Answer:
Operating systems and web browsers
Explanation:
i did the test
Answer:
c
Explanation:
What is a promotional activity for a film?
Answer:
Sometimes called the press junket or film junket, film promotion generally includes press releases, advertising campaigns, merchandising, franchising, media and interviews with the key people involved with the making of the film, like actors and directors.
Explanation:
Consider a banking system with ten accounts. Funds may be transferred between two of those accounts by following these steps:
lock A(i); lock A(j);
Update A(i); Update A(j);
Unlock A(i); Unlock A(j);
Required:
a. Can this system become deadlocked? If yes, show how. If no, explain why not?
b. Could the numbering request policy (presented in the chapter discussion about detection) be implemented to prevent deadlock if the number of accounts is dynamic? Explain why or why not?
Answer:
qegfds
Explanation:
What allows you to create a wireless connection among your smart devices.
Answer:
Probably Wi-Fi or a network but if you need more specific i'm not sure
Explanation:
Based on MLA guidelines, what is the correct line spacing?
O Double space
O Single space
O 1.5 lines
According to the Modern Language Association (MLA) guidelines, the correct line spacing for a document is double-spacing. This means that there should be a full blank line between each line of text in the document. Hence, option A is the correct answer.
Double spacing helps improve readability and makes it easier for readers to distinguish between different lines of text. It also allows for better legibility and makes it easier to add annotations or comments to the document.
It's important to note that the MLA guidelines may change over time, so it's always a good idea to consult the most recent edition of the MLA Handbook or check with your instructor or institution for any specific requirements regarding line spacing or formatting.
Hence, option A is the correct answer.
Learn more about MLA here:
brainly.com/question/32131813
#SPJ6
There are 12 inches in a foot and 3 feet in a yard. Create a class named InchConversion. Its main() method accepts a value in inches from a user at the keyboard, and in turn passes the entered value to two methods. One converts the value from inches to feet, and the other converts the same value from inches to yards. Each method displays the results with appropriate explanation.
Answer:
import java.util.Scanner;
public class InchConversion
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter inches: ");
double inches = input.nextDouble();
inchesToFeet(inches);
inchesToYards(inches);
}
public static void inchesToFeet(double inches){
double feet = inches / 12;
System.out.println(inches + " inches = " + feet + " feet");
}
public static void inchesToYards(double inches){
double yards = inches / 36;
System.out.println(inches + " inches = " + yards + " yards");
}
}
Explanation:
In the inchesToFeet() method that takes one parameter, inches:
Convert the inches to feet using the conversion rate, divide inches by 12
Print the feet
In the inchesToYards() method that takes one parameter, inches:
Convert the inches to yards using the conversion rate, divide inches by 36
Print the yards
In the main:
Ask the user to enter the inches
Call the inchesToFeet() and inchesToYards() methods passing the inches as parameter for each method
This program is to ask the user N number of math (using only +, -, *, and /) questions. Once the program start it asks the user to enter how many questions will be asked (N, which is between 3-10). Then, the program asks N questions to the user. Each question will be one of four math operations (+, -, *, and /). The operation and operands will be selected randomly in your program.Operand are "unsigned short" between 0 and 100. After N questions, program exits by showing success score (number of correct / number of all questions).
------Sample Run------
Enter number of questions I need to ask: 5
1) 3 + 4 = 6
Incorrect, 7 was the answer.
1) 8 - 4 = 4
Correct
1) 5 * 6= 30
Correct
1) 5 - 345= -300
Incorrect, it should be -340.
1) 0-0=0
Correct
Your success rate is 60%.
Answer:
Written in Python
import random
N = int(input("Enter number of questions I need to ask: "))
if N >2 and N < 11:
signs = ['+', '-', '*', '/']
correct = 0
for i in range(1,N+1):
num1 = random.randint(1,101)
num2 = random.randint(1,101)
sign = random.choice(signs)
print(str(i)+":) "+str(num1)+" "+sign+" "+str(num2)+" = ")
res = int(input(""))
if sign == '+':
result = num1 + num2
elif sign == '-':
result = num1 - num2
elif sign == '*':
result = num1 * num2
elif sign == '/':
result = num1 / num2
if result == res:
correct = correct + 1
print("Your success rate is "+str(round(correct * 100/N))+"%")
Explanation:
I've added the source program as an attachment where I used comments to explain difficult lines
Please help on a timer!!
Answer:
I believe it is the Second Option as all the others are correct.
Write a function that takes two integer lists (not necessarily sorted) and returns true precisely when the first list is a sublist of the second.
The first list may appear anywhere within the second, but its elements must appear contiguously.
HINT: You should define and test a helper function that you can use in sublist.
