Answer:
none of these
Explanation:
The expression:
P1/T1 = P2/T2 is a derivative of the combined gas law.
From the combination of the Boyle's and Charles's law, if the volume is taken to be constant, the pressure of the given mass of gas is directly proportional to the absolute temperature.
This is how the expression
P1/T1 = P2/T2 was obtained.
The higher the pH, the less acidic the solution
Answer:
yh thats true lol, ty for that very interesting fact
If the pH is higher the concentration of hydrogen ions becomes less and the solution becomes less acidic.
As the pH becomes lower, the concentration of hydrogen ions becomes greater, and the solution becomes more acidic.
HOPE IT'S HELPFUL : )
A sample of oxygen has a volume of 25.00 mL with a pressure of 2.0 atm. What pressure (in atm) will the sample of O2 gas occupy at 100.0 mL?
Answer:
0.5 atmExplanation:
The final pressure can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we are finding the new pressure
[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]
From the question we have
[tex]P_2 = \frac{25 \times 2}{100} = \frac{50}{100} = \frac{1}{2} \\ [/tex]
We have the final answer as
0.5 atmHope this helps you
Plsss help. No links. Thank you!
Answer:
good luckkkkkkkkkkkkkkk
Consider a copper-zinc corrosion couple. If the current density at the copper cathode is 0.05 A/cm2, calculate the weight loss of zinc per hour if the copper cathode area is 100 cm2 and the zinc anode area is 1 cm2 . Group of answer choices 0.061 g/h 6.1 g/h 61 g/h
Answer: the weight loss of zinc per hour is 6.1 g/h
Option c) 6.1 g/h is the correct answer.
Explanation:
Given that
copper cathode area is = 100 cm²
zinc anode area = 1 cm²
current density at the copper cathode = 0.05 A/cm²
The corrosion current can be converted to a rate of metal loss from its surface by using Faraday's law
W = ItM / nF
W is weight loss of metal , I is current ,
I = iCu × ACu = 0.05 A/cm² x 100 cm² = 5.0 A
M is atomic weight of metal
Atomic mass of Zn = 65.38 g/mol
n = number of electron
F = Faraday’s constant = 96,500 C/mol
so we substitute
W loss of Zn = (5 A) × (3600/h) (65.38 g/mol) / [2 × (96,500 C/mol) ]
= 1176840 / 193000
= 6.098 ≈ 6.1 g/h
Therefore the weight loss of zinc per hour is 6.1 g/h
Option c) 6.1 g/h is the correct answer.
HELP ME PLEASE ASAP FOR MY FINALSS!!!!!
Plant Leaf Model
Students read the following information about photosynthesis in their science textbook:
Plants use photosynthesis to make food
Animals get their food from plants
Photosynthesis produces a compound needed for respiration
The students want to build a simple model to represent photosynthesis in plants. They start with the materials shown below that they cut out of paper and label.
image c221f83634f54faf8522f256b7fce5a6
Which list BEST identifies how the arrows should be arranged around the paper leaf in the model to represent the movement of matter and flow of energy during photosynthesis?
A.
image 61ded7b213b443e08be3f457b66a7c02
B.
image 59241613e289486295f9fa893d4748e0
C.
image 4d21a3beee3a4555aed99677ecd74b7c
D.
image 66f376a76bb8401caffba053d6cf8973
Based on the proteins that were found in runners 2 cells, what can u say about his genes ?
Answer:runner has a1 and a2 it is heterozygous because it is two different gene verions.
Explanation:
An unknown weak base with a concentration of 0.0910 M has a pH of 10.50. What is the Kb of this base
Answer: The [tex]K_b[/tex] for the weak base is [tex]3.5\times 10^{-3}[/tex]
Explanation:
[tex]A^-+H_2O\rightarrow HA+OH^-[/tex]
cM 0 0
[tex]c-c\alpha[/tex] [tex]c\alpha[/tex] [tex]c\alpha[/tex]
So dissociation constant will be:
[tex]K_b=\frac{[HA][OH^-]}{[A^-]}[/tex]
[tex]K_b=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]
Given :
c= 0.0910 M and pH = 10.50
pOH = 14-pH = 14-10.50 = 3.5
Also [tex]pOH=-log[OH^-][/tex]
[tex][OH^-]=antilog(-3.5)= 3.2\times 10^{-4}M[/tex]
[tex][OH^-]=c\alpha=3.2\times 10^{-4}[/tex]
[tex]K_b=\frac{(3.2\times 10^{-4})^2}{(0.0910-3.2\times 10^{-4}}[/tex]
[tex]K_b=\frac{(3.2\times 10^{-4})^2}{(0.09068}[/tex]
[tex]K_b=3.5\times 10^{-3}[/tex]
Thus [tex]K_b[/tex] for the weak base is [tex]3.5\times 10^{-3}[/tex]
The Kb for the unknown weak base is 3.5 × 10⁻³.
