Answer:
Let the number be x
The statement
A number is increased by five is written as
x + 5
Then it's squared
So we the final answer as
(x + 5)²Hope this helps
Find two numbers with difference 62 and whose product is a minimum.
Answer:
31 and -31
Step-by-step explanation:
The two numbers with a difference of 62 and whose product is a minimum are; 31 and -31
Let the two numbers be x and y.We are told that their difference is 62.
Thus; x - y = 62 ---(1)
We want their products to be minimum. Thus;f(x,y) = xy
From eq, making y the subject gives us;
y = x - 62
Thus;
f(x) = x(x - 62)
f(x) = x² - 62x
For the product to be minimum, let us find the derivative of f(x) and equate to zero. Thus;f'(x) = 2x - 62
At f'(x) = 0
2x - 62 = 0
2x = 62
x = 62/2
x = 31
Thus;
y = 31 - 62
y = -31
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Which graph represents the equation?
Answer:
The bottom left
Step-by-step explanation:
the -4 tells you the y intercept and the 1/3 tells you slope
hope this helps!
1
?
x + 5and
Which line is parallel to the line y =
passes through the point (-2, 1)?
x+
O y=x+3
1
y =
+2
1
y =
4
*-
oy-
1
-X
y=-2
Answer:
second option
Step-by-step explanation:
Parallel lines have the same slope, and since the slope of the given line is 1/2, we know the slope of the answer will be 1/2, which eliminates the first and last options. We know the slope and a point that belongs to the line, (-2, 1), so we can use point-slope formula to derive the equation of the line.
y - 1 = 1/2(x + 2)
y - 1 = 1/2x + 1
y = 1/2x + 2
What is the domain of a function in this table? X 1,2,3,4 Y 2,4,3,2
Answer:
Domain {1,2,3,4}
Step-by-step explanation:
The domain is the values for the input, in this case it is the x values
Domain {1,2,3,4}
Customers can pick their own pumpkins at the great pumpkin patch. They pay $4 to enter and $3 per pound for the pumpkins they pick. Write an equitation to model the total cost, y, for x pounds of pumpkins.
Answer:
y=3x+4
Step-by-step explanation:
4 is the y intercept and 3 is the slope which is how much per pound. The equation you can use is y=mx+b, m is the slope so you fill it in with 3 and b is the y intercept so you fill it in with 4.
express 11011 in base two
Answer:
27
Step-by-step explanation:
Hello,
11011 in base 2 is
1 * 16 + 1 * 8 + 0 * 4 + 1 * 2 + 1 in base 10
which is 16 +8+2+1=27
Do not hesitate if you have any question
Esibu and Dela are in a part-time business manufacturing clock case. Esibu must work 4 hours and Dela 2 hours to complete one case for a grandmother clock. To build one case for a wall clock, Esibu must work 3 hours and Dela 4 hours. Neither partners wish to work more than 20 hours per week. If they receive GHC80.00 for each grandmother clock and GHC64.00 for each wall clock, how many of each should they build each week to maximize their profit?
Answer:
Correct Answer:
To maximize their profit, Esibu must build 6 (2 grandmother clock and 4 wall clock) while Dela must build 8 (6 grandmother clock and 2 wall clock).
Step-by-step explanation:
Since they don't want to work for more than 20 hrs in a week
In-order to maximize the profit,
For Esibu,
2 grandmother clock = 4 hours ×2 = 8 hours
4 wall clock = 3 hours × 4 = 12 hours
Total hours = 20 hours.
For Dela,
6 grandmother clock = 2 hours × 6 = 12 hours
2 wall clock = 4 hours × 2 = 8 hours
Total hours = 20 hours.
6(a+2b+3c) USE THE DISTRIBUTIVE PROPERTY TO CREATE AN EQUIVALENT EXPRESSION!!!!!!!!
Answer:
6a + 12b + 18c
Step-by-step explanation:
To solve, we distribute the 6 to all of the terms inside the parentheses.
[tex]6*a\\6*2b\\6*3c\\6a+12b+18c[/tex]
Our answer is 6a + 12b + 18c. Hope this helps!
Vocabulary:
Distribute: Give shares of something. In math: Divide / give to each term (in this case)
Answer:
6a+12b+18c
Step-by-step explanation:
To create an equivalent expression, we must distribute the 6. Multiply each term inside of the parentheses by 6.
