Answer:
[tex]c =\sqrt{a^{2}+b^{2} }[/tex]
Step-by-step explanation:
You clear c, wich is the hypotenuse
[tex]c =\sqrt{a^{2}+b^{2} }[/tex]
Solve the following: (1 point) x + 3y = 9 3x − 3y = −13
Answer:
Step-by-step explanation:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
Point Form:
(
−
1
,
10
3
)
Equation Form:
x
=
−
1
,
y
=
10
3
Tap to view steps...
image of graph
Tap to hide graph...
40 points 1. Write a two-column proof for the following conjecture. You may not need to use all of the rows of the two-column table provided below. You may also add additional rows if needed. Given: Prove: and are supplementary. and are supplementary. Answer: Statement Reason 1. 1. 2. 2. 3. 3. 4. 4. 5. 5. 6. 6. 7. 7.
Answer:
Step-by-step explanation:
by looking at the given image...
the shape ABCD is a parallelogram.
Required:
is to prove ∡A and ∡B are supplementary
and ∡C and ∡D are supplementary.
so, m∠A + m∠B = 180°
and m∠C + m∠D = 180°
the Statement
1. ABCD is a parallelogram
the reason is..
It is Given!
the Statement
2.m∠A=m∠C and m∠B=m∠D
the reason is..
Definition of parallelogram.
the Statement
3.m∠A+m∠B+m∠C+m∠D=360°
the reason is..
Definition of quadrilateral
the Statement
4. m∠A+m∠B+m∠A+m∠B=360°
the reason is..
By substitution
⇒ 2( m∠A + m∠B ) = 360°
⇒ m∠A + m∠B = 180°
it is also similar m∠C + m∠D = 180°
the Statement
5.∠A and ∠C are supplementary
the reason is..
by the definition of Supplementary ∠ B and ∠D are supplementary
Hope it helps!
Answer:
see below
Step-by-step explanation:
by looking at the given image...
the shape ABCD is a parallelogram.
Required:
is to prove ∡A and ∡B are supplementary
and ∡C and ∡D are supplementary.
so, m∠A + m∠B = 180°
and m∠C + m∠D = 180°
the Statement
1. ABCD is a parallelogram
the reason is..
It is Given!
the Statement
2.m∠A=m∠C and m∠B=m∠D
the reason is..
Definition of parallelogram.
the Statement
3.m∠A+m∠B+m∠C+m∠D=360°
the reason is..
Definition of quadrilateral
the Statement
4. m∠A+m∠B+m∠A+m∠B=360°
the reason is..
By substitution
⇒ 2( m∠A + m∠B ) = 360°
⇒ m∠A + m∠B = 180°
it is also similar m∠C + m∠D = 180°
the Statement
5.∠A and ∠C are supplementary
the reason is..
by the definition of Supplementary ∠ B and ∠D are supplementary
Hope it helps!
4 1/3 b+b=6b–10.4 efvnabvkjaebv
Answer: The value of b= 15.6
Step-by-step explanation:
The given equation: [tex]4\dfrac{1}{3}b+b=6b-10.4[/tex]
To find : Value of b.
Since, we can write [tex]4\dfrac{1}{3}=\dfrac{13}{3}[/tex]
So, the given equation becomes [tex]\dfrac{13}{3}b+b=6b-10.4[/tex]
[tex]\Rightarrow\dfrac{13b+3b}{3}=6b-10.4\Rightarrow\dfrac{16b}{3}=6b-10.4[/tex]
Subtract 6b from both sides , we get
[tex]\Rightarrow\dfrac{16b}{3}=6b-10.4\\\\\Rightarrow\dfrac{16b-18b}{3}=-10.4\\\\\Rightarrow\dfrac{-2b}{3}=-10.4\\\\\Rightarrow b=-10.4\times\dfrac{-3}{2}\\\\\Rightarrow\ b= 15.6[/tex]
hence, the value of b= 15.6
Use special right triangles to solve for the exact value of x. 4 16 9
Answer:
16
Step-by-step explanation:
I took the test and that's the answer.
Answer:
16
Step-by-step explanation:
CHECK THE ATTACHMENT FOR THE FIQURE OF THE QUESTION;
✓The given figure is a special right triangle and it's a 30° 60° 90° angle.
