Which factor does not affect the rate of dissolving a solid in a liquid?
A) Temperature.
B) Surface area of the solvent.
C) Surface area of the solute.
D) Agitation.

A welder's acetylene tank has volume of 75.0L There are approximately 196.7 moles of acetylene in the tank.

Acetylene is a chemical compound with the formula as C₂H₂ and structure H−C≡C−H.

PV = nRT

P is pressure, V is volume, n is number of moles, R is gas constant, and T is temperature in kelvins.

Now convert the temperature from degrees Celsius to kelvins:

T = 23.24°C + 273.15 = 296.39 K

n = PV / RT

=(7667 kPa)(75.0 L) / [(8.314 J/mol K)(296.39 K)]

So, n = 196.7 mol

Therefore, there are approximately 196.7 moles of acetylene in the tank.

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Ar has three naturally occurring isotopes  ³⁶Ar, ³⁸Ar, and ⁴⁰Ar. Each contains 18 electrons and protons. The no of neutrons in ³⁶Ar, ³⁸Ar, and ⁴⁰Ar are 18, 20 and 22 respectively. The mass number of ³⁶Ar, ³⁸Ar, and ⁴⁰Ar are 36, 38 and 40 respectively.

Protons and neutrons are positively charged and neutral species respectively found in the nucleus of an element. Whereas, electrons are negatively charged species present in the orbitals surrounding the nucleus.

The sum of number of protons and number of neutrons of an element is called the atomic mass. It is represented by the symbol "A". And, atomic number is defined as the number of electrons present in an element. It is represented by "Z".

Isotopes are defined as the elements which have the same atomic number but their atomic masses are different. Number of proton is equal to number of electrons present in an element.

The atomic number of ³⁶Ar, ³⁸Ar, and ⁴⁰Ar is 18.

∴ Neutrons = atomic mass - atomic number

Neutrons of ³⁶Ar = 36-18 = 18

Neutrons of ³⁸Ar= 38- 18= 20

Neutrons of ⁴⁰Ar = 40- 18= 22

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The amount of acyclovir  milliliters to be administered per dosage is 100 ml.

To calculate the number of milliliters to be administered per dosage, you will have to follow the following steps:

1. Convert micrograms (mcg) to milligrams (mg). To do this, divide the micrograms by 1000. Therefore, 1000 mcg = 1 mg.

2. The concentration after reconstitution is given as 0.5 mg/ml.

3. Dilute 1 mg in 50 mL of normal saline. This can also be expressed as 0.02 mg/mL (1 mg/50 mL).

4. Use a ratio of the concentration after reconstitution to the diluted concentration to calculate the final concentration of the medication. It is done by multiplying the concentration after reconstitution by the dilution factor.

Therefore, 0.5 mg/mL * 0.02 = 0.01 mg/mL.5. The prescribed dose is 1,000 mcg or 1 mg.6. Divide the dose by the concentration to find the number of milliliters to be administered per dose. 1 mg / 0.01 mg/mL = 100 mL. Therefore, you will administer 100 mL per dose. Therefore, the amount of milliliters to be administered per dosage is 100 ml.

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Entrepreneurs revitalise communities by creating jobs that raise the standardization of living and enhance lifestyles by relocating their new companies to Florida.

The east coast of Florida was developed by Henry Morrison Flagler, who is best known for this. Between Daytona and Key West, he was in charge of constructing the Florida Eastern Seaboard Railway. Through tourism and agriculture, Flagler made a big contribution to Florida's economy.

Florida is growing in popularity among business owners and entrepreneurs for a variety of reasons. The state has a cutting-edge public policy that supports the creation of new products. In addition, it offers a sizable, multilingual workforce, cheap taxes, and a supportive business environment.

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a normal result for the glucose screening test is a blood sugar that is equal to or much less than 140 mg/dL (7.8 mmol/L) 1 hour after drinking the glucose solution.

you'll drink a liquid that includes glucose, and then 1 hour later your blood will be drawn to test your blood sugar degree. A ordinary end result is a hundred and forty mg/dL or lower. if your stage is better than 140 mg/dL, you will need to take a glucose screening check.don't devour excessive-sugar meals or easy carbs (such as delicate grains) the morning of your glucose screening. The body breaks those meals down quick, main to a spike in blood sugar levels. meaning avoiding breakfast favorites like: Orange juice and different fruit juices

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The solution has a boiling point of 100.354 °C and a freezing point of -1.2927 °C.

