\ \sf\longmapsto 2(3+7)[/tex]
[tex]\\ \sf\longmapsto 2(10)[/tex]
[tex]\\ \sf\longmapsto 20cm[/tex]
Area:-
[tex]\\ \sf\longmapsto Length\times Breadth[/tex]
[tex]\\ \sf\longmapsto 3(7)[/tex]
[tex]\\ \sf\longmapsto 21cm^2[/tex]
Answer:
Length=3cm
breadth=7cm
Area(A)=?
we know that,
Area of rectangle (A)=l*b
=3cm*7cm
= 21cm^2
Now,
Perimeter (P)= 2(l+b)
=2(3cm+7cm)
=2*10cm
=20cm Ans.
derivative : y=[(1+x^2)arctgx-x]/2
Answer:
s,-8*2-`±_'682-¥´owhsi
Need answers in 2 minutes ASAP
Step-by-step explanation:
f(10)=10
f(-2)=-2
f(a)=a
f(a+b)=a+b
g(10)=5×10-12=3
g(-2)=5×(-2)-12=-10-12=-22
g(a)=5×a-12=5a-12
g(a+b)=5×(a+b)-12=5a+5b-12
h(10)=(10)^2 +4(10)-7=100+40-7=133
h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11
h(a)=a^2 +4a -7
h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7
log base 4 (x+3)²- log base 4 y² = 0
Answer:
x = - |y| - 3
Step-by-step explanation:
Write a two-step equation and solve.
Four more than six times a number is 22
Five less than eleven times a number is 50
Seven less than nine times a number is -16
Step-by-step explanation:
1) let number=a
six times a number=6a
Condition:
6a+4=22
2) eleven times a number=11a
Condition:
11a-5=50
3) 9 times a number=9a
Condition:
9a-7=-16
Note:if you need to ask any question please let me know.
7. What's the perimeter of a rectangle with length 12 m and width 5 m?
A. 60 m
B. 49 m
C. 34 m
D. 17 m
Answer:
Option(c) 34m
Step-by-step explanation:
Perimeter of a rectangle = 2(length + breadth)
length = 12m
breadth/width = 5m
Perimeter = 2(12 + 5)
= 2(17)
= 34m
Answer:
34
you just add, 12+5+12+5 to get 34
A triangle has a perimeter of 75 inches. Find the length of three sides
if one side is 15 inches larger than the smallest side, and the third
side is twice the smallest
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Answer:
15 in, 30 in, 30 in
Step-by-step explanation:
Let x represent the length of the smallest side. Then the other two sides are (x+15) and (2x). The perimeter is the sum of the side lengths:
x +(x +15) +2x = 75
4x = 60
x = 15 . . . . . . . . . . . shortest side
(x+15) = 30 . . . . . . second side
(2x) = 30 . . . . . . . third side
The shortest side is 15 inches, the second side is 30 inches, and the third side is 30 inches.
Select the correct answer.
Based on these segment lengths, which group of segments cannot form a triangle?
OA 12,7,8
OB. 8, 7, 13
OC. 1,2,3
OD. 80,140, 70
Reset
Next
2021 EdimentumAll rights
Answer:
C
Step-by-step explanation:
If you add up the length of two sides, the sum must be greater than the third side of the triangle.
If you add 1 and 2, it equals 3
But that means it will be equal to the length of the third side, 3
It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.
It's sort of difficult to explain this without any visual
You can look up "triangle inequality" to find out more about this
19. When the members of a high school club are
arranged in rows of 2, 3, or 4, there is one
person always left over. But when the club
members are arranged in rows of 5, no one is
left over. What is the least number of people
who could be in the club?
À 15 people
C 45 people
B 25 people D 85 people
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Answer:
B. 25 people
Step-by-step explanation:
The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.
The least number of people who could be in the club is 2·12+1 = 25.
After writing a $400 check to pay a bill, a student had a balance of $550 in his account. How much did he have in the account before he wrote the check?
a) Let x= his balance before writing the check. Write the equation you would use to solve this problem.