The length of its side have the ratio of
1: √3: 2 i.e adjacent, opposite, Hypotenuse
✓ it has an Hypotenuse which is double in value to the adjacent.
✓ the adjacent ( shortest sides) = 8 unit,
Then the Hypotenuse= ( 2×8)= 16 units
There are 4 pieces of paper, numbered 10 to 13, in a hat. After another numbered piece of paper is added, the probability of picking a number between 10 and 13 inclusive is 4/5. Which of the following numbers could
Answer: The fifth piece of paper could have any number 9 and less or 14 and greater.
Step-by-step explanation: The list of choices is not given in the question, but it makes sense that the new number would not be a duplicate of any of the numbers 10, 11, 12, 13. Otherwise that would change the probability to 5/5.
So any other number could be a possibility.
Complete the solution of the equation. Find the
value of y when x equals 13.
-3x – 2y = -25
Enter the correct answer.
Answer:
y = -7
Step-by-step explanation:
-3x – 2y = -25
Let x = 13
-3 * 13 -2y = -25
-39 -2y = -25
Add 39 to each side
-39+39 -2y = -25+39
-2y =14
Divide by -2
-2y/-2 = 14/-2
y = -7
Answer:
y = -7
Step-by-step explanation:
-3x - 2y = -25
Plug x as 13.
-3(13) - 2y = -25
-39 - 2y = -25
Add 39 on both sides,
- 2y = 14
Divide both sides by -2.
y = -7
a pile of steel plates is 2.75 feet high. if the plates are 0.375 inch thick. how many are there in the pile.
Answer:
88
Step-by-step explanation:
2.75 ft = (2.75 ft)(12 in/ft) = 33 in
At 0.375 inches per plate, there will be ...
(33 in)/(0.375 in/plate) = 88 plates
There are 88 steel plates in the pile.
Simplify the expression 53 × 5-5.
Answer:
260
Step-by-step explanation:
By PEMDAS, we know multiplican comes first. 53*5=265. Then, subtract 5 to get 260.
If you want additional help with math or another subject for FREE, check out growthinyouth.org.
Answer:
260
Step-by-step explanation:
the rule is to start with multiplication first 53*5=265 then subtract 5
53 × 5-5= 265-5=260
WIll mark brainliest asap
Answer:
If the number is x, we can write the following equation:
2 + 10x = 2
10x = 0 so therefore, x must be 0. There is no other number that satisfies this property.
Find the equation of the line.
Answer:
y = -2x + 5
Step-by-step explanation:
You use the equation y = mx + b, where m is the slope and b is the y-intercept. We see that the line hits the y-axis at 5, so that will be your b. To find the slope, use [tex]\frac{rise}{run}[/tex]. You have to go down 4 and right 2, so your slope will be [tex]-\frac{4}{2}[/tex] which simplifies to -2. Hope this helps!
Answer: y=2/-5x+5
Step-by-step explanation:
The quadratic 4x^2+2x-1 can be written in the form a(x+b)^2+c, where a, b, and c are constants. What is a+b+c?
Answer:
[tex]\large \boxed{\sf \ \ \ a+b+c=3 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]4x^2+2x-1=4(x^2+\dfrac{2}{4}x)-1=4[(x+\dfrac{1}{4})^2-\dfrac{1}{4^2}]-1[/tex]
As
[tex](x+\dfrac{1}{4})^2=x^2+\dfrac{2}{4}x+\dfrac{1^2}{4^2}=x^2+\dfrac{2}{4}x+\dfrac{1}{4^2} \ \ So \\\\x^2+\dfrac{2}{4}x=(x+\dfrac{1}{4})^2-\dfrac{1}{4^2}[/tex]
Let 's go back to the first equation
[tex]4x^2+2x-1=4[(x+\dfrac{1}{4})^2-\dfrac{1}{4^2}]-1=4(x+\dfrac{1}{4})^2-\dfrac{1}{4}-1\\\\=4(x+\dfrac{1}{4})^2-\dfrac{1+4}{4}=\boxed{4(x+\dfrac{1}{4})^2-\dfrac{5}{4}}[/tex]
a = 4
[tex]b=\dfrac{1}{4}\\\\c=-\dfrac{5}{4}[/tex]
[tex]a+b+c=4+\dfrac{1}{4}-\dfrac{5}{4}=\dfrac{4*4+1-5}{4}=\dfrac{12}{4}=3[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Find the fraction half way between 1/7 and 1/5
Answer:
6/35
Step-by-step explanation:
add ¹/7+¹/5 =12/35
divide 12/35 by 2
=6/35
specific radioactive substance follows a continuous exponential decay model. It has a half-life of hours. At the start of the experiment, is present.