The boiling and melting points of a solution are affected by the number of solute particles present in the solvent. To determine these points, we need to calculate the molar concentration of glucose (C₆H₁₂O₆) in the solution.

First, we need to convert 25 g of glucose to moles. The molar mass of glucose is 180 g/mol, so 25 g of glucose is 0.139 moles.

Next, we need to calculate the molarity of the solution. Since we have 0.20 L of water, the total volume of the solution is 0.20 L. Therefore, the molarity of the solution is 0.139 moles / 0.20 L = 0.695 M.

Using the molal boiling point elevation constant for water of 0.51 °C/m, we can calculate the boiling point elevation of the solution. ΔTb = Kbm, where ΔTb is the boiling point elevation, Kb is the molal boiling point elevation constant, and m is the molality of the solution. For a 1.00 m aqueous solution, ΔTb is 0.51°C. So for our 0.695 m solution, ΔTb is (0.51°C/m) x (0.695 m) = 0.354°C. Therefore, the boiling point of the solution is slightly elevated from the boiling point of pure water (100°C) to 100.354°C.

To calculate the freezing point depression of the solution, we can use the formula ΔTf = Kfm, where ΔTf is the freezing point depression, Kf is the molal freezing point depression constant, and m is the molality of the solution. The molal freezing point depression constant for water is 1.86°C/m [3]. Thus, ΔTf = (1.86°C/m) x (0.695 m) = 1.2927°C. Therefore, the freezing point of the solution is depressed from the freezing point of pure water (0°C) to -1.2927°C.

In summary, the boiling point of the solution is 100.354°C, and the freezing point of the solution is -1.2927°C.

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The unknown acid is a weak: diprotic acid. The first pKa of the unknown acid is: 3.0, and the second pKa is: 5.0.

A substance that releases hydrogen ions in water is known as an acid. It has a pH of less than 7, which is the acidic range. Acids are the opposite of bases in chemistry, which release hydroxide ions when dissolved in water.The unknown acid is a weak diprotic acid.

pKa is the negative logarithm of the acid dissociation constant (Ka). It is a measure of the acidity of a molecule, with lower values indicating stronger acids. A pKa value of 3.0 corresponds to a weak acid.

A diprotic acid is a substance that has two hydrogen ions to donate when dissolved in water. The chemical formula for a diprotic acid is often written in the following way: H2A, with the acid donating two hydrogen ions to the water. A weak diprotic acid is an acid that does not fully dissociate in water.

The first pKa of the unknown acid is 3.0.

The second pKa of the unknown acid is 5.0.

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The addition of 2 mL of 6.0 M HCl caused the equilibrium to shift in the reverse direction.

This is because the HCl added to the solution decreases the amount of SbClz in solution. This dilutes the solution by increasing the total volume, and increases the moles of H' and CH in solution.

To reach equilibrium, the system must increase the amount of reactants, so an equilibrium shift in the reverse direction is observed. The reaction of the SbClz in solution with the added H' and Cl' in solution also contributes to the shift in equilibrium, as more products are formed. The net effect of the addition of HCl is an equilibrium shift in the reverse direction.

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The temperature change for substance A will be half that of substance B. Since they both start at the same temperature, substance B will have the higher final temperature.

What is specific heat capacity?

The specific heat capacity of a substance refers to the quantity of energy required to increase the temperature of a given mass of that substance by one degree Celsius or one Kelvin. In this case, substance A has twice the specific heat capacity of substance B. Thus, substance A requires twice as much energy to increase its temperature by a certain amount as substance B.

Let the temperature of both substances be equal, and each absorbs 100 J of energy. This implies that the temperature increase in both substances will be equal. Consider that both substances have the same mass, and hence the same number of molecules. If the heat absorbed by both substances is the same and the mass of both substances is equal, the change in temperature would be the same.

The equation that relates the quantity of heat absorbed, the mass of the substance, the temperature change, and the specific heat capacity of the substance is Q = mcΔT where Q is the quantity of heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the temperature change.

Since the change in temperature is equal for both substances, and since the heat absorbed is the same, the specific heat capacity of the substance with the higher specific heat capacity would result in a lower temperature rise. Thus, Substance B will have a higher final temperature as compared to Substance A.

