Answer:
The graph will be an exponential function that crosses the y-axis at about (0, -4).
Step-by-step explanation:
[tex]g(x) = (0.5)^{x + 3} - 4[/tex]
That means that when x = 0...
[tex]g(0) = (0.5)^{0 + 3} - 4[/tex]
[tex]g(0) = (0.5)^{3} - 4[/tex]
[tex]g(0) = 0.125 - 4[/tex]
[tex]g(0) = -3.875[/tex]
So, the graph will be an exponential function that crosses the y-axis at about (0, -4).
Hope this helps!
Answer:
its a
Step-by-step explanation:
i put the equation in desmos and the graph looked exactly like a lol
bh. Find the area of the shape with the given
The area of a triangle can be found by the formula A
base (b) and height (h).
h
b
b = 5 cm and h = 3 cm
Answer:
[tex]7.5cm^2[/tex]
Step-by-step explanation:
Well using the following formula,
[tex]\frac{b*h}{2}[/tex]
5*3 = 15
15 / 2
7.5cm^2
Answer:[tex]7.5cm^{2}[/tex]
Step-by-step explanation:
h=3
b=5
area=1/2 x b x h
1/2 x 5 x 3
area=7.5
Find the mean and standard deviation for each binomial random variable:
Answer: a) Mean = [tex]=37.80[/tex]
Standard deviation=[tex]=1.9442[/tex]
b) Mean = [tex]56.00[/tex]
Standard deviation=[tex]4.0988[/tex]
c) Mean = [tex]=24[/tex]
Standard deviation=[tex]2.4495[/tex]
Step-by-step explanation:
To compute Mean and standard deviation , we use following formula:
Mean = [tex]n\pi[/tex]
Standard deviation=[tex]\sqrt{n\pi(1-\pi)}[/tex]
a. [tex]n=42,\ \pi=0.90[/tex]
Mean = [tex]42\times0.90=37.80[/tex]
Standard deviation=[tex]\sqrt{42(0.90)(0.10)}=\sqrt{3.78}\approx1.9442[/tex]
b. [tex]n=80,\ \pi=0.70[/tex]
Mean = [tex]80\times0.70=56.00[/tex]
Standard deviation=[tex]\sqrt{80(0.70)(0.30)}=\sqrt{16.8}\approx4.0988[/tex]
c. [tex]n=32,\ \pi=0.75[/tex]
Mean = [tex]32\times0.75=24[/tex]
Standard deviation=[tex]\sqrt{32(0.75)(0.25)}=\sqrt{6}\approx2.4495[/tex]
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it times. Here are the observed frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively: , , , , , . Use a significance level to test the claim that the outcomes are not equally likely. Does it appear that the loaded die behaves differently than a fair die?
Answer: There is no sufficient evidence to support the claim that loaded die behaves differently than a fair die
Step-by-step explanation:
Find explanations in the attached file
Hong buys a bag of 11 tangerines for $2.86.
Find the unit price in dollars per tangerine.
If necessary, round your answer to the nearest cent.
Answer:
$0.26
Step-by-step explanation:
To find the unit price, divide the cost by the amount you have.
$2.86/11 = $0.26
The unit price is $0.26.
18. Which of the following equations is equivalent to 25x = 7?
A. x=
log2 (3)
+1+9= 3? Is
B.
log27
5
C.
X=
log, 2
5
log, 5
D. x=
2
Answer:
x = log (7)/ 2log 5
Step-by-step explanation:
25^ x = 7
Replace 25 with 5^2
5^ 2x = 7
Take log on each side
log (5 ^2x) = log ( 7)
We know that log a^ b = b log a
2x log 5 = log (7)
Divide each side by log 5
2x log 5/ log 5= log (7)/ log 5
2x = log (7)/ log 5
Divide each side by 2
x = log (7)/ 2log 5
Zen spent $255 on a bag and a belt. She wanted to buy another
similar bag with the remaining money but was short of $30. In the
end, she bought another similar belt and had $15 left in the end.
(a) How much more did the bag cost than the belt?
(b) How much did the belt cost?