Answer:
[tex] y = A_o (b)^t[/tex]
With [tex] A_o = 82.6[/tex] the initial amount and t the time on hours and t the time in hours. since the half life is 12 hours we can find the parameter of decay like this:
[tex] 41.3= 82.6(b)^{12}[/tex]
And solving for b we got:
[tex] \frac{1}{2}= b^{12}[/tex]
And then we have:
[tex] b= (\frac{1}{2})^{\frac{1}{12}}[/tex]
And the model would be given by:
[tex] y(t) = 82.6 (\frac{1}{2})^{\frac{1}{12}}[/tex]
Step-by-step explanation:
Assuming this complete question: "A specific radioactive substance follows a continuous exponential decay model. It has a half-life of 12 hours. At the start of the experiment, 82.6g is present. "
For this case we can create a model like this one:
[tex] y = A_o (b)^t[/tex]
With [tex] A_o = 82.6[/tex] the initial amount and t the time on hours and t the time in hours. since the half life is 12 hours we can find the parameter of decay like this:
[tex] 41.3= 82.6(b)^{12}[/tex]
And solving for b we got:
[tex] \frac{1}{2}= b^{12}[/tex]
And then we have:
[tex] b= (\frac{1}{2})^{\frac{1}{12}}[/tex]
And the model would be given by:
[tex] y(t) = 82.6 (\frac{1}{2})^{\frac{1}{12}}[/tex]
A ladder is leaning against a wall at an angle of 70° with the ground. The distance along the ground is 86cm. Find the length of the ladder
Answer:
[tex]\boxed{x = 251.4 cm}[/tex]
Step-by-step explanation:
Part 1: Sketching the triangle
We are given the angle of elevation, 70°, and the distance along the ground, 86 centimeters. Our unknown is a ladder leaning against the building. Buildings are erected vertically, so the unknown side length is the hypotenuse of the triangle.
We can then sketch this triangle out to visualize it (attachment).
Part 2: Determining what trigonometric ratio can solve the problem
Now, we need to refer to our three trigonometric ratios:
[tex]sin = \frac{opposite}{hypotenuse}[/tex]
[tex]cos = \frac{adjacent}{hypotenuse}[/tex]
[tex]tan = \frac{opposite}{adjacent}[/tex]
Visualizing the sketched triangle, we can assign the three sides their terms in correspondence to the known angle -- this angle cannot be the right angle because the hypotenuse is opposite of it.
Therefore, we know our unknown side length is the hypotenuse of the triangle and because the other side is bordering the 70° angle, it is the adjacent side.
By assigning the sides, we can see that we need to use the trigonometric function that utilizes both the hypotenuse and the adjacent side to find the angle. This is the cosine function.
Part 3: Solving for the unknown variable
Now that we have determined what side we need to solve for and what trigonometric function we are going to use to do so, we just need to plug it all into the equation.
The cosine function is provided: [tex]cos( \alpha) = \frac{adjacent}{hypotenuse}[/tex], where [tex]\alpha[/tex] is the angle. We just need to plug in our values and solve for our unknown side; the hypotenuse.
[tex]cos (70) = \frac{86 cm}{x}[/tex], where x is the unknown side/the hypotenuse.
[tex]x * cos (70) = \frac{86 cm}{x} * x[/tex] Multiply by x on both sides of the equation to eliminate the denominator and make the unknown easier to solve for.
[tex]\frac{xcos (70)}{cos(70)} = \frac{86 cm}{cos(70)}[/tex], Evaluate the second fraction because the first one cancels down to just the unknown, x.
[tex]\frac{86}{cos(70)} = 251.4[/tex], round to one decimal place.