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the solubility of kcl at 60 °c in 100g of h2o is about 45 g/100 g H2O


with a view to be capable of understand what's occurring while the solution is cooled from  60∘C  to  0∘C , you want to look at the solubility graph for potassium chloride,  KCl .
notice that the solubility curve shows that at  60∘C , potassium chloride has a solubility of about  45 g/100 g H2O .
What which means is that at that temperature, you may best dissolve  45 g of potassium chloride in step with  100 g  of water. This genuine amount of potassium chloride will result in a saturated solution.
A saturated solution is an answer in that you have an equilibrium between the strong solute and debris of solute which can be being dissolved into answer

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Moles of gold present in a ring that contains 3.4x10¹⁹ gold atoms is  5.64x10⁻⁵. The correct option is (d).

The thin coating of gold metal on a ring contains 3.4x10¹⁹ gold atoms. We need to find how many moles of gold is this.

Gold (Au) is a chemical element with the symbol Au (from Latin: aurum) and atomic number 79. It is a soft, dense, yellow metal with a bright, metallic luster. Gold has an atomic mass of 196.967 g/mol. Hence one mole of gold atoms will have a mass of 196.967 grams.

The number of moles of gold can be calculated as follows.

Calculate the number of grams of gold present in the ring coating.

Avogadro's number (N) is a physical constant defined as the number of atoms or molecules in one mole of a substance. Its value is 6.02214076 × 10²³ mol⁻¹.

There are 3.4x10¹⁹ gold atoms present in the ring coating.

Moles of gold atoms = Number of gold atoms / Avogadro's number

The number of gold atoms = 3.4x10¹⁹ atoms; Avogadro's number (N) = 6.02214076 × 10²³ mol⁻¹

∴Moles of gold atoms = 3.4x10¹⁹ / 6.02214076 × 10²³ = 5.64x10⁻⁵

Hence the number of moles of gold is 5.64x10⁻⁵.

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803 mmHg is equal to 106.44 kPa. This can be calculated using the equation P (kPa) = P (mmHg) × 0.133322.

The pressure of 803 mmHg is equal to 106.44 kPa. This can be calculated by using the following equation: P (kPa) = P (mmHg) × 0.133322. Therefore, 803 mmHg is equal to 106.44 kPa. To understand this relationship better, pressure can be thought of as a measure of how much force is applied to a certain area. The unit of measure for pressure is the Pascal (Pa), and one kPa is equal to 1000 Pa. The unit of measure for pressure in mmHg is the millimeter of mercury (mmHg). One mmHg is equal to 133.322 Pa. Therefore, one kPa is equal to 7.5 mmHg. To convert from mmHg to kPa, the equation is

P (kPa) = P (mmHg) × 0.133322. Using this equation, the pressure of 803 mmHg can be converted to 106.44 kPa.  

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When acid and/or base is added to a non-buffered solution, the pH of the solution will undergo drastic changes. On the other hand, the pH of a buffered solution will remain relatively constant upon the addition of an acid or a base.

A buffer solution is one that can resist changes in pH upon the addition of an acid or base. A buffer solution is made up of a weak acid and its corresponding base or a weak base and its corresponding acid.

1. When acid is added to a buffered solution, the weak acid in the buffer reacts with the added H+ ions to form more of the conjugate base of the weak acid. This reaction consumes the added H+ ions and helps to maintain the pH of the solution.

2. When a base is added to a buffered solution, the weak base in the buffer reacts with the added OH- ions to form more of the conjugate acid of the weak base. This reaction consumes the added OH- ions and helps to maintain the pH of the solution.

3. When acid is added to a non-buffered solution, the concentration of H+ ions in the solution increases, leading to a significant decrease in the pH of the solution. When a base is added to a non-buffered solution, the concentration of OH- ions in the solution increases, leading to a significant increase in the pH of the solution.

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Answer:

70,219.4 Joules

Explanation:

To calculate the amount of energy required to heat a substance, we can use the following formula:

Q = m * C * ΔT

Where Q is the amount of heat energy required (in Joules), m is the mass of the substance being heated (in grams), C is the specific heat capacity of the substance (in J/g - °C), and ΔT is the change in temperature (in °C).