Answer:
The function written in Python is as follows:
def checksublist(lista,listb):
if(all(elem in lista for elem in listb)):
print("The first list is a sub list of the second list.")
else:
print("The first list is not a sub list of the second list.")
Explanation:
This line defines the function
def checksublist(lista,listb):
The following if condition checks if list1 is a subset of list2
if(all(elem in lista for elem in listb)):
print("The first list is a sub list of the second list.")
The following else statement is executed if the above if statement is not true
else:
print("The first list is not a sub list of the second list.")
The function that takes two integer lists (not necessarily sorted) and returns true precisely when the first list is a sub list of the second is as follows:
def check_sublist(x, y):
if(set(x).issubset(set(y))):
return "The first list is a sublist of the second"
else:
return "The first list is not a sublist of the second"
print(check_sublist([2, 3, 5], [1, 2, 3, 4, 5, 6, 7]))
The code is written is python.
Code explanation:A function is declared called check_sublist. The function accept two parameters namely x and y.if the parameter x is a subset of y then the it will return "The first list is a sublist of the second"Else it will return "The first list is not a sublist of the second"Finally, we use the print statement to call our function with the required parameter.learn more on python code here; https://brainly.com/question/25797503?referrer=searchResults
You're a short-order cook in a pancake restaurant, so you need to cook pancakes as fast as possible. You have one pan that can fit capacity pancakes at a time. Using this pan you must cook pamCakes pancakes. Each pancake must be cooked for five minutes on each side, and once a pancake starts cooking on a side it has to cook for five minutes on that side. However, you can take a pancake out of the pan when you're ready to flip it after five minutes and put it back in the pan later to cook it on the other side. Write the method, minutes Needed, that returns the shortest time needed to cook numCakes pancakes in a pan that holds capacity pancakes at once.
Answer:
Explanation:
The shortest time needed means that we are not taking into account the amount of time it takes to switch pancakes, flip them, or take them out of the pan, etc. Only cooking them. Therefore, written in Java would be the following...
public static int minutesNeeded (int numCakes, int panCapacity) {
int minutesNeededtoCook = 0;
while (numCakes != 0) {
if (numCakes > panCapacity) {
numCakes -= panCapacity;
minutesNeededtoCook += 10;
} else {
numCakes = 0;
minutesNeededtoCook += 10;
}
}
return minutesNeededtoCook;
}
The code takes in the amount of pancakes and the pan capacity, then compares them and adds 10 minutes (5 on each side) per pancake batch that is being made until all the pancakes are made.
Cam needs to turn her Turtle to the right 50 pixels. Which line of code should Cam use? O tom(50) O tom. turtle(50) Otom. forward(fifty) O tom.right(50) WILL MARK BRAINEST
Answer:
I believe it is D
Explanation:
Answer:
Its D
Explanation:
explain working principle of computer?
Answer:
The working principle of the computer system. Computers do the work primarily in the machine and we can not see, a control center that converts the information data input to output. This control center, called the central processing unit (CPU), How Computers Work is a very complex system.
Explanation:
Which of the following statements BEST describe why Agile is winning?
Answer:
nunya
Explanation:
A non-abstract class that implements an interface: __________
a. can use any constants defined by the interface
b. must provide an implementation for each abstract method
c. defined by the interface must inherit the interface
d. all of the above
e. a and b only
Answer:
b
Explanation:
because i think i go with my gut
ILL MARK BRAINEST.
What must a new object have in Turtle Graphics? O Export O Name Title O Rank
Answer:
Name
Explanation:
Answer:
name
Explanation:
brain
Serveral cheetas are growling at each other while hunting for animals.for which need are they competing?
Answer:
prey
Explanation:
Answer:
food plis let me now if am wrong
Explanation:
Which of the following section does not exist in a slide layout?
A. Titles
B. Lists
C. Charts
D Animations
Answer:
D
Explanation:
Question 7 of 10
When is it more professional not to send a business email?
O A. When a number of people should be included.
B. When the content is highly sensitive or emotional.
O C. When a written record is needed.
D. As a cover letter for an attachment
Answer:
B. When the content is highly sensitive or emotional
Explanation:
B. When the content is highly sensitive or emotional.
Shut down and unplug the computer. Remove the CPU case lid. Locate the various fans, and then use compressed air to blow dirt out through the internal slits from inside the case.
✔ cleaning the fan
Save files to an external storage device to aid in file recovery.
✔ backup
This process allows you to permanently delete files you no longer need.
✔ cleaning out unneeded files
This mini program may be an unwanted application.
✔ widget
Remove programs you accidentally downloaded when you purchased an e-book.
✔ removing unwanted applications
This application scans, locates, and makes needed repairs on the hard drive.
