Answer:
it will most likely be the free energy
In the free-body diagram, the magnitude of the normal force is 40 N, the friction force is
25N, the net force is 80N: What is the magnitude of the applied force?
Answer:
Explanation:
F = 80 + 25 = 105 N
A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.
By Newton's second law, the net vertical force on the block is
∑ F = N - mg = 0
so that the normal force exerted by the surface has magnitude
N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N
Then as the block slides over the surface, it feels a frictional force of
f = µ (24.7 N)
where µ is the coefficient of kinetic friction.
As the block is pushed by the spring to its equilibrium position, friction performs
µ (-24.7 N) (0.0973 m) = -2.40µ J
of work (which is negative because it opposes the block's motion).
In compressing the spring by 9.73 cm = 0.0973 m, we store
1/2 (116 N/m) (0.0973 m)² = 0.549 J
of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.
By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:
W = ∆K
0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0
where v is the speed of the block at the equilibrium position. Solving for v, we get
v = 0.891 √(0.549 - 2.40µ) m/s
After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs
µ (-24.7 N) (0.537 m) = -13.3µ J
of work.
Using the work-energy theorem again, we have
W = ∆K
-13.3µ J = 0 - 1/2 (2.52 kg) v ²
Substitute the velocity we found in terms of µ, and solve for µ :
-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²
===> µ = 0.0350
How much force (in Newtons) is needed to accelerate a 160 kg object at a rate of 4 m/s2?
A. 15
B. 40
C. 640
D. .025
Answer:
C. 640
Explanation:
The minimum force would occur in a frictionless environment and act parallel to any abutting surface.
F = ma = 160(4) = 640 N
Please help on these two thanks
Explanation:
Number 29
= 10 N (from rocket) + 10 N (from wheels) - 7 N (from parachute 'cause force in other direction)
= 20 N - 7 N
= 13 N ✔
Number 30
= 100 N - 85 N
= 15 N to the left ✔
If a person weighs 160 Newtons on Earth, what is their weight in pounds on Earth?
A. 27
B. 36
C. 712
D. 534
Answer:
B. 36 lb
Explanation:
m = 160/9.8 = 16.3 kg
16.3 kg ( 2.205 lb/kg) = 36 lb
When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulum’s motion at that point?
it tells you that it has a lot of force
Answer:
Since I couldn't find the other answers to the same question, I wrote the wrong answer to help ya'll get the sample response. So here's from Edge
Explanation:
Sample Response: If KE = 0, the pendulum is not moving. At the top of the swing, the pendulum must stop for a brief moment.
The Sun's primary energy source is
Answer:
nuclear fusion
Explanation:
converting hydrogen to helium.
Which is not poor conductor?
a) pure water
b) Cotton thread
c) plastic spoon
d) metal vase
Answer:
Metal vase
Explanation:
Pure water is not a good conductor, and neither is plastic or cotton. Metal is the only one of the four that actually is a good conductor. For example, lighting hitting metal, this happens because the lightning connects to anything that has some kind of conductant.
If the tension in the string is equal to 2 W when the stone is at its lowest point, then the tension when the stone is at the highest point will be
This question involves the concept of tension, centripetal force, centrifugal force, and weight.
The tension of the stone at the highest point is "0 N".
The centrifugal force always acts away from the circle. The tension always acts toward the support that is the center of the circle in this case. When the stone is at its lowest point, the centrifugal force, and the weight of the stone, both act downward. But the tension is pointing in the upward direction. Hence, the equilibrium equation will be:
[tex]Tension = Weight\ + \ Cenrifugal\ Force\\T = W + F_c\\T = 2\ W\ (given)\\2\ W = W+F_c\\F_c = 2\ W - W\\F_c = W[/tex]
Now, we consider the stone at the top position. Here, the centrifugal force will act in the upward direction (away from the center of the circle), while the weight and tension will be acting in the downward direction. Thus, the equilibrium equation, in this case, will be:
[tex]F_c = W+T\\T=F_c-W\\T = W-W\\[/tex]
T = 0 N
Learn more about tension here:
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The attached picture shows the free body diagram of the stone at different locations.
Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation
We have that the balanced chemical equation is mathematically given as.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2O
From the question we are told
Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation.
Generally the way to balance an equation is by making all elements present on the Left hand side(LHS) same with the right hand side RHS.