How we calculate the dissociation constant for a weak base?Dissociation constant for a weak base at equilibrium is the ratio of the product of concentration of product to the concentration of un-ionized base.
Chemical reaction for a weak base at initial and equilibrium state can be represented as follow:
[tex]\[\mathop {{{\rm{A}}^{\rm{ - }}}}\limits_{\scriptstyle{\rm{c}}\hfill\atop\scriptstyle{\rm{c - c\alpha }}\hfill} {\rm{ + }}{{\rm{H}}_{\rm{2}}}{\rm{O}}\mathop { \to {\rm{HA}}}\limits_{\scriptstyle{\rm{0}}\hfill\atop\scriptstyle{\rm{c\alpha }}\hfill} {\rm{ + }}\mathop {{\rm{O}}{{\rm{H}}^{\rm{ - }}}}\limits_{\scriptstyle{\rm{0}}\hfill\atop\scriptstyle{\rm{c\alpha }}\hfill} \][/tex]
Kb = [HA] [OH⁻] / [A⁻]
Kb = (c∝)² / (c - c∝)
In the question given that,
pH = 10.50
Concentration of weak base c = 0.0910 M
We know that, pOH = 14 - pH
pOH = 14 - 10.50 = 3.5
Also we now that,
pOH = -log[OH⁻]
[OH⁻] = c∝ = antilog (-3.5) = 3.2 × 10⁻⁴ M
Now we put all these values in the above equation of Kb, we get
Kb = (3.2 × 10⁻⁴)² / (0.0910 - 3.2 × 10⁻⁴) = 3.5 × 10⁻³
Hence, 3.5 × 10⁻³ is the value of Kb.
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What is the anion in the chemical formula MnSe2?
Calculate the amount of heat required to completely sublime 96.0 gg of solid dry ice (CO2)(CO2) at its sublimation temperature. The heat of sublimation for carbon dioxide is 32.3 kJ/molkJ/mol. Express your answer in kilojoules.
Answer:
The correct answer is 70.41 kJ ≅ 70.4 kJ
Explanation:
The heat required to sublimate the solid at its sublimation temperature is calculated by using the following formula:
heat = ΔHs x moles of substance
Where ΔHs is the heat of sublimation, which is known (32.3 kJ/mol).
So, we have to calculate the moles of substance. For this, we can divide the mass of substance by the molecular weight of substance (CO₂):
mass CO₂ = 96.0 g
molecular weight CO₂ = (12 g/mol x 1) + (16 g/mol x 2) = 44 g/mol
⇒ moles of CO₂ = mass CO₂/molecular weight CO₂ = (96.0 g)/(44 g/mol) = 2.18 moles
Finally, we use the first formula to calculate the heat:
heat = ΔHs x moles = 32.3 kJ/mol x 2.18 mol = 70.41 kJ ≅ 70.4 kJ
Which of the following has kinetic energy?
Wind blowing at 3 km/h
A fully stretched elastic band
A boulder sitting on top of a hill
An unused battery
Answer:
wind blowing
Explanation:
"Wind is energy in motion—kinetic energy"
Answer: Wind Blowing
Explanation:
uhh ill give brainliest??
Explanation:
Given parameters:
Density of the ethanol = 0.789g/mL
Volume of the ethanol in the cylinder = 900mL
Unknown:
Mass of the ethanol = ?
Solution:
Since density is the mass per unit volume of a substance;
mass = density x volume
Now insert the parameters and solve;
mass = 0.789g/mL x 900mL
mass = 710g
In scientific notation we have 7.10 x 10²g
The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hertz (s^ -1 )? pls help
Answer:
6.56×10¹⁴ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength = 457 nm
Frequency =?