Your final answer is [tex]\boxed{x=251.4cm}[/tex].
first correct answer gets best marks
Answer:
the answer would be x is less than 6.
Step-by-step explanation:
the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.
Answer:
B
Step-by-step explanation:
x≤6
We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.
Hope this helps ;) ❤❤❤
Which order of function composition would benefit Blake the most? Justify your answer. (-100 *0.9) (x) = -100 * 0.9x = -90x
Answer:
Step-by-step explanation:
(-100*0.9)(x)==-90x
Blake should first multiply the numbers in parenthesis and then multiply by x, even the answer is right but the process is wrong Blake has to follow the rule
Parenthesis , Exponent, Multiplication/Division, Addition/ Subtraction
P E M D A S
What else would need to be congruent to show that ABC = XYZ by SAS?
To show that triangle ABC is congruent to triangle XYZ by side-angle-side congruency theorem, BC must be equal to YZ (BC ≅ YZ).
What are congruent triangles?Two triangles are said to be similar if they have the same shape and the corresponding sides are congruent to each other. Also, corresponding angles are congruent.
To show that triangle ABC is congruent to triangle XYZ by side-angle-side congruency theorem, BC must be equal to YZ (BC ≅ YZ).
Find out more on similar triangles at: https://brainly.com/question/2644832
#SPJ1
In a fiftness class, there was a warm up of 14 press-ups. Anyone unable to do 14 or more recives a punishment. Jessica can do 10 press-ups without ever failing, however, the chances of her successfully doing each subsequent press-up halves. Whats the probality of her receiving a punishment? A. 1 in 8 B. 1 in 1024 C. 15 in 16 D. 1023 in 1024
Answer:
The correct option is;
C. 15 in 16
Step-by-step explanation:
The given information are;
The number of press-ups required = 14 press-ups
The number of press-ups Jessica is sure to do = 10 press-ups
The chance of Jessica doing subsequent press-ups after 10 halves each time
The consequence of not completing the 14 press-ups = Punishment
The probability that Jessica does goes on to do 11 press-ups = 1/2
The probability that Jessica does goes on to do 12 press-ups = 1/2×1/2
The probability that Jessica does goes on to do 13 press-ups = 1/2×1/2×1/2
The probability that Jessica does goes on to do (completes) 14 press-ups = 1/2×1/2×1/2×1/2 = 1/16
Therefore;
Since the probability that Jessica does not receive a punishment because she completed the 14 push-ups is 1/16, we have;
The probability that Jessica does not complete the 14 press-ups and receives a punishment = 1 - 1/16 = 15/16 which is 15 times out of 16 or 15 in 16.
A bag contains five white marbles and five black marbles. What is the probability of drawing a white marble, not replacing it, and then drawing a black marble? A. 5/9 B. 1/4 C. 5/18 D. 1/2
~ ANSWER=1/2 ~
Simple probability is found by counting all the results which fit requirements and dividing by all possible results.
To find probability of two results in a row, multiply chance of first result by chance of second result.
Since you are replacing the marble before the second draw, we don’t have to figure out the various changes in odds for the different possible first draws. It’s just that simple.
There are 5 white marbles
There are 4 red marbles
There are always 20 marbles in all
5/20*4/20=1/4*1/5=1/20 or 1/2
By coincidence, the same as the chance of drawing the white marble in one draw.
Answer:
5/18
Step-by-step explanation:
Which of the following describes the zeroes of the graph of f(x) = –x^5 + 9x^4 – 18x^3?
Answer:
second option
Step-by-step explanation:
Given
f(x) = - [tex]x^{5}[/tex] + 9[tex]x^{4}[/tex] - 18x³
To find the zeros let f(x) = 0, that is
- [tex]x^{5}[/tex] + 9[tex]x^{4}[/tex] - 18x³ = 0 ( multiply through by - 1 )
[tex]x^{5}[/tex] - 9[tex]x^{4}[/tex] + 18x³ = 0 ← factor out x³ from each term
x³ (x² - 9x + 18) = 0 ← in standard form
x³(x - 3)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x³ = 0 ⇒ x = 0 with multiplicity 3
x - 3 = 0 ⇒ x = 3 with multiplicity 1
x - 6 = 0 ⇒ x = 6 with multiplicity 1
Answer: It is B
Step-by-step explanation: Checked on a online calculator.