Therefore
The equation is mathematically given as.
Ti_3N + MgO → Mg_3N_2 +Ti_2OWe consider the Left hand side(LHS) first.
2Ti_3N + 3MgO → Mg_3N_2 +Ti_2OThen we consider the right hand side RHS.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2OTherefore the balanced chemical equation is mathematically given as.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2OFor more information on this visit
https://brainly.com/question/17756498
A student practicing for a track meet ran 3500 m in 500 s. What was her average speed? a. 4,000 m/s b. 0.14 m/s c. 7 m/s d. 1,750, 000 m/s
Answer:
c. 7 m/s
Explanation:
3500 m / 500 s = 7 m/s
the density of free electron in a copper conductor is 8.5×10^28m-3. how long does an electron take to dift from one end of a wire 3.0m long to it's other end?
Answer:
missing information what is your cross-section and current in Amperes
What force prevents a machine from having 100% efficiency? A. Magnetic B. Electric O C. Friction O D. Gravity
Answer:
I believe it would be C ? my apologies if I'm wrong.
A train travels meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its
acceleration is
O 0 m/s
6 m/s
O 12 m/s/s
18 m/s
O None of the above
Answer:
0 m/sExplanation:
there is no acceleration, it's velocity is always 6m/s
so your answer is 0m/s
DUE IN AN HOUR! HELP!!
A charged ball has a charge of -3.5x10-17c . How many electrons are found in the ball?
Answer:
218 electrons
Explanation:
pls find the attached image for solution
the weight on each foot of an elephant 500n. what will be the contact force
Answer:
The weight of an object is the force it exerts due to gravity. Pressure is force per unit area, or force divided by area over which the pressure is exerted.
Explanation:
1. For Jo:
1. For Jo:force = 500 N
1. For Jo:force = 500 Narea = 0.0001 m^2
1. For Jo:force = 500 Narea = 0.0001 m^2pressure = F/A = 500N/0.0001m^2 = 5,000,000 N/m^2
Which area of study involves how mechanics and motion affect sports performance?
1.) Momentum. 2.) Velocity. 3.) Biomechanics. 4. )Centripetal force.
Answer:
biomechanics
Explanation:
Biomechanics is part of the larger field of kinesiology, specifically focusing on the mechanics of the movement. 1 It is both a basic and applied science, encompassing research and practical use of its findings.
A heavy train of mass 200 tonnes has a maximum speed of 20m/s up a hill inclined at 1.15⁰ to the horizontal when the engine is working at 800 kwatts. What is the resistance to the motion of the train?
Answer:
https://www.brainlyanswer.com
Explanation:
click the link the answer is in the link:)
Answer:
train to busan
shadow train
the horror train
train game
5. Sarah is standing 32.0 m away from Jason. If Sarah throws a snowball at a 45 degree
angle for maximum distance, what velocity must the snowball have to hit Jason directly.
(Assume Jason and Sarah are about the same height so that if she throws the snowball
from head level, it will hit Jason in the head.)
Answer:
Explanation:
If air resistance is ignored and assume UP and Toward Jason are the positive directions.
horizontal analysis
d = (vx₀)t
t = d/vx₀
horizontal analysis
0 = vy₀t + ½gt²
0 = vy₀(d/vx₀)+ ½g(d/vx₀)²
as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.
0 = d + ½g(d²/v₀²cos²45)
-d = ½g(d²/v₀²cos²45)
-dv₀² = ½g(d²/cos²45)
v₀² = -½g(d/cos²45)
v₀² = -½(-9.81(32.0/cos²45)
v₀² = 313.92
v₀ = 17.717787...
v₀ = 17.7 m/s
In the absence of air resistance, as an object falls freely, its
O velocity increases
O acceleration increases
both A and B
O none of the above
Answer:
None of the above
Explanation:
None of the above
HELP me please !!!!
at 30°c an almunium spher is 30cm³ long
the cofficen linear expansion is 24×10`⁶ if the final volume is 30.5cm³
what's the final temperatur of the almunium sphere
Answer:
Change volume / volume = .5 / 30 = .01666
coefficient of volume expansion = 3 * 24E-6 = 72E-6
Change in temp = .0167 / 24E-6 = 232 deg C
Final temp = 232 + 30 = 262 deg C
Change in volume / volume = 3 * coeff linear expansion * change in deg C
Someone pls help I don’t understand this
Answer:
[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]
Explanation:
• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".
plz help owo
What characteristic is shared by sunspots, solar flares, and coronal mass ejections? Select the two correct responses.