6(a+2b+3c)
(6*a)+(6*2b)+(6*3c)
6*a=6a
6a+(6*2b)+(6*3c)
6*2b=(6*2)b=12b
6a+12b+(6*3c)
6*3c=(6*3)c=18c
6a+12b+18c
The equivalent expression using the distributive property is 6a+12b+18c
If my car averages 27 miles to the gallon, how many miles can I drive on3/4 tank of gas
Answer:
20.25 miles
Step-by-step explanation:
If your car travels 27 miles on a full tank of gas, then your car will travel [tex]27\cdot\frac{3}{4}[/tex] miles on [tex]\frac{3}{4}[/tex] tank of gas.
[tex]27 \cdot 0.75 = 20.25[/tex]
I hope this helped!
What is the equation of the circle show in the image?
Use all the information below to find the missing x-value for the point that is on this line. m = - 1 / 3 b = 7 ( x, 4 )
Answer:
[tex]\boxed{x = 9}[/tex]
Step-by-step explanation:
m = -1/3
b = 7
And y = 4 (Given)
Putting all of the givens in [tex]y = mx+b[/tex] to solve for x
=> 4 = (-1/3) x + 7
Subtracting 7 to both sides
=> 4-7 = (-1/3) x
=> -3 = (-1/3) x
Multiplying both sides by -3
=> -3 * -3 = x
=> 9 = x
OR
=> x = 9
Answer:
x = 9
Step-by-step explanation:
m = -1/3
b = 7
Using slope-intercept form:
y = mx + b
m is slope, b is y-intercept.
y = -1/3x + 7
Solve for x:
Plug y as 4
4 = 1/3x + 7
Subtract 7 on both sides.
-3 = -1/3x
Multiply both sides by -3.
9 = x
Complete the point-slope equation of the line through (3,-8) (6,-4)
Answer:
y + 4 = 4/3(x - 6).
Step-by-step explanation:
The point-slope formula is shown below. We just need to find the slope.
(-4 - (-8)) / (6 - 3) = (-4 + 8) / 3 = 4 / 3
m = 4/3, y1 = -4, and x1 = 6.
y - (-4) = 4/3(x - 6)
y + 4 = 4/3(x - 6).
Hope this helps!
a food snack manufacturer samples 9 bags of pretzels off the assembly line and weights their contents. If the sample mean is 14.2 oz. and teh sample devision is 0.70 oz, find the 95% confidense interval of the true mean
Answer:
13.7≤[tex]\mu[/tex]≤14.7Step-by-step explanation:
The formula for calculating the confidence interval is expressed as shown;
CI = xbar ± Z(б/√n)
xbar is the sample mean
Z is the value at 95% confidence interval
б is the standard deviation of the sample
n is the number of samples
Given xbar = 14.2, Z at 95% CI = 1.96, б = 0.70 and n = 9
Substituting this values into the formula;
CI = 14.2 ± 1.96(0.70/√9)
CI = 14.2 ± 1.96(0.70/3)
CI = 14.2 ± 1.96(0.2333)
CI = 14.2 ± 0.4573
CI = (14.2-0.4573, 14.2+0.4573)
CI = (13.7427, 14.6537)
Hence, the 95% confidence interval of the true mean is within the range
13.7≤[tex]\mu[/tex]≤14.7 (to 1 decimal place).
As soluções da equação 2X² - 7 = 7 (x-1) + 2x são:
{A) x= 2 ou x= 7}
{B) x= 0 ou x= 2}
{C) x= 0 ou x= 9}
{D) x= 2 ou x= -7/2}
{E) x= 0 ou x= 9/2}
Answer:
E) x= 0 or x= 9/2
Step-by-step explanation:
You have the following equation:
[tex]2x^2-7=7(x-1)+2x[/tex] (1)
In order to find the solutions for x of the equation (1), you simplify it and factorize in a convenient way, as follow:
[tex]2x^2-7=7x-7+2x\\\\2x^2-9x=0\\\\x(2x-9)=0[/tex] (2)
Then, by the previous factors, it is necessary that either x=0 or 2x-9 = 0.
Thus, one of the solution is x=0. The other solution is:
[tex]2x-9=0\\\\x=\frac{9}{2}[/tex]
Hence, the solutions of the equation (1) are:
E) x= 0 or x= 9/2
Crime and Punishment: In a study of pleas and prison sentences, it is found that 45% of the subjects studied were sent to prison. Among those sent to prison, 40% chose to plead guilty. Among those not sent to prison, 55% chose to plead guilty.
(A) If one of the study subjects is randomly selected, find the probability of getting someone who was not sent to prison.
(B) If a study subject is randomly selected and it is then found that the subject entered a guilty plea, find the probability that this person was not sent to prison.
Answer:
(a) The probability of getting someone who was not sent to prison is 0.55.