In this case, we want to find the amount of energy required to heat 706 g of nickel from 25°C to 300°C, given that the specific heat capacity of nickel is 0.444 J/g - °C.

First, we need to calculate ΔT, which is the difference between the final temperature (300°C) and the initial temperature (25°C):

ΔT = 300°C - 25°C = 275°C

Next, we can plug in the values we know into the formula:

Q = m * C * ΔT

Q = 706 g * 0.444 J/g - °C * 275°C

Q = 70,219.4 J

Therefore, it would require approximately 70,219.4 Joules of energy to heat 706 g of nickel from 25°C to 300°C.

The sets of reagents that will result in an efficient Williamson ether synthesis (SN2) are  A. ii and iv

The Williamson ether synthesis is a process for preparing ethers. The reaction involves the nucleophilic substitution of an alkyl or aryl halide with a deprotonated alcohol (alkoxide ion).

A Williamson ether synthesis is a reaction in which an alkyl or aryl halide reacts with an alcohol in the presence of a strong base to create an ether. Because the mechanism for this reaction entails an S_N2 nucleophilic substitution, it is typically used with primary alkyl halides or methyl halides.The two sets of reagents that will result in an efficient Williamson ether synthesis (SN2) are Br + ONa and iBr + ONa. The answer is option A, ii and iv.  Br +ONa and iBr +ONa.

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The fabrication method that joins together materials, usually metal, is known as welding.

There are several different types of welding, including:

Arc welding - This involves using an electric arc to create heat and melt the metal pieces to be joined. The most common types of arc welding include shielded metal arc welding (SMAW), gas metal arc welding (GMAW), and gas tungsten arc welding (GTAW).

Gas welding - This involves using a gas flame to heat the metal pieces to be joined. The most common types of gas welding include oxy-fuel welding and oxy-acetylene welding.

Resistance welding - This involves using an electric current to heat the metal pieces to be joined. The most common types of resistance welding include spot welding, seam welding, and projection welding.

Laser welding - This involves using a high-energy laser beam to heat and melt the metal pieces to be joined.

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The more massive particle will move at the same speed as the less-massive particle. The correct answer is Option D.

In physics, mass is a measure of an object's resistance to acceleration when a net force is applied to it. The larger the mass, the more force is required to accelerate it. This property is usually referred to as inertia in everyday speech.

In physics, the mass of an object is frequently denoted by m. The standard unit of mass is the kilogram (kg).

Mass has a considerable influence on the velocity of an object. The greater the mass of an object, the slower it travels at a given speed. According to Newton's second law of motion, a force acting on an object equals the mass of the object times its acceleration.

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In the given question, 0.550 J/g-°C is the specific heat of the metal. The correct answer is option a.

Specific heat is defined as the amount of heat energy needed to raise the temperature of one unit of mass of a substance by one degree Celsius (or one Kelvin).

To calculate the specific heat of the metal, we can use the equation:

q(metal) = -q(water)

where q(metal) is the heat absorbed by the metal, and q(water) is the heat released by the water. The negative sign indicates that the heat lost by the water is equal in magnitude to the heat gained by the metal.

c(metal) = [m(water) [tex]\times[/tex] c(water) [tex]\times[/tex] ΔT] / [m(metal) [tex]\times[/tex] ΔT]

where,

c(metal) is the specific heat of the metal,

m(water) is the mass of the water,

c(water) is the specific heat of water,

ΔT is the change in temperature and

m(metal) is the mass of the metal.

Substituting the given values, we get:

c(metal) = [100.0 g [tex]\times[/tex] 4.18 J/g-°C [tex]\times[/tex] (25.7°C - 15.0°C)] / [72.0 g [tex]\times[/tex] (105.3°C - 25.7°C)]

c(metal) = 0.550 J/g-°C

Therefore, the specific heat of the metal is option a. 0.550 J/g-°C.

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The mathematical expression that can be used to determine the value of s, the molar solubility of PBI2(s), given that a saturated solution is prepared by dissolving PBI2(s) in distilled water until no more solid dissolves is given by the equation below.