They are caused by outward fluctuations of the sun's magnetic field.
They appear as dark spots on the sun's surface.
They tend to occur during active periods of the solar cycle.
They appear as bright spots on the sun's surface.
Answer:
They are caused by outward fluctuations of the sun's magnetic field.
They tend to occur during active periods of the solar cycle.
Explanation:
While sun spots will appear darker than the surrounding surface, flares will tend to appear brighter. CME's are associated with massive flares.
The two correct responses are as follows:
They are caused by outward fluctuations of the sun's magnetic field.They tend to occur during active periods of the solar cycle.The following information should be considered:
At the time when sunspots should appear darker as compared to the surrounding surface, so flares should be appear brighter. CME's are along with massive flares.Due to this, the above answers are considered.Learn more: brainly.com/question/16911495
Two skaters face one another and stand motionless, then push against each other on the ice. If one's mass is 55 kg and he moves to the left after the push at a velocity of 4.3 m/s, how fast was the other skater traveling after the push if her mass was 48 kg.
Answer:
3.75 m/s
Explanation:
55/4.3 = 48/x
12.8 = 48/x
x = 48 : 12.8
x = 3.75 m/s
#LearnWithEXO
CARRY ON LEARNING
CAN YOU BRAINLEST ME PLEASE
What happens if hair has static electricity
Answer:
it goes up
Explanation:
Help ,I wanna know if this is correct or not
Answer:
it looks correct to me but im not 11% sure
Explanation:
The weight of an object is 180 N at a distance of 150 km above a planet's center. What is the weight of the object when it moves 450 km above the center of the planet?
By using Newton law of gravitation, the weight of the object when it moves 450 km above the center of the planet is 20N
Given that the weight of an object is 180 N at a distance of 150 km above a planet's center.
F = GMm/[tex]r^{2}[/tex]
F = mg = 180N
r = 150
When it moves 450 km above the center of the planet, G, M and m will be constant. only r will vary.
180 = GMm/[tex]150^{2}[/tex]
Make GMm the subject of the formula
GMm = 180 x 22500
GMm = 4050000
As it moves 450 km above the center of the planet, Its weight will be
F = GMm/[tex]r^{2}[/tex]
Substitute all the values and parameters
F = 4050000/[tex]450^{2}[/tex]
F = 20 N
Therefore, the weight of the object When it moves 450 km above the center of the planet is 20 Newtons
Learn more here: https://brainly.com/question/22412075
Chọn câu sai :
A. Đồ thị vận tốc theo thời gian chuyển động thẳng đều là một đường song song với trục hoành Ot
B. Trong chuyển động thẳng đều ,đồ thị theo thời gian của tọa độ và của vận tốc đều là những đường thẳng
C. Đồ thị toạ độ theo thời gian của chuyển động thẳng đều bao giờ cũng là một đường thẳng
D. Đồ thị toạ độ theo thời gian của chuyển động thẳng đều là một đường thẳng xiên góc
P.s this language is: Viatnamese :)
Answer:
This is just to help the other readers help you. Or so that you understand:
Đây là để giúp bạn đọc giúp bạn!
What they tried to say:
Choose the wrong sentence:
A. The velocity-time graph of uniform linear motion is a line parallel to the horizontal axis Ot
B. In uniform linear motion, the time graphs of the coordinates and of the velocity are both straight lines
C. The time-coordinate graph of uniform rectilinear motion is always a straight line
D. The coordinate-time graph of uniform linear motion is an oblique line
Is what they asked you.
Thankyou and your welcome
Vì tôi đã giúp đỡ, tôi có thể vui lòng có cám ơn nào không?
Have a great day!
~Happy helper~
You are driving to grandma's house, and you are traveling at an average of 70 mph. How long will it take you to travel 70 miles?
O 1 hour
O 1 second
70 hours
O 70 seconds
Answer: 1 hour
Explanation: Focus on the units; 70 miles per hour means that each hour, you will travel 70 miles
or you can use the equation time = distance/speed. You have 70miles/ 70mph = 1hour