Next, we shall convert 457 nm to metre (m). This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
457 nm = 457 nm × 1×10¯⁹ m / 1 nm
457 nm = 4.57×10¯⁷ m
Thus, 457 nm is equivalent to 4.57×10¯⁷ m
Finally, we shall determine the frequency of the blue light as follow:
Wavelength = 4.57×10¯⁷ m
Velocity of light = 3×10⁸ m/s
Frequency =?
Velocity = wavelength x frequency
3×10⁸ = 4.57×10¯⁷ × frequency
Divide both side by 4.57×10¯⁷
frequency = 3×10⁸ / 4.57×10¯⁷
frequency = 6.56×10¹⁴ Hz
Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz
Using the periodic table locate the element with the average atomic mass 87.62 which of the following is the chemical symbol for the element
Answer:
Strontium (Sr)
Explanation:
Atomic number 38
Relative atomic mass 87.62
If you have 25 pieces of bread and 9 pieces of turkey and a turkey
sandwich is made from 2 pieces of bread and 1 piece of turkey, what is the
limiting reagent?
Turkey plus bread
None of these
Bread
Turkey
Determine whether each observation describes a chemical or a physical property. 1. When a piece of sodium metal is placed in a test tube with water, the sodium zees and bubbles of gas are formed. 2. When table salt is added to water in a test tube, the table salt dissolves. . 3. When a glass marble is heated and then quickly cooled, it shatters. *
1.Sodium metal reacts rapidly with water to form a colorless solution of sodium hydroxide ... strip is placed in a test tube containing 5 mL of hydrochloric acid, HCl. Both liquids ... If it fizzes and bubbles
2.When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules.
3.When platinum is heated, then cooled to its original state, we say this is a physical change. 19. ... Scratches glass. Sour taste ... A bar of lead is more easily bent than is a bar of aluminum of the same size.
rock with a mass of 70 grams is dropped into a graduated cylinder with 30 mL of water. The water level rose. Whats the density of the rock in g/mL.
The density of the rock in g/mL : 14 g/ml
Complete question :
A rock with a mass of 70 grams is dropped into a graduated cylinder with 30 mL of water in it. The water level rose to 35 mL calculate the density of the rock in g/mL
Further explanationDensity is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]
ρ = density
m = mass
v = volume
mass of rock = 70 g
Volume of the rock : 35 - 30 = 5 ml
So the density :
[tex]\tt \rho=\dfrac{70}{5}\\\\\rho=14~g/ml[/tex]
An unknown element (Uk) has three isotopes, as presented in
the table below. One of the percentage values is missing.
After calculating the missing percent abundance (%).
determine the average atomic mass of Uk.
Enter your answer to the hundredths place.
Percent
Abundance
(%)
Uk-66 65.994 58.00
Isotope Mass
Notation (amu)
Uk-69 68.958
Uk-71 70.975
10.00
?
The average atomic mass of the element, Uk is 67.44 amu.
What is the average atomic mass of the element, Uk?The average atomic mass of the element Uk is determined from the sum of the isotopic masses of the isotopes of the element and their relative abundances.
average atomic mass = sum of (isotopic mass * relative abundance) of the isotopesThe isotopic masses and relative abundance of the isotopes are given below:
Isotope:Uk-66; Isotopic mass = 65.994; relative abundance = 58.00%
Isotope:Uk-69; Isotopic mass = 68.958; relative abundance = ?
Isotope:Uk-71; Isotopic mass = 70.975; relative abundance = 10.00%
Relative abundance of Uk-69 = 100% - (58 + 10)% = 32%
The average atomic mass of Uk = (65.994 * 58.00%) + (68.958 * 32%) + (70.975 * 10.00%)
The average atomic mass of Uk = 67.44 amu
In conclusion, the average atomic mass of an element is obtained from the of the isotopic masses of the isotopes of the element and their relative abundances.
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18 pointssssssssssss help plz :)
why fe2o3 is called ferric oxide
Answer:
it contains O3, therefore making it an oxide
Answer:
iron (11) oxide
Explanation:
Hydrazine reacts with oxygen according to the following equation: N2H4(g) +O2(g) → N2(g) + 2 H2O(l) How many L of N2, measured at 34.9 °C and 755.08 torr, will be produced at the same time that 914.894 g of H2O is produced?