The mathematical expression that can be used to determine the value of s, the molar solubility of PBI2(s) is given by the following equation:

s = (x mol/L)

where;

x= molar solubility of PBI2(s) in mol/L

The concentration of the PBI2(s) in a saturated solution can be represented as x. The concentration is expressed in terms of the amount of substance (mol) per unit volume (L). Therefore, the mathematical expression that can be used to determine the value of s, the molar solubility of PBI2(s) is s = (x mol/L) which can be used to calculate the molar solubility of PBI2(s). Therefore, the answer is:

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The percent mass of the red dye is 2.92% when  7.3 g of red dye is dissolved in water to form 250 g solution.

Percent composition is defined as a convenient way to record concentration of solution.It is useful in making solutions of different concentrations.It is a expression which relates element to compound as,mass of element/mass of compound ×100.There are 2 types :percent  mass and percent by volume .Substitution of values in formula gives, 7.3/250×100= 2.92 %.

Thus, percent mass of the red dye is 2.92% when  7.3 g of red dye is dissolved in water to form 250 g solution.

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The balanced chemical equation, including physical state symbols, for the combustion of gaseous butane into gaseous carbon dioxide and gaseous water is:C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

Firstly, write the unbalanced chemical equation and then balance it using the given steps:

Step 1: Write the unbalanced equation for the given chemical reaction.C4H10 + O2 → CO2 + H2O

Step 2: Count the number of atoms of each element in the reactants and the products. C4H10 + O2 → CO2 + H2O

Reactants: Carbon = 4Hydrogen = 10Oxygen = 2 + (1/2) × 13 = 8.5

Products: Carbon = 1 × 4 = 4Hydrogen = 2 × 5 = 10Oxygen = 2 + (1/2) × 10 = 7

Step 3: Balance the equation by putting coefficients in front of the compounds.C4H10 + O2 → 4CO2 + 5H2O

Reactants: Carbon = 4Hydrogen = 10Oxygen = 2 + (1/2) × 13 = 8.5

Products: Carbon = 1 × 4 = 4Hydrogen = 2 × 5 = 10Oxygen = 2 + (1/2) × 10 = 7

By multiplying 4 to CO2, the Carbon will get balanced. By multiplying 5 to H2O, the Hydrogen will get balanced. By multiplying 13/2 to O2, Oxygen will get balanced.

The balanced chemical equation for the combustion of gaseous butane into gaseous carbon dioxide and gaseous water is C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g).

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The moles of the magnesium ions and the chlorate ions are produced by the dissolving 1.5 mol of the magnesium chlorate is the magnesium ion is 1.5 mol and the moles of the chlorate ions is 3 mol.

The chemical equation is as :

Mg(ClO₃ )₂ (s)      ⇄    Mg⁺²      +      2ClO₃⁻

The moles of the magnesium chlorate, Mg(ClO₃ )₂ = 1.5 mol

The 1 mole of the magnesium chlorate produces the 1 mole

of the magnesium ion.

The moles of the magnesium ion = 1.5 mol

1 mole of the magnesium chlorate produces the 2 mole

of the chlorate ions.

The moles of the chlorate ions = 2 × 1.5 mol

The moles of the chlorate ions = 3 mol

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An object's gravitational potential energy depends on its mass and its height above a reference level. The higher the object and the greater its mass, the more gravitational potential energy it has.

The amount of gravitational potential energy that an object has depends on two factors: its mass and its height above a reference level, such as the ground. The gravitational potential energy of an object increases with its mass, as well as its height above the reference level. The higher the object is from the reference level, the more potential energy it has due to the gravitational force between it and the Earth. This is expressed mathematically as:

Gravitational potential energy = mass x gravity x height

where "mass" is the mass of the object, "gravity" is the acceleration due to gravity, and "height" is the distance of the object from the reference level.

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The compounds that give positive results in the Jones oxidation test are primary and secondary alcohols. The compounds that give negative results in the Jones oxidation test are tertiary alcohols and unsaturated alcohols.

As per the Jones oxidation test, it is considered that primary and secondary alcohols give positive results while tertiary alcohols and unsaturated alcohols give negative results. Jones oxidation test is a method to oxidize primary and secondary alcohols to their corresponding aldehydes and ketones. The reagents required for the Jones oxidation test are chromic acid, sulfuric acid, and acetone.

The Jones oxidation test is a method for oxidizing primary and secondary alcohols to their corresponding aldehydes and ketones. The test reagents are chromic acid, sulfuric acid, and acetone. This test was first introduced by Sir Edward Frankland Jones in the year 1887. This test is used to differentiate between primary, secondary, and tertiary alcohols.