Answer:
x=950
Step-by-step explanation:
550+400=x
Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, is steady for a while, and then goes down over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins in the middle of the vertical axis, goes down at first, is steady for a while, and then goes up over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, goes down for a while, and then is steady over time.
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Answer:
A
Step-by-step explanation:
If you read your own question, you find that it answers itself.
The problem statement tells you that speed ...
... increasing its speed, constant speed, then decreases
And it tells you the graphs show ...
(a) begins at 0, goes up, is steady for a while, and then goes down
(b) begins in the middle, goes down, is steady, and then goes up
(c) begins at 0, goes up, goes down, and then is steady
___
The first graph has the increasing, steady, decreasing pattern you're looking for.
Solve the below:
4x+3y=7 3x-2y=9
Determine the sum by suitable re arrangement .
a) 6254 + 1297 + 446 + 103 Ans:
b) 1983 + 647 + 217 + 353 2.
Answer:
a.8100
b.3200
Step-by-step explanation:
hope you're okay
express 3x-x^2 as m-(x-n)^2. Ill give brainliest to correct answer!
(Also please see the picture since you might mistake x having a square as a 2x)
This is simply done by Method of Completing the Square.
3x - x²
Add and subtract half the coefficient of x and square it.
( This is done so there'd be no alterations to the quadractic Expression)
So To start
We'd like x² to be positive...(So factor out a negative).
–(x² - 3x )
Now In this case
You see there's a Negative Outside the the bracket
Instead of adding and Subtracting squared values of half the coefficient of X... We'd Add Twice and do not subtract.
Reason: If you add outside the bracket and subtract the other inside the bracket... This will be wrong because there's a negative patiently waiting outside the bracket to Interact with the negative you subtracted to make it Positive.
See what I mean.
Let's say you added 2² and subtracted 2² in this problem
2² – ( x² - 3x - 2²)
If you decide to open the bracket
You'll have
2² – x² + 3x + 2²
NOW THIS IS WRONG BECAUSE WE ALTERED THIS EXPRESSION. WHERE'D 2² + 2² COME FROM?
THIS IS WHY YOU'LL ADD THE SQUARED COEFFICIENT OF X TWICE IN CASES LIKE THESE.
SO GOING BACK TO THE ORIGINAL QUESTION.
– (x² - 3x )
Adding the half the coefficient of x twice and squaring them...
Coefficient of x = 3
Half of 3 = 3/2
Squaring it gives (3/2)²
NOW PROCEEDING
(3/2)² – [ x² - 3x + (3/2)²]
If you open this bracket... (3/2)² will cancel out with —(3/2)²
Meaning that we haven't altered the expression in any way
Moving On...
Applying basic factorizing principle
9/4 – ( x - 3/2)².
Answer = 9/4 – ( x - 3/2)² Which is in the Form m – ( x - n )²
Therefore m = 9/4 and n = 3/2.
Hope This Helps
The Earth scientist most likely to study volcanoes is a (n)
A. Meteorologist
B. Geologist
C. Oceanographer
D. Astronomer
The answer is B Geologist
Answer:
geologist
Step-by-step explanation:
they work with the earths surface and natural land that changes
divide write your answer in simplest form 2/3 divided by 1/4
Answer:
8/3 or 2.6667
Step-by-step explanation:
when you divide fractions you use a technique called KCF
K = keep
C = change
F = flip
You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]
you keep [tex]\frac{2}{3}[/tex]
you change the symbol, so from ÷ you change it to x
and flip the last fraction, so you would have [tex]\frac{4}{1}[/tex]
then you solve it
[tex]\frac{2}{3}[/tex] x [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]
The result of 2/3 divided by 1/4 in simplest form is 8/3 .
Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.
Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].
Division of fractional terms:
[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]
Apply, division process of fractional terms.
[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]
[tex]= \frac{8}{3}[/tex]
Know more about division,
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QUESTION 1 11 How does the term quartile relate to how data values are grouped when using a five- number summory?
On solving equation 3*1/5b+5=50, the value of b will be?
Answer:
Step-by-step explanation:
14 1⁄16