Answer:
V ≈ 646.50 L
General Formulas and Concepts:
Chemistry - Gas Laws
Reading a Periodic TableStoichiometryCombined Gas Law: PV = nRTR constant - 62.4 (L · torr)/(mol · K)Kelvin Conversion: K = °C + 273.15Explanation:
Step 1: Define
RxN: N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)
Given: 34.9 °C, 755.08 torr, 914.894 g H₂O
Step 2: Identify Conversions
Kelvin Conversion
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Convert
Stoichiometry: [tex]914.894 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )(\frac{1 \ mol \ N_2}{2 \ mol \ H_2O} )[/tex] = 25.3955 mol N₂
Temperature: 34.9 + 273.15 = 308.05 K
Step 4: Find Volume
Substitute variables: (755.08 torr)V = (25.3955 mol)(62.4 (L · torr)/(mol · K))(308.05 K)Multiply: (755.08 torr)V = 488160 L · torrIsolate V: V = 646.502 LStep 5: Check
We are given 5 sig figs as our lowest. Follow sig fig rules and round.
646.502 L ≈ 646.50 L
Scientific notation.
Answer:
The answer is 2.31×10^12
Explanation:
(4.2×10^9)(5.5×10^2)
(4.2×5.5)×(10^9×10^2)
23.1×10^9+2
23.1×10^11
Answer:2.31×10^12
Can anyone help me with my homework
The exclusion zone restricts access to the area around Chernobyl. The soil is still radioactively contaminated after the Chernobyl nuclear explosion. Chernobyl had four nuclear reactors. Uranium dioxide, UO2, was the fuel in the reactors in Chernobyl.
Control rods slow chemical reactions because they absorb neutrons. This prevents the neutrons from reacting with additional uranium Protons and neutrons are found in the nucleus of an atom.
Isotopes are atoms of the same element that have the same number of protons and electrons but different numbers of neutrons. Iodine -131 half-life of eight days, strontium – 90 half-life of 29 years, cesium-137 half-life of 30 years In fission, the nucleus of a Uranium dioxide U-235 atom is bombarded by a neutron.
This splits the nucleus to release a daughter nuclei, more neutrons, and energy. If we start with a 30 g sample of Uranium dioxide I-131, there would be 7.5 grams of I-131.be after 16 days When one atom of uranium goes through fission, the reaction releases a small amount of energy. When the reaction is repeated on the mole scale though, the self-sustaining reaction becomes significantly larger, producing exponentially more energy.
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When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________.
Answer: equivalence point
When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the equivalence point.
The equivalence point is called the moment when the equivalents of the titrated substance and those of the titrant substance are equal.
When a strong acid is neutralized with a strong base, the pH undergoes a sharp change just at the equivalence point.
At the time of neutralization, it is true that the number of equivalents of acid that have reacted is equal to the number of equivalents of the base.
This equivalence point is very easily detected since a sharp pH jump is observed in its vicinity, which can be detected in a pH meter or with an indicator.
Therefore, we can conclude that the equivalence point of a reaction is the point at which an equivalent amount of acid and base has been added.
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A 0.4708 g sample of a pure soluble bromide compound is dissolved in water, and all of the bromide ion is precipitated as AgBr by the addition of an excess of silver nitrate. The mass of the resulting AgBr is found to be 0.9093 g. What is the mass percentage of bromine in the original compound
Answer:
The correct answer is 82.18%.
Explanation:
Based on the given information, the mass of the pure soluble bromide compound is 0.4708 grams, and the mass of the formed silver bromide is found to be 0.9093 grams.
The molecular weight of AgBr is 187.77 g/mol, and the molecular weight of Br is 79.9 g/mol.
So, 0.9093 grams of AgBr comprise (79.9 * 0.9093)/187.77 = 0.3869 grams of bromine.
Now, 0.4708 grams of sample comprise 0.3869 grams of bromine. Therefore, 100 grams of sample comprise (0.3869*100) / 0.4708 g = 82.18 grams of bromine.
The mass % of bromine in the original compound is 82.18%.
Which chemical reaction involves the fewest oxygen atoms?