Here are the given compounds and their answer for the Jones oxidation test: cyclohexanol - Yes, cyclohexanol will give a positive result in the Jones oxidation test.2, 3-dimethyl-2-hexanol - No, 2,3-dimethyl-2-hexanol will not give a positive result in the Jones oxidation test. 1-butanol - Yes, 1-butanol will give a positive result in the Jones oxidation test.

Morphine - No, morphine will not give a positive result in the Jones oxidation test.Tert-butanol - No, tert-butanol will not give a positive result in the Jones oxidation test.

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The balanced form of the equations are:

To write a balanced chemical equation, follow these steps:

Write the correct chemical formula for each reactant and product. Write the unbalanced equation using chemical symbols and formulas. Balance the equation by adjusting the coefficients so that the number of atoms of each element is the same on both sides of the equation. Check that the equation is balanced by counting the number of atoms of each element on both sides of the equation.

Note that in a balanced equation, the number of atoms of each element and the total charge are the same on both sides of the equation. Also, be sure to write the state of matter for each reactant and product (solid, liquid, gas, aqueous solution).

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Image transcribed:

Balance the following equations

1. N₂ + H₂ → NH₃

2. S₈ + O₂ → SO₃

3. HgO → Hg + O₂

4. Zn + HCI → ZnCl₂ + H₂

5. SiCl₄ + H₂O → H₄SiO₄ + HCL

6. Na + H₂O → NaOH + H₂

7. H₃PO₄ → H₄P₂O₇ + H₂O

8. Si₂H₃+ O₂ → SiO₂+ H₂O

9. AI(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O

10. Fe + O₂ → Fe₂O₃

11. Fe₂(SO₄)₃ + KOH → K₂SO₄ + Fe(OH)₃

12. FeS₂ + O₂ → Fe₂O₃ + SO₂

13. Al + FeO → Al₂O₃ + Fe

14. Na₂CO₃ + HCI → NaCl + H₂O+ CO₂

15. K + Br₂→ KBr

16. P₄ + O₂ → P₂0₅

17. C₂H₂ + O₂ → CO₂ + H₂O

Chlorophyll absorbs blue, red, and orange light most strongly, so the color of light that is not strongly absorbed by chlorophyll is green.

Chlorophyll is a pigment found in plant cells and is accountable for the plant's green color. It also assists in the absorption of light energy from the sun, which is essential for photosynthesis to occur. The two types of chlorophyll, chlorophyll a and chlorophyll b, differ slightly in their molecular structure, but they both absorb light best in the blue and red areas of the spectrum. While chlorophyll absorbs light in most areas of the visible spectrum, it is least effective at absorbing green light, which is reflected and provides plants with their green appearance.

Photosynthesis is a process in which green plants produce organic compounds like carbohydrates and oxygen from carbon dioxide and water using sunlight as an energy source. The process of photosynthesis takes place in organelles called chloroplasts, which are found in the green parts of plants, including leaves and stems. Photosynthesis takes place in two stages: the light-dependent reaction and the light-independent reaction. Light is absorbed by pigments like chlorophyll in the first stage, which is followed by the production of ATP and NADPH. These products are subsequently utilized to convert carbon dioxide and water into glucose in the second stage of photosynthesis. The glucose generated may be utilized for energy or stored as starch.

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Answer:

The salts which are obtained by the partial replacement of ionizable hydrogen atoms of a polybasic acid by a metal or an ammonium ion are called acidic salts.

H2SO4 + NaOH → NaHSO4 +H2O

Answer:

Acid salts are a class of salts that produce an acidic solution after being dissolved in a solvent.

Explanation:

your messageConvert to number of atoms 294 grams AuTo convert 294 grams of Au to the number of atoms, we need to use the Avogadro's number, which is 6.022 x 10^23 atoms/mole. First, we need to find the number of moles of Au in 294 grams: 294 grams Au / 196.97 g/mole = 1.49 moles Au Next, we can calculate the number of atoms: 1.49 moles Au x 6.022 x 10^23 atoms/mole = 8.97 x 10^23 atoms Au Therefore, there are approximately 8.97 x 10^23 atoms of gold in 294 grams.