(b) If a study subject is randomly selected and it is then found that the subject entered a guilty plea, the probability that this person was not sent to prison is 0.63.
Step-by-step explanation:
We are given that in a study of pleas and prison sentences, it is found that 45% of the subjects studied were sent to prison. Among those sent to prison, 40% chose to plead guilty. Among those not sent to prison, 55% chose to plead guilty.
Let the probability that subjects studied were sent to prison = P(A) = 0.45
Let G = event that subject chose to plead guilty
So, the probability that the subjects chose to plead guilty given that they were sent to prison = P(G/A) = 0.40
and the probability that the subjects chose to plead guilty given that they were not sent to prison = P(G/A') = 0.55
(a) The probability of getting someone who was not sent to prison = 1 - Probability of getting someone who was sent to prison
P(A') = 1 - P(A)
= 1 - 0.45 = 0.55
(b) If a study subject is randomly selected and it is then found that the subject entered a guilty plea, the probability that this person was not sent to prison is given by = P(A'/G)
We will use Bayes' Theorem here to calculate the above probability;
P(A'/G) = [tex]\frac{P(A') \times P(G/A')}{P(A') \times P(G/A') +P(A) \times P(G/A)}[/tex]
= [tex]\frac{0.55 \times 0.55}{0.55\times 0.55 +0.45 \times 0.40}[/tex]
= [tex]\frac{0.3025}{0.4825}[/tex]
= 0.63
In the diagram, line a is the perpendicular bisector of KM. Line a is a perpendicular bisector of line segment K M. It intersects line segment K M at point L. Line a also contains point N. Line segment K L is 6 x + 4. Line segment K N is 9 x minus 5. Line segment N M is 7 x + 7. What is the length of KM? 22 units 40 units 44 units 80 units
Answer:
D. 80 :)
Step-by-step explanation:
The solution is : The value of segment LM is 9x + 5.
What is an angle?In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.
here, we have,
Consider the image below.
A perpendicular bisector is a line segment that bisects another line segment into two equal parts and is perpendicular to this line segment.
So from the diagram below we know:
KL = LM
line a is ⊥ to KM
∠NLK = 90°
Since the angle measure of ∠NKL is not provided we cannot determine the value of x.
So, the value of segment LM is 9x + 5.
To learn more on angle click:
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Complete question:
Line a is a perpendicular bisector of line segment K M. It intersects line segment K M at point L. Line a also contains point N. Line segment K L is 9 x +5. Line segment K N is 14 x minus 3. What is the length of segment LM? units
What point lies on the line described by the equation below? Y+3=2 (x-1
Answer:
[tex]\boxed{(1, -3)}[/tex]
Step-by-step explanation:
[tex]y+3=2 (x-1)[/tex]
Put equation in slope-intercept form.
[tex]y=mx+b[/tex]
[tex]y=2(x-1)-3[/tex]
[tex]y=2x-2-3[/tex]
[tex]y=2x-5[/tex]
Let x = 1
[tex]y=2(1)-5[/tex]
[tex]y=2-5[/tex]
[tex]y=-3[/tex]
The point (1, -3) lies on the line.
convert the equation y= -4x + 2/3 into general form equation and find t the values of A,B and C.
Answer:
Standard form: [tex]12x+3y-2=0[/tex]
A = 12, B = 3 and C = -2
Step-by-step explanation:
Given:
The equation:
[tex]y= -4x + \dfrac{2}3[/tex]
To find:
The standard form of given equation and find A, B and C.
Solution:
First of all, let us write the standard form of an equation.
Standard form of an equation is represented as:
[tex]Ax+By+C=0[/tex]
A is the coefficient of x and can be positive or negative.
B is the coefficient of y and can be positive or negative.
C can also be positive or negative.
Now, let us consider the given equation:
[tex]y= -4x + \dfrac{2}3[/tex]
Multiplying the whole equation with 3 first:
[tex]3 \times y= 3 \times -4x + 3 \times \dfrac{2}3\\\Rightarrow 3y=-12x+2[/tex]
Now, let us take all the terms on one side:
[tex]\Rightarrow 3y+12x-2=0\\\Rightarrow 12x+3y-2=0[/tex]
Now, let us compare with [tex]Ax+By+C=0[/tex].