✔ checking the hard drive for errors
I DID THIS CAUSE TI COULDNT FIND THE ANSWERS SO I WANTED TO HELP ANYONE WHO NEEDS THIS
the answers are:
- cleaning the fan
- backup
- cleaning out unneeded files
- widget
- removing unwanted applications
- checking the hard drive for errors
fill in the blanks to save a file in Paint used...... key combination
Next, copy in your strip_punctuation function and define a function called get_pos which takes one parameter, a string which represents one or more sentences, and calculates how many words in the string are considered positive words. Use the list, positive_words to determine what words will count as positive. The function should return a positive integer - how many occurrences there are of positive words in the text. Note that all of the words in positive_words are lower cased, so you’ll need to convert all the words in the input string to lower case as well.
punctuation_chars = ["", ","," 3 # list of positive words to use 4 positive_words = 0 5 with open ("positive_words.txt") as pos_f: for lin in pos_f: if lin[0] != ';' and lin[0] != '\n': positive_words.append(lin.strip) 6 7 8 9 10
Answer:
Here is the get_pos function:
def get_post(string): #function that takes string as parameter
string=string.lower() #converts the string to lower case
string=strip_punctuation(string) #calls strip_punctuation to remove punctuation from string
string=string.split() #split the string into a list
count_positive=0 #counts the occurrences of positive words
for word in string: #loops through the string
if word in positive_words: #if a word in a string is a positive words
count_positive=count_positive+1 #adds 1 to the count of count_positive each time a positive word appears
return count_positive #returns the positive integer - how many occurrences there are of positive words in the string
Explanation:
In order to explain the working of this function lets suppose the punctuation_chars list contains the following punctuation characters:
punctuation_chars = ["'", '"', ",", ".", "!", ":","?", ";", '#']
Lets suppose the positive_words.txt file contains the following two words i.e. yes okay
Lets suppose the string is Hi! I am okay, see you later.
string = " Hi! I am okay, see you later. "
string=string.lower() statement converts the string to lower case:
string = hi! i am okay, see you later.
string=strip_punctuation(string) this statement calls strip_punctuation method to remove the punctuation from string.
string = hi i am okay see you later
string=string.split() this statement splits the sentence into list
['hi', 'i', 'am', 'okay', 'see', 'you', 'later']
for word in string: this loop iterates through the string
At first iteration if condition checks if word "hi" is in positive_words. This is not true because positive_words only contain the words okay and yes.
At next iteration if condition checks if word "i" is in positive_words. This is not true because positive_words only contain the words okay and yes.
At next iteration if condition checks if word "am" is in positive_words. This is also not true.
At next iteration if condition checks if word "okay" is in positive_words. This is true because positive_words contains the words okay. So count_positive=count_positive+1 statement executes which adds 1 to the count of count_positive so
count_positive = 1
At next iteration if condition if word in positive_words checks if word "see" is in positive_words. This is not true.
At next iteration if condition checks if word "you" is in positive_words. This is also not true.
At next iteration if condition checks if word "later" is in positive_words. This is also not true.
Now the statement: return count_positive returns the occurrence of positive words in the string which is 1. So the output of this is 1.
Here is the strip_punctuation method:
def strip_punctuation(word): #removes punctuation from words
New_word="" #initializes new word string to empty
print("Word is: ",word) #prints the word
for w in word: #iterates through words
if w not in punctuation_chars: #if word is not in punctuation_char list
New_word=New_word+w #adds that word to new word string
return New_word #returns word after removing punctuation
Let A, B, and C, and D be the following statements:
A The villain is French.
B The hero is American.
C The heroine is British.
D The movie is good.
Translate the following compound statements into symbolic notation.
a. The hero is American and the movie is good.
b. Athough the villain is French, the movie is good.
c. If the movie is good, then either the hero is American or the heroine is British.
d. The hero is not American, but the villain is French.
e. A British heroine is a necessary condition for the movie to be good.
what tha hell is that my bad i try lol im so dumb it is what it is
true false the table can have only one primary key
Microsoft
is one of the world's most popular operating systems.
Answer:
The answer is "Cooperation
"
Explanation:
Answer:
Microsoft Windows is one of the world most popular operating system
. answer is windows please mark me brain list
What is the shortcut for inserting fraction in word?(except insert equation)
Answer:
\frac is the shortcut for inserting fraction in ms-word
e.g of a/b = \frac {a}{b}
Write a Java program that will 1. Ask the user to type in a sentence, using a JOptionPane.showInputDialog(). 2. The program will examine each letter in the string and count how many time the upper-case letter 'E' appears, and how many times the lower-case letter 'e' appears. The key here is to use the charAt method in class String. 3. Using a JOptionPane.showMessageDialog(), tell the user how many upper and lower case e's were in the string. 4. Repeat this process until the user types the word "Stop". (Check out the method equalsIgnoreCase in class String to cover all upper/lower case possibilities of the word "STOP").