Answer:
A)$ 45
B) $105
Step-by-step explanation:
Bag and a belt cost $255
Let bag = x
Let belt = y
X+y= 255 equation 1
Let total money be z first
Remaining money= z-255
X-30 = z-255
Y +15 = z-255
Equating the left side of the equation
X+30 = y+15
X-y= 45 equation 2
Solving simultaneously
X+y= 255
X-y= 45
2x = 300
X= 150
If x= 150
150-y= 45
150-45= y
105=y
Bag = $150
Belt = $105
Bag Is 150-105 more than the belt
150-105= $45
The profit y (in dollars) for a company for selling x games is represented by y=32x. Graph the equation. ANSWER BEFORE 11 FOr BOnUs PoINTS!!!
Answer:
I guess that we have the linear equation:
y = 32*x
Where y is the profit, and x is the number of games sold.
Then the first step may be doing a table.
Give x different values, then find the value of y.
if x = 0
y = 32*0 = 0
if x = 1, y = 32*1 = 32
if x = 2, y = 2*32 = 64
Then the points:
(0,0) (1,32) and (2, 64) belong to this line, now we need to conect them with a straigth line and its ready.
The graph will be:
A sample of 4 different calculators is randomly selected from a group containing 42 that are defective and 20 that have no defects. What is the probability that all four of the calculators selected are defective? No replacement. Round to four decimal places.
Answer:
0.2006
Step-by-step explanation:
The probability the first calculator is defective is 42/62.
The probability the second calculator is defective is 41/61.
The probability the third calculator is defective is 40/60.
The probability the fourth calculator is defective is 39/59.
The probability all four calculators are defective:
(42/62) (41/61) (40/60) (39/59) = 0.2006
A sign company is creating a pennant in the shape of an equilateral triangle
The length of each side is 8 inches. What is the alttitude length so the
company will know what size box to ship the pennant in?
Hey there! :)
Answer:
4√3 in.
Step-by-step explanation:
Given:
-Equilateral triangle
-Side lengths of 8 in
Find the altitude using the Pythagorean Theorem (c² = a² + b²) where:
'a' is the shorter leg, or half of the base to find the altitude
'b' is the altitude
'c' is the Hypotenuse, or 8 in.
Therefore:
8² = 4² + b²
64 = 16 + b²
48 = b²
b = √48 or 4√3 in.
Therefore, the altitude of the triangle is 4√3 in.
Find the measure of y. Polygon Angle-Sum theorems
Answer:
z = 70°
y = 103°
Step-by-step explanation:
From the picture attached,
110° + z° = 180° [Supplementary angles]
z = 180 - 110
z = 70°
Since sum of interior angles of a polygon = (n - 2)×180°
where n = number of sides of the polygon
For a quadrilateral (n = 4),
Sum of interior angles = (4 - 2) × 180°
= 360°
z° + y° + 100° + 87° = 360°
70° + y° + 187° = 360°
y = 103°
Therefore, measure of the angles x = 70° and y = 103°.
How will the metric system be used in your furture career
Answer:
i feel as if in the United States, both the metric system and the English system of measurement are used, although the English system predominates. This discussion question has three parts:
Look around you to find something in the U.S. that is measured in metrics. Describe it to the class.
Give an example of how you think the metric system will be used in your future career.
Do you think the U.S. should switch to metric system exclusively? Why or why not?
This week we learned about the metric and U.S. customary measurement systems. Please upload and submit your responses to the following questions in at least 150 words:
In reflecting on both measurement systems, what did you find most important?
Explain how both measurement systems could relate to your life, community, or current/future career.
Expert Answer
Step-by-step explanation:
Suppose that MNO is isosceles with base NM. Suppose also that =m∠N+4x7° and =m∠M+2x29°. Find the degree measure of each angle in the triangle.
Answer:
m∠N = 51°
m∠M = 31°
m∠O = 98°
Step-by-step explanation:
It is given that ΔMNO is an isosceles triangle with base NM.
m∠N = (4x + 7)° and m∠M = (2x + 29)°
By the property of an isosceles triangle,
Two legs of an isosceles triangle are equal in measure.
ON ≅ OM
And angles opposite to these equal sides measure the same.
m∠N = m∠M
(4x + 7) = (2x + 29)
4x - 2x = 29 - 7
2x = 22
x = 11
m∠N = (4x + 7)° = 51°
m∠M = (2x + 9)° = 31°
m∠O = 180° - (m∠N + m∠M)
= 180° - (51° + 31°)
= 180° - 82°
= 98°
A catering service offers 11 appetizers, 8 main courses, and 4 desserts. A customer is to select 9 appetizers, 3 main courses, and 2 desserts for a banquet. In how many ways can this be done?