HELP ASAP. Please select the best answer from the choices provided.
Answer:
a.
Explanation:
In the chart, the average temperature of each month at the beginning of the year gradually rises until August, where it begins to decrease. This trend is displayed in graph a. Additionally, each month on the x-axis is shown correctly because the months should only span numbers 1-12.
Answer: the answer is A
Step-by-step explanation: hope this helps :D can u plz give a brainliest
√144² =
√9 + √16 =
√9 + √16 × √400 =
Answer:
Step-by-step explanation
√144²
12²
144
√9 + √16
3 + 4
7
√9 + √16 × √400 =
3 + 2^{4} x 5
3 + 80
83
Which is the simplified form of the expression ((2sqrt-2)(3sqrt4))sqrt-3 * ((2sqrt-3)(3sqrt2))sqrt2
Answer:
[tex]\boxed{-432\sqrt{2} i}[/tex]
Step-by-step explanation:
[tex]( 2 \sqrt{-2} )( 3 \sqrt{4} ) \sqrt{-3} \times ( 2 \sqrt{-3} )( 3 \sqrt{2} ) \sqrt{2}[/tex]
[tex]2 \times \sqrt{-2} \times 3 \times \sqrt{4} \times \sqrt{-3} \times 2 \times \sqrt{-3} \times 3 \times \sqrt{2} \times \sqrt{2}[/tex]
[tex]2 \times \sqrt{-2} \times 3 \times 2 \times \sqrt{-3} \times 2 \times \sqrt{-3} \times 3 \times 2[/tex]
[tex]2 \times \sqrt{-2} \times 3 \times 2 \times -3 \times 2 \times 3 \times 2[/tex]
[tex]-432\sqrt{2}\sqrt{-1}[/tex]
[tex]-432\sqrt{2} i[/tex]
Answer: it’s d!
Step-by-step explanation:
What is the area of this polygon?
Enter your answer in the box.
units2
Answer:
39 units²
Step-by-step explanation:
The figure is composed of a rectangle VEDR and Δ RMV
Area of rectangle = VE × ED = 5 × 6 = 30 units²
Area of Δ = 0.5 × RV × perpendicular from M to RV
= 0.5 × 6 × 3 = 9 units²
Thus
Area of polygon = 30 + 9 = 39 units²
Maya is interning at a law firm over the summer and is paid by the hour. If her hourly wage is $52, which equation represents the proportional relationship between the wages she earns (w) and the number of hours (h)?
Answer: w= 52h
Step-by-step explanation:
Given: Maya is interning at a law firm over the summer and is paid by the hour.
Her hourly pay = $52
i.e. She is paid $52 per hour.
Let the wages she earns is denoted by 'w' and the number of hours is denoted by 'h'.
Now, (Total wages earned) = (hourly pay) x (Number of hours)
w = (52) (h)
⇒ w= 52h
Hence, the equation represents the proportional relationship between the wages she earns (w) and the number of hours (h): w= 52h
Answer:52h
Step-by-step explanation: tried got it right
What is the translation from quadrilateral IJK to
quadrilateral I'J’K’
Answer:
The translation from triangle IJK to triangle I'J'K' is [tex]T_{(2, 6)}[/tex] which is 2 units to the right and 6 units up
Step-by-step explanation:
The coordinates of triangle JKI are;
J has coordinates (1, - 1)
K has coordinates (1, - 4)
I has coordinates (-3, - 2)
While, the coordinates of translation triangle J'K'I' are;
J' has coordinates (3, 5)
K' has coordinates (3, 2)
I' has coordinates (-1, 4)
Which give the translation as follows
Translation in the y-coordinate (y values);
For J = 5 - (-1) = 6
For K = 2 - (-4) = 6
For I = 4 - (-2) = 6
Translation in the x-coordinate (x values);
For J = 3 - 1 = 2
Therefore, the translation from triangle IJK to triangle I'J'K' is T(2, 6) which is 2 units to the right and 6 units up
Find the interquartile range for a data set having the five-number summary: 3.5, 12, 19.1, 25.8, 31.8
Answer:
interquartile range=21.05
Step-by-step explanation:
3.5, 12, 19.1, 25.8, 31.8
median is 19.1
Quartile 1= (3.5+12)/2=7.75
Quartile 3=(25.8+31.8)/2=28.8
interquartile range=Q3-Q1=28.8-7.75= 21.05
Given: x + 2 < -5. Choose the solution set.