So, A = 12, B = 3 and C = -2
Which of the following is the solution to 4|x+2|≥16
Answer:
x ≥ 2 or x ≤ -6
Step-by-step explanation:
4|x + 2| ≥ 16
|x + 2| ≥ 4
x + 2 ≥ 4 or -(x + 2) ≥ 4
x ≥ 2 or x + 2 ≤ -4 → x ≤ -6
[tex]\text{Solve the absolute value}\\\\4|x+2|\geq 16\\\\\text{We can make this equation a lot simpler by dividing both sides by 4}\\\\|x+2|\geq4\\\\\text{According to the absolute value, there can be two outcomes. In this case,}\\\text{it would be either:}\\\\x+2\geq4\,\,or\,\,x+2\leq-4\\\\\text{Solve first outcome:}\\\\x+2\geq4\\\\\text{Subtract both sides by 2}\\\\x\geq2\\\\\text{Solve second outcome:}\\\\x+2\leq-4\\\\\text{Subtract 2 from both sides}\\\\x\leq-6\\\\[/tex]
[tex]\boxed{x\geq2\,\,or\,\,x\leq-6}[/tex]
A regression analysis involved 8 independent variables and 99 observations. The critical value of t for testing the significance of each of the independent variable's coefficients will have a. 7 degrees of freedom. b. 90 degrees of freedom. c. 97 degrees of freedom. d. 98 degrees of freedom.
Answer:
Option b = 90 degrees of freedom.
Step-by-step explanation:
So, in this particular Question we are given the following parameters or data or information which is going allow us to be able to solve this particular problem or Question;
=> "A regression analysis involved 8 independent variables"
=> "99 observations. "
Requirement : to determine the critical value of t for testing the significance of each of the independent variable's coefficient.
Hence, the formula below will used in Calculating or in the determination of the degree of freedom;
Degree of freedom= total number of observations - number of independent variables- 1.
Thus, slotting bin the values into the formula above, we have;
The degree of freedom = 99 - 8 - 1 = 90.
rationalize root six divided by root three minus root two. [tex]\frac{\sqrt{6} }{\sqrt{3}-\sqrt{2} }[/tex]
Answer:
the answer is
[tex]3 \sqrt{2} + 2 \sqrt{3} [/tex]
Step-by-step explanation:
the explanation is given in the image.
Answer:
[tex]\huge\boxed{\dfrac{\sqrt6}{\sqrt3-\sqrt2}=3\sqrt2+2\sqrt3}[/tex]
Step-by-step explanation:
[tex]\dfrac{\sqrt6}{\sqrt3-\sqrt2}\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\\\\\dfrac{\sqrt6}{\sqrt3-\sqrt2}\cdot\dfrac{\sqrt3+\sqrt2}{\sqrt3+\sqrt2}=\dfrac{\sqrt6(\sqrt3+\sqrt2)}{(\sqrt3-\sqrt2)(\sqrt3+\sqrt2)}=\dfrac{(\sqrt6)(\sqrt3)+(\sqrt6)(\sqrt2)}{(\sqrt3)^2-(\sqrt2)^2}[/tex]
[tex]\text{use}\ \sqrt{a}\cdot\sqrt{b}=\sqrt{ab}\ \text{and}\ (\sqrt{a})^2=a[/tex]
[tex]=\dfrac{\sqrt{(6)(3)}+\sqrt{(6)(2)}}{3-2}=\dfrac{\sqrt{18}+\sqrt{12}}{1}=\sqrt{9\cdot2}+\sqrt{4\cdot3}\\\\=\sqrt9\cdot\sqrt2+\sqrt4\cdot\sqrt3=3\sqrt2+2\sqrt3[/tex]
b) Representa el perímetro total del área acordonada por el polígono =3n + 5, n2 – 4, n2 – 4, 3n + 5 perímetro =
Responder:
2n² + 6n + 2Explicación paso a paso:
Dado un polígono con los siguientes lados 3n + 5, n² - 4, n² - 4 y 3n + 5, el perímetro del polígono dado será equivalente a la suma de todos los lados del polígono. Como el polígono está formado por 4 lados, el perímetro de la forma será;
P = s₁ + s₂ + s₃ + s₄
P = (3n + 5) + (n² - 4) + (n² - 4) + (3n + 5)
P = 3n + 5 + n² - 4 + n² - 4 + 3n + 5
Recolectando los términos similares;
P = n² + n² + 3n + 3n + 5 + 5-4-4
P = 2n² + 6n + 10-8
P = 2n² + 6n + 2
Por lo tanto, el perímetro del polígono es 2n² + 6n + 2
x^2-y^2=3y in polar form
Answer:
Step-by-step explanation:
put x=r cos θ
y=r sin θ
r²cos²θ-r²sin²θ=3rsin θ
r²(cos²θ -sin²θ)=3r sin θ
r²cos 2θ=3rsinθ
r cos 2θ=3 sin θ
r=3sec 2θ sin θ
an organisms population in the year 2000 was about 9 billion and was increasing with a double time of 20 years. Suppose the population continued this growth pattern from the year 2000 into the future. Complete part a through d
Answer:
For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:
[tex]18 =9(b)^20[/tex]
And if we solve for b we got:
[tex] 2 = b^20[/tex]
[tex]2^{1/20}= b[/tex]
And then the model would be:
[tex] y(t) = 9 (2)^{\frac{t}{20}}[/tex]
Where y is on billions and t the time in years since 2000.