Answer:
Total number of required ways = 18480
Step-by-step explanation:
Given that
Total appetizers = 11
Total main courses = 8
Total desserts = 4
To be selected 9 appetizers
3 main courses and
2 desserts.
To find:
Number of ways of selecting them.
Solution:
Number of ways to select 'r' number of items out of 'n' number of items is given as:
[tex]_nC_r = \dfrac{n!}{(n-r)!r!}[/tex]
One important property:
[tex]_nC_r = _nC_{n-r}[/tex]
Here we have 3 items, we will find each items' number of ways of selecting and then will multiply all of them.
Number of ways to select 9 appetizers out of 11 appetizers:
[tex]_{11}C_9\ or\ _{11}C_2 = \dfrac{11 \times 10}{2} = 55[/tex]
Number of ways to select 3 out of 8 main courses:
[tex]_{8}C_3= \dfrac{8 \times 7 \times 6}{6} = 56[/tex]
Number of ways to select 2 desserts out of 4:
[tex]_{4}C_2= \dfrac{4 \times 3}{2} = 6[/tex]
Total number of ways = [tex]55 \times 56 \times 6[/tex] = 18480
Which could be the area of one lateral face of the triangular prism?
6.5 ft
6 ft
8 ft
2.5 ft
[Not drawn to scale]
7.5 ft2
15 ft?
20 ft
39 ft
Answer:
[tex](A)7.5 ft^2\\(C)20 ft^2[/tex]
Step-by-step explanation:
The diagram is attached below.
Area of the Rectangular Faces
[tex]8 X 6.5 =52$ ft^2\\8 X 2.5 =20$ ft^2\\8 X 6= 48$ ft^2[/tex]
Area of the Triangular face
[tex]=\dfrac12 X 2.5 X 6 =7.5$ ft^2[/tex]
Therefore, Options A and C could be the area of one lateral face of the triangular prism.
Answer:
C
Step-by-step explanation:
Find the volume of the region enclosed by the cylinder x squared plus y squared equals 36 and the planes z equals 0 and y plus z equals 36.
Answer:
[tex]\mathbf{V = 1296 \pi }[/tex]
Step-by-step explanation:
Given that :
Find the volume of the region enclosed by the cylinder [tex]x^2 + y^2 =36[/tex] and the plane z = 0 and y + z = 36
From y + z = 36
z = 36 - y
The volume of the region can be represented by the equation:
[tex]V = \int\limits \int\limits_D(36-y)dA[/tex]
In this case;
D is the region given by [tex]x^2 + y^2 = 36[/tex]
Relating this to polar coordinates
x = rcosθ y = rsinθ
x² + y² = r²
x² + y² = 36
r² = 36
r = [tex]\sqrt{36}[/tex]
r = 6
dA = rdrdθ
r → 0 to 6
θ to 0 to 2π
Therefore:
[tex]V = \int\limits^{2 \pi} _0 \int\limits ^6_0 (36-r sin \theta ) (rdrd \theta)[/tex]
[tex]V = \int\limits^{2 \pi} _0 \int\limits ^6_0 (36-r^2 sin \theta ) drd \theta[/tex]
[tex]V = \int\limits^{2 \pi} _0 [\dfrac{36r^2}{2}- \dfrac{r^3}{3}sin \theta]^6_0 \ d\theta[/tex]
[tex]V = \int\limits^{2 \pi} _0 [648- \dfrac{216}{3}sin \theta]d\theta[/tex]
[tex]V = \int\limits^{2 \pi} _0 [648+\dfrac{216}{3}cos \theta]d\theta[/tex]
[tex]V = [648+\dfrac{216}{3}cos \theta]^{2 \pi}_0[/tex]
[tex]V = [648(2 \pi -0)+\dfrac{216}{3}(1-1)][/tex]
[tex]V = [648(2 \pi )+\dfrac{216}{3}(0)][/tex]
[tex]V = 648(2 \pi )[/tex]
[tex]\mathbf{V = 1296 \pi }[/tex]
6x²-7x=20 solve the following quadratic equation
Answer:
x = -4/3 and x = 5/2.
Step-by-step explanation:
6x² - 7x = 20
6x² - 7x - 20 = 0
To solve this, we can use the quadratic formula to solve this.