A. 2AgNO3 + K2SO4 → Ag2SO4 + 2KNO3
B. 4Fe + 6H2O + 302 4Fe(OH)3
C. 6CO2 + 6H20 - C6H12O6 + 602
D. C2H4 + 302 - 2CO2 + 2H2O
Answer:
4Fe + 6H2O + 3O2 -------> 4Fe(OH)3
Explanation:
The chemical reaction involves the fewest oxygen atoms is 4Fe + 6H2O + 302 4Fe(OH)3. Therefore, option B is correct.
What is chemical reaction ?The chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances.
When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.
We can learn about a substance's qualities by studying chemical reactions. We can learn about a substance's chemical characteristics by looking at how it interacts with other substances. These characteristics can be utilized to recognize an unidentified sample.
Thus, option B is correct.
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Which of the following excited state electron configurations of C would require the longest wavelength of light to produce?
Question 1 options:
1s22s22p2
1s22s22p13p1
1s22s22p24s1
1s22s22p13s1
Electronic configuration of carbon at excited state is 1s₂, 2s₂, 2p₂. so, option A is correct.
What is electronic configuration ?
According to electronic configurations, each electron moves individually within an orbital while being surrounded by an average field produced by all other orbitals.
Electronic configuration includes the number of shell, orbit, orbital. s, p, d, f different shell present in it.
One orbital can house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels.
As was said, each element's position on the periodic table determines the specific electron configuration of that element.
Thus, option A is correct.
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What are the spectator ions in the reaction between KCl (aq) and AgNO3 (aq)?
A) K+ and Ag+
B) Ag+ and Cl-
C) K+ and NO3
-
D) Ag+ and NO3
Answer:
K^+ and NO3-
Explanation:
The correct answer to the question is Option C. K⁺ and NO₃¯
Spectator ions are ions that remains unchanged in a reaction i.e they can be seen in the reactants and products of a particular reaction.
To obtain the spectator ions in the reaction between KCl (aq) and AgNO₃ (aq), we shall write the ionic equation. This is illustrated below:
KCl (aq) —> K⁺(aq) + Cl¯(aq)
AgNO₃ (aq) —> Ag⁺(aq) + NO₃¯(aq)
KCl (aq) + AgNO₃ (aq) —>
K⁺(aq) + Cl¯(aq) + Ag⁺(aq) + NO₃¯(aq) —> AgCl(s) + K⁺(aq) + NO₃¯(aq)
From the ionic above, we can see that K⁺ and NO₃¯ appears on both side of the equation.
Therefore, K⁺ and NO₃¯ are the spectator ions.
Thus, Option C. K⁺ and NO₃¯ gives the correct answer to the question.
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PLEASE HELP ASAP!!!!!
Claw length on Galapagos Island iguanas is an adaptation to its:
A. Predators
B. Habitat
C. Climate
D. Attractiveness to mates
Answer:
B. habitat
Explanation:
got it right on my test hope this helps:)
Answer:
It's habitat.
Explanation:
I took the Module 3 Exam and got it right.
How many molecules are there in 39 grams of water
Answer:
I think its 117
Explanation:
H20
2*39 (hydrogens)
78
78+39(oxygens)
117
Which explains the change in ionization energy that occurs between removing
the first and second electrons from an
atom?
O The ionization energy decreases because the ratio of the protons to electrons increases.
O The ionization energy increases because the ratio of the protons to electrons increases.
O The ionization
energy decreases because the ratio of the protons to electrons decreases.
O The ionization energy increases because the ratio of the protons to electrons decreases.
The ionization energy increases as the ration of protons to electrons increases.
On the periodic table, as we move from left to right through a period, the initial ionization energy rises. This is due to the outermost electron becoming more closely bound to the nucleus as the nuclear charge increases.
Ionization energy - the energy needed to remove an electron from a gaseous atom, is the one that best exemplifies periodic behavior.
The energy needed to remove each additional electron from an atom grows gradually, with the removal of an electron from a filled inner shell causing a significant increase.
A stable atom becomes electrically imperfect or imbalanced if we remove one of its electrons. In other words, the nucleus's protons (positive charges) outnumber its electrons (negative charges). It is a positive ion because the atom has a plus-one charge after losing an electron.
Therefore on removing the second electron more ionization energy will be required than first. So option D is correct.
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