Please provide a code for this in JAVA.
Answer:
Here is the JAVA program :
import javax.swing.JOptionPane; //to use JOptionPane
public class Main { //class name
public static void main(String[] args) { //start of main method
int ECount= 0; //counts number of upper case E
int eCount= 0; //counts number of lower case e
String sentence; //stores input sentence string
sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit)"); //uses showInputDialog method to display a dialog box which prompts user to enter a sentence
int length = sentence.length(); //stores the length of the sentence
while (!sentence.equalsIgnoreCase("stop")) //the loop continues to execute until the user types stop
{ for (int i = 0; i < length; i++) { //loops through the sentence
if (sentence.charAt(i) == 'E') //if the character is an uppercase E
ECount += 1; //adds 1 to the count of Ecount
if (sentence.charAt(i) == 'e') //if the character in a sentence is lowercase e
eCount += 1;} //adds 1 to the count of lower case e
JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + " number of e's in " +sentence); //displays the number of times uppercase and lowercase (E and e) occur in sentence
sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit"); //prompts user to enter the next sentence
length = sentence.length(); //stores the length of sentence at each iteration of while loop until user enters stop
eCount=0; //resets the counter of lowercase e
ECount=0; } } } //resets the counter of uppercase e
Explanation:
The program uses showInputDialog() method that displays a dialog box on output screen. This dialog box prompts the user to enter a string (sentence) Suppose user enters "Evergreen" as input sentence so
sentence = "Evergreen"
Next the length of this string is computed using length() method and stored in length variable. So
length = sentence.length();
length = 9
The for loop iterates through this input sentence until the variable i is less than length i.e. 9
At first iteration
if (sentence.charAt(i) == 'E') becomes
if (sentence.charAt(0) == 'E')
Here charAt() method is used which returns the character at the specified index i. This if condition is true because the character at 0-th index (first character) of the sentence Evergreen is E. So ECount += 1; statement adds 1 to the count of upper case E so
ECount = 1
At second iteration:
if (sentence.charAt(1) == 'E')
this condition is false because the character at 1st index of sentence is 'v' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is also false because the character is not a lower case e either.
At third iteration:
if (sentence.charAt(2) == 'E')
this condition is false because the character at 2nd index of sentence is 'e' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is true because the character is a lower case e. So the statement eCount += 1; executes which adds 1 to the count of e.
eCount = 1
So at each iteration the sentence is checked for an upper case E and lower case e. After the loop breaks, the program moves to the statement:
JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + " number of e's in " +sentence);
which displays the number of uppercase E and lower case e in a message dialog box. So the output is:
There are 1 number of E's and 3 number of e's in Evergreen.
Then because of while loop user is prompted again to enter a sentence until the user enters "stop". Now the user can enter Stop, StOp, STOp etc. So equalsIgnoreCase method is used to cover all upper/lower case possibilities of the word "stop".
The screenshot of the program and its output is attached.
How do I give brainliest (I’m new) .Actually answer my question!
Answer: I’m sorry, but what is your question? Then, I may be able to help you. Also, add a link (image)!
Explanation: Thank You!
Answer:
Hi! There has to be two answers to your question. That is the only way you are able to give a brainliest. You can give a brainliest if you believe a person who wrote an answer to your question fully detailed and organized. It has to answer your question.
Hope this helps! :D
As you apply to college when should you apply for financial aid
Answer:
after you are accepted in the college
Explanation:
You should apply for admission to the colleges you are interested in BEFORE filing your FAFSA. Once you are accepted to the colleges you have applied to, you can add those schools to receive financial aid award offers from when you file your FAFSA.
What are sums of money that are given out for specific reasons?
conventional loans
grants
venture capitals
angel fundings
Answer:
B. grants
Explanation: This is the correct answer on Edge 2021, just did the assignment. Hope this helps ^-^.
Joe just joined a new team at his marketing firm, which has been working on a campaign ad for the new Elmo doll. Everyone in the group has children except for Joe, and thus they are familiar with the doll. Joe has never seen an Elmo doll before. How should he deal with the situation?
Answer: ask someone to show or explain the doll to him
Explanation:
edmentum
Answer: ask someone to show or explain the doll to him
Explanation:
If Joe asks his teammates to show or explain the doll to him, he too can contribute ideas for the successful completion of the project.
Raw facts, or ____
are the input for a computer process.
O data
O software
O output
O peripherals