[please ignore the A-hat; that is a bug]
[tex]\frac{-b±\sqrt{b^2 - 4ac} }{2a}[/tex]
In this case, a = 6, b = -7, and c = -20.
[tex]\frac{-(-7)±\sqrt{(-7)^2 - 4 * 6 * (-20)} }{2(6)}[/tex]
= [tex]\frac{7±\sqrt{49 + 80 * 6} }{12}[/tex]
= [tex]\frac{7±\sqrt{49 + 480} }{12}[/tex]
= [tex]\frac{7±\sqrt{529} }{12}[/tex]
= [tex]\frac{7±23 }{12}[/tex]
[tex]\frac{7 - 23 }{12}[/tex] = [tex]\frac{-16 }{12}[/tex] = -8 / 6 = -4 / 3
[tex]\frac{7 + 23 }{12}[/tex] = [tex]\frac{30}{12}[/tex] = 15 / 6 = 5 / 2
So, x = -4/3 and x = 5/2.
Hope this helps!
Answer:
[tex]x1 = - \frac{4}{3} [/tex][tex]x2 = \frac{5}{2} [/tex]Step-by-step explanation:
[tex]6 {x}^{2} - 7x = 20[/tex]
Move constant to the left and change its sign
[tex] {6x}^{2} - 7x - 20 = 0[/tex]
Write -7x as a difference
[tex]6 {x}^{2} + 8x - 15x - 20 = 0[/tex]
Factor out 2x from the expression
[tex]2x(3x + 4) - 15x - 20 = 0[/tex]
Factor out -5 from the expression
[tex]2x(3x + 4) - 5(3x + 4) = 0[/tex]
Factor out 3x + 4 from the expression
[tex](3x + 4)(2x - 5) = 0[/tex]
When the product of factors equals 0 , at least one factor is 0
[tex]3x + 4 = 0[/tex]
[tex]2x - 5 = 0[/tex]
Solve the equation for X1
[tex]3x + 4 = 0[/tex]
Move constant to right side and change its sign
[tex] 3x = 0 - 4[/tex]
Calculate the difference
[tex]3x = - 4[/tex]
Divide both sides of the equation by 3
[tex] \frac{3x}{3} = \frac{ - 4}{3} [/tex]
Calculate
[tex]x = - \frac{4}{3} [/tex]
Again,
Solve for x2
[tex]2x - 5 = 0[/tex]
Move constant to right side and change its sign
[tex]2x = 0 + 5[/tex]
Calculate the sum
[tex]2x = 5[/tex]
Divide both sides of the equation by 2
[tex] \frac{2x}{2} = \frac{5}{2} [/tex]
Calculate
[tex]x = \frac{5}{2} [/tex]
[tex]x1 = - \frac{4}{3} [/tex]
[tex]x2 = \frac{5}{2} [/tex]
Hope this helps...
Best regards!!
Suppose a city official conducts a hypothesis test to test the claim that the majority of voters oppose a proposed school tax. Assume that all of the conditions fro proceeding with a one-sample test on proportions have been met. The calculated test statistic is approximately 1.23 with an associated p-value of approximately 0.1093. Choose the conclusion that provides the best interpretation for the p-value at a significance level of alpha = 0.05.
A. If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is surprising (or considered unusual) and could not easily happen by chance.
B. If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is not surprising (or considered unusual) and could easily happen by chance
C. The p-value should be considered extreme: therefore, the hypothesis test proves that the null hypothesis is true
D. none of the above
Answer:
The correct option is (B).
Step-by-step explanation:
The p-value is well-defined as per the probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.
In this case, we need to test the claim that the majority of voters oppose a proposed school tax.
The hypothesis can be defined as follows:
H₀: The proportion of voters opposing a proposed school tax is not a majority, i.e. p ≤ 0.50.
Hₐ: The proportion of voters opposing a proposed school tax is a majority, i.e. p > 0.50.
It is provided that the test statistic value and p-value are:
z = 1.23
p-value = 0.1093
The probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic is 0.1093.
The significance level of the test is:
α = 0.05
The p-value of the test is larger than the significance level of the test.
p-value = 0.1093 > α = 0.05
The null hypothesis will not be rejected.
Concluding that there is not enough evidence to support the claim.
Thus, the correct option is:
"If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is not surprising (or considered unusual) and could easily happen by chance"
A firm has the marginal-demand function Upper D prime (x )equalsStartFraction negative 1200 x Over StartRoot 25 minus x squared EndRoot EndFraction . Find the demand function given that Dequals16 comma 000 when x equals $ 4 per unit.
Answer:
The demand function is [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
Step-by-step explanation:
A firm has the marginal-demand function [tex]D' x = \dfrac{-1200}{\sqrt{25-x^2 } }[/tex].
Find the demand function given that D = 16,000 when x = $4 per unit.
What we are required to do is to find the demand function D(x);
If we integrate D'(x) with respect to x ; we have :
[tex]\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
Let represent t with [tex]\sqrt{25-x^2}}[/tex]
The differential of t with respect to x is :
[tex]\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)[/tex]
[tex]\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}[/tex]
[tex]{dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]
replacing the value of [tex]\dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex] for dt in [tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
So; we can say :
[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = 1200\int\limits \ dt[/tex]
[tex]D(x) = 1200t+ C[/tex]
Let's Recall that :
t = [tex]\sqrt{25-x^2}}[/tex]
Now;
[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex]
GIven that:
D = 16,000 when x = $4 per unit.
i.e
D(4) = 16000
SO;
[tex]D(x) = 1200(\sqrt{25-x^2}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{25-4^2}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{25-16}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{9}})+ C[/tex]
[tex]D(4) = 1200(3}})+ C[/tex]
16000 = 1200 (3) + C
16000 = 3600 + C
16000 - 3600 = C
C = 12400
replacing the value of C = 12400 into [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex], we have:
[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
∴ The demand function is [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
(SAT Prep) Find the value of x.
Answer:
x = 65°
Step-by-step explanation:
Naming the sides of the parallelogram formed ABCD as shown in the attached image to this solution.
Angle A = 2x (vertically opposite angles are equal)
Angle A = Angle C (opposite angles of a parallelogram are equal)
Angle A = Angle C = 2x
(Angle C) + 50° = 180° (Sum of angles on a straight line is 180°)
2x + 50° = 180°
2x = 180° - 50° = 130°
x = (130°/2) = 65°
Hope this Helps!!!
Answer:
65 degrees
Step-by-step explanation:
Determine whether the function below is an even function, an odd function, both, or neither.
f(x)=x^6 + 10x^4-11x^2+19
ОА.
neither even nor odd
OB.
odd function
Ос.
both even and odd
OD.
even function
Reset
Next
Answer:
Step-by-step explanation:
even function are symmetrical about the y axis or f(-x)=f(x)
odd function are symmetrical about the origin -f(-x)=f(x)
f(x)=x^6 + 10x^4-11x^2+19
f(-x)=(-x)^6+10(-x)^4+11(-x)^2+19=x^6 + 10x^4-11x^2+19
the function is even
FOR BRAINLIEST ANSWER HURRY HELP THANKS If (a,b) is a point in quadrant IV, what must be true about a? What must be true about b?
Answer:
Well if (a,b) is in Quadrant IV which is the last quadrant the a or x is a positive number and the b or y is a negative number.
Answer:
a should be a positive number
b should be a negative number
A bag contains six balls labeled 1 through 6. One ball will be randomly picked.
What is the probability of picking an odd number?
Write your answer as a fraction in simplest form.
S = sample space = set of all possible outcomes
S = set of whole numbers 1 through 6
S = {1,2,3,4,5,6}
E = event space = set of outcomes we want to happen
E = set of odd numbers between 1 through 6
E = {1,3,5}
We have 3 items in set E and 6 items in set S. So there are 3 ways to get what we want to happen out of 6 ways total. The probability is therefore 3/6 = 1/2
Answer: 1/2Raven has a bag of 33 red and black marbles. The number of red marbles is 6 more than double the number of black marbles. Let r represent the number of red marbles and b represent the number of black marbles. Which statements about the marbles are true? Check all that apply. The equation r + b = 33 represents the total number of marbles. The equation r = 2 b + 6 can be used to find the number of red marbles. The equation r = 2 b + 6 represents the total number of marbles. The equation r + b = 33 can be used to find the number of red marbles. There are 9 red marbles in the bag. There are 9 black marbles in the bag. There are 24 black marbles in the bag. There are 24 red marbles in the bag.
Hey there! I'm happy to help!
If the number of red marbles is 6 more than double the number of black marbles, we can create this equation, with r representing the red marbles and b representing the black marbles.
r=2b+6
We also know that r+b=33, and if we know that r is equal to 2b+6, we can just replace r with that and then solve for b.
2b+6+b=33
We combine like terms.
3b+6=33
We subtract six from both sides.
3b=27
We divide both sides by 3.
b=9
Now we just subtract 9 from 33 to see how many red ones there are.
33-9=24
So, there are 24 red marbles and 9 black marbles.
Now, let's see which of these options are correct.
The equation r+b=33 represents the total number of marbles.
This is true because r plus b is equal to the total, which is 33.
The equation r=2b+6 can be used to find the number of red marbles.
This is true because it we used this r-value to find how many black marbles there were.
The equation r=2b+6 represents the total number of marbles.
This is false because it does not have the total number, which is 33.
The equation r=b=33 can be used to find the number of red marbles.
This is true because we plugged in the r-value to solve for b with this equation.
There are 9 red marbles in the bag.
This is false. There are 24 red marbles.
There are 9 black marbles in the bag.
This is true.
There are 24 black marbles in the bag.
This is false. There are 9 black marbles.
There are 24 red marbles in the bag.
This is true.
Have a wonderful day! :D
Answer:
1,2,4,6,8
Step-by-step explanation:
Identify any outlier(s) in the data. {52, 61, 42, 46, 50, 51, 49, 44, 40, 66, 53, 67, 45, 64, 60, 69}
An outlier in statistics is a data point that deviates considerably from other observations. The given data set has no outlier.
What is an outlier?An outlier in statistics is a data point that deviates considerably from other observations. An outlier can be caused by measurement variability or by experimental mistake; the latter is sometimes eliminated from the data set.
To find the outlier for the given data set follow the given steps.
Step one: The first step is to find the quartiles for the data set.
For this data set, the quartiles are:
Q1 = 45.5
Q3 = 62.5
Step Two: Find the Interquartile Range
The interquartile range is the difference between the first and third quartiles.
IQR = Q3 - Q1
IQR = 45.5 - 62.5
IQR = 17
Step Three:
The next step is to set up a fence beyond the first and third quartiles using the interquartile range.
Lower Fence = Q1 - (1.5 × IQR)
Lower Fence = 45.5 - (1.5 × 17)
Lower Fence = 20
Upper Fence = Q3 + (1.5 × IQR)
Upper Fence = 62.5 + (1.5 × 17)
Upper Fence = 88
Step Four: Find the Outliers
Any numbers in the data that are above or below the fences are outliers.
Since there are no numbers outside the two fences. Hence, it can be concluded that the given data set does not have, any outlier.
Learn more about Outlier:
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When dividing 336 by the natural number n> 10, the remainder is 2. Then the remainder obtained by dividing 2007 by n is
Answer:
3
Step-by-step explanation:
336 / n = k + 2/n, where k is an integer
336 = kn + 2
334 = kn
2007 / n
(2004 + 3) / n
(334×6 + 3) / n
334×6/n + 3/n
6k + 3/n
The remainder is 3.
Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard deviation for the given sample data.
33 29 97 56 26 78 83 74 65 47 58
What do the results tell us?
A. Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.
B. Jersey numbers on a football team vary much more than expected.
C. The sample standard deviation is too large in comparison to the range.
D. Jersey numbers on a football team do not vary as much as expected.
Answer:
Option(A) is correct
Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.
Step-by-step explanation:
The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58
the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:
Highest = 97
Lowest = 71
Range = highest value - Minimum value
Range = 97 - 26 = 71
[tex] Range= 71[/tex]
mean of the data is the summation of all the numbers in the data set divided by the number of given samples.
Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11
= 647/11
[tex]Mean value =58.7[/tex]
Now to find the variance of the data set by using below formular
σ²=[ (xᵢ -mean)²]/n-1
[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10
[tex]Variance=546[/tex]
Now, we will calculate standard deviation by taking square root over variance
σ =√(variance)
σ =√(546)
[tex]Standard deviation= 23.4[/tex]
Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,
Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.
the numbers of students in the 10 schools in a district are given below. ( Note that these are already ordered from Least to Greatest) 198, 216, 220, 236, 246, 252, 253, 260, 290, 319. Suppose that the number 319 from this list changes to 369. Answer the following what happens to the median? what happens to the mean?