Answer:
[tex] x+2-2 <-5-2[/tex]
And after operate we got:
[tex] x <-7[/tex]
And then the solution would be [tex]x<-7[/tex]
Step-by-step explanation:
For this problem we have the following inequality:
[tex] x+2 <-5[/tex]
The first step would be subtract 2 from both sides of the equation and we got:
[tex] x+2-2 <-5-2[/tex]
And after operate we got:
[tex] x <-7[/tex]
And then the solution would be [tex]x<-7[/tex]
A play school is designing two sand pits in ts play area . Each must have an area of 36 m2 . However , one of the sand pits must be rectangular , and the other must be square haped . What might be the dimensions of ach of the sand pits ?
Answer:
Dimensions of square shaped pit = 6m [tex]\times[/tex] 6m
Dimensions of rectangular pit = 1m [tex]\times[/tex] 36m or 2m [tex]\times[/tex] 18m or 3m [tex]\times[/tex] 12m or 4m [tex]\times[/tex] 9m
Step-by-step explanation:
Given:
Two pits in the school playground area (one square shaped and one rectangular shaped).
Each pit must have an area = 36 [tex]m^2[/tex]
To find:
Dimensions of each pit = ?
Solution:
First of all, let us have a look at the formula for area of a square and a rectangle:
[tex]Area_{square} = (Side)^2[/tex]
[tex]Area_{Rectangle} = Length\times Width[/tex]
Now, let us try to find out dimensions of square:
[tex]36 = Side^2\\\Rightarrow Side = 6\ m[/tex]
So, dimensions of Square will be 6m [tex]\times[/tex] 6m.
Now, let us try to find out dimensions of rectangle.
[tex]36 = Length\times Width[/tex]
We are not given any restrictions on the Length and Width of the rectangle.
So, let us explore all the possibilities by factorizing 36:
[tex]36 = 1 \times 36\\36 = 2 \times 18\\36 = 3 \times 12\\36 = 4 \times 9[/tex]
6 [tex]\times[/tex] 6 factors not considered because then it will become a square and which is not the required case.
Dimensions of rectangular pit = 1m [tex]\times[/tex] 36m or 2m [tex]\times[/tex] 18m or 3m [tex]\times[/tex] 12m or 4m [tex]\times[/tex] 9m
With steps... Thanks..
Answer:
[tex]\boxed{-25x-y}[/tex]
[tex]\boxed{-p^2q +5pq^2}[/tex]
Step-by-step explanation:
[tex](-15x+6y)-(10x+7y)[/tex]
Distribute negative sign.
[tex]-15x+6y-10x-7x[/tex]
Combine like terms.
[tex]\boxed{-25x-y}[/tex]
[tex]2pq(p+q)- (3pq(p-q))[/tex]
Expand brackets.
[tex]2p^2 q+2pq^2 -(3p^2q-3pq^2)[/tex]
Distribute negative sign.
[tex]-3p^2q+3pq^2+2p^2q+2pq^2[/tex]
Combine like terms.
[tex]\boxed{-p^2q +5pq^2}[/tex]
Answer:
a. -25x - yb. pq ( - p + 5q )Step-by-step explanation:
a.
[tex] - 15x + 6y - (10x + 7y)[/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] - 15x + 6y - 10x - 7y[/tex]
Collect like terms
[tex] - 15x - 10x + 6y - 7y[/tex]
[tex] - 25x - y[/tex]
b.
[tex]2pq(p + q) - 3pq(p - q)[/tex]
Factor out pq from the expression
[tex]pq(2(p + q) - 3(p - q))[/tex]
Distribute 2 through the parentheses
[tex]pq \: (2p + 2q - 3(p - q)[/tex]
Distribute -3 through the parentheses
[tex]pq \: (2p + 2q - 3p + 3q)[/tex]
Collect like terms
[tex]pq( - p + 5q)[/tex]
Hope this helps...
Best regards!!