And for this equation is possible to find the population any year after 2000
Step-by-step explanation:
For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:
[tex]18 =9(b)^20[/tex]
And if we solve for b we got:
[tex] 2 = b^20[/tex]
[tex]2^{1/20}= b[/tex]
And then the model would be:
[tex] y(t) = 9 (2)^{\frac{t}{20}}[/tex]
Where y is on billions and t the time in years since 2000.
And for this equation is possible to find the population any year after 2000
i got 11 first but im not too sure cause sometimes it will ask me it's wrong Use the integers that are closest to the number in the middle.
Answer:
11 < √137 < 12
Step-by-step explanation:
the closest squares are 121 and 144; 11² and 12²
Write the point slope equation of the line with the given slope that passes through the given point
M= -3, (3,5)
Answer:
y - 5 = -3(x - 3).
Step-by-step explanation:
The point-slope form is y - y1 = m(x - x1).
In this case, y1 = 5, x1 = 3, and m = -3.
y - 5 = -3(x - 3).
Hope this helps!
Answer:
[tex]\boxed{y-5= -3(x-3)}[/tex]
Step-by-step explanation:
Point-slope is in the general form:
[tex]y-y_1 = m(x-x_1)[/tex]
The values are given.
[tex]m=-3\\x_1=3\\y_1=5[/tex]
Plug in the values,
[tex]y-5= -3(x-3)[/tex]
Who knows how to do this
Answer:
144 [tex] {cm}^{2} [/tex]Step-by-step explanation:
Given,
As we know that the all sides of the square are equal.
Length of a square paper = 12 cm
Area of square = ?
Now, let's find the area of square
[tex] = {l}^{2} [/tex]
plugging the value of length,
[tex] {(12)}^{2} [/tex]
Evaluate the power
[tex] = 144[/tex] square cm
Hope this helps...
Best regards!!
4. Considera la función f(x) = 2*. Determina la función g(x) que se obtiene al trasladar
f(x)
a.tres unidades a la izquierda y dos unidades hacia arriba
b. cinco unidades a la derecha y cuatro unidades hacia abajo
Answer:
a. [tex]g(x)=f(x+3)+2[/tex]
b. [tex]g(x)=f(x-5)-4[/tex]
Step-by-step explanation:
Como f(x) no está especificada correctamente, vamos a tratarla genéricamente.
Las transformaciones que se proponen son traslaciones en el eje x y en el eje y.
Cuando se traslada'la función en el eje x, la variable independiente se reemplaza por una variable auxiliar u que es equivalente a la variable original x mas el valor desplazado hacia la izquierda.
Cuando se traslada la función en el eje y, simplemente se suma una constante a la función con un valor equivalente a las unidades que la función se traslado hacia arriba (si es hacia abajo, este valor es negativo).
Entonces, para trasladar f(x) 3 unidades a la izquierda u 2 unidades hacia arriba, empezamos por reemplazar la variable independiente por u=x+3 y luego agregar una constante igual a 2:
[tex]g(x)=f(x+3)+2[/tex]
Si queremos trasladar f(x) 5 unidades a la derecha y 4 unidades hacia abajo, empezamos por reemplazar la variable independiente por u=x-5 y luego agregar una constante igual a -4:
[tex]g(x)=f(x-5)-4[/tex]
En la figura se puede ver un ejemplo de la transformación para f(x)=x^2.
Each character in a password is either a digit [0-9] or lowercase letter [a-z]. How many valid passwords are there with the given restriction(s)? Length is 13. No character repeats.
Answer:
2310789600
Step-by-step explanation:
10 digits + 26 letters = 36
₃₆C₁₃ = 2310789600
Hope this helps, although i am not 100 percent sure its right.
Una masa de 16 libras viaja con una velocidad de 30 m/s . Cuál es su energía cinética?
Energía cinética = 1 / 2mv²
Donde m es la masa y v es la velocidad
De la pregunta
la masa es de 16 libras
la velocidad es de 30 m / s
16 libras es equivalente a 7.257 kg
Entonces la energía cinética es
1/2(7.257)(30)²
Que es 3265.65 juliosEspero que esto te ayude