Answer:median:249
Step-by-step explanation:
median:198] 216} 220] 236] 246 252 [253[ 260 {290[ 369
246 +252=498
498/2=249
as for the mean i will give you that later
At noon, ship A is 70 km west of ship B. Ship A is sailing south at 35 km/h and ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 4:00 PM
Answer:
57.6 km/h
Step-by-step explanation:
We are told that At noon, ship A is 70 km west of ship B.
Thus, coordinates of initial position of A and B is;
A(0,0) and B(70,0)
Now, we are told that Ship A is sailing south at 35 km/h and ship B is sailing north at 25 km/h. Thus, the final position of ship A and B after t hours are;
A(0,-35t) and B(70,25t)
Thus, distance between the two ships at time t hours is;
d(t) = √[(70 - 0)² + (25t - (-35t))²]
d(t) = √(4900 + 3600t²)
Now, to find how fast the distance between the ships changing, let's differentiate using the chain rule;
d'(t) = [1/(2√(4900 + 3600t²))] × 7200t
d'(t) = 3600t/√(4900 + 3600t²)
d'(t) = 3600t/10√(49 + 36t²)
d'(t) = 360t/√(49 + 36t²)
Now, at 4pm,it would have been 4 hours from noon. Thus, t = 4.
So;
d'(t) = (360×4)/√(49 + 36(4²))
d'(t) = 1440/√(49 + 576)
d'(t) = 1440/√625
d'(t) = 1440/25
d'(t) = 57.6 km/h
a truck and a car drive uniformly among the expressway from city a to city b. The truck leaves at 09:15 am and arrives at 1:15 pm. The car leaves at 10:00 am and arrives at 12:45 pm. At what times does the car overtake the truck? please help
Answer:
the car overtake the truck at time 11:40 am.
Step-by-step explanation:
We have both vehicules going at constant speed from city a to city b. The distance is unknown, but can be written as d.
We will express the time in hours (and decimals of hours).
The truck speed can be calculated estimating the time between arrival and start:
- The arrival time is 1.15 pm. This is t2=13.25.
- The starting time is 9:15 am. This is t1=9.25.
The truck took t2-t1=13.25-9.25=4 to go from city a to b.
The average speed is then:
[tex]v_t=\dfrac{\Delta x}{\Delta t}=\dfrac{d}{4}[/tex]
We can write the equation for the position x(t) for the truck as:
[tex]x(t)=x_0+v_t\cdot t=x_0+\dfrac{d}{4}t\\\\\\x(13.25)=x_0+\dfrac{d}{4}(13.25)=d\\\\x_0=d-3.3125d=-2.3125d\\\\\\x(t)=-2.3125d+0.25d\cdot t[/tex]
For the car we have:
- The arrival time is 12:45 am. This is t2=12.75.
- The starting time is 10 am. This is t1=10.
The car took t2-t1=12.75-10=2.75.
The average speed is then:
[tex]v_c=\dfrac{\Delta x}{\Delta t}=\dfrac{d}{2.75}[/tex]
We can write the equation for the position x(t) for the car as:
[tex]x(t)=x_0+v_c\cdot t=x_0+\dfrac{d}{2.75}t\\\\\\x(12.75)=x_0+\dfrac{d}{2.75}(12.75)=d\\\\x_0=d-4.6363d=-3.6363d\\\\\\x(t)=-3.6363d+0.3636d\cdot t[/tex]
The time at which the car overtake the car is the time when both vehicles have the same position:
[tex]x(t)/d=-2.3125+0.25\cdot t = -3.6363+0.3636\cdot t\\\\-2.3125+3.6363=(0.3636-0.25)t\\\\1.3238=0.1136t\\\\t=1.3238/0.1136\approx11.65[/tex]
The car overtakes the truck at t=11.65 hours or 11:39 am.
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Answer:
Likely
Step-by-step explanation: Mathematically it is likely because there are 4 options certain is the thing that will defiantly happen so it would be 4/4. The impossible thing would be 1/4 this is because 1/4 is the smallest so it is obviously going to be impossible. Likely would be 3/4 and unlikely would clearly be 2/4
Answer:
it is likely
Step-by-step explanation:
it is not certant because it is not 4/4 but it is not impossible because its not 0/4 so the answer is likely 3/4