Which Graph represents the solution to the compound inequality 4x +8< -16 or 4x + 8 > 4

Which Graph Represents The Solution To The Compound Inequality 4x +8&lt; -16 Or 4x + 8 &gt; 4

Answers

Answer 1

Answer:

option 3

Step-by-step explanation:

4x+8<-16

x<-6

4x+8_>-16

x_>-1

(it's more and equal .so the circle has to be shaded and move to the right of -1)

Answer 2

Answer:C

Step-by-step explanation:


Related Questions

What is the difference of the rational expressions below?
6/x - 5x/x+2
A.
5x + 6
2
O
B. 5x + 6x +12
** + 2x
O
c.
5x6
2x+2

D. 5x' +6x +12
2x + 2

Answers

The difference of the rational expressions 6/x - 5x/x+2 is (x + 12)/(x(x+2)).

Thus, the correct option would be:

C. (x + 12)/(x(x+2))

To find the difference of the rational expressions, we need to subtract the second expression from the first expression.

Let's simplify the expressions first:

The first expression is 6/x - 5x/(x+2).

To combine the terms, we need a common denominator, which is (x)(x+2).

Converting the first term, 6/x, to have a denominator of (x)(x+2), we get (6(x+2))/(x(x+2)).

Now, we can combine the terms:

[(6(x+2))/(x(x+2))] - [5x/(x+2)]

To subtract the fractions, we need to have a common denominator, which is (x)(x+2).

Expanding the numerators, we get:

[(6x + 12)/(x(x+2))] - [5x/(x+2)]

Now, we can subtract the fractions:

[(6x + 12 - 5x)/(x(x+2))]

Simplifying the numerator, we have:

(6x - 5x + 12)/(x(x+2))

Combining like terms, we get:

(x + 12)/(x(x+2))

Therefore, the difference of the rational expressions 6/x - 5x/x+2 is (x + 12)/(x(x+2)).

Thus, the correct option would be:

C. (x + 12)/(x(x+2))

For similar question on rational expressions.  

https://brainly.com/question/29061047

#SPJ8

plzz help brainliest thanks and 20 points Look at the cups shown below (images are not drawn to scale): A cone is shown with width 2 inches and height 3 inches, and a cylinder is shown with width 2 inches and height 7 inches. How many more cubic inches of juice will cup B hold than cup A when both are completely full? Round your answer to the nearest tenth. 18.8 cubic inches 21.9 cubic inches 25.1 cubic inches 32.6 cubic inches

Answers

Answer:

18.8 cubic inches

Step-by-step explanation:

1. Solve for the volume of Cup A. (volume of a cone = 1/3πr² · h)

1/3 · 3.14 · 1² · 3 = 3.14 in³

2. Solve for the volume of Cup B (volume of a cylinder = πr² · h)

3.14 · 1² · 7 = 21.98 in³

3. Subtract the volume of Cup A from Cup B

21.98 - 3.14 = 18.84

4. Round 18.84 to the nearest tenth

18.84 → 18.8 in.³

Answer:

18 .8

Step-by-step explanation:

got it right on test

Solve for x. Answer as an integer or simplified fraction. Please include steps. Thanks!

Answers

Answer:

x=40 degrees

Step-by-step explanation:

According to the angle sum theorem, the interior angles of a triangle add up to 180 degrees:

So, we can use the following equation to find x:

x+(x+10)+(210-3x)=180

now add like terms:

x+x+(-3x)+10+210=180

-x+220=180

now isolate the variable:

-x=180-220

-x=-40

x=-40/-1

x=40/1

x=40

The answer is that: the measure of x is 40 degrees

Can anyone help? I am stuck. Find m∠G.

Answers

Answer:

80

Step-by-step explanation:

The quadrilateral is a kite.

The angle opposite to angle H is equal to angle H.

Angle F = 110 degrees

Angles in a quadrilateral add up to 360 degrees.

60 + 110 + 110 + G = 360

280 + G = 360

G = 360 - 280

G = 80

The measure of angle G is 80 degrees.

Answer: 80 degrees.

Step-by-step explanation:

In a kite, the angles formed by noncongruent sides are congruent.  Thus, <EFG is 110 degrees.  Then, because a kite is a quadrilateral, all of the angles in it add up to 360.  Thus, is <FGH = x, then 110+110+60+x=360.  Thus, x = 80.

Hope it helps <3

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out to see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n 15 t 1.66 a 0.05
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n 15 t 1.66 a 0.05
Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n 26, t 2.55 a 0.01
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n 26, t 3.95
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 0.5 \ in[/tex]

     

Generally the Null hypothesis is  [tex]H_o : \mu = 0. 5 \ in[/tex]

                The Alternative hypothesis is  [tex]H_a : \mu \ne 0.5 \ in[/tex]

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]

We are making use of this  [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that  [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

 

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that  t  lies in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

determining probability of events. please help! ​

Answers

I am inclined to think that it is A. or B. Because they represent the highest probability, if it is not those it might be D.

This probably didn’t help, but if it did. I am glad (╹◡╹)

Determine whether the following sampling is dependent or independent. Indicate whether the response variable is qualitative or quantitative. A researcher wishes to compare of and She obtains a random sample of who and determines each Determine whether the following sampling is dependent or independent. A. B. The sampling is independent because an individual selected for one sample does dictate which individual is to be in the second sample. C. The sampling is dependent because an individual selected for one sample does not dictate which individual is to be in the second sample. D. Indicate whether the response variable is qualitative or quantitative. A. The variable is because it . B. The variable is because it . C. The variable is because it . D. The variable is because it .

Answers

Answer:

The sampling is dependent because an individual selected for one sample does dictate about which individual to be selected in the second sample.

The variable is qualitative because it classifies the individual.

Step-by-step explanation:

The sample is dependent as the second individual selected in the sample is dependent on the first individual selection. The sample selection is not random and is dictated. The variables selected are qualitative in nature because they identify the quality of response variable which is non numerical in nature.

A backpacking company requires each camper to bring a lantern to go on a trip. The company supplies 4 extra in case any lanterns get lost or broken. If 13 campers go on the trip, how many lanterns will they bring?

Answers

Answer:

17 lanterns.

Step-by-step explanation:

There are 13 campers with one lantern each, so that will be 13 * 1 = 13 lanterns.

The company supplies 4 extra lanterns for the whole group.

So, they will bring 13 + 4 = 17 lanterns.

Hope this helps!

Find exact value of cos

Answers

Answer: Choice B. [tex]\frac{\sqrt{91}}{10}[/tex]

Work Shown:

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\[/tex]

Answer:

√91/10

Step-by-step explanation:

sin 0.3 is equal to 18(approximate value)

cos18°=0.951

which is √91/10

6th grade math , help me please :)

Answers

Answer:

(a) 3:5

(b) 15

Step-by-step explanation:

Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.

It is asking for unshaded first so our ratio will be,

3:5

(a) 3:5

So if there is 9 unshaded how many shaded is there.

Well we can just make the following ratio 9:x

So 9/3 = 3

Meaning 3*5 = 15

So x = 15

(b) 15

Answer:

a) 3/5

b) 15

Step-by-step explanation:

(a)

unshaded: 3

shaded: 5

unshaded to shaded: 3/5

(b)

There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.

Add two more lines just like the given line.

Each new line will have 5 shaded and 3 unshaded squares.

Now you have a total of 9 unshaded and 15 shaded squares.

4 1/2 +1 3/5 (in the simplest form)

Answers

6 1/10

Step-by-step explanation:

4 + 1/2+1+3/5

5+1+1/10=6 1/10

PLEASE ANSWER QUICK A manufacturing facility pays its employees an average wage of $4.50 an hour with a standard deviation of 50cents. If the wages are normally distributed, what is the percentage of workers getting paid between #3.75 and $5.00 an hour? A. 80.4% B.77.4% C.70.5% D.65.4%

Answers

Answer:

B.77.4%

Step-by-step explanation:

Mean wage (μ) = $4.50

Standard deviation (σ) = $0.50

For nay given salary X, the z-score is given by:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

For X = $3.75, the z-score is:

[tex]z=\frac{3.75-4.50}{0.50}\\z=-1.5[/tex]

For X = $5.00, the z-score is:

[tex]z=\frac{5.00-4.50}{0.50}\\z=1[/tex]

A z-score of -1.5 corresponds to the 6.68th percentile, while a score of 1 corresponds to the 84.13th percentile. Therefore, the percentage of workers getting paid between $3.75 and $5.00 an hour is:

[tex]P=84.13-6.68\\P=77.45\%[/tex]

The answer is alternative B.77.4%


What is the greatest prime you must consider to test whether 7066 is prime?

Answers

Answer:

Step-by-step explanation:

The square root of 7066 is 84.0595....

Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...

That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.

84 isn't prime. But 83 is prime.

Therefore, the greatest prime that needs to be considered for divisibility is 83.

Answer:

The numbers 7066 is not prime .

But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.

Step-by-step explanation:

It is known with certainty that a number is prime when it is only divisible by and by unity.

But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.

for example; 7066/2=3533 , the remainder is zero;

Does the median represent the center of the​ data? A. The median represents the center. B. The median does not represent the center because it is the smallest data value. C. The median does not represent the center because it is the largest data value. D. The median does not represent the center because it is not a data value. E. There is no median age

Answers

Answer:

A. The median represents the center.

Step-by-step explanation:

In statistics and probability theory, the median value is the middle value or center value in a group of data values or numbers. To find the median, the values have to be placed in value order, from smallest to largest. The center number would be the median. The number lies between the higher half and the lower half. Therefore the median represents the center of the data values.

objective: central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds is/are

Answers

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

The CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

It is given that the objective that central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds.

It is required to describe the above theorem.

What is the central limit theorem?

It is defined as the in statistics the assumption holds that the sample means distribution of arbitrary variables follows a normal distribution or close to normal distribution if the sample size is big.

We have an objective:

The CLT is the factor to be considered when assessing if the CLT holds a large sample size.

If we draw the random sample data and its measures, the Central limit theorem explains the distribution will explain the normal bell curve, the mean of the parameters and the distribution will be the same.

Thus, the CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

Learn more about the Central limit theorem here:

https://brainly.com/question/5027686

6th grade math help me, please :)

Answers

Answer:

B. 168 students

Step-by-step explanation:

Given that there are a total of 600 students.

28% of the students pack their lunch.

To find:

Total number of students who pack their lunch = ?

Solution:

Percentage of a given number is calculated using the following method.

[tex]y\%[/tex] of a number [tex]x[/tex] is given by:

[tex]x \times \dfrac{y}{100}[/tex]

i.e. multiply the number by percentage to be found and divide by 100.

So, we have to find 28% of 600 here, to find the answer to the question.

[tex]\therefore[/tex] Number of students who pack their lunch is given as: (Multiply the given number 600 with 28 and divide by 100.)

[tex]600 \times \dfrac{28}{100}\\\Rightarrow 6 \times 28\\\Rightarrow \bold{168}[/tex]

So, the correct answer is:

B. 168

Add the following polynomials, then place the answer in the proper location on the grid.
2x3 - 4x2 + 6x - 3
29 +6x2 - 8x + 12
- 3x3 + 2x2 - 4x - 7
Help ????????

Answers

Answer:

[tex] x^3 - 6x + 2 [/tex]

Step-by-step explanation:

The given polynomials can be added together by adding like terms together as shown below:

=> Add together, the coefficient of all terms that have the power of 3.

[tex] (2x^3) + (x^3) + (-3x^3) [/tex]

[tex] 2x^3 + x^3 - 3x^3 [/tex]

[tex] 3x^3 - 3x^3 [/tex]

[tex] x^3 [/tex]

=> [tex] (-4x^2) + (6x^2) + (2x^2) [/tex]

[tex] -4x^2 + 8x^2 [/tex]

[tex] 4x^2 [/tex]

=> [tex] (6x) + (-8x) + (-4x) [/tex]

[tex] 6x - 8x - 4x [/tex]

[tex] -6x [/tex]

=> [tex] (-3) + (12) +(-7) [/tex]

[tex] -3 + 12 - 7 [/tex]

[tex] 2 [/tex]

The answer = [tex] x^3 - 6x + 2 [/tex]

Answer:

4x^2-6x+2

Step-by-step explanation:

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x)

Answers

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

[tex]f(x) = \sqrt{x}[/tex]

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

[tex]f^i(c) = \frac{f(b) - f(a)}{b -a }[/tex]

After this,

[tex]f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}[/tex]

[tex]f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\[/tex]

After this,

Put the values of a and b to the above equation

[tex]f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}[/tex]

= 2.25

In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $31 and standard deviation of $6. Construct a confidence interval at a 80% confidence level.

Answers

Answer:

29.4≤μ≤32.6

Step-by-step explanation:

The datas given from the questions are as shown:

Number of people n = 24

Mean xbar= $31

Standard deviation σ = $6

Confidence Interval formula is expressed as:

CI = xbar ± Z(σ/√n)

Z value for 80% confidence interval is 1.282

Substituting the values into the Confidence Interval formula will give;

CI = 31 ± 1.282{6/√24}

CI = 31 ± 1.282(1.225)

CI = 31 ± 1.57045

CI = 31+1.57045 and 31-1.57045

CI = (29.42955, 32.57045)

CI = (29.4, 32.6) to 1dp

The confidence interval will be within the range 29.4≤μ≤32.6

A group of children is trying to share a pile of stickers. If every
child gets two stickers, there will be 7 stickers left over. If two
children do not get any stickers, then each of the remaining
children will get exactly 3 stickers.
How many children are in the group?​

Answers

Answer:

7 children

Step-by-step explanation:

Answer:

7 children is the correct answer

and you follow me if you can't I will unfollow you

Identify an equation in point-slope form for the line perpendicular to
y= - 1/3x - 6 that passes through (-1,5).

O A. y + 1 = 3(x - 5)
O B. y + 5 = 1/3(x - 1)
O C. y - 5 = 3(x + 1)
O D. y - 5 = - 1/3(x + 1)

Answers

Answer:

hope you get it....sorry for any mistake calculations


A necklace was on sale for 20% discount off the original price of
$1250.00. What was the final sale price if 12.5% VAT has to be
paid?​

Answers

$1250 x 0.8 = $1000
$1000 x 1.125 = $1125
Therefore $1125 must be paid.

Answer:

= $ [tex] \mathsf{1125}[/tex]

Step-by-step explanation:

[tex] \mathrm{Given}[/tex],

[tex] \mathrm{Discount\% = 20\%}[/tex]

[tex] \mathrm{Marked \: price = 1250}[/tex]

[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]

[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]

[tex] \mathrm { = 20\% \: of \: 1250}[/tex]

[tex] \mathrm{ = 250}[/tex]

[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]

[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]

[tex] \mathrm{ = 1250 - 250}[/tex]

= $ [tex] \mathrm{1000}[/tex]

[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]

[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]

[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]

= $ [tex] \mathrm{ 125}[/tex]

[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]

[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]

[tex] \mathrm{ = 1000 + 125}[/tex]

= $ [tex] \mathrm{1125}[/tex]

Therefore, The final sale of the necklace is $ 1125

Hope I helped

Best regards!

*4.8.21
Question Help
O
After the release of radioactive material into the atmosphere from a nuclear power plant in a country in 2000, the hay in that country was contaminated by a radioactive
isotope (half-life 7 days). If it is safe to feed the hay to cows when 14% of the radioactive isotope remains, how long did the farmers need to wait to use this hay?
The farmers needed to wait approximately days for it to be safe to feed the hay to the cows.
(Round to one decimal place as needed.)
ות
nts
Enter your answer in the answer box and then click Check Answer.
All parts showing
Clear All
Check Answer
OK
here to search
O​

Answers

Answer:

  19.9 days

Step-by-step explanation:

The amount remaining after d days is ...

  a = (1/2)^(d/7)

We want to find d when a = 0.14

  log(a) = (d/7)log(1/2)

  d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9

The farmers need to wait about 19.9 days for it to be safe.

can i please get help with this

Answers

Step-by-step explanation:

Intersecting secant angles theorem: The angle between two secants is half the difference of the intersected arcs.

52 = ½ (x − 38)

x = 142

Arc angles add up to 360.

360 = 80 + 38 + z + x

z = 100

Tangent-chord theorem: The angle between a tangent and a chord is half the intercepted arc angle.

y = x/2

y = 71

Find the value of EB

Answers

Answer:

31

Step-by-step explanation:

Given,

AD = 38

EB = 7x - 4

FC = 6x - 6

Now, we have to find the value of X

[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )

Plug the values

[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]

Calculate the difference

[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]

Remove the parentheses

[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]

[tex]7x - 4 = 16 + 3x[/tex]

Move variable to L.H.S and change its sign

Similarly, Move constant to R.H.S and change its sign

[tex]7x - 3x = 16 + 4[/tex]

Collect like terms

[tex]4x = 16 + 4[/tex]

Calculate the sum

[tex]4x = 20[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{20}{4} [/tex]

Calculate

[tex]x = 5[/tex]

The value of X is 5

Now, let's find the value of EB

EB = 7x - 4

Plug the value of X

[tex] = 7 \times 5 - 4[/tex]

Calculate the product

[tex] = 35 - 4[/tex]

Calculate the difference

[tex] = 31[/tex]

The value of EB is 31

Hope this helps..

Best regards!!

Show all work for 135 points (90 points + brainliest = 135 pts)

Answers

Answer:

(a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

(I NEED HELP) The data below shows the scores of some students on a test: 23, 27, 21, 20, 25, 31, 22 Which box-and-whisker plot represents the data?

Answers

Answer:

B

Step-by-step explanation:

Answer:

the 2nd one

Step-by-step explanation:

because the Minimum is 20

the Maximum is 31

the median is 23

20, 21, 22, 23, 25, 27,  31,

21, 22, 23, 25, 27

22, 23, 25,

23

Help please!! Thank you

Answers

Answer:

D. 6

Step-by-step explanation:

here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}

and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }

so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.

Tessa solves the equation below by first squaring both sides of the equation HELP PLEASE

Answers

Answer:

-7

Step-by-step explanation:

[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]

Squaring on both sides:

[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]

Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]

[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]

Combine like terms.

[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]

[tex] - 3x + 2x = 7[/tex]

Calculate

[tex] - x = 7[/tex]

[tex]x = - 7[/tex]

Hope this helps...

Good luck on your assignment..

Answer:

-7

Step-by-step explanation:

Khan academy

Solving exponential functions

Answers

Answer:

Option B

an increasing